A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
K UNIHIKO K AJITANI M ASAHIRO M IKAMI
The Cauchy problem for degenerate parabolic equations in Gevrey classes
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 26, n
o2 (1998), p. 383-406
<http://www.numdam.org/item?id=ASNSP_1998_4_26_2_383_0>
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383
The Cauchy Problem for Degenerate Parabolic Equations in Gevrey Classes
KUNIHIKO KAJITANI - MASAHIRO MIKAMI ( 1998).
Abstract. This paper is devoted to the
study
ofparabolic
operators which aredegenerate
at the time variable t = 0. Under theassumptions
associated with the Newton’spolygon
theCauchy problem
for this operator can be solveduniquely
in Sobolev spaces and
Gevrey
spaces.Mathematics
Subject
Classification (1991): 35K30.1. - Introduction
In this paper we
investigate
theCauchy problem
fordegenerate parabolic
operators
associated with Newton’spolygon.
Let us consider thefollowing Cauchy problem
in a band(0, T)
x R’( T
>0)
where
We assume that P is
degenerate
at t =0, namely,
the coefficients(t, x) satisfy
where
or(ja)
are nonnegative integers
andx ) belongs
toC’ ([0, To] ; y (so))
(respectively C~([0, To] ; y~o))).
Denoteby y(s) (respectively y(s))
the set ofPervenuto alla Redazione il 2
maggio
1996 e in forma definitiva il 23luglio
1997.function
a (x )
defined in R’ such that for any A > 0(respectively 3 A
>0)
there isCA
> 0 such thatThere are several papers on the
Cauchy problem
fordegenerate parabolic equations published
in the 1970’s. M.Miyake
in[9]
and K.Igari
in[2]
gave necessary conditions to be
H°°-wellposed
in the case of first order ina’.
K. Shinkai in
[10]
constructed the fundamental solution of theCauchy problem
for a
single operator
ofhigher
order.Recently
S. Gindikin and L. R. Volevich in[1]
treated theequations
with constant coefficientsusing
the method ofNewton’s
polygon.
DEFINITION 1. Let
R~_=[0, oo)
and lett ( P ) _ { ( j , a )
Eb~ a (0, x ) ~ 0}
and
v(P) = {(1
+U(ja)lj, JU11j)
ER 2 (ja)
E-r (P) 1.
Denoteby N(P)
thesmallest convex
polygon
inpossessing following properties:
(i) v(P)
C,
(ii)
if(q, r)
EJRt, (q’, r’)
E and rr’,
then(q, r)
EN(P).
’
N ( P )
is called the Newton’spolygon
associated with P.For a number ro > 0 let
L,.o
be the linepassing through
thepoint Qo
=(0, ro)
which is
tangent
to the Newton’spolygon N ( P) .
Denoteby Q
=ri)
ELro
the vertex of
N(P)
such that and ri > r hold if(1
+ q,r) belongs
toN(P)
andLro
and denoteby Q
1 =( 1
+r 1 ) , ...
andQl
=(1
+ ql,rl),
the vertices ofN(P)
indexed in the clockwise directionbeginning
withQl.
Fori =
1, ... , I -
1 the sidesjoining
the two verticesQi,
1 will be denotedas
ri
and let r = if I > 2 and r =Q
1 if I = 1. It is evident that the choice ofQ
1depends only
ro. Moreover denoteby
I" =Q 1 Q 1 U
r if there isa vertex
Q 1
-( 1
+q 1,
ofN(P) except 61
1 in the lineL ro
and r’ = r ifit is not so.
Property (ii)
of the Newton’spolygon N(P) implies
that the verticesQ
=( 1
+ qi,ri ), i
-1,...,
I mustsatisfy
theinequalities
We shall define the
principal part
of P associated with the Newton’spolygon
N(P).
