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HAL Id: hal-00362417

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Preprint submitted on 18 Feb 2009

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Sub Hilbert spaces In the unit Ball of

n

Frédéric Symesak

To cite this version:

Frédéric Symesak. Sub Hilbert spaces In the unit Ball ofn. 2009. �hal-00362417�

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Abstract. Let Φ(z) = (ϕ1(z),· · ·, ϕl(z)) :BlBn be holomorphic. We denote byBα(z, w) the weighted Berman kernel. We give a condition so that the kernel

1Φ(z)Φ(w)

Bα(z, w) is a reproducing kernel and we study the related Hilbert space.

1. Introduction

The aim of this note is to give a characterization of some reproducing kernels of spaces of holomorphic functions on the unit ball of Cn. These kernels are obtained with the weighted Bergman kernelBα(z, w) and bounded holomorphic functions ϕ1(z),· · · , ϕl(z).

We denote by B the unit ball of Cn and by r(z) = Pn

i=1|zi|2 −1 a defining function. Let α >−1 and let dVα(z) = (−r(z))αdV(z). We denote by A2α the weighted Bergman space of B with respect the measure dVα(z) [3]. It is a Hilbert space and its reproducing kernel is given by Bα(z, w) = cα

(1−zw)n+1+α. When α = 0, we denote by B(z, w) the usual Bergman kernel and byA2 the Bergman space. we have

Theorem 1.1. Let α > −1 and Φ(z) = (ϕ1(z),· · · , ϕl(z)) be holomorphic. The kernel Kα(z, w) =

1−Φ(z)Φ(w)

Bα(z, w) is a reproducing kernel if and only if supB|Φ(w)| ≤1.

The reproducing properties of kernels of type (1 − ϕ(z)ϕ(w))B(z, w) was studied by F.

Beatrous and J. Burbea [1], for spaces of holomorphic functions on domains of Cn and by S.

Saitoh for abstract kernels of Hilbert spaces of functions [5]. In the case of he unit disc of C, when ϕ is finite Blaschke product, the characterization of the related Hilbert space was obtained by K. Zhu [8] and [9] for Bergman space and by S. Sultanic for weighted Bergman spaces [7]. The same questions was introduced by L. De Branges ang J. Rovnyak in the context of Hardy spaces [6]. The following theorem gives the Hilbert space associated to the kernel Kα(z, w). We have

Theorem 1.2. Let α ≥ 1 and let Φ(z) = (ϕ1(z),· · · , ϕl(z)) be holomorphic. The Kernel Kα(z, w)is a reproducing kernel ofA2α−1 if and only if there existsC > 0such that1−|Φ(z)|2 ≤ C(−r(z)), z in B.

For −1 ≤ α < 0, we denote by Bα2 the diagonal Besov space. A holomorphic function f belongs toBα2 if and only if (I+N)f is inA2α+1, where N =Pn

k=1zkzk is the normal complex field [3]. We have

1

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2 FREDERIC SYMESAK

Theorem 1.3. Let Φ(z) = (ϕ1(z),· · · , ϕl(z)) be holomorphic. If there exists C >0 such that supB|N ϕi(w)| ≤C i, 1≤i≤l, then

(1) If 0< α <1, Kα(z, w) is a reproducing kernel of A2α−1. (2) K0(z, w) is a reproducing kernel of the Hardy space H2. (3) If −1< α <0, Kα(z, w) is a reproducing kernel of B2α.

2. Sub-Bergman spaces

Recall that the Bergman projection Bα is the orthogonal projection from L2(dVα) onto A2α. Given a bounded function ϕ the To¨eplitz operator of symbol ϕ is defined by Tϕf = Bα(ϕf).

We consider the self-adjoint operator H given by

Definition 2.1. Let Φ(z) = (ϕ1(z),· · · , ϕl(z)) be holomorphic. We set Hf =

l

X

i=1

ϕiTϕif f ∈A2α.

