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HAL Id: hal-02571549

https://hal.archives-ouvertes.fr/hal-02571549

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Degree as a Monoid

Harpreet Bedi

To cite this version:

Harpreet Bedi. Degree as a Monoid. 2020. �hal-02571549�

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Degree as a Monoid

1

Harpreet Singh Bedi bedi@alfred.edu

2

May 12, 2020

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Abstract

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In this paper ‘polynomial’ with degree as an ordered monoid say∆are constructed along with corresponding

5

schemes and line bundles O(d), d∈∆. The cohomology of these line bundles is then computed using ˇCech

6

cohomology. The last section of the paper gives new proofs of zero cohomology of affine schemes.

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1 Introduction

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In this paper it is shown that degree can be considered as an ordered monoid (denoted by ∆) for example

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Z0,Z[1/p]0,Q0,R0. In section 2 such polynomials (denoted by R[X0, . . . , Xn]) are constructed and corre-

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sponding affine schemes are described. The graded rings and Proj construction is given in section 4. The line

11

bundles are constructed in section 5 and their cohomology computed in theorems 6.1 and 6.3 given below.

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Theorem(6.1). LetS=R[X0, . . . , Xn]andX= ProjS, then for anyn∈∆

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1. There is an isomorphismS' ⊕nH0(X,OX(n)).

14

2. Hn(X,OX(−n−1))is a free module generated by monomials of negative degree.

15

Theorem(6.3). LetA=R[X0, . . . , Xn]andX= ProjA, m∈∆, thenHi(X,OX(m)) = 0for0< i < n.

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New proofs of vanishing theorems are given in section 7.

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2 Polynomials of degree

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LetBbe a ordered ring with additive identity denoted as0and underlying abelian group(B,+). Since, the ring is

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orderedB0forms an ordered monoid with operation+, for exampleZ0,Q0,R0. In this paper monoids of the

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formB0 will be considered and denoted by∆.

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2.1 Construction. Let ∆ be a monoid, R a commutative ring and X an indeterminate, then one can define

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polynomials with degree∆as finite sums

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(2.1) X

i

aiXi where aiR and X0:= 1.

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The addition is defined as

24

(2.2) f(X) =X

i

aiXi, g(X) =X

i

biXi, f(X) +g(X) =X

i

(ai+bi)Xi.

The multiplication by a monomialcXj, cR, j∈∆is given as

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(2.3) cXjf(X) =cXjX

i

aiXi =X

i

caiXi?j wherecaiRandi ? j∈∆,

where ? is binary operation in the monoid (which is addition by assumption). The multiplication by monomial

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can be extended inductively to multiplication by a polynomial. This ring will be denoted by R[X] and the

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multivariate version will be denoted byR[X0, . . . , Xn]. Since,∆ is ordered it is possible to talk about the degree

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of a ‘polynomial’, as the maximum element of∆in the polynomial.

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2.2 Example. The following examples illustrate the construction above.

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1. Z[X]Q0 consists of polynomials with coefficients inZand degree inQ0 for example1 + 2X−3X1/5.

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2. Z[X]R0 consists of polynomials with coefficients inZand degree inR0for example1 + 2X−3X1/

5.

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3. Z[X]Z0 consists of polynomials with coefficients inZand degree inZ0for example1 + 2X−3X5.

33

2.1 Zeros of Polynomials

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The ring R[X0, . . . , Xn] is well defined and thus it is possible to define affine schemes and projective schemes

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directly. In this section zeros of polynomials with degree∆are defined, and the constructions are used for proving

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Nullstellensatz.

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2.3 Definition. LetS be a commutative ring andϕt be a well defined homomorphism given as an evaluation at

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tS (along with the compatibility condition).

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(2.4) ϕt:R[X]S, X7→tS

compatibility condition {Xi}i7→ {ti}i The elementtSis called zero of a polynomialf(X)in the ringS iff(t)∈Kerϕt.

40

Notice that√

4 =±2 thus evaluating the polynomial X1/2−2 involves giving a choice (X, X1/2)7→(4,2) or

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(X, X1/2)7→(4,−2), the former map gives zero of the polynomial. The rational degree could give many possible

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solutions, but that is also true for standard algebraic geometry for example consider infintely many points that

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satisfy the equation of a circleX2+Y2= 1. These evaluation maps are not needed in the general theory of affine

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and projective schemes.