For each vertexQ i ,
for each vertical sideri
i and for r the union of vertical sidesri
i(i
=1, ... , I - 1)
we definerespectively
We define a
weight
function associated withN ( P )
as follows:DEFINITION 2. The
operator
P is said to ber-parabolic
at t = 0 ifPr
satisfies theinequality
belowfor
x, ~
E Jaen and À E C with 0.We shall introduce the functional spaces in which we consider the
Cauchy problem (1)-(2). For s >
1 denoteby (respectively H(s))
the set of functionsof which element
u(x)
defined in R’ satisfies that E for anyp > 0
(respectively 3 p
>0),
means a Fourier transform of u. Forsake of convenience denote
by
the usual Sobolev space H°° = and = B°° which means the set of functions of which all derivatives arebounded in
In this paper we prove:
THEOREM 3. For a
differential operator
Psatisfying (4)
we assume that1 s
ro
1if ro
> 0 and 1 so s ooif ro -
0(respectively
1s
ro
1(0),
thecoefficients bja(t, x) belong
toCoo([O, To]; y (so)) (respectively COO([O, To]; y(so»)) (To > 0)
and P is r(respectively r’) -parabolic
att = 0. Then there is T > 0
(T To)
suchthat for any
Uj EH(s) (respectively H(s»)
and
f
EC°° ([o, T] ; H(s)) (respectively C°° ([o, T]; H(s»))
there exists aunique
so-lution u E
C°° ([o, T]; H(s)) (respectively C°° ([o, T]; H(s»)) of
theCauchy problem (1)-(2).
This theorem will be
proved
in Section 4.Let
ÀQik, Àrik
andÀrk (k = 1,..., m)
be the zeros withrespect
to Àof
PQi’ Pri
andPr respectively.
Then we caneasily
see that P isr-parabolic
at t = 0 if and
only
if there is 3 > 0 such that all the zeros ofPr satisfy
for t > 0,
andx, ~
E R’~. Theinequalities (11)
hold if andonly
if there is8 > 0 such that the
following inequalities
are verified:for t >
0 andx, ~
E JRn. This fact will beproved
later inProposition
5.REMARK. K.
Kitagawa
in[5], [6]
derived thefollowing
two necessary conditions weaker than theinequalities (12)
and(13)
in order that theCauchy problem (1)-(2)
is wellposed
in(s > 1):
for t > 0
and x, ~
E Moreover M. Mikami in[8] proved
that whenthe coefficients of P are
independent
of the space variable x, thehomogeneous Cauchy problem
for P is wellposed
in H°° under theassumption (12)
and(15)
and the
non-homogeneous Cauchy problem
for P is wellposed
in H°° underthe
assumption (12)
and(13).
NOTATION. We use the
following
notation in this paper:X)
denotes the set of m timescontinuously
differentiable functions of t E I with value in X.2. -
r-parabolic polynomials
In this section our aim is to show
Proposition
4 mentioned later. For the sake of convenienceput
qo= -1,
1 = oo and rl+ 1 = rl. Let ai(i
=0,..., l )
stand for the
slopes
of the sidesQi Qi+1,
i.e.Putting
= we have(I)I"° S
.-- ~(I)1"~
forh >
1 and~
E JRn. Letf
=/(~, ~) = (t
+ andwhere
belongs
toC°° ([0, (0))
and is monotoneincreasing
function. The constantT > 0 is sufficient small and will be determined later.
PROPOSITION 4. Assume that P is r
(respectively r’) -parabolic
at t = 0. Thenthere are co >
0, Mo
» 1(respectively
0Mo
«1 ), ho
» 1 and 0 T « 1 such thatfor 0 t T, x, ~
eJRn, M > Mo (respectively
0M Mo), E ==
r(respectively ~
=r’)
e C(Re ~. > ho (respectively h > ho(M)))
and there is such that
In the
proposition
above we should remark that the constantCijafJ
if inde-pendent
of M.PROPOSITION 5. There are A > 0 and h > 0 such that when t >
A - 11 ~
andI ~ I
~h,
theinequalities ( 11 )
holdif
andonly if
theinequalities ( 12)
and( 13)
areverified.
