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Journal of Computational Physics
www.elsevier.com/locate/jcp
Numerical solution of an inverse boundary value problem for the heat equation with unknown inclusions
Haibing Wang
∗, Yi Li
SchoolofMathematics,SoutheastUniversity,Nanjing 210096,PRChina
a r t i c l e i n f o a b s t r a c t
Articlehistory:
Received1August2017
Receivedinrevisedform3February2018 Accepted4May2018
Availableonline9May2018
Keywords:
Inverseproblem Unknowninclusions Heatequation Layerpotential
Weconsidertheproblemofreconstructingunknowninclusionsinsideathermalconductor fromboundarymeasurements,whicharisesfromactivethermographyandisformulated as an inverse boundary value problem for the heat equation. In our previous works, weproposed asampling-type methodfor reconstructingthe boundaryofthe unknown inclusionand gaveitsrigorousmathematical justification.Inthispaper,wecontinueour previous works and provide afurther investigation ofthe reconstruction method from both the theoretical and numerical points of view. First, weanalyze the solvability of the Neumann-to-Dirichlet map gap equationand establish arelation of its solution to the Greenfunctionofan interior transmissionproblemfor the inclusion.Thisnaturally provides away of computingthis Greenfunction from the Neumann-to-Dirichlet map.
Ournewfindingsrevealtheessence ofthereconstruction method.Aconvergenceresult for noisy measurement data is also proved. Second, basedon the heatlayer potential argument,weperformanumericalimplementationofthereconstructionmethodforthe homogeneousinclusioncase.Numericalresultsare presentedtoshowthe efficiencyand stabilityoftheproposedmethod.
©2018ElsevierInc.Allrightsreserved.
1. Introduction
Consider the heat conduction in a two-layered medium (Fig. 1.1). Denote by D0 and D the outer and inner layers, respectively. Set
=D∪D0. Suppose that the thermal conductivities of D0 and D are 1 and k, respectively. We also assumethattheboundaries
∂
D0 and∂
D ofD0 andD,respectively,areofclass C2.Forsimplicityofnotations,throughout thispaperwedenote X×(
0,
T)
and∂
X×(
0,
T)
by XT and(∂
X)
T,respectively,where X isaboundeddomaininR2 and∂
X denotesits boundary.Injecting aheatflux g on∂
oversome timeinterval(
0,
T)
,the temperaturedistribution u inT canbemodeledbythefollowinginitial-boundaryvalueproblem:
⎧ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎨
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎩
(∂
t− ∇ ·
k∇)
u=
0 inDT, (∂
t− )
u=
0 in( \
D)
T,
u|
−−
u|
+=
0 on(∂
D)
T,
k∂
νu|
−− ∂
νu|
+=
0 on(∂
D)
T,
∂
νu=
g on(∂)
T,
u
=
0 att=
0,
(1.1)
*
Correspondingauthor.E-mailaddress:hbwang@seu.edu.cn(H. Wang).
https://doi.org/10.1016/j.jcp.2018.05.008
0021-9991/©2018ElsevierInc.Allrightsreserved.
Fig. 1.1.Configuration of the medium.
where
ν
on∂
D (or∂
)istheunitnormalvectordirectedintotheexteriorof D (or).Herethesubscripts“+”and“−” indicatethetracetakenfromtheexteriorandinteriorofD,respectively.
The abovemodelhasmanyimportantapplications insciencesandengineering. Inactive thermography, D isregarded as an inclusion and D0 is the background medium. In thiscase, the forward problem is to determine the temperature distributionin
T foranyinjectedheatfluxgon
(∂)
T,whiletheinverseproblemistoreconstructtheunknowninclusion D fromboundary measurements. Instead of recovering the thermal conductivity, we are more interested in finding the location,sizeandshapeoftheinclusionasadefectinsidetheconductor.Weprovedin[17] thatforanyg∈H−12,−14((∂)
T)
thereexistsauniquesolutionuto(1.1) in H˜1,12(
T)
.DefinetheNeumann-to-DirichletmapbyD
:
H−12,−14((∂)
T) →
H12,14((∂)
T),
g→
u|
(∂)T,
whichisan idealizedmeasurementdataforactive thermography.Thenourinverseproblemistoreconstruct D from
D, wherekisunknown.Theuniquenessandstabilityestimateareestablishedin[7,8].Asforreconstructionmethods,werefer to[6,9,13–16,21] andthereferencestherein,wherethedynamicalprobemethodandtheenclosuremethodaredeveloped.
