C OMPOSITIO M ATHEMATICA
D ANIEL B ÄTTIG H ORST K NÖRRER E UGENE T RUBOWITZ
A directional compactification of the complex Fermi surface
Compositio Mathematica, tome 79, n
o2 (1991), p. 205-229
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A directional compactification of the complex Fermi surface
DANIEL
BÄTTIG1,
HORSTKNÖRRER2
and EUGENETRUBOWITZ2
0 1991 Kluwer Academic Publishers. Printed in the Netherlands.
1 Université Paris-Nord, Villetaneuse and
2Eidg.
Technische Hochschule, Zürich Received 22 February 1990; accepted 15 October 19901. Introduction
Let r c
R3
be a lattice of maximal rank andLR(R3/r)
the Hilbert space ofsquare-integrable,
real-valued functions on the torusR3/0393. Let q
be inLR(R3/r).
For each
k~R3
theself-adjoint boundary
valueproblem
has a discrete
spectrum customarily
denotedby
The
eigenvalue 03B5n(k), n 1,
defines a function of k called the n th band function. It is continuous andperiodic
withrespect
to the latticedual to r.
The
physical
Fermi surface forenergy 03BB
is the setFphys,03BB(q):= {k~R3 | 03B5n(k) = 03BB
for some n1}.
For
example,
ifq(x)
= const, thenFphys,03BB(q)
is the union of thespheres
with b =
(bl, b2, b3)~0393#.
In section 3 we prove
THEOREM 1.
If q
is inL2R(R3/0393)
andif for a single
real À oneof
the componentsof Fphys,03BB(q) is a sphere (not necessarily
centered at apoint
in thedual lattice),
thenq is
constant.Actually,
weconjecture
that the same conclusion holds ifFphys,03BB(q)
contains analgebraic component
X. In section 3 we prove this with some further as-sumptions
on thealgebraic
surface X. Theseassumptions
are fulfilled if X is asphere
or anellipsoid.
To prove Theorem 1 we
complexify
the Fermi surface. The(lifted) complex
Fermi surface is defined
by
F03BB(q):= {k~C3| there
is a nontrivialsolution 03C8
inH2loc(R3)
of(
-0394 +q(x))03C8 = 03BB03C8, satisfying 03C8(x
+y)
=eik,03B3>03C8(x)
for all y in0393}
Clearly,
the dual lattice0393#
acts onFÂ(q) by k ~ k + b, b ~ 0393#. Furthermore,
wehave
FA(q) ~ R3
=Fphys,03BB(q)
thephysical
Fermi surface.It is easy to
show, using regularized
determinants(see [KT],
section1),
thatF03BB(q)
is acomplex analytic hypersurface
inC3.
The main purpose of this paper isto construct a directional
compactification
ofFA(q)
in the sense of[KT].
Theabove statement follows from the
analysis
of thepoints
added at"infinity"
and ageometric interpretation
ofBorg’s
theorem[Bo].
To
compactify F03BB(q)
we first embedC3
in aquadric Q lying
inP4.
For eachaffine
line g
={c + tb|t ~ R}
inR 3, where b,
c e0393#
and b isprimitive,
we blow up twodistinguished points
ofp4
that lie on thequadric Q,
toget, by using
inverselimits,
a space M. Denoteby El(g)
andE2(g)
thecorresponding exceptional
divisors.
THEOREM 2. The directional closure
of F03BB(q)
in the space M intersectsEl(g)
and
E2(g) along
curves bothof which
areisomorphic
to the one-dimensional Blochvariety(1)
Recall that in
[KT]
thecomplex
one-dimensional Blochvariety
forp(x)
EL2(R/lbl. Z)
isB(p) = {(k, 03BB)~
Cx C | there
is a non-trivialfunction 03C8
inHfoc(R) satisfying -03C8" + p(x)03C8 = 03BB03C8
and03C8(x
+Ibl. n)
=eik·(|b|·n)03C8(X)
for alln~Z}.
To
get
Theorem 1 weapply Borg’s
theorem[Bo]
in the versionof [KT]:
Assumep is real then
B(p)
contains acomponent
that is thegraph
of an entire function03BB(k)
if andonly if p is
constant. In section 3 we prove that if forexample Fphys,03BB(q)
is a
sphere,
its directional closure meetssufficiently
many one-dimensional Bloch-varietiesB(qg),
soB(g,)
isalgebraic
andtherefore qg
is constant.We
conjecture,
that for all q EL2(R 3/r)
and for each 03BB E C thecomplex
Fermisurface
F03BB(q)/0393#
is irreducible. In otherwords,
theconjecture
is that for any two irreduciblecomponents C1, C2
ofF03BB(q)
there is ab~0393#
such thatC2
= b +Cl
At the end of section 1 we prove the
conjecture
forsplit potentials.