Proposition
4 andProposition
5 will beproved
after theproof
of Lemma 10.LEMMA 6. Assume that P is
r parabolic
at t = 0. Then there is cl > 0 such thatE JRn,
À E C(Re ~, > hrl) and h >
1.PROOF. It is sufficient to show that there is 6 > 0 such that
for t >
0, x, ~
ERn, ’k
E Ch")
andh >
1. Infact, [§ [ a (~)h/2
if!~! I
~h,
then(21)
holds. Besides(T I
ifReÀ ~
hriand [§ h,
then(21)
also holds. We note that(20)
holds forr’.
aBy simple computation
weget:
LEMMA 7. Let i =
1,..., l, (1 lallj)
EN(P) and A
> 0.1.
fort > 0, x, ~
1.PROOF.
(i) By assumption
it follows that(ii)
In the same way it follows thatWe
investigate
theproperties
of the characteristicpolynomial P (t,
x,À, ~).
First we consider the case
A-1 (~ ) h ~° t
T.PROPOSITION 8. Assume that P is
r parabolic
at t = 0. Then there are co >0,
0 T «1,
0 A « 1 andho
» 1 such that .PROOF.
Decompose
P as follows:It is obvious that the first term
Pr(~.~) satisfy (24).
When(1 ~- ~ ( j a) / j ,
r,
it follows that > 0 andil ( j a ) >
0 for i =1, ... , I
ifql. If t
~A-1 (~)h ~°,
there are three cases as follows:1*
A 1 (~)h ~° ~ t ~ (~)h ~l ~
2* there is
k (2 I)
such that(~ ) h °‘k-1 t _ (~ ) h ~k ,
3*
~(~.
(i)
In the caseIn the case
1 *, 2*’and
3*by
Lemma 7 we haveh-il (ja) (tql (~}~)-’,
and respec-
tively. Putting
To =infi { il ( j a ) ,
> 0 we have(ii)
In the caseBy
the same way of(i)
we haveThus from
(25), (26),
0 A « 1 andho
» 1 we haveAnd from 0 T « 1 we
get
hence we obtain
(24).
We note that
(24)
is valid for r’.PROPOSITION 9. There are > 0 and 0 A « 1 such that
fori, j E Nn, T,x,~
1.PROOF.
Noting
‘ andfrom Lemma 7 we have
Next we consider the case 0
A -1 (~ ~ h ~° .
LEMMA 10. Let 0
A
1.If laljj ::s qo)
+ ro, there isMo
=M(A)
> 0 such thatA-1 (~ ~ h ~~, ~
EJRn,
1., PROOF.
By assumption
andSince ago =
(rl -
+1)
theinequality
belowis
equivalent
tofor
t (~ ~ h° A -1.
Thus we can choose the constantsatisfying
this lemma.Now we shall prove
Proposition
4 andProposition
5.PROOF OF PROPOSITION 4. In the case
A -1 ~~ ~ h ~° t
T we caneasily
see that
(18)
and(19)
holdby (24)
and(27) respectively,
so weonly
prove in the caseA-1 ~~ ~ h ~° . First,
we prove(18)
when 0 tA-1 ~~ ~ h ao .
It is obvious that
satisfy (18).
There isMl
» 1(respec- tively ho (M)
> 0 for M >0)
such thatfor
Ml (respectively ho(M)).
Infact, by
Lemma10, putting
K =
maxjax Ibja(O, x) I
we haveThus
taking Mi = 2MoKco (respectively ho(M) -
whereTO =
inf io ( j a )
>0,
since P isr’-parabolic
at t =0)
we obtain(29), imply-
ing (18)inO~~A-~)~.
Next,
we prove(19)
in0 :::
tA -1 ( ~ ) h ~° .
