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January16 ,2019 Part2:Antiderivativesandindefiniteintegrals Calculus!

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MAT137Y1 – LEC0501

Calculus!

Part 2:

Antiderivatives and indefinite integrals

January 16 th , 2019

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Initial Value Problem

Find a function 𝑓 ∶ ℝ → ℝ such that

• For every 𝑥 ∈ ℝ, 𝑓 (𝑥) = sin 𝑥 + 𝑥 2 ,

• 𝑓 (0) = 5,

• 𝑓 (0) = 7.

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Towards FTC

−1 1 2 3 4 5

−2

−1 1 2

𝑂

𝑦 = 𝑓 (𝑥)

Compute:

1

1 0

𝑓 (𝑡)𝑑𝑡

2

2 0

𝑓 (𝑡)𝑑𝑡

3

3 0

𝑓 (𝑡)𝑑𝑡

4

4 0

𝑓 (𝑡)𝑑𝑡

5

5 0

𝑓 (𝑡)𝑑𝑡

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Towards FTC (continued)

−1 1 2 3 4 5

−2

−1 1 2

𝑂

𝑦 = 𝑓 (𝑥)

Call 𝐹 (𝑥) =

𝑥 0

𝑓 (𝑡)𝑑𝑡. This is a new function.

• Sketch the graph of 𝑦 = 𝐹 (𝑥).

• Using the graph you just sketched, sketch the graph of

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Trig-exp antiderivatives

1 Compute 𝑑

𝑑𝑥 [ 𝑒 𝑥 sin 𝑥] , 𝑑

𝑑𝑥 [ 𝑒 𝑥 cos 𝑥] .

2 Use the previous answer to Compute

∫ 𝑒 𝑥 sin 𝑥 𝑑𝑥,

∫ 𝑒 𝑥 cos 𝑥 𝑑𝑥.

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A harder antiderivative

1 Compute 𝑑

𝑑𝑥 [arctan 𝑥] , 𝑑 𝑑𝑥 [

𝑥 1 + 𝑥 2 ] .

2 Use the previous answer to compute

1 (1 + 𝑥 2 ) 2

𝑑𝑥

Références

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