A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
P IERO V ILLAGGIO
The shape of the free surface of a unilaterally supported elastic body
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 18, n
o4 (1991), p. 525-539
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it is
possible
find theprofile
of the freeboundary
and describe itsregularity.
1. - Introduction
The
prototype
of a unilateralproblem
in two-dimensional linearelasticity
is the
following.
An elastic thin diskoccupies
a domain D cR 2.
Theboundary
s of D consists of two parts r and
r’,
the first of which is a rectilinear segmentinitially resting
on arigid plane support
which may be taken as the x-axis ofa Cartesian system of coordinates
(Fig. 1).
Fig.
1Pervenuto alla Redazione il 30 Marzo 1991.
The
supporting plane
excludesdisplacements
in the direction of thenegative y-axis,
whereastangential displacements
are allowed since contactis assumed to be smooth.
Regarding
exteriorloads,
there areonly
tractionsapplied
on the part r’ of theboundary,
thebody
forcesbeing
assumed zerofor
simplicity.
The tractions exerted on r’ mustsatisfy
certain conditions ofcompatibility
able to ensure that D does not slidealong
the x-axis nor losecontact with it. If
Px
andPy
are the components of the resultant of surfacetractions,
these conditionsrequire
thatPx
= 0and Py
0.The existence of weak solutions to the
problem
isnowadays
a classicalresult of the
theory
of variationalinequalities.
As Fichera[ 1972]
and Lions andStampacchia [1967]
have proven with differenttechniques,
there is aunique
solution
belonging
to the Hilbert spaceH 1 ~2 (D)
such that thedisplacement
component v
along
they-axis
is greater than orequal
to zero on r. It is thusnatural to ask how smooth the solutions are. In the case of two-dimensional
elasticity,
Kinderlehrer[1981] ] proved
thecontinuity
ofsolutions,
but this result could not be extended tohigher
dimensions.Recently
Schumann[1989]
proved
that the property also holds for an n-dimensional elasticbody,
butwithout
determing
theprecise
value of the Holder exponent, a E(0, 1).
.. But, besides the
question
ofregularity,
theshape
of the part of r which leaves theplane
y = 0, whenever thishappens,
is still unknown. Theexplicit
construction of these
pieces
of freeboundary is,
ingeneral, extremely
difficulteven in
relatively simple geometric
situations. The case considered here is lim-iting,
in the sense that Doccupies
the entirehalf-plane
y > 0 and r is the whole x-axis. Inaddition,
the loads have certainsymmetries
so as togive
inadvance some idea of the
shape
of the detached set. But,having
constructed the solution in terms ofelementary functions,
theproperties predicted by
theabstract
theory
can then be checked with theformulae,
whichshow,
forinstance,
that solutions are of class with
a -
at thepoints
where the elasticbody
leaves its support.
2
2. - A contact
problem
for a semi-infinite diskLet V be an elastic disk of thickness 2h,
sufficiently
small with respect to its other transversaldimensions,
and let x, y, z indicate the axes of a Cartesian reference system such that the x,y-plane
coincides with the middleplane
of thedisk,
so that the faces areplanes
with theequations z
= ±h. The section of the diskthrough
its middleplane
is aregion
D of the x,y-plane,
withboundary
S.In this
specific
case, D is ahalf-plane
and the x, y-axes canalways
beplaced
in such a way that it
occupies
the upper part y > 0 of theplane (Fig. 2).
Fig.
2The disk is made up of an
elastic, homogeneous, isotropic
material and is loadedby
forces whose resultants act in the middleplane z
= 0. If thickness 2h isthin,
the average values of the components ofdisplacement, strain,
and stress, taken over the thickness of theplate,
lead to aknowledge nearly
asuseful as that of the actual values of the
quantities
at eachpoint.
Theaveraged
values of elastic
displacements
in the directions of the x, y-axes are denotedby
u and v,
respectively;
theaveraged
strains areconsequently
Upon
theassumptions
made on the nature of thematerial,
stresses are related to strainsby
Lam6’sequations
where E is
Young’s
modulus and a Poisson’s ratio. States of stresses such asthese are termed
"generalized plane stresses", according
to a denomination first introducedby
Filon(Love [1927,
Art.94]).