Recently, the authors establisheda linear sampling-typemethod fortheheat equation in [12,17,18]. However, numerical studiesofthesereconstructionmethodsforparabolicinverseboundaryvalueproblemsareratherlimited[19].Somerelated worksonotherkindsofparabolicinverseboundaryvalueproblemscanbefoundin[2,3,5,10,11,20].
Inthiswork,basedontheheat layerpotentialtheory,weinvestigateboththeforwardandinverseproblemsfromthe numerical pointofview.Especially, thesampling-typereconstruction methodestablished in[17] for ourinverseproblem will be numerically implemented. Roughly speaking,this reconstruction methodis based on the characterization of the solutiontotheso-calledNeumann-to-Dirichletmapgapequation
(
D−
∅)
g=
G(y,s)(
x,
t),
(1.2)where
∅ is theNeumann-to-Dirichlet map when D= ∅, and G(y,s)
(
x,
t)
:=G(
x,
t;y,
s)
isthe Green function forthe heat operator∂
t−in
T withhomogeneous Neumannboundaryconditionon
(∂ )
T.Intermsofthischaracterization, thenormofthesolutionto(1.2) servesasanindicatorfunctionandtheboundaryofD canbereconstructedapproximately by computingthevaluesoftheindicator functionataset ofsamplingpoints. Althoughthesampling-typereconstruction methodforinversescatteringproblemshasbeenextensivelystudied;see[1] andthereferencestherein,veryfewnumerical resultsforparabolicinverseboundaryvalueproblemsarereported.Werecentlystudiedin[19] thenumericalimplementa- tionofthesamplingmethodforidentifyingunknowncavitiesinthethermalconductor,buttherigidinclusioncasehasnot yetconsidered.In this paper, we continue our previous worksand investigatethe numerical realizationof the samplingmethod for parabolicinverseboundaryvalueproblemswithunknowninclusions.Firstofall,wesupplementthetheoreticalanalysisof ourreconstructionmethodbyanalyzingthesolvabilityoftheequation(1.2) andshowingtherelationofitssolutiontothe Greenfunctionofan associatedinteriortransmissionproblem.Thesenewfindingsrevealtheessence ofthesampling-type reconstruction method. In addition, a convergence resultfor noisy measurement data is proved. Then, we simulate the measurementdata
D bysolvingtheforwardproblem(1.1),andcomputetheNeumann-to-Dirichletmap
∅andtheGreen function G(y,s)
(
x,
t)
by solving the problem(1.1) with D= ∅. Byexpressingthe solutionasa single-layer heat potential, theinitial-boundary valueproblem(1.1) istransformedintoasystemofboundaryintegral equations.Anumericalscheme for solvingthe resultingintegral equationsisintroduced. Finally,we solvethe discretizedNeumann-to-Dirichlet map gap equation usingthe Tikhonov regularizationtechnique. We show the performance ofthe reconstruction method fromthe following twoaspects.1.We testthemethodforinclusionsofdifferentshapesandthermalconductivities.2.We testthe method with shorttime measurements, namely, usingmeasured dataonly in a very short time interval. Our numerical resultsillustratetheefficiencyofthereconstructionmethod.Therestofthispaperisorganizedasfollows.InSection2,werevisitthesampling-typereconstructionmethodandshow some newtheoretical results.InSection 3,weintroduceanumericalschemeforsolvingtheforwardproblemtosimulate themeasurementforourinverseproblem.TwonumericalexamplesareprovidedinSection4.Finally,inSection5,wegive someconcludingremarks.
