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EQUATIONS UNDER THE RICCI FLOW

YI LI AND XIAORUI ZHU

Abstract. In this paper, we consider first the Li-Yau Harnack estimates for a nonlinear parabolic equationtu= ∆tuquau(lnu)α under the Ricci flow, whereα >0 is a constant. To extend these estimates to a more general situation, in the second part, we consider the gradient estimates for a positive solution of the nonlinear parabolic equationtu= ∆tu+hupon a Riemannian manifold whose metrics evolve under the geometric flowtg(t) =−2Sg(t). To obtain these estimates, we introduce a quantitySalong the flow which mea- sures whether the tensorSij satisfies the second contracted Bianchi identity.

Under conditions on Ricg(t), Sg(t), andS, we obtain the gradient estimates.

1. Introduction

The nonlinear parabolic equation is a classical subject that has been extensively studied, which leads to lots of important results especially in researches of differen- tial geometry. One of the important technique in studying the heat equation is the differential Harnack inequality developed by Li and Yau [8]. This is also applied to Ricci flow by Hamilton [6], and plays an important role in solving the Poincar´e conjecture [12].

1.1. Gradient estimates for (1.2) under the Ricci flow. Consider first pos- itive solutions of a nonlinear parabolic equation on an n-dimensional complete manifold M, which evolves under the Ricci flow. A series of gradient estimates are obtained for such solutions, including several Li-Yau-type inequalities. Let (M, g(t))t∈[0,T] be a complete solution to the Ricci flow

(1.1) ∂tg(t) =−2 Ricg(t), t∈[0, T].

We assume that its Ricci curvature remains uniformly bounded for all t ∈ [0, T].

Consider a positive functionu=u(x, t) defined onM×[0, T] solving the equation (1.2) ∆g(t)−q−∂t

u=au(lnu)α, t∈[0, T],

which has been first studied in [19] whereg(t)≡g is a fixed metric. Qian [13] and Wu [18] got a series of similar conclusions. Here ∆g(t) stands for the Laplacian ofg(x, t) defined onM ×[0, T] and q(x, t) is a C2 function defined on M×[0, T].

Notice that the Laplacian ∆g(t)depends on the parametert, and we should study

2010Mathematics Subject Classification. Primary 53C44.

Key words and phrases. Harnack estimate, Ricci flow, geometric flow.

Yi Li is partially supported by the Fonds National de la Recherche Luxembourg (FNR) unde the OPEN scheme (project GEOMREV O14/7628746). Xiaorui Zhu is partially supported by CPSF (grant) No. 2014M551721 and Zhejiang Province Natural Science Foundation of China (grant) No. Q14A010002.

1

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the nonlinear parabolic equation (1.2) coupled with the Ricci flow (1.1).

We introduce notions used throughout this paper. Let Bρ,T ={(x, t) ∈ M × [0, T] : distg(t)(x, x0)< ρ}, where distg(t)(x, x0) denotes the distance between xto a fixed point x0 with respect to g(t). ∇g(t) and | · |g(t) stand for the Levi-Civita connection and norm with respect tog(t) respectively. For the simplicity, we always omit the subscriptsg(t) ortin the concrete computations.

We divide the study of the equation (1.2) into two cases: (1) α = 1 and (2) α6= 1. For the first case, we have

Theorem 1.1. Suppose that (M, g(t))t∈[0,T] is a complete solution to the Ricci flow (1.1) on ann-dimensional manifoldM withsupBρ,T|Ricg(t)|g(t)≤K for some K >0, and uis a smooth positive function onM ×[0, T] satisfying the nonlinear parabolic equation (1.2) where the functionq(x, t)is defined onM×[0, T] which is C2 in thex-variable and C1 in the t-variable. If u(x, t) ≤A for some A >0 on Bρ,T,α= 1,|∇g(t)q|g(t)≤γ, and

b:=1

8 + min

M×[0,T]q−max{a,0} ∈

0,1 2

then there exists a constantC that depends only onn such that (1.3) |∇g(t)u|g(t)

u ≤ C

b 1

ρ+ 1

√t +√

K+ 1 +√ γ+p

|a| 1 + lnA u

onBρ/2,T with t6= 0.

Whenqis nonnegative anda≤0, the constantC/bcan be a universal constant which means a constant depending only on the dimensionn. The number 1/8 inb is not essential, because in the following proof we shall see that we can replace 1/8 by 1/2.

For the general value ofα, we have the following version of estimates.

Theorem 1.2. Suppose that(M, g(t))t∈[0,T]is a complete solution to the Ricci flow (1.1) on ann-dimensional manifold M with −K1g(t)≤Ricg(t)≤K2g(t)for some K1, K2 > 0 on Bρ,T. If u is a smooth positive function satisfying the nonlinear parabolic equation (1.2), then there exists a constant C depending only on nsuch that, on Bρ/2,T,

(1) fora≥0, we have

|∇g(t)f|2g(t)−βft−βq−βafα ≤ nβ

2c(1−)t+(A+γ)nβ

2c(1−) + n2β3C2 4c2(1−)(β−1)ρ2 + nβ[βK1+a(β−1)α|fα−1|]

c(1−)(β−1) + nβ2aα|α−1||fα−2|

2c(β−1)(1−) +

s

[βθ+ (β−1)γ+2dK2]nβ 2c(1−)

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(2) fora≤0, we have

|∇g(t)f|2g(t)−βft−βq−βafα ≤ nβ

2c(1−)t+(A+γ)nβ

2(1−c) + n2β3C12 4c2(1−)(β−1)ρ2 + nβ[βK1a2(β−1)α|fα−1|]

c(1−)(β−1) +

s

[βθ+ (β−1)γ+2dK2]nβ

2c(1−) .

Here f := lnu, |f| := maxM|f|, K := max{K1, K2}, β > 1, 0 < < 1,

|∇g(t)q|g(t)≤γ,∆g(t)q≤θ, A=C

1 ρ2+

√K1

ρ +1 t +K

andc, d >0 withc+d= 1/β.

