A NNALES DE L ’I. H. P., SECTION C
Y VES R ICHARD
L AURENT V ERON
Isotropic singularities of solutions of nonlinear elliptic inequalities
Annales de l’I. H. P., section C, tome 6, n
o1 (1989), p. 37-72
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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
Isotropic singularities of solutions of nonlinear elliptic inequalities
Yves RICHARD and Laurent VERON Département de Mathematiques,
Faculté des Sciences, Parc de Grandmont 37200 Tours
Vol. 6, n’ 1, 1989, p. 37-72. Analyse non linéaire
ABSTRACT. -
If g
isnondecreasing
functionsatisfying
the weaksingulari-
ties existence condition then all the
positive
solutions ofB 1 { o) B~ 0 ~
wheref is
radial andintegrable
in areisotropic
inmeasure near 0. We
apply
this result to solutions ofAu+g(u)=0
inparticular when g (r)
~ g(r)
or g(r)
= r(L: r)°".
Key words : Elliptic equations, fundamental solutions, singularities, convergence in
measure.
RESUME. -
Si g
est une fonction croissante sur ll~ verifiant la condition d’existence desingularites
faibles etf
une fonctionintegrable
radiale dansB (0),
alors toutes les solutionspositives
de du g(u)
+f dans B 1 (o)B~ 0 ~
sont
isotropes
en mesurepres
de 0. Nousappliquons
ce resultat auxsolutions de en
particulier quand
Classification A.M.S. : 35 J 60.
Annales de l’Institut Henri Poincaré - Analyse non linéaire - 0294-1449 Vol. 6,’89,/O 1 !37,%36155,60; Q Gauthier-Villars
0. INTRODUCTION
Let n be an open subset of
IRN containing
0 andS2’=S2Bf 0}.
In thepast
few years many results about the behaviour near 0 of apositive
functionsatisfying
or
( q > l. )
in Q’ have beenpublished ([1], [2], [7], [8], [11], [23]). Although
those
equations
are very different(existence
or nonexistence of acompari-
son
principle
between theirsolutions),
there exists agreat similarity
between them in the case N> 3 and
1 q N/(N - 2)
in the sense thatthere
always
exist solutionssatisfying
with
y > 0,
whichimplies
thator
holds in
D’(Q) ([23], [11])
whereSo
is the Dirac measure at 0 andC (N) _ (N - 2)
ifN >- 3, C (2) = 2 ~,
but the twoproofs
of thisphenomenon
run verydifferently.
In fact the mainpoint
to notice is that for a usatisfying (0.3)
uq isintegrable
near 0 and this leads us to a newtype
ofisotropy
which is thekey-stone
for thestudy
of isolatedsingularities
of
positive
solutions of nonlinearelliptic inequalities
of thefollowing type
Assume
N ? 3,
g is a continuousnondecreasing function defined
on[0,
+~) satisfying
the weaksingularities
existence conditionfe L1loc (S2)
is radial near 0 and u eC2 (Q’)
is apositive
solutionof (0 . 6)
inn’. T’he n
(i)
either there existsy E [0,
+oo )
such thatrN - 2 u (r, . )
converges inmeasure on
SN - ~
to ~y as r tends to0,
In the case N = 2 it is necessary to introduce the
exponential
order ofgrowth of g [20]
and we prove that under the same conditions on
f
and usatisfying (0 . 6)
inQ’;
then- = 0 we have either
(i)
or(ii) with x 2 - N replaced by
x~)
-
if a;
> 0 we have(iii)
either there exists y E[0, 2/a9 )
such that u(r,. )/Ln { 1/r)
converges inmeasure to Y on
S 1
as r tends to0, (iv)
or lim u(x)/Ln ( 1 /) x,)
>_2/a9 .
Those results
play
animportant
role for thedescription
of isolatedsingularities
ofnonnegative
solutions ofFor
example,
whenN > 3
we prove thatif g is nondecreasing
andsatisfies
the weak
singularities
existencecondition,
then any u EC2 (Q’) nonnegative
andsatisfying (0 . 9)
in Q’ is suchthat
converges to someas x tends to 0. This result extends to the case N = 2 with some minor modifications. An other
important
tool forproving
thistype
of result is Serrin and Ni’ssymmetry
theorem[12].
