A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
S HIGERU S AKAGUCHI
Critical points of solutions to the obstacle problem in the plane
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 21, n
o2 (1994), p. 157-173
<http://www.numdam.org/item?id=ASNSP_1994_4_21_2_157_0>
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Obstacle Problem
inthe Plane
SHIGERU SAKAGUCHI
1. - Introduction
In
[1] ]
Alessandrini considered solutions of the Dirichletproblem
for anelliptic equation
without zero-order terms over a boundedsimply
connecteddomain in
JR..2,
and showed that if the set of local maximumpoints
of theboundary
datum consists of N connected components, then the interior criticalpoints
of the solution are finite in number and thefollowing inequality
holdswhere MI, m2,..., mk denote the
respective multiplicities
orthe interior criticalpoints
of the solution. It was shownby
Hartman and Wintner in[3]
that thezeros of the
gradient
of a non-constant solution(critical points)
are isolated and each zero has finiteintegral multiplicity,
if the coefficients of theequation
aresufficiently
smooth(see [1,
p.231]).
Similararguments
and results were used in thetheory
of minimal surfacesby
Schneider in[6].
In this paper we consider solutions of the obstacle
problem
over a boundedsimply
connected domain inV.
Our main purpose is to show that if the number of criticalpoints
of the obtacle is finite and the obstacle hasonly
N localmaximum
points,
then the sameinequality (1.1)
holds for the criticalpoints
of the solution in the noncoincidence set. We note that the
multiplicity
of acritical
point
in the noncoincidence set is well-defined if the solution is not constant near the criticalpoint,
since the solution satisfies anelliptic equation
without zero-order terms in the noncoincidence set.
Precisely,
let S2 be a boundedsimply connected
domain inV
with smoothboundary
an. Consider a function1/;
EC2(S2)
which isnegative
on aQ and haspositive
maximum in SZ. LetPervenuto alla Redazione il 26 Luglio 1991 e in forma definitiva il 20 Giugno 1993.
a =
(a¡, a2)
be a Coo vector field on]R2 satisfying
for some
positive
constantsA, A.
Consider thefollowing
variationalinequality:
Find u E K
satisfying
It is known that there exists a
unique
solution u to(1.3)
and ubelongs
to(see
the book of Kinderlehrer andStampacchia [5]).
Let I be the coincidence setSince 1b
isnegative
on aS2, I is a compact set contained in Q. Note that u satisfies thefollowing:
and
where G is the set of
Lipschitz
continuousfunctions g
over Qsatisfying
(see [5]).
Now our results are the
following:
THEOREM 1.
Suppose
that the numberof
criticalpoints of V)
in{x
E Q :,O(x)
>0)
isfinite. If 1/J
hasonly
N local maximumpoints,
then the numberof
critical
points of
u isfinite. Furthermore,
denoteby
M I, - - - mk themultiplicities
of
the criticalpoints of
u in Then thefollowing inequality
holdsTHEOREM 2.
If 0
hasonly
Nglobal
maximumpoints
and has no othercritical
point
in{x
E Q : >0}
thenequality
holds in(1.9).
Letting
N beequal
to 1, we have:COROLLARY 3.
If 1/;
hasonly
one criticalpoint
then u hasonly
one criticalpoint.
REMARK 4. Kawohl showed in
[4]
that in the case SZ c R~(n ~ 2)
anda(p)
= p, if S2 isstarshaped
withrespect
to theorigin
and x - 0 forx E
S2B{o},
then x - 0 in~B{o}
and u hasonly
one criticalpoint.
However,
forgeneral a(p),
or fornon-starshaped
domainsQ,
similar results are not known. Thetypical
case isa(p) = p (minimal
surfacecase)
with1 + Ipl2
convex domain Q. We note that in this case we can obtain a bound for the
gradient
of the solution and so we canmodify a(p)
to have the condition(1.2) (see [5]).
