C OMPOSITIO M ATHEMATICA
S. B LOCH A. K AS
D. L IEBERMAN
Zero cycles on surfaces with p
g= 0
Compositio Mathematica, tome 33, n
o2 (1976), p. 135-145
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135
ZERO CYCLES ON SURFACES
WITH pg
= 0*S.
Bloch,
A.Kas,
D. Lieberman**Publishing Printed in the Netherlands
Let X be a
nonsingular projective algebraic
surface over thecomplex
numbers. We use the standard notationsKx
= Canonical bundle of XPg
= dimF(X, Kx)
rc = Kodaira dimension X = dim
Proj ~ F(X, Kx~n).
n>0
Alb
(X) = (group
ofC-points of)
the Albanesevariety
of X.In
addition,
we denoteby T(X)
the group of zerocycles
ofdegree
zeroon X which map to zero in Alb
(X),
modulo thoserationally equivalent
to zero. Bloch’s
conjecture [7]
asserts that pg = 0implies T(X) = 0.
Mumford
[3]
hasshown p, 0
0implies
T ~ 0. See also Roitman[4].
Weverify
theconjecture
under theassumption
that the Kodaira dimen-sion,
K, satisfies K 2. If X is anEnriques
surface we find that any twopoints
arerationally equivalent, contradicting
Severi’s assertion that this condition shouldimply H1(X, Z)
= 0. Theconjecture
isclearly
birational in X.
Note that if K 0 then X is either
rational,
or is birational to C xP’
where C is
nonsingular
and is theimage
of X ~ Alb(X).
In the formercase every
degree
zerocycle
on X isrationally equivalent
to zero. Inthe latter case every zero
cycle
on C xP’
isrationally equivalent
to acycle
on C x101
and the rationalequivalence
class(on C )
of thiscycle
iscompletely
determinedby
itsdegree
and itsimage
in Alb(X) =
Alb(C).
Hence we may assume 0 ~ 03BA 2. A
rapid glance through
theclassification of surfaces will reveal that in this range the
hypothesis
* Appendix: Zero cycles on abelian surfaces by S. Bloch.
** Research partially supported by Sloan Foundation Fellowship and NSF grant GP-28323A3.
pg = 0
implies
that X is in factelliptic.
Weverify
below that the associated Jacobian fibration J also satisfies pg = 0 and that theconjecture
for X isimplied by
that for J. Theirregularity q
isnecessarily
0 or 1. In the former case we show that J is rational and in the latter case weemploy
the classification of surfaces with pg= 0,
q = 1 to
complete
theproof.
These surfaces allprovide
counterexamples
to assertions made in[4b]
and[8].
The authorsacknowledge helpful
conversations with A.Roitman,
T.Suwa,
P.Murthy,
R.Swan,
and D. Mumford. The results in this paper have beenindependently
obtained
by
A. Roitman. The results for theEnriques
surface weresketched to us
by
M. Artin. His remarks form anintegral part
of thepresent
argument.REMARK 1: In
general
ourproofs
show thatgiven
X there exists aninteger
N ~ 0 such that N . T = 0. The result T = 0 then follows from:PROPOSITION 1: The group
T(X)
is divisible.(Hence given
N ~ 0 such that N - Z = 0 for all Z eT,
then since any W E T is of the formN-Z,
Z E T it follows W = N · Z =0.)
PROOF:
Let z(X)
denote thecycles
ofdegree
zero modulo rationalequivalence.
Notethat z(X)
isdivisible,
indeedgiven
W~ z(X)
thereexists a curve C and a
correspondence
Y on C x X such that W lies in theimage
ofY : Pico (C) ~ z(X) (e.g.
take C to be anonsingular
curveon X
passing through
allpoints
of W and Y to be thegraph
of theinclusion.) Noting
thatPico (C)
isdivisible,
one can "divide"W,
inY(Pico (C)),
hencein ¡(X).
In view of the exact sequence
and the
divisibility of e
andAlb,
the asserteddivisibility
of T isequivalent
to the assertion that N-torsionin z(X)
maps onto N-torsionin Alb
(X)
for all N. Now let C C X be a smoothhyperplane
section ofX. Note that for any
compact
Kahler manifoldM,
one has a canonicalisomorphism
Alb(M) ~ H1(M, R/Z), (by
the usual identification of Alb(M)
as the cokernel ofH,(M, Z) ~ H1(M, R).)
