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February25 ,2019 Improperintegrals Calculus!

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MAT137Y1 – LEC0501

Calculus!

Improper integrals

February 25th, 2019

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For next lecture

For Wednesday (Feb 27), watch the videos:

• BCT: 12.7, 12.8

• LCT: 12.9, 12.10

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Improper intergrals: definition – 1

Let𝑓 ∶ [𝑎, +∞) → ℝbe a function which is integrable on each subinterval[𝑎, 𝑐] ⊂ [𝑎, +∞)(for instance continuous), then we set

+∞ 𝑎

𝑓 (𝑥)𝑑𝑥 ∶= lim

𝑐→+∞

𝑐 𝑎

𝑓 (𝑥)𝑑𝑥

whenever it makes sense.

Let𝑓 ∶ (−∞, 𝑏] → ℝbe a function which is integrable on each subinterval[𝑐, 𝑏] ⊂ (−∞, 𝑏](for instance continuous), then we set

𝑏

−∞

𝑓 (𝑥)𝑑𝑥 ∶= lim

𝑐→−∞

𝑏 𝑐

𝑓 (𝑥)𝑑𝑥 whenever it makes sense.

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Improper intergrals: definition – 1

Let𝑓 ∶ [𝑎, +∞) → ℝbe a function which is integrable on each subinterval[𝑎, 𝑐] ⊂ [𝑎, +∞)(for instance continuous), then we set

+∞

𝑎

𝑓 (𝑥)𝑑𝑥 ∶= lim

𝑐→+∞

𝑐 𝑎

𝑓 (𝑥)𝑑𝑥

whenever it makes sense.

Let𝑓 ∶ (−∞, 𝑏] → ℝbe a function which is integrable on each subinterval[𝑐, 𝑏] ⊂ (−∞, 𝑏](for instance continuous), then we set

𝑏

−∞

𝑓 (𝑥)𝑑𝑥 ∶= lim

𝑐→−∞

𝑏 𝑐

𝑓 (𝑥)𝑑𝑥 whenever it makes sense.

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Improper intergrals: definition – 2

Let𝑓 ∶ [𝑎, 𝑏) → ℝbe a function which is integrable on each subinterval [𝑎, 𝑐] ⊂ [𝑎, 𝑏)(for instance continuous), then we set

𝑏 𝑎

𝑓 (𝑥)𝑑𝑥 ∶= lim

𝑐→𝑏

𝑐 𝑎

𝑓 (𝑥)𝑑𝑥

whenever it makes sense.

Let𝑓 ∶ (𝑎, 𝑏] → ℝbe a function which is integrable on each subinterval [𝑐, 𝑏] ⊂ (𝑎, 𝑏](for instance continuous), then we set

𝑏 𝑎

𝑓 (𝑥)𝑑𝑥 ∶= lim

𝑐→𝑎+

𝑏 𝑐

𝑓 (𝑥)𝑑𝑥 whenever it makes sense.

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Improper intergrals: definition – 2

Let𝑓 ∶ [𝑎, 𝑏) → ℝbe a function which is integrable on each subinterval [𝑎, 𝑐] ⊂ [𝑎, 𝑏)(for instance continuous), then we set

𝑏 𝑎

𝑓 (𝑥)𝑑𝑥 ∶= lim

𝑐→𝑏

𝑐 𝑎

𝑓 (𝑥)𝑑𝑥

whenever it makes sense.

Let𝑓 ∶ (𝑎, 𝑏] → ℝbe a function which is integrable on each subinterval [𝑐, 𝑏] ⊂ (𝑎, 𝑏](for instance continuous), then we set

𝑏 𝑎

𝑓 (𝑥)𝑑𝑥 ∶= lim

𝑐→𝑎+

𝑏 𝑐

𝑓 (𝑥)𝑑𝑥 whenever it makes sense.

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Riemann integrals

• For which𝑝 ∈ ℝis the following improper integral convergent?

+∞

1

1 𝑥𝑝𝑑𝑥

• For which𝑝 ∈ ℝis the following improper integral convergent?

1 0

1 𝑥𝑝𝑑𝑥

• For which𝑝 ∈ ℝis the following improper integral convergent?

+∞

0

1 𝑥𝑝𝑑𝑥

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Antiderivatives

• Let𝑓 ∶ ℝ → ℝbe a continuous function.

Can all the antiderivatives of 𝑓 be written as 𝐹 (𝑥) =

𝑥 𝑎

𝑓 (𝑡)𝑑𝑡 where𝑎 ∈ ℝ?

• Find one function such that the above statement is true.

• Find one function such that the above statement is false.

(Additional question, not related to the above phenomenon) Find all the antiderivatives of𝑓 ∶ ℝ ⧵ {0} → ℝdefined by 𝑓 (𝑥) = 1

𝑥.

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Antiderivatives

• Let𝑓 ∶ ℝ → ℝbe a continuous function.

Can all the antiderivatives of 𝑓 be written as 𝐹 (𝑥) =

𝑥 𝑎

𝑓 (𝑡)𝑑𝑡 where𝑎 ∈ ℝ?

• Find one function such that the above statement is true.

• Find one function such that the above statement is false.

(Additional question, not related to the above phenomenon) Find all the antiderivatives of𝑓 ∶ ℝ ⧵ {0} → ℝdefined by 𝑓 (𝑥) = 1

𝑥.

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Antiderivatives

• Let𝑓 ∶ ℝ → ℝbe a continuous function.

Can all the antiderivatives of 𝑓 be written as 𝐹 (𝑥) =

𝑥 𝑎

𝑓 (𝑡)𝑑𝑡 where𝑎 ∈ ℝ?

• Find one function such that the above statement is true.

• Find one function such that the above statement is false.

(Additional question, not related to the above phenomenon) Find all the antiderivatives of 𝑓 ∶ ℝ ⧵ {0} → ℝdefined by 𝑓 (𝑥) = 1

𝑥.

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An example

What can you tell about the following integral?

+∞

1

1

𝑥

2

+ 𝑥 𝑑𝑥

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What’s wrong with the following computation?

1

−1

1

𝑥 𝑑𝑥 = [ ln (|𝑥|)]

1−1

= ln(|1|) − ln(| − 1|)

= 0

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A first step to the BCT – Homework

Let 𝑓 ∶ [𝑎, +∞) → ℝ a function such that:

• ∀𝑐 ∈ [𝑎, +∞), 𝑓 is integrable on [𝑎, 𝑐], and,

• ∀𝑥 ∈ [𝑎, +∞), 𝑓 (𝑥) ≥ 0.

Prove that

+∞

𝑎

𝑓 (𝑡)𝑑𝑡 is convergent if and only if

{∫

𝑐 𝑎

𝑓 (𝑡)𝑑𝑡, 𝑐 ∈ [𝑎, +∞)

}

is bounded from above.

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