A NNALES DE LA FACULTÉ DES SCIENCES DE T OULOUSE
S AÏD B ENAYADI
Structure of perfect Lie algebras without center and outer derivations
Annales de la faculté des sciences de Toulouse 6
esérie, tome 5, n
o2 (1996), p. 203-231
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- 203 -
Structure of perfect Lie algebras without
center
and
outerderivations(*)
SAÏD
BENAYADI(1)
Annales de la Faculté des Sciences de Toulouse Vol. V, n° 2, 1996
RÉSUMÉ. 2014 On montre que certaines propriétés classiques des algebres
de Lie semi-simples restent vraies pour les algebres de Lie g qui vérifient [ g , g ~ ] = g, Der(g) = ad(g),
Z(g) = ~0~,
que nous appellerons les algebresde Lie sympathiques.
On construit une algebre de Lie sympathique non semi-simple de dimen-
sion 25. Cette algebre de Lie est la plus petite algebre de Lie sympathique
non semi-simple connue a ce jour.
Si g est une algebre de Lie, on montre que g contient un plus grand
ideal sympathique M, et qu’il existe un ideal résoluble de g note P(g) qui est le plus grand ideal résoluble I de g tel que I n M = ~0~. Et
on montre l’existence d’une sous-algebre de Lie sympathique m telle que g = m EB P(g), et g est sympathique si et seulement si P(g) = ~0~.
On etudie les ideaux I d’une algebre de Lie g tel que g/I est sympathique.
ABSTRACT. - We show that some classical properties of semi-simple Lie algebras are still valid for pertect Lie algebras 9 without center and
outer derivations satisfies [ g ,
g ~
= g, Der(g) = ad(g),Z(g) = ~0~).
Let us call them sympathetic Lie algebras.
We construct the smallest non semi-simple Lie algebra (of dimension 25)
known until now.
If g a Lie algebra, then we show that g contains a greatest sympathetic
ideal M, and there exists a solvable ideal of g denoted P(g) which is
the greatest among the solvable ideals I of g for which I n M = ~0~.
And we show that there exists a sympathetic sub algebra m of g such that
g = and g is a sympathetic Lie algebra if and only if P(g) = ~0~.
We study the ideals I of a Lie algebra 9 such that 9 / I is a sympathetic
Lie algebra.
(*) } Recule 2 mars 1994
This work has been taken from my doctoral dissertation (fevrier 1993)
~ Laboratoire de Physique Mathematique, Université de Bourgogne, B.P. 138, F-21004 Dijon Cedex (France)
and current address : Departement de Mathématiques, Université de Metz, URA
CNRS 399, lle-de-Saulcy, F-57045 Metz Cedex (France)
Notations and definitions
Let g
be a finite dimensional Liealgebra
over K = R or C. LetDer(g), ad(g), Z(g), R(g),
denoterespectively
thealgebra
of derivations of g, the ideal of inner derivations of g, the center of g, the radical of g, the derived series of g, the
descending
central series of g.(i)
A Liealgebra g
isperfect
if g =~ g
,g ~
.(ii)
A Liealgebra
g issympathetic if g
=~ g , g ~, Der(g) = ad(g)
andZ(g) = ~0~.
(iii) Let g
a Liealgebra,
and let I an ideal of g.I is a direct factor
of g
if there exists an ideal Jof g
such that(iv)
A Liealgebra
is irreducible if it has no non-zero direct factor.Introduction and
principal
resultsLet us
give
a brief survey ofsympathetic
Liealgebras story.
In theseventies,
M. Flato asked thefollowing question: "Any semi-simple
Liealgebra g
satisfies~ g
, g~ =
g,Der(g)
=ad(g), Z(g) = ~0~;
are these threeproperties
characteristic ofsemi-simple
Liealgebras ?".
A
negative
answer wasgiven
abouttwenty
years laterby
E.Angelopoulos [An],
who constructed a class of Liealgebras satisfying
these three proper-ties,
but which are notsemi-simple,
thecounter-example
of minimal dimen- sionbeing
a Liealgebra
of dimension 35 and Levisubalgebra isomorphic
tosl(2).