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2.4 Example. The following two examples, illustrate the definition.

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1. Consider the mapZ[X]Z[1/p]0→Z, then the evaluation mapX7→n∈Zmakes sense only forn= 0or1,

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sincepth power roots of other elements do not exist in the ring.

48

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2. The zero ofX

2−5

2∈Z[X]R0 is5(inRorC), sinceX

2−5

2∈Kerϕ5 whereϕ5:Z[X]R0→Ror

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ϕ5:Z[X]R0→C. Furthermore, the compatibility condition is satisfied since all real powers of5 exist in

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the ringRorC.

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2.5 Remark. The monoid∆ could as well be a matrix with addition as binary operation. In such a case the user

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needs to define ringsRandSappropriately. This can be done by carefully considering exponential and logarithm

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maps. For example, for matricesM andN defineMN= exp(NlogM)where

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(2.5) exp(A) =X

n0

An

n!, log(I+A) =X

n1

(−1)n1An n

and appropriate assumptions are made for convergence (such as assuming nilpotence, or a bound of one on singular

55

values etc.). This point of view helps make sense of evaluation maps for monomialsaXN as follows

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(2.6) aXN7→aMN wherea, M, N are Matrices which are ordered in∆.

The above idea can be extended linearly to form polynomials. This gives a ‘new algebraic geometry’ mixing linear

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algebra and polynomials.

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2.2 Affine Schemes

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LetA:=R[X0, . . . , Xn], sinceAis a ring,SpecAcan be endowed with Zariski topology with closed and open sets

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defined as follows

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(2.7) V(I) :={p∈SpecAsuch thatI⊆p},

D(f) := SpecA\V(f A).

2.6 Construction. LetfAof degree`∈∆then the elementfn, n∈Z0 can be defined as

62

(2.8) fn:=f × · · · ×f

| {z }

ntimes

and degfn= (`+. . .+`)

| {z }

ntimes

.

Hence, {1, f , f2, . . . , fi, . . .}i

Z0 is a multiplicatively closed, which can be used for localization. Recall that every

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ring is aZmodule, and this is reflected above in the powers.

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The theory of affine schemes can be applied to the ringA. IfMis anAmodule, then for any principal open subset

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D(f)ofSpecA, setM(D(f˜ )) =Mf where Mf is localizationofM with respect to the multiplicatively closed set

66

{1, f , f2, . . . , fi, . . .}iZ

0. This defines a sheaf onSpecAand is called the quasi-coherent sheaf.

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3 Nullstellensatz

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In this section the weak Nullstellensatz is proved by adapting [BSCG09, p 17-18] and [MP07, pp 15]. Letk be an

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uncountable algebraically closed field andA:=k[T1, . . . , Tn] such that the evaluation map

70

(3.1) (T1, . . . , Tn)7→(a1, . . . , an), aik

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is a well defined homomorphism satisfying definition 2.3.

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3.1 Theorem. LetI(k[T1, . . . , Tn] be a proper ideal withk algebraically closed and uncountable, andcountable.

72

ThenV(I)defined as

73

V(I) ={ykn|f(y) = 0for allfI} is non empty.

74

Proof. Using Zorn’s Lemma the ideal I(Ais contained within some maximal ideal mofA. Let B=A/mwhere

75

mis a maximal ideal and thusBis a field. Since, Bis generated overk by the monomials inT1, . . . , Tn and their

76

∆powers, the dimension dimkB (as ak vector space) is atmost countable overk. PickbB\k and consider the

77

family of elements

78

(3.2) 1

ab

, ak withbfixed.

This family is uncountable becausek is uncountable. Since,dimkB is countable, the elements of the family are

79

linearly dependent. Hence, there exists a relationship of the form

80

(3.3) λ1

a1b+. . .+ λj

ajb = 0for somej∈Z>0

Multiplying throughout byQ

i(aib)and settingai =Xgives a polynomialf(X)∈k[X]of degree>0 such that

81

f(b) = 0, showing thatb is algebraic overk. Since this holds for any arbitrarybB, the fieldBis algebraic over

82

k. But,kis algebraically closed, henceB=k.

