C OMPOSITIO M ATHEMATICA
H. N IEDERREITER
On the existence of uniformly distributed sequences in compact spaces
Compositio Mathematica, tome 25, n
o1 (1972), p. 93-99
<http://www.numdam.org/item?id=CM_1972__25_1_93_0>
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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
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93
ON THE EXISTENCE OF UNIFORMLY DISTRIBUTED
SEQUENCES
IN COMPACT SPACESby H. Niederreiter
Wolters-Noordhoff Publishing Printed in the Netherlands
The
theory
of uniform distribution of sequences incompact
Hausdorff spaces wasdeveloped by
Hlawka[8 ], [9].
The notion of uniform distrib-utivity
of such sequences is defined relative to agiven nonnegative regular
normed Borel measure y on the space. In many papers on thesubject
matter, thecompact
Hausdorff space wassupposed
tosatisfy
thesecond axiom
of countability. Naturally,
this offersadvantages, especially
when
proving
metric results([2], [8], [11]). Furthermore,
the existenceproblem
foruniformly
distributed sequences in those spaces can beeasily
settled. Infact,
if X is acompact
Hausdorff space with countablebase, then,
in a natural sense, almost all sequences in X areuniformly
distributed with
respect
to the measure03BC([8]). Nevertheless,
a satis-factory theory
of uniform distribution can also bedeveloped
to a certainextent for
arbitrary compact
Hausdorff spaces([2]). But, strangely enough, nobody
seems to have touched the existenceproblem
in thisgeneral setting.
Thestrongest
constructive result still appears to be theone
by
Hedrlin[4] ]
who showed thatuniformly
distributed sequences exist in everycompact
metric space,by using
anexplicit
construction.In this paper, we propose to
study
anarbitrary compact
Hausdorffspace X together
with a(not necessarily regular) nonnegative
normed Borel measure y on X. We characterize all measures y for which there existuniformly
distributed sequences.By using
thegeneral theory
ofweak convergence of measures as
developed by Varadarajan [14] ]
andTopsoe [13],
the methods of thepresent
paperyield
similar results forcompletely regular
spaces withr-smoothprobability
measures.1 have not succeeded to prove a
corresponding
result for well distributed sequences, but at least a metric result can begiven
in this case(see
Theorem
3).
We showthat,
in a natural sense, almost no sequence is well distributed in X withrespect
to aregular
y. This metric theorem wasgiven by Helmberg
and Paalman-de Miranda[6 for compact
Hausdorff spaces with countable base. For such spaces, the existence of well distributed sequences was shownby Baayen
and Hedrlin[1 ].
Nogeneral
existencetheorem for well distributed sequences is
yet
known.94
Let X be a
compact
Hausdorff space. LetM+(X)
be the set of allnonnegative
normed Borel measureson X,
letR(X)
be the set of allsigned regular
Borel measures onX,
and letR+(X) = M+(X)
n-4(X).
We first extend some well-known definitions to our
general
case.DEFINITION 1.
Let y
eM+(X).
A subset M of X is called a9-continuity
set if its
boundary
is ap-null
set.DEFINITION 2.
Let y
EM+(X),
and let co =(xn),
n =1, 2, ...,
be asequence in X. For a subset M of X and a
positive integer N,
we define thecounting function A(M; N; co) by A(M; N; 03C9) = 03A3Nn=1 CM(Xn)
wherecm denotes the characteristic function of M. The sequence
(xn)
is calledM-uniformly
distributed in X ifholds for every
03BC-continuity
set M in X.REMARK.
If 03BC
eR+(X),
then(xn)
is03BC-uniformly
distributed in X if andonly
iflimN~~ 1/N03A3Nn-1f(xn)
=xf d03BC
holds for every real-valued(complex-valued)
continuous functionf
on X. This follows as in Helm-berg [5],
and could also be inferred from the Portmanteau Theorem[13,
p.40].