The N-torsion in Alb is therefore identifiable with theimage
ofH,(M, Z/NZ) ~ H1(M, R/Z)
(induced by
the exact sequence0 ~ Z/NZ~ R/Z ~N R/Z ~ 0.)
Thenatural
diagram
has
surjective
rows(Lefschetz Theorem),
hence the N-torsion in Alb(C)
maps onto that in Alb(X).
Ourrequired surjectivity
nowfollows
immediately
from the commutativediagram
REMARK 2: The above
proposition
is valid for X ofarbitrary
dimension. The
argument
also shows that the group of codimension pcycles algebraically equivalent
to zero modulo those --equivalent
tozero is divisible where -- denotes any
adequate equivalence
relation(in
the sense of Samuel
[6]). Indeed,
all suchcycles
come via correspon- dences fromjacobians
of curves, and thejacobians
are divisible. Weassume in the
sequel
that pg =0,
0:5 K 2 andemploy
the standard notations: K = canonicaldivisor, q
=irregularity;
Pr =h°(rK); X
=2 - 4q
+ h 1,1 denotes thetopological
Euler characteristic.PROOF: Indeed if
K2 0
then K0, ([5], VIII, § 1 )
while if K2 > 0 and 03BA ~ 0 then the Riemann-Roch estimate shows Pr growsquadrati- cally
in r whence K = 2.The Noether formula
K2 + ~ = 12(1- q + Pg)
becomeswhich combines with the definition
of X
toyield
whence either
(a)
q =1,
h 1,1 =2, X
= 0 or(b)
q =0,
h 1,1 =10,
X = 12.One has the well known
PROPOSITION 3:
If
K = pg = q = 0 then 2K = 0 and X is anEnriques
surface.
PROOF:
See,
forexample, [5], VIII, § 1.
The
Enriques
surface is known to beelliptic, (Kodaira [2]
refers for this result to[5], Chapter X, although
the result is notexplicitly
statedthere).
On the other hand all surfaces with K = 1 are known to beelliptic. Moreover,
if q = 1 thensince X
= 0 the Albanesemapping
X ~ E either is a
(locally analytically trivial)
fibration of X with fibre Fa curve of genus > 1
(in
which case K =1),
or hasgeneral
fibre a curveof genus 1 and nonreduced
special fibres, (c.f. [5], IV, §7).
Thus inevery case X admits an
elliptic
fibration 03C0 : X ~ B. Let J ~ B denotethe associated Jacobian
fibration, ([5], VII, §5,
or[1], II).
Fixing
a "multisection" Y C X for the map X - B(i.e.
a divisor onX
mapping finitely
toB )
one may construct a rational dominant mapf : X - J
as follows. LetY ~ 03C0-1(b) = ~ni=1, pi (b)
and mapX x B X x B .XBX ~ J by
where the qi are
points
of asingle general
fibreXb, b
=03C0(qi).
Definef by composing
with themultidiagonal.
Sincef
is dominant we see thatPr (J) S Pr (X),
inparticular pg (J)
= 0.PROOF: Note that the map
f
has a"quasi
inverse."Namely given
any
point
a E Jlying
over b E B there is aunique point qi(b)
on Xsuch that
qi(b) - pi(b) represents
a EPico (7T-1(b )).
The correspon- dence03BB : 03B1 - ~ni=1
1 qi satisfiesNow
given
anydegree
zerocycle
Z on X notice that thecycle
n2·Z - 03BB (f* (Z))
is carried on a finite number of fibres of 7r and theportion
of thecycle
carried on asingle
fibre isrationally equivalent
tozero on that fibre
(Abel’s Theorem).
Indeed,
if we fix a fibre03C0-1(b) = F ~ X
and let E C J be thecorresponding elliptic curve, F
is aprincipal homogeneous
space under E. We have03C11, ..., 03C1n ~ F,
and thecorrespondences f*
and Àare
given f or q E F,
a EE, by
Thus
the last
equality being
Abel’s Theorem on the genus 1 curve F(i.e.
