A NNALES DE L ’I. H. P., SECTION C
P. C ARDALIAGUET
B. D ACOROGNA W. G ANGBO N. G EORGY
Geometric restrictions for the existence of viscosity solutions
Annales de l’I. H. P., section C, tome 16, n
o2 (1999), p. 189-220
<http://www.numdam.org/item?id=AIHPC_1999__16_2_189_0>
© Gauthier-Villars, 1999, tous droits réservés.
L’accès aux archives de la revue « Annales de l’I. H. P., section C » (http://www.elsevier.com/locate/anihpc) implique l’accord avec les condi- tions générales d’utilisation (http://www.numdam.org/conditions). Toute uti- lisation commerciale ou impression systématique est constitutive d’une infraction pénale. Toute copie ou impression de ce fichier doit conte- nir la présente mention de copyright.
Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
http://www.numdam.org/
Geometric restrictions for the existence of viscosity solutions
P. CARDALIAGUET
Departement de Mathematiques, Paris, France.
E-mail:
cardaliaguet@ceremade.dauphine.fr
B. DACOROGNADepartement
de Mathematiques,Ecole Polytechnique Federale de Lausanne, CH 1015 Lausanne, Suisse.
E-mail: Bernard.Dacorogna@epfl.ch W. GANGBO*
School of Mathematics, Georgia Institute of Technology, Atlanta, GA 30332, USA.
E-mail: gangbo@math.gtech.edu
N. GEORGY Departement de Mathematiques,
Ecole Polytechnique Fédérale de Lausanne, CH 1015 Lausanne, Suisse.
E-mail: Nicolas.Georgy@epfl.ch
Vol. 16, n° 2, 1999, p. 189-220 Analyse non linéaire
ABSTRACT. - We
study
the Hamilton-Jacobiequation
where F :.
IRN
2014~ [R is notnecessarily
convex. When S2 is a convex set,under technical
assumptions
our first main resultgives
a necessary and* Supported by NSF grant DMS-9622734 AMS Classifications: 35F, 49L.
Annales de l’Institut Henri Poincaré - Analyse non linéaire - 0294-1449 Vol. 16/99/02/© Elsevier, Paris
sufficient condition on the
geometry
of H andon D03C6
for(0.1)
to admit aLipschitz viscosity
solution. When wedrop
theconvexity assumption
onQ,
and relax technical
assumptions
our second main result uses theviability theory
togive
a necessary condition on thegeometry
of S2 and onDp
for(0.1)
to admit aLipschitz viscosity
solution. ©Elsevier,
ParisRESUME. - Nous etudions
1’ equation
de Hamilton-Jacobi suivanteou F : ---~ R n’est pas
necessairement
convexe.Lorsque
H est unensemble convexe, notre
premier
resultat donne une condition necessaire et suffisante sur lageometrie
du domaine n et surDp
afin que(0.2)
admette une solution de viscosité
lipschitzienne.
Si on enlève la condition de convexite du domaineH,
notre second resultatpermet,
a l’aide du theoreme deviabilite,
de donner une condition necessaire sur lageometrie
du domaine H et sur
Dcp
afin que(0.2)
admette une solution de viscositélipschitzienne.
@Elsevier,
Paris1. INTRODUCTION
In this article we
give
a necessary and sufficientgeometric
condition for thefollowing
Hamilton-Jacobiequation
to admit a
W~~°° (SZ) viscosity
solution.Here,
SZ C is abounded,
openset, F :
IRN
--~ I~ is continuous and cp EC1 (SZ).
We prove that existence ofviscosity solutions ’ depends strongly
ongeometric compatibilities
ofthe set of zeroes of
F,
of p and ofQ,
however it does notdepend
onthe smoothness of the data.
The Hamilton-Jacobi
equations
areclassically
derived from the calculus ofvariations,
and the interest offinding viscosity
solutions(notion
introduced
by
M.G. Crandall-P.L. Lions[8])
ofproblem (1.1)
is well-known1 Equation (1.1) may admit only continuous or even discontinuous viscosity solutions (see [4]).
We are here interested only in W 1 ~ x solutions.
Annales de l’Institut Henri Poincaré - Analyse non linéaire
in
optimal
control and differential gamestheory (c.f.
