A NNALES DE L ’I. H. P., SECTION C
R UGANG Y E
How to blow infinitely large soap bubbles with a fixed boundary
Annales de l’I. H. P., section C, tome 8, n
o1 (1991), p. 59-78
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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
How to blow infinitely large soap bubbles with
afixed boundary
Rugang YE
(1)
Department of Mathematics, Stanford University, Stanford, CA 94305, U.S.A.
Vol. 8, n° 1, 1991, p. 59-78. Analyse non linéaire
ABSTRACT. - Consider
(area minimizing)
soap bubbles(i.
e. surfaces of constant meancurvature) spanning
a Jordan curve r in~3.
We show thatthey
converge toinfinitely large
minimal surfacesspanning
r as theirvolumes
approach infinity.
RESUME. - On considere des bulles de savon
(i. e.
des surfaces de courbure moyenneconstante)
a bord d’une courbe Jordan rclR3. Nous demontronsqu’ils
convergent vers des surfaces minimales infinimentlarges
a bord r si leur volume tend vers l’infini.
Mots clés : Surfaces de courbure moyenne constante.
1. INTRODUCTION
In order to find soap bubbles
(i.
e. surfaces of constant meancurvature) spanning
anoriented,
rectifiable Jordan curve r in~3,
one minimizesClassification A.M.S. : 49 F 10, 53 A 10.
(~) Partially supported by an NSF grant.
Annales de l’Institut Henri Poincaré - Analyse non linéaire - 0294-1449
area
(or
the Dirichletenergy)
under a volume constraint. Let andHr = { u
EH~ (D, [R3)
n C°(D, f1~3):
u~ aD is a
weakly
monotonicrepresentation
ofr}.
For
u E H2 (Q, f~3),
Qee one defines the Dirichlet energythe area
and the oriented volume
We also use the notation E
(u, Q’) :
= E(u~
for Q’ c SZ.The
following
solution of the volume constrained Plateauproblem
is dueto H. Wente
[23] (the
immersion property was established in[19]).
EXISTENCE THEOREM. - Let V be a
given
constant andThen there exists in an element which minimizes the Dirichlet energy and area. The
mapping
u~ D is a realanalytic conformal
immersionof
constant mean curvature.
[Such
a u will called a "minimizer of volume V"(spanning 1,).]
In 1980 Wente
[23]
establishedSOAP BUBBLE THEOREM. - Let be a sequence
of
orientedrectifiable
Jordan curves in R3 with 0 E and
length (h’k)
~ 0 as k - ~. Let uk be minimizersof volume 4 ~ spanning
Then asubsequence of
u(still
3
denoted
by uk)
converges to a roundsphere So of
radius 1 andcontaining
the
origin
inthe following
sense: there exist radii r~ -~ oo andconformal
maps
Drk
D such that cpk and theirfirst
derivatives converge to vo and itsfirst
derivatives on any diskDR,
where vo is aconformal
representa- tionof So
with vo(oo)
= 0.(A
moregeneral study
in this direction was lateron taken
by
Brezis and Coron[3].)
Formulated in another way, this theorem says that for a fixed r minimizers uv of volume V become more and more
spherical
as V -~ o0in the sense that after suitable
rescaling
u~ converge to roundspheres.
In this paper we are concerned with the
following question
raisedby
Wente: if we do not rescale u~, can we get
infinitely large
minimal surfacesspanning
r in the limit? Or: if we blowlarger
andlarger
soap bubbles with a fixedboundary,
can we get an"infinitely large
soap bubble" ?We prove.
MAIN THEOREM. - Let uk be a sequence
of
minimizersof
volumeV k
o0spanning r,
whichsatisfy
the classical threepoint
conditionof
the Plateauproblem [4].
Then asubsequence of
uk(still
denotedby
converges toan
infinitely large
minimalsurface
uspanning
r. Moreprecisely,
we have(D* ~ - DB~ ~ ~~ D* ~ = DrB{ ~ ~)~
A.
(properties
ofu).