We call the Liealgebras g
whichsatisfy ~ g
, g~ =
g,Z(g)
=~0~
andDer(g)
=ad(g)
thesympathetic
Liealgebras.
In
[ABBP],
we showed that thissympathetic
Liealgebra g
of dimension 35 satisfies~2(g, g) _ ~0~,
whichimplies
that it is(a) rigid (Lie algebra).
Therefore the
sympathetic
structure isn’t a directdegeneration
of semi-simple
structure(e.g., by contraction). Moreover,
for fixeddimension, sympathetic
Liealgebras provide
an open set in thevariety
of Liealgebras.
So we started a
general study
of this structure.In
[Bel],
we showed that several classicalproperties
ofsemi-simple
Liealgebras
are still valid for the class ofsympathetic
Liealgebras.
For instance:(i) Let g
be asympathetic
Liealgebra,
I an ideal of g.Then,
I issympathetic
if andonly
if I is a direct factorof g [Bel, corollary
2of
proposition 4].
(ii) Every
extension of twosympathetic
Liealgebras
issympathetic
andtrivial
[Bel, corollary
3 ofproposition 4].
(iii)
A Liealgebra
issympathetic
if andonly
if it is a direct sum ofirreducible
sympathetic
ideals[Bel,
theorem1].
In
[Be2],
wegive
anexample
of a nonsemi-simple sympathetic
Liealgebra
of dimension 48 which is non
rigid by
deformations. And in[AnBe],
wegive
the firstexamples
of nonsemi-simple sympathetic
Liealgebras
withinvariant scalar
products (i.e. symmetric, non-degenerate
and invariant bilinearforms).
In the
present
paper, we continue thestudy
initiated in[Bel]. Actually,
several results can be started for
perfect
Liealgebras,
and then restricted tosympathetic
ones.In the first section of this paper, we recall
Angelopoulos
method ofconstruction of non
semi-simple sympathetic
Liealgebras [An].
In thesecond
section,
we construct a nonsemi-simple sympathetic
Liealgebra
ofdimension 25. This Lie
algebra
is the smallest nonsemi-simple sympathetic
Lie
algebra
known until now.In the third
section,
we show that several classicalproperties
of semi-simple
Liealgebras
are still valid for the class ofperfect
Liealgebras.
Inthis
section,
we obtain thefollowing principal
results:(i) Let g
be aperfect
Liealgebra.
Then g
=/~i
(B ... where eachhi
is an irreducibleperfect
ideal
of g. Furthermore,
thisdecomposition
isunique.
This result
generalizes
theorem 1 of[Bel],
and shows that the de-composition
of asympathetic
Liealgebra
into irreduciblesympathetic
ideals is
unique.
(ii) Let g
be asympathetic
Liealgebra, and g
=/~i
(B ... be itsunique decomposition
into irreduciblesympathetic
ideals.Then
/~i..., hn
are theonly
irreduciblesympathetic
ideals of g.These results are classical if we
replace perfect
orsympathetic by semi-simple,
but thesemi-simplicity
isn’t a necessary condition to obtain them.It is known that every Lie
algebra g
has agreatest semi-simple
idealS,
and that its radical
R(g)
satisfies thefollowing properties:
(i)
S =(ii)
is the smallest among the ideals Iof g
for which is semi-simple.
Then we ask the
following questions:
Question 1
Does there exist agreatest sympathetic
ideal N~ ofg ?
Question 2
Does there exist a solvable idealP(g) of g
which is thegreatest
among solvable ideals I
of g
for whichI n lt~ _ ~ 0 ~ ?
.Question
3 Does there exist an idealT(g)
of g which is the smallest among ideals Iof g
for which9 / I
is asympathetic
Liealgebra?
Question 4
IfP(g)
andT(g) exist,
dothey
coincide?In the fourth section of this
work,
we answer toquestions
1 and2,
andin the fifth section we
study
the ideals I of g such that9 / I
is asympathetic
Lie
algebra.