Thatis,
weconsider
potentials
of the form(1)(b):= R3/0393 q(x)e-ib,x> dx
for b~0393#. Without loss of generality we assume thatR3/r
hasR3/r
volume one.
or
and show that
F03BB(q)/0393#
forsplit potentials
isalways
irreducible. The fullconjecture
for the discreteperiodic Schrôdinger operator
is proven in[Bä].
We say that the
physical
Fermi surfaceFphys,Â(q)
isnon-degenerate,
if somepiece
of it is a two-dimensional real surface. Forexample, Fphys,0(0)
={0}
isdegenerate.
It follows from theconjecture
that for a real03BB,
anon-degenerate
Fphys,03BB(q)
determines thecomplexified
Fermi surface andby
Theorem 1 theisospectral
classes of allaveraged potentials
qg.In
particular
we obtainTHEOREM 3.
If
q EL2(R3/r)
and the Fermisurface F phys,;.(q)
is the same asF phyS,;.( q’),
whereq’ is a split potential of
theform (1)
or(2)
then q alsosplits.
We further
conjecture that, generically,
thephysical
Fermi surface determinesthe
potential q
up to(obvious)
translations and reflections.2. The
compactification
First we construct a
compactification
ofC3
which serves as the ambient space for the directionalcompactification
ofF03BB(q).
Thiscompactification
ofC3
will beindependent
of q. Its construction is motivatedby considering
the free Fermisurface
F03BB(0)
which is the union of thequadrics
We want to
compactify C3
in such a way that the closures of the differentcomponents of F03BB(0)
intersect asnicely
aspossible.
If wecompactified C3
in thenaïve way to
p3
orP’
xP’
xP’
we would have toblow-up
many times before thecomponents of F03BB(0)
would be ingeneral position.
Instead we embedC3
in acomplex projective
3-dimensionalnonsingular quadric
by mapping (kl, k2, k3)
to(kl, k2, k3, ki
+k2
+k23, 1).
Theimage
of theembedding
is the
complement
inQ
ofThe closures of the
components
ofF03BB(0)
inQ
are the intersections ofQ
withthe
hyperplanes Hb
inp4 given by
If b ~ b’,
thenHb
nH’
is aplane
inP4.
It intersectsQoo in
the setDb,b., consisting
of two
points given by
theequations
One checks that
Db,b’
andDb..,b",
aredisjoint if b, b’, b",
b"’ do not lie on a line andthat
Db,b’ = Db",b"’
if these fourpoints
of0393#
are on a line.Thus,
apoint
ofDb,b’
lies
precisely
on thehyperplanes Hc
where c ~0393#
is on the linethrough
b and b’.So let us denote this line
by g
and thepoints Db,b, by D(g).
The group
0393#
actsby
translation onC3.
Oneeasily
sees that this action extends toQ
and thatc~0393#
mapsD(g)
toD(c
+g).
If b and
b’~0393#
are differentpoints
on aline g
= c 1+ Rc2 (c1, c2 ~ 0393#)
thenQ n Hb
andQ ~ Hb’,
have differenttangent planes
at thepoints
ofD(g).
Therefore,
we canseparate Q~Hb
andQ n Hb,, by blowing
up thepoints of D(g).
Precisely,
for eachline g
= CI +Rc, (ci,
C2 E0393#)
letM(g)
be the space obtained fromp4 by blowing
up thepoints
ofD(g), Q(g)
the strict transform ofQ
inM(g), Q~(g)
the strict transform ofQ~,
andE1(g), E2(g)
the twoexceptional
divisorsover the two
points
ofD(g).
So we introduce as
compactification
M ofC3
the inverse limit of all the spacesM(G),
where G is a finite set of affine lines andM(G)
is obtained fromp4 by blowing
up thepoints
ofg~G D(g),
definedby
the natural mapsM(G1) ~ M(G2)
for
G2
cG1.
In thefollowing
we are notgoing
to use this inverselimit,
but workdirectly
with the manifoldsM(g).