Since a critical
point
in the noncoincidence set is a saddlepoint
ifthe solution is not constant on some
neighborhood
of thepoint,
we get ageneralization
of Theorem 1 as follows:THEOREM 5.
Suppose
that the numberof
connected componentsof
localmaximum
points of 7p
isequal
to N. Then the numberof
saddlepoints of
u inQB7
isfinite
and the sameinequality (1.9)
holdsfor
these saddlepoints.
In Section 2 we prove Theorem 1 and in Section 3 we prove Theorem 2.
The
proof
of Theorem 5 is similar to that of Theorem 1. Section 4provides
some
examples
of Theorem 2. In Section 5 wegeneralize
the results of the obstacleproblem
for thegeneral
non-constantboundary
data.2. - Proof of Theorem 1
We
begin
with thefollowing
five basic lemmas.LEMMA 2.1. u is not constant over any open subset
of K2BI.
PROOF. Since u = 0 on
aS2, (1.6)
and thestrong
maximumprinciple imply
that u ispositive
in S2.Suppose
that there exists a connected openset w contained in where u is a
positive
constant. Since the theorem of Hartman and Wintnerimplies
theunique
continuation ofsolutions,
it follows from(1.5)
that uequals
the same constant over the connectedcomponent
w ofcontaining
w. Since u = 0 onaU,
then aw c I. Hence Vu = 0 on9(D, since u - 1b
attains a minimum on I. This contradicts theassumption
thatthe number of critical
points of 0
in{x
Ei 12 : >0}
is finite. DLEMMA 2.2. For any t E
(O,max1/;)
we have thefollowing:
0
(1)
The set{2;
E Q;u(x) t} is
connected.(2) Any
connected componentof f x
E Q :u(x)
>t}
issimply
connected.PROOF. Since u = 0 on 8Q and 8Q is
connected, only
one component of~x
E S~ :u(x) tl
reachesSuppose
that there exists another component, say w. Then acv C Q. Since u = t onaw,
it follows from(1.6)
and the maximumprinciple
that u > t in w. This is a contradiction and weget (1).
Let A bea connected
component
of Q :u(x)
>t}
andlet,
be asimple
closedcurve in A.
By
the Jordan curve theorem there exists a bounded domain B with aB = u. Since Q issimply connected, B
is contained in Q.Then,
since u > ton u, the maximum
principle
and(1.6) yield u
> t in B. This shows that B is contained in A,namely
A issimply
connected and we get(2).
DLEMMA 2.3. We have the
following:
(1)
The interior criticalpoints of
u in are isolated.(2)
u has no local maximumpoint
in(3)
u has no local minimumpoint
in Q.PROOF. In view of Lemma
2.1,
we obtain(1)
and(2)
from(1.5)
and theresults of Hartman and Wintner
[3] (see [1,
p.231]). (3)
is a direct consequenceof
(1.6)
and the maximumprinciple.
DLEMMA 2.4.
Any
local maximumpoint of
u in 0. is also a local maximumpoint of 1/;,
and the numberof
the local maximumpoints of
u in K2 is at most N.PROOF. Since u = 0 on aS2,
by
Lemma2.3(2)
any local maximumpoint
of u
belongs
to I.Then,
in 0. and u= 1b
on I, any local maximumpoint
of u is also a local maximumpoint
of0. Since 0
hasonly
N localmaximum
points,
we get this lemma. DLEMMA 2.5. Let xo E
K2BI
be an interior criticalpoint of
u in92BI,
andlet m be its
multiplicity.
Then m + 1 distinct connected componentsof
the level ’set
~x u(x)
> cluster round thepoint
xo.PROOF.
By
the results of Hartman and Wintner[3],
in aneighborhood
of xothe level line
~x
e Q :u(x)
= consists of m + Isimple
arcsintersecting
atxo
(see [1,
p.231]).
Since anycomponent
of the level setu(x)
>cannot surround a
component
of~x u(x) by
Lemma2.2( 1 ),
allthe
components
of{x u(x)
>u(xo)l clustering
round xo have to bedistinct. This
completes
theproof.