We obtain thefollowing principal
results:(i) Let g
be a Liealgebra, I
and J be twosympathetic
ideals of g.Then I n J and I + J are
sympathetic
ideals of g.(ii) Every
Liealgebra
contains agreatest sympathetic
ideal.(iii)
Let g be a Liealgebra,
M itsgreatest sympathetic
ideal. There exists a solvable idealof g
denotedP(g)
which is thegreatest
among the solvable ideals Iof g
for which In M= ~ 0 ~ .
(iv) g
is asympathetic
Liealgebra
if andonly
ifP(g)
=~0~.
If wereplace sympathetic by semi-simple
andP(g) by R(g),
we obtainthe characterization of
semi-simple
Liealgebras : g
issemi-simple
ifand
only
ifR(g) = ~0~.
We callP(g)
thesympathetic
radical of g.(v) Let g
be a Liealgebra, P(g)
itssympathetic
radical.Then there exists a
sympathetic subalgebra
mof g
such thatg =
If we
replace sympathetic by semi-simple
andP(g) by R(g),
weobtain the Levi-Malcev
decomposition
of g.(vi) Let g
be a Liealgebra,
H be an ideal of g, be the union of theascending
central series of g. If H is minimal among the ideals Iof g
for whichg/I
is asympathetic
Liealgebra,
then:(1)
H is a solvable ideal of g,In the sixth
section,
wegive negative
answers toquestions
3 and4, giving examples
of thefollowing
situation:(i) Let g
be a Liealgebra,
I and J be idealsof g
such that9 / I
andg/J
are
sympathetic
Liealgebras.
It canhappen
thatg/I
n J is not asympathetic
Liealgebra.
(ii)
There exists Liealgebras g
which have an infinite number of minimal ideals among the ideals Iof g
for whichg/I
is asympathetic
Liealgebra.
Therefore,
the answer toquestion
3 is no.(iii)
There exists Liealgebras g
such thatP(g)
andT(g)
do exist asdefined in
questions
2 and3,
but do not coincide.Therefore,
the answer toquestion
4 is no. Moreover:(iv)
There exists irreduciblesympathetic
Liealgebras
with(non trivial) sympathetic
nonsemi-simple quotients.
This last
example
shows that(contrarily
to thesemi-simple case)
irre-ducibility,
in thesympathetic
case, is notreally
a minimal condition. One should introduce a smaller class of irreduciblesympathetic
Liealgebras
without
(non trivial) sympathetic
nonsemi-siinple quotients.
For instanceAngelopoulos’s examples belong
to this class.In our
opinion,
theseexamples
show howflabby
thesympathetic
struc-ture is
(compared
e.g., tosemi-simple),
and that classification isprobably impossible,
even if the Levisubalgebra s
isspecified,
and even if s isspecified
to be
sl(2).
The
Liealgebras envisaged
in this work are of finite dimension overK = R or C.
1.
Angelopoulos’s
theorem and construction of nonsemi-simple sympathetic
Liealgebras [An]
In this section K = C.
1.1 E.
Angelopoulos’s
theoremTHEOREM
[An].-
Let g be a Liealgebra,
g = S ®R(g)
be its Levidecomposition,
and S =~~=1 Sj
be thedecomposition of
S intosimple
ideals.
If
gsatisfies
thefollowing
assertions:~i~ R(g)
isnilpotent
andR(g)
= wherethegi,
1 i4,
are non zero
simple
S-modules such that:g~ is a non trivial
S-module,
(iii)
any two modulesof
S-modules gi, g2, g3, g4~sl
~ ...SN
are nonisomorphic,
then g is a non
semi-simple sympathetic
Liealgebra.
1.2 Method of construction of non
semi-simple sympathetic
Liealgebras
Let S = go be a
simple
Liealgebra
and let~gi~ 1_i_4
be four S-modules.If there exist non trivial
morphisms
of S’-modules:and if:
(i)
91 A 91 A gl doesn’t contain any 5’-moduleisomorphic
to g4,(ii)
the S-module g4 is nontrivial,
(iii)
the modules0 ~
i ~4,
aresimple
and any two of them are nonisomorphic,
then there exists a
product [ . , . ] on g
= suchthat g equipped
with[ . , . ] is
a nonsemi-simple sympathetic
Liealgebra.