M. Bardi-I.Capuzzo
Dolcetta
[3],
G. Barles[4],
W.H.Fleming-H.M.
Soner[13]
and P.L.Lions
[17]).
It has
recently
been shownby
B.Dacorogna-P.
Marcellini in[9], [10]
and
[11] (cf.
also A. Bressan and F. Flores[6])
that(1.1)
hasinfinitely (even G8 dense)
many solutions u Eprovided
thecompatibility
condition
holds,
whereand
conv(Zp)
denotes the convex hull ofZF
andint(conv(Zp))
itsinterior. In fact
(1.2) is,
in some sense, almost a necessary condition for the existence of solution of(1.1).
The classical existence results onviscosity
solution of( 1.1 ) require stronger assumptions
than( 1.2) (see
M. Bardi-I.Capuzzo Dolcetta, [3],
G. Barles[4],
W.H.Fleming-H.M.
Soner
[13]
and P.L. Lions[17]).
Here we wish to
investigate
thequestion
of existence ofviscosity
solution under the soleassumption ( 1.2).
As mentionedabove,
theanswer will
be,
ingeneral,
that such solutions do not exist unlessstrong
geometric
restrictions on the setZp,
on f2 and on cp are assumed.To understand better our results one should
keep
in mind thefollowing example.
EXAMPLE 1.1. - Let
(Note
that F is apolynomial of degree 4). Clearly,
Our article will be divided into two
parts, obtaining essentially
the sameresults. The first one
(c.f.
Section2)
will compare the Dirichletproblem (1.1)
Vo!.16,n° 2-1999.
with an
appropriate problem involving
a certain gauge. The second one(c.f.
Section
3)
will use theviability approach.
We start
by describing
the firstapproach.
We will assume there that H isconvex. To the set
conv ( ZF )
we associate its gauge, i.e.(In
theexample p(~) _ ~ ~ ~ ~ ).
The
W 1 ~°° (SZ) viscosity
solutions of( 1.1 )
will then becompared
tothose of
The
compatibility
condition on cp will then beWe will first show
(c.f.
Theorem2.2)
that ifZF
C andZF
isbounded,
then anyviscosity
solution of( 1.1 )
is aviscosity
solutionof
(1.7).
Howeverby
classical results(c.f.
S.H. Benton[5],
A.Douglis [12],
S.N. Kruzkov
[16],
P.L. Lions[17]
and thebibliography there)
we knowthat the
viscosity
solution of(1.7)
isgiven by
where pO
is thepolar
of p, i.e.(In
theexample _ ~ ~* ~ 1 + ~2 ~ .)
The main result of Section 2
(c.f.
Theorem2.6,
c.f. also Theorem3.2)
usesthe above
representation
formula togive
a necessary andsufficient
conditionfor existence of
viscosity
solutions of( 1.1 ).
Thisgeometrical
condition can be
roughly
stated asVy
E ~03A9 where the inward unitnormal,
v,(y),
isuniquely
defined(recall
that here S2 is convex and therefore this is the case for almost every y E there existsA(y)
> 0 such thatAnnales de l’Institut Henri Poincaré - Analyse non linéaire
In
particular
if p =0,
we findthat ~ ( ~ )
= and therefore the necessary and sufficient condition reads asIn the above
example ZF = ~ ( -1, -1 ) , ( -1,1 ) , (1, -1 ) , ( 1,1 ) ~ ,
thereforethe
only
convexH,
which allows for(SZ) viscosity
solution ofare
rectangles
whose normals are inZ p.
Inparticular
for any smooth domain(such
as the unitdisk), (1.1)
has noW 1 ~°° ( SZ) viscosity solution,
while
by
the result of B.Dacorogna-P.
Marcellini in[9], [10]
and[ 11 ], (since
0 Eint(conv(Zp)))
the existence ofgeneral W 1 ~ °° ( SZ )
solutions isguaranteed.
Note that in the aboveexample
with 03A9 the unitdisk, F
andcp are
analytic
and therefore existence ofW l °° (SZ) viscosity
solutions donot
depend
on the smoothness of the data.It is
interesting
to note that if F : ---~ R is convex and coercive(such
as the eikonalequation),
as in the classicalliterature,
c
ZF.