1.
u E H2 (DBDr)
for everyr > 0,
u|~Dparametrizes
r topo-logically
and is a realanalytic
conformal minimalimmersion;
2.
lim I u (z) == oo,
lim n(z) exists,
where n denotes a continuous unit normal of u;3. for some is an
embedding
of finite total Gaussian curvature and u(D*)
is agraph
over aplane;
4. u minimizes area under constant volume constraint
(for precise
mean-ing
seeProposition 2. 2).
B.
(Convergence
ofuk)
There is a conformal transformation D ~ D such that1. converge to u
uniformly
on andstrongly
inH2
for earchr > o;
2. uk cp converge to u
locally smoothly
inD*;
3. if r is a
regular
Jordan curve of class for somel >_
1 andae(0, 1),
then Uk 0 cp also converge to u in theCl
norm onfor
each r>O.We remark that this theorem also
provides
a resolution of the exterior Plateauproblem:
find a minimal surfacespanning r,
which has the confor-mal type of the
punctured
disk and stretches out toinfinity.
Thisproblem
has been solved in
[21] ] by employing
a sequence ofexpanding
minimalannuli,
where oneadditionally prescribes
theasymptotical
normal at infin-ity.
In the present paper we encounter the sameanalytical difficulty
as in[21],
i. e. we have to deal with sequences ofmappings
whose Dirichletenergies approach infinity.
This kind ofdifficulty
seems to be new, andwe
hope
that our arguments(in
this paper and in[21])
can be useful toother
problems
also. We note that the situation in the present paper ismore
complicated
than in[21].
Onemajor
reason is that the size of aminimal surface is well-controlled
by
itsboundary
via the maximumprinciple
orisoperimetric inequality
whereas ingeneral
this is not the casefor surfaces of nonzero mean curvature. This presents additional difficulties for
estimating
the area of certain subsets of our soap bubbles. Weappeal
to the
monotonicity
formula for area, Wente’sSoap
BubbleTheorem,
hisdiameter estimate for soap bubbles in
[23]
and Heinz’isoperimetric inequality
for "small" surfaces of constant mean curvature[10].
An additional remark: the Main Theorem of this paper is a counterpart
to Wente’s
Soap
BubbleTheorem,
but asubtlety
should berecognized.
The round
sphere
limit of the rescaled bubblesdisappears
atinfinity during
the convergence of the unscaled bubbles uv as V -~ oo, while the minimal surface limit of the unscaled bubbles shrinks to apoint during
the rescaled convergence. Thus the two theorems capture different parts of the
expanding
soap bubbles in the limit.We are indebted to H. Wente for
introducing
us to thesubject
andstimulating
discussions. This work was done atHeidelberg University
andRuhr
University, Bochum,
we aregrateful
to F.Tomi,
J. Jost and SFB 237for kind supports.
(The
author was alsopartially supported by
an NSFgrant.)
We thank the referee forpointing
out a gap in theoriginal manuscript.
2. CONVERGENCE OF MINIMIZERS OF LARGE VOLUME We fix a least area disk uo
spanning
r and defineao = A (uo), Vo = V (uo).
Putdo = diam r, lo = length (r), a (V)=inf {E (u) :
u EHr, v ~
and
~f
(V) = {
H : H is the mean curvatureof some minimizer u of volume V
spanning r}.
Here the
sign
of H is determinedby
theequation
~u = 2 Themean curvature of u will be denoted
by
H(u).
We assume w. 1. o. g. thatOEr.
LEMMA 2.1. - We have
1. for all V E IR:
2. for
all V E IR and H ~ H(V):
We refer to
[17]
for aproof.
This lemma says that the area and mean curvature of a minimizer of volume Vapproximately equal
those of around
sphere
of the same volume if V islarge.
For a continuous
mapping
u defined on a closedplane
domain whoseboundary
contains S 1: = aD we define Q(u, p)
=(BP), SZo (u, p)
= theconnected component of S~ in Q
(u, p),
whereWe shall abbreviate E
(u,
Q(u, p))
toEp (u).
We also define
S~o (u, p)
to be the annulus boundedby S 1
and theoutside
boundary
ofQo (u, p), provided
thatQo (u, p)
is .a bounded C~domain contained in
CBD. Thus, Q$ (u, p)
is obtained from00 (u, p) by filling
in holes between the inside and outside boundaries ofQo (u, p).