Here from 0
A-1 ~~ ~ h ~°
we haveBesides
from
ro we haveHence
(19)
isproved
in from(30), (31 )
and(32).
DPROOF OF PROPOSITION 5. First remark that
(§)h $ [§ I 2 ( ~ ) h if [§ I
~ h.(0
A1 ),
then there isi >
1 such that there are threecases as follows:
(i)
1~ t ~ A(~)h ~‘ ~
(ii)
(iii) t > A -1 (~ ) hl .
(i)
In the caseA-1 (~)h ~i-1 t A(~)h ~l :
It follows that
for h >
1. Therefore there exists 0 A « 1 such thatMoreover it is obvious that
We have then from Lemma 7
and then there is A =
A,
> 0 or h =h,
> 0 for any 8 > 0 such thatfor t E
[A-1 (~) h 0" -’, A (~) h "’ ].
We have then from(35)
and(36)
Then,
from(10),
it follows that forsufficiently
small E > 0for
Re h g
0. In the same way it follows thatfor Re h a 0. Thus
for
Re ~, >
0. Hence we see that theinequalities (11)
hold if andonly
if theinequalities (12)
and(13)
are verified whenA -1 (~ ) h ~i -1 t
(ii)
In the caseA-’(~)h":
It is obvious that there is C =
CA
> 0 such thatNote
that (1 - a ,
E rB ri
isequivalent
tothat la 1/ j
qi ) + ri (i.e. I
>0).
In the same way as(i)
we obtain the
following, remarking
thatA t ~~ ~ h‘ A -1:
for any E > 0 and h =
A)
> 0. Thus in the same way as(i)
weget
Hence we see that the
inequalities ( 11 )
hold if andonly
if theinequalities (12)
and
(13)
are verified when~)~ ~ ~ ~ A-1 (~ ) h °~i .
(iii)
In the case t >A -1 (~ ) h ~l :
We
have t > since al
= 0. If( 1-I- a--~ .~"~ ,
erBQI
0and
Then it is obvious that there is C =CA
> 0 such thatThus there exists 0 A « 1 for any 8 > 0 such that
In the same way as
(i)
it follows thatfor
Re h g
0. Thus we see that theinequalities (11)
hold if andonly
if theinequalities (12)
and(13)
are verifiedwhen t > A -1 (~ ) h °~l .
D3. - Construction of
parametrix
Write cr = ao. Let
x (t) belongs
toCoo ([0, oo))
and is monotoneincreasing
function. Letwhere
From
Proposition
4 it followsimmediately
that:PROPOSITION 11. Assume that P is r
(respectively r’) -parabolic
at t =0,
then(respectively
h >ho(M)
and M >0). (Cijaf3
isindependent of M.)
Consider the
Cauchy problem
for theoperator P
instead of theoperator P,
thatis,
Note
that P
= P for 0T /2.
Translate theproblem
above into anotherone
by
thefollowing
reduction. LetRemark that =
M f .
It followsevidently
thatfor j E N,
a E t >0, x , ~
E RI and h > 1.(Ci
andA o
> 0 areindependent
ofa, ~
andh.)
From
[3,
Section6]
and[4, Proposition 2.3]
we haveLEMMA 12. Assume that A
satisfies (49)
anda (x, ~ ) satisfies
thatfor
any A> 0 there are CA > 0, K >
for
a,,8
Ex, ~
E R" and h >1,
wherea’c"
=aa
Thenwith
for j
EN, a, f3
E t >0, x, ~
E and h >1,
wherestand for
thepseudo-differential operators
with theirsymbols respectively.
Inparticular
if 0
M « 1 we can takeCjaf3M
=MCjaf3.
Change
unknown functionu(t, x)
for(46)-(47)
asv(t, x)
=x).
Remarking
thatat u (t, x) = e A (t, D) (at
+At) v (t, x),
we havewhere
Hereafter we shall consider the
following Cauchy problem
instead of(46)-(47):
LEMMA 13. Let
a (a (at, D))
standsfor
thesymbol of
a;a (~,, ~),
then itfol-
lows that
1.