When g
hasnon positive
values we prove that when N ? 3 anynonnegative
solution u ~C2 (Q’) of (0 . 9)
is such thatrN - 2
u(r, . )
converges inL1 ( SN -1)
to some Y E
[0,
+oo)
as r tends to 0. Under a moderategrowth assumption
on g we prove that
1im
When N = 2 the situation isquite
x - o
more
complicated. Using
a result due to John andNirenberg
we prove thatwhen g
hasnon positive
values and isof exponential
orsubexponential
type anynonnegative
solution uof (0 . 9)
in Q’satisfies
The last section is devoted to the
study
of the behavior near 0 ofpositive
solutions of
Vol. 6, n° 1-1989.
in
SZ’ (a > o).
Thisequation
reduces to a Hamilton-Jacobiequation
insetting v = Ln + u
and v satisfieson
{ x E S2’ : u (x) >_ 1 ~.
If we setg (r) = r (Ln+ r)°‘,
it is clear that(0 . 7)
isalways satisfied,
hence for anyy ?
0 therealways
exist solutionssatisfying (0.3);
howeverVazquez
apriori
estimate conditionfor some ro > 0 is satisfied if and
only
if a > 2 and we prove thefollowing:
Assume N >_ 3 and is a
nonnegative
solutionof (0. 11)
inQ’;
then
’
(i)
either u can be extended to S2 as aC2
solutionof (0 . 11 )
in Q(ii)
or there existsy>O
such thatlim
-
if a>2
(iii)
either u behaves as in(i)
or(ii)
(iv) or u (x) = y (a, N) e03B3(03B1)|x|2/(2-03B1)(1+O(|x|2/(03B1-2))
near 0 with03B3
(03B1)
=(2 03B1-2
)2/(03B1-2)
and
y(a, N)
=e(a -
(N -1 ) (a - 2))/2 a. This result extends in dimension 2.The contents of this article is the
following:
1.
Isotropic
solutions ofelliptic inequalities
2.
Singular
solutions of Au= ± g (u)
3.
Singularities
ofAu = u (Ln + u)a.
1. ISOTROPIC SOLUTIONS OF ELLIPTIC
INEQUALITIES
Throughout
this section Q is an open subset ofN >_
2containing 0,
0 ~
and g is anondecreasing
function. For the sake ofsimplicity
we shall assume
that g
is continuous. IfN >_ 3
it is wellknown that thefollowing
conditionis a necessary and sufficient condition for the existence for any of a
solution ~ belonging
to someappropriate
Marcinkiewicz space ofin D’
(Q) [3],
orequivalently
of a solution ofin Q’ with a weak
singularity
at0,
that is such that[22].
If N = 2 the situation is more
complicated
and we define theexponential
order of
growth of g
[20],
and the condition y E[0,2/a9 is
a necessary and sufficient condition for the existence of afunction ~
EC2 (SZ’) satisfying ( 1. 3)
in ~2’ andMoreover for such a and
( 1. 2)
holds inD’ (S~’) [21].
Ourfirst result is the
following
PROPOSITION 1. 1. - Assume
g ( o) = o,
f E (Q) is nonnegative
and u EC2 (S~’)
is anonnegative
solutionof
in Q’.
If
v EC2 (BRB~
0~)
is a radialnonnegative
solutionof
in
0}
such that g(v
+b) ~ L1 (BR) for
some b >0,
then there existsa >_ 0 such that
for
any q E[ 1, oo )
where 03C9=inf
(u, (x)
=I x (2 -N if N
> 3 and p(x)
= Ln(1/|
x() if N
= 2.The main
ingredient
forproving
this result is thefollowing
theorem dueto Brezis and Lions
[5].
LEMMA 1. 1. - Assume N >_
2,
03C9 EL1loc (Q’) satisfies
039403C9 E
(Q’)
in the senseof
distributions inQ’,
Vol. 6, n’ 1-1989.
where a is some
nonnegative
constant and F EL1loc (SZ).
Then 03C9 E(SZ)
andthere exist a >_ 0 such that
in D’
(SZ).
LEMMA 1. 2. - Assume N >
2,
h EL1 (BJ
is radial and ~p is anonnegative
radial solution
of
in
D’(BRB{0}) [resp.
inD’(BJ].
Then there existsv E [o, + oo)
such thatlim lim
cp (x)/~, (x) = o].
xo xo
Proof -
From Lemma 1. 1 there exists v >_ 0 such thatin
D’ (Ba
and satisfies( 1.12)
in D’ Without any loss ofgenerality
we can assume that h isnonnegative
inB(0, R),
henceis
nonincreasing
and thenkeeps
a constantsign
near 0.Case 1. -
rN -1
on(0, £].