83

Consider the images of T1, . . . , Tn in the field B =k, given as a1, . . . , an as in 3.1. If P(T1, . . . , Tn)∈ m then

84

P(a1, . . . , an) = 0or the point(a1, . . . , an)∈kn is inV(I).

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4 Proj Construction

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4.1 Graded Modules

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Recall that a ring or a module can be graded over a commutative monoid ∆ as in [Bou98, pp 363, Chapter

88

II, §1]. A ring A can be endowed with decomposition A=⊕d0Ad of abelian groups such that AdAeAd+e

89

for all d, e≥0 where d, e∈∆. Similarly graded Amodules can be defined with AdMeMd+e for all d, e≥0

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andd, e∈∆.A homogeneous ideal is of the form I =⊕d0(I∩Ad) and the quotientA/I has a natural grading

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(A/I)d =Ad/(IAd). Let ProjAdenote the set of prime ideals of Athat do not contain A+ :=⊕d>0Ad, then

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ProjAcan be endowed with the structure of a scheme. The closed and open sets for homogeneous idealsI are of

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the form

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(4.1) V+(I) :={p∈Proj Asuch thatI ⊆p}

D+(f) := Proj A\V(f A).

4.2 Localization

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LetU be a multiplicatively closed set ofR[X], then localization atU gives the ringR[X][U1]. An important

96

example is the multiplicatively closed setU={Xi}i

, note that1∈U sinceX0:= 1in (2.2).

97

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4.1 Example. The various avatars of multiplicatively closed setU={Xi}iin the ringR[X]are given as follows

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1. {1, X, X2, . . . , Xi, . . .}i

Z0 for∆=Z0,

99

2. {1, X, X2, . . . , Xi, . . .}i

Q0 for∆=Q0,

100

3. {1, X, X2, . . . , Xi, . . .}i

R0 for∆=R0.

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4.2.1 Localization of a module

102

LetMbe anAmodule andfA.

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The localizationMf has a∆grading (or underlying abelian group see remark 4.3 ) where homogeneous elements

104

of degreedare of the formm/fn wheremM, fAare homogeneous and

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(4.2) d= degm−(degf+. . .+ degf)

| {z }

ntimes

, degm,degf ∈∆

wherenis a positive integer and+is the binary operation of the additive monoid. The degree zero elements are

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denoted asM(f)Mf andA(f)Af, furthermore,M(f)is anA(f)module.

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4.2 Example. The polynomial ringA:=R[X0, . . . , Xn]Q0 is a gradedRalgebra andAd consists of polynomials

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of degreed∈Q0. The localization at the affine plane is given as

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(4.3) A(Xi)=R

"

X0 Xi

!

, . . . , Xn Xi

!#

Q0

.

4.3 Remark. The degree d after localization could be <0 due to subtraction as in (4.2), thus it will lie in the

110

underlying abelian group of the monoid(B,+).

111

5 Twisting Sheaves O (n)

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LetAbe a∆ graded and letn∈∆, define a new gradedAmoduleA(n)d:=An+d for alld∈∆, defineOX(n) :=

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A(n)e. Theedenotes the localization on the affine open. Thus, on D+(f) an affine open subsetOX(n)|D

+(f)=

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fnOX|D

+(f), furthermore, the usual equality holdsOX(n)⊗O

XOX(m) =OX(n+m).

115

5.1 Example O (1)

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Letkbe a field,∆=Q0 and considerProjk[X0, X1], the affine open sets areU0=D(X0) = Spec k[(X1/X0)]

117

andU1=D(X1) = Spec k[(X0/X1)].

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For example, consider the section of degree one.

119

(5.1)

Global Section X0+X01/5X14/5+X1

U1 (X0/X1) + (X0/X1)1/5+ 1 U0 1 + (X1/X0)4/5+ (X1/X0)

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The transition function from U1 to U0 is given as X1/X0. It is evident that the global sections of O(1) are

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infinitely generated by monomials of the form X0, X1, X0rX1(1r) where r∈ Q∩(0,1).For example consider the

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following degree one sections

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(5.2) X0, X1, X01/2X11/2, X01/4X13/4, . . . , X01/2iX111/2i, . . .