Although
we do not have a notion ofsupport
fornonregular ,u,
thefollowing
definition is stillmeaningful.
For ageneral concept
ofsupport
see
Topsoe [13,
p.XIII].
DEFINITION 3. The measure
03BC ~ M+(X)
is called a measureof finite
support if there exists a finite subset E of X with
03BC(E)
= 1. LetF(X)
be the set of all measures of finite
support
on X.COROLLARY 1.
If 03BC ~ F (X),
then thereexist , finitely
manypoints
x1, · · ·,
xk in X
such that03BC({xi}) = Ài
> 0for all i,
1~ i ~ k,
and03A3ki=1 Ài
= 1.The points
x1, · · ·, xk areuniquely determined by
J.l, and weput supp 03BC =
{x1, · · ·, xk}.
We have now al1 the
concepts
and theterminology
available toenunciate our main result.
THEOREM 1. Let
03BC ~ M+(X).
There exist03BC-uniformly
distributedsequences in X if and only if there
exists a sequence(03BCj), j
=1, 2, ...,
inF(X)
such thatfor every 03BC-continuity
set M in X.Before we set out to prove this
theorem,
we draw someinteresting
conclusions. First of
all,
let us notethat, by Corollary 1,
every v EF(X)
is a convex linear combination of
point
measures. Inparticular,
everyv ~ F(X)
isregular.
If p eR+(X),
then condition(1) just
means thatthe sequence
(03BCj)
convergesweakly
to p([13,
p.40]).
Furnished with thetopology
of weak convergence,9(X)
is atopological linear
space.We can then reformulate Theorem 1 as follows.
COROLLARY 2. Let
R+(X) satisfy
thefirst
axiomof countability,
and letli
~ R+(X).
There exist03BC-uniformly
distributed sequences in Xif
andonly if
p lies in the closed convex hull in-q(X) of
the setof
normedpoint
measures.
lt is an
important
result in thetheory
of weak convergence inR(X)
that the closed convex hull in
R(X)
of the set ofnormedpoint
measuresis,
infact,
all ofR+(X) ([3,
Ch.III, § 2,
no.4,
Cor.3], [13,
p.48]).
Therefore we
get:
THEOREM 2.
Let R+(X) satisfy
thefirst
axiomof countability.
Thenfor
every 1À~R+ (X)
there existy-uniformly
distributed sequences.REMARK. Theorem 2
generalizes
the result of Hedrlin[4],
since forcompact
metric X thespace R+(X)
is metrizable([14,
Theorem13]).
The basic idea in the
sufhciency part
of theproof
of Theorem 1 is the construction of sequences in X which are’very
well’ distributed withrespect
to themeasures 03BCj
EF(X), j
=1, 2, ’ ’ ’.
Those sequences will allow us toexplicitly
constructy-uniformly
distributed sequences in X.LEMMA 1.
For y
EF(X),
there exists apositive
constantC(03BC)
and asequence co =
(yn) in X
such thatfor
all N ~ 1and for
all subsets Mof X.
Inparticular,
will
do,
where k = card(supp f.l).
PROOF. Let supp p =
{x1, · · ·, xk}.
It will sufhce to show that thereexists a sequence co =
(yn)
in supp y such thatfor
all i,
1 ~i ~ k,
and for allN ~
1. Forthen,
theinequality (2)
can be96
shown as follows. For any subset M of
X,
we haveA(M; N; Q)) = A(M
n supp p;N; 03C9)
and03BC(M) = 03BC(M
n supp03BC),
therefore it sufficesto consider a set M c suppy.
Moreover,
for such a set M we haveA(supp 03BCBM; N; co)
=N-A(M; N; co)
and03BC(supp 03BCBM)
=1- Il(M),
hence we need
only
look at those sets M with card M ~[k/2].
Butthen
and we are done.
To prove
(3),
weproceed by
induction on card(supp Il).
