R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
P. C. C RAIGHERO A result on m-flats in A
nkRendiconti del Seminario Matematico della Università di Padova, tome 75 (1986), p. 39-46
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P. C. CRAIGHERO
(*)
RIASSUNTO - In questa nota si dimostra che
ogni
varieta VCm)diA~,
che siaisomorfa ad
Amk,
con m1/3(n - 1),
6 la trasformata di unsottospazio
li-neare
C tjlk
mediante un automorfismoglobale O: Ank - Ak
ilquale
risulta
prodotto
di automorfismi lineari etriangolari.
Come conse-guenza di cib si ha il fatto che
ogni
linea diAk,
con n > 4, risulta ele- mentarmente rettificabile.Introduction.
Let k be an
algebraically
closed field of characteristic zero. Anautomorphism W : Ak
which is theproduct
of linear and trian-gular automorphisms
is called tame. Avariety
5’(m) which isisomorphic
to will be called an m-flat. A 1-flat is called a line. Two varieties
Y’,
7 V" such that there exists anautomorphism O: Ank - Ank
withØ(V’)
=V",
will be calledequivalent.
An m-flat which isequivalent
to a linear
subspace
B(m) ofAfl
will be calledshortly
linearizable.A linearizable 1-flat will be called
rectifiable.
If an m-flat istransformed into a linear
subspace by
means of a tameautomorphism
of
Ak,
we say that ,~ ~~~ istamely
linearizable. InChapter
11 of[1],
p.
413,
Prof.Abhyankar
raises thefollowing interesting
Question:
is it true that inA7k,
with~~3,
there are m-flats whichare not
equivalent?
(*)
Indirizzo dell’A.: Istituto di MatematicaApplicata,
via Belzoni 7, 35100 Padova(Italy).
40
This
question
isexactly
the same as to ask thefollowing:
is ittrue that in
A~,
withn ~ 3,
there are m-flats which are not linearizable~In this paper we
give
apartial
answer to this lastquestion by showing
in Theorem1) that,
ifm c 3 (n -1 ),
any m-flat inAk
is ta-mely
linearizable. This has theinteresting
consequence that any line inA’
withn>4,
istamely rectifiable,
which corners down the pos-sibility
for a line not to be rectifiable inA~,
so thatConjecture 1),
p. 413 in
[1],
can be trueonly
for n = 3(in A§
every line istamely rectifiable,
as a consequence of the well known Theorem ofAbhyan-
kar and Moh
[2]).
On the otherhand,
inAk ,
there areexamples
ofrigid
lines which are very difhcult torectify, namely
the(see Conjecture 3), [1],
p.414).
However in aprevious
work[3],
wemanaged
torectify just C,, by
means of anautomorphism which, according
to aConjecture
of M.Nagata (see [4],
p.47),
should notbe tame
(we
recallthat,
forn>3,
it is notyet
known whether a nontame
automorphism
ofA~ exists).
Let us consider in
A~,
anarbitrary
m-flat~~m~,
withm c 3 (n -1 ) (of
course it will ben>4).
admits abiregular parametric
rep- resentationby polynomials:
with
T’1,
...k[Xl, ... , Xm]
andG1,
... ,Gm
E7~;~X1,
... ,Xn].
Let uscall a
straight
line a chord of if it meets in at least two distinctpoints.
The union of all the chords of is contained in the(uni- rational) algebraic variety V,
whoseparametric representation
iswhere 7
vl, ... , v,~, ~,
arealgebraically independent
over k.Of course dim
Y c 2m -E- 1.
It can be shown that TT contains also the union of all thetangent straight
lines to,~ ~~~,
which is containedin the
variety
W whoseparametric representation
iswhere U. ... , ~m , I
~,1, ... , A.
arealgebraically independent over k,
andmeans
of ifoXj
calculated in(U.
...,um).
Anyway,
even withoutproving
that W cV,
we have dimW 2m.
Let us embed
canonically A7k
inP~.
Let theprojective
clo-sures of
Y,
W andV 00 , Woo respectively
the intersectionsof V and
with the
hyperplane
atinfinity
We haveLet us
identify
’Jtoo withp~-l.
Sinceby assumption
it ism ~ 3 (n -1 ),
1we have
this means that in nro we can
surely
find a linearsubspace
ofdimension
m -1,
which does not interectW~ .
Now we canstate the
following
LEMMA 1. With the
previous notations,
any linearsubspace
8(m)o f
dimension m in
AJ,
such that8(m) n
nro =8:-1),
cannot meetmore than one
point;
moreover,i f it
meets onepoint P, it
cannotbe
tangent in
P toPROOF.