1.3 Construction in case where s =
sl(2)
We
designate by D(n)
thesl(2)-module
of dimension2n -E-1, n
E(1/2)N.
Let gj ~ D( ij), 1 j 4,
be four non trivialsl(2)-modules
such that:(2)
g1^ g1 (resp.
g2A g2)
contains asl(2)-submodule isomorphic
to g3(resp. g4);
gi ® g2 and contain somesl(2)-modules isomorphic
to g4;
(3)
g~ A gi A gi has nosl(2)-submodule isomorphic
to g4, then there existsa
product [’, ’ I On g
=sl{2) ® 9j)
such that:1)~91~9’1~=93~~91~92~=~92~92~=~9’1~93~=94~~9’4~9’i~=~~~
for all i
E ~ l, 2, 3, 4~, ~ s , s~ ~ _ ~ s , s~ ~ Sl(2)
for all s, s’ Esl(2),
ii) 9 equipped with [’, ’ ]
is a nonsemi-simple sympathetic
Liealgebra.
REMARK AND DEFINITION . .2014
Let g
=sl(2) ~
the Liealgebra
above.sl(2)
is a Levicomponent of
g, and _~1~_i_4
gi- Wecall g
aLie-Angelopoulos algebra.
~ ~
Examples [An]
2. A non
semi-simple sympathetic
Liealgebra
of dimension 25
In this section K = C. Recall the method of calculation of Clebsch- Gordan coefficients of
[ABBP].
Let s =
C~~ p ,
,q ~
with the Poisson bracket :and let
,S~
be the space ofhomogeneous polynomials
ofdegree
k.S2
isinvariant
by
the Poissonbracket, isomorphic
tosl(2),
and n E(1/2)~1
is a
sl(2)-module
for theadjoint
actionisomorphic
toD(n).
The
Moyal *-produit
definedby:
is an associative
product,
and for ~ in,5’2
=sl(2),
we have~~, ~ ~ _ ~ ~ , ~ ~
*.We
identify D(n)
andD(p)
and the map u ® v ~ u * v ofD(n)
®D(p)
inD(n)
*D(p)
is anisomorphism
ofsl(2)-modules. Using
the
development
of u * v, weget directly
the reductionD(n)
®D(p)
=which
gives
the coefficients of Clebsch-Gordan.PROPOSITION 2.1. - There exists a Lie
algebra
g = gi such that:(i~
go isisomorphic
tosl(2);
(it)
theonly (non zero)
commutators between g2 and gj,i, j
> 1 are:D(3),
92 ^-rD(2),
93 ’~D(3),
g4 ^-’D(1)
asProof. - By
the reductionD(n)
0D(p)
=D(i~,
there existnon trivial
morphisms
ofgo-modules:
These
morphisms
and the action of go oneach g2
define askew-symmetric product [’, -]
on g such that the assertion(ii)
is verified.It’s easy to see that the Jacobi
identity
is verified onSince
D(3)
AD(3)
AD(3)
=D(6)
CD(4)
CD(3)
eD(2)
CD(0),
thendoesn’t contain a
go-submodule isomorphic
to g4, whichimplies
that the Jacobi
identity
is verified on[~i , , ~g1 , gl~~
.We conclude
that g
with theproduct [ -, - ] is
a Liealgebra
which verifies(i), (ii),
and(iii).
Realizations
of
g. - We canrealize
g as the space ofhomogeneous polynomials
of evendegree ~
6 without constant terms. Thebracket [-, -] ]
on g is defined
by:
(a)
g1= ~ (za, 0) }
and g3= ~ (0, v) }
where v eD(3). Let v,
w ED(3), i) ~(v, 0) , (w, 0)~ - (0, P3(v, w))
, we recall thatP3(v, w)
=-
P3(w, v)
becauseP3
isskew-symmetric.
ii) ~(v, 0) , (0, w)~ - P5(z~, w)
[(0, v) ~ (w~ 0)]
= -0) (0, ~)]
=~) = -P5(~ ~)
because
Ps
isskew-symmetric.
So~(v, 0) (0 , w)~
=~(o, v), (w, 0)~ .