If card(supp 03BC)
=1, then y
is the normedpoint
measure at xl~ X,
and theconstant sequence m =
(Yn) with yn
= xl forall n ~
1 will do. Assum-ing
theproposition
to be true for all v eF(X)
with card(supp v)
=k,
we take
03BC ~ F(X)
with03BC({xi})
=03BBi
> 0 for 1 ~ i ~ k+ 1 and03A3k+1i=1 03BBi
= 1. We define a measure v E5(X)
with supp v ={x1, · · ·
· · ·,
xk}, namely v({xi}) = 03BBi/(03BB1 + · · · +03BBk)
for 1~ i ~
k. There existsa
sequence 03B6 = (Zn)
in supp v withfor all
i,
1~
i~ k,
and all N ~ 1. Now we define the sequence cv =(yn)
in the
following
way: yn = z. if n =[m/(03BB1
+ · · ·+ 03BBk)] for some m ~
1(m
isunique
becauseof 03BB1 + · · · + 03BBk 1),
Yn = xk+1 otherwise.In order to show
(3),
we consider first apoint xi
with 1~
i k. ThenA({xi}; N; cv)
will beequal
to the number ofpositive integers m
such that[m/(03BB1 + · · · +03BBk)] ~
N and z. = Xi’ ThereforeA({xi}; N; 03C9)
=A({xi};
L; 03BE)
where L =[(N+1)(03BB1 + · · · + 03BBk)] - 03B5
and s = 1 or 0according
as(N+ 1)(03BB1
+ · · ·+ 03BBk)
is aninteger
or is not aninteger.
Weget
Discussing
the twopossibilities
for Bseparately,
it followseasily
that theabsolute value
occurring
in the lastexpression
is at most1/N..
It remains to consider the
point
xk + 1. SinceA({xk+1}; N; cv)
= N- Lwhere L is defined as
above,
we haveas above.
As the attentive reader will have
observed,
we did notattempt
to find the bestpossible
value forC(03BC).
The above lemma is of the sametype
asa result
of Meijer [12,
Theorem1 ] who
showed the existenceof ’very
well’distributed sequences in a different
setting.
PROOF oF THEOREM 1.
Suppose
there exists ay-uniformly
distributed sequence W =(xn)
in X.Let a,,,
denote the normedpoint
measure at thepoint
x E X. Then the sequence(03BCj)
inF(X)
definedby Ilj
=1/j Ej= 1
ex.satisfies the condition
(1).
Conversely,
suppose the condition of the theorem is satisfiedby
thesequence
(03BCj)
inF(X).
We want to construct ay-uniformly
distributed sequence in X.By
Lemma1,
foreach 03BCj
there exists apositive
constantC(03BCj)
=Cj
and a sequenceCOi
=(Xjn), n
=1, 2, ···,
such that(2)
holds. For
each j ~ 1,
choose apositive integer rj with rj ~ j(C1
+C2
+...
+ Cj+1).
As a matter ofconvenience, put
ro = 0. We define a se-quence 03C9 =
(xn)
in X in thefollowing
way.Every positive integer n
hasa
unique representation
of the form n= r0 + r1 + ··· + rj-1 + s
withj ~
1 and 0s ~ rj;
we set xn =Xjs’
Take aninteger
N > rl ; N can be written asN = r1 + r2 + ··· +rk + s
with0 s ~ rk+1.
For a Il-continuity
set M inX,
weget A(M; N; cv) = 03A3kj=1 A(M; rj; 03C9j) +
A (M;
s;03C9k+1).
ThereforeIf N ~ oo, then k - oo, and the first term in the above sum tends to zero.
Moreover, by (1)
andby Cauchy’s Theorem,
the second term tends tozero. The
proof
iscomplete.
We shall now prove the metric result for
y-well
distributed sequences98
which we announced above. Since we will suppose 03BC e
R+ (X),
the knowndefinition of
p-well distributivity
in acompact
Hausdorff space, asgiven by Baayen
andHelmberg [2],
can beemployed.