2. Reconstructionmethodfortheinverseproblem
In this section, we revisit the sampling-type reconstruction method for the heat equation with unknown inclusions studiedin[17],andgiveafurtherinvestigationonthismethodbyshowingsomenewtheoreticalresults.Explicitly,wewill analyzethesolvabilityoftheNeumann-to-Dirichletmap gapequationandexplainwhatisthesolutionifitdoesexist.The relationof its solutionto theGreen function ofa relatedinteriortransmissionproblemis established,which revealsthe essenceofthereconstructionmethod.Fornoisymeasurementdata,aconvergenceresultisalsoproved.
Tobeginwith,letusintroducetheanisotropicSobolevspaces.For p
,
q≥0 wedefineHp,q
(R
2× R) :=
L2(R;
Hp(R
2)) ∩
Hq(R;
L2(R
2)).
Forp
,
q≤0 wedefinethespaceHp,q bydualityHp,q(R
2×R):=H−p,−q
(R
2×R).ByHp,q
(
XT)
wedenotethespaceof restrictionsofelements inHp,q(
R2×R)
to XT.ThespaceHp,q((∂
X)
T)
isdefinedanalogously.Wealsodefinethefunction spacesH
˜
1,12(
XT) :=
u
∈
H1,12(
X× (−∞,
T))
u(
x,
t) =
0 fort<
0,
Hˆ
1,12(
XT) :=
u
∈
H1,12(
X× (
0, +∞ ))
u(
x,
t) =
0 fort>
T,
H˜
1,12(
XT; ∂
t− ∇ · γ ∇) :=
u
∈ ˜
H1,12(
XT) (∂
t− ∇ · γ ∇)
u∈
L2(
XT)
,
where
γ
=1+(
k−1) χ
D,andχ
D isthecharacteristicfunctionofD.Inthispaper,weworkintheaboveSobolevspaces,andsolutionstoinitial-boundaryvalueproblemsshouldbeunder- stoodintheweaksense.Forexample,thesolutionto(1.1) shouldbeinterpretedasfollows.Forgiveng∈H−12,−14
((∂)
T)
, weseeku∈ ˜H1,12(
T;∂
t− ∇ ·γ
∇)
suchthat T 0
γ ∇
u· ∇
v+ ∂
u∂
tvdxdt
=
g,
vforanyv∈ ˆH1,12
(
T)
,where istheDirichlettracemapon(∂)
T and·,·shouldbeunderstoodinthesenseofduality.Forlateruse,wedenoteby
Ga
(
x,
t;
y,
s) :=
⎧ ⎨
⎩
14a
π (
t−
s)
exp− |
x−
y|
2 4a(
t−
s)
,
t>
s,
0
,
t≤
s(2.1)
thefundamentalsolutionoftheheatoperator
∂
t−a,wherea isaconstant.WesometimeswriteitasGa(y,s)
(
x,
t)
. Notethat∅isdefinedby
∅g:=v|(∂)T withv satisfying
⎧ ⎪
⎨
⎪ ⎩
(∂
t− )
v=
0 inT
,
∂
νv=
g on(∂)
T,
v=
0 att=
0.
(2.2)
Definetheoperator
F
:=
D−
∅.
Then our reconstruction scheme is based on the characterization of the solution to the Neumann-to-Dirichlet map gap equation
(
F g)(
x,
t) =
G(y,s)(
x,
t), (
x,
t) ∈ (∂)
T (2.3)forafixedtimes∈
(
0,
T)
andthesamplingpoint y∈. First,weanalyzethesolvabilityof(2.3).
Theorem2.1.Fory∈D ands∈
(
0,
T)
,theequation(2.3)hasasolutionifandonlyiftheinteriortransmissionproblem⎧ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎨
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎩
(∂
t− ∇ ·
k∇ )
w=
0 inDT,
(∂
t− )
v=
0 inDT,
w
−
v=
G(y,s)(
x,
t)
on(∂
D)
T,
k∂
νw− ∂
νv= ∂
νG(y,s)(
x,
t)
on(∂
D)
T,
w
=
0 att=
0,
v
=
0 att=
0(2.4)
issolvablewiththesolutionw andv satisfyingtheequations
(∂
t− ∇ ·γ
∇)
w=0and(∂
t−)
v=0inT,respectively.