Aprecise
version of Theorem 2 stated in the introduction isTHEOREM 2’. For each
affine line g
={c+tb|t~R}; b, c ~ 0393#,
bprimitive,
there is a
subset 03A3(g) of c3
such thatfor
anyq ~ L2R(R3/0393)
the closureof F03BB(q) ~ 03A3(g) in Q(g)
intersectsE,(g)
andE2(g) along
curvesisomorphic
to theBloch-variety B(qg) of
the one-dimensionalpotential
Proof. Using
the actionof 0393# we
may assumethat g
passesthrough
theorigin,
i.e. that c = 0. After
rotating
andscaling
we further assume that b = b:=(1, 0, 0).
Then
We consider the
exceptional
divisorE1:= E1(g) lying
above thepoint (0, i, 1, 0, 0),
the otherplane
is treatedsimilarly.
Near thispoint
we takeas coordinates.
In the
blown-up
space M : =M(g)
we consider the chart with the coordinatessuch that
For convenience we
perform
thechange
of variablesIn these coordinates the
blow-up
map M -p4
isTherefore, Q(g)
has theequation
In
particular Q(g)
intersectsE 1
in theplane
z= 12
= 0.Finally,
the stricttransform of the
hyperplane Hb, b~0393#,
does not meetEl
ifh2 =1=
0 orb3 =1=
0.Further,
the strict transform ofH(b,,0,0)
intersectsE1
inRemember that the strict transform of
Q n Hb
is the curve of acomponent
of the free Fermi-surfaceF03BB(0),
and that the one-dimensionalBloch-variety
forpotential
zero isThis shows that
for q -
0 the union of the closures of thecomponents
ofF03BB(0)
meets
E1
nQ(g) along
a curveisomorphic
to the one-dimensionalBloch-variety
for
potential
zero. Observe however that the closure ofF03BB(0)
inQ(g)
isbigger
than the union of the closures of its
components.
This indicates that it is necessary for thegeneral
case to restrict the way one takes limits toEl.
Thisrestriction is made
precise by
the introduction of the set E(g).
Recall from
[KT]
that(without
loss ofgenerality
we assume4(0)
=0)
is an
equation
forF03BB(q)
outside of the free Fermi surfaceF03BB(0),
and that this determinant can becomputed by taking
limits of finiteprincipal
minors.In the coordinates
(l1, 12, J.l, z)
ofM(g)
the entries of the matrix for(-0394k+q-03BB)·(-0394k-03BB)-1
considered above areWe are interested in the restriction of the determinant of this matrix to
Q(g),
butfor the moment we consider it on all
M(g).
We block the matrix in the form
With this notation
This is the matrix whose determinant describes the
Bloch-variety
of theaveraged potential q.
outsideB(O).
Furthermore onQ(g)
nEl
={z = l2
=0}
thematrix B = 0 and D = 1.
We will
define Y- (g)
in such a way that the matrixF(1,, 12, J-l, z)
restricted to E(g)
converges in Hilbert-Schmidt norm toThe square of the Hilbert-Schmidt norm of
is bounded
by
We define
REMARK.
The second term in the definition of E(g)
is needed notonly
tocontrol the
Hilbert-Schmidt
norm ofFUI’ 12,
/1,z)
-F(1,, 0,
/1,0)
but also that of its derivativesôll F, al2F, ôgF.
Clearly,
the restriction ofdet2
F to E(g)
is continuous at z = 0:Therefore the intersection of
F03BB(q)
n 03A3(g)
withQ(g)
nE1 is
contained inB(q.).
We now want to prove the converse. For this we need information about the structure of E
(g)
in theneighbourhood
of anypoint
ofQ(g)
nE1.
PROPOSITION. For every
point p = (1*, 1*, 03BC*, 0) of E,(g)
andfor
all A > 0 there is aneighbourhood
Uof
p inM(g)
and an open set Zeehaving
0 as acluster
point
such thatProof.
We have to estimate the function S:=S 1 + 2 ,
wherenear z = 0 in a
neighbourhood
of(l*1, l2, 11*, 0).
We firstsubstitute «Z = : -
iw. Thenand
For
where
Observe that
So, using
theestimate |wb(l1, 03BC)| !lb21
for allb~0393#BZ·(1, 0, 0)
outside a finiteset
S(l1, 03BC)
c0393#
and the fact that the unionis finite we have:
Furthermore,
for each w in a disc of radius centered at wbThus,
theseregions
must be excluded since we want S to go to 0as |w|
~ ~.LEMMA 1. Let
Db(ll’ y)
be the discThen,
there exists aneighbourhood U2 of (1i, 03BC*)
such thatfor
all(11, 03BC)
EU2
theopen set
is not bounded.