The sequence(xn)
inX is called
03BC-well
distributed in Xif,
for every03BC-continuity
set M inX,
wehave
limN~~ 1/N 03A3Nn=1 cM(xn+h) = /leM) uniformly
in h =0, 1, 2, · · ·.
By
anargument
which was first usedby
Hlawka[10,
Satz2],
we caneasily
infer from this definition thefollowing interesting property
of03BC-well
distributed sequences.LEMMA 2.
If (xn) is 03BC-well
distributed inX,
thenfor
every/l-continuity
set M with
03BC(M)
> 0 there exists apositive integer No
=N0(M)
suchthat at least one
of any No
consecutiveelements from (xn)
lies in M.Let
X 00
be the cartesianproduct
ofcountably
manycopies
ofX,
i.e.X~ = 03A0~i=1 Xi
withXi
= X for alli ~
1. Let /loo be thecompletion
of theproduct
measure onXoo
inducedby
J.l. We note that a sequence(xn)
inX can be viewed as a
point
inX~,
and afamily
of sequences in X can be viewed as a subset ofX 00’
Let M’ stand for thecomplement
of M in X.THEOREM 3. Let
03BC ~ R+(X), and 03BC
not apoint
measure. Then thefamily W of
all03BC-well
distributedsequences in X,
viewed as a subsetof
X~, satifies 03BC~(W) = 0.
PROOF. As in the
proof
of Theorem 2 in[6],
there exists a03BC-continuity
set M in X with 0
03BC(M)
1. ForN ~ 1,
letWN
be thefamily
of all03BC-well
distributed sequences in X for which at least oneof any
N consecu-tive elements lies in M.
By
Lemma2,
we have iY =~~N =1 WN.
Thusit suSices to show that
03BC~(WN)
= 0 for allN ?
1. Forgiven N ~ 1,
letXN
be the cartesianproduct
of Ncopies of X,
and let 03BCN be theproduct
measure on
XN .
DefineFN
to be the setconsisting
of allpoints
ofXN
for which at least one coordinate
belongs
toM,
i.e.FN
=XN "’Df= 1 Mi’
with
Mi
= M for all i. We note that03BCN(FN)
=1-(1-03B1)N,
where03B1 = 03BC(M).
·For k ~ 0, put F(k)N = {(x1, x2, · · ·) ~ X~/(xjN+1, · · ·,
>’ ’ ’ ’ ,
xjN+N)
eFN
for0 ~ j ~ k}.
If follows from the definition ofWN
that
WN ~ ~~k=0 F(k)N.
Now03BC~(F(k)N)
=(1-(1-03B1)N)k+1,
and so 1-(1- ex)N
1implies 03BC~(~~k=0 F(k)N)
= 0.Thus,
afortiori, 03BC~(WN)
= 0.REMARK.
If 03BC
is the normedpoint
measure at somepoint
x0 ~X,
then Theorem 3 is not true. The constant sequence Xo, x o , ’ ’ ’ is
03BC-well
distributed in X and
corresponds
to apoint
inXoo having
03BC~-measureequal
to one.As a
conclusion,
1 would like to pose thefollowing problem
whichwas not settled in this paper. It follows from both the zero-one law of Visser
[15] and
of Hewitt andSavage [7] that
thefamily
of03BC-uniformly
distributed sequences in
X,
viewed as a subset ofX~,
has either 03BC~- measure zero or one, if it is/loo -measurable
at all. Characterize themeasures
03BC ~ M+(X),
or at least those inR+(X),
for which this /loo-measure is
equal
to one!REFERENCES
P. C. BAAYEN AND Z. HEDRLÍN
[1] The existence of well distributed sequences in compact spaces, Indag. Math.
27 (1965), 221-228.
P. C. BAAYEN AND G. HELMBERG
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N. BOURBAKI
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(Oblatum 22-II-1971 ) Department of Mathematics Southern Illinois University Carbondale, Ill. 62901 U.S.A.