Proof. Supposethat g∈H−12,−14
((∂)
T)
isasolutionto(2.3).Letw andv satisfy⎧ ⎪
⎨
⎪ ⎩
(∂
t− ∇ · γ ∇ )
w=
0 inT
,
∂
νw=
g on(∂)
T,
w
=
0 att=
0(2.5)
and
⎧ ⎪
⎨
⎪ ⎩
(∂
t− )
v=
0 inT
,
∂
νv=
g on(∂)
T,
v=
0 att=
0,
(2.6)
respectively.Thenwehave
w
−
v=
Dg−
∅g=
G(y,s) on(∂)
T,
∂
νw− ∂
νv=
0= ∂
νG(y,s) on(∂)
T,
andtherefore
w
−
v=
G(y,s) in( \
D)
T.
Bythecontinuitiesofw andv across
∂
D,wefurtherhavew
|
−−
v|
−=
G(y,s) on(∂
D)
T,
k∂
νw|
−− ∂
νv|
−= ∂
νG(y,s) on(∂
D)
T.
Totally,wehavetheinteriortransmissionproblem(2.4).
Conversely,assumethat
(
w,
v)
isasolutionto(2.4) andsatisfiestheequations(∂
t− ∇ ·γ
∇)
w=0 and(∂
t−)
v=0 inT,respectively.Bythecontinuitiesofwandv across
∂
D,weobtainfromthetransmissionconditionsin(2.4) thatw
|
+−
v|
+=
G(y,s) on(∂
D)
T,
∂
νw|
+− ∂
νv|
+= ∂
νG(y,s) on(∂
D)
T.
Noticethat w−vsatisfiestheheatequation
(∂
t−)(
w−v)
=0 in(
\D)
T.Thenitfollowsfromtheuniquecontinuation principlethatw
−
v=
G(y,s) in( \
D)
T,
(2.7)andhence
w
−
v=
G(y,s), ∂
ν(
w−
v) = ∂
νG(y,s) on(∂)
T.
(2.8) Thisimpliesthat∂
νw=∂
νv on(∂)
T andg:=∂
νvisthesolutionto(2.3).Theproofisnowcomplete. 2ThistheoremanalyzesthesolvabilityoftheNeumann-to-Dirichletmapgapequation(2.3). Furthermore,ifitdoesexist asolution,weexplainwhatisthesolutioninthefollowingtheorem.
Theorem2.2.Ifg isthesolutionto(2.3),weletv bethesolutionto(2.6)withtheboundarydata
∂
νv|(∂)T =g.Thenwecanconclude thatv
=
GD(y,s)(
x,
t) −
G(y,s)(
x,
t)
inDT,
(2.9)whereGD(y,s)
(
x,
t)
isdefinedby⎧ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎨
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎩
(∂
t− ∇ ·
k∇ )
H(Dy,s)=
0 inDT, (∂
t− )
G(Dy,s)= δ(
x−
y) δ(
t−
s)
inDT,
H(Dy,s)−
G(Dy,s)=
0 on(∂
D)
T,
k∂
νH(Dy,s)− ∂
νG(Dy,s)=
0 on(∂
D)
T,
H(Dy,s)=
0 att=
0,
GD(y,s)=
0 att=
0.
(2.10)
Proof. Set
G
˜
D(y,s)(
x,
t) =
G(Dy,s)(
x,
t) −
G1(y,s)(
x,
t),
(2.11) G˜
(y,s)(
x,
t) =
G(y,s)(
x,
t) −
G1(y,s)(
x,
t).
(2.12) Notethat G˜(y,s)(
x,
t)
isthereflectedsolutionofthefundamentalsolutionG1(y,s)(
x,
t)
inT andsatisfies
⎧ ⎪
⎪ ⎪
⎨
⎪ ⎪
⎪ ⎩
(∂
t− )
G˜
(y,s)=
0 inT
,
∂
νG˜
(y,s)= −∂
νG1(y,s)(
x,
t)
on(∂)
T,
G˜
(y,s)=
0 att=
0.