6 Computing cohomology

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6.1 Theorem. LetS=R[X0, . . . , Xn]andX= ProjS, then for anyn∈∆

124

1. There is an isomorphismS' ⊕nH0(X,OX(n)).

125

2. Hn(X,OX(−n−1))is a free module generated by monomials of negative degree.

126

Proof. 1. Take the standard cover by affine sets U={Ui}i where each Ui =D(Xi), i = 0, . . . , n. The global

127

sections are given as the kernel of the following map

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(6.1) Y

SXi

0

−→Y SXi

0Xi1

The element mapping to the Kernel has to lie in all the intersectionsS=∩iSXi, as given on [Har77, pp 118]

129

and is thus the ringS itself.

130

2. Hn(X,OX(−m))is the cokernel of the map

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(6.2) dn1:Y

k

SX0···Xˆk···Xn−→SX0···Xn

SX0···Xn is a freeRmodule with basisX0l0· · ·Xnln with eachliB(whereBis the underlying group of∆). The

132

image ofdn1is the free submodule generated by those basis elements with atleast oneli ≥0(that is atleast

133

oneli∈∆). ThusHn is the free module with basis as negative monomials

134

(6.3) {X0l0· · ·Xnln}such thatli<0

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6.2 Example. LetA=R[X0, . . . , Xn]Q0 in the theorem 6.1. In the second part the grading is given byP li and

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there are infinitely many monomials with degree−nwhereis something very small and∈Q0. Recall, that

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in the standard coherent cohomology there is only one such monomialX01· · ·Xn1 . For example, in case ofP2

138

we haveX01X11X21 but here we also haveX01/2X11/2X22.

139

Recall that in coherent cohomology of Pn the dual basis of X0m0· · ·Xnmn is given by X0m01· · ·Xnmn1 and the

140

operation of multiplication gives pairing. We do not have this pairing here, but we can pairX0m0 withX0m0.

141

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6.1 Zero cohomology

142

6.3 Theorem. LetA=R[X0, . . . , Xn]andX= ProjA, m∈∆, thenHi(X,OX(m)) = 0for0< i < n.

143

The proof is adapted from from [Vak17, pp 474-475]. We will work withn= 2for the sake of clarity, the case for

144

generalnis identical. Another proof for allnis given in section 7.

145

Proof. Start by writing down the ˇCech complex forn= 2.

146

U0 U0U1

⊕ ⊕

0 P2 U1 U0U2 U0U1U2 0

⊕ ⊕

U2 U1U2 ΓX0 ΓX0,X1

⊕ ⊕

0 Γ ΓX1 ΓX0,X2 ΓX0,X1,X2 0

⊕ ⊕

ΓX2 ΓX1,X2

Figure 1: ˇCech Complex forn= 2

The cohomology groups are zero if it can be shown that the image is equal to kernel. SinceΓX0X1X2 is localization

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of global sections its elements are fractions of the forma/b∈ΓX0X1X2, wherea∈Γ and there are four possibilities

148

forbwhich is formed by monomialsX0a0X1a1X2a2.

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1. All threeX0, X1, X2are inb, that is there are three negative exponents.

150

2. Only two ofX0, X1, X2are inb, that is there are two negative exponents.

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3. Only one ofX0, X1, X2 is inb, that is there is one negative exponent.

152

4. None ofX0, X1, X2is inb(orb= 1), that is zero negative exponent.

153

3negative exponents The monomialX0a0·X1a1·X2a2 whereai <0. We cannot lift it to any of the coboundaries

154

(that is lift only to0coefficients). IfK012denotes the coefficient of the monomial in the complex (Figure 2),

155

we get zero cohomology except for the spot corresponding toU0U1U2(as in theorem 6.1).

156

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0 0

⊕ ⊕

0 0 0 0 K012 0

⊕ ⊕

0 0

Figure 2: 3negative exponents

2negative exponents The monomialX0a0·X1a1·X2a2 where two exponents are negative, saya0, a1<0. Then we

157

can perfectly lift to coboundary coming fromU0U1, which gives exactness.