1.2. Gradient estimates for (1.4) under the geometric flow. In the sec- ond part, we consider the gradient estimates of (1.2) under a general geomet- ric flow; these results generalize our previous works [9, 21]. More generally, let (M, g(t))t∈[0,T] be a complete solution to the geomtric flow

(1.4) ∂tg(t) =−2Sg(t), t∈[0, T].

on a complete and noncompactn-dimensional manifoldM and consider a positive functionu=u(x, t) defined onM×[0, T] solving the equation

(1.5) ∂tu= ∆g(t)u+hup, t∈[0, T],

where ∆g(t) stands for the Laplacian ofg(t),his a function defined onM ×[0, T] which isC2inxandC1 int, andpis a positive constant. When metrics are fixed, the study on the gradient estimates of (1.5) arose from [7]. If h= 0, Sun [17] de- rived the gradient estimates and the Harnack inequalities for the positive solutions of the linear parabolic equation ∂tu = ∆g(t)u under the geometric flow. In this paper, we consider the general case for the nonlinear parabolic equation. Notice that the ∆g(t)depends on the parametert, and we should study the equation (1.5) coupled with the geometric flow (1.4).

Introduce a 1-formSg(t) onM×[0, T] by Sg(t):= divg(t)Sg(t)−1

2∇g(t) trg(t)Sg(t) .

Locally, one has

Si=∇jSij−1

2∇i trg(t)Sg(t) .

For example, ifSij =Rij, that is, (1.4) is the Ricci flow, we have Si=∇jRij−1

2∇iRg(t)=1

2∇iRg(t)−1

2∇iRg(t)= 0

by the second contracted Bianchi identity. Thus, the quantity Sg(t) measures whetherSij satisfies the second contracted Bianchi identity.

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Theorem 1.3. Suppose that(M, g(t))t∈[0,T]is a solution to the geometric flow (1.4) on M with −K1g(t)≤ Sg(t) ≤K2g(t), −K3g(t) ≤Ricg(t)−Sg(t) ≤K3g(t), and

|Sg(t)|g(t)≤K4 for some K1, K2, K3, K4>0 on B2R,T, with K := max{K1, K2}.

Let h(x, t) be a function defined on M ×[0, T] which is C2 in x and C1 in t, satisfying∆g(t)h≥ −θ and|∇g(t)h|g(t)≤γ onB2R,T×[0, T]for some nonnegative constants θ andγ. Ifu(x, t) is a positive smooth solution of (1.5) on M ×[0, T], then

(i) for0< p <1, we have

|∇g(t)u|2g(t) u2 +h

pup−1−1 p

ut

u ≤ C1

p2t +n(1−p)

p2 M1M2+n[3K1+ 2(K3+K4)p]

2p2(1−p) + C1

p2 1

R2 +

√K1+K3

R +K+ n

p(1−p) (1.6)

+ n

p 3/2

pθM2+

pn/K1

p γM2+ n p2

rK4

2n, whereC1 is a positive constant depending only on nand

M1:= max

B2R,T

h, M2:= max

B2R,T

up−1, h:= max(−h,0).

(ii) forp≥1,we have

|∇g(t)u|2g(t) u2 +h

pup−1−1 p

ut

t ≤ k2C2

p2t +nk2(p−1)

p2 M4M5+ k3n k−pM3M4 + k2C2

p2 1

R2 +

√K1+K3

R +K+ k2n p(k−p)

(1.7)

+ 2k3n (k−p)p2

h K1+p

k(K3+K4)i +k2

nγ p M4

+ kn

p 3/2

pθM4+k2n p2 K+

rK4

2n

! ,

wherek > p,C2 is a positive constant depending only onn and M3:= max

B2R,Th, M4:= max

B2R,Tup−1, M5:= max

B2R,Th.

As an immediate consequence of the above theorem we have

Theorem 1.4. Suppose that (M, g(t))t∈[0,T] is a solution to the geometric flow (1.4) on M. Let h(x, t) be a function defined on M ×[0, T] which is C2in xand C1 int.

(i) For 0 < p < 1, assume that h ≥ 0, |∇g(t)h|g(t) ≤ γ, ∆g(t)h ≥ 0 along the geometric flow with −K1g(t)≤ Sg(t) ≤ K2g(t), −K3g(t) ≤Ricg(t)−Sg(t) ≤ K3g(t), |Sg(t)|g(t) ≤K4 for some positive constants γ, K1, K2, K3, K4 with K :=

max{K1, K2}, along the geometric flow. Ifuis a smooth positive function satisfying

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the nonlinear parabolic equation (1.5), then

|∇g(t)u|2g(t) u2 +h

pup−1−1 p

ut

u ≤ C1

p2t+ C1

p3(1−p)+C1

p2K+ 2nK1

p2(1−p) +

pn/K1

p γM+ n p2

rK4

2n +n(K3+K4) p(1−p) (1.8)

for some positive constantC1 depending only on n, whereM := maxM×[0,T]up−1. (ii) For p = 1, assume that −K1g(t) ≤ Sg(t) ≤K2g(t), −K3g(t) ≤ Ricg(t)− Sg(t) ≤ K3g(t), |Sg(t)|g(t) ≤ K4 for some positive constants K1, K2, K3, K4 with K := max{K1, K2}, h≥0, ∆g(t)h≥ −θ (θ is nonnegative), and |∇g(t)h|g(t) ≤γ (γ is nonnegative), along the geometric flow. If u is a smooth positive function satisfying the nonlinear parabolic equation (1.5), then

(1.9) |∇g(t)u|2g(t)

u2 +h−ut

u ≤ C2

t +C2

1 +K1+K2+K3+K4+K+γ+

√ θ for some positive constantC2 depending only on n.

