C OMPOSITIO M ATHEMATICA
T. A. C HAPMAN
On the structure of Hilbert cube manifolds
Compositio Mathematica, tome 24, n
o3 (1972), p. 329-353
<http://www.numdam.org/item?id=CM_1972__24_3_329_0>
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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
http://www.numdam.org/
329
ON THE STRUCTURE OF HILBERT CUBE MANIFOLDS by
T. A.
Chapman
Wolters-Noordhoff Publishing Printed in the Netherlands
1. Introduction
Let s denote the countable infinite
product
of open intervals and let 100 denote the Hilbertcube,
i.e. the countable infiniteproduct
of closedintervals. A Fréchet
manifold (or F-manifold)
is aseparable
metric spacehaving
an open coverby
sets eachhomeomorphic
to an open subset of s.A Hilbert cube
manifold (or Q-manifold)
is aseparable
metric spacehaving
an open coverby
sets eachhomeomorphic
to an open subset of 100.In
[2] it
is shown that real Hilbert space12
ishomeomorphic
to s andindeed it is known that all
separable
infinite-dimensional Fréchet spacesare
homeomorphic (see [2]
forreferences).
Thus F-manifolds can be viewed asseparable
metric manifolds modeled on anyseparable
infinite-dimensional Fréchet space.
Using
linear spaceapparatus
and a number of earlierresults,
Henderson[9]
has obtainedembedding,
characteri-zation,
andrepresentation
theoremsconcerning
F manifolds(see [10] for generalizations
to manifolds modeled on moregeneral
infinite-dimen- sional linearspaces).
In
[6] a
number of results similar in nature to those of[9] were
obtainedconcerning
certainincomplete, sigma-compact countably
infinite-dimen- sional manifolds. Some results were also established in[6] concerning
the
relationship
of suchincomplete
manifolds toQ-manifolds.
Since thenature of these results is such that a
good
bit of information aboutQ-manifolds
can be obtained from the ’related’incomplete manifolds,
we thus have a device for
attacking Q-manifold problems.
It is the purpose of this paper to use ’related’
incomplete
manifolds toestablish for
Q-manifolds
some more results similar to those of[9].
Welist the main results of this paper in section 2.
Unfortunately
we leaveimportant questions concerning Q-manifolds
unanswered. We call
particular
attention to the paper Hilbert cubemanifolds [Bull.
Amer. Math. Soc. 76(1970), 1326-1330],
in which theauthor
gives
an extensive list of openquestions concerning Q-manifolds.
The author is indebted to R. D. Anderson for
helpful
commentsduring
the
preparation
of this paper.2. Statements of results
A
(topological) polyhedron
is a spacehomeomorphic (~)
to|K|,
where K is a
complex (i.e.
a countablelocally-finite simplicial complex).
Unless otherwise
specified
allpolyhedra
will betopological polyhedra.
West
[15]
has shown that P x s is an F-manifold and P I~ is aQ- manifold,
for anypolyhedron
P.A closed set F in a space X in said to be a Z-set in X
provided
that foreach non-null
homotopically
trivial(i.e.
allhomotopy
groups aretrivial)
open subset U of
X, UBF
is non-null andhomotopically
trivial. We usethe
representation s
=1I£ 1 iio
and 100 =03A0~i= 1 Ii,
where for each i > 0I0i
is the open interval( -1, 1 )
andh
is the closed interval[ -1, 1 ].
In Theorem 1 we show how to
’fatten-up’
apolyhedron
which is aZ-set in a
Q-manifold
to a ’nice’neighborhood
of thepolyhedron.
Thiswill be useful in the
sequel.
THEOREM 1. Let X be a
Q-manifold
and let P be apolyhedron
which isalso a Z-set in X.
If q
EI~B{(0,0,···)},
then there is an openembedding
h : P x
(I~B{q}) ~
X such thath(x, (0, 0, ...))
= x,for
all x ~ P.In
[9]
thefollowing
results are established.(1) Every
F-manifold can be embedded as an open subset ofl2 .
(2)
If X and Y are F-manifoldshaving
the samehomotopy type (i.e.
X -
Y),
then X -- Y.(3)
If X is anyF-manifold,
then there is apolyhedron
P for whichX ~ P l2.
If J is a
simple
closed curve, then Jx 100 is aQ-manifold
which cannotbe embedded as an open subset of I°°.
Also,
100 andI~B{point}
areQ-
manifolds of the same
homotopy type
which are nothomeomorphic.
Thus the obvious
straightforward analogues
of(1)
and(2)
forQ-
manifolds are not valid. Most of the results that follow are concerned with
obtaining partial analogues
of(1), (2),
and(3)
forQ-manifolds.
THEOREM 2. Let X be a
Q-manifold
and let P beany polyhedron
suchthat X - P. Then there is a Z-set F c X such that
XEF éé
P x(I~B {point}).