(b)
LetX,
Y ED(2),
(c)
Let X ED(2)
and v ED(3),
We recall that
P4
issymmetric.
(d)
Let iE ~ 1, 2, 3, 4 } ,
~ E gi , s E go,(e) ~ s , s~ ] = ~s , s~ ~ s
for all s, s’ E go =S,
where[ -, - ] ~
is the bracketon S =
sl(2).
THEOREM a non
semi-simple sympathetic
Liealgebra of
dimension ~5.
Proof.
- It’s easy to see that R = g2 is the radical of g, whichimplies that g
isn’tsemi-simple.
Since R doesn’t contain anygo-submodule isomorphic
toD(0),
thenZ(g)
={0}.
.~ g
, g~ =
g because each gi is a nontrivial
simple go-module.
Let D be a derivation of g, then there exists y E g such that
(D - ad y)/go
=0,
whichimplies
that T = D -ad(y)
is amorphism
of go- modules.Therefore
Since
[R, R] ~
is a characteristic idealof g
and[R, R] ~
= g3 ~ g4, then~’~g3 )
C g3 andT(g4)
C 94 ~By
Schur’sLemma,
we haveand
T ((v, 0))
=a(v, 0) + b(0, v)
for all v ED(3),where
y, a, b E C. Sowe obtain:
This
implies
thata - b - a - ~3 = ~y~ = 0,
therefore T = 0. SoD =
ad(y)
Ead(g).
We conclude
that g
is a nonsemi-simple sympathetic
Liealgebra.
Remark. . - This Lie
algebra
is the smallest nonsemi-simple sympathetic
Lie
algebra
known until now. Recall that 25 is the dimension of this Liealgebra.
Question
1. . - J. Simon[Si]
showed that there doesn’t exist any nonsemi-simple sympathetic
Liealgebra g
such thatdim g
10. Does exist a nonsemi-simple sympathetic
Liealgebra g
such that11 dim g 24 ?
3.
Decomposition
ofperfect
Liealgebras
PROPOSITION 3.1.2014 Let g be a
perfect
Liealgebra
and let I be an idealof
g.If
I is a directfactor of
g, then I isperfect.
Proof.
- I is a direct factor of g, then there exists J an idealof g
suchthat g
= . Since~ I
,J ~ _ ~ 0 ~ ,
then we have~ g
, g~ = ~ I
, I~ ® [
J , J~ consequently 7 == [7, , I].
LEMMA 3.1.2014 Let g be a Lie
algebra.
Then g =I1
® ~ ~ ~ ®~~,
where eachIi is
an irreducible idealof
g.Proof.
- We will prove the Lemmaby
induction on the dimensionof g.
If
dim g
= 0 or1,
then the lemma is true.We assume that the lemma is true if
dim g
n.Let g
be a Liealgebra
such that
dimg
= n.If g
isn’tirreducible,
then there exist two proper idealsof g
suchthat g
= J.By
our inductivehypothesis,
we have I =Ii
where eachIi
is anirreducible ideal of I and J =
J1
~ ... (BJm
where eachJi
is an irreducible ideal of J.To
conclude,
it is sufficient to see that every ideal of I(resp. J)
is anideal
of g.
LEMMA 3.2.2014 Let g be a Lie
algebra
and let I be aperfect
idealof g. If
g =
7i In
where eachI2
is an idealof
g, thenProof.
- Given that I isperfect,
then~ ~ , g ~
=I, consequently
I =[
I ,h ] ~
... ®[I
,In].
. Which proves that I = I~ I1
® ... ® I n In .THEOREM 3.1. . - Let g be
perfect algebra.
Then g =hi
® ~ ~ ~ ®hn
where eachhZ
is an irreducibleperfect
idealof
g.Furthermore,
thisdecomposition
is
unique.
Proof.
- The existence of thedecomposition
results fromProposition
3.1 and Lemma 3.1. Let
be two
decomposition of g
into irreducibleperfect
ideals.Let i E
~ 1,
... ,n) , by
Lemma3.2,
we havetherefore there exist
E ~ 1, ... , m}
such thathi
=hi
nh~,ti} ,
whichimplies
thathi
Ch~~2~ . By Lemma 3.2,
then there
exists j E {1,
... ,, m~
such thathj
nh~{i) ~ ~0~, consequently i = j and hi = h~{2) .
