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Additional File 2 of ”Goodness-of-fit tests and nonparamet- ric adaptive estimation for spike train analysis”: proof of Theorem 2 of [1]

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Additional File 2 of ”Goodness-of-fit tests and nonparamet- ric adaptive estimation for spike train analysis”: proof of Theorem 2 of [1]

Patricia Reynaud-Bouret

∗1

and Vincent Rivoirard

2

and Franck Grammont

1

and Christine Tuleau- Malot

1

1Univ. Nice Sophia Antipolis, CNRS, LJAD, UMR 7351, 06100 Nice, France

2CEREMADE UMR CNRS 7534, Universit´e Paris Dauphine, Place du Mar´echal De Lattre De Tassigny, 75775 PARIS Cedex 16, France

Email: Patricia Reynaud-Bouret- [email protected]; Vincent Rivoirard - [email protected]; Franck Grammont - [email protected]; Christine Tuleau-Malot - [email protected];

Corresponding author

In this additional file, the intensityλ(.) should be understood as a function on the whole real line which is null outside [0, Tmax]. In particular, the Poisson processNa,n, with intensitynλ(.), exists now onR, but there is no points outside [0, Tmax] andNa,n(R) =Na,n([0, Tmax]). The proof is inspired by Proposition 2 of [2]. We set:

χ= (1 +η)(1 +kKk1)kKk2. Therefore, we have:

A(h) = sup

h∈H

(

kλˆh,hn −λˆKnh′k2−χp

Na,n(R) n√

h )

+

and

ˆh= arg min

h∈H

(

A(h) +χp

Na,n(R) n√

h )

. For anyh∈ H,

kλˆGLn −λk2≤A1+A2+A3, with

A1:=kˆλGLn −ˆλˆh,hn k2≤A(h) +χp

Na,n(R) np

ˆh , A2:=kˆλˆh,hn −λˆKnhk2≤A(ˆh) +χp

Na,n(R) n√

h

(2)

and

A3:=kˆλKnh−λk2. By definition of ˆh, we have:

A1+A2≤2A(h) +2χp

Na,n(R) n√

h . Therefore, by setting

ζn(h) := sup

h∈H

(

k(ˆλh,hn −E[ˆλh,hn ])−(ˆλKnh′ −E[ˆλKnh′])k2−χp

Na,n(R) n√

h )

+

we have:

A1+A2 ≤ 2ζn(h) + 2 sup

h∈HkE[ˆλh,hn ]−E[ˆλKnh]k2+2χp

Na,n(R) n√

h

≤ 2ζn(h) + 2 sup

h∈HkKh⋆ Kh⋆ λ−Kh⋆ λk2+2χp

Na,n(R) n√

h

≤ 2ζn(h) + 2kKk1kKh⋆ λ−λk2+2χp

Na,n(R) n√

h . Finally, since (a+b+c)2≤3a2+ 3b2+ 3c2,

E[(A1+A2)2] ≤ 12E[ζn2(h)] + 12kKk21kKh⋆ λ−λk22+12χ2E[Na,n(R)]

n2h

≤ 12E[ζn2(h)] + 12kKk21kKh⋆ λ−λk22+12χ2kλk1

nh . For the last term, we obtain:

E[A23] = Z

Var(ˆλKnh(x))dx+kKh⋆ λ−λk22

= 1

n2 Z Z

Kh2(x−u)nλ(u)dudx+kKh⋆ λ−λk22

= kλk1

nh kKk22+kKh⋆ λ−λk22. Finally, replacingχwith its definition, we obtain: for anyh∈ H,

EkλˆGLn −λk22 ≤ 2E[(A1+A2)2] + 2E[A23]

≤ 2(1 + 12kKk21)kKh⋆ λ−λk22+ 2(1 + 12(1 +η)2(1 +kKk1)2)kλk1

nh kKk22+ 24E[ζn2(h)].

The result follows by using the next lemma.

Lemma 1. If H ⊂ {D1: D= 1, ..., Dmax}with Dmax=δnfor some δ >0, and ifkλk<∞, then there exists a constantC depending onδ, η,kKk2,kKk1,kλk1 andkλk such that for anyh∈ H

E[ζn2(h)]≤Cn1.

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Proof. First, we notice that for anyh∈ H ζn(h) ≤ sup

h∈H

(

kλˆh,hn −E[ˆλh,hn ]k2+kˆλKnh′−E[ˆλKnh′]k2−χp

Na,n(R) n√

h )

+

≤ sup

h∈H

(

(kKk1+ 1)kλˆKnh′ −E[ˆλKnh′]k2−χp

Na,n(R) n√

h )

+

≤ (kKk1+ 1)Sn, with

Sn:= sup

h∈H

(

kλˆKnh−E[ˆλKnh]k2−kKk2(1 +η)p

Na,n(R) n√

h

)

+

. We then have:

E[ζn2(h)]≤(kKk1+ 1)2(A+B) with

A:=E[S2n1{Na,n(R)(1α)2nkλk1}], B:=E[Sn21{Na,n(R)>(1−α)2nkλk1}] for allα∈(0,1). We have:

Sn2 ≤ 2 sup

h∈HkλˆKnhk22+ 2 sup

h∈HkE[ˆλKnh]k22

≤ 2n2sup

h∈H

Z dx

Z

Kh(x−u)dNa,n(u) 2

+ 2 sup

h∈HkKh⋆ λk22

≤ 2n2sup

h∈H

Z Z

Kh2(x−u)dNa,n(u))dx×Na,n(R) + 2 sup

h∈HkKh⋆ λk22

≤ 2n2sup

h∈H

kKk22

h ×Na,n(R)2+ 2 sup

h∈H

kKk22

h kλk21

≤ 2δnkKk22

Na,n(R)2

n2 +kλk21

. Therefore,

A≤4δnkKk22kλk21×P(Na,n(R)≤(1−α)2nkλk1).

To bound the last term, we use, for instance, Inequality (5.2) of [3] (withξ= (2α−α2)nkλk1 and with the functionf ≡ −1), which shows that there existsα >0 only depending onαsuch that

P(Na,n(R)≤(1−α)2nkλk1)≤exp(−αkλk1×n).

This shows that

A≤CAn1,

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whereCA depends onα,δ,kKk2 andkλk1. Now, we deal with the term B by fixing the previous valueα:

we setα= min(η/2,1/4). This implies

(1 +η)(1−α)≥1 + η 4 and

B = E[Sn21{Na,n(R)>(1α)2nkλk1}]

≤ E

sup

h∈H

(

kˆλKnh−E[ˆλKnh]k2−(1 + η4)kKk2

pkλk1

√nh

)2

+

=

Z + 0

P

sup

h∈H

(

kλˆKnh−E[ˆλKnh]k2−(1 +η4)kKk2

pkλk1

√nh

)2

+

≥x

dx

≤ X

h∈H

Z + 0

P

 (

kλˆKnh−E[ˆλKnh]k2−(1 +η4)kKk2

pkλk1

√nh

)2

+

≥x

dx.

To conclude, it remains to control for anyx≥0, the probability inside the integral. For this purpose, we apply Corollary 2 of [3] and we set

U(x) = ˆλKnh(x)−E[ˆλKnh(x)] = 1 n

Z

Kh(x−u)dNa,n(u)−(Kh⋆ λ)(x).

IfAis a countable dense subset of the unit ball ofL2(R), we have:

kUk2 = sup

a∈A

Z

a(t)U(t)dt

= sup

a∈A

Z a(t)

1 n

Z

Kh(t−u)dNa,n(u)− Z

Kh(t−u)λ(u)du

dt

= sup

a∈A

Z

ψa(u)(dNa,n(u)−nλ(u))du, with for anya∈ Aand anyu∈R,

ψa(u) = 1 n

Z

a(t)Kh(t−u)dt.

We have for anyu,

ψ2a(u)≤ 1 n2

Z

a2(t)dt Z

Kh2(t−u)dt=kKk22

n2h . So, ifb= kKk2

n

h, kψak≤b.We have E[kUk22] =

Z

E[U2(t)]dt= Z

var(ˆλKnh(t))dt= kλk1

nh kKk22,

(5)

which implies

E[kUk2]≤ pkλk1

√nh kKk2. Finally,

v := sup

a∈A

Z

ψ2a(x)nλ(x)dx

= sup

a∈A

Z Z a(t)

n Kh(t−x)dt 2

nλ(x)dx

≤ 1 n

Z

λ(x)dx Z

a2(t)|Kh(t−x)|dt Z

|Kh(t−x)|dt

≤ kKk21kλk

n .

Corollary 2 of [3] gives: for anyǫ >0, for anyu >0, P kλˆKnh−E[ˆλKnh]k2≥(1 +ǫ)

pkλk1

√nh kKk2+ r12

nkKk21kλku+ 5

4+32 ǫ

kKk2 n√

hu

!

≤exp(−u).

Then, we conclude by using exactly the same computation as in the proof of Lemma 1 of [4, p 32-34] that gives:

B≤CBn1, whereCB is a constant depending onδ, η,kKk2,kKk1andkλk.

The lemma leads to the result.

References

1. Reynaud-Bouret P, Rivoirard V, Grammont F, Tuleau-Malot C:Goodness-of-fit tests and nonparametric adaptive estimation for spike train analysis. Tech. rep., http://hal.archives-ouvertes.fr/hal-00789127 2013.

2. Doumic M, Hoffmann M, Reynaud-Bouret P, Rivoirard V:Nonparametric estimation of the division rate of a size-structured population.SIAM J. Numer. Anal.2012,50(2):925–950.

3. Reynaud-Bouret P: Adaptive estimation of the intensity of inhomogeneous Poisson processes via concentration inequalities.Probab. Theory Related Fields 2003,126:103–153.

4. Doumic M, Hoffmann M, Reynaud-Bouret P, Rivoirard V:Nonparametric estimation of the division rate of a size-structured population. Tech. rep., http://hal.archives-ouvertes.fr/hal-00578694 2012.

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