R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
N. K ALAMIDAS
A pseudocompact space with Kelley’s property has a strictly positive measure
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has
aStrictly Positive Measure.
N.
KALAMIDAS (*)
ABSTRACT - A
pseudocompact
space withKelley’s
property (**)(resp.
c.c.c.) has a Bairestrictly positive
measure(resp. (cv 1, m)-caliber).
These results wereknown for the class of compact spaces.
In this paper
by
a space we mean acompletely regular
Hausdorffspace. Our notation and
terminology
follow[3].
A
family
~8 ofnonempty
open subsets of a space X is apseudobase
for X if every
nonempty
open subset of X contains an element of 83.DEFINITIONS. Let X be a space.
(a)
X has astrictly positive
measure if there are apseudobase
83for X and a
probability
measure y defined on thea-algebra generated by
~B, such thaty(B)
>0,
for all B E 83.(b)
X has(Kelley’s) property (**)
if itsStone-Cech compactifica-
tion has a
Borel, regular strictly positive
measure.(c)
If ~, arecardinals,
then X has(r, ~,)-caliber
if for everyfamily y
ofnonempty
open subsets of X withI y I
= z there is a subfami-ly y 1 c y
such that[
= Aand ny1 =
0. If X has(r, r)-caliber
we say that X has r-caliber.In
[3], property (**)
is defined in terms of intersection numbers of the set ofnonempty
open subsets. It is easy to see thatproperty (**)
is(*) Indirizzo dell’A.:
Department
of Mathematics, Section of MathematicalAnalysis, Panepistemiopolis,
15784 Athens, Greece.AMS
Subject
Classification (1980): 54C35, 54A25.18
preserved
in densesubspaces.
A space with astrictly positive
measurehas
property (**) ([3], p. 127)
and also has(w 1, w)-caliber. If {UE:E
to i I
is afamily
ofnonempty
open subsets in a space with astrictly posi-
tive measure, we may suppose
d, ~
for a 6 > 0. Thenf1 ~ U~ : ~ E A ~ _ ~
for every infiniteimplies
thatXUçn
-~ 0denotes the characteristic function
on M
for every sequenceç n.
Theresult follows from
Lebesgue’s
dominated convergence theorem.The space
~~, ~ 0, 1 )°1 = ( z e ( 0, 1 ~~’1: I (I
cv 1:x(i)
=111 f (o
has
property (**),
since it is densein ~ 0, 1 ~wl ,
but fails to have a strict-ly positive
measure, since it has not( cv 1, cv )-caliber.
It is also known that a
compact
space with c.c.c.(countable
chaincondition)
has(to,, cv)-caliber ([3]).
The space~~, ~ 0, 1)°1
isagain
acounterexample
for thenon-compact
case.We prove that a space X has
property (**) (resp. w)-caliber)
iffvX
(the
realcompactification
ofX)
does so. It follows that apseudocom- pact
space withproperty (**) (resp. c.c.c.)
has a Bairestrictly positive
measure
(resp. (c~ 1, o)-caliber).
If X is a space, then
Cp (X)
is the space of all real-valued continuous functions on X with thetopology
ofpointwise
convergence.It is known that if X is
compact
with c.c.c. then everypseudocom- pact subspace K
ofCp (X)
is metrizable([2]).
This is no true ifcompact-
ness of X is relaxed to
pseudocompactness.
This followsby
a construc-tion of Shakhmatov
([7]).
Also A. Tulceaproved
that if X has astrictly positive
measure and K is eithersequentially compact
or convex andcompact,
then K is metrizable([9]).
It is an openproblem
whether thesame result is valid for a
simply compact K ([5]). Anyway
thishappens
if X contains a continuous
image
of aproduct
ofseparable
spaces as a densesubspace ([8]) (such
a space is called to be analmost-separable space). Every almost-separable
space has astrictly positive
measureand to
1-caliber.
This is a consequence of thefollowing properties: 1)
aproduct
ofseparable
spaces has astrictly positive
measure and also hasw1-caliber,
and2)
analmost-separable
space is a continuousimage
of aproduct
ofseparable
spaces.We prove that not
always
a space with astrictly positive
measure isalmost-separable.
LEMMA 1. A
space X
has a Bairestrictly positive
measure(resp.