Proof.
LetSR
be theshell {w~C|R|w|2R}.
We show thatG n SR
haspositive Lebesque-measure
for all Rbig enough,
evenSince,
there exists a
neighbourhood U2
of(11, li*)
such that for all(l1, 03BC) ~ U2
where
Therefore,
theLebesque-measure
Let R be
big enough,
such that Jn SR
=0.
SinceIWb(1!, 03BC*)|
2R andb ~J,
we have
1(11
+bl)2 - MI
=O(R),
i.e.b21
Const R. SoOn the other hand
meas(SR)
=O(R 2).
Thisimplies
Lemma 1.Now assume that for all R
big enough
and for all w E G withlwl R,
If we can show that this claim leads to a contradiction the
proposition
isproved.
So let us assume
(*).
ThenSince
limR~~ (meas(G
nSR)/meas(SR))
= 1(see proof
of Lemma1)
we havefor R
big enough.
We now calculate the left-hand side of the above
inequality.
Forsimplicity
wedo it for
l1=03BC=0 (g= 0).
We haveIf
IWbl
3R thenIf
|Wb|
3R then we can bound thisintegral by Therefore,
The first sum is bounded
by (since lwbl
3R and thereforeb21 3R)
For the second sum we first sum over
b 1.
The coefficient in the sum ismonotonically decreasing
in(bi) (if |b1|~0),
socomparable
withFor the
integral put
then thisexpression
is boundedby
This is
equal
toSo we
get
With the same methods one calculates
Comparing
bothexpressions
with(1)
leads to a contradictionof ( * ).
This proves theproposition.
REMARK. The method of
proof
does notgive
much information about the form of E(g),
i.e. of Z.However, by estimating
the functionS(ll , l2 , 03BC, z),
which defines 1(g), explicit- ly,
thefollowing
can be shown: Letand consider a direction y =
(b2, b3),
where y is aprimitive
vector ofExclude all
points
inon the line
Then on the
segment L03B3:= {t·03B3| [|03B3|]-1 t [|03B3|}
there arepoints
which donot lie on D and for these
points
w ELyBD
one hasfor
(l1, l2, 03BC) in a neighbourhood
ofWe therefore can reach w = ~ on 03A3
(g) by hopping
from asegment Ly
toanother
segment Ly, with )y’ ) > |03B3|.
We now prove Theorem 2’. We
already
observed thatSo we have to prove the
opposite
inclusion. Let us fix a smoothpoint
p =
(li, 0, 03BC*, 0)
ofQ(g)
nE,
nB(qg).
Forsimplicity
we assume that p does not lieon the free
Bloch-variety B(O)
inQ(g)
nE1. By
theproposition
there is aneighbourhood
Uof p
inM(g)
and an open subset Z of Chaving
0 as a clusterpoint,
such thatis contained in 03A3
(g).
LEMMA 2. The restriction
of
thefunction
to
T
has thefollowing properties (i) f(p)
= 0.(ii)
There is a constantC,
such thatfor
all z EZ, (/1’ l2,
J-l,z)
E U.(iii)
For any z~Z
themapping f(., z)
isdifferentiable
and(/1’ 12,
J-l,z)
~(~(l1,l2,03BC)f)(l1, l2, 03BC, z)
is continuous onT
are not both
equal
to zero.Lemma 2
implies
the theorem as follows: SinceQ(g)
intersectsEi
transvers-ally,
we can choose(l1, 03BC, z)
as local coordinates onQ(g) ~ =: V
near p(observe
that there exists an A > 0 such that|l2|
A·Izl
for allpoints
near p onQ(g)).
. Assume~f ~l1(p)
~ 0( the
other case is treatedsimilarly, using
~l2(03BC, z) ~03BC (p) = 0) and
consider the continuousmapping
am
defined
by
This
mapping
fulfills theassumptions
of the modification of theimplicit
functiontheorem described in
Appendix
1. Thereforep lies
in the closure of the zero-set off
in(Q(g) - Q~(g)) ~ T,
hence in the closure ofF03BB(q)
n X(g).
One knows that theequation defining
the one-dimensionalBloch-variety B(qg)
is reduced. So the smoothpoints
are dense in the zero-set off(l1, 0,
y,0)
and theproof
of thetheorem is
complete.