For nlarge enough
define0 _ ~,~ 1 on
[o, E]
and(r)
dr = -1. From( 1.12)
weget
0
Using
themonotonicity
ofrl’1-1
we deduce/~BN-1~ 2
which
implies
lim{ - )==()
and~ -. + ~
B~/
BM/Case 2. - on
(0, E]. Using
the same method as above weget
which
again implies ( 1. 16).
From
( 1. 16)
it is clear that limcp (x)/~ (x) = o.
Proof of Proposition
1. 1. - Let p be the even convex functiondefined on R
by
.and
let ~ s
be1 ~
u + v -h ~
u -Then
2
It is clear that and Moreover
We now set
0 ~ = G1
UG3
withand
VoL 6, n° 1-1989.
On
G3,
henceand
by
thecontinuity of g
there exists8 = 8 (x) E [o, 1]
such thatF _ g ( e u + ( 1- ®) v) +_ f.
If we assume forexample
thatv _ u _ v + ~,
thenF
_ g (u) + f
and 3 whichimplies
that4
We do the same and
finally
holds in
BRB~ 0 ~ .
We takenow ~ _ ~,
so theright-hand
side of(1.22)
isintegrable
inBR
and there exists such thatFrom Lemma 1. 2. ~s
(x)
remains bounded near 0 and it is thesame with cps = Moreover cps satisfies
in D’
( B~ .
Letand
be the
spherical
averages of cps and 03A6respectively, (r, a) being
thespherical
coordinates in
f~N~~ 0 ~,
thenApplying
Lemma 1. 2 we deduce that lim As a consequencewhich
implies (with
the uniformboundedness)
for any
+00).
As we deducewhich is
( 1. 9).
Remark 1. 1. -
As { ~~s ~ _ ~
isintegrable
inBR
andDEFINITION 1. 1. - Assume
(E, L, ~,)
is an abstract measure space where E is aa-algebra
of subsets of Eand
apositive
a-additive andcomplete
measure such a subset of measurable
functions
(for
the measureu)
with value in We say that converges in measure to some measurable function~r
as r tends to 0 if for any E > 0we have
It is
equivalent
to say that from anysequence {rn} converging
to 0 wecan extract a
subsequence {
suchthat {
converges toB)/ ~ 2014
a. e.on E as nk goes to +00.
The
generic isotropy
result is thefollowing
THEOREM 1. 1. - Assume N >_
3,
gsatisfies ( 1. 1 ), f E L1loc (S?’)
is radialnear 0 and u E
C2 (Q’)
isnonnegative
andsatisfies
in S~’. Then we have the
following
Vol. 6, n’ 1-1989.
(i) either rN - 2
u(r, . )
converges in measure onSN -1
to somenonnegative
real number y as r tends to0,
(ii)
orProof -
We recall that(r, ?) E ( o,
+oo )
x are thespherical
coordi-nates in
0 ~.
For ~, > 0 let v~ be the solution ofSuch a v~
exists,
is radial andpositive
near 0.As If
is radial it does not affect the behaviour near 0(see
Lemma1. 2).
From
Proposition
1. 1 there existsv (~,) >__ 0
such thatin
1 q + oo,
andv (~,) ~,
fromconvexity.
Moreover the function~, H v (~,)
isnondecreasing.
Case 1. - Assume lim
v (~.) = y
+ o~o. For we have( 1. 33).
3L -~ + o0
Assume ~ r~ ~
is some sequenceconverging
to0,
then there exists a sub-sequence {
such thatAs v
( ~,)
y and = y we deduce thatn~ -~ +00
for nk large enough
andFor ~,’ > ~, we repeat this
operation with ~ r,~ ~ replaced by ~ r"~ ~
and thereexists a
subsequence {
such thatFrom
(1.35)
and(1.36)
we deduce thatv (~,’) = v (~,) _ ~y
for~, > ~
whichimplies ( i) .
Case 2. - Assume lim
v (~,) _
+ oo. For b > 0 we call p the function~, ~ + o0
introduced in the
proof
ofProposition
1. 1 and for~, > o,
~ s = 1 2~ u + v ~. P( u - v + 3 ~.
From( 1. 22)
we haveMoreover converges to
v ( ~,)
in( 1 _ q + oo)
as rtends to 0. We consider now w = v" ~~~ the solution of
( 1. 32)
and we sety~’~
(s) = r"N 2 (r), ~s ( 5~ ~) _ ~ 2 ~s ( r,
~P(S) =.f ~r)-
Then
(1.32)
and(1.37)
becomewhere
k = k (N) _ (N - 2) ~4 -N»~N - 2~
andASN-
is theLaplace-Beltrami
ope-rator on
SN -1.