0Since any connected component of a level set
~x u(x)
>t}
witht E R contains at least one local maximum
point
of u, Lemma 2.4 and Lemma2.5 suggest to count the number of
disjoint components
of{2:
E Q :u(x)
>t}
by using multiplicities.
The firststep
is thefollowing:
LEMMA 2.6. Let x 1, ... , Xn E
S2BI
be the interior criticalpoints of
uin
0.B1
and let ml, ... mn be theirrespective multiplicities. Suppose
thatu(xi) = ... = u(xn) =
tfor
some t E R, and suppose that all thepoints
xl, ... , xn
together
with the componentsof {x
E SZ :u(x)
>t} clustering
roundthese
points form
a connected set. Then this connected set containsexactly
n
L
m j + 1 connected componentsof
the level set{ x
E=- il :u(x)
>t }.
j=l
PROOF. We prove this
by
induction on the number n of criticalpoints.
When n = 1, the result holds
by
Lemma 2.5. Assume that k > 1 and that if n k then the connected set, which consists of n criticalpoints
and the componentsn
clustering
round thesepoints,
containsexactly L
mj + 1components
of thej=l
level set
{ x
E S2 :u(x)
>t } .
Let n = k + 1. Let A be the set which consists of thepoints together
with therespective components clustering
roundthese
points.
Since A isconnected,
up to arenumbering
we may assume that thepoints
X 1, - - - , Xktogether
with therespective components clustering
roundthese
points
form a connected set, say B.By
Lemma2.2(l)
A cannot surrounda
component
of{x
E S2 :u(x) t}.
Therefore there isonly
onecomponent
of{x
E Q :u(x)
>t}
whoseboundary
contains both Xk+l and x j for some 1j k,
since both A and B are connected.Hence, using
Lemma 2.5 andapplying
the inductiveassumption
to B, we see that A containsexactly
connected
components
of the level set{x
E 0 :u(x)
>t}.
Thiscompletes
theproof.
DUsing
this we obtain:LEMMA 2.7. Let x 1, ... , Xk E
S2BI
be the interior criticalpoints of
u inS2BI
and let ml, ... , mk be theirrespective multiplicities.
Then u has at leastk
L
m j + 1 local maximumpoints
in SZ.j=l
PROOF. In case
= U(Xk)
= t, if thepoints
xl, ... , Xktogether
with the
components
of{x
E S2 :u(x)
>t} clustering
round thesepoints
form q connected sets,by applying
Lemma 2.6 to each set we see that these sets containk
exactly L
mj + q connected components of the level set{ x u(x)
>t } .
j=l k
Therefore,
in this case the level setalways
has at leastL
mj + 1 connectedk j=l
components, and u has at least
L
mj + 1 local maximumpoints
in o.j=l
Hence,
without loss ofgenerality,
we may assume thatwhere
js+ 1 = k
and s > 1. For 1 n s + 1 lethn
be the set of allcomponents
of the opensets {:r u(x)
>( j
=1,...,jn),
and letJ~n
be the subset of those members w of such that either w is acomponent
of{ x u(x)
> or W is acomponent
of{ x u(x)
> forsome 1 i n - 1
satisfying
Note that
Jj, = Ij, . By
thedefinition, Jjn
consists ofdisjoint
components. De-il
note
by I
the number of elements ofJjn’
Let us show that + 1~-=1
by
induction on the number t. When £ = 1, we havealready
shown thisby
ip
Lemma 2.6.
Suppose that
+ 1 for p > 1. Let £ = p + 1.Then, by
j=1
(2.1) {x jp+1, ... ,
C andeach x j (j
=jp+ 1, ... , jp+1 ) belongs
to somew e
Jjp
which is acomponent
of~x
e Q :u(x)
> Let{~+1,...,~,}
be contained in
exactly
q components w 1, ... , wq .Then, counting
the number of components of~x
E Q :u(x)
> in each =1, ... , q)
with thehelp
of Lemma
2.6,
in view of the definition of we obtainTherefore, by
the inductiveassumption
we getThis
completes
theproof.