(iii) For p > 1, assume that −K1g(t)≤ Sg(t) ≤K2g(t), −K3g(t) ≤ Ricg(t)− Sg(t)≤K3g(t),|Sg(t)|g(t)≤K4 for some positive constantsγ, K1, K2, K3, K4 with K := max{K1, K2}. ∆g(t)h ≥ −θ, |∇g(t)h|g(t) ≤ γ, and −k1 ≤ h ≤ k2, where θ, γ, k1, k2>0, along the geometric flow. Ifuis a bounded smooth positive function satisfying the nonlinear parabolic equation (1.5), then

|∇g(t)u|2g(t) u2 +h

pup−1−1 p

ut

u ≤ k

p 2C3

t + k

p 3 k

k−pC3+ k

p 2

C3

K+

+ k

k−p(K1+K3+K4) + rK4

2n

+ k

p 2

n(p−1)k2M + k3n k−pk1M (1.10)

+k2√ n p γM+

kn p

3/2√ θM ,

for some positive constantC3 depending only onn, where M := maxM×[0,T]up−1 andk > p. In particular, takingk= 2p, we get

|∇g(t)u|2g(t) u2 +h

pup−1−1 p

ut

u ≤ C4

t +C5 1 +K1+K2+K3+K4+K +C4p2h

(k1+k2)M +γM+

√ θMi

, (1.11)

for some positive constantC4 depending only on n.

Another type of Harnack inequality is the following

Theorem 1.5. Suppose that(M, g(t))t∈[0,T]is a solution to the geometric flow (1.4) on M, satisfying−K1g(t)≤Sg(t) ≤K2g(t), −K3g(t)≤Ricg(t)−Sg(t) ≤K3g(t),

|∇g(t)Sg(t)|g(t)≤K4, for some K1, K2, K3, K4>0, withK := max{K1, K2}. Let h(x, t)be a nonnegative function defined onM×[0, T]which isC2 inxandC1 in t,∆g(t)h+ht−2Cn,pp|∇g(t)h|

2 g(t)

h ≥0onM×[0, T](whereCn,p=p−1p ifp >1and

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Cn,p=nif p≤1), and0< p≤ 2n−12n (n≥3). If uis a positive solution of (1.5), then

|∇g(t)u|2g(t) u2 +h

pup−1−2 p

ut

u ≤ C

p2t+8n

p2K+8n p2

s 2n p(2−p)K1

+ 4n

p(2−p)(K1+K3+K4) + 1 p2

p8nK4, (1.12)

for some positive constantC depending only onn.

This theorem has three important consequences.

Corollary 1.6. Suppose that (M, g(t))t∈[0,T] is a solution to the geometric flow (1.4) on M, satisfying 0 ≤ Sg(t) ≤ K2g(t), −K3 ≤ Ricg(t)−Sg(t) ≤ K3g(t),

|∇g(t)Sg(t)|g(t) ≤ K4, for some positive constants K2, K3, K4. Let h(x, t) be a nonnegative function defined onM×[0, T]which is C2in xandC1 int,∆g(t)h+ ht−2Cn,pp|∇g(t)h|

2 g(t)

h ≥0 onM ×[0, T](where Cn,p =p−1p if p >1 andCn,p=n if p≤1), and 0< p≤2n−12n (n≥3). If uis a positive solution of (1.5), then (1.13) |∇g(t)u|2g(t)

u2 +h

pup−1−2 p

ut t ≤ C

p2t+8n

p2K2+ 4n

p(2−p)(K3+K4)+ 1 p2

p8nK4 for some positive constantC depending only onn.

Corollary 1.7. Suppose that (M, g(t))t∈[0,T] is a solution to the geometric flow (1.4) on M, satisfying −K1g(t) ≤ Sg(t) ≤ K2g(t), −K3g(t) ≤ Ricg(t)−Sg(t) ≤ K3g(t),|∇g(t)Sg(t)|g(t)≤K4, for someK1, K2, K3, K4>0, withK:= max{K1, K2}.

Leth(x, t)be a nonnegative function defined onM×[0, T]which isC2inxandC1 int,∆g(t)h+ht−2Cn,pp|∇g(t)h|

2 g(t)

h ≥0 onM ×[0, T](where Cn,p= p−1p ifp >1 and Cn,p =n if p≤1), and 0 < p≤ 2n−12n (n≥3). If uis a positive solution of (1.5), then

u(x2, t2) u(x1, t1) ≥

t2 t1

−C/p

exp

"

− 1

2p min

γ∈Θ(x1,t1,x2,t2)

Z t2 t1

|γ(t)|˙ 2g(t)dt−2n(t2−t1) 1

pK+2 p

s 2n

p(2−p)K1+ 1

2−p(K1+K3+K4) +1 p

p2nK4

! # (1.14)

for some positive constant C depending only on n, where (x1, t1),(x2, t2)∈ M × [0, T] witht1< t2.

WhenK1= 0, we have the following

Corollary 1.8. Suppose that (M, g(t))t∈[0,T] is a solution to the geometric flow (1.4) on M, satisfying 0 ≤Sg(t) ≤ K2g(t), −K3g(t) ≤ Ricg(t)−Sg(t) ≤K3g(t),

|∇g(t)Sg(t)|g(t) ≤ K4, for some K2, K3, K4 > 0. Let h(x, t) be a nonnegative function defined on M ×[0, T] which is C2 in x and C1 in t, ∆g(t)h+ht− 2Cn,pp|∇g(t)h|

2 g(t)

h ≥ 0 on M ×[0, T] (where Cn,p = p−1p if p > 1 and Cn,p = n

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if p≤1), and 0< p≤2n−12n (n≥3). If uis a positive solution of (1.5), then u(x2, t2)

u(x1, t1) ≥ t2

t1

−C/p

exp

"

− 1

2p min

γ∈Θ(x1,t1,x2,t2)

Z t2 t1

|γ(t)|˙ 2g(t)dt

−2n(t2−t1) K2

p +K3+K4 2−p +

√2nK4 p

#

for some positive constant C depending only on n, where (x1, t1),(x2, t2)∈ M × [0, T] witht1< t2.

2. Gradient estimates for (1.2) under the Ricci flow

Firstly, we introduce a cut-off function (see [3, 8, 10, 11, 19]) onBρ,T :={(χ, t)∈ M×[0, T] : distg(t)(χ, x0)< ρ}, where distg(t)(χ, x0) stands for the distance between χ and x0 with respect to the metric g(t), which satisfies a basic analytical result stated in the following lemma.

Lemma 2.1. Givenτ ∈(0, T],there exists a smooth functionΨ : [0,∞)×[0, T]→ R satisfying the following requirements:

(1) The support of Ψ(r, t) is a subset of [0, ρ]×[0, T], 0 ≤ Ψ(r, t) ≤ 1 in [0, ρ]×[0, T], andΨ(r, t) = 1 holds in[0,ρ2]×[τ, T].