Consider a C °° function p such thatp E L °° ( f~), p=0
on-r
(
- ~,0), p’ > 0
on(0,
+oo) and j (r) =
Fromconvexity
andmonotonicity
we haveAs
j
d a C d a and as w’(s)
and03C9’03B4(s,.)
converges to in as s tends to 0 we deduce that
j (w’ -
da = 0 on(0, RN- 2/(N - 2)]
and w’ - orSN - 1
on
(O,RN-2j(N-2)]
andw’iõ~
orwhich
implies
and we get
(1.31).
Remark 1. 2. - If u satisfies
(i)
then v~,(x)
u(x)
in0 ~.
VoL 6, n° 1-1989.
Remark 1. 3. - If u is a radial solution of
( 1. 29),
u> 0,
inB~B~
0~,
then a
simple adaptation
of theproof
of Theorem 1.1 shows thatu (x)
admits a limit in[0, -~- oo ]
as x tends to 4.The 2-dimensional version of Theorem 1. 1 is the
following
THEOREM 1. 2. - Assume N
= 2, f~L1 (Q)
is radial near 0 andis a
nonnegative
solutionof (1 . 29)
in Q’. Then-
If ag
= 0 the alternativeof
Theorem 1. 1 holdswith x ~ replaced
by
Ln x~).
-
If a9
>0,
we have thefollowing
alternative(i)
either there exists anonnegative
real number ~y E[o, 2,~a9 )
such thatu
(r,. )/Ln ( 1 /r)
converges in measure onS 1
to y as r tends to0, (it)
orProof -
Case 1. -Assume a+g
= 0. We define03BD(03BB)
asAs
v(À)
isnondecreasing and VÀ
exists for every ~, > o we canproceed
as in theproof
of Theorem 1. 1 if limv (~,) _ ~y
+00. If~. --~ + o~
lim
03BD(03BB) =
+00 we introduce03C903B4
and v,, (03BB) = w as in Theorem 1. 1 and~. -~ +00
make the
following change
of variableHence w’
and 03C9’03B4
satisfieson
(T,
+oo)
xS~
and with the samefunction j
as beforeAs
t -1 (w’ - ~s)
converges to 0 inLl(Sl)
we deduceand we get
finally
Case 2. -
Assume a+g
>0 and set y = lim03BD(03BB). Clearly y 2/a9 .
Ify
2/a9
we canproceed
as in Theorem 1. 1. If y =2/aJ~
we get as in Case 1for any ~,
2
and x E0 ).
We can take inparticular
~, =2
= v(~,)
a9
a9
and we get
(ii).
2. SINGULAR SOLUTIONS OF Au =
+ g (u)
The first
application
of Theorem 1.1 is thefollowing
THEOREM 2 . 1. - Assume N >
3,
g is anondecreasing locally Lipschitz
continuous
function satisfying ( 1. 1 )
and u EC2 (Q’)
is anonnegative
solutionof
in Q’.
Then x
tl(x)
admits a limit in[0,
+oo]
as x tends to 0.Proof -
From Theorem 1. 1 we can assume that there exist y E[0,
+oo)
and a
sequence ~ r" ~ converging
to 0 such thatCase 1. - Assume
y > o.
For E > 0 set wE the solution of(we
may assume thatBR
cQ).
From maximumprinciple u _ w£
inT’~,
R.Let
us = u + wE { R),
thenand
finally
inr E. R
and there exists a sequenceconverging
to 0 and a function
satisfying -0394w+g(w)=0
in0 ~
suchthat { w~~ ~
converges to w in theCI-topology
of 0~.
Vol. 6. nC 1-1989.
Moreover
From Remark 1. 2
lim ! x IN-2 w (x) = y,
hence we deduce from Serrin and Ni’s results[12]
that w is radial and from(2 . 2)
and(2. 5)
If
w’ (s~ = w’ (rN - 2/(N - 2)) = rN - 2 w (r),
thenwe deduce is convex and
Case 2. - Assume
y = 0.
For E > 0 and v > 0 set the solution ofA s in case 1 we have
in
hE,
R. For 0 v’ v let v", be the radial solution of- w,,, +g (v~,) = C (1~ v’ ~o
in such thatv,,. = 0
onaBR.