Therefore the above necessary and sufficient condition does notimpose
any restriction on the set H. However as soon as non convex F areconsidered,
such as in theexample, (1.10) drastically
restricts the
geometry
of the setH,
if existence ofW l °° (SZ) viscosity
solution is to be ensured.
In Section 3 the basic
ingredient
forproving
such a result is theviability
Theorem
(Theorem
3.3.2 of[2]).
This Theoremgives
anequivalence
between the
geometry
of a closed set and the existence of solutions of some differential inclusionremaining
in this set. The idea ofputting together viscosity
solutions and theviability
Theorem is due to H. Frankowska in[15].
Vol. 16, n° 2-1999.
The main result of this section
(c.f.
Theorem3.1,
c.f. alsoCorollary 2.8)
will show that if
then we can
always
find an affinefunction p
withDp
Eint(conv(ZF))
so that
(1.1)
has noviscosity
solution.The
advantage
of the secondapproach
is that it willrequire
weakerassumptions
on F and on H than the first one. However the firstapproach
will
give
moreprecise
information since we will use theexplicit
formulafor the
viscosity
solution of(1.7).
Some technical results are
gathered
in twoappendixes.
2. COMPARISON WITH THE SOLUTION ASSOCIATED TO THE GAUGE
Throughout
this section we assume that F :IRN
-~ R is continuous and that.
(HI) Zp
CWe recall that
ZF
= =0~.
.
(H2) ZF
is bounded..
(H3)
Eirat,(co7av(ZF)),
b’:z E S2.In addition we assume that the interior of the convex hull of
Zr
isnonempty,
i.e.REMARKS 2.1.
(i)
Inlight of (2.1 )
we may assume without lossof generality
that0 E
int(conv(Zp)),
since up to a translation thisalways
holds.(ii)
Observe thatint(conv(ZF)) ~
is necessaryfor (H3)
to make sense.(iii)
Recall that(H3) (without
theinterior) is,
in some sense, necessaryfor
existence solutions(c.!
P. L. Lions~l 7J).
(iv)
It is well-known(c.f. (18J)
that thefollowing properties
hold:. p is convex,
homogeneous of degree
one andp~~
= p..
conv(ZF) _ ~z
Ep(z) l~.
.
a(conv(ZF)) _ ~z
Ep(z)
=1~.
, Annales de l’Institut Henri Poincaré - Analyse non linéaire
.
p(z)
> 0for
everyz ~
0.(v)
SinceZF
thefunction
F has adefinite sign
inWe will assume, without loss
of generality,
thatfor every ~
Eint( conv ( ZF ) ) .
Otherwise in thefollowing analysis
we shouldreplace
Fby - F.
Our first result compares
viscosity
solutions of( 1.1 )
and those of( 1.7).
THEOREM 2.2. - Let S~ C be a bounded open set, let F and ~p
satisfy (Hl ), (H2), (H3)
and(2.2).
Then anyW l °° (SZ) viscosity
solutionof ( 1.1 )
is also a
W l~°° (SZ) viscosity
solutionof (1.7). Conversely if
in additionF > 0 outside
conv(Zp)
then aW 1 ~°° ( SZ) viscosity
solutionof ( 1.7)
is alsoa
W 1 ~°° ( SZ) viscosity
solutionof ( 1.1 ).
REMARK 2.3. - In the converse
part of
the above theorem thefacts
thatF is
continuous,
F 0 inint(conv(Zp )),
and F > 0 outsideconv(Zp) implies
thatWe recall the definition of subdifferential and
superdifferential
offunctions
(c.f.
M. Bardi-I.Capuzzo
Dolcetta[3],
G. Barles[4]
or W.H.Fleming-H.M.
Soner[13]).
DEFINITION 2.4. - Let u E
C(f2),
wedefine for
x E SZ thefollowing
sets,D+u(x) (D-u(x))
is calledsuperdifferential (subdifferential) of u
at x.We recall a useful lemma stated in G. Barles
[4].
LEMMA 2.5.
(i)
u EC(SZ)
is aviscosity
subsolutionof F(D(u(x)))
= 0 in SZif
andonly if F(p)
0for
every x EQ, Vp
ED+u(x).