(2) Ψ is decreasing as a radial function in the spatial variables.

(3) The estimate|∂tΨ| ≤ CτΨ1/2is satisfied on [0,∞)×[0, T] for someC >0.

(4) The inequalities −CραΨα≤∂rΨ≤0 and |∂r2Ψ| ≤ Cρ2αΨα hold on [0,∞)× [0, T] for everya∈(0,1) with some constantCαdependent on a.

Proof. See [1].

These properties are derived from Calabi’s argument(see, e.g., [2, 4, 15]). Using this auxiliary function and applying the maximum principle, we are able to estab- lish Li-Yau-type inequality for the system (1.1) – (1.2).

In the following, we always omit the subscriptsg(t) ortin concrete computations.

For example, we write ∆ instead of ∆g(t).

2.1. Gradient estimates I: α= 1. To prove Theorem 1.1, we need the following crucial lemma.

Lemma 2.2. Let (M, g(t))t∈[0,T] be a complete solution to the Ricci flow (1.1) on an n-dimensional manifold M with supB

ρ,T|Ricg(t)|g(t)≤K for some K >0, anduis a smooth positive function onM×[0, T] satisfying the nonlinear parabolic equation (1.2) with α= 1, a <0. We assume thatu≤1 on Bρ,T. If f := lnuand w:=|∇g(t)ln(1−f)|2g(t)=|∇g(t)f|2g(t)/(1−f)2, then the inequality

(∆−∂t)w ≥ 2 f

1−fh∇f,∇wi+ 2(1−f)w2 + 2h∇f,∇qi

(1−f)2 + 2a |∇f|2

(1−f)2 + 2|∇f|2(q+af) (1−f)3 (2.1)

holds on Bρ,T.

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Proof. Sinceuis a positive solution to the nonlinear parabolic equation (1.2) with α= 1 anda <0, direct calculation shows that

∆f+|∇f|2−ft−q−af = 0, ft:=∂tf.

The partial derivative ofw with respect totis given by wt = 2h∇f,∇fti

(1−f)2 +2|∇f|2ft

(1−f)3 +2Ric(∇f,∇f) (1−f)2

= 2h∇f,∇(∆f+|∇f|2−q−af)i

(1−f)2 +2Ric(∇f,∇f) (1−f)2 + 2|∇f|2(∆f +|∇f|2−q−af)

(1−f)3 .

Using Bochner’s identityh∇f,∇∆fi=h∇f,∆∇fi −Ric(∇f,∇f) we obtain wt = 2h∇f,∆∇fi+ 2h∇f,∇(|∇f|2−q−af)i

(1−f)2 + 2|∇f|2(∆f+|∇f|2−q−af)

(1−f)3 . The partial derivative ofw with respect toxis given by

∆w= 2 |∇2f|2

(1−f)2 + 2h∇f,∆∇fi

(1−f)2 + 4h∇f,∇|∇f|2i

(1−f)3 + 6 |∇f|4

(1−f)4 + 2|∇f|2∆f (1−f)3. Combining those partial derivatives imply

(∆−∂t)w = 2 |∇2f|2

(1−f)2 + 4h∇f,∇|∇f|2i

(1−f)3 + 6 |∇f|4

(1−f)4 −2h∇f,∇|∇f|2i (1−f)2

−2 |∇f|4

(1−f)3 + 2a |∇f|2

(1−f)2 + 2h∇f,∇qi

(1−f)2 + 2 q|∇f|2

(1−f)3 + 2a f|∇f|2 (1−f)3. On the other hand, the gradient termh∇f,∇wiis determined by

h∇f,∇wi=h∇f,∇|∇f|2i

(1−f)2 + 2 |∇f|4 (1−f)3. Plugging it into the evolution of (∆−∂t)wwe conclude that

(∆−∂t)w = 2 |∇2f|2

(1−f)2 + 2h∇f,∇|∇f|2i (1−f)3 + 2

1−fh∇f,∇wi + 2 |∇f|4

(1−f)4 −2h∇f,∇wi+ 2 |∇f|4

(1−f)3 + 2a |∇f|2 (1−f)2 + 2h∇f,∇qi

(1−f)2 + 2 q|∇f|2

(1−f)3+ 2af|∇f|2 (1−f)3. Because of the identity

|∇2f|2

(1−f)2 +h∇f,∇|∇f|2i

(1−f)3 + |∇f|4 (1−f)4 =

2f

1−f +∇f ⊗ ∇f (1−f)2

2

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we therefore arrive at (∆−∂t)w = 2

2f

1−f +∇f⊗ ∇f (1−f)2

2

+ 2

1−fh∇f,∇wi+ 2 |∇f|4 (1−f)3

−2h∇f,∇wi+2h∇f,∇qi

(1−f)2 + 2a |∇f|2

(1−f)2 +2|∇f|2(q+af) (1−f)3 which immediately implies

(∆−∂t)w ≥ 2f

1−fh∇f,∇wi+ 2|∇f|4

(1−f)3+2h∇f,∇qi (1−f)2 + 2a |∇f|2

(1−f)2 +2|∇f|2(q+af) (1−f)3 .

This complete the proof.

Theorem 2.3. Suppose that (M, g(t))t∈[0,T] is a complete solution to the Ricci flow (1.1) on ann-dimensional manifoldM withsupBρ,T|Ricg(t)|g(t)≤K for some K >0, and uis a smooth positive function onM ×[0, T] satisfying the nonlinear parabolic equation (1.2) where the functionq(x, t)is defined onM×[0, T] which is C2 in thex-variable and C1 in the t-variable. If u(x, t) ≤A for some A >0 on Bρ,T,α= 1,|∇g(t)q|g(t)≤γ, and

b:=1

8 + min

M×[0,T]q−max{a,0} ∈

0,1 2

then there exists a constantC that depends only onn such that

(2.2) |∇g(t)u|g(t)

u ≤ C

b 1

ρ+ 1

√t +

K+ 1 +√ γ+p

|a| 1 + lnA u

onBρ/2,T with t6= 0.