Aslim
we deduce that for s smallenough
onaB~
~nd finally
and as in Case 1 there exists a
subsequence {
such that lim function w" inBR
such that w£, ,, conver- to w" in theC1loc topology
of0}
and we haveApplying again [12]
we deduce that w" is radial and as in Case 1 weget
thatAs v is
arbitrary
limI
xIN - 2
u(x)
= 0 and u can be extended to Q as aC2
x - o
solution of
(2. 1)
in Q.In the same way we can prove the two dimensional case
THEOREM 2. 2. - Assume N = 2 and g is a
nondecreasing locally Lipschitz
continuous
function defined
on l~+.If
u EC2 (Q’)
is anonnegative
solutionof (2 . 1 )
inQ’,
we have thefollowing:
-
if a9
=0u (x)/L n (1/I x I )
admits a limit in[0, + oo]
as x tends to 0;-
if a9
> 0 and gsatisfies
u
(x)/Ln ( 1/I
xI)
admits a limit in[o, 2/a9 ~
as x tends to 0.Proof -
Ifa9
= 0 weproceed
as in Theorem 2 . 1. Ifa9
= + ooand g
satisfies
(2. 14),
u can be extended to Q as aC2
solution of(2. 1)
in Q[21].
If 0
a9
+ oo we have two cases(i)
either there exists y E[o, 2/a9 )
and asequence ~ r,~ ~ converging
to 0such that
(it)
or lim u(x)/Ln (1/I
x()
>2/a9 .
In case
(i)
we have limu (x)/Ln ( 1 /I x I) = y
as in Theorem 2 . 1. In case(it)
x - o
we have an a
priori
estimate thanks to(2. 14) [21] :
near 0 for any E > o. This
clearly implies
THEOREM 2. 3. - Assume N >_
3,
g is acontinuous function defined
on[0,
+oo )
such that limg (r)/r = K for
some K > - oo and u EC2 (Q’)
is ar - + o~
nonnegative
solutionof
in Q’. Then there exists y E
[0,
+ao)
such that1’0l. 6, n~ 1-1989.
g
(u)
EL1loc (Q)
and u solvesin D’
(Q). If
we assume moreover thatfor
any oc,[i > 0,
theny = 0.
Proof. -
The fact that and u satisfies(2 . 20)
for somey >
0 isproved
in[5].
Ifu (r) [res.
g(u) (r)]
is thespherical
average of u[resp. g (u)]
thenin
0 ~
c Q’ and we deduce from Lemma 1. 2 thatfor some and
u
solvesin
D’(BR).
Whencey=y’.
Let us assume now thaty>0
and g satisfies(2.21)
for any a,~3 > o.
AsrN - 2 u (r, . )
converges to y inL1(SN-l)
itconverges in measure and for there exists
such that for any
r E (o, ro)
there exists a measurablesubset o(r)
cSN -1
such
that
and( rN - 2 u (r, a) - y I y/2
for Asg (r) >_ K’r - L and
u E there is no loss ofgenerality
to assume thaton
(0, + oo),
hence ’For p E
(o, ro]
and a ~03C9( p), y p2 -N
_ u(p, 6)
2 yp2 -N
and as g is conti- 2nuous, g
(u (p, ~)) ?
inf2 g y
2p2 -N , ~
g(2 -N)
As g satisfies(2 . 21)
weget
contradiction. Hence
Y = o.
Under an
assumption
ofmonotonicity
on g we get a much more accurate result:PROPOSITION 2 . 1. - Assume N >_
3,
g is anondecreasing locally Lipschitz
continuous
function defined
on[0,
+oo)
andu E C2 (Q’)
is anonnegative
solutionof (2. 18)
in S~2’. Assume also thatBR
c S~ and that there exists aradial continuous
function ~ defined
in0 ~
andsatisfying
T’hen
x ~N-2
u(x)
converges to somenonnegative
real number y when xtends to 0.
Proof -
From Remark1. 3 ~
x~N - 2 ~ (x)
converges to somey’ > 0
as xtends to 0. If
y’ = 0
thenlim
u(x)
= o. Let us assume thaty’
> o.x - o
From Brezis and Lions’ result
which
implies
thatand g
satisfies( 1. 1 ) .
From Theorem 2. 3 there exists such thatrN - 2 u (r, . )
converges to y in as r tends to 0. We consider now the sequence of functions defined
by
and for N > 1Then
u~
is radial and It is clear converges in(BRB~ 0 ~)
to a radial functionu
which satisfiesand
u >_ u.