Thus n = m and there exists a
permutation
crof {1,
...,n~
such thathi
= for all i E~ l,
... ,, n~,
so that thedecomposition
of g into irreducibleperfect
ideals isunique.
COROLLARY . Let g be a
perfect
Liealgebra,
I be a proper idealof
g andlet 9
=hi
0 -’ - ~ ®hn
be theunique decomposition of g
into irreducibleperfect
ideal.(i)
I is an irreducible directfactor of g if
andonly if
there exists i E~ 1,
..., n~
such that I =hi.
.(ii)
I is a directfactor of
gif
andonly if
there exists ... asubset
of ~ 1,
..., n~
such that I =hil
~ ~ ~ ~ ®him.
.Proof
(i)
Assume that I is an irreducible direct factorof g, by Proposition
3.1and Lemma 3.2 there exists i E
~ 1,
...,, n~
such that I = I nhi,
so thatI C
hi.
. Since I is a direct factorof g,
then there exists an idealJ of g
suchthat g
= I ®J,
andby
Lemma3.2, hi
=hi
nI,
whichimplies
that I =hi.
.(ii)
Assume that I is a direct factor of g,by Proposition 3.1,
I is aperfect
ideal
of g,
andby
Theorem3.1,
there exist7i,
..., irreducibleperfect
ideals of I such that I =
Ii
® ... ~ ~ .To
conclude,
it is sufficient to see that every ideal of I is an idealof g
and to
apply (i).
The converse is evident.LEMMA 3.3.2014 Let g be a Lie
algebra
and I be a directfactor of
g.Proof.
- I is a direct factorof g,
then there exists J an idealof g
suchthat g
= J. The assertion(i)
is true because(ii)
Let d EDer(7),
we consider theendomorphism
of g definedby: D/I
= dand
D/J
=0,
it is easy to check that D is a derivation of g, therefore there exist x E g such that D =adg(x).
Since g
=I ® J,
then ~ = where x I E I and ~~ EJ, consequently
d = We
get
thatDer(I)
=ad(I).
PROPOSITION 3.2
(i)
Let g be aperfect
Liealgebra
such thatDer(g)
=ad(g) (resp.
Z(g)
=~0~~.
Thenwhere each
hi
is an irreducibleperfect
idealof
g such thatFurthermore,
thisdecomposition
isunique.
(ii)
Let g be asympathetic
Liealgebra.
Thenwhere each
hi
is an irreduciblesympathetic
idealof
g.Furthermore,
thisdecomposition
isunique.
From
[Bel, corollary
2 of theproposition 1~, corollary
of Theorem 3.1 andProposition
3.2 results thefollowing corollary.
COROLLARY . - ~et g be a
sympathetic
Liealgebra.
(i~
g has afinite
numberof
irreduciblesympathetic
idealshi,
..., hn
and
(ii)
An ideal Iof
g issympathetic if
andonly if I
=hil
~...~him
where~21,
... , C~l,
...,72~.
.PROPOSITION 3.3. Let g be a
perfect
Liealgebra
and let S be itsgreatest semi-simple
ideal. Then there exists aperfect
ideal Iof
g such that g = S ~ I and I has no non-zerosemi-simple
ideal.Proof.
- Since S is asemi-simple
ideal of g, there exists .~ an ideal of g such that g = S ® I.By Proposition 3.1,
I is aperfect
ideal of g.Let J be a
semi-simple
ideal ofI then
J is asemi-simple
ideal of g soRemark. -
Proposition
3.3 reduces thestudy
ofperfect
Liealgebras
tothose which have no non-zero
semi-simple
ideal.Combining
with Theorem3 .1,
we see that such a Liealgebra
is reduced to a direct sum ofnon-simple
irreducible
perfect
ideals.4. The
greatest sympathetic
idealand the
sympathetic
radical of Liealgebra
THEOREM 4.1. Let g be a Lie
algebra. If
I and J are two idealssatisf ying:
(i~
I is asympathetic
idealof
g,there exists a vector
subspace
Vof
g such that g = J ® V and~ I
,V]
C V. Then I fl J is asympathetic
idealof
g.Proof.