We now prove Lemma 2: Statement
(i)
isobvious, (iv)
follows from the factthat p
is a smoothpoint
ofB(qg). (ii)
Is a consequence of the definition of E(g)
and the fact that
det2
is continuous in the Hilbert-Schmidt norm.Similarly
wehave
so
(iii) again
follows from the definition of 1:(g).
COROLLARY. Assume that q is a real
potential
and thatF03BB(q)
contains analgebraic
component X.If
the closureX of
X inQ
contains oneof
the curveswith
c ~ 0393# then q
is constant.Proof.
For b E0393# - {0}
let gb be the line{c + tb | t ~ R}. Then X
contains all the setsD(gb), b~0393#. By
theproposition
above for eachb~0393#
the closure ofX n
03A3(gb)
inQ(gb)
meetsE1(gb)
andE2(gb) along
a(non-empty) algebraic
curve,namely
the intersection of the strict transformof X
withE1(gb)
resp.E2(gb).
Hence
by
Theorem 2’ the Bloch varieties of all theaveraged potentials qb
eachcontains an
algebraic component.
Aseach qb
isreal, Borg’s
theorem[Bo]
implies that qb
is constant.Therefore q
is constant.The
assumption
of thecorollary
is fulfilledif F03BB(q)
contains asphere
around apoint
of0393#.
In the introduction we
conjectured
thatF03BB(q)/0393#
isalways
irreducible.Assuming
thisconjecture
one could finish theproof
of Theorem 1 stated in the introductionimmediately:
If X were anyalgebraic component of F03BB(q) (e.g.
thecomplexification
of asphere)
thenby
Theorem 2’ there would be an affineline g
in each
direction,
such that X n1(g)
intersectsEi(g) (i
=1, 2) along
a curve. Thenone would deduce the fact
that q
is constant as above. In the next section we willsee
that,
under furtherassumptions
onX,
one does not need theirreducibility
ofF03BB(q)/0393#
tocomplete
theproof
of Theorem 1.We can prove the
conjecture
forsplit potentials.
PROPOSITION. Let r c
R3 be a
latticegenerated by the
vectors al, a2, a3 ER3
with(aI’ ai)
= 0(i
=2, 3).
Thenfor
allpotentials
with p1 e
L2(R/al . Z)
and P2 EL2(R2/a2Z
+a3Z)
the Fermisurface F03BB(p1 + p2)/0393#
is irreducible.
Proof.
LetB(pl) c e2
resp.B(P2) - C3 be
the one-, resp. two-dimensional Blochvariety
for thepotential
pi resp. P2 .Suppose
that(kl, 03BB1)
EB(pl)
withcorresponding eigenfunction 03C81(x1)
and(k2, k3, 03BB)~B(p2)
witheigenfunction t/12(X2,X3)’
thent/1(x):= 03C81(x1)·03C82(x2, x3)
is aneigenfunction
forTherefore the
image
of the mapis contained in the three dimensional Bloch
variety.
Since theoperator defining B(p, + p2)
has acompact
resolvent it follows from the method ofseparation
ofvariables that each
(kl, k2, k3, À)
EB(p,
+P2) corresponds
to aneigenfunction
ofthe form
03C8(x1)· 03C8(x2, X3), so j
issurjective.
Next consider the map n:
B(pl)
xB(p2) ~
C definedby 03C0((k1, 03BB1), (k2, k3, Â2» = 03BB1
+03BB2.
The restrictionof j to n - l(Â)
is asurjective
map from03C0-1(03BB)
toF..
In order to show thatF03BB/0393#
is irreducible it thus suffices to show that03C0-1(03BB)/0393#
is irreducible.By [KT],
Theorem 1 of section3,
the varietiesare irreducible. We can view
03C0-1(03BB)
as the fiberedproduct
ofB(Pl)
andB(p2)
with
respect
to the mapsand
This construction is
compatible
with the action of0393#,
andtherefore 03C0-1(03BB)/0393#
is a fiber
product
of two irreducible varieties withdim B(P2)
>1,
hence irreducible.The
proposition
above alsoapplies
topotentials
of the formas a
special
case. As described in the introduction one deduces Theorem 3 from thisproposition.
3.
Algebraic components
of the Fermi surfaceIf q
is a realpotential
and thephysical
Fermi surface contains anellipsoid
thenthe
complexification
of thisellipsoid
is analgebraic component
ofFÂ(q).
In thiscase one verifies that the closure of this
component
is transversal toQ 00
inalmost all
points
of the intersection.So,
Theorem 1 stated in the introduction isa
special
case ofTHEOREM 1’. Let q be a real
potential.