Each
Q-manifold
is an ANR and it follows from[11]
that eachseparable
metric ANR has thehomotopy type
of somepolyhedron.
Thuseach
Q-manifold
has thehomotopy type
of somepolyhedron.
THEOREM 3. Let X be any
Q-manifold
and let P be anypolyhedron
suchthat X - P. Then X x
[0,1) ~
P x(I~B{point}).
COROLLARY 1.
If X is
anyQ-manifold,
then there is apolyhedron
Psuch that X x
[0, 1) ~
P x I~.COROLLARY 2.
If
X and Y areQ-manifolds
such that X -Y,
thenXx
[0, 1) ~
Yx[0,1).
COROLLARY 3.
If
P and R arepolyhedra
such that P -R,
then P x(I~B{point}) ~
R x(I~B{point}).
In a sense
Corollary
3 isanalogous
to a result of West[15].
It is shownthere that if a
polyhedron
P is aformal deformation
of apolyhedron
R(in
the sense of Whitehead[16]),
then P x 100 ~ R x 100.THEOREM 4.
If
X is aQ-manifold,
then X x[0, 1)
can be embedded as anopen subset
of
100 .COROLLARY 4.
If
X is aQ-manifold,
then X = U uV,
where U and Vare open subsets
of
X which arehomeomorphic
to open subsetsof I~.
If X is any
Q-manifold,
then it is shown in[5] that
X éé Xx 100(and
therefore X ~ X x
[0,
1]).
Thus the above results offer some information about the internal structure ofQ-manifolds.
In
[ 10 ] it
is shown that if X and Y are F-manifoldsand f :
X ~ Y is ahomotopy equivalence,
thenf
ishomotopic
to ahomeomorphism
of Xonto Y. We obtain a
corresponding property
forQ-manifolds
whichstrengthens Corollary
2.THEOREM 5. Let
X,
Y beQ-manifolds
and letf :
X ~ Y be ahomotopy equivalence.
Then there is ahomeomorphism of
X x[0, 1)
onto Y x[0, 1)
which is
homotopic
tof x
id : X x[0, 1)
- Y x[0, 1).
The
following
results are somepartial
answers toquestions concerning compact Q-manifolds.
THEOREM 6. Let X be a compact
Q-manifold
and assume that X -P,
where P is a compact
polyhedron.
Then there is a copy P’of
P in X suchthat P’ is a Z-set in X and
XBP’ ~
P x(I~B{point}).
COROLLARY 5.
If
X is a compacthomotopically
trivialQ-manifold,
thenX ~ I~.
THEOREM 7. Let X be a compact
Q-manifold
and assume that X -P,
where P is a compactpolyhedron.
Then there is anembedding
h : X - 100such that
Bd(h(X)) ~
P I~ andCl(I~Bh(X)) ~
100.In
regard
to Theorem 7 we remark that in[8 ] a similar,
and somewhatstronger,
result is established for F-manifolds.We show that if X is an open subset of
1°°,
then the factor[0,1)
ofCorollary
1 can be omitted.THEOREM 8.
If
X is an open subsetof I~,
then there is apolyhedron
Psuch that X ~ P x 100 .
We remark that the
proof of this
result isquite
different from theproof
of the
corresponding property
for open subsetsof l2 (see [8]).
We also establish a
Schoenflies-type
result forQ-manifolds.
THEOREM 9. Let X and Y be
Q-manifolds
and letf,
g : X ~ Y be closedembeddings
which arehomotopy equivalences
and suchthat f(X), g(X)
arebicollared in Y
(’bicollared’
isdefined
in Section3).
Then the homeomor-phism g~f-1
x id :f(X)
x[0,1)
-g(X)
x[0, 1)
can be extended to ahomeomorphism of
Y x[0, 1)
ontoitself.
We remark that in the case X = Y =
I~,
the factor[0,1 )
can be omittedin the statement of Theorem 9. The
proof
of this followsroutinely
from[17].
The
proof
of Theorem 9applies
togive
us acorresponding
result forF-manifolds.
THEOREM 10. Let X and Y be
F-manifolds
and letf,
g : X - Y be closedembeddings
which arehomotopy equivalences
and suchthat f(X), g(X)
arebicollared in Y. Then the
homeomorphism
gof-l :f(X) ~ g(X)
can beextended to a
homeomorphism of
Y ontoitself.
In case X = Y =
l2 ,
Theorem 10 followsroutinely
from the Schoen-flies result of
[13].
3. Preliminaries
In this section we describe some of the
apparatus
that will be used in thesucceeding
sections.For
spaces X
andY,
a continuousfunction f :
X ~ Y is said to beproper
provided
that the inverseimage
of eachcompact
subset of Y iscompact.
Then a properhomotopy
is ahomotopy
F : X x I ~ Y which is a proper map(we
let I =[0, 1 ]).