By
Lemma 2.7 and Lemma 2.4 weget
This shows that the number of interior critical
points
of u inilBI
is finite and theproof
of Theorem 1 iscompleted,
since u has no criticalpoint
on 9Qby
virtue of
Hopf’s boundary point
lemma(see
the book ofGilbarg
andTrudinger [2,
Lemma3.4,
p.34])
and Vu =Vo
on I.3. - Proof of Theorem 2
By
Theorem 1equality
in(1.9)
is trivial in case N = 1. Therefore weconsider the case N > 2. Let PI,..., P N be the
global
maximumpoints
of1/;.
By considering g(x) - max w
in(1.7)
we get(0 )u max 0
in Q.Then,
allK2 92
the
points
pi, ... , pNbelong
to I and are all local maximumpoints
of uby
Lemma 2.4. Since
by
Theorem 1 the criticalpoints
of u are finite in numberand 1/;
has no criticalpoint
in{x
E SZ : >0}
other than pl, ... , pN, theset of all critical
points
of u consists of a finite number of saddlepoints
in92BI
and pi , ... , pN.Therefore, by using
theimplicit
function theorem and the theorem of Hartman and Wintner we obtain thefollowing
aboutproperties
ofthe level curves of u.
LEMMA 3.1. Let 0 t
max 9
andlet 1 be a
connected componentof
Q
the level curve
{x
E Q :u(x)
=t}.
Then we get thefollowing:
(1) If,
does not contain any criticalpoint of
u,then,
is asimple C
1regular
closed curve which surrounds at least one
point of { pl , ... ,
PN}.
(2) If,
contains at least one criticalpoint of
u,then,
is afinite
collectionof simple piecewise Cl regular
closed curves, eachof
which meets theothers
exclusively
at criticalpoints of
u and surrounds at least onepoint of {PI, ... , pN }.
(3) Each,
does not surround any other component.(4)
The numberof
connected componentsof
the level curve{x
E il :u(x)
=t}
is
finite.
PROOF. Proof of
( 1 ):
Since the level curve inquestion
iscompact,
theimplicit
function theoremguarantees that -1
is asimple C
1regular
closed curve.In view of the
simply-connectedness
ofS2, (1.6)
and the maximumprinciple imply that u
is theboundary
of acomponent
of{x
E Q :u(x)
>t}. Hence, by
Lemma
2.4, ,
has to surround at least onepoint
of{ pl , ... , pN } .
Proof of(2):
With the
help
of the theorem of Hartman andWintner,
we can prove thisalong
the line of the
proof
of(1).
Proof of(3):
This is a consequence of the maxi-mum
principle
as in theproof
of(1).
Proof of(4):
This is a direct consequence of(1), (2)
and(3),
since the number of elements of the set{ pl , ... , pN }
is finite.D Since the critical
points
of u are finite in numberand 0
has no criticalpoint
in{x
E Q : >0 1
other than pl, ... , pN, it follows from Lemma2.3(2)
that there exists a small number r > 0 which satisfies the
following:
where each denotes an open ball with radius r centered at pj.
Hence there exists a
sufficiently
small number 6 > 0 such thatVuf0
inx
E Sz :max y -
6u(x) max lb). Therefore,
it follows from Lemma 3.1Q 0
that the set
{x
u(x) =max 1b -
consists of Nsimple C1
Iregular
closedQ curves for any 0 7y d .
Let us show that there exists at least one critical
point
of u inSuppose
that
Vu f 0 in Q(I.