As a consequence of Lemma 1. 2lim
Fromx - o
Remark 1. 2 lim
x IN - 2
u(x) =
y which ends theproof.
x1 0
Remark 2.1. - The
hypothesis
ofradiality
of 03A6 which is rather restrictive can be withdrown if we know that limu(x)=
+ ~ andVol. 6, n° 1-1989.
~ ~
sup u(x).
In that case we can consider thefollowing
iterative scheme withC~
= C andThen
u _ c~N ~N - ~ ~
converges inC o~ ( BR~{ U ~ )
to some~ -
satisfying
>_ u. As
(x) =
+ oo we deduce from Serrin and Ni’ results[12]
that 03A6- is radial and we canapply
Lemma 1. 2.PROPOSITION 2. 2. - Assume N >_
3,
g is anondecreasing locally Lipschitz
continuous
function defined
on[0,
+oo) satisfying for
some q >N/2.
for
any cpand 03C8
continuous andnonnegative
in S2’ such thatg( cp)
andg E
(SZ). If
u EC’.2 (S2’)
is anonnegative
solutionof (2 . 18)
inS2’,
thenconverges to some
nonnegative
real number y as x tends to 0.Proof -
From Theorem 2 . 3 we have(2 . 20)
for somey >_ 0
andg
(u)
E( S2) -
Case 1. -
Y = 0.
Without any restriction we can assume that U>E in0 ~
c SZ’ and we write( 2 . 20)
asin
0 ~
where d(x) _ (g (u) -
g{o))/u.
A s g(u) ( 2 . 32) implies
that and we deduce from
[18]
that either u has a removablesingularity
at 0 orwhich is
impossible
asy=0.
Case 2. -
y > o. Let Vy
be the solution ofv~, is constructed
using
anincreasing
sequence ofapproximate
solutions asin
[ 11 J,
in0 ~
and vr is radial. Let w be u - vr thenin with Then we deduce from
[18]
that either w has a removablesingularity
at 0 orwhich is
impossible
asRemark 2. 2. - Under the
hypotheses
ofProposition
2. 2 two nonnega- tive solutionsui (i =1, 2)
ofin D’
(SZ)
are such that ul - u2 E(Q).
As for thesolvability
of(2. 39)
we have
PROPOSITION 2. 3. - Assume N >_
3,
SZ is bounded with aC1 boundary
a~ and g is a
nondecreasing function defined
on[0,
+oo ), satisfying ( 1. 1 )
and g
(r)
= o(r)
near 0. Then there existsy*
E(0,
+oo]
with thefollowing properties:
(i) for
anyY E [0, y*)
there exists at least onenonnegative function u~C1 (03A9B{ 0}) vanishing
on aS2 solutionof (2 . 39)
inD’ (Q),
(it) for
y >y*
no such u exists.Proof - Step
1. Assume Q =BR. -
A function uvanishing
onaBR
is aradial solution of
(2. 40)
in D’(B~
if andonly
if the function v(t)
= u(r),
with t = r2 -
N,
satisfiesAs v is concave the last condition is
equivalent
toVol. 6, n’ 1-1989.
For
a > o,
let va be the solution of the initial valueproblem
defined on amaximal interval
~R 2 - N, T*)
If T* + oo then lim v°‘
(t)
= 0 as a consequence ofconcavity
and theret i T*
exists
TE(R2-N,T*)
such thatvt ( T) = o.
If T*=+oo and limvt (t) = 0
t -. +00
then the same relation holds with T = + oo . A s a consequence if no solution VCI of
(2 . 42)
satisfies(2. 41)
withy > 0
we haveand the
right-hand
side of( 2 . 43)
ismaj orized by
or
For E > 0 there exists
r~ > 0
such thataR 2 - N t ~ implies
Hence the
right-hand
side of( 2 . 45)
ismajorized by
or
Consequently
contradicting (2. 45).
As a consequence there exists a* > 0 such that for anyoc E (o, a*)
the solution u°‘ of(2. 42)
is defined on[R2 -N,
+oo)
andsatisfies
(2 . 41)
for somey > o.
Step
2. Thegeneral
case. - There exists R > 0 such that Q cBR.
Ify > 0
is such that there exists a solution v to(2. 40),
then for any Y E[o, Y]
the
sequence {
definedby
uo = 0 and forn > 1
increases,
ismajorized by v
in Q and converges to some u which vanisheson an and satisfies
(2. 39)
inD’ (Q).
For the same reasons, the set ofy > 0
such that there exists a
nonnegative
solution of(2. 39) vanishing
on an isan interval.