Assume thatF03BB(q)
contains analgebraic
component X whose closure
X
is transversal toQoo
at almost everypoint of X
nQ 00.
Then q is constant.For the
proof
it suffices to show thatIn this case
X
nQ~
contains one of the curvesand one can
apply
thecorollary
of theprevious
section. A firststep
towardsproving
the inclusion(*)
is to show thatpoints
ofX n Qoo
are all wellapproximable by
the curves{(k,
y,0)
EQ~ | k, b)
+ y =01.
Moreprecisely,
setD:=
{(03BA1, x2,
K3,1, 0)
EQoo 1 there
areM, 03C4
0 such that for b E0393# - 101
onePROPOSITION. Let q E
L2
be anypotential,
and let p =(K, 1, 0)
be apoint of D.
Then there is no
algebraic
componentof F03BB(q)
whose closure passesthrough
p and is transversal toQ~
at thispoint.
Its
proof
is similar to that of theProposition
and Lemma 2 of theprevious chapter:
one blows up thepoint
p E D inp4
and shows thatdet2 F,
whose zero set is the Fermisurface,
is different from zero near theexceptional
divisor. Thediophantine
conditions weimposed
on p are used toget
an upper bound for the Hilbert Schmidt norm of F -1. Thecomplete proof
isgiven
inAppendix
2.Now let C be a
component
ofX
nQoo,
and assume that C is not contained inb~0393# {(k,
y,0)~ Qoo | k, b)
+ y =01. Then,
C meets{(k,
y,0)
EQ~|y
=01
inonly finitely
manypoints,
i.e.is an affine curve.
By
theproposition
above C’r) D consists ofonly finitely
manypoints.
We want to show that this leads to a contradiction.Let
Do
be the set of allpoints [y]= [yl,
y2,y3]
inP2(R)
for which one - andthen all -
representative
y fulfills adiaphantine
estimatewith some
K, 03C4
0.Clearly
apoint (k, 1, 0)~Q~ with k ~
0 lies in D if itsimaginary part
1 mkrepresents
apoint
ofDo.
So let no : C’ -{(0; 1, 0)} ~ P2(R) be
the
projection (k, 1, 0)
~[Imk].
From what we said above it follows that theimage
of no intersectsDo
inonly finitely
manypoints.
On the other hand oneeasily
verifies thatP2(R) - Do
has measure zero. Henceby
Sard’s theorem 03C00 does not have maximal rankanywhere.
A firststep
towardsreaching
thecontradiction is
LEMMA. C’ is contained in a
plane.
Proof.
Let p =(K ; 1, 0) = (03BA1, 03BA2, 03BA3, 1, 0)
be a smoothpoint
of C’ where thetorque
of C’ is non-zero. Since no hasrank
1 at p anytangent
vectorv =
(vl, v2, v3)
to C’at p
fulfillsdet(Im k,
Re v, Imv)
= 0.Therefore,
we can find a linearchange
of variableswhere A is a
real,
invertible 3 x 3 - matrix such thatk 1 = v’1
= 0 at p. Withoutloss
of generality
we may assume thatIm k2
and Imk3
are different from zero. Inthese new variables C’ has the
parametrization
Since the
torque
of C’at p
is non-zero wehave 03B2
~ 0.The
image 03C00(C’)
has theparametrization (in
the coordinatey’ = Ay)
where the
components
of k’ on theright-hand
side are evaluated at p. For this map to haverank
1 for allpoints t
= tl +it2 in a neighbourhood
of 0 inC = R + iR one must have
In other words v’ is
proportional
to Imk’,
and hence v isproportional
to k. Thisshows that no has rank zero at every
point
of C’ where thetorque
does not vanish.If the
torque
of C’ is zeroeverywhere
then C’ is contained in aplane,
and thelemma is proven.
Otherwise, 03C00(C’)
is apoint [yo]
and thetangent
vector of C’ ateach of its smooth
points
isproportional
to yo . But then C’ is aline,
andagain
the lemma is proven.
Returning
to theproof
of Theorem1’,
if C c{(k, y, 0)~Q~ y
=01,
we arefinished. Otherwise there is y E
C3
such thatFrom the fact that no has
rank
1 one concludes that y is eitherpurely
real orpurely imaginary.
We discuss the case that y isreal,
the other casebeing
similar.Thus,
we may now assume thatWe want to show that y E
0393#. So,
assume thaty e 0393#. By
theproposition
aboveit suffices to show that C’ n D consists of
infinitely
manypoints.