E: (u)
will stand for E(u, Q$ (u, p)).
In the
sequel
weonly
treat minimizers ofpositive volumes,
sincenegative
volumes
merely
involve a switch in orientation. Let so E( 0, 2014)
be thenumber
satisfying 1 1-~20 e2
Eo= 6 .
PutRo
= maxd
2d° l°
/
y
E o 5 °
~ B 7T /J
-LEMMA 2. 2. - There exists
Ro
>Eo 1 Ro
such that ’for
all P E(Ro,
EoR),
whenever u is a minimizerof
volume -1t R 3 withR > ko.
Proof -
Assume the contrary. Then there are minimizers 03C5k of volumex
R)
with Rk ~ oJ and radii 03C1k e(Ro,
so such that 3We
apply
the Soab Bubble Theorem to to obtainR~
or
Hence
by
Lemma 2. 1On the other
hand,
themonotonicity
formula for area[16] implies
forr 1 and
p>do
where
Hk
= H(uk)
and ds denotes thearclength
element in the metricinduced
by
vk. Butf
aDr dslength (r)
as r -~ 1by [ 10],
hence we obtainMultiplying (2. 3) by e’
and thenintegrating
ityield
for
But Lemma 2.1
implies
Choosing
p = EoRk
in(2. 4)
we deduce on account of(2 . 2)
and(2. 5)
if
Rk
islarge enough
anda>Ro. Applying
this to a= 03C1k we get a contradiction to(2 . I).
Q.E.D.
The
following
lemma is an easycorollary
of Wente’sSoap
BubbleTheorem.
LEMMA 2 . 3. - There exists a number
Ro > ko
such that thefollowing
istrue. For each minimizer u
of volume 4 3 03C0 R3
with R ~ R0, there is asmooth, simply
connected domain03A9~
such that ujq, is anembedding
andE
(u, Q) > 31 8 03C0 R2.
Moreover, there is a roundsphere So of
radius I andcontaining
theorigin,
such that the embeddedsurface
u(fi)
is withinR
distance
from
thespherical
capS0BB1/100
in the C1 sence. We shall1 ,000
call o a
sphere
domainfor
u. We choose zo e o suchthat
u(zo)
is aR
closest
point on
u(fi)
to the northpole of So (the origin
isthought of
asR
the south
pole of so).
We call zo a northpole of
u.For each minimizer u of volume no less
than 03C0 Rg,
we define a3
nomalization for u to be a conformal transformation 03C6 : D - D such that 03C6 maps the
origin
to a northpole
of u. If theorigin
is itself a northpole
of u, then we say that u is
normalized..
For a map u : D -
R3,
we define û:B ~ R3 via ti(z) = u(1 z).
LEMMA 2.4. Let u be a normalized minimizer
of
volume4 3
x R3(R > Ro).
Thenprovided that 03C1~(R0,1 2 ~0 R)
and P? 2 p are bothregular
valuesof
theSince M is
normalized,
theassumption
about pimplies
thatQ~ (M, p)
andQ$ (M,
2p)
are well-defined annuli with common insideboundary
S1. Considerz0 ~ ~03A9*0 (û, 03C1)BS1
such thatdist
(z,,
2p)BS’)=~:
=dist(~ p)BSB ~ (~
2p)B~).
Set
and
If
r >_ 1,
we are done.Otherwise, by
theCourant-Lebesgue
lemma[4]
thereexists r 1 E
(r, Jr )
such thatSince
rl 1
and~03A9*0 (M, ~03A9*0 (M,
2 surroundSl,
we canfind an arc in a’
Drl (zo) connecting ~03A9*0 (u,
and~03A9*0 (u,
2Hence
Then the desired
inequality
follows from(2. 6)
and Lemma 2. 2.Q.E.D.