Whenqis nonnegative anda≤0, the constantC/bcan be a universal constant which means a constant depending only on the dimensionn. The number 1/8 inb is not essential, because in the following proof we shall see that we can replace 1/8 by 1/2.

Proof. Without loss of generality, we may assume thatA = 1; otherwise, we can replace uby u/A. Pick a number τ ∈ (0, T] and fix a function Ψ(x, t) satisfying the conditions of Lemma 2.1. We will establish (2.2) at (x, τ) for all xsuch that distg(τ)(x, x0)< ρ/2. Define Ψ :M×[0, T]→Rby setting

Ψ(x, t) := Ψ distg(t)(x, x0), t .

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Then, using the identity (2.1) and a straightforward calculation, one has (∆−∂t) (Ψw) ≥ Ψh−Λ,∇wi+

2(1−f)w2+2h∇f,∇qi

(1−f)2 + 2a |∇f|2 (1−f)2 + 2|∇f|2(q+af)

(1−f)3

Ψ + 2h∇w,∇Ψi+w∆Ψ−w∂tΨ

≥ h−Λ,∇(Ψw)i+ 2Ψ(1−f)w2+whΛ,∇Ψi +w∆Ψ−wΨt+ 2

Ψh∇Ψ,∇(Ψw)i −2|∇Ψ|2

Ψ w

+

2h∇f,∇qi

(1−f)2 + 2a |∇f|2

(1−f)2 +2|∇f|2(q+af) (1−f)3

Ψ where Λ =−1−f2f ∇f. By our assumption that |Ric| ≤K onBρ,T and Lemma 2.1 that−Cρ1Ψ1/2≤Ψr≤0, and the identity

−wΨt=−

Ψt+ Ψrtdistg(t)(·, x0) w,

we have (because−∂tdistt(·, x0)≤4p

(m−1)K, c.f. Lemma 8.33 in [5])

−wΨt≥ −Ψtw−4C1

p(m−1)K ρ wΨ1/2.

Suppose that Ψwachieves its maximum at (x0, t0).By [8], without loss of generality, we may assume thatx0is not in the cut-locus of M.At the point (x0, t0), one has

∆(Ψw)≤0,∇(Ψw) = 0,(Ψw)t≥0.Therefore 2Ψ(1−f)w2 ≤ −whΛ,∇Ψi+ 2|∇Ψ|2

Ψ w−w∆Ψ +wΨt

2h∇f,∇qi

(1−f)2 + 2a |∇f|2

(1−f)2 +2|∇f|2(q+af) (1−f)3

Ψ (2.3)

at (x0, t0). We need to bound each term on the right-hand side of (2.3):

|whΛ,∇Ψi| ≤2 w|f|

1−f|∇f||∇Ψ|= 2w3/2|f||∇Ψ| ≤Ψ(1−f)w2+27 16

|f|4|∇Ψ|4 [Ψ(1−f)]3 where we used the Young’s inequality thatab≤ap+bq/(q(p)q/p) for anya, b, >0 andp, q >1 withp−1+q−1= 1. This together with Lemma 2.1 implies

(2.4) |whΛ,∇Ψi| ≤Ψ(1−f)w2+C2

f4 ρ4(1−f)3. Using again Lemma 2.1 we have

(2.5) |∇Ψ|2

Ψ w= Ψ1/2w|∇Ψ|2 Ψ3/2 ≤1

8Ψw2+ 2|∇Ψ|4 Ψ3 ≤1

8Ψw2+C3 ρ4.

Furthermore, by the properties of Ψ and the assumption of the Ricci curvature, one has (c.f., [16, 20])

(2.6) −w∆Ψ≤1

8Ψw2+C4

ρ4 +C4K2. The estimation forwΨt is given by (c.f. [11])

(2.7) |wΨt| ≤ 1

8Ψw2+C5

τ2 +C5K2.

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Sincef ≤0 it follows that

2h∇f,∇qi (1−f)2 Ψ

≤ |∇f|2+|∇q|2

(1−f)2 Ψ ≤ wΨ +γ2Ψ

≤ 1

8Ψw2+ (2 +γ2)Ψ, (2.8)

2a |∇f|2 (1−f)2Ψ

= 2awΨ ≤ 1

8Ψw2+ 2a2Ψ (2.9)

and

−2|∇f|2(q+af)

(1−f)3 Ψ = 2Ψw2 −q

1−f +a −f 1−f

≤ 2Ψw2

− min

M×[0,T]q+a −f 1−f

(2.10)

≤ 2

max{a,0} − min

M×[0,T]q

Ψw2. Substituting (2.5) – (2.10) to the right-hand side of (2.3), we deduce that

Ψ(1−f)w2 ≤ C6

f4

ρ4(1−f)3 +3

4Ψw2+ 2

max{a,0} − min

M×[0,T]q

Ψw2 + C6

τ2 +C6

ρ4 +C6K2+ 2 +γ2+ 2a2 at (x0, t0). Sincef <0, it follows thatf4/(1−f)4≤1 and then

Ψw2 ≤ C6 ρ4 + 1

1−f 3

4Ψw2+ 2

max{a,0} − min

M×[0,T]q

Ψw2 + C6

τ2 +C6

ρ4 +C6K2+ (2 +γ2+ 2a2)

≤ C6 ρ4 +3

4Ψw2+ 2

max{a,0} − min

M×[0,T]q

Ψw2 + C6

τ2 +C6

ρ4 +C6K2+ 2 +γ2+ 2a2 at (x0, t0), when

(2.11) min

M×[0,T]q−max{a,0} ≤ 3 8. Therefore, we can conclude that

1 4 + 2

min

M×[0,T]q−max{a,0}

Ψw2≤2C6

ρ4 +C6

τ2 +C6K2+ (2 +γ2+ 2a2) at (x0, t0). If we assume in addition that

(2.12) 1

8+ min

M×[0,T]q−max{a,0}>0, we arrive at

Ψw2≤ C7

1

8+ minM×[0,T]q−max{a,0}

1 ρ4 + 1

τ2+K2+ 1 +γ2+a2

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at (x0, t0). Because Ψ(x, τ) = 1 when distτ(x, x0)< ρ/2, we finally arrive at w2(x, τ)≤ C7

1

8+ minM××[0,T]q−max{a,0}

1 ρ4 + 1

τ2 +K2+ 1 +γ2+a2

onBρ/2,T, which, sinceτ∈(0, T] was arbitrary, implies

|∇f|

1−f ≤ C8

1

8+ minM×[0,T]q−max{a,0}

1 ρ+ 1

√t +√

K+ 1 +√ γ+p

|a|

,

provided (2.11) and (2.12), or provided

(2.13) −1

8 < min

M×[0,T]q−max{a,0} ≤ 3 8.