158

0 K01

⊕ ⊕

0 0 0 0 K012 0

⊕ ⊕

0 0

Figure 3: 2negative exponents

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1negative exponent The monomial X0a0·X1a1·X2a2 where one exponents is negative, say a0 < 0, we get the

159

complex (Figure 4). Notice thatK0maps injectively giving zero cohomology group.

160

K0 K01

⊕ ⊕

0 0 0 K02 K012 0

⊕ ⊕

0 0

Figure 4: 1negative exponent

Furthermore, the mapping in the Figure 5 gives Kernel whenf =g which is possible for zero only. Again

161

giving us zero cohomology groups.

162

K0 f

⊕ ⊕

0 0 0 g fg 0

⊕ ⊕

0 0

Figure 5: Mapping for1negative exponent

0negative exponent The monomial X0a0·X1a1·X2a2 where none of the exponents is negative ai >0, gives the

163

complex Figure 6.

164

K0 K01

⊕ ⊕

0 KH0 K1 K02 K012 0

⊕ ⊕

K2 K12

Figure 6: 0negative exponent

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Recall that SES of cochain complexesABC gives a LES and if the cohomology groups ofAand

165

C are zero, then cohomology groups of B are also zero. Consider the SES of complex as in Figure 7 .

166

The top and bottom row come from the1negative exponent case, thus giving zero cohomology. The SES

167

of complex gives LES of cohomology groups, since top and bottom row have zero cohomology, so does the

168

middle.

169

A 0 0 K2 K02K12 K012 0

B 0 KH0 K0K1K2 K01K02K12 K012 0

C 0 KH0 K0K1 K01 0 0

Figure 7: SES of Complex

170

6.2 Kunneth Formula

171

We can produce a complex forPn×Pm by taking tensor product of the corresponding ˇCech complex associated

172

with each space, and by the Theorem of Eilenberg-Zilber we get

173

(6.4) Hi(Pn×Pm,O(a, b)) = Xi j=0

Hj(Pn,O(a))⊗Hij(Pm,O(b)) a, b∈∆ Furthermore, we can define a cup product following [Liu02, pp 194] to get a homomorphism

174

(6.5) ^:Hp(Pn,O(a))×Hq(Pm,O(b))→Hp+q(Pn×Pm,O(a, b)) a, b∈∆

6.3 Derived functor and ˇCech cohomology

175

Recall the following theorem (see for example, [Vak17, pp 637, 23.5.1 ])

176

Theorem. IfF is a quasicoherent sheaf on a quasicompact separated schemeX, then the ˇCech cohomology agrees with

177

derived functor cohomology.

178

6.4 Proposition. LetS=R[X0, . . . , Xn] setX= Proj S, andF be the sheaf associated with ˇCech complex, then the

179

ˇCech cohomology agrees with derived functor cohomology.

180

Proof. Using the theorem above it needs to be shown that projective space associated with S is quasicompact,

181

quasicoherent and separated.

182

quasicompact : The projective space is covered by affine opens, and each affine open is quasicompact, sinceSpec

183

of a ring is always quasicompact.

184

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quasicoherence : The localization definition of quasicoherence is satisfied. At each affine openUi :={Xi} the

185

sheafF (Ui)is obtained via localization atXi.

186

separated : This follows from Proposition 3.6 [Liu02, pp 100] or a direct proof in Proposition 10.1.5 [Vak17, pp

187

281]. The open setsUi×Uj⊂Pn×Pn are of the form

188

(6.6) Ui×Uj= SpecR

"

X0 Xi

, . . . ,Xn Xi

,Y0 Yj

, . . . ,Yn Yj

#

, Xi Xi

−1,Yi Yi

−1

! .

The diagonal morphism corresponds to the mapUiUjUi×Ujleading to a surjective mapping of rings

189

(6.7)

R

"

X0 Xi, . . . ,Xn

Xi,Y0 Yj, . . . ,Yn

Yj

#

R

"

X0 Xi, . . . ,Xn

Xi,Xj Xi

#

Xk Xi

7→ Xk

Xi and Yk

Yj

7→Xk Xi

Xi Xj, which implies separatedness.

190

191

7 Vanishing Cohomology

192

In this section new proofs of vanishing cohomology of affine and projective schemes are given, without using any

193

computations. These proofs use ideas from [Vak17, Chapter 18] and [Sta20, tag01X8] but elimate all computation,

194

and hence, become ideal proofs to present in a classroom.