Remark 2. 3. - If lim
g (r)/r > 0
it isproved
in[11]
thaty*
+00. Ifr -~ + o0
we no
longer
assume thatlim g(r)/r=O
it can beproved
that for anyr-+O
Vo > 0
there existsRo > 0
such that for any Q cBRo
and anythere exists a solution u of
(2. 39)
in D’(Q).
The two-dimensional version of Theorem 2. 3 is the
following
THEOREM 2. 4. - Assume N =
2,
g is a continuousfunction defined
on[o, + oo)
such that lim and anonnegative
r -. + oo
solution
of (2. 18)
in SZ’. Then there exists ~y E[0,
+oo)
such thatg
(u)
E and u solvesin D’
(Q). If
we assume moreover thatfor
anya, ~ > 0,
theny = 0.
Vol. 6, nQ 1-1989.
Remark 2. 4. - When
a9
=0, Proposition
2. 2 which holds in the caseN = 2
with x ~ 2 - N replaced by provides
aninteresting
criterionfor
proving
thatfor some
Proposition
2 . 1 is also valid in the case N = 2(with
thesame
modifications).
We introduce now a class new of
g’s
defined on[0,
+oo)
which arethose
satisfying
and we have
[20]
THEOREM 2. 5. - Assume N =
2,
g is a continuousfunction defined
on[0, + ao) satisfying
limg (r)/r > -
oo and(2. 52)
witha9
+ oo andr -. + 00
is a
nonnegative
solutionof (2 . 18)
in Q’ and assume also(i)
eithera9
=0,
Then there exists ’Y E
0, a 2 9 + such that u - ’Y Ln 1 r
is locall .Y
bounded in 03A9.
Proof. -
The mainingredient
forproving
this is a theorem due to John andNirenberg ( [9],
Th. 7 .21 )
that we recall«Let u E
W 1 ~ 1 (G)
where G c S2 is convex and suppose that there existsa constant K such that
then there exist
positive
constant ~,o and C such thatwhere ~. _ ~.o
G
and u G1
From Theorem 2 . 4 there exists such that
u (r, . )/Ln ( 1 /r)
converges to y inL i ( S 1 )
as r tends to 0 and Setthen
in
D’(Q).
It is now classical that whereM2 (G)
is the usual Marcinkiewicz space over G. If we takeG = BR
then V w satisfies( 2 . 54)
for someK>O,
whichimplies
for some ex>O and
0p_R.
Case 1. - Assume
a9
= o. Then for any E > 0 we havefor some
K£ > 0
and any From(2. 57)
we haveIf
y > 0
we havefor p,
a > 1 and 7~ > 0( ~’ _ ~/( ~ -1 ) ) .
Weset a p E = a,
hencepE
= ay p
E/( a -p E) .
Hence for any p > 1 we can take E small
enough
so that ~’7~ 2 and As a consequenceg(u)ELP(Bp)
and Ify=0, ( 2 . 59) implies
that g(u)
E LP for any p E[1, oo)
and u E L°°Step
1. -0 2 .
A ssume the contrary that is>_ 2014.
> 0we have lim
g (r) _
+ oo and from Remark 1. 2r --~ + ao
where vY satisfies
Vol. 6, nO 1-1989.
in
D’ (B~, v~, = 0
on As a consequence[21]
limu (x) _
+00 and for~
xI
R’ smallenough
in
D~(B~).
As a consequenceB 2014. )2014~ ~!/
whichimplies
(n)
dx = +00, contradiction.Step
2. 2014 We claim that for any a>0 there existpe(0,R]
such that(2.57)
holds. We fix 0 R/ R and write w = w~ + w~ where Wi is harmonic inB~,
and take the value w on and w~ satisfiesin
BR,
and w2 = 0 on As V wl EL2 (BR,)
we deduceand for w2 we have
where C is
independent
of R’. As a consequence we getand the constant K in
(2. 55)
can be taken as small as we wantprovided G = Bp
and u isreplaced by
w. Thisimplies
that for any ex>O we can findpe(0, R)
such that(2. 57)
holds.Step
3: Endof
theproof -
From the definition ofa~ ,
for any E>0there exists
K£ > 0
such thatfor and we have from
(2. 59)
We take
[we
assumey > 0
other-whilefor any p > 1 and and
+ E), + E)
and= xyp (a9 + E)).
Asyag
2 there exist p >1, E > o,
a > 0such that 2 which
implies
g(u)
E(Q)
and we end theproof
as inCase 1.