We have completed the proof of Theorem 1.1 sincef = ln(u/A) with A scaled to

1.

The number 1/8 in (2.12) is not essential, because in the above argument we can replace 1/8 in (2.5) – (2.9) by a given positive number , and hence we need only to require that

1−6+ 2 min

M×[0,T]q−2 max{a,0}>0, 6+ 2

max{a,0} − min

M×[0,T]q

≥0 or

3−1

2 < min

M×[0,T]q−max{a,0} ≤3 instead of (2.13). When

1

2 + min

M×[0,T]q−max{a,0} ∈

0,1 2

we can choose to be any positive number in the interval [A3,A3 +16), where A:=

minM×[0,T]q−max{a,0} ∈(−1/2,0].

2.2. Gradient estimates II: general case. In this section we extend Theorem 1.1 withα= 1 to the general case.

Lemma 2.4. Suppose(M, g(t))t∈[0,T] is a complete solution to the Ricci flow (1.1) on an n-dimensional manifold M, with −K1g(t) ≤ Ricg(t) ≤ K2g(t) for some K1, K2 > 0 on Bρ,T. If u is a smooth positive function satisfying the nonlinear parabolic equation (1.2), then, for given β ≥1 and any c, d >0 withc+d= 1/β, we have

F ≥ −2h∇f,∇Fi −F

t +2cβt

n |∇f|2−q−ft−afα2

−2(β−1)th∇f,∇qi −2(β−1)taαfα−1|∇f|2

−βtaα(α−1)fα−2|∇f|2−2βtK1|∇f|2−nβt 2dK2 (2.14)

−βaαtfα−1 −|∇f|2+ft+q+afα

−βt∆q,

whereK:= max{K1, K2},f := lnu, andF:=t(|∇f|2−βft−βq−βafα).

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Proof. The proof of this lemma was original from [11]. Now we will find a convenient bound on ∆F like the way in [21].Notice that

iF =t 2∇jf∇ijf −β∇ift−β∇iq−βaαfα−1if .

Then the Laplace ofF equals

∆F = ∇iiF

= t

2|∇2f|2+ 2h∇f,∆∇fi −β∆ft−β∆q

−βaα (α−1)fα−2|∇f|2+fα−1∆f

.

Using the Bochner’s formula ∆∇f =∇∆f+ Ric(∇f,·), we get

∆F = t

2|∇2f|2+ 2h∇f,∇∆fi+ 2Ric(∇f,∇f)−β∆ft

−β∆q−βaα

(α−1)fα−2|∇f|2+fα−1∆f

≥ t

2(∆f)2

n + 2h∇f,∇∆fi −2K1|∇f|2−β(∆f)t−β∆q

−βaα

(α−1)fα−2|∇f|2+fα−1∆f

+ 2βRijijf

since|∇2f|2n1(∆f)2and ∆ft= (∆f)t−2Rijijf. Recalling from the result

∆f =−|∇f|2+q+ft+afα=−F

t −(β−1) (q+ft+afα), we arrive at

∆F ≥ 2cβt

n |∇f|2−q−ft−afα2

+ 2dβt

n (∆f)2+ 2tβRijijf

−2t

∇f,∇ F

t + (β−1)(q+ft+afα)

−2K1t|∇f|2−tβ

−F

t −(β−1)(q+ft+afα)

t

−βt∆q (2.15)

−βaαt

(α−1)fα−2|∇f|2+fα−1∆f in the setBρ,T. Because

2dβt

n (∆f)2+ 2tβRijijf = 2dβt n

h

(∆f)2+n

dRijijfi

= 2dβt n

2f+ n 2dRic

2

−nβt 2d |Ric|2

≥ −nβt 2d |Ric|2,

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the inequality (2.15) can be written as

∆F ≥ 2cβt

n |∇f|2−q−ft−afα2

−nβt 2d |Ric|2

−2t

∇f,∇ F

t + (β−1)(q+ft+afα)

−2K1t|∇f|2−tβ

−F

t −(β−1)(q+ft+afα)

t

−βt∆q (2.16)

−βaαt

(α−1)fα−2|∇f|2+fα−1∆f To get the time derivative ofF, we shall use the identity

Ft= F t +t

|∇f|2−βft−βq−aβfα

t

.

Subtracting this from (2.16), we get (∆−∂t)F ≥ −2h∇f,∇Fi −F

t +2cβt

n |∇f|2−q−ft−afα2

−βt∆q−2(β−1)th∇f,∇qi −nβt 2d |Ric|2

−2(β−1)taαfα−1|∇f|2−βtaα(α−1)fα−2|∇f|2

−βaαtfα−1

− |∇f|2+ft+q+afα

−2βK1t|∇f|2.

Now the inequality (2.14) follows immediately by noting that|Ric| ≤K.

Now we can consider the local space-time gradient estimate with Lemma 2.3. In the following part,nis the dimension of M.