195

7.1 Remark. Recall that a short exact sequence of complexes0→ A → B → C →0leads to a long exact sequence

196

of cohomology groups.

197

(7.1)

. . . Hi(A) Hi(B) Hi(C) Hi+1(A) Hi+1(B) Hi+1(C)

. . .

δi1

δi

If the complexAis same asCbut shifted by one, thenHi(C) =Hi+1(A)which immediately implies thatHi(B) = 0

198

for alli >0.

199

7.2 Theorem. LetX= SpecAbe an affine scheme with finite covering by principal open subsetsU =Sn

i=1D(fi)and

200

F a quasicoherent sheaf onX. ThenHp(U,F) = 0forp >0.

201

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Proof. LetX be a scheme with open cover U=Sn

i=1D(fi)wheref1, . . . , fn generate the global sections. In other

202

words ifX= SpecA, thenf1, . . . , fn generateA. It is always possible to find a cover ofSpecAsince it is known to

203

be quasi compact for any ringA. Recall ˇCech complex

204

Cp(U,F) = Y

(i0,...,ip)Ip+1

F(Ui0...ip) = Y

(i0,...,ip)Ip+1

Mfi

0...fip whereM is someAmodule.

The problem is to show that the complex below is exact

205

(7.2) 0→M→Y

i0

Mfi

0

→Y

i0,i1

Mfi

0fi1→ Y

i0,i1,i2

Mfi

0fi1fi2. . .

Since, localization is an exact functor it is equivalent to check if the complex is exact after localization at a prime

206

idealp.

207

(7.3) 0→Mp→Y

i0

Mfi0p→Y

i0,i1

Mfi0fi1p→ Y

i0,i1,i2

Mfi0fi1fi2p. . .

Sincef1, . . . , fn generateA, there isfj<por fj lies in the complement of the prime ideal. Since localization at a

208

prime ideal is on the multiplicatively closed set which is a complement of the prime ideal this impliesMfj,p=Mp.

209

It is advisable to see example 7.3 now, since the rest of the proof is simply generalising it.

210

Consider the projection mapQ Mfi

0...fipp→Q

index,jMfi

0...fipp which gives rise to a short exact sequence

211

(7.4) 0→ Y

index=j

Mfi

0...fipp→Y Mfi

0...fipp→ Y

index,j

Mfi

0...fipp→0.

Note thatQ

index=jMfi

0=Mfjp=Mp(consists of only one indexj).The above SES now fits into the complex

212

(7.5)

A 0 Mp Q

index=jMfi

0fi1p Q

index=j

QMfi

0fi1fi2p . . .

B Mp Q

Mfi

0p Q

Mfi

0fi1p Q

Mfi

0fi1fi2p . . .

C Mp Q

index,jMfi

0p Q

index,jMfi

0fi1p Q

index,j

QMfi

0fi1fi2p . . . Notice that the first and the third row are the same, there is just a shifting by 1 in the first row and thus the remark

213

7.1 can be applied to give the result.

214

215

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7.3 Example. For example let three elementsf1, f2, f3generateAwithf1<pthen we have

216

(7.6) Mf1p=Mp, Mf1f2p=Mf2p, Mf1f3p=Mf3p and Mf1f2f3p=Mf2f3p

In the diagram below the second row is the ˇCech complex associate with the elements f1, f2, f3, the third row

217

consists of only those elements from second row which do not have f1. For example in the second row fourth

218

column there is an elementMf1f2pMf2f3pMf1f3p which projects to Mf2f3p in the third row. The first row is

219

simply the kernel of the projection map and these elements are rewritten according to (7.6). For example, looking

220

at the fourth column again there is a SES

221

(7.7) 0→(Mf2pMf3p) = (Mf1f2pMf1f3p)→Mf1f2pMf2f3pMf1f3pMf2f3p→0.

(7.8)

A 0 Mp Mf2pMf3p Mf2f3p

B Mp Mf1pMf2pMf3p Mf1f2pMf2f3pMf1f3p Mf1f2f3p=Mf2f3p

C Mp Mf2pMf3p Mf2f3p 0

Notice that the first and the third row are the same, there is just a shifting by 1 in the first row and thus the remark

222

7.1 can be applied to give the result.