A word about the strategy of our arguments: in order to estimate the Dirichlet energy of ti on compact
regions,
we look at certain"good"
regions
on which the Dirichlet energy of ti is under control and try to show that theseregions
exhaust the whole domain of ti. Now theregion S2o (M, p)
have theexhausting
propertyby
the abovelemma,
andLemma 2. 2
provides
an estimate of the Dirichlet energy of ti on thesubregions Qo (M, p). SZo (M, (M, p)
is the union of several disk typedomains,
we call theirimages
under the inversion disks.z
It remains to control the Dirichlet energy of u on these disks. Let
L (u)
denote the 1-dimensional Hausdorff measure of the set u -1
(aBp)
in themetric induced
by
u. Note that for aregular
valuep > do
ofI u I, Lp (u)
isjust
thelength
of the curve u|~03A9 (u, 03C1)BS1).LEMMA 2. 5. - There is a
positive
constant c > 0 such thatwhenever u is a normalized minimizer
of volume 4 303C0
R3 withR > Ro
andp e
Ro, ~ ~° l ,000 ~ R
is a regular
value of ]
u ] satisfying
Proof -
We claim that there is a constantR 1 >_- FZ°
such that thefollowing
is true. If u is a normalized minimized ofvolume 4 ~ 3
R~ withand p E (Ro, 2014~2014 R
is aregular
value of then-
B~ 1, 000
whenever z lies in a
p-bubble
disk. For later use we note that(2.9)
alsoholds on for
provided
thatR~R2
for some1,000
-
R2.
This is a direct consequence of Lemma 2 . 1. We may assumeR 1 >_ R2.
Whenever the above claim is
established,
the desired energy estimate(2.7)
followsimmediately.
Infact,
we deduce from(2.9)
and Heinz’isoperimetric inequality [10]
thatfor each
p-bubble
disk Q’. Hencewhich
together
with Lemma 2 . 2implies (2. 7). (This
covers all R >_R1.
But
(2. 7)
is automatic forRe[Ro, R1] ]
on account of Lemma2 .1,
if wechoose c
suitably.)
Now we prove the claim. Consider a
sphere
domain Q for ugiven by
Lemma 2. 3. Since u is
normalized,
it isreadily
seen that Q must containthe
origin;
inparticular,
Q is not ap-bubble
disk. Since_
p_2014~2014 R _ 1
R and the distance of u(Q)
from theorigin
is at least1,000
_
1,000 ~ )
g1 R,
it follows that Q isdisjoint
from thep-bubble
disks. Hence200
Lemma 2.1 and Lemma 2. 4
imply
for anyp-bubble
disk Q’provided
that R islarge enough
incomparison
with ao andVo. According
to Theorem 4 .1 in
[23]
we have for z E S2’Combining (2 .10), (2 .11 )
with Lemma 2 .1 thenyields
the estimate(2. 9), provided
that R islarge enough
incomparison
with ao,do, lo
andVo.
Q.E.D.
LEMMA 2. 6. - There is a constant c > 0 such that
for
any normalized minimized uo.f’ orbitrary
volume and r E(o, 1).
Proof. -
In view of Lemma 2 .1 weonly
need to consider minimizers uof volume no less
than 4 ~ R3.
We first observefor
p > 0
and some universal constant c > o. One shows thisby writing
p = 2m + s for a natural number m and s E
(0,2), applying
Lemma 2. 3 toradii
2k,
k m andsumming
up.(We actually apply
Lemma 2. 3 toregular
values of
I û
whichapproximate
the radii2k.)
The desired estimate follows from(2 .13)
and Lemma2.5,
because for any the coarea formula and Lemma 2. 2imply
and hence for a
regular value
p E[p’/2, p’]
ofI u ]
the condition(2. 8)
issatisfied.
Q.E.D.
We fix once for all three distinct
points
zl, z2, z3 E S1 and three distinctpoints
pl, p2, Recall the classical threepoint
condition foru E Hr:
umaps (
zl, z2,z3 } bijectively to { p1,
p2,p3 } . (We
do notspecify
whichzi is
mapped
to which p~, because we need to switch orientation to treatnegative volumes,
see the commentpreceeding
Lemma2. 2).
We define_
~P
: ~P is a normalization for a minimizer ofvolume - >_ 4 ~ R3
which satisfies the three
point
condition .(R1
was defined in theproof
of Lemma2. 5.)