ThenVu f 0 in
u2
sinceVu f 0
on
by
virtue ofHopf’s boundary point
lemma.Therefore,
with thehelp
of the
implicit
functiontheorem,
we see that{x
e Q :u(x) - max y - 61
_ Q _
is
C1-diffeomorphic
to{x E S2 :
u(x) -0}). Indeed,
letrs - {x
u(x) =
s 1. } By
Y Lemma3.1,
for 0 s F, consists of a finiten
y-
2
number of
simple C
1regular
closed curves, each of which does not surround any other one. Furthermore the interior domain surroundedby
rs is the level set{x
e Q :u(x)
>s}.
Since the interior normal derivative of u with respect to this domain ispositive
on F,, with thehelp
of theimplicit
function theorem we see that for any 0 " smax 0 - 1 6
there exists a small numbers > 0 suchn
~’
2
that
rt
isC 1-diffeomorphic
tors
for all s - ~ t s + e.Also,
forro
there exists a small number eo > 0 such thatrt
isC1-diffeomorphic
toro(= aSZ)
for all 0 t Since the interval
[0, max y Q
06]
iscompact,
we concludethat
rmax
v,-6 isdiffeomorphic
to aK2. This is acontradiction,
since N > 2.Q
Then,
there exists at least one criticalpoint
of u inS2BI.
Let x 1, ... , Xk E
s2BI
be the criticalpoints
of u and let mi,..., be therespective multiplicities.
We may assume that there is no criticalpoint
of u inQ except the
points
x 1, ... , pN.As in the
proof
of Lemma2.7,
we firstconsider
the case = ... =U(Xk) = t
for some t E R.Since
in{x
ES2 : u(x) t},
thenby
thesame arguments as above
{x
ES2 : u(x) = s}
isCl-diffeomorphic
to aS2 for any0 s t.
Therefore, by
thecontinuity,
the level curve{x u(x)
=t}
isconnected.
Indeed,
in view of Lemma3.1(4),
suppose that this level curve hasexactly h
components(h > 2),
say 11,..., ~h. Then the sett}
has
exactly h
components with boundaries 11,..., Ihrespectively.
Put
Bj = { x
E0.; dist(x, Aj) ~ }
for a small number 1/ > 0 and for each 1j
h. Since eachA j
iscompact, by choosing
q > 0sufficiently
small we_ h may assume that
Bi
if Sinceu(x)
t for any x cQB ~J Aj,
j=l _ h there exists a number 6 > 0 such that
u(x)
::; t - ê for all x ES2B ~J Bj.
j=l Consider the level curve
rs(= x u(x - ) s}) })
2 s t.Then,
in view of Lemma 3.1 we see that this level curve rs consists of h
simple C’
regular
closed curves, each of which is contained in =1,..., h).
Thiscontradicts the fact that
F,
isCl-diffeomorphic
to aS2.Hence, by
Lemma 2.6 and Lemma 3.1 the number of connectedk
components of
{ x
Ei K2 :u(x)
>t }
isexactly r mj
+ 1 and eachcomponent
j=l
contains at least one
point
of Of course all thepoints
PI, pN are contained in thesecomponents. Furthermore,
each component containsexactly
onepoint
of{ p 1, ... , Indeed,
suppose that there exists acomponent containing
at least twopoints
of{pl, ... pN},
say w.By
Lemma2.2(2),
we notethat w is
simply
connected.Furthermore, using
the theorem of Hartman andWintner,
we see that there exists a small number - > 0 which satisfies(3.4) {x
E w :u(x)
= t +6*}
is asimple C1 regular
closed curve.Of course we
already
know that(3.5)
{x
E w :u(x)
=max 1b - 61
consists of at least twosimple- (3.5)
C
1regular
closed curves.On the other
hand,
sinceVu f0
in{x
E w : tu(x) max V)I,
12by using
the
implicit
function theorem asabove,
we see that{ x
E w : = t+ 61
isCl-diffeomorphic
to{x
E w :u(x) = m~ax ~ - 8}.