223

The following example illustrates the zero cohomology groups associated with the projective space.

224

7.4 Example. The augumented ˇCech complex of a given degree associated with the projective space say P2

225

covered by∪n

i=1D(Xi)is given as

226

(7.9) 0→Γ →ΓX1⊕ΓX2⊕ΓX3→ΓX1X2⊕ΓX2X3⊕ΓX1X3→ΓX1X2X3→0.

In order to choose a primeXi<pfor somei= 1,2or3, we have to drop the termΓX1X2X3 (which contains all the

227

Xi and our prime should work for all degrees). The cohomology of the dropped term is computed separately. Let

228

X1<pwe also have to drop the localized avatarΓX1X2X3pX2X3p. In other words localization atpgives

229

(7.10) 0→Γp→ΓX1p⊕ΓX2p⊕ΓX3p→ΓX1X2p⊕ΓX1X3p→0,

which we want to show is exact. Copying example 7.3 gives the SES of cochain complexes below, and hence the

230

desired result of zero cohomology groups.

231

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(7.11)

A 0 Γp ΓX2p⊕ΓX3p 0

B Γp ΓX1p⊕ΓX2p⊕ΓX3p ΓX1X2p⊕ΓX1X3p 0

C Γp ΓX2p⊕ΓX3p 0 0

7.5 Theorem. LetA=R[X0, . . . , Xn]andX= ProjA, m∈∆, thenHi(X,OX(m)) = 0for0< i < n.

232

Proof. Let Pn be covered by open sets of the formSn

i=0D(Xi). If Γ denotes the graded global sections, that is

233

Γ =⊕mAm, then the corresponding ˇCech complex is given as

234

(7.12) 0→Y

i0

ΓXi

0

→Y

i0<i1

ΓXi

0Xi1→ Y

i0<i1<i2

ΓXi

0Xi1Xi2. . .→ΓX0···Xn

We want to localize the above complex with respect to a primepsuch that there is atleast someXj <p. Thus we

235

will be forced to drop the termΓX0···Xn since it contains all theXi of all degrees. Furthermore, we will also have to

236

drop any associated localizations. Thus, the localization at the end part is to be computed separately. The ˇCech

237

complex is also augumented at the start to make the cohomology zero.

238

We can now localize at the primeXj<pand follow the process outlined in the proof of theorem 7.2 to get a SES

239

of cochain complexes below which then implies the result.

240

(7.13)

A 0 Γp Q

index=jΓXi

0Xi1p . . .

B Γp Q

ΓXi

0p Q

ΓXi

0Xi1p . . .

C Γp Q

index,jΓXi

0p Q

index,jΓXi

0Xi1p . . .

241

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References

242

[Bou98] N. Bourbaki. Algebra I: Chapters 1-3. Actualités scientifiques et industrielles. Springer, 1998. (Cited on

243

page 4)

244

[BSCG09] M. Beltrametti, F.J. Sullivan, Ettore Carletti, and D. Gallarati. Lectures on Curves, Surfaces and Projective

245

Varieties: A Classical View of Algebraic Geometry. EMS textbooks in mathematics. European Mathematical

246

Society, 2009. (Cited on page 3)

247

[Har77] R. Hartshorne. Algebraic Geometry. Encyclopaedia of mathematical sciences. Springer, 1977. (Cited on

248

page 6)

249

[Liu02] Q. Liu. Algebraic Geometry and Arithmetic Curves. Oxford graduate texts in mathematics. Oxford Univer-

250

sity Press, 2002. (Cited on page 10, 11)

251

[MP07] C. Maclean and D. Perrin. Algebraic Geometry: An Introduction. Universitext. Springer London, 2007.

252

(Cited on page 3)

253

[Sta20] The Stacks Project Authors. stacks project. http://stacks.math.columbia.edu, 2020. (Cited on

254

page 11)

255

[Vak17] Ravi Vakil. Foundations of algebraic geometry. http://math.stanford.edu/~vakil/216blog/

256

FOAGfeb0717public.pdf, 2017. (Cited on page 7, 10, 11)

257

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