LEMMA 2 . 7. - ~ is compact in the
topology.
We defer the
proof
till the end of this section. Now we are in aposition
to show the convergence of minimizers with volume
blowing
up.PROPOSITION 2. 1. - Let vk be a sequence
of minimizers of
volumevk
-~ o0spanning r,
whichsatisfy
the threepoint
condition. Then there are asubsequence of
vk(still
denotedby
aconformal diffeomorphism
cp : D -~ D and a map u E C°(D*, I~3)
(~ C°°(ID*, f~3)
such that1. The
mappings
cp converge to uuniformly
on andstrongly
inH2 for
each r E(0, 1),
uk also converge to ulocally smoothly
inTD* ;
moreover,if
r is aregular
Jordan curveof
classfor
some l >-1 and a E
(0, 1),
then uk converge to u in the Cl norm on D rfor
each r E(o,1 ) ;
2. u~ S1
parametrizes
rtopologically
and u~ D* is aconformal
branchedminimal immersion ;
Proof -
We may assume that all v have volume~4 303C0 R31.
For eachvk we choose a normalization
By
Lemma 2. 7 we may assumeby
passing
to asubsequence
that cpk converge to a conformaldiffeomorphism
cp : D -~ D.
Then the energy estimate(2.12)
holds for uk = vk ° cp,possibly
with a
different constant
c.By passing
to asubsequence
we deduce thatuk converge to a map Me n
H2 weakly
inH2
foror1 i
each
rE(O,I).
To show the uniform convergence of uk away from theorigin,
we first observe that the threepoint
condition and the energy estimate(2 .12) imply
that S1 areequicontinuous, cf. [4].
Since uksatisfy
the
equation 0394uk
= 2 Hauk
Aauk
and we have the estimate(2.9),
weax
ay
can then
apply
Theorem 4.1 and Theorem 4 . 3 in[11] ]
to conclude thatare
equicontinuous
for each fixedre(0,1).
The desired uniform convergence follows.Once the
equicontinuity
isestablished,
the local smooth convergence is standard. For the additionalCl
convergence on we refer to[20].
Taking
limit in theequations auk
yields
~u =0,
henceax
ay
u has zero mean curvature
(u
is conformal since so are That u|S1parameterizes
rtopologically
is standard. The estimate 3 follows from Lemma 2. 2.We
finally
show the strong convergenceof uk
inH2 (D B Dr)
for r E(0, 1 ).
Passing
to asubsequence
we may assume that lim E DB D1~2)
exists.k -i 00
It suffices to show lim E D
B D 1 ~2).
Forlarge
k wek - 00
can connect uk I D1/2 with
1/2 along ~D1/2 by
a(parameterized)
thinstrip
of area Ek - 0 and volume~k
- 0 to obtain a mapuk
defined on D.Then
In order to achieve V
(uk)
= V(uk)
wemodify uk
in thefollowing
way. First observe thatby
the weak and uniform convergence of uk we have lim V BD1~2)
= V(u~ D B D1~2), cf.
Theorem 2 . 3 in[20].
Now fix k andk -~ 00
choose a
point
Choose an oriented roundsphere
S nearwhose volume is
roughly
V(uk ~ D B D1~2) - V (y D B D1~2) - bk~
cut asmall disk S’ from S and a small disk
Dp(z)
cD1~2 B ~ 0 }
fromD,
andthen connect
S "’- St
with (z)along
a(S B S’)
andaD p (z) by
a thintube T. The
resulting
map will bedenoted by
uk. For suitable choice ofS, S’, r and
T we can make sure that andwith as koo. It follows that Hence
A
D1~2~ -
AB D1~2~ + Ek >
0.Taking
limityields
Q.E.D.
We shall call u a "limit minimal surface"
(spanning r).