Theorem 2.5. Suppose that(M, g(t))t∈[0,T]is a complete solution to the Ricci flow (1.1) on ann-dimensional manifold M with −K1g(t)≤Ricg(t)≤K2g(t)for some K1, K2 > 0 on Bρ,T. If u is a smooth positive function satisfying the nonlinear parabolic equation (1.2), then there exists a constant C depending only on nsuch that, on Bρ/2,T,

(1) fora≥0, we have

|∇g(t)f|2g(t)−βft−βq−βafα ≤ nβ

2c(1−)t+(A+γ)nβ

2c(1−) + n2β3C2 4c2(1−)(β−1)ρ2 + nβ[βK1+a(β−1)α|fα−1|]

c(1−)(β−1) + nβ2aα|α−1||fα−2|

2c(β−1)(1−) +

s

[βθ+ (β−1)γ+2dK2]nβ 2c(1−)

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(2) fora≤0, we have

|∇g(t)f|2g(t)−βft−βq−βafα ≤ nβ

2c(1−)t+(A+γ)nβ

2(1−c) + n2β3C12 4c2(1−)(β−1)ρ2 + nβ[βK1a2(β−1)α|fα−1|]

c(1−)(β−1) +

s

[βθ+ (β−1)γ+2dK2]nβ

2c(1−) .

Here f := lnu, |f| := maxM|f|, K := max{K1, K2}, β > 1, 0 < < 1,

|∇g(t)q|g(t)≤γ,∆g(t)q≤θ, A=C

1 ρ2+

√K1

ρ +1 t +K

andc, d >0 withc+d= 1/β.

Proof. We will use the same notationf = lnuandF =t(|∇f|2−βft−βq−βafα) as in lemma 2.4. For the fixedτ ∈(0, T], chose the cut-off function Ψ constructed in Lemma 2.1. Define Ψ :M×[0, T]→Rby setting

Ψ(x, t) = Ψ distg(t)(x, x0), t .

Lemma 2.4 implies that

(∆−∂t) (ΨF) ≥ −2h∇f,∇(ΨF)i+ 2Fh∇f,∇Ψi +

2cβt

n |∇f|2−q−ft−afα2

−F

t − βt∆q

−2(β−1)th∇f,∇qi −2(β−1)taαfα−1|∇f|2

−βtaα(α−1)fα−2|∇f|2−2βtK1|∇f|2−nβt 2d K2

−βaαtfα−1 −|∇f|2+ft+q+afα

Ψ +F∆Ψ + 2

Ψh∇Ψ,∇(ΨF)i −2|∇Ψ|2

Ψ F−F∂Ψ

∂t.

Let (x0, t0) be a maximum point for the function ΨF in the set {(x, t)|0≤t≤τ, dt(x, x0)≤ρ}.Then at the point (x0, t0) we have

0 ≥ 2Fh∇f,∇Ψi+F(∆−∂t) Ψ−2|∇Ψ|2

Ψ F

+

−F

t +2cβt

n |∇f|2−q−ft−afα2

−βt∆q

−2(β−1)th∇f,∇qi −2(β−1)taαfα−1|∇f|2

−βtaα(α−1)fα−2|∇f|2−βaαtfα−1 −|∇f|2+ft+q+afα

−2βtK1|∇f|2−nβt 2d K2

Ψ.

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By Lemma 2.1 and the Laplacian comparison theorem, we have

|∇Ψ|2

Ψ ≤ C1/22 ρ2 ,

∆Ψ ≥ −C1/2Ψ12

ρ2 −C1/2Ψ12

ρ (n−1)p

K1coth(p k1ρ)

≥ −d1

ρ2 −d1Ψ12 ρ

pK1,

−∂tΨ ≥ −CΨ12

τ −C1/212

where C1/2, C andd1 are positive constants depending only onn. Plugging those estimates into above inequality yields that

0 ≥ d2

−1

ρ2−Ψ1/2 ρ

pK1−Ψ1/2

τ −KΨ1/2

F−2F|∇f||∇Ψ|

+ 2cβt

n |∇f|2−q−ft−afα2

−F

t − βt∆q−nβt 2d K2

−2(β−1)th∇f,∇qi −2(β−1)taαfα−1|∇f|2−2βtk1|∇f|2 (2.17)

−βtaα(α−1)fα−2|∇f|2−βaαtfα−1 −|∇f|2+ft+q+afα

Ψ at (x0, t0), whered2 is equal to max{d1, C, C1/2,2C1/22 }. Introduce a function

A:=d2

1

ρ21/2 ρ

pK11/2

τ +KΨ1/2

.

If one multiplies bytΨ and makes a few elementary manipulations, one will obtain 0 ≥ −2F|∇f||∇Ψ|Ψt−AFΨt+

2cβt

n |∇f|2−q−ft−afα2

−βt∆q−2(β−1)th∇f,∇qi −2(β−1)taαfα−1|∇f|2

−βtaα(α−1)fα−2|∇f|2−βaαtfα−1 −|∇f|2+ft+q+afα (2.18)

−2βtK1|∇f|2−nβt 2d K2

Ψ2t−FΨ2 at (x0, t0). As in [3, 19], we set

µ:= |∇f|2(x0, t0) F(x0, t0) ≥0.

Because|∇f|=µ1/2F1/2 and

|∇f|2−ft−q−afα = F

µ−µt−1 βt

,

h∇f,∇Ψi ≤ |∇f||∇Ψ| ≤ C1

ρ Ψ1/2|∇f|

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we can simplify (2.18) into the following inequality

AF tΨ ≥ −2C1t

ρ Ψ3/2µ1/2F3/2−Ψ2F+2cΨ2

nβ [1 + (β−1)µt]2F2−nβ

2dK2(Ψt)2

−2(tΨ)2[βK1+a(β−1)αfα−1]µF+atΨ2αfα−1[1 + (β−1)tµ]F (2.19)

−β(tΨ)2θ−2(β−1)(tΨ)2γ(µF)1/2−β(tΨ)2aα(α−1)fα−2µF

at (x0, t0). If we set G := ΨF, then at the point (x0, t0) the inequality (2.19) becomes

AtG ≥ −2C1t

ρ µ1/2G3/2−ΨG+ 2c

nβ[1 + (β−1)µt]2G2−nβ

2dK2(Ψt)2

−2Ψt2[βK1+a(β−1)αfα−1]µG+aΨtαfα−1[1 + (β−1)µt]G (2.20)