PROOF. We use induction
on j.
The claim is trivialfor j = 1, ... , 4;
assume it is true
for j -
1( j > 5).
LetQj (t, ~, , ~ )
=a«at
+ ThenThus
putting
we have
(58)
and(59) inductively.
From
(53)
we can writewhere
a~~,1 (t, x, ~) -
Here estimateIi, 12
and13
inturn. If
t + ($ )§" > s (0
s »1 ),
thentaking ReÀ ~
hrlwith h > ho
« 1we have
and if t +
($)§" s
s, thenHence
taking 8
=h -8
andchoosing 8
> 0suitably
we can obtainFrom Lemma
7, (28)
and Lemma 12 it follows that if s > 1If s = 1 and 0 M «
1,
Lemma 12implies
In the same way as
I,
Hence
À,~)
satisfiesProposition
11 if we takeMl (respectively ho(M))
since
i~(t, x, X +At, ~)
satisfiesProposition
11. Thus we havePROPOSITION 14. Assume that P is r
(respectively r’) -parabolic
at t =0,
thenfor i, j
EN, a, f3
E0, x, ~
EM > Ml (respectively h > ho(M)
andNow we shall defined a Riemannian metric g as follows:
We use notation in
[7,
Section18.4].
DEFINITION 15. Denote
by S (m , g )
the set of functionsa (t , x , ~, , ~ )
whichis
holomorphic
withrespect
to À inh
I and satisfiesfor i, j e N,
a,~8
E0, x , ~
EJRn, À
Ehl)
andh > h 1,
where
h
1 > 0 andm (t,
x,~,, ~ )
is aweight
function withrespect
to g defined later.(Definition 17).
For
u (t, x)
Eoo)
x defineFourier-Laplace
transformationBesides for
a (t, x, ~,, ~)
ES(m, g)
andu (t, x)
E withsupp[u]
c[0, oo)
definewhere
~
=~/(27r)"
andj~
= Note thatsupp[au]
c[0, oo)
x MBFor z =
(t,
X,~., ~)
ER+
x M" x C x R" denoteDEFINITION 16.
(i)
A functionm(t,
x,k, ~)
is calledslowly varying
withrespect
to g if there are C > 0 and co > 0 such thatfor
(t, x, ~,, ~), (s,
y, T,1J)
ER+
x R’ x C x JRn(Rek,
Re -r >hi)
ifgz(s,
y, T,1J)
co.
(ii)
A functionm(t,
x,k, ~)
is called a -gtemperate
if there are C > 0 andN >
0 such thatDEFINITION 17. A
positive
real-valued functionm (t, x , ~, , ~ )
is called aweight
withrespect to g
if(i)
and(ii)
in Definition 16 are valid.LEMMA 18. There exists
ho >
1 and 8 > 0 such thatit follows that
Hence from
(64)
is verified.LEMMA 19.
= j Then m is a weight with respect
to g,
1(ro
=0)
andh > (ro
>0).
PROOF. First we shall prove that m is
slowly varying
withrespect
to g. As-sume
gz (s,
y, r,1])
Co, then it followsthat s i j com (t, À,~) and 1
Then from~~ ) h / C (~ + r~ ) h C ~~ ) h
we haveHence
m (t -~ s, ), + -r, ~ + q) Cm (t, À, ~),
where C isindependent
of M and h.Besides we have
Hence
m (t, ~,, ~ )/ C m (t
+s, ~,
+r, §
+q),
where C isindependent
of Mand h.
Next we shall show that m is a - g
temperate.
SinceI -r I m (t,
g’ by
Lemma18,
we obtainBy (~ + n)h 5 2(1)h(I
+ andI i7l
sg~
weget
Next we show
In
fact,
since +s) >
T and T fold for t >T,
we can seeT, noting (t
+~)~)~/~, ~(~)
= t and +s )
+ s,we
get
If
cp(t),
we haveand if
cp(t),
holds.