First we show that almost all
points
of C’ fulfill the firstdiophantine
conditionin the definition of D. For this purpose we introduce the
following
notation: If(i.e. |Re k| = |Im k| and (Re k,
Imk> =0)
letv(k)
be the unit vector inR3
suchthat
Re k, Im k, v(k)
form an orientedorthogonal
basis. Alsoput
D - {v~R3 1 IVI = 1,
vb
for allb~0393# - 0
and there areonly finitel many b~0393#
such that|v - b |b|| 1
.A standard
argument (as
in[SM] §25,
p.191)
shows that thecomplement of D1
on the unit
sphere S2
hasLebesque
measure zero.LEMMA. For
any k
eC3 - {0} with k’ 1 + k2 + k23
= 0 andv(k)
eDl
there is K’ > 0 suchthat for all b~0393# - {0}
Proof.
Let E be theplane
inR3 passing through by 0,
Rek,
Im k. For anyb~0393#, K > 0 the set
is a
strip
centered at{03BE
EE (ç, b)
=0}
of width at mostFor all
b~0393# - {0}
outside a finite set S this width is at most4nk.
If K ischosen
sufficiently
small then none of thesestrips
contains both Re k and lm kSince
(b,k)
~ 0 for allb~0393# - {0}
we can shrink K such that|k, b>| 1:2
also for all b~S.
One sees that the map
C’ ~ S2, (k; 1, 0) ~ v(k)
has maximal rank almosteverywhere. Therefore,
for allpoints (k, 1, 0)
outside a set ofLebesque
measurezero in C’ there is K > 0 such that
|k, b>| K |b|2 for
allb~0393# - {0}.
Now let E’ be the
plane
inR3
One
easily
checks that the map C’ ~E’, (k, 1, 0)
~ Re k issurjective
andsubmersive.
Thus,
the Theorem l’ will be proven once we have shown LEMMA. The setof points
x in E’for
which there isK, !
> 0 such thathas
positive (in fact infinite) Lebesque
measure.Proof.
For each b E0393# - {0}
the setis a
strip
around the lineof width at most
The distance of this line
{x
eE’l x, b>
+ 1 =01
from thepoint 03B3 |03B3|2
on E’ is atmost
Therefore,
for R >0,
area
If -c > 2 and K is
sufficiently
small this area is smaller than2nR2,
the area of thewhole disc of radius R around
03B3 |03B3|2.
4.
Appendix
1Let Z be an open subset of
Rm,
that has zero as a clusterpoint,
and let V be aneighbourhood
of zero in R". Consider a continuousmapping
with the
following properties:
(i) F(O, 0)
= 0.(ii)
For z EZ
themapping F(·, z):
V - R" is differentiable and(x, z)
~Fx(x, z)
iscontinuous on V
x Z.
(iii) IF(x, z) - F(x, 0)| |z|03B1
for all xE JI;
z EZ (where
a is a real number >0).
(iv) Fx(0, 0)
is invertible.Then there exists a sequence
(xk, Zk)keN
in V x Z withZk -1=
0converging
to(o, 0)
such that
F(x,, Zk)
= 0.Proof. Using properties (ii)
and(iv)
we canapply,
for each fixed zE Z
near0,
the inverse
mapping
theorem toF(·, z).
So there exists an openneighbourhood Wl x W2 c
V x Rm of 0 such that for each z EW2
nZ
themapping
is
bijective, F-1
continuous andF(., z)(W1)
contains an open ball. Then themapping
defined
by
is
bijective
andG-1
is continuous.We have to show:
(0, z) ~ G(Wl
xW2
n V xZ)
for zsufficiently
close to 0.Fig.5
Observe that
by (i), G(Wl
x{0})
is an openneighbourhood
of zero in R" x{0}.
Using (iii)
we see thatfor |z|
smallenough
an open ball inG(Wi
x{z})
of R" x{z}
contains
101
x{z}.
This proves the modification of theimplicit
functiontheorem.
5.
Appendix
2: Proof of theproposition
ofChapter
3We blow up p in
P4.