We first estimate the norm of H. We have

Proposition 2.2. Let H as above. Then kHk= supB|Φ(w)|2. Proof : Letf inA2α. Then

kHfkA2α

l

X

i=1

iBαif)kA2α ≤sup

B

|Φ(w)|

l

X

i=1

kBαif)kA2α. Since Bα is a projection,kBαif)kA2α ≤ kϕifkA2α, then

l

X

i=1

kBαif)kA2

α ≤sup

B

|Φ(w)|kfkA2

α.

Let fw(z) = Bα(z, w)

pBα(w, w), u in B. Then Hfw(z) = Pl

i=1ϕi(z)ϕi(w)fw(z) and hHfw, fwiα =

|Φ(w)|2, where h·,·iα is the inner product of A2α. The relationhHfw, fwiα ≤ kHkkfk2

A2α and the

fact thatkfwkA2α = 1 finish the proof.

Proof of the theorem 1.1: Assume that supB|Φ(w)|2 ≤ 1. Then H is a contraction and the operator (I−H)1/2 is well defined. It is a self-adjoint operator and it is well known that (I−H)1/2A2α is a sub-Hilbert space whose reproducing kernel is given by (I−H)Bα(z, w) = Kα(z, w) see [6],[8] for details.

Assume now that Kα(z, w) is a reproducing kernel, then for any finite sequences (wj) Kα(wj, wk) is a definite positive matrix. Let w be a point in the ball, then Kα(w, w) = (1− |Φ(w)|2)Bα(w, w)≥0, then |Φ(w)|2 ≤1.

Proof of the theorem 1.2: The proof involves the Douglas criterion [2] we mention here the statement.

Douglas criterion : Let H1, H2 and H be Hilbert spaces. Let A from H1 into H and B from H2 into H be bounded operators.

There exists λ >0 such that AA λBB if and only if Im(A)⊂Im(B).

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In the definition, the relationAA λBB means that λBB−AA is a positive operator.

We consider the coordinate functions Φ0(z) = (z1,· · ·, zn) and we denote byH0 its associated operator. The kernel of the Hilbert space (I −H0)1/2A2α is given by (1−zw)Bα(z, w) = cαBα−1(z, w). Then (I−H0)1/2A2α =A2α−1 by the uniqueness of the reproducing kernel.

If we suppose thatKα(z, w) is a reproducing kernel ofA2α−1, from the Douglas criterion, there existsλ >0 such thatI−H λ(I−H0). Letf inA2α. Thenh(I−H)f, fiα ≤λh(I−H0)f, fiα. Letw in B. The functionf(z) = Bα(z, w) gives 1− |Φ(w)|2 ≤λ(−r(w)).

The sufficient conditions follows from the result :

Proposition 2.3. Let Φ(z) = (ϕ1(z),· · · , ϕl(z)) be holomorphic. If 1− |Φ(z)|2 ≤ C(−r(z)), there exists λ >0 such that

1

λ(I−H0)I−H λ(I−H0).

Proof of the proposition 2.3 : Letα≥1. The right part of the ”inequality” follows from two technical lemmas :

Lemma 2.4. There exists C > 0 such that for f in A2α, h(I−H)f, fiα ≤Ckfk2

A2α+1. Proof : Letf inA2α. Then

(1) h(I−H)f, fiα = Z

B

Z

B

Kα(z, w)f(w)f(z)(−r(w))α(−r(z))αdV(w)dV(z).

Let K(z, w) = Kα(z, w)(−r(w))1/2+α/2(−r(z))1/2+α/2 and notice by K the integral operator given by

(2) Kg(z) =

Z

B

K(z, w)g(w)dV(w), g ∈L2(B)

Assume for the moment that K is bounded in L2(B), the Chauchy-Schwarz inequality gives h(I−H)f, fiα≤ kK(f(−r(·))1/2+α/2)kL2(B)kfkA2

α+1 ≤Ckfk2

A2α+1.