For each
integer n
> 0 letW+n = {(xi)~I~|xn= 1}
andW-n =
{(xi) ~ I~|xn = -1}.
We callW+n
andWn
endslices of I~. For eachinteger n
> 0 we let 7rn : I~ ~II n 1 Ii
be the naturalprojection
andput
B(I~)
=I~Bs.
A subset of I~ of the form
H~i=1Ji
is called a basic closed set in I~provided that Ji
is a closed subinterval ofIi
for each i >0, and Ji = Ii
for all but
finitely
many i. Note that any basic closed subset of 100 may be viewed as a Hilbertcube,
with itstopological boundary being
a finiteunion of endslices.
Let X and Y be spaces and
U
be an open cover of Y. Then functionsf, g :
X ~ Y are said to be U-closeprovided
that for each x EX, f(x)
andg(x)
lie in some element of . Afunction f :
Y ~ Y is said to belimited by
03BC
provided
thatf
andidy (the identity
function onY)
are u-close. Afunction
f :
X x I ~ Y is said to be limitedby
uprovided
that for eachx E
X, f({x}
xI )
lies in a member of U.Following
Anderson[1] we
say that a subset M of a metric space X has the compactabsorption
property in X(or
M is a cap-set forX)
if(1)
M =Mn,
where eachMn
is acompact
Z-set in X such thatMn ~ Mn+1,
and(2)
for each a >0,
eachinteger
m >0,
and eachcompact
subset F ofX,
there is aninteger
n > 0 and anembedding
h : F -Mn
suchthat
hlF
nMm
= id andd(h, id)
e.For each
integer
n > 0 let03A3n = [-n(n + 1), n/(n + 1)]
andl =
Un= 1 03A3n.
In[1 ] it
is shown that E andB(I°°)
arecap-sets
for I"0.We will need the
following properties
ofcap-sets
inQ-manifolds.
Allof these can be found in
[6].
We let Xrepresent
aQ-manifold.
LEMMA 3.1.
Cap-sets
exist inQ-manifolds,
and any cap-setfor
X isof
the
form
P x03A3, for
anypolyhedron
Psatisfying
P - X.LEMMA 3.2.
If
M is a cap-setfor
X and F c X is aZ-set,
then M ~ F andMBF
are cap-setsfor
X.LEMMA 3.3.
If
M and N are cap-setsfor
X and u is an open coverof X,
then there is ahomeomorphism of
X ontoitself
which takes M onto N and which is limitedby
u.LEMMA 3.4.
If
M is a cap-setfor
X and F c X is a closed setsatisfying
F n M =
~,
then F is a Z-set in X.LEMMA 3.5.
If
P is apolyhedron,
then P xIn
is a Z-set in P x I.If
Mis a cap-set
for
X and F c M is a Z-set inM,
thenClX(F) (the
c!osureof
F in
X)
is a Z-set in X.LEMMA 3.6.
If M is
acap-set for X,
thenXBM
is anF-manifold satisfying XBM ~
X. Infact,
M ~ X xB(I~),
which is a cap-setfor
X x 100.If
F c
XBM
is a Z-set inXBM,
thenClx(F)
is a Z-set in X.Let X be a space and let u be any open cover of X. Then define
St0(u)
= u and for each n > 0 defineStn(u)
to consist of all sets of the form A ~(~{U
Eul
U nA ~ 0}),
where A EStn -1 (u).
The
following
result on extensionsof homeomorphisms
inQ-manifolds
is established in
[3 ].
LEMMA 3.7. Let X be a
Q-manifold,
u be an open coverof X, Fl
andF2
be Z-sets in
X,
and let h :F1 ~ F2
be ahomeomorphism. If
there is aproper
homotopy
H :Fl
I ~ X such thatHo = id, Hl = h,
and His limited
by
u, then h can be extended to ahomeomorphism of
X ontoitse f which
is limitedby St4(U).
The
following
characterization of Z-sets inQ-manifolds
is established in[6].
LEMMA 3.8. Let X be a
Q-manifold
and let F c X be a closed set. ThenF is a Z-set in X
if and only if
there is ahomeomorphism of
X onto X x I~taking
F intoX {(0, 0, ···)}.
It is shown in
[3]
that for any Z-set F in aQ-manifold X,
there is ahomeomorphism
of X onto X x I~ such that x is taken to(x, (0, 0, ... ),
for all x E F. It is shown in
[7]
that acorresponding property
for F- manifolds is also true.We say that a subset A of a
space X
is bicollaredprovided
that thereexists an open
embedding h:A (-1,1) ~
Xsatisfying h(x, 0)
= x, forall xEA.