In the blown up space there are coordinates11, l2, l3, z
suchthat
The
exceptional plane
Elying
over p is{z
=01. Suppose
that X is analgebraic component
ofF ;.(q)
whose closureX
passestransversally
toQoo through
p. Then the strict transform X’ ofX
would passtransversally through
apoint
(1, 2, 0)
of E. Then for allpoints (l1, l2, l3, z) in X
near to thispoint
thematrix
whose determinant describes the Fermi
surface,
isnon-invertible,
since the zeroset of this determinant contains X. In
particular,
at thesepoints
the Hilbert- Schmidt norm ofis at least one. The square of this Hilbert-Schmidt norm is bounded above
by
As X’ is transversal to E at
(, 0)
there is a constant A > 0 such that for allsufficiently
small z E C there exists l~c3
withIl - ll
AIzl
and(1, z)
~ X. Inparticular
the sum above isbigger
than one. This contradicts theLEMMA. Assume
that for
allb ~ 0393#
one has|03BA, b>
+1| M |b|03C4.
Let 03B5, A > 0 andbe
apoint
inC3.
Then there is a subset Zof
C -{0}
that has 0 as clusterpoint
such that
for
all z E Z and alll E C3
with|l-|
AIzl
Proof.
We consider thespecial case |03BA|
=1, = 0, À
=0,
thegeneral
caseis just
somewhat more
notationally
awkward. Putw:= -1
and define forb~0393#
z
We are
going
to show that there arearbitrary large
w E C for which03A3b~0393# fb(w) e’.
Thisclearly implies
the lemma. Observe thatThere is a finite set S c
0393#
such that for allb~0393# - S and
all w E C withone has
Put
:= max(4A, 2·03B5-1)
and denoteby D(b)
the disc of radius|03BA, b>+1|
around the
point b2 03BA, b>+1.
Then for allb~0393# - S (1) fb(w) 03B52
for all w E Cwith |w| > A, w ~ D(b),
(2) A|w|R fb(w)|dw
Adw| 8·03C0 |03BA, b>+1|2
.The second
inequality follows,
because one has tointegrate
a function smallerthan
over a
region,
where this latterexpression
is smaller thanE’. Therefore,
oneincreases this
integral,
if oneintegrates
this latter function over a ball of radius2R around
b2 03BA, b>+1. Thus,
We now
decompose 0393#
into sets of the formBy
thediophantine
estimate for x the set0393#(03B1, fi)
has finitecomplement
in0393#
whenever 03B2
-03C4, 03B1> 1.For r >
0,
denoteby Br
the ball of radius r inR3.
ThenThe first O-estimate is the
growth
of the volume in theregion
(Observe
that{x
eR3|1
+(K, x)
=0}
is a line inR3,
sincexi + x2 + 03BA23
=0.)
Thesecond estimate follows from the fact that for
b1, b2~0393#(03B1, 03B2) with |b1| Ib21
CLAIM. For any a
> 03B2
with03B2 ~ 3/2
and a -03B2 ~ 1/2 (i)
area({w~C|A H R, w E D(b)
for someb~0393#(03B1, 03B2)})
In
fact,
forb~0393#(03B1, 03B2)
The center
of D(b) is b2 03BA, b>+1 , which
has distance at leastIbl2 -a.
from theorigin.
So if R is
big enough D(b)
does not meet the shell Alwl
R unlessIbl2 -lX 2R.
ThereforeThis, together
with thegrowth
estimates for0393#(03B1, 03B2), gives part (i)
of the claim.Part
(ii)
is provenusing
theargument
at the end of theproof
of theproposition
in section 2.We now return to the
proof
of the lemma. It follows from the claim that one can find p > 0 andfinitely
manypairs (03B11, 03B21),..., (aN, 03B2N)
such that the union of the open intervals(03B2n, an)
covers[ - i, 1]
and such that for n =1,..., N
Since the
complement
ofNn=1 0393#(03B1n, 03B2n)
in0393#
isfinite,
thisimplies
thatAs we remarked above this
implies
thelemma,
and so theproof
of theproposition
iscompleted.
Acknowledgement
D.
Bâttig
thanks theForschungsinstitut
für Mathematik Zürich for itssupport.
References
[Bä] D. Bättig, A toroidal compactification of the Fermi surface for the discrete Laplace operator.
Preprint, ETH Zürich 1989.
[Bo] G. Borg, Eine Umkehrung der Sturm-Liouvilleschen Eigenwertaufgabe, Acta Math. 78, 1-96
( 1946).
[KT] H. Knörrer, E. Trubowitz, A directional compactification of the complex Bloch variety.
Comm. Math. Helvetici 65, 114-149 (1990).
[SM] C. Siegel, J. Moser, Lectures on Celestial Mechanics, Springer-Verlag 1979.