,4(F) ~ E).
Hencen2Z - 03BB (f*(Z))~
0. If Z vanishes in Alb(X)
thenf *(Z)
vanishes in Alb(J),
and ifT(J)
= 0 we concludef*(Z) ~ 0,
and03BB(f*(Z)) ~
0. Thusn2Z ~
0.Consequently n2 · T(X)
= 0 and weapply
remark 1.
To conclude the
analysis
westudy separately
the cases q = 0 andq=1.
q = 0: "Recall the criterion of Castelnuovo that a surface is rational if P2 = q = 0."
We prove J is rational
by showing
P2 =0, employing
anargument
of Kodaira[ 1 ],
III. We have03C0 : J ~ B = P1 together
with a section0" : B ~ J. The fact that B = P1
follows,
e.g. because Alb(J)
maps onto Alb(B). Noting
that the canonical classKJ
is anintegral
combination of fibres of 7r[5], VII, §3,
one hasKJ
=1T*(KJ . u(B». By
theadjunction formula, KJ · a(B)
=KB - N,
where N is the class of the normal bundle of B in J. Thusho(J,
r ·Kj)
=ho(J, 1T*(r(KB - N))) = h°(B, r(KB - N)). However, since pg
= 0 we seeh°(B, (KB - N))
= 0.Since B =
PB necessarily KB -
N isnegative.
Thereforeh°(B, r(KB - N)) = 0
if r > 0 andPr(J) = 0.
q = 1: Let E = Alb
(X).
If the genus of the fibres 11’ : X ~ E exceeds 1then,
as notedearlier,
w is smooth and in fact X = F xE / G
where G is a finite group of translations on Eacting
on F x Eby g (f, e) = (cp(g)f,
e +g)
for a suitablehomomorphism
cp : G -Aut(F).
If thegenus of the fibres is 1 then
replacing
Xby
its Jacobian fibration wemay assume that 11’: X ~ E has a
section,
and hence isnecessarily
smooth and of the form
F x EIG
asabove, (c.f. [5], VII, §9).
Since G acts without fixed
points,
theglobal
2-forms on X will bethe G invariant
global
2-forms onF x E,
i.e. the tensors ofcp (G)
invariant 1-forms on F with
global 1-forms
on E. Since~(G)
invariant1-forms are
precisely
1-forms onF/cp(G),
we see thatpg(X)
= 0 isequivalent
to ¡pl ==FI cp (G).
Now let Z be any
degree
zerocycle
inT(X). Lifting
Z back toZ
on F x E we have
However since
F/G
is rational theequivalence
class Y of~g~G~(g) · qi
isindependent
of i. HencenZ~~iri (Y x pi). Finally
since X ripi = 0 we have
nÉ --
0.However n 2 -
Z is theimage
ofnZ
under F x E ~ X. Thus n2 ·Z ~ 0 and n2 ·
T(X)
=0,
asrequired.
REFERENCES
[1] K. KODAIRA: On Compact Analytic surfaces II, III. Ann. of Math. (2) 77 (1963) 563-626, 78 (1963) 1-40.
[2] K. KODAIRA: On the structure of compact complex analytic surfaces IV. Amer. J.
Math. 90 (1968) 1048-1066.
[3] D. MUMFORD: Rational equivalence of zero cycles on surfaces. J. Math. Kyoto 9 (1969) 195-204.
[4] A. A. ROITMAN: (a) Rational equivalence of zero cycles. Math. USSR Sbornik, 18 (1972) 571-588. (b) Ruledness of an algebraic surface with finite dimensional
nonzero group of classes of zero dimensional cycles of degree zero modulo rational equivalence. Funct. Anal. i Pril. 8 (1974) 88-89.
[5] I. R.
0160AFAREVIC,
et al.: Algebraic surfaces. Proc. Steklov Inst. Math. 75 (1965).[6] P. SAMUEL: Relations d’équivalence en géometrie algébrique. Proc. Int. Congress
Math. 1958, 470-487.
[7] S. BLOCH: K2 or artinian Q-algebras with application to algebraic cycles. Com- munications in Algebra. (To appear).