Let X be a metric space and A be a closed subset of X. An open cover u of
XBA
is said to be normal with respect to Aprovided
that for each8 >
0,
there is a 03B4 > 0 such that if U E u andd(A, U) b,
thendiam(U)
8. Under these circumstances it is easy to see that anyhomeomorphism
h :XBA ~ XBA
which is limitedby
u has an extensionto a
homeomorphism
À : X - X which satisfiesh|A
= id.4. Proof of Theorem 1
For any
complex K,
we useK(n)
to denote thenth barycentric
subdivision of K and.Kn
to denote the n-skeleton of K. For any subset C of|K|
andintegers
m, n >0,
we letSt(C, K(m)n)
denote the subset ofIKI consisting
of the union of the closed
simplexes
ofK(m)n
which intersectC,
whereK(m)
willalways
mean themth barycentric
subdivision ofKn.
We now
present
a sequence of lemmas that will lead up to aproof
ofTheorem 1. The
proof
wegive
uses an induction on the n-skeletons of atriangulation
of thepolyhedron
P. The fourth lemma we establish is theactual inductive
step,
and the first three are technical results that we need there.LEMMA 4.1. Let K be a
complex,
n > 0 be aninteger,
C be acompact
subsetof IKI
such thatSt(C, Kn+1)
cIKnl,
and let Il =St(|Kn|, K(2)n+1).
Then there is a
homeomorphism
h : L xI~ ~ |Kn| x
100 such thathiC
x 100 =id, h(L x W+1) = |Kn|
xWi ,
andh(x, (0, 0, ...))
=(x, (0, 0, ···)), for
all x ~
|Kn|.
PROOF. Let
Q
=Ii.
It follows from Theorem 4.2 of[15]
thatthere is a
homeomorphism
h’ : L xQ ~ |Kn|
xQ.
Since thecollapse (see
[15] for definitions)
from Lto IKnl
takesplace in |K|BC,
an open setmissing C,
theproof given
thereimmediately implies
that we mayadditionally require
thath’|C Q = id. Although
the conditionh’(x, (0, 0···)) = (x, (0, 0, ···)),
for all x ~|Kn|,
is not mentioned in[15],
it caneasily
be obtained from theapparatus given
there. All onehas to do is follow the
steps
in theproof
of Theorem 4.2 of[15],
cor-recting
at eachstage
of thecollapse
to achieve ourrequired
condition.Now define h : L x
I~ ~ |Kn|
x 100 so thath(x, (x1, x2, ···))
=(y, (x1, y2, y3, ···)),
for all x E L and(x1, x2, ···) ~ I~,
whereh’(x, (x2, x3, ···)) = ( y, (y2, y3, ···)).
Then hobviously
fulfills ourrequirements.
Let
85
b the n-dimensional ball of radius r(0 r ~ 1)
andSr -1
theboundary
of85 .
For convenience we will assume thatLEMMA 4.2. Let X be a
Q-manifold,
F c X be a closed set, and letf : Bn1 ~
X be anembedding
suchthat f(Bn1)
is a Z-setand f(Bn1)
n F cf(Sn-11).
For any r E(0,1)
there is anembedding
h :Bnr
x I~ ~ Xsatisfying
the
following properties.
PROOF. It is clear that there is an
embedding
gl : I~ ~ X and a finite union W of endslices of 100 such thatf((0, 0, ...)) 03B5 g1(I~BW)
andBd(g1(I~))
=g1(W).
Choose s > 0 sothat f(Bn03B5)
cg1(I~BW)
anduse Lemma 3.7 to
get
ahomeomorphism
g2 : X ~ Xsatisfying
g2
~f(Bn03B5) = f(Bn1).
Then(g2 ~g1)-1 ~f(Bn1)
is a Z-set in 100missing
W.Applying
Lemma 3.7 to 100 there is ahomomorphism
g3: I~ ~ 100satisfying g3(W)
= W and g3 ~(g2~g1)-1 0 f(x)
= x, for allx ~ Bnr1,
where r rl 1. Choose m > n and 03B4 e
(0, 1)
such that K n W =0
and K n g3 ~(g2
og1)-1(f(Bn1)~ F)
=Bnr,
whereThen
put
It is obvious that there is a
homeomorphism
g4 :Bnr
xI~ ~ Q satisfying
and
g4(X, (0,0,...))
= x, for all x EBnr.
Then h = g2 o gl~g-13 ~ g4
isour
required embedding.
LEMMA 4.3. Let K be a
complex,
n > 0 be aninteger,
C be acompact
subsetof IKI satisfying St(C, Kn+l)
c|Kn|,
and let L =St (IK K(2)n+1).
Let X be a
Q-manifold
and let h : L x I~ ~ X be a closedembedding
suchthat
Bd(h(LxIoo))
=h(L x wt)
and it is bicollared. Let Fe X be aZ-set such that
where
Bd(L)
is thetopological boundary of L
in|Kn+1|.