Weobservefrom(2.10) that
⎧ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎨
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎩
(∂
t− ∇ ·
k∇)
H(Dy,s)=
0 inDT, (∂
t− )
G˜
(Dy,s)=
0 inDT,
H(Dy,s)− ˜
G(Dy,s)=
G1(y,s)(
x,
t)
on(∂
D)
T,
k∂
νH(Dy,s)− ∂
νG˜
(Dy,s)= ∂
νG1(y,s)(
x,
t)
on(∂
D)
T,
H(Dy,s)=
0 att=
0,
G˜
D(y,s)=
0 att=
0.
Letwandv bethesolutionsto(2.5) and(2.6) withthesameboundarydata
∂
νv|(∂)T=g,respectively.Thenwehave⎧ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎨
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎪ ⎪
⎩
(∂
t− ∇ ·
k∇ )(
w−
H(Dy,s)) =
0 inDT, (∂
t− )(
v− ˜
GD(y,s)+ ˜
G(y,s)) =
0 inDT, (
w−
H(Dy,s)) − (
v− ˜
G(Dy,s)+ ˜
G(y,s)) =
0 on(∂
D)
T,
k∂
ν(
w−
HD(y,s)) − ∂
ν(
v− ˜
G(Dy,s)+ ˜
G(y,s)) =
0 on(∂
D)
T,
w−
H(Dy,s)=
0 att=
0,
v− ˜
G(Dy,s)+ ˜
G(y,s)=
0 att=
0.
(2.13)
Theuniquenessofsolutionstotheinteriortransmissionproblem(2.4) saysthat v
= ˜
GD(y,s)(
x,
t) − ˜
G(y,s)(
x,
t)
inDT,
whichgives(2.9) andcompletestheproof. 2
Here we wouldliketo emphasizethat the reflectedsolution G˜(y,s)
(
x,
t)
andthe Greenfunction G(y,s)(
x,
t)
are com- pletelydeterminedbythedomain.Sotheyareactuallyknowninourinverseproblem.Thus,oncewehavethesolution
g to(2.3),wesolvetheinitial-boundaryvalueproblem(2.6) withtheboundarydata
∂
νv=g on(∂)
T andthenobtainthe Greenfunction GD(y,s)(
x,
t)
=v+G(y,s)(
x,
t)
.Inthissense,ourreconstructionmethodinprincipleprovidesawayofcom- putingtheGreenfunctionG(Dy,s)(
x,
t)
fortheinteriortransmissionproblem(2.4) fromtheNeumann-to-DirichletmapD.
For y∈
\D,wehaveproventhefollowingresultinourpreviouswork [17]:
Theorem2.3.Fors∈
(
0,
T)
andy∈\D,theequation(2.3)hasnosolution.
AccordingtoTheorems2.2and2.3,wecannotguaranteethe solvability of(2.3).However,wecouldfindanapproxima- tion solutionin some sense thatcharacterizes the boundaryofthe inclusion.The theoretical resultsare obtainedin[17]
andcanbesummarizedasfollows.
Theorem2.4.Lets∈
(
0,
T)
befixed.Wehavethefollowingconclusions:(1)ify∈D,thenforany
ε >
0thereexistsafunctiongy∈H−12,−14((∂)
T)
satisfying F gy−
G(y,s)H12,14((∂)T)
< ε
suchthat
ylim→∂D
gyH−12,−14((∂)T)
= ∞
(2.14)and
ylim→∂D
S gy˜H1,12(DT)
= ∞,
(2.15)wheretheoperatorS isdefinedby
S
:
H−12,−14((∂)
T) → ˜
H1,12(
DT),
gy→
v|
DT,
withv beingthesolutionto(2.2);
(2)ify∈
\D,thenforany
ε , η >
0thereexistsafunctiongy∈H−12,−14((∂)
T)
satisfying F gy−
G(y,s)H12,14((∂)T)
< ε + η
suchthat ηlim→0
gyH−12,−14((∂)T)
= ∞
(2.16)and
ηlim→0
S gy˜H1,12(DT)
= ∞.
(2.17)BasedonTheorem2.4,wedefinetheindicatorfunctionby I
(
y) :=
gyH−12,−14((∂)T)
andreconstructthegeometricinformationon D usingthefollowingalgorithm:
Algorithm2.5.