[8] O. ZARISKI: Algebraic Surfaces, Appendix by D. Mumford to the second sup-
plemented edition. Ergeb. du Math. 61 (1971).
[9] D. MUMFORD: Abelian Varieties. Oxford University Press (1970).
Appendix-Zero cycles
on an abelian surfaceSpencer
BlochIn contrast to the
above,
it isamusing
to see what can be said aboutthe structure of
0-cycles
on surfaces withPg ~
0. In thisappendix,
1consider the case of abelian and Kummer surfaces.
THEOREM
(A.1):
Let A be an abeliansurface
over analgebraically
closed
field
kof
characteristic 0. Let a,b,
c EA(k)
bepoints,
andwrite
(a) for
the rationalequivalence
classof
a. Then the zerocycle
is
rationally equivalent
to zero. Inparticular,
the mapis
bilinear,
anddefines
asurjection
THEOREM
(A.2):
Withhypotheses
asabove,
intersectionof
divisorsdefines
asurjective
mapTHEOREM
(A.3):
Let X be the Kummersurface
associated to anabelian
surface
A.Then e(X)
isisogenous
toT(A).
These theorems
give
some indication what sort of structure one canexpect T(X)
to have(in particular,
what sort of boundedness conditions one canhope for)
whenPg
> 0. Ageneral
référence for the results abelian varieties needed is[9].
Forexample
therigidity
lemmaused in
(A.4)
is found on page 43. For X C Aample divisor,
thefact,
used in(A.5) that 03B1~ Xa 2014
X defines anisogeny A - Pico (A)
followsfrom
Corollary 4,
page59,
and theorem1,
page 77. The fact that any abelianvariety
isisogenous
to aprincipally polarized
abelianvariety
is
essentially
theCorollary
on page 231.Some lemmas
It will be convenient to write
CH(X)
for the group of zerocycles
on a surface X modulo rational
equivalence.
We have exactsequences
Let
03BC : Pic(X)~Pic(X)~CH(X)
denote the intersection map, andz
let ii. be the restriction to
Pico (X) ~ Pico(X).
z
PROOF:
Clearly Image 03BCo ~ Z(X). Composing
with the mapZ(X) ~
Alb(X)
we obtain afamily
ofmaps i~ : Pico (X) ~
Alb(X) i~ (e) = q - e
parameterized by ~ ~Pico (X). By rigidity,
thisfamily
is constant, henceequal
to io =0-map. Q.E.D.
LEMMA
(A.5):
Letf : A’ ~ A
be anisogeny of
abeliansurfaces.
Assume
Image
03BC0,A’ =T(A’).
ThenImage
03BCo,A =T(A).
PROOF : Let d =
deg f
sof* f*
=multiplication by
d onCH(A).
Thefunctor
T(.)
is covariant and also contravariant for finite maps. SinceT(A)
is divisible(proposition
1 of thepaper)
weget
asurjection f* : T(A’) -» T(A).
Let X be a
non-degenerate (ample)
divisor onA,
X’ =f*(X)
on A’ .Then X’ is
non-degenerate,
so every element inPico (A’)
can bewritten in the form
For any
y’ E Pico (A’)
we haveby
theprojection
formulaLEMMA
(A.6):
Let A be aprincipally polarized
abeliansurface,
p E A a
point.
Letbe the intersection map. Then
2(p) ~ Image
g.PROOF: A
principally polarized
abelian surface is either aproduct
of two
elliptic
curves or thejacobian
of a genus 2 curve. In the former case the assertion is clear. In fact if A =A 1 x A2
and p =(p 1, p 2)
then(p) = 03BC[(A1 x {P2})~({P1} x A2 )].
Suppose
now A =J(C)
for C a genus 2 curve. TheImage of 1£
isstable under translation
by points a
EA,
so we may assume p EC 4 J( C).
Let(p)c E
Pic(C)
denote the class of p as a divisor on C.Since
Pico (J(C)) ~ ~Pico(C)
and(C - C)
=2,
we get2(p)c
EImage (Pic (J(C)) ~
Pic(C))
so2(p)
= C -(something
in Pic(J(C ))). Q.E.D.
LEMMA
(A.7):
Let A be an abeliansurface.
ThenT(A)
isgenerated
by cycles (a
+b) 2014 (a) 2014 (b)
+(0).