The
half-plane
D is boundedby
thestraight
line y = 0,representing
thetrace of a
rigid
smooth wallpreventing v-displacements
in thenegative
directionof the
y-axis
but not those in thepositive
direction.Assuming
that the entirehalf-plane
ispushed against
the wallby
a uniform uniaxialstress oy
= -q, thestate of stress in D is of the form
and the associated elastic
displacements
aresimply
This state of stresses and
displacements clearly satisfy
the condition of unilateral contact on the line y = 0, since here thev-displacement
is zero andthe normal stress is
purely compressive.
Such a state is called "fundamental."Now let Y be an additional
point
loadapplied
at theorigin
in thepositive
direction of the
y-axis.
The effect of Y is that ofperturbing
the fundamental stateand,
inparticular,
ofcausing
the detachment of the lower border of the elastichalf-plane
from itssupport
in theneighborhood
of theorigin.
Theproblem
thus arises of
determining
the final distribution of stresses in thehalf-plane
andof
finding,
ifpossible,
theshape
and the extent of the detached part of theboundary.
In order to answer the
question,
it is necessary to make someassumptions
on how the lower
boundary
of D leaves the support in thevicinity
of theorigin,
since it is not known in advance whether thisrising
occursalong
asingle
interval of the x-axis or isfragmented
into many small intervals. In the presentsituation,
however, it is reasonable toconjecture
that the intervalis
unique and,
due to the symmetry of theloads, symmetrically placed
withrespect the
y-axis.
The endpoints
of thisinterval,
-a x a, are of courseunknown and must be determined
by
the condition that the normalstress uy
and the
v-displacement
vanish at them.Another
situation,
in a certain sensecomplementary
to thatjust described,
occurs when the
displaced
state isgenerated,
notby
Y, but insteadby
apoint
force X
applied
at theorigin
in the direction of thepositive
x-axis. In thiscase
again
anexplicit
solution can be found upon theassumption
that therising boundary
is made up of asingle
interval. In contrast to theprevious
case,however,
this interval is nolonger symmetric
with respect to theorigin
butinstead is
placed completely
to theright
of theload,
which is nowoperative
atthe left end of the interval. The
length
of this interval must be determinedby requiring
that the normal stress uy vanishes at theright end,
but not at the leftend,
which coincides with thepoint
ofapplication
of X.3. - The case of a vertical load Y
The first of the two situations described above is the
rising
of the border of thehalf-plane
y = 0 effectedby
anupwardly
directed force Yapplied
at theorigin (Fig. 3) superimposed
onto thestate (J y
= -q. Under the influence of Y, theboundary
in theneighboorhood
of theorigin
detaches from the x-axisalong
a certain unknown segment. Since the domain D is
symmetric
withrespect
to they-axis,
as are theloads,
it is natural to expect that this segment admits theorigin
as its midpoint
and isrepresentable
as -a x a.Fig.
3In order to find the stresses and
displacements
associated to theloads,
it is convenient to introducecomplex
coordinatesand to express the stress
components
in terms of a biharmonic function(the Airy
stressfunction)
where
fi(z), f2(z)
are twoanalytic
functions called"complex potentials".
Thestresses are related to the
complex potentials by
the formulaewhile the
displacements
have thecomplex expression
where G is the
tangential
modulus ofelasticity
anda numerical constant
depending solely
on Poisson’s ratio.Summing (3.3)
and(3.4) immediately yields
the combinationor,
alternatively,
Another useful form for stresses and
displacements
has beensuggested by
Muskhelishvili
[1953]
and consists inintroducing
theauxiliary
functionso that
(3.4)
and(3.6)
can be written asThese stresses and
displacements
mustsatisfy
theboundary
conditions of theproblem,
which are of mixed type sincethey require
for for
In
addition,
theinequalities v
> 0for lxl
a,and u.
0for Ixl
> a must beimposed.
In order to find the functions and
f3(z)
it is convenient to observe thatthey
are also solutions to the elasticproblem
of an infiniteplane
with astraight
cut oflength
2a,subjected
to a uniformpressure 60y
= -q atinfinity
and to a
pair
of forces Y and -Yapplied
at the midpoint
of the upper and loweredge.
In otherwords,
the solution does notchange by removing
therigid
smooth support y = 0 and at the same time
prolonging
D with its loads into its mirrorimage
with respect to the x-axis.After this
symmetrization
the solution is reduced tofinding
the stressesin an infinite
plane
with astraight
cut: aproblem
which can be treated with amethod first introduced
by
Muskhelishvili[1953].