Then there existsa
homeomorphism f :
X ~ X such thatPROOF. Let A =
h(L [-1,0] {(0, 0, ···)})
uh(L x Wl-)
which is aZ-set in X, and let B
=h(CxIoo)
uh(L {(0, 0, ···)})
uh(Bd(L)
xI~),
which is closed in X. Let X’ =
XBB, A’ = A
nX’,
and F’ = F n X’.Since A’ and F’ are intersections of Z-sets in X with the open subset X’ of
X,
it follows that A’ and F’ are Z-sets in X’. Now choose an opencover u of X’ which is normal with
respect
to B.Using
Lemma 3.8 there is ahomeomorphism f1: X’ ~
X’ x 100 suchthat f1(A’ ~ F’ )
c X’{(0, 0, ···)}.
We canobviously
obtain a homeo-morphism f2: X’
I~ - X’ x I~ such thatf2 ~f1(F’) ~ f1(A’) =
andf2
is limitedby fl (u).
Thenfl-l o f2 o fl :
X’ - X’ is ahomeomorphism
limited
by
u andsatisfying fj 1
of2
of1(F’)
n A’ =.
From Section 3 it followsthat fl 1 o f2 o fl
extends to ahomeomorphism g :
X ~ X suchthat
glB
= id andg(F)
n A u B ch(Bd(L)
xWi ).
We can use a motion in L x I°° in
only
theIl-direction
and transfer itback to X
by
means of h to obtain ahomeomorphism g1:X ~
X suchthatgllB
=id andgl o g(F) n h(L x [-1,1 2] Ii)= . The problem
is now to move gl
~ g(F)B(h(Bd(L) Wl’)
the rest of the way out ofh(L I~),
with no motiontaking place
on B. BecauseBd(h(L
xI-»
isbicollared,
we caneasily
find ahomeomorphism g2:X ~
Xsatisfying 92 IB
= id and g2 o glo g(F)
nh(L I~)
ch(Bd(L) x W+1).
Thenput
f
= 92 0 91 0 9 tosatisfy
ourrequirements.
We now combine these results to obtain the inductive
step
in theproof
of Theorem 1.
LEMMA 4.4 Let K be a
complex,
let n > 0 be aninteger,
and let C be a compact subsetof |K|
such thatSt(C, Kn+ 1) ~ |Kn|.
Let X be aQ-manifold
and let qJ :
|K|
~ X be anembedding
such thatqJ(lKI)
is a Z-set. Lethn : IKnl
x I~ ~ X be a closedembedding
such thatBd(hn(|Kn|
xI~))
=hn(|Kn|
XWl+)
and it isbicollared, hn(|Kn|
xI"0)
nqJ(IKI)
cqJ(St(/Kn/, K(3))),
andhn(x, (0, 0, ···))
=~(x), for
all x ~/Kn/.
Then there exists aclosed
embedding hn+
1 :/Kn+
1|
I’ - X such thatBd(hn+ 1 (/Kn+ 11
XI~))
=
hn+1(|Kn+1| Wl+)
and it isbicollared, hn+1(|Kn+1| xIoo)
nqJ(IKI)
cqJ(St(IKn+ 1/’ K(3))), hn+
1|C
X I- =hn|
C XI~,
andhn+
1(x, (0, 0, ...) =
~(x), for
allXE |Kn+1|.
PROOF. Let L =
St (IK n+1)
and letBd(L) represent
theboundary
of L
in |Kn+1|.
Let{03C3i}~i=1
be the collection of(n + 1 )-simplexes
of Kand note that
u; = Cl(03C3iBL)
is an(n+1)-cell
contained in the com- binatorial interior of 6i . For each i letBd(03C3’i)
denote the combinatorialboundary
of03C3’i. (We
areassuming
that if i ~j,
thenui 0
uj. If the collection of(n
+1 )-simplexes
of K isfinite,
then theargument
issimilar).
It follows from the
given
conditions that~( 03C3’i)
nhn(|Kn| x I~) = . Using
Lemma 4.2 there is a closedembedding
f :(~i=1 03C3’i)
x I~ ~ Xsuch that the
following properties
are satisfied.and it is bicollared.
For each i let
Int(03C3’i) = 03C3’iBBd(03C3’i)
andput
which is a
Q-manifold containing
as a Z-set.
(This
last assertion easilv follows sinceBd(f((03C3’i)
x7°°))
is
bicollared). Using
Lemma 4.1 there is ahomeomorphism 0 :
L x I~ ~IKnl
I~ such thatO(x, (0, 0, ...))
=x, (0, 0, ...)),
for all XEIKnl,
OIC x 100
=id, and 03B8(L W+1) = |Kn| W+1. Then hn = hn~e:L I
--;X’ is a closed
embedding
such thathn(x, (0, 0, ···))= ~(x),
for allxEIKnl, Bd(hn(L I~)) = hn(L W+1)
and it isbicollared,
andÍÏnlCxIoo =.