PROOF: This is clear if one thinks of
T(A)
= Ker(Z(A ) ~
Alb(A )).
Q.E.D.
LEMMA
(A.8):
Let A be an abeliansurface,
and let F EImage (g :
Pic(A )~Pic (A ) ~ CH(A )).
Leta, b ~
A and write Fa = Ta(F) for
the translation
of
Fby
a. Then(i)
Fa+b -Fa - Fb
+ F eImage (03BC0 : Pico (A)OPic,, (A ) ~ T(A)) (ii)
The map A x A -T(A ), (a,b) ~ Fa+b2014 Fa - Fb
+ Fis bilinear.
PROOF: Both assertions are linear in F so we may assume F = D - E for divisors D and E. Note for
example
that Db - D is squareequivalent
to zero soTa (Db - D )
isrationally equivalent
toDb -
D.Thus we have
so
Since e.g. Da - D is linear in a
(Theorem
of thesquare)
weget (ii)
aswell.
Q.E.D.
The theorems
THEOREM
(A.2):
Let A be an abeliansurface
over analgebraically
closed
field
kof
characteristic 0. Then the map 03BCo :Pico (A ) 0 Pico (A) - T(A) is surjective.
PROOF:
By (A.5)
we may assume A isprincipally polarized. By (A.6)
we have
2(0)
eImage g,
andby (A.8) (i)
we get2[(a + b) - (a) - (b)
+(0)] Image
li,,.By (A.7)
we conclude that thequotient
T (A )/Image
p,ois killed
by multiplication by
2. Since.T(A)
is divisible(proposition
1 ofthe
paper)
we getImage
03BCo =T (A ). Q.E.D.
COROLLARY
(A.9):
Let n8 : : A ~ A be theisogeny multiplication by
nfor
some n ~ Z. Then the maps(n8)*
and(n8)*
onT(A)
are bothmultiplication by n 2.
PROOF: The map
(n8)*
oismultiplication by
n onPico (A),
so theassertion for
(n8)*
follows from(A.8) together
with thecompatibility
of
products
withpullback.
Inparticular (n8)*
issurjective.
Since(n03B4)*(n03B4)*
=multiplication by n 4
we
get
that(n8)*
=multiplication by
n 2 alsoQ.E.D.
COROLLARY
(A.10):
Let A be an abeliansurface
and let X =A /±
1(with singularities resolved)
be the Kummersurface of
A. The rational mapf : A ~ X
induces asurjective isogeny
Since these
cycles
generateT(A),
it follows thatf *
issurjective.
f * f *
=2 ~ f*
anisogeny.
REMARK
(A.11) (i):
Roitman hasrecently
announced a result whichimplies T(X)
is torsion-free for any surface X.Using this,
one gets anisomorphism
between T(Kummer Surface)
andT (A).
(ii)
Theorem(A.3)
follows from(A.10) plus
the fact Alb(Kummer) = (0).
THEOREM
(A.1):
Let A be an abeliansurface,
and let a,b,
c bepoints of
A. Then thecycle
is zero in
T(A) . Equivalently,
the map 0394 : A x A ~T(A),
à(a, b) =
(a
+b )2014 (a)2014 (b)
+(0)
is bilinear anddefines
asurjection
is an
isogeny,
thenso we may assume as before that A is either a
product
of twoelliptic
curves or the
jacobian
of a genus two curve C. It follows from(A.6)
and
(A.8) (ii) (applied
to F =2(0))
that 2~ is bilinear. From(A.9)
Surjectivity
of L1 follows from(A.7). Q.E.D.
COROLLARY
(A.12):
Let X be asmooth, quasi -projective variety,
andlet A be an abelian
surface.
Let r be acycle of
codimension p on A x X.Let CHP
(X)
denote the Chow groupof
codimension pcycles
on X.Then the map
of
sets 0393 : A ~CH’(X),
is
quadratic,
i.e. theexpression
is linear in a and in b.
(Oblatum
24-111-1975 &2-111-1976) Math. Department
Brandeis
University Waltham,
Mass. 02154 U.S.A.Institut des Hautes Etudes
Scientifiques
91440 Bures Sur Yvette France