Remark 2. 5. - If
a9
= + oo then y = 0 from Theorem 2. 4. In that caseit is
unlikely
that Theorem 2. 5 still holds. However weconjecture
thatlim u
(x)/Ln (1/I
xI )
= O.Concerning
the existence of solutions of(2. 49)
thefollowing
result canbe
proved
as inProposition
2. 3.PROPOSITION 2. 4. - Assume N =
2,
S2 is bounded with aC 1 boundary
aSZ and g is a
nondecreasing function defined
on[0,
+oo)
such thatag
E(0,
+oo] ]
and g(r)
= o(r)
near 0. Then there existsy*
E(O, 2/a9 ]
withthe
following properties:
(i) for
anyy E [O, y*)
there exists at least onenonnegative function u~C1 (03A9B{ 0}) vanishing
on ~03A9 solutionof (2 . 49)
in D’(Q),
(it) for
y >y*
no such u exists.Remark 2. 6. - If it is easy to see that
y*
existsonly
ifdiam.
SZ
is smallenough.
Moreover in that case* 2 - 2 .
a9
a3. SINGULARITIES OF
u)°‘
Our first result deals with the one-dimensional case
THEOREM 3. 1. - Assume u E
C2 (0, R)
is anonnegative
solutionof
Then:
-
ifOex2,
u
(r)
admits afinite
limit as r tends to0;
-
if a>2,
(i)
either u(r)
admits afinite
limit as r tends to0, (ii)
ornear 0 where
Vol. 6, nC 1-1989.
From
(3.1)
u is convex andu (r)
admits a limit inR+ U {
+~}
as rtends to 0. If this limit is
larger
than1, (3. 1)
isequivalent
toon some interval
(0, R’)
with the transformation u=ef}. Theorem 3 .1 isan immediate consequence of the
following
resultLEMMA 3 . 1. - Assume v E
C2 (0, R’)
is anonnegative
solutionof (3 . 4)
in
(0, R’).
Then-
if
0 a_ 2,
v remains bounded near0;
-
if
a>2(i)
either v remains bounded near0, (it)
orProof.
-Assuming
that u is unbounded near0,
thenlim u
(r)
= + oo = lim v(r)
and v isdecreasing
near 0. So we can defineand
( 3 . 5)
becomeHence h
(P) - ~ ~ e2 ~
P~ -~- 2e 2 P
dS.a
As
and
we get
as p goes to + oo, which
implies
Integrating (3.9) implies
thatv~2 - a)/2 (r) (if 0 a 2)
or Lnv (r) (if a = 2)
remains bounded near 0 which is a contradiction. So we are left with the
case a >
2,
lim v(r)
= + oo . From( 3 . 8)
we haver -~ 0
near
0, which implies
limr2/(03B1-2)v(r)=( 20142014 ) =03B3(a).
As a conse-quence
20142014
=201420142014L~~/(a-2)
and(3.10)
becomesu(r) y(cx)
Integrating (3. 11)
on(0, r)
for r smallyields
which
implies,
with(3.10),
Reasoning
as before weget
near 0 and
We assume now that Q is an open subset of
N > 2, containing 0,
Q’
= S2B{ 0 ~
and we consider thefollowing equation
in Q’where u E
C2 (Q’)
isnonnegative.
LEMMA 3. 2. -
If
03B1>2 andBR
cSZ;
then there exists a constant C = C( x, N, R,
dist( aBR, ~03A9)
such thatVol. 6, n‘ 1-1989.
/*f
Proo f -
We definet)°‘,
andAs T(2)
+ ~ we deduce fromVazquez’s
result that theequation ( 3 . 16)
satisfies the apriori
interior estimateproperty [19]:
ifxo E Q’ and if the cube
Qp (xo) = {
x E~N :
supx~ p }
is included inQ’,
then for anya E (o, 1)
there exists a constant such thatSo the main
point
is toget
aprecise
estimate oni - ~ .
If so >e°‘~2
and C(so)
°= 1 -
a it is easy to check that2 4 Ln so
.
j (t)
> C(so) t2 (L
nt)°‘
for t > so.If C °
(
03B1-2) 2
C(
so) , then i ( ) s C
for s>s0 and
for For
R,
cBR.
We setRo = min (1 2 R, 1 2 03C4(s0) )
and for
we canapply (3 . 18), (3. 19) which gives
The estimate in is
obtained
from( 3 . 18)
with asimple compactness argument
and weget (3.17).
LEMMA 3. 3. - Assume N >_
2,
a > 0 and v EC2 (BRB{
0~)
is anonnegative
solutionof
’