Let us consider the two sets
hn(L
x{(0,0, ···)}) ~ fi,,(Bd(L)
xI~)
andf((
1Bd(03C3’i))
xI~) ~ ~(L),
which are Z-sets in X’. Define a homeo-morphism
a of the former onto the latter such that a oÍÏn(x, (0, 0, ···)) =
~(x),
for all x EL,
and a oÍÏn(x, t)
=f(x, t),
for all x ~Bd(L)
and t E I~.Using
the fact that~(x) = ÍÏn(x, (0, 0, ···)),
for all x ~|Kn|,
and thefact
that f(x, (0,0,···)) = ~(x),
for all x ~it
is clear that ais
properly homotopic
to theidentity
in X’. Infact,
there is an open coveru of
X’Bhn(C I~)
which is normal withrespect
tohn(C
xI’)
and forwhich there is a proper
homotopy
satisfying Ho
=id,
and H is limited
by
u.Using
Lemma 3.7 we can extend a to a homeo-morphism
03B1: X’ ~ X’satisfying 03B1|hn(C I~) =
id. Thenis a closed
embedding which
satisfiesBd(03B1
ohn(L
xI~))
= â ohn(L
xWi )
and it is
bicollared,
and
Thus
f : (X
and are closedembeddings
which arecompatible,
i.e. we canpatch
themtogether
toobtain a closed
embedding
which satisfiesBd(h’n+1(|Kn+1 I~)) = h’n+ (|Kn+1 X Wl+), h’n+1|C I~ = ,
and
h’n+1(x, (0,0,...)) = ~(x),
for allXE |Kn+1|.
Of course we have made no
provision
torequire
thatbe
bicollared,
but thispresents
noproblem
sinceis bicollared. It is also true that we
might
not havebut this can be
clearly
achievedby ’squeezing’
Thus we can
modify h’. 1
to obtain ourrequired hn+1.
PROOF OF THEOREM 1.
Write X =
Un
1Xn,
where eachXn
is acompact
set contained in the interiorof Xn+ 1.
Let K be acomplex
and let cp :|K|
~ P be a homeomor-phism.
LetHl
be a finitesubcomplex
of K such that Pn Xl
c9 (j Hl 1)
and choose nl
large enough
so thatOne can
clearly
construct a closedembedding h0 : |K0| I~ ~ X
which satisfies
h0(x, (0, 0, ···)) = ~(x),
forall x e 1 Ko 1,
andand it is bicollared. Then
using
Lemma 4.4 and an obvious inductiveargument
we can obtain a closedembedding hnl : IKnll I~ ~
Xsatisfying hnl(x, (0, 0, ···))
=~(x),
for all x ~|Kn1|,
andand it is bicollared.
Now let
H2
be a finitesubcomplex
of K sothat IHll |
cInt(lH2D
and~(|K|) ~ X2 ~ (p(JH21). Choose n2
> nl such thatUsing
Lemma 4.4 and an inductiveargument
we can find a closed em-bedding hn2 : |Kn2|
I~ ~ X such thathn2(x, (0,0, ...))
=~(x),
for allXE
IKn21, Bd(hn2(|Kn2| x 1(0))
=hn2(|Kn2|
xWl+)
and it isbicollared,
and.
In
general
let{Hi}~i=1
be a collection of finitesubcomplexes
of Kso that for
each i, |Hi|
cInt(|Hi+1|) and ~(|K|) n Xi
c~(|Hi|).
Chooseintegers {ni}~i=1
such that foreach i,
ni ni+1 andUsing
the abovetechniques
we find that for each i > 0 there is a closedembedding hni: |Kni|
x I X such thathni(x, (0, 0, ···)) = ~(x),
forall x ~
IKnil, Bd(hni(|Kni| x I~)) = hni(|Kni| x W+1)
and it isbicollared,
andhni+1||Hi| I~ = hnil|Hi| I~.
For eachx ~ |Hi| (I~BW+1)
define
h’(x)
=hni(x).
It is clear thath’: IKI
x(I~BW+1) ~
X is an openembedding satisfying h’(x, (0,0, ...)) = ~(x),
for allXE |K|.
SinceI~BW+1 ~ I~B{point}
we canclearly modify
h’ to obtain ourrequired
open
embedding
h.5. Proof of Theorem 2
We will first establish two technical results
concerning cap-sets
inQ-manifolds.
These are usedonly
in theproof
of Theorem 2.LEMMA 5.1. Let X be a
Q-manifold,
P bea polyhedron,
~ : P 03A3 ~ X be anembedding
such thatcp(P 03A3)
is a cap-setfor
X and~(P 03A31)
isclosed in
X,
and let F be acompact
Z-set in X. Then there is a homeo-morphism
h : X ~ X such thath(F) c ~(P 03A32)
andh|~(P 03A31)
= id.PROOF.