- Since .I =~ I , I J,
we have I =~ I , g J, consequently
I =~ ~
, JJ ® ~ I , ~ J
. Then~ 1, J J
is a direct factor of I because~ I , ~ J
isan ideal of I.
By [Bel corollary
2 ofproposition 4J, [I
, J] and [I, V ] are
ideals of g,therefore Z
~.~/ ~ I J J ~ _ ~ 0 ~ .
We consider the canonical
surjection 03C6
: I ~I/[
I, J].
Let x E I n Jand
let y
EI,
Thus I n J
= ~ ~ , J ~, consequently
I n J is asympathetic
ideal of g.COROLLARY 1. - Let g be a Lie
algebra,
I and J be two idealsof
g.(i~ If
I is asympathetic
idealof
g and J is a directfactor of
g, then I n J is a.sympathetic
idealof
g.(ii) If
I and J aresympathetic
idealsof
g, then I fl J and I + J aresympathetic
idealsof
g.Proof.
- The assertion(i)
resultsdirectly
from Theorem 4.1.(ii) By ~Bel, corollary
1 of theproposition 4~,
we have J is a factor direct of g,consequently
I n J is asympathetic
ideal of g. Thefollowing
sequenceis exact :
defined
by
= .r for all .r ~ I and +.cj)
=jV(.cj)
for all ~ C I andall xJ
E J where N : J --~J/I n
J is the canonicalsurjection.
Thus I + J is an extension of
sympathetic
Liealgebras,
so I + J is asympathetic
idealof g by [Bel, corollary
3 of theproposition 4].
.COROLLARY 2.2014
Every
Liealgebra
contains a greatestsympathetic
ideal.
Proof.
-Let g
be a Liealgebra.
A =
~dim I
, I is asympathetic
ideal ofg~
is a non-empty subset ofN bounded above
by dim g,
then it has a greatest element p,consequently
there exists asympathetic
ideal Mof g
such thatdim m = p.
Let I be a
sympathetic
ideal of g;by corollary
1 of Theorem4.1,
M + Iis a
sympathetic
ideal of g. Thus M = M +I,
so I ç M.We conclude that M is the greatest
sympathetic
idealof g.
LEMMA 4.1. - Let g be a Lie
algebra
and let I be an idealof
g.~f
thereexist an ideal J
of
gsatisfying:
(i) [ J J]=J andZ(J)= ~o~, (ii)g=I®J.
Then I is a characteristic ideal
of
g.Proof. -
Let x E I and let D EDer(g). D(x)
= y + z where y E I andz E J. Let z ’ E
J,
then[ z , z’ ~
=- [ x , Dz’ ~
.By
Lemma 1 of Jis a characteristic ideal of g, then
[ z , z’ ~ ]
= 0. Which proves that z =0, consequently D(x)
E I. We conclude thatD(I )
C I.PROPOSITION 4.1. Let g be a Lie
algebra
and M be itsgreatest
,
sympathetic
ideal. Then there exists a characteristic ideal Lof
gsatisfying:
(i)
g = ~~l ® L .(ii)
L is thegreatest
among the idealsof
g which are directfactors of
g and do not have any non-zerosympathetic
ideal.Proof.
-By [Bel, corollary
2 of theproposition 4~ ,
there exists an ideal L of g such that g = M E~9L,
andby
Lemma4.1,
L is a characteristic ideal of g.Let I be a
sympathetic
ideal ofL,
then I is asympathetic
ideal of g,consequently I
C ~ n L= ~ 0 ~ .
Let J be an ideal of g which is a direct factor of g and doesn’t have any non-zero
sympathetic ideal,
then there exists an ideal H of g such that Let M’ be thegreatest sympathetic
ideal of~,
then there exists an ideal L’ of H such that H = M’ ® L’ and L’ is a characteristic ideal of H which doesn’t have any non-zerosympathetic
ideal.Therefore,
g = M’ ® L’ ® J where M’ is asympathetic
ideal of g and where L’ and J are ideals of g which don’t have any non-zerosympathetic
ideal.