Furthermore,
from the definition of a it followsthat ri
- forV i,
and~(~) ~ M/(~~) ~
holds. Hence we canget
Thus we obtain
where N =
(or + ro) /2, (rl -~ ql ) /2}
and C isindependent
of M and h.Therefore m is a-g
temperate.
DFrom
[3,
Section6]
andPaley-Winner
theorem forFourier-Laplace
trans-formation we have
then
for
N =0, 1, 2, ...
(ii)
Let a ES(1, g).
Thenif u
E withsupp[u]
C[0,00)
x(ii)’ It follows
thatE with C
[0, (0)
x(k
=0,
... ,m).
From
Proposition 14,
Lemma 18 and Lemma 20 weget
REMARK. From Lemma 18 we have
PROPOSITION 22. Let
Then
PA (t,
x,at, Dx)
is one-to-one and ontomapping from
tox,
at, Dx) (k
=0, 1,...,
to
PROOF. From Lemma 20 and
Proposition
21taking
h » 1 and M » 1(respectively
h >h (M)
and M >0),
weget
Thus Newmann series assures the existence of
(I
+R)-1
and(I
+R,)-1
whichmap
continuously
from to Hence( P~ ) -1
=Q (I
+7?)~
mapscontinuously
from toD(PA).
Besides since E=
0, 1, ... ,
mimplies
that mapscontinuously
fromto it follows that
at ( P~ ) -1
=at Q ( I -+- R ) -1
also mapscontinuously
from to
°
D REMARK. If
g(t, x)
e then from(ii)’
in Lemma 20 it followsthat e
(k - 0, 1,..., m ), implying
that 0(~ ==0, 1,... ,~z - 1).
4. - Proof of Theorem 2
First we shall solve the
Cauchy problem (56)-(57).
Letuj(x)
EH(s) (respectively H(s))
andNote that from ro
1 /s
If
v(t, x)
satisfies(56)-(57),
thenw(t, x)
=v(t, x) - vo(t, x)
satisfies below:where
g(t, x)
=x) - PA vo (t, x).
Seek thefunction w(t, x) satisfy-
ing (67)-(68).
Note thatg(t, x)
E Letw(t, x) = (PA)-lg(t, x),
thenw (t, x) belongs
to and satisfies(67)-(68) by Proposition
22 and itsremark. Thus
v (t, x)
is a solution of(56)-(57).
Moreover a solution of
(46)-(47)
isgiven by u (t, x)
=x)
Esatisfying
because of A =Moreover it follows from Remark after
Proposition
22 and from theequation (1)
that for any
positive integer k, n ft
~0})
and conse-quently
u Eoo ) ; H(s)) (respectively oo ) ; H(s))).
Since P = Pfor
T /2, u (t, x)
is a solution of(1)-(2)
inT /2.
Next we shall prove the
uniqueness
of solution for theCauchy problem (56)- (57).
Assume thatThen
v(t, x) = (P~)-lg(t, x) - (I
+x).
Henceby supp[g]
C[T, oo)
x andPaley-Winner
theorem forFourier-Laplace
transformation we see thatsupp [ v ]
c[ T, oo )
xR’~,
thatis, v(t, x)
- 0 for t T. Thereforesince there exists a
unique
solutionv (t, x)
inL~([0, T /2]; L2)
for theCauchy problem (56)-(57),
under theassumptions
in Theorem3,
there exists aunique
solution
u (t , x )
inC- ([0, T /2] ; H(s)) (respectively T / 2] ; H(s)))
for theCauchy problem (1)-(2).
REFERENCES
[1] S. GINDIKIN - L. R. VOLEVICH, "The Method of Newton’s
Polyhedron
in theTheory
of Partial Differential
Equations",
Kluwer Academic Publisher, Dordrecht-Boston-London 1992.[2] K. IGARI, Well-Posedness
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