By
Lemma 3.5. it follows that~(P 03A31)
is a Z-set in X. Let X’ =XB~(P 03A31), F’ = F n X’,
and M =~(P 03A3)B~(P 03A31).
ThenX’ is a
Q-manifold,
F’ is a Z-set inX’,
and M is acap-set
for X’. Choosean open cover u of X’ which is normal with
respect
to~(P 03A31).
Lemma 3.2.
implies
that Mu F’ is acap-set
for X’.Using
Lemma 3.3there is a
homeomorphism f : X’ ~
X’ suchthat f(M w F’ )
= M andf is
limitedby
u. Thenf clearly
extends to ahomeomorphism f:X ~ X satisfying f|~(P 03A31)
= idand l(F)
c~(P 03A3).
Put F* = nI o
cp -1 o l(F),
which is acompact
set in 03A3.Clearly
there isa proper
isotopy gt :
F* ~03A31 ~ 03A3
such thatgo = id, gl (F*)
c03A32
andgt|03A31
= id for all t. Now define anisotopy
for all
(x,y) ~ P 03A3
thatsatisfy ~(x,y)~(F) ~~(P 03A31).
Note thath1((F) ~ ~(P 03A31))
is a Z-set in X andht
is a properisotopy. Using
Lemma 3.7 we can extend
hl
to ahomeomorphism
g : X ~ X. Then h =g~f
fulfills ourrequirements.
LEMMA 5.2. Let X be a
Q-manifold,
P be apolyhedron,
and letcp : P E ~ X be an
embedding
such thatcp(P x 1)
is acap-set for
X andcp(P
x03A32)
is closed in X. Let h : P x I~ ~ X be a closedembedding
so thath(x, (0, 0, ···))
=cp(x, (0, 0, ···)), for
all x eP,
andBd(h(P x I~) = h(P
xWi+).
If F c X is acompact Z-set,
then there is ahomeomorphism
f : X ~ X such
that f(F)
ch(P I~) and f|h(P W-1)
= id.PROOF. Let Let be the
homeomorphism
defined
by 03B8~~(x,y)
=h(x, y),
for all(x, y)
E PxI 2.
It is clear that 0 isproperly homeotopic
to theidentity.
Let qJ 1 be an extension of 0 to ahomeomorphism
of X onto itself. Then~1~~:P 03A3~X is an embedding
such that~1~~(P 03A3)
is acap-set
forX, ~1~~(P 03A31)
=h(P 03A31),
and ~1 0 (p(x, (0, 0, ...)) = h(x, (0, 0, ···)),
for all x E P.It is clear that there exists a
homeomorphism
a :h(P 03A31)
~h(P
xW-1)
such that ce o
h(x, (0, 0, ···))
=h(x, (-1, 0, 0, ···))
for all x EP,
and forwhich a is
properly homotopic
to theidentity,
with thehomotopy taking place
insideh(P
xI~). By choosing
coversappropriately
andusing
Lem-ma 3.7 we can extend a to a
homeomorphism
qJ2 : X ~ X which satisfies~2|XBh(P
xI~)
= id. It is clear now thatip
= qJ2 0 ~1~qJ : P 03A3 ~ X is anembedding
such that(o (P x 1)
is acap-set
for X and~(P 03A32)
isa Z-set in X.
Using
Lemma 5.1 there is ahomeomorphism f :
X ~ X such thatf(F)
c(P 03A32) and f|(P 03A31)
= id. Thisimplies that f|h(P Wl-)
= id. Note that ~1 0
~(P 03A32)
=h(P
x03A32)
andwhich
implies
thatf(F)
ch(P
xI~).
PROOF OF THEOREM 2.
Roughly
the idea of theproof
is to find a copy of P in X which is aZ-set,
use Theorem 1 to build a ’nice’ open set around thispolyhedron,
and use Lemma 5.2 to ’blow
up’
this open set toengulf
acap-set.
Thepart
of X that this open set misses is the Z-set F which we arelooking
for.Using
Lemma 3.1 let~:P 03A3 ~ X
be anembedding
such thatcp(P x 1)
is acap-set
for X. A routineargument
proves that if A is anylocally compact
subset ofX,
thenCl(A)BA
is a closed subset of X.Thus, F1 = Cl(~(P 03A32))B~(P 03A32)
is a closed subset of Xmissing cp(P x 03A3).