PROPOSITION 2 . 2. - Let u be a limit minimal
surface spanning
r. Thenu minimizes area under constant volume constraint in the
following
sense:if v E
nH2 (D B Dr),
v EC° (D*, R3),
03C5|s is aweakly
monotonic repre-or1 1
sentation
of
r and v~ Dr B ~ o ~= u’ Dr B ~ V D B
Dr)
= V(u~ D B Dr) for
somer E
(0,1),
It follows from a classical argument of R. Osserman
([14], [6])
that uhas no true branch
points
in theinterior,
L e. for eachz E ID*,
u maps aneighborhood
of z onto an embedded surface.Proof of
theProposition. -
Let uk ~ u be as inProposition
2 . 1. Forlarge
k we connect with v~along aDr by
a thinstrip
of areaEk - 0 and volume
bk
- 0 to obtain a map uk defined on D. ThenBy
the same argument as in the last part of theproof of Proposition
2.1we can
modify uk to
obtain a suitablecomparison
mapuk. Taking litpit
inthe
inequality
A(uk) >_ (uk) yields
A(VI D
BDr) >_-
A(u~ D B D).
Q.E.D.
Proof of
Lemma 2.7. - Consider the three chosenpoints
zl, z2, z3 on S 1. It suffices to show dist(cp -1 (z~))
> 0 for eachpair
i,j,
i ~j.
Assume the contrary, say we have a sequence of minimizers a normalization cpk for each uk such that
dist(03C6-1k (z 1 ), 03C6-1k (z2))
~ 0 ask - oo . Then the
boundary
valuesk|S1
of are notequiconti-
nuous. But the convergence argument in the
proof
ofProposition
2. 1 forthe sequence uk
applies to Uk
here and shows that S1 areequicontinuous.
Q.E.D.
3. THE ASYMPTOTICAL BEHAVIOR OF LIMIT MINIMAL SURFACES
We fix a limit minimal surface u and a sequence uk ~ u as in
Proposition
2.1.LEMMA 3 . 1. -
Qo (û, p) is a
bounded subsetof
Cfor
every p > 0. On the otherhand, dist (0, ~03A90 (u, p) B S1)
>_clog
pfor
some constant c > 0.Proof. -
We first showQo(û, Otherwise,
u would havefinite Dirichlet energy
by Proposition
2.1. Hence theorigin
is a removablesingularity
of u. Inparticular,
and u has finite volume. More- over,using
theCourant-Lebesgue
lemma we can findradii rl
- 0 andpositive
numbers E, - 0 such thatThen
on
Drl
whenever forsome kl depending
on I. Henceforth weonly
consider for each I.
Let vk
be the harmonic extension of uk|Drl toDrl.
Thenand
Hence,
if we define on and on thenNow we
apply
theisoperimetric inequality [18]
to getChoose an oriented round
sphere
S of volume(we
sup- press thedependence
of Son k, /).
Thenby (3 . 1)
~
In order to correct the volume of
uk,
we aregoing
to "attach" S to it.Consider a disk
Dr (z)
c such that is anembedding.
Thenu (Dr (z))
contains agraph
G defined over aplane
diskQp
of radiusp > 0
and contained in the
cylinder c p2)
for some c > o. Whilekeeping
c fixed we shall determine p later on.By
the convergence of uk towards u, there is someko
such that ifk _> ko,
then is also anembedding
and for someQk
cDr (z),
uk is agraph Gk
overQP
withGk c Zp.
For fixed
I,
observefor k
large enough.
ButV (Uk)
-~+00,thus
S has volume> 3 ~ (say)
for4
large
k. We translate S so that it touches the center p of the top ofZp
from above. Here we assume that the normal of uk
points upwards. (For
later
applications
we remarkthat,
if S hadnegative volume,
then we shouldbring
S to the bottom ofZp.)
Denoteby So
thespherical
cap of Slying
overQp
and centered at p, andby G~
theregion
of thecylinder Qp
x (~ 1lying
betweenSo
undGk.
Wereplace So
UGk by G~
and useS ~So
andGk
to construct a new map D ~ (~3.Easy
compu- tations showNow we fix an I with O
(p4).
Then
Since the volume of S
has a
uniformpositive
lowerbound,
we canmodify
it to make the volume
equal
while the areaof uk
increases atmost
by
O(p4).
Hence A A(uk), provided
that p has been chosen smallenough (independent
ofk, /).
This contradicts theminimizing
prop- erty of uk, however.Next we assume that
~20 (û, p)
is unbounded for some p and letp’ >
p be aregular
value for thefunction u I2.