It remains to study the boundedness ofK. This follows from the Schur criterion [10]. We have only to prove that there exists C > 0 such that K(z, w) = C

|1−zw|n+1. Recall that, [4] prop 8.1.4.,

(3) |1−Φ(z)Φ(w)|2

(1− |Φ(z)|2)(1− |Φ(w)|2) ≤ |1−zw|2 (−r(z))(−r(w)). Therefore there exists C > 0 such that

1−Φ(z)Φ(w)

≤ C|1−zw| then |K(z, w)| has the desired pointwise estimate.

We finish the proof of the proposition with the following result : Lemma 2.5. Let α >−1. There exists C >0 such that

1 Ckfk2

A2α+1 ≤ h(I −H0)f, fiα ≤Ckfk2

A2α+1, f ∈A2α.

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4 FREDERIC SYMESAK

Proof : The proof is direct. Letf(z) =X

m

amzm. Recall that

kzmk2

A2α =cαΓ(m1+ 1)· · ·Γ(mn+ 1) Γ(|m|+n+ 1 +α) ,

where|m|=m1+· · ·+mn [4]. Let us remark that (1−zw)Bα(z, w) = cBα−1(z, w). Then (I−H0)f(z) =c

Z

B

Bα−1(z, w)f(w)(−r(w))αdV(w) = cX

m

amzm

|m|+n+α. and

h(I−H0)f, fiα =cX

m

|am|2 Γ(m1+ 1)· · ·Γ(mn+ 1) (|m|+n+α)Γ(|m|+n+ 1 +α). Notice that

kfk2

A2α+1 =cX

m

|am|2kzmk2

A2α+1 =cX

m

|am|2Γ(m1 + 1)· · ·Γ(mn+ 1) Γ(|m|+n+ 2 +α) . The equivalence follows from the relation Γ(z+ 1) =zΓ(z).

For the left part of the ”inequality” (of the proposition 2.3), we consider the auxiliary operator He given byHfe =Bα(|Φ|2f),α >−1. Let us remark thatkHk ≤e supB|Φ(w)|2 andhHf, fiα = Pl

i=1if, Bαif)iα ≤Pl

i=1if, ϕifiα =hHf, fe iα, then

(4) I−He I−H

We have the following result :

Lemma 2.6. Let He as above. There exists λ >0 such that I−H0 λ(I −H).e Proof : Let us remark that 1− |Φ(0)|2 ≤2|1−Φ(z)Φ(0)|, the relation (3) gives

1

1− |Φ(z)|2 ≤ 4 1− |Φ(0)|2

|1−Φ(z)Φ(0)|2

(1− |Φ(z)|2)(1− |Φ(0)|2) ≤ C (−r(z)). Then −r(z)≤C(1− |Φ(z)|2) and kfk2

A2α+1 ≤Ch(I−H)f, fe iα. It remains to apply the lemma 2.5 to achieve the proof.

Proof of the theorem 1.3 : The proof is similar for 0 ≤ α ≤ 1 but require a minor modification to use the Schur criterion. We recall that for uan v holomorphic functions [4],

Z

B

u(w)v(w)(−r(w))αdV(w) = Z

B

(N + (n+ 1 +α)I)u(w)v(w)(−r(w))α+1dV(w)

= Z

B

u(w)(N + (n+ 1 +α)I)v(w)(−r(w))α+1dV(w), (5)

In this case the kernel of (I − H0)1/2A2α is given by (1−zw)Bα(z, w) = cBα−1(z, w) thus (I−H0)1/2A2α is the weighted Bergman space A2α−1 when 0 < α < 1, the Hardy space H2 for α= 0 and the Besov space Bα for −1< α <0.