(ii)
u EC(SZ)
is aviscosity supersolution of
= 0 in SZifand only if F(p) >
0for
every x EQ, Vp
ED-u(x).
2-1999.
We now
give
theproof
of our first theorem.Proof of
Theorem 2.2.1. Let u E be a
viscosity
solution of( 1.1 ).
(i)
We first show that u is aviscosity supersolution
of( 1.7).
Since u isa
viscosity supersolution
of( 1.1 ),
then inlight
of Lemma 4.2 and 2.5 wehave for every x E
H,
and every p ED - u ( x ) ,
Combining (2.2), (2.3)
and(HI),
we obtain that p E and so,p(p) -
1 = 0.Hence, by
Lemma2.5,
u is aviscosity supersolution
of(1.7).
(ii)
We next show that tc is aviscosity
subsolution of( 1.7).
Since ~c is aviscosity
subsolution of(l.l),
then for every x ESZ,
and p E we haveby
Lemma4.2,
p Econv(Zp)
and so,p(p) -
1 0 . ’ We thereforededuce that u is a
viscosity
subsolution of(1.7).
Combining (i)
and(ii)
we have that u E is aviscosity
solutionof
(1.7).
2. We show that u E the
viscosity
solution of(1.7)
definedby (1.8),
is also aviscosity
solution of( 1.1 ).
(iii)
We recall thatfor
all ~
Econv(ZF) .
Since u is aviscosity supersolution
of(1.7),
then for every x E
H,
and p E we have thatp(p) -
1 >0,
i.e.p E
int ( conv ( ZF ) ) .
From(2.4),
it follows thatF(p)
> 0 and thusu is a
viscosity supersolution
of( 1.1 ).
(iv)
Since u is aviscosity
subsolution of( 1.7),
we have for every x ESZ,
and p E
D+u(x),
thatp(p) - 1 0,
i.e. p Econv(ZF)
and thenF(p)
0.Thus u is a
viscosity
subsolution of( 1.1 ).
Combining (iii)
and(iv)
we conclude that u is aviscosity
solutionof
(1.1).
DWe now state the main result of this section
(see
also Theorem3.4).
THEOREM 2.6. - Let F and cp
satisfy (HI ), (H2), (H3)
and(2.2). If
!1 is
bounded,
open and convex and p EC 1 ( SZ ),
then the twofollowing
conditions are
equivalent
1. There exists u E
W 1 ~ °° ( S~ ) viscosity
solutionof ( 1.1 ).
Annales de l’Institut Henri Poincaré - Analyse non linéaire
2. For every y E where the unit inward normal in y
(denoted v(y))
exists,
there exists aunique
> 0 such thatBefore
proving
Theorem2.6,
we make fewremarks,
mention animmediate
corollary
and prove a lemma.REMARKS 2.7. -
(i) By v(y),
the unit inward normal at y, exists we meanthat it is
uniquely defined
there. Since SZ is convex, then this is the casefor
almost every y E ~SZ.
(ii) In particular if
~p -0,
thenand so, the necessary and
sufficient
condition becomes(iii) If F
is convex andcoercive,
then{2.5)
isalways satisfied
andtherefore
no restriction on the
geometry of
SZ isimposed by
our theorem(as
in theclassical
theory of
M. G. Crandall-P.L. Lions(8J).
COROLLARY 2.8. - Let SZ C be a bounded open convex set, let F :
(~N
-~ L~ be continuous and such thatThen there exists ~p
affine
withDp(x)
E dx E SZ suchthat
( 1.1 )
has noviscosity
solutions.In section 3 we will
strengthen
thiscorollary by assuming only
thatQ~.
We next state a lemma which
plays
a crucial role in theproof
ofTheorem 2.6.
LEMMA 2.9. - Let SZ be bounded open and convex and p E with
l,
b’x E Q. Let u bedefined by
Let
y(x)
E ~S~ be such thatu(x)
= +p°(x - y(x)).
The twofollowing properties
then holdVol. 2-1999.
(i) If is
nonempty then the inward unit normal aty(x)
exists
(l. e.
isuniquely defined).
(ii)
Furthermoreif
p ED-u(x)
then there exists > 0 suchthat,
p = + where is the unit inwardnormal to ~SZ at y.