ThenQ~ (û, p’)
is also unbounded.The maximum
principle,
theimplicit
function theorem and the factimply
that~03A90 (u, p’) B
S 1 consist ofproperly
embed-ded
analytic
curvesrunning
toinfinity
in both directions such that each compact subset of C meetsonly finitely
many of them.By
the Courant-Lebesgue
lemma andProposition 2 .1,
3, we can findarbitrarily
smallcircles around the
origin
such thatno (u, 03C1’)|~u ~03B8|
d03B8 and hence d03B8 also become
arbitrarily
small.Choosing r
smallenough
we can achieve thatC1/r
meets~03A90 (u, p’) B
S 1 at least once. Thenit
follows
that any component ofp’)
has aboundary point
on
Hence u ~2
differsarbitrarily
little from(p’)2
on(~
p’). Consequently I u (2 > p2
on the outsideboundary
of00 (u, p’)
~1D1lr
for asuitably
chosen r.This
implies contradicting
theassumption
aboutQo (û, p).
HenceQo (û, p)
is bounded.Finally
the estimatedist(0, ~03A90 (u, p) B S 1 ) >_ clog
p follows from(2. 7)
and a limit
procedure,
where we may assume that p is aregular
valueQ.E.D.
COROLLARY 3 .1. - Let
p > do be a regular
valueof u I2.
ThenSZo (u, p)
is an annulus and each component
of
SZ(u, p) B 03A90 (u, p)
is a disk.Proof. -
The maximumprinciple implies
thatp)
is an annulusand each bounded component of
aSZ (u, p) B aSZo (u, p)
bounds a disk inS2 (u, p).
On the otherhand, aSZ (u, p)
has no unbounded component, otherwise it would intersectaoo (û, p’)
for somelarge p’ >
pby
the lemma.The assersion follows.
Q.E.D.
LEMMA 3. 2. - For some ro E
(0, 1),
u~Dro
is a stable minimal immersionof finite
total Gaussian curvature.°
Proof. -
Choose 0 R r 1 such that u has no branchpoint along
the circles
Cr, CR.
Let zl, ..., zN be all branchpoints
of u inwith orders m 1, ... , ,mN.
By
the Gauss-Bonnet formula for branched surfaces[13]
we havewhere K = the Gaussian curvature of u, d~ = the area form induced
by
uand K~, ds denote the
geodesic
curvature andarclength
element in the metric inducedby
urespectively. Letting
thesuperscript k
indicate that ageometric quantity
is determinedby
uk, we haveClearly
On the other
hand,
if then Henceby
Lemma
2.1,
~-~oo lim supf.
We deduce
Letting
R ~ + oo we conclude thatK
dro is finite and u has no branchpoints
onD*,
for somer’ E (o,_ r).
If the minimal immersion ul Dr, isstable,
we are done. Otherwise there is a test function cp with supp cp c
D*,
suchthat the second variation of area
~~
isnegative.
Choose ro E
(0, r’)
such that supp cp UD:o
=0.
Then ulD;o
is stable.In
fact,
if this were wrong, we would be able tofind B~
withBut then
( ~ ~ cp (2 + 2 K cp2) d~ 0
for a linear combination(p
of cp,B)/
with
~~
This contradicts theminimizing
property of u(Prop. 2. 2), cf [2].
Q.E.D.
The immersion uj
Dro,
considered as an immersed surface(an equivalence
class of immersions
as
well as an orientedintegral
varifold in the senseof
[12]),
will be denotedby
E.According
to Lemma3.1,
E iscomplete
away from its
boundary
aE ^-_~ ujBy Proposition 2 .1, 3, E
hasquadratic
areagrowth
Consider the contained in the unit ball
Bi.
ItP
follows from Theorem 3 . 6 . 3 in
[12]
that any sequence oo sub- converges to an orientedintegral
2-varifold03A3~
which issupported
inB1
1and
stationary
in0 ~ .
Moreover(M
means mass[12], [16])
in
particular
M(Y~)~ -7t.
A standard cut-off function
argument
shows that isstationary
inB 1.