The idea of theprocedure
isbased on the condition
that, having
extended the domain to the entireplane,
ifz lies in the
half-plane
y > 0, then z lies in thehalf-plane
y 0, and viceversa.Let now
(a. -
be the stress vector on the upperedge
and(uy -
thatWith these
preliminaries understood,
theremaining procedure
is classical.The
equations (3.10),
after summation andsubtraction,
becomeThese represent two
boundary
valueproblems
of Riemann-Hilbert type, the solutions of which areexpressible
in the formswhere
f l (oo),
denote the values offl’(z),
atinfinity
and ao, a1 arecomplex
constants to be determinedby
the conditions atinfinity.
The
integral
in the latterequation
can be evaluated in finite form.Recalling
that
p+(x)
=p-(x)
= po have support on -8 x e, andusing integral
tables(cf.
Gr6bner and Hofreiter[1966]),
it is easy to find thatHence,
with recourse to the addition formulae of the function arcsinx(cf.
Gradshteyn
andRizhyk [1965, 1.6])
andtaking
the limit for - - 0, it follows thatTo determine the constants it is sufficient to recall
that,
atinfinity,
theonly
active stress
component
isconsequently
thecomplex potentials
have the valueswhere the
symbols
B and B’ used here to denote fundamental stresses were introducedby
Muskhelishvili. To find the other coefficients ao, a, in(3.14)
it isexpedient
to choose the branch of the multivalued functionsuch that and to put
England [1971, §3.10].
It thus follows that a 1 issimply given by
The other coefficient ao must instead be determined
by
the condition ofsingle-
valuedness of
displacements
when thepoint z
describes ageneric
closed curveC
surrounding
the cut. Inparticular,
the curve C may be taken as constitutedby
the circleOê : Iz
+a) I
= 6’; thesegment
r+ : - a + 6’ ~ a - 6:, y = 0,arg(z
+a) =
0,arg(z - a) =
7r; the circle = é, and the segment r- : a - é > x > -a + 6:, y = 0,arg(z - a) =
7r,arg(z
+a)
= 27r, aspictured
inFigure
3(cf. Weinberger [1965, §62]).
Since theintegrals
onC,
and0,
vanishas 6’ - 0,
only
theintegrals
on r+ and r - areleft,
so that the above condition becomesHence, considering
the values of these functions on the upper and loweredge
of the cut, it is easy to arrive at
Evaluating
theintegral (3.15)
thenyields
ao = 0.Having
thus found thesolution,
the formulae(3.8) permit
the stressesalong
the x-axis to be obtained forIxl
> a:in agreement with a result
quoted by
Parker[1981,
page41].
The
displacements
on the upper side of theinterval Ixl
a are insteadgiven by integration
of(3.18)
with the end conditionsu(O)
= 0,v(a)
=v(-a)
= 0:It is worth
remarking
that v+ islogarithmically singular
at theorigin
where Yacts.
So far the
magnitude
of a is still unknown and must be determinedby requiring
that the normal stress vanish at the ends of the freeboundary.
This condition is not
immediate,
since the stresses aresingular
at thesepoints;
it is thus necessary to suppose that which
yields
as the
half-length
of theboundary.
It remains to be verified that the stress is
purely compressive
forIxl
> a. But this property isevident, since, by
virtue of(3 .22), ~ y(x)
has theexpression
,.. ,v - -- I ,
which is
everywhere negative.
As to theproof
of the othercontraint,
thatv’(x)
is
non-negative for lxl
a, this too is almost trivial since the formula(3.18),
after
replacement
ofY by
qa,
gives
7r
proving
thatv+(x)
isstrictly increasing
for -a x 0,strictly decreasing
for0 x a, and
vanishing
at the ends. Aqualitative picture
of theprofile
ofthe free
boundary
is shownby
theheavy
line inFigure
3. As a finalremark,
the
equation
forvl(x)
confirms theproperties,
statedby
Kinderlehrer[1981], that,
inplane elasticity,
the elasticbody
leaves the unilateral obstacle maintain-ing continuity
of normaldisplacements
and of theirtangential
derivatives. This property is also known as Barenblatt’sconjecture (Fichera [1972]), but,
in thiscase, the result is rendered more
precise
becausedisplacements
areexactly
ofclass
C1’a
with a= 1.