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Forf inA2α,

(I−H)f(z) = Z

B

(N + (n+ 1 +α)I)Kα(z, w)f(w)(−r(w))α+1dV(w) and the relation (1) becomes

h(I−H)f, fiα = Z

B

(N + (n+ 1 +α)I)(I −H)f(z)f(z)(−r(z))α+1dV(z) Let

K(z, w) = (−r(z))α/2+1/2(−r(w))α/2+1/2×

(N + (n+ 1 +α)I)(N + (n+ 1 +α)I)Kα(z, w) and K be the integral operator given by (2). Then

h(I−H)f, fiα = Z

B

K(f(·)(−r(·))1/2)(z)f(z)(−r(z))1/2dV(z).

K(z, w) =

1

X

s,t=0

(I+ (n+ 1)N)s(I + (n+ 1)N)t(1−Φ(z)Φ(w))

×(I+ (n+ 1)N)1−s(I + (n+ 1)N)1−tBα(z, w).

Then there exists C >0 such that

|K(z, w)| ≤ C(−r(z))α/2+1/2(−r(w))α/2+1/2( |1−Φ(z)Φ(w)|

|1−zw|n+1+α+2 +

P

i|N ϕi(w)|+P

i|N ϕi(z)|

|1−zw|n+1+α+1 +(P

i|N ϕi(z)|) (P

i|N ϕi(w)|)

|1−zw|n+1+α ). Recall that |1−Φ(z)Φ(w)| ≤C|1−zw| and supB|N ϕi(w)| ≤C, then

|K(z, w)| ≤ C(−r(z))1/2(−r(w))1/2

|1−zw|n+2 .

Let us remark that (−r(z)) and (−r(w)) are bounded by a constant times |1−zw|. Then

|K(z, w)| ≤ C

|1−zw|n+1. The operator K is bounded in L2(B) and the relation (1) gives h(I−H)f, fiα ≤Ckfk2

A2α+1. The lemma 2.5 givesI −H ≤λ(I −H0).

The theorem 1.2 and 1.3 characterize the sub-Hilbert space (I−H)1/2(Aα), this space is the analogue for the unit ball of Cn of the complementary space. The space (I−H)e 1/2(Aα) is also a complementary space. It is a consequence of the relation (4) and the lemma 2.6 that there existsC > 0 such that

1

C(I−H0)I−He I−H

Under the condition on Φ given in the theorem 1.2 and theorem 1.3, we have (I−H)e 1/2(Aα) = (I−H)1/2(Aα).

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6 FREDERIC SYMESAK

References

[1] F. Beatrous and J. Burbea, Interpolation problems for holomorphic functions, Trans. Am. of Math 284, (1984), p. 247-270.

[2] R. Douglas,On majorization, factorization, and range inclusion of operators on Hilbert space, Proc.Amer.

Math. Soc. 1, (1966), p. 413-415.

[3] S. Krantz,Function theory of several complex variables, John Wiley and Sons, New York, 1982 [4] W. Rudin,Function theory in the Unit Ball ofCn, 241, Srpinger Verlag, New York-Berlin, 1980.

[5] S. Saitoh,Theory of reproducing kernel and its applications, Pitan research notes in Mathematics 189, New York, 1988.

[6] D. Sarason,Sub-Hardy Hilbert spaces in the Unit Disk, John Wiley & Sons, Inc., New York, 1994.

[7] S. Sultanic,Sub-Bergman Hilbert spaces, J. of Math. Anal and App. 234 (2005) p. 639-649.

[8] K. Zhu, Sub-Bergman Hilbert Spaces on the Unit Disk, Indiana Univ. Math. J. 45 (1996), p. 165-176.

[9] K. Zhu, Sub-Bergman Hilbert Spaces on the Unit Disk II, Journal of Func. Anal. 202 (2003), p. 327-341.

[10] K. Zhu,Operator Theory in Function Spaces, Dekker, New-York, 1990.

Fr´ed´eric Symesak, Universit´e de Poitiers, UMR 6086 CNRS, Laboratoire de Math´ematiques et Application, T´el´eport 2, Boulevard Pierre et Marie Curie, BP30179, 86962 FUTUROSCOPE.

Frederic.Symesak@univ-poitiers.fr

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