This contradicts(3.4)
andQ
k
(3.5). Consequently,
we getL mj
+ 1 = N.j=l
Consider the
general
case as in theproof
of Lemma 2.7. We use thesame notation as in the
proof
of Lemma 2.7(see (2.1 )).
We want to provek it
that Let us prove that
ljjl
for 1 .~ s + 1j=l j=l
by
induction on the number t. We remark that since any local maximumpoint
of u is aglobal
maximumpoint
of u,by
definitionJjn
consists of components of{ x
E Q :u(x)
>only.
When t = 1, we havealready
shown this as in the case
~(a:i) = ...
=U(Xk) = t
for some t E R.Suppose
ip
that
+ 1 forp >
1. Let £ = p + 1. Then{x jP+1, ... ,
Cj=1
and
each xj (1
=jp + 1,... ,Jp+1) belongs
to some w EJjp
which is acomponent
of{ x
E S2 :u(x)
> Let(zj~+i, ... , zj~~ )
be contained inexactly
qcomponents
~i,...,o~. Ineach Wi (1
iq)
the level curve{x
e Wi :u(x)
= is connected.Indeed,
sinceeach Wi
issimply
connectedby
Lemma2.2(2), using
the theorem of Hartman and Wintner we see that{x
E w2 :u(x)
> is asimple C1 regular
closed curve for small E > 0.Furthermore,
since for{x
E w2 :u(x) by
the sameargument
as in the case~(a:i) = " ’
= = t for some t E R we get the above conclusion.Therefore,
in view of this and Lemma 2.6counting
the number of components of{x
E s2 :u(x)
> ineach Wi (i
=1,... q),
we getk
This shows
that
mj + 1.Finally,
since infX U(Xk)
j=l
u(x) max 01,
0 as in the case = ... =u(zk)
= t for some t e R, we obtaina one-to-one
correspondence
betweenJk
and Therefore we get=
N, whichcompletes
theproof.
D4. - Some
examples
We
give
a fewexamples
in the situation of Theorem 2. The firstexample
shows that there exists a critical
point
with anarbitrarily large multiplicity.
Precisely,
let S2 be a unit open ball inR 2
centered at theorigin.
Considera(p)
definedby a(p)
=b(lpl)p
for some real valuedpositive
functionb(.).
Weintroduce
polar
coordinates(r, 0).
Fix aninteger
m > 1. Put a =27r/(m
+1).
Consider m + 1 balls
Bk (k
=0, 1,..., m)
centered atPk
=(1 /2, ka)
with radiusr > 0. We choose r
sufficiently
small to make these ballspairwise disjoint.
LetSp be a
radially symmetric
smooth function on B ={ x
EI r}
whichsatisfies the
following
conditions:and and
EXAMPLE 1. Consider an
obstacle 1b
E which satisfies thefollowing
conditions:
Then, by symmetry,
theorigin
is a criticalpoint
of the solution u.Furthermore, by
Theorem 2 and thesymmetry
theorigin
is theonly
criticalpoint
of u inS2BI
and themultiplicity
of theorigin
isexactly
m. Here N = m + 1 in Theorem2.
EXAMPLE 2. Consider an
obstacle 1b
EC2(S2) satisfying (4.3)
and thefollowing
conditions:Then, by
symmetry, there exist m + 1 criticalpoints (rl, ka) (k
=0,..., m)
forsome 0 rl
1/2,
and themultiplicity
of eachpoint equals
1. Here N = m + 2in Theorem 2.
EXAMPLE 3. Let
Qj,k = (,~’/3, ka)
inpolar
coordinatesfor j = 1, 2
andk =
0, l, ... ,
m. LetBj,k
be a ball in centered atQj,k
with radius r foreach j and
k. Of course we choose rsufficiently
small. Consider an obstacle1b
E which satisfies thefollowing
conditions:Then, by
symmetry, the set of all criticalpoints
of the solution inK2BI
consistsof the
origin
withmultiplicity
m and m + 1points (r2, ka)
withmultiplicity
1(k
=0,1,..., m)
for some1/3
r22/3.