Proof
1. Let
If p then for every
compact
set K C(~ N
and h >0,
we havewhere E satisfies lim inf
E~h ~
= 0.In the
sequel
we assume without loss ofgenerality
thatsince, by
achange
of variables(2.7)
holds. Let p~ be the gauge associated to 03A9 i.e.We recall that
and
Now,
let Xo ES2,
let g~~ EI(xo)
and let qo E(the
subdifferential of pS2 at yo, in the sense of convexanalysis,
see R.T. Rockafellar[18]).
SincePsz is a convex
function,
we have~03C103A9(y0)
=(see [4]).
We haveNote that 0 since otherwise we would have 0 E and so, Yo would be a minimizer for p~ whereas > = 0. Define the
hyperplane touching
~03A9 at Yo and normal to qo,Annales de l ’lnstitut Henri Poincaré - Analyse non linéaire
and the barrier function
2. Claim 1. - We have u v on nand
u(.xo)
=v(xo).
Indeed,
for xEn,
let?/i(.r)
EPo
be such thatand let
In
light
of(2.8), (2.9), (2.10),
and the fact that EPo,
we haveand
Using (2.8), (2.11),
and(2.12)
we conclude that thereexists ~
E(0,1]
such that
Using
thehomogenity of 03C1°
we obtain thatWe therefore deduce that
As
p(Dp)
1 we have(see
Lemma4.1)
From
(2.14)
and the definitionof u,
we obtainSo we have
v(x)
>u(x).
Observe also thatv(xo) u(xo)
and so,v (xo )
=u(xo).
This concludes theproof
of Claim 1.Vol. 16, nO 2-1999.
3. Claim 2. - We have p E
D-v(xo).
Indeed,
inlight
of Claim 1 and(2.6)
we havefor every d in a
compact
set, and so,4. Claim
parallel
to qo(recall
that qo7~ 0).
Let ~i, -’’, be such that
{~o?’’’,
is a set oforthogonal
vectors.
Using
the definitionof v,
Claim 1 and the fact thatwe obtain
Combining (2.15)
and(2.17)
we deduce thatWhen we divide both sides of
(2.18) by h
> 0 and let h tend to 0 we obtainSimilarly,
when we divide both sides of(2.18) by
h 0 and let h tendto 0 we obtain
Using (2.19)
and(2.20)
we conclude thatthus,
for some A E R. It is clear
that 03BB ~ 0,
sincep(p)
= 1(by
the fact that u isa
supersolution
of(1.7)
andby
Lemma4.2)
and 1.Annales de 1 ’Institut Henri Poincaré - Analyse non linéaire
5. Claim 4. - p~ is differentiable at yo
(so
exists andv(yo)
= qoby
definition ofqo).
Suppose
thereexists q
E with qo. We obtainrepeating
thesame
development
asbefore,
thatfor some ~
/=
0. Sowith a
= ~ 7~
0. If a0,
then any convex combinationof q
and qo is inand thus 0 E which
yields
that yo is a minimizer for pS2which,
asalready
seen, is absurd. So we have a > 0.We will next prove that
for every q E
Assume for the moment that
(2.24)
holds and assumethat q
Esatisfies
(2.23). Then,
Consequently,
a =l, q
= qo and so,By (2.25)
we deduce that p~ is differentiable at Yo(see [18]
Theorem25.1).
We now prove
(2.24). Denoting by p~
theLegendre
tranform of onecan
readily
check thatWe recall the
following
well known facts:for every q E
(see [18]
Theorem23.5)
andVol. 16, n 2-1999.
Since Yo E we have =
l, which, together
with(2.27)
and(2.28) implies
thatHence, ps2(q) being finite,
we deduce = 0.Using (2.26)
and(2.29)
we obtain that .