By [Bel, corollary
2 ofproposition 4]
andby
Lemma3.2,
weget
M = M’. .
Let x E
J,
then x = y + z where y E M and z E L. Since =~0~
and
[M,
Then J CL.DEFINITION 4.1. - Let g be a Lie
algebra.
Callsympathetic decomposi-
tion
of
g, thedecomposition of
theProposition (i. e.
thedecomposition
g = ® L where is the
greatest sympathetic
idealof
g and where L is thegreatest
among the idealsof
g which are directfactors of
g and don’t have any non-zerosympathetic ideal).
PROPOSITION 4.2. - Let g be a Lie
algebra,
M be itsgreatest sympathetic
ideal and g = M ® L be its
sympathetic decomposition.
Then thefollowing
assertions are
equivalent:
(i)
g is asympathetic
Liealgebra;
(ii)
L =~0~;
(iii) R(L)
=~o~.
Proof
(i)~(ii) By [Bel, corollary
2 ofproposition 4],
L is asympathetic
Liealgebra,
so L =~0~.
(ii)~(iii)
It’s clear.R(L)
=~0~ implies
that L issemi-simple, consequently
L =~0~.
Then g = N~ .
DEFINITION 4.2. - Let g be a Lie
algebra,
M be itsgreatest sympathetic
ideal and g = M ® L be its
sympathetic decomposition.
We call
R(L)
thesympathetic
radicalof
g which will be denotedP(g).
Remark. - This
terminology
isjustified by Proposition
4.2.PROPOSITION 4.3. - Let g be a Lie
algebra,
M be itsgreatest sympathetic
ideal and
P(g)
be itssympathetic
radical.(i~ P(g)
is a characteristic idealof
g.(ii) P(g)
is the greatest among the solvable ideals Iof
gfor
which(iii)
There exists asympathetic subalgebra
mof
g such that g =m®P(g).
Proof.
- Let g = M ® L be thesympathetic decomposition
of g. The. assertion
(i)
is clear.(ii)
Let I be a solvable idealof g
such that I n M =~0~,
thenconsequently
M n(I
+P(g))
=~0~
Thisimplies
thatR(M)
n(I
+P(g))
=~ 0 ~ ,
therefore I CP(~).
.(iii)
Let S be a Levicomponent
of L.By [Bel, corollary
3 of theproposition 4],
m = M C 5 is asympathetic
Liesubalgebra
of g. So that g = m EBP(g)
where m is asympathetic subalgebra
of g.PROPOSITION 4.4.2014 Let g be a Lie
algebra, P(g)
be itssympathetic
radical and M be its
greatest sympathetic
ideal.If
m is asympathetic subalgebra of
g such that g = m ®P(g),
then thefollowing
assertions areequivalent:
~i~
M C m; ;[M, m] C
m;(iii) R(m)
is an idealof g.
Proof.
-Let g
= M (B L be thesympathetic decomposition
of g.(i)=~(iii) R(g)
=R(m)
CP(g) implies
thatR(m)
=R(M).
(iii)=~(i)
Let 5 be a Levicomponent
of m, then S is a Levicomponent
ofg and S’ =
S’1
052
whereS1
and52
are two ideals of ,S such that51 (resp.
52)
is a Levicomponent
of M(resp. L).
. ThusS1
CR(m)
is an idealof g
such
that g
=,Sl
CR(m)
CL,
so that M =9i
CR(m).
Which proves that M C m.(ii)=~(i)
M =[M, M] implies that M , g = M,
therefore M =~ m , M ~,
which
implies
that M C m.(i)==~(ii)
It’s clear.Question
2. .Let g
be a Liealgebra.
We know that if ,S and 5’ are two Levi componentsof g,
then there exists aspecial automorphism 03C6 of g
suchthat
~(9) == S’ [Bo,
Levitheorem]. So,
if m and m’ are twosympathetic
Lie
subalgebras of g satisfying
does there exist an