1. Fixs∈
(
0,
T)
andselectasetof“samplingpoints y”in;
2. Computeanapproximatesolutiontotheequation(2.3) foreachsamplingpoint;
3. Assertthat y∈D ifandonlyifI
(
y)
≤C,wherethecut-offconstantC shouldbechosenproperly.In practice, the measurement data always contain some noise, so the operator F cannot be given exactly andsome regularizationtechniqueisnecessaryinnumericalimplementations.Denoteby Fδ theperturbedoperatorof F with
Fδ−
F≤ δ,
where
δ
is the noise level and · is the operator norm. Using the Tikhonov regularization method, we construct an approximatesolutiontotheperturbedNeumann-to-DirichletmapgapequationFδg
=
G(y,s)by
gαy,δ
:=
α
I+ (
Fδ)
∗Fδ−1 Fδ∗G(y,s)
.
(2.18)Thenwehavethefollowingconvergenceresult:
Theorem2.6.Lety∈D andtheNeumann-to-Dirichletmapgapequation(2.3)haveauniquesolutiongy.Ifwechoosetheregular- izationparameter
α
properlysuchthatα (δ)
→0andα3/2δ(δ)→0asδ
→0,thenitholdsthatgαy,δ
→
gy asδ →
0.
(2.19)Proof. Bydirectcalculations,wehave gαy,δ
−
gy=
α
I+
Fδ∗Fδ
−1−
α
I+
F∗F−1Fδ
∗ G(y,s)+
α
I+
F∗F−1 Fδ∗−
F∗ G(y,s)+
α
I+
F∗F−1F∗
G(y,s)
−
gy.
(2.20)Fromtheestimate
α
I+
Fδ
∗ Fδ −1−
α
I+
F∗F−1≤
2δ
α
3/2,
wehave
α
I+
Fδ∗Fδ
−1−
α
I+
F∗F−1Fδ
∗ G(y,s)≤
Fδ
∗G(y,s)
2
δ
α
3/2.
(2.21)Noticethat
( α
I+
B)
−1≤
1α
holdsforanyself-adjointandpositiveoperatorB inHilbertspace.Thenweobtainthat
α
I+
F∗F−1 Fδ∗−
F∗ G(y,s)≤
G(y,s)δ
α .
(2.22)Inaddition,itfollowsfromstandardregularizationtheorythat
α
I+
F∗F−1F∗
G(y,s)→
gy asα →
0.
Thus,theproofiscompletedbycombiningitwiththeestimates(2.21) and(2.22). 2
Remark2.7.Bythewell-posednessoftheinitial-boundaryvalueproblem(2.2) andtheequality(2.9),wecaneasilydeduce from(2.19) that
S
[
gαy,δ] −
G(Dy,s)
(
x,
t) −
G(y,s)(
x,
t)
˜H1,12(DT)
→
0 asδ →
0,
(2.23)whichleadstotheconvergenceforcomputingtheGreenfunctionGD(y,s)
(
x,
t)
fromtheNeumann-to-DirichletmapD.
3. Numericalschemeforsolvingthedirectproblem
Inthissection,wepresentanumericalschemetosolvetheforwardproblem(1.1) fortwo-dimensionalspatialdomains.