Here N = 2m + 2 in Theorem 2.5. - Obstacle
problems
forgeneral
non-constantboundary
dataLet
f
EC2 (S2)
be a non-constant function on Fix afunction y
esatisfying o f
on aSZ. Consider the variationalinequality:
Find u
E k satisfying
for all
It is known
that
there exists aunique
solution u to(5 .1 )
and ubelongs
ton Let I be the coincidence set as in
(1.4). Since ’0 f
on 80., I is a compact set contained in S2 or empty.Then, only replacing "g >
0 onby "g > f
on at2" in(1.8),
we get(1.5), (1.6)
and(1.7). By (1.6), (1.7)
and the maximum
principle
we see that min aQf
umax{max
Q0, max
aQf }
inS2. Our results for
general
non-constantboundary
data are thefollowing:
THEOREM 6.
Suppose
that the numberof critical points of 0
in{x
E Q :1b(z)
>finite,
where w EC2 (12)
n theunique
solutionof
theDirichlet
problem
If 0
hasonly
N local maximumpoints
and hasonly
M local maximumpoints,
then the numberof
criticalpoints of
u in SZ isfinite
and thefollowing inequality
holdswhere M 1, - - - , mk are the
multiplicities of
the criticalpoints of
u inSZBI.
THEOREM 7. Assume the
hypotheses of
Theorem 6 and thefollowing:
(1) ~
hasonly
Nglobal
maximumpoints
and has no other criticalpoint
in~x
E Q :O(x)
>w(x)}.
(2) flaQ
hasonly
Mglobal
maximumpoints
and Mglobal
minimumpoints,
and the
tangential
derivativeof f
on ai2 is not zero outof
thesepoints.
Then
equality
holds in(5.2).
REMARK 8. The
assumption (2)
of Theorem 7 is the same as that for theboundary
data in Theorem 3.1 of Alessandrini(see [1,
p.243]). Although
we can prove these theorems almost
along
the same lines as in theproofs
ofTheorem 1 and Theorem
2,
what weadditionally
have to consider is that the solution .may have a local maximumpoint
on theboundary
a~2 and that the level curves of the solution may meet theboundary
an.PROOF OF THEOREM 6. If
{x
E Q : > isempty,
then u = w inQ. Therefore the theorem follows from the result of Alessandrini
[1].
Assumein Q and
that
{x
E S2 : >w(x)}
is not empty. Then it follows from(1.6)
and thecomparison principle
thatu(x)
>w(x)
in Q. Of course I is not empty and I is contained in{x EO.: 1/;(x)
>w(x)}.
We first prove Lemma 2.1.
Suppose
that there exists a connectedcomponent w
of92BI
such that u is constant in w. Then aw is not empty, sincef
is a non-constant function on an. Hence aw n I contains an infinite number ofpoints.
This contradicts theassumption
that the number of criticalpoints of 0
in{x
E S2; > isfinite,
since I C{x
E Q; >This shows Lemma 2.1.
Instead of Lemma 2.2 we have the
following:
LEMMA 2.2*. For any t E
(min
aQf, max{max
Q1/;, max
a~f 1)
we have thefollowing:
(1)
The set{x
E K2;u(x) t}
u connected.(2) Any
connected componentof { x
c K2:u(x)
>t }
issimply
connected.PROOF. It follows from the maximum
principle
and(1.6)
that anycomponent
of{x
E S2 :u(x) t}
has to meet theboundary
Thereforewe get
(1).
Theproof
of(2)
is the same as that of Lemma 2.2. D We get Lemma 2.3by
the sameproof.
Instead of Lemma 2.4 we have thefollowing:
LEMMA 2.4*.
Any
local maximumpoint of
u in Q is also a localmaximum
point of
eitherIlaQ
or1/;,
and the numberof
local maximumpoints of
u in S2is at most N + M.
PROOF.