6. Claim 5. - We have p =
Dcp(yo)
+ wherev(yo)
is the unit inward normal at yo.By
Claim 3 and Claim4,
there existsAo
such thatThe task will be to show that
Ao
> 0. LetWe have
Using
the definition of xh and thehomogeneity of 03C1°
weget
which, along
with(2.32) implies
In
light
of(2.6)
and(2.33),
we havewhich
yields,
Using
the definitionof 03C1° (see (1.9))
we haveAnnales de l ’lnstitut Henri Poincaré - Analyse non linéaire
Also, by (H3),
there exists 8 > 0 such thatCombining (2.34)
and(2.35)
we obtainMoreover,
since we can express xo as a linear combination of the normalv(Yo)
and thetangential vectors {qi}N-1i=1
at aSZ in yo, there exista and ~c2 with i =
1, ~ ~ ~ ,
N - 1 such thatAs and SZ is convex, a 0.
Using (2.31),
and(2.36)
we obtainThus, Ao
> 0. DWe now
give
theproof
of the main theoremProof of
Theorem 2.6.1.
(1)
=~(2)
We assume that u is aviscosity
solution of( 1.1 ).
From Theorem
2.2,
we have that everyviscosity
solution of( 1.1 )
is aviscosity
solution of( 1.7)
and thereforeby ( 1.8)
u can be written asLet ~/o E dSZ be a
point
where(see
the notations of theproof
of Lemma2.9).
Let x~ 03A9
be such that u is differentiable at x and xsufficiently
close from yo. Moreover the minimum in(2.37)
isattained,
at somey(x)
E ~SZ close to yo. Inlight
of Lemma 2.9 there exists> 0 such that
(i.e Du(x) - Dcp(y(:c))
isperpendicular
to thetangential hyperplane).
Note that
~o(y(x))
is boundedby 2~Du~~. Indeed, using
thehomogeneity
of p,
assuming
that = 1 we haveAs u is a solution of
(1.1),
i.e.Du(x)
EZF,
we obtain thatLetting x
tend to yo, we obtain thaty(x)
tends to y«. Sincewe have from Theorem 25.1 in
[18]
that /)Q is differentiableat yo.
By
Lemma 2.9 we have thatdpS2(y(x))
=f v(y(~))~
and p~ isdifferentiable at
y(x). Using
Theorem 25.5 in[18],
we obtain thatv(y(x))
tends to
Also, by (2.39) tends,
up to asubsequence,
toa
limit,
denotedAo
when x goes to yo. SinceZF
isclosed,
and F iscontinuous,
and so isDcp, (2.40) implies
As >
0,
we have thatÀo
0. Moreover u is solution of(1.7)
and so
Ao
isuniquely
determinedby
theequation
As
p(Dcp(yo)) l,
we have that 0 and so~~
> 0. This establishes that(1)
~(2).
2.
(2)
~(1) Conversely,
assume that(2.5)
holds.Using (1.8)
we obtain that u definedby
is the
viscosity
solution of(1.7).
We have to show that u is aviscosity
solution of
(1.1).
. Since u is a
viscosity
subsolution of(1.7),
then for every x E Q andVp
ED+u(x),
we have from Lemma4.2,
p Econv(ZF) (i.e.
p(p) 1).
As(Hl)
is satisfied(with
the convention:F(~) 0, b’~
Eint(conv(ZF ) ))
and as F iscontinuous,
it follows thatF(p)
0.So u is a
viscosity
sub solution of( 1.1 ).
. u is also a
viscosity supersolution
of(1.7),
and so, for every x E S~and every p E
D-u(x)
we havep(p)
> 1and,
from Lemma4.2,
sincep E
conv(ZF) (i.e. p(p) 1),
we obtainp(p)
= 1. From Lemma2.9,
there exists
y( x)
E ~SZ where the inward unit normal is well defined such thatAnnales de l’lnstitut Henri Poincaré - Analyse non linéaire
Since
p(p)
=1, then A(y(x))
> 0 isuniquely
determinedby
And so from
(2.5),
we deduce that p EZF.
ThusF(p)
=0, Vp
ED-u(x).
We have therefore obtained that u is aviscosity supersolution
of(1.1).
The two above obsevations
complete
theproof
of thesufficiency part
ofthe theorem. D
We conclude this section with the
proof
ofCorollary
2.8.Proof of Corollary
2.8.To prove that there
exists p
E such that theproblem (1.1)
has noviscosity solution,
it is sufficientusing
Theorem 2.6 tofind y
E wherethe unit inward normal
exists,
such that1. Without loss of
generality,
we suppose that 0 E Let p be the gauge associated with the setco7av(ZF).