Based on the potential theory for the heat equation, we first reformulate the initial-boundary value problem (1.1) as a systemofboundaryintegral equations,andthenintroducea discretizationschemeforsolvingthissystem.Thisschemeis anextensionofthemethodproposedin[2,3] tothelayeredmediumcase.Ourproblem(1.1) involvestheoperator
∂
t−awitha=1
,
k,sothediscretizationoftheintegraloperatorsforageneralconstanta willbeconsidered.Definethefollowingheatlayerpotentials:
Vai j
[ ϕ ](
x,
t) :=
t 0Si
Ga
(
x,
t;
y,
s) ϕ (
y,
s)
dσ (
y)
ds, (
x,
t) ∈
Sj× (
0,
T),
Nai j
[ ϕ ] (
x,
t) :=
t 0Si
∂
Ga(
x,
t;
y,
s)
∂ ν (
x) ϕ (
y,
s)
dσ (
y)
ds, (
x,
t) ∈
Sj× (
0,
T),
whereGa
(
x,
t;y,
s)
isthefundamentalsolutiondefinedby(2.1).Laterwewilltakei,
j=1,
2 with S1=∂
Dand S2=∂
. Assumethat D isahomogeneous inclusion,that is,kisaconstant.Weexpressthesolutionu to(1.1) bythefollowing single-layerpotentials:u
(
x,
t) =
t 0∂D
Gk
(
x,
t;
y,
s) ϕ
1(
y,
s)
dσ (
y)
ds, (
x,
t) ∈
DT,
(3.1)u
(
x,
t) =
t 0∂D
G1
(
x,
t;
y,
s) ϕ
2(
y,
s)
dσ (
y)
ds+
t 0∂
G1
(
x,
t;
y,
s) ϕ
3(
y,
s)
dσ (
y)
ds, (
x,
t) ∈ ( \
D)
T,
(3.2)where
ϕ
1,ϕ
2andϕ
3 aredensityfunctionstobedetermined.Usingjumprelationsofheatlayerpotentials[4],wecanverify that uexpressedby(3.1) and(3.2) isthesolutionto(1.1) providethatϕ
1,ϕ
2 andϕ
3 satisfyV11k
[ ϕ
1] −
V111[ ϕ
2] −
V211[ ϕ
3] =
0,
(3.3)ϕ
1+
2kNk11[ ϕ
1] + ϕ
2−
2N111[ ϕ
2] −
2N121[ ϕ
3] =
0,
(3.4)2N112
[ ϕ
2] + ϕ
3+
2N122[ ϕ
3] =
2g.
(3.5)Notethat theintegral kernelsofV211 ,N121andN112aresmooth,whilethoseof V11k ,Nk11,V111, N111andN221 aresingularat
(
x,
t)
=(
y,
s)
.Tonumericallysolvetheequations(3.3)-(3.5),wepresentadiscretizationschemeasfollows[2,3].Assumethattheboundaries
∂
D and∂
havetheparametricrepresentations∂
D= {
x1( α ) :
x1( α ) = (
x11( α ),
x12( α )),
0≤ α ≤
2π } ,
∂ = {
x2( α ) :
x2( α ) = (
x21( α ),
x22( α )),
0≤ α ≤
2π } ,
where xi j
(
x)
(i,
j=1,
2) are ofclass C2 and2π
-periodicfunctions. The unitoutward normalvectorson∂
D and∂
are givenbyν
1( α ) = (
x12( α ), −
x11( α ))
|
x1( α ) | , ν
2( α ) = (
x22( α ), −
x21( α ))
|
x2( α ) | .
Set
ϕ
˜1(β,
s)
:=ϕ
1(
x1(β),
s)
,ϕ
˜2(β,
s)
:=ϕ
2(
x1(β),
s)
,ϕ
˜3(β,
s)
:=ϕ
3(
x2(β),
s)
,ri j( α , β)
= |xj( α )
−xi(β)
|.Weapplyacollocationmethodusingpiecewiseconstantinterpolationwithrespecttothetimevariableontheequidis- tantgridtn:=nT
/
N,n=0,
1,
· · ·,
N.Thatis,weapproximatethedensityϕ
˜i(β,
s)
by˜
ϕ
i(β,
s) ≈
N n=1˜
ϕ
i,n(β)
n(
s),
where
ϕ
˜i,n(β)
:= ˜ϕ
i(β,
tn)
,i=1,
2,
3 andn
(
s) :=
1,
tn−1<
s≤
tn,
0,
otherwise.
Take
Ki ja,p
( α , β) :=
⎧ ⎪
⎪ ⎨
⎪ ⎪
⎩
1 4πaE1
Nri j2(α, β) 4aT,
p=
0,
1 4πaE1
Nr2i j(α, β) 4aT(p+1)−
4π1aE1 Nr2i j(α, β) 4aT p,
p=
1, · · · ,
N−
1,
(3.6)