By
Lemma2.3(2)
any local maximumpoint
of u in SZbelongs
to aQ U I. Let p be a local maximum
point
of u. If pbelongs
to I, then p isa local maximum
point
of0.
If pbelongs
to aQ, then p is a local maximumpoint
off lao. By
theassumptions of 0
andf
we get this lemma. DUsing
Lemma2.2*(1)
instead of Lemma2.2(1)
we get Lemma 2.5 and Lemma 2.6by
the sameproofs.
Instead of Lemma 2.7 we have thefollowing:
LEMMA 2.7*. Let xl, ... , xk E
SZBI
be the interior criticalpoints of
u inQB7
and let ml, ... , mk be theirrespective multiplicities.
Then u has at leastk _
~
mj + 1 local maximumpoints
in S2.j=i
PROOF. Since
in
the situation of Theorem 6 any connected component ofa
level setIx u(x)
>tl
has at least one local maximumpoint
of uin Q
(not
inS2),
the difference between Lemma 2.7 and Lemma 2.7* isonly
concerned with the location of local maximum
points
of u. Therefore theproof
is the same as that of Lemma 2.7. D
By
Lemma 2.7* and Lemma 2.4* weget inequality (5.2).
This shows that the number of the interior criticalpoints
of u inK2BI
is finite and theproof
ofTheorem 6 is
complete,
since Vu = on I. DPROOF OF THEOREM 7. Let pl , ... , pN be the
global
maximumpoints of 0
and let ql,..., qM and zl , ... , ZM berespectively
theglobal
maxi-mum
points
ofIlao
and theglobal
minimumpoints
ofIlao. By considering g(x) -
max1/;(=
maxf )
in(1.7),
weget
umax 0
in Q. Then all thepoints
a an 0
Pi 5..., PN
belong
to I. Thereforeby
Lemma 2.4* the set of all local maximumpoints
of u in 0. consists of thepoints
PI, - - - , pN, ql , ... , qM. On the otherhand,
it follows from(1.6)
and the maximumprinciple
thatmin
anf
u in Q. Hencewe see that min
f
u maxf
inS2BI.
Therefore it follows from(1.5)
andan an
Hopf’s boundary point
lemma that the interior normal derivative of u on ao. ispositive
at zj(j
=1,
...,M)
and it isnegative
atqj (j
=1,
...,M). Consequently, by
theassumption (2)
of Theorem 7 weget
on aS2.Hence, by
Theorem6 and
assumption ( 1 )
the set of all criticalpoints
of u consists of a finite number of saddlepoints
inSZBI
and PI, ... , PN.Therefore, by using
theimplicit
function
theorem,
the theorem of Hartman and Wintner and the maximumprinciple,
instead of Lemma 3.1 we can obtain thefollowing
aboutproperties
of the level curves of u:
LEMMA 3.1 *. Let min
f
t max maxf )
and let I be a connectedan 0 an
component
of
the level curve{x
E Q :u(x)
=t}.
Then we get thefollowing:
(1)
does not contain any criticalpoint of
u, then either ~y is asimple C
1regular
closed curve in 0.surrounding
at least onepoint of lp, ... , pN }
or ~y is a
simple C1 regular
archaving endpoints
on aQ.(2) If
I contains at least one criticalpoint of
u, then ~y is afinite
collectionof
thefollowing
two kindsof
curves(a)
or(b),
eachof
which meets theothers
exclusively
at criticalpoints of
u:(a) simple piecewise Cl regular
closed curves
surrounding
at least onepoint of {Pl
... ,pN }, (b) simple piecewise C1 regular
arcshaving endpoints
on age(3)
Each -1 does not surround any other component.(4)
The numberof
connected componentsof
the level curve{x
E0 : u(x)
=tl
is
finite.
(5) Every endpoint of
arcs as in(1)
and(2)
on aS2belongs
toonly
onearc which has non-zero
angle against
theboundary an,
and the numberof endpoints
isexactly
2M.Since the critical