It follows from Lemma 3.4 thatFl
is a Z-set in X. Put X’ =XBF1
and note thatcp(P
x1)
is acap-set
for X’. But we now have~(P 03A32)
a Z-set inX’,
because it is closed.Using
Theorem 1 there. is a closedembedding
h : P x I~ ~ X’ such thath(x, (0, 0, ···)) = (p (x, (0, 0, ... )),
for all x ~P,
andWrite
~(P 03A3)
=Mn,
a tower ofcompact
Z-sets.Using
Lemma5.2 there is a
homeomorphism fl :
X’ ~ X’ such thatThen
put
g1 =fl- 1
tocomplete
the firststep
of our construction.Now let X" =
X’Bgl
o h(P [-1, ) Ii),
which isobviously
a
Q-manifold containing
as a Z-set. PutM2 - M2
nX",
which isclearly
acompact
Z-set in X". One canobviously
construct ahomeomorphism
et : X’ ~ X" such thatfor all x E P. Then
~’
= a o gl ~~: P X I - X" is anembedding
suchthat
lfJ’ (P
x03A3)
is acap-set
for X" andfor all XE P. Also gl o h : P x
[1 2, 1 ]
x X" is a closedembedding satisfying Bdx" (gl
oh(P x [1 2, 1] 03A0Ii))
= 91 oh(P x W+1).
Once more
applying
Lemma 5.2 there is ahomeomorphism f2 :
X" ~ X" suchthat f2|g1
oh(P x {1 2} Ii)
= id andThen
let f2
be the extensionof f2
to all of X’ such thatNow
put
g2 =f2 1,
which is ahomeomorphism
of X’ onto itself satis-fying g2|g1 ~ h(P [-1, 1 2] Ii)
= id andIt is then clear that we can obtain a sequence
[gi}~i=1
of homeomor-phisms
of X’ onto itself such thatand
for all n > 1. Then let
g(x)
=limgn
0 ...0g1(x)
for allIt is clear
that g : h(P
x(I)) ~
X’ is an openembedding
such thatg o
h(P x (I~BW+1))
contains~(P 03A3).
Thusis a Z-set in X’ and therefore F =
F, u F2
is a Z-set in X such thatXBF ~
P x(I~BW+1).
6. Proofs of Theorems
3, 4,
5 and their Corollaries Thefollowing
result will be used in theproof of Theorem
3.LEMMA 6.1. Let X be a
Q-manifold
and let F c X be a Z-set. Then(XBF)
x[0, 1) ~
X x[0, 1),
where thehomeomorphism
can be chosen tobe
homotopic
to the inclusionof (XBF)
x[0, 1)
in X x[0, 1).
PROOF. If
Xl
is anyQ-manifold
and C cXl
is anyZ-set,
thenC x
[0,
1] is
a Z-set inXl
x[0, 1 ].
In order to see this let us take a homeo-morphism h 1
ofXl
ontoXl
x 100taking
C intoXl {(0, 0, ···)}.
Thenhl
x id :Xl
x[0, 1 ] ~ X1
x 100 x[0, 1 ] is
ahomeomorphism
which takes C x[o, 1 ] into Xl {(0, 0, ···)}
x[0, 1].
Letbe a
homeomorphism
in which[0,1] ]
is factored back intoXl
Thenh2
o(h1
xid) : Xl
x[0,1 ] ~ X1
x 1°° is ahomeomorphism taking
C x[0,1 ]
into
Xl {(0, 0, ···)},
andby
Lemma 3.8 it follows thatis a Z-set in
Xl
x 100. Thus C x[o, 1 ] is
a Z-set inXl
x[0,1].
Let A =
(X {1})
u(F x [0,1])
and B =(X {1})
u(F x [ 2, 1])
besubsets of X x
[0, 1 ].
Since A and B are Z-sets in X x[o, 1 ]
we can useLemma 3.7 to
get
ahomeomorphism f :
X x[0,
1] -
X x[0, 1 ] satisfying
f(A)
=B and f|X {1}
= id. It follows from[3 ] that
we canadditionally choose f to
beisotopic
toidX [0,1] (with
each level fixed onX {1}).
Therefore
f|X [0, 1) gives
ahomeomorphism
of X x[0, 1)
onto itselfwhich is
homotopic (in
X x[0, 1))
toidX [0, 1).
Let ht : [0,1] ~ [0,1] ]
be ahomotopy
which satisfies thefollowing properties:
(1) ho = id,
(2) h1([1 2, 1]) = {1},
(3) h1|[0, 2 is
ahomeomorphism
of[0, 2 onto [0, 1], (4) ht : [0, 1 ] ~ [0, 1 ]
is ahomeomorphism
for all t ~ 1.Define a continuous
function g :
X x[o, 1 ] -
X x[o, 1 ] as
follows: for each x EX and y
E[0, 1 ], letg(x, y) = (x, ht(y)),
where t =1/(1 + d(x, F)).
Clearly g|(X [0, 1])BB gives
ahomeomorphism
of(X x [0, 1])BB
ontoX x
[0, 1)
which ishomotopic
to the inclusion of(X x [0, 1])BB
inX [0, 1).
Theng~f|(XBF) [0,1) gives
ahomeomorphism
of(XBF) [0, 1)
onto X x[0,1)
which ishomotopic
to the inclusion of(XBF) [0, 1)
in X x[0, 1).
We will also need the