(to,, w)-caliber) if
vX does so.PROOF. For a continuous function
f
onX, put f
for its continuous extension on vX.CLAIM. A sequence
fn, n
=1, 2,
... of continuous functions on X convergespointwise
to the constant function 0 iff the sequencefi, n = 1, 2,
... convergespointwise
to 0 in vX.[Assume
thatfor p
EvXBX
the sequence
fn ( p)
does not converge to0;
there is E > 0 such that S =Iln(y)1 I
zero-set in
vX,
and it isnonempty,
since it contains p. The result follows from the fact that X meets everynonempty
zero-set in vX([4],
p. 118).]
If p
is a Bairestrictly positive
measure onvX,
define a Bairestrictly positive
measure on Xby
thetype
Now let
f U~ : ~ cv 1 ~
be afamily
ofnonempty
open subsets of X.For ~
choose a continuousfunction.4:
X -[0, 1]
such that == 1 and
support (.4)
cU~ ~If
vX has(w
1,co)-caliber,
then there exists asequence
W~n
>1 /2 ~,
n =1, 2,
... such that isnonempty.
If the =1, 2, ...}
contains no infinite sub-family
withnonempty
intersection 0.By
the claim it follows thatf~n
-0,
contradiction.PROPOSITION 2. A
pseudocompact
space withproperty (**) (resp.
c.c.c.)
has a Bairestrictly positive
measure(resp. ( cv 1, w)-caliber).
PROOF. If X is
pseudocompact
then vX =~BX.
As a consequence of Lemma 1 we have that the
sigma-product
1
~ 0 ~ ~ ~
have a Bairestrictly positive
measure.Indeed, they
areboth C-embedded
([3],
p.224)
and dense in therespective product spaces {0, 1 }WI
1 and which are theirrespective
realcompactifica- tions ; being separable,
these spaces have a Bairestrictly positive
measure.
The next lemma appears
in [8].
Wegive
a differentproof.
LEMMA 3.
If
X isalmost-separable
then everypseudocompact subspace
Kof Cp (X)
is metrizable.PROOF.
On X,
define anequivalence
relation -by saying
x ---y iff f(x) = f ( y )
for everyf e
K. LetX
be thequotient
spaceXI -;
thenX
isalso
almost-separable. For f E
K we have a functionf:
X - Rgiven by
writtingl([x]) = f(x); fe KI.
ThenK
c is homeomor-phic
to K.20
We may suppose
that X
contains a continuousimage
of for a car-dinal z, as a dense
subspace.
For n =1, 2,
...put En = {I, 2,
... ,Then
En
iscompact
with c.c.c. and UE,
is dense in NT. It follows that X contains a sequence ofcompact subspaces .9,,,
n =1, 2,
... with c.c.c.and such that
U En
is dense inX. Since K separates points
inX,
it fol-lows that
En
embeds inCp (IK). By
well known facts(see [2],
p.30)
it fol- lowsthat En
is metrizable.Consequently
X isseparable
and the result follows.PROPOSITION 4.
If X is pseudocompact
thenCp (X) is almost-sepa- rable iff it
isseparable.
PROOF. The result follows for the
embedding
X cCp (Cp (X))
andLemma 3.
The space
has a Baire
strictly positive
measure, but it is not almostseparable,
since it has not
w1-caliber.
Shakhmatov
in [7]
constructed a non-metrizablepseudocompact
space
X,
with c.c.c. andCp (Xs, I) pseudocompact (I
is the unitinterval).
The space
Cp (X~ , I)
hasproperty (**),
since it is dense in so it hasa Baire
strictly positive
measure, butby
Lemma 3 it follows that it is not almostseparable.
So,
we have thefollowing
PROPOSITION 5. There exists a non-almost
separable
space with aBaire
strictly positive
measure.REMARKS.
(i)
Shakhmatov’sexample
shows thatalmost-separabil- ity
in Lemma 3 cannot bereplaced by
the existense of astrictly positive
measure.
(ii)
If X is discrete with[X[ I
> 2~’ thenCp (X)
isalmost-separable
but not
separable.
(iii)
Since X embeds intoCp (Cp (X)),
Shakhmatov’sexample
shows that Tulcea’s result for the
metrizability
of convexcompact
sub-spaces K of
Cp (X),
with Xhaving
astrictly positive
measure, is notvalid for
simply
convexpseudocompact subspaces.
We have the sameassertion for the Lindel6f
subspaces.
This follows from the fact that ishomeomorphic
to whereLw
is the onepoint
Lin-del6fication of
([1]).
Acknowledgement.
I express mygratitude
to the Referee for his valuablesuggestions
which were decisive for the final form of this paper.REFERENCES
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function
spacesof
compactsubspaces of ~-products of the
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