2
4. - The case of a horizontal load X
The solution is more difficult when the additional load is a force X
acting
in the
positive
direction of the x-axis(Fig. 4)
since now stresses and strainsare no
longer symmetric
withrespect
they-axis
and therefore the interval of detachement is notnecessarily
centered at theorigin.
Hower,
it ispossible
toexploit
the artifice of reflection with respecy tothe x-axis since the solution is the same as that of an infinite elastic
plane
withFig.
4In order to find the stresses induced in the
plane by
the forces X, the latterare
replaced by
two constant distributions oftangential
tractions s+ _ - s- - so such thatHere
again
the solution isfully
definedby
twoanalytic functions,
still denotedby
andf2(z),
which are solutions to the Riemann-Hilbertproblem
where,
in contrast toequation (3.12),
thenon-homogeneous
term appears in the secondequation.
From thegeneral
form of solutions to the Riemann-Hilbertproblem,
it turns out that the combinationsfl’(z) -
andf i (z) + f3 (z)
havethe
espressions
where
again
and ao, a I are newconstants. To determine these constants it is first necessary to recall that
since now the support of
s+(x) = -s-(x)
is a small intervalcontiguous
to thepoint
x = -a. In consequence, thelimiting
condition(4.1) yields
Thus, knowing
the values of and atinfinity,
it follows that a = -qas before. Hence
f’(z)
and can be written asand it is
again
easy to derive thedisplacements
on bothedges
of the cutThe first
integral
iseasily
evaluatedthrough
the residues at z = z = -a:Moreover the second
integral
can becomputed by using (4.7), (4.8):
It thus follows that the constant ao has the value
and the final values of the
complex potentials
areFrom these
expressions
the stressesfor y
=0, Ixl
> a can beimmediately
obtained
by applying (3.8),
that isAs for the
displacements
on theinterval Ixl
a,they
must be determinedby integrating
the functionand
by applying
theboundary
conditions. These conditions are two: the first is v(a) = 0,expressing
the fact that the endpoint x
= a rests in contact with theplane
y = 0; the second is notmandatory
becausetangential displacement u
isdefined within a constant
rigid motion,
which may be determinedby putting,
for
instance, u(O)
= 0. Thus(4.13),
afterintegration, yields
The still unknown
length
a is then determinedby
the condition= 0, whence
x-al
Since K: - 1
1, thelength
of the detachedboundary
is less than before.K+1 g y
It remains to be verified that the normal stress
uy(x)
is nowhere tensilefor lxl
> a. But this property isclearly valid,
sinceQ y (x),
as a consequence of(4.15 ),
has the formREFERENCES
[1927]
A.E.H. LOVE, A Treatise on the Mathematical Theory of Elasticity. Cambridge:The University Press.
[1953]
N.I. MUSKHELISHVILI, Some Basic Problems of the Mathematical Theory of Elasticity. Groningen: Noordhoff.[1965]
H. WEINBERGER, A First Course in Partial Differential Equations. Waltham-Toronto- London : Blaisdell.[1965]
I.S. GRADSHTEYN - LM. RYZHIK, Table of Integrals, Series, and Products. New York and London: Academic Press.[1966]
W. GRÖBNER - N. HOFREITER, Integraltafel. Wien: Springer.[1967]
J.L. LIONS - G. STAMPACCHIA, "Variational Inequalities". Comm. Pure Appl.Mathem. Vol. 20, pp. 439-519.
[1971]
A.H. ENGLAND, Complex Variable Methods in Elasticity. London-New York-Sydney-Toronto : Wiley.
[1972]
G. FICHERA, "Existence Theorems in Elasticity. Boundary Value Problems of Elasticity with Unilateral Constraints". In: Handbuch der Physik (S. Flügge ed.),Vol. VIa/2. Berlin-Göttingen. Heidelberg: Springer.
[1981]
A.P. PARKER, The Mechanics of Fracture and Fatigue. London-New York: Spon.[1981]
D. KINDERLEHRER, "Remarks about Signorini’s Problem in Linear Elasticity". Ann.Sc. Norm. Sup. Pisa Vol. 8, pp. 605-645.
[1989]
R. SCHUMANN, "Regularity for Signorini’s Problem in Linear Elasticity".Manuscripta Math. Vol. 63, pp. 255-291.
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