The varifolds
I:oo
obtained in this fashion will be calledasymptotic
vari-folds.
Let be an
asymptotic
varifold. Theproof
of Theorem 1.1 in[1] ] implies
that is a cone. Note that contrary to the situation in[1] ]
wehave here
aI:p cF ~B1.
But this does not affect the argument, because thelength
of converges to zero as p - oo . On the otherhand,
thecurvature estimates for stable minimal surfaces obtained
by
R. Schoen in[15]
and(3 . 2) imply
thatproperly
immersed minimal surface. It follows that is a cone on the sum offinitely
many great circles inaB 1. By
the area estimate(3. 2), E ~
must be a flat disk ofmultiplicity
1.Hence we can
apply
the results of L. Simon[17]
to obtain.LEMMA 3 . 3. - the
unique asymptotic varifold
andE p
converges tosmoothly
as 03C1 ~ ~. Inparticular,
Efor
somePo>O
is agraph (of multiplicity 1)
over theplane containing E~
and the unit normalof
Ehas an
asymptotical limit at infinity.
This
lemma,
the next one and Lemma 3 .1 establish theasymptotic
behavior of u as stated in the Main Theorem.
LEMMA 3 . 4. - We have
1.
if
p > 0 islarge enough,
then SZ(u, p)
=SZo (u, p) ;
2.
if r > 0 is
smallenough,
then u~ Dr is anembedding.
Proof. -
1. If p > po islarge enough,
then p is aregular
value ofI u 12
and
image (u)
naBp
is a smooth Jordan curve yaccording
to Lemma3.1,
3 . 2 and 3 . 3.
Consequently,
u maps the insideboundary
ofQo (u, p)
ontoy. If
Q (u, p)
has a componentp),
then u also maps aSZ onto y.This contradicts the fact that E
B Bpo
is agraph (with multiplicity 1).
2. This follows from
1,
Lemma 3 .1 and the fact that is anembedded surface of
multiplicity
1.Q.E.D.
To
give
acomplete proof
of the MainTheorem,
thereonly
remains thefollowing
last step.PROPOSITION 3 . 1. - u is an immersion in the interior.
Proof. -
Choose aregular
valuep > do of
such that u is anembedding
onp).
Recall thatp)
is a smoothannulus
region
with outsideboundary
Sl. Assume that u has branchpoints
in
M. According
to[7]
and the fact that u has no true branchpoints
in theinterior
(Prop. 2.2)
there is an orientationpreserving
branchedcovering
x : M -~ M’
together
with a commutativediagram,
where the
quotient
space M’ is a compact and oriented surfacepossibly
with
boundary
and u’ is an immersion inM’
and continuous on M’.Let L denote the inside
boundary
of M. Sinceu (L)
is extreme(u (L)
caBp
and p >do)
and ul L is anembedding,
is adiffeomorphism
onto a
boundary
component L’ of M’. Wedistinguish
between two cases.Case 1. - aM’ has a second component.
In this case M’ is an annulus and 03C0 maps aM onto aM’. Hence the
generalized
Riemann-Hurwitz formula[8]
implies
whereOn
denotes the total branch orderWe arrive at a contradiction.
Case 2. - aM’ = L’.
Then M’ is a disk. The Jordan curve bounds a
(closed)
disSZ 1
in
1VI’.
Since x is anembedding along L,
we haveM, z) =1
for any where Because L" must havepreimage points
inM,
we obtain
deg (x, M, z) = 2
for all It follows thatNow we choose an
orientation preserving diffcomorphism
cp :_M --~ Q~
withand define
.u:D* -~ ~3,
viaThen a
topological representation
of r.Moreover,
Next we choose a smooth disk v : D
B ~
[R3with 03C5|L = u|L
and define vl,[19]
there is anintegral
3-current I withaI = JVl - JV2
andV (I) = V (v 1 ) - V (v 2),
whereJ"i
denotes theintegral
2-current inducedby
v; and
V (I)
is the oriented volume ofI,
defined as I(dx1
Adxl
Adx3). By
the construction of vi , v2 and the fact about the
degree
of 7~~ we haveHence the mass of
aI,
M(aI)
satisfiesNote V