Suppose P’,
P" two distinctpoints
of .~ ~’~~ and that there exists an 8(m) such thatP’,
P" e 8(m) n.~ ~m>,
with 8(m) r1 _,~~-1’;
then the chord l of Y">
through P’,
P" is contained in8(m),
sothat 1
meets
8:-1)
and cannot meetby
consequence which isdisjoint
from
8f~~~~~ :
this is absurd because Next suppose P e 8(m) n and that 8(m) istangent
in P to.~ ~m~;
then everystraight
line l ofthrought P
istangent
in P to .~ ~m~ :again
this leeds to anabsurd,
because
42
Now choose n - m
hyperplanes
... , :77:n-m inA:,
so thatand, calling
11 a linearautomorphism
ofA~
such thatlet
be the
biregular parametric representation
of the m-flat ll(~’~~~)
thatwe obtain from
(*)
and(**)
aboveby applying
~1..Calling ~l
theextension of II. to
P"
we have of course that:(1) A(V), A(W)
are the varietiescontaining
the chords and the tan-gents
of~I(~~m~) ;
(5)
The above Lemma 1holds substituting respectively ~’cm), S(-)
7,~ (m) with
A(8°~», 1(8"’», (8~m»)oo’ ~(~ ) (m)
Now let us consider the linear
subspace
and let
be the
projection
ofA~
on to from We callthe restriction to
We can state the
following
LEMMA 2. With the
previous notations, 1p
is anisomorphic embedding.
PROOF. 1p
is a finitemapping (see [5],
Th.7,
p.50).
Of course3C ===
~1(~~)
is a smoothvariety.
y,by construction,
isinjective, because,
ifPl, P2
are two distinctpoints
of~l(,~ c~~)
such that- y~(P~)
=Q
E then the twosubspaces Bim)
andprojecting P1
andP2
from would coincide with~SQ ’, projecting Q
fromthis would then contradict Lemma 1
(modified according
to
(5) above). By
this same Lemma the differentialmapping of y
in
P, dp1p:
-_ ~Sc~-m~,
where is thetangent
space in P to thevariety X,
is anisomorphic embedding
for every .P e 3C ==
A(Y"». Indeed,
in our case, isexactly
the restriction to andsince,
2by
Lemma1,
wehave,
dP EX,
r10
=0,
then is
injective:
suppose in factP1, P2
two distinctpoints
of0p,x,
and suppose = thisimplies
_ =so that the
straight
lineI(Pl, P2)
is contained in n which is absurd because we would find(6~
n _0?
asabove, by
Lemma
1)
Beeing
a linearinjective mapping
between linearsubspaces
ofA~,, dpy
is anisomorphic embedding.
Now we canapply
the Lemmain
[5],
Ch.2,
p.124,
and concludethat 1p
is anisomorphic embedding.
COROLLARY 1. With the notations
o f
Lemma2,
theaffine variety
an
PROOF. Obvious:
y~(11(,~ ~~~))
isisomorphic
to which is anm-flat,
via y.REMARK 1. The
isomorphism (which
we callagain 1p)
has a
regular inverse,
thatis, 1p-l
isgiven by polynomials.
44
REMARK 2. For every
point
Y2’ ... , wehave, by
thechoice of
(s~m»)(X)
andso
that 1p
and1p-l
will haveequations
of thefollowing type
and where
(see
Remark1 )) H1,
... ,Hn
are suitablepolynomials
Ek[X1,
... ,
consequently
we haveand, by ( o o ) above,
we also havewhere we write
shortly F;
for ... ,Now we can prove the
following
THEOREM
1. Every m-flat
withtamely
linearizable.
PROOF. Let A be a linear
automorphism
such that the conditions forvalidity
of Lemma2,
and Remark 1 and 2 arefulfilled,
with thesame
notations,
y and consider theautomorphism
where 0
and X
arefollowing
tameautomorphisms
with obvious
meaning
of the notations ... , Wefind, by (7)
and(6)
abovewhich means that transforms our :F(m) into the linear
subspace
and our theorem is
proved.
In
particular
we can state thefollowing
remarkableCOROLLARY 2.
Any
lineof
withn>4,
istamely rectifiable.
46
PROOF.
Apply
Theorem 1 to 1-flats inA:,
withn>4:
we have1 c 3 (n -1),
so that any 1-flat ofAk,
withn > 4,
istamely
lineariz-able,
which is our statementaccording
to the nomenclature in the introduction.REFERENCES
[1]
S. S. ABHYANKAR, On thesemigronp of
ameromorphic
curve(Part 1),
Intl.
Symp.
onAlgebraic Geometry (Kyoto, 1977),
pp. 249-414.[2] S. S. ABHYANKAR - T. T. MOH,
Embeddings of
the line in theplane,
Journalfur die reine und angewangte Mathematik, Band 276, pp. 148-166.
[3]
P. C. CRAIGHERO, AboutAbhyankar’s conjectures
on space lines, Rendiconti del Seminario Matematico di Padova, to appear.[4] M. NAGATA, On
antomorphisms of K[X, Y],
Lecture in Mathematics(Kinokunija,
Tokio,1972).
[5]
I. SHAFAREVICH, BasicAlgebraic Geometry (Springer-Verlag, Berlin, 1977).
Manoscritto pervenuto in redazione il 6