−β(Ψt)2θ−2(β−1)t2Ψ3/2γµ1/2G1/2−βt2Ψaα(α−1)fα−2µG

at (x0, t0). According to the Cauchy inequality, where 0< <1, 2C1t

R µ1/2G3/2 ≤ 2c

nβ[1 + (β−1)µt]2G2+ nβC12t2µG 2cρ2[1 + (β−1)µt]2, 2µ1/2G1/2 ≤ 1 +µG,

we can simplify (2.20)as

AtG ≥ 2c(1−)

nβ [1 + (β−1)µt]2G2−ΨG− nβ2C12t2µ 2cρ2[1 + (β−1)µt]2G

−2Ψt2[βK1+a(β−1)αfα−1]µG+aΨtαfα−1[1 + (β−1)µt]G

−βΨ2t2θ−(β−1)t2Ψ3/2γ−(β−1)t2Ψ3/2γµG

−βt2Ψaα(α−1)fα−2µG−nβ

2dK2(Ψt)2, at (x0, t0), or equivalently,

2c(1−)[1 + (β−1)µt]2G2

nβ ≤

2C12t2µ

2cρ2[1 + (β−1)µt]2 +βt2Ψaα(α−1)fα−2µ

−aΨtαfα−1[1 + (β−1)µt] + (β−1)t2Ψ3/2γµ + 2Ψt2[βK1+a(β−1)αfα−1]µ+At+ Ψ

G

+

βΨ2θ+ (β−1)Ψ3/2γ+nβ 2dK2Ψ2

t2

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at (x0, t0). Note that 0≤Ψ≤1 and 1 + (β−1)µt0≥1. Therefore 2c(1−)G2

nβ ≤

At+ 1 + nβ2C12t2µ

2cρ2[1 + (β−1)µt] +2Ψt2[βK1+a(β−1)αfα−1]µ [1 + (β−1)µt]2

− aΨtαfα−1

1 + (β−1)µt + (β−1)γt2µ

1 + (β−1)µt+βt2Ψaα|α−1|fα−2µ 1 + (β−1)µt

G

+

βθ+ (β−1)γ+nβ 2dK2

t2

At+ 1 + nβ2C12t

2cρ2(β−1)+2Ψt2[βK1+a(β−1)α|fα−1|]µ [1 + (β−1)µt]2

(2.21)

+γt− aΨtαfα−1

1 + (β−1)µt+βtΨaα|α−1||fα−2| β−1

G

+

βθ+ (β−1)γ+nβ 2dK2

t2.

Before completing the proof, we recall a fact: if x2 ≤ax+b for somea, b, x ≥0, then

(2.22) x≤ a

2 + r

b+a 2

2

≤ a 2 +√

b+a

2 =a+√ b.

Ifa≥0 in (2.21), then from (2.21) we deduce that G2

(A+γ)nβt

2c(1−) + nβ

2c(1−)+ n2β3C12t 4c2(1−)ρ2(β−1) + nβ2aα|α−1||fα−2|t

2c(β−1)(1−) +nβ[βK1+a(β−1)α|fα−1|]t c(1−)(β−1)

G (2.23)

+ [βθ+ (β−1)γ+2dK2]nβt2

2c(1−) .

Applying (2.22) to the inequality (2.23), we get an upper bound forG:

G ≤

(A+γ)nβ

2c(1−) + n2β3C12

4c2(1−)(β−1)ρ2 +nβ[βK1+a(β−1)α|fα−1|] c(1−)(β−1) + nβ2aα|α−1||fα−2|

2c(β−1)(1−)

τ+ s

[βθ+ (β−1)γ+2dK2]nβ

2c(1−) τ+ nβ

2c(1−), since t1 ≤ τ. By the construction of Ψ, we have supB

ρ/2,TF ≤ supBρ,T(ΨF) ≤ G(x0, t0) for allt∈[0, τ]. Becauseτ ≤T is arbitrary, it follows that

|∇f|2−βft−βq−βafα ≤ nβ

2c(1−)t +(A+γ)nβ

2c(1−) + n2β3C12 4c2(1−)(β−1)ρ2 + nβ[βK1+a(β−1)α|fα−1|]

c(1−)(β−1) + nβ2aα|α−1||fα−2|

2c(β−1)(1−) +

s

[βθ+ (β−1)γ+2dK2]nβ 2c(1−)

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where|f|:= maxM|f|. Similarly, whena≤0, we have G2

(A+γ)nβt

2c(1−) + nβ

2c(1−)+ n2β3C12t

4c2(1−)ρ2(β−1) + nβ2K1t c(1−)(β−1)

− nβatα|fα−1| 2c(1−)

G+[βθ+ (β−1)γ+2dK2]nβt2

2c(1−) .

(2.24)

From (2.22), (2.24), and above argument, an upper bound for desired quantity in this case is

|∇f|2−βft−βq−βafα ≤ nβ

2c(1−)t +(A+γ)nβ

2c(1−) + n2β3C12 4c2(1−)(β−1)ρ2 + nβ[βK1a2(β−1)α|fα−1|]

c(1−)(β−1) +

s

[βθ+ (β−1)γ+2dK2]nβ

2c(1−) .

Hence, we complete the proof.

3. Gradient estimates for (1.4) under the geometric flow Suppose now u is a positive solution of (1.5), and as in [7], we introduce a function

(3.1) W :=u−q,

where qis a positive constant to be determined later. For convenience, we always omit time variable tand writeQt for the partial derivative ofQrelative tot. For example, throughout this paper, ∆,∇,| · |mean the correspondence quantities with respect tog(t). Write

:= ∆−∂t. A simple computation shows that

∇W = −qu−q−1∇u, |∇W|2 = q2u−2q−2|∇u|2,

Wt = −qu−q−1ut, ∆W = q(q+ 1)u−q−2|∇u|2−qu−q−1∆u.

The relation (3.1) yields (see [7, 9])

(3.2) |∇u|2= |∇W|2

q2W2+2/q, ut=− Wt

qW1+1/q, and hence

(3.3) W =q+ 1

q

|∇W|2

W +qhW1+1−pq .

Since |∇W|2/W2 = q2|∇u|2/u2 and hW(1−p)/q = hup−1, we consider again the same quantities as in [7, 9],

F0 := |∇W|2

W2 +αhW(1−p)/q = |∇lnW|2+αhW(1−p)/q, (3.4)

F1 := Wt

W = ∂tlnW, (3.5)

F := F0+βF1. (3.6)

Références

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