We have that pis differentiable for almost every a E
So,
sinceZF ~ a(corav(ZF))
andZF
isclosed,
we can choosea E
ZF
such that a is apoint
ofdifferentiability
of p.2. We first prove that there exists
yo e aS2,
wherev(yo) exists,
withfor A 0 small
enough.
Let a =Dp(a). By
Lemma 4.3 the exists yo E aSZsuch that the normal
v(yo)
to dSZ at yo exists andUsing (2.42)
and the fact that p is differentiable at a we obtain(keeping
in mind that
p(a)
=1)
for A 0 small
enough.
This concludes theproof
of(2.41).
3. Choose y E
dS2,
wherev(y) exists,
and A0,
such that/3
= Eint(conv(ZF)) (such ~
existsby
theprevious step).
Observe thatby convexity of p
we have sincep(a)
= 1 andp(a
+ 1 thatp(a
+ > 1 forevery ~
> 0. Letcp(~) _ ,~, ~
>. We thereforehave
for
every A
> 0. That is the claimed result.Vol. 16, nO
3. THE VIABILITY APPROACH
In the
previous section,
we have assumed thatZF
C andS2 is convex. We have
proved
that a necessary and sufficient conditions for the Hamilton-Jacobiequation
to admit a
viscosity
solution isthat,
for any y E ~SZ where there is an inward unitnormal, v(y),
there existsA(y)
> 0 such thatIn this
section,
we nolonger
assume thatZF
Ca(conv(ZF))
and S2is convex. We
investigate
the existence of aviscosity
solutionfor Hamilton-Jacobi
equation (3.1)
for any (/?satisfying
thecompatibility
condition
Dp(y)
Eint(co7av(ZF)).
The main result of this section is
that,
ifthen there is some affine map 03C6
satisfying
thecompatibility condition,
and for which there is no
viscosity
solution to(3.1 ) (c.f.
Corrolary 2.8).
THEOREM 3.1. - Let F :
(~N
--~ R be continuous such that the setZF = ~ ~
EF ( ~)
=0) is compact ~.
Then
for
any bounded domain SZ there is someaffine function
p withDcp
Eint(conv(ZF))
such that theproblem
has no
viscosity
solution.The
proof
of Theorem 3.1 is a consequence of Theorem 3.4 below.For
stating
thisresult,
we need the definition ofgeneralized
normals(see
also
[1]).
DEFINITION 3.2. - Let K be a
locally compact
subsetof ~p,
x E K. Avector v E
(~p
istangent
to K at xif
there arehn
-~0+,
vn -~ v such thatx +
hnvn belongs
to Kfor
any n E N.Annales de l’lnstitut Henri Poincaré - Analyse non linéaire
A vector v E is a
generalized
normal to K at xif for
everytangent
v to K at x
We denote
by NK (x)
the setof generalized
normals to K at x.REMARK 3.3. -
i) If
theboundary of
K ispiecewise Cl,
then thegeneralized
normals coincide with the usual outward normals at anypoint
where these normals exist.
ii) If
S2 is an open subsetof RP
and xbelongs
to~03A9,
then ageneralized
normal v E can be
regarded
as an interior normal to SZ at x.THEOREM 3.4. - Let SZ c
I~N
be a bounded domain and let F :(~N
~ (~be continuous such that the set
ZF = ~ ~
E( F ( ~)
=0 ~
iscompact.
Let_
b, y
> with b Eint(conv(ZF)).
If F(~)
0(resp. F(~)
>0) for
everysufficiently large
andif equation (3.1)
has a(S~) viscosity supersolution (resp. subsolution),
then
for
any y Efor
any non zerogeneralized
normal vy Eto SZ at y, there is some ~ > 0 such that
REMARK 3.5. - In some sense, Theorem 3.4
improves
the necessarypart of
Theorem 2.6 since we do not assume any more thatZF
cand that SZ is convex.
Moreover,
this resultgives
a necessary conditionof
existence
for
sub orsupersolution.
For
proving
Theorem 3.4 and3.1,
we assume for a moment that thefollowing
lemma holds.LEMMA 3.6. - Let SZ c
I~N
and F be as in Theorem 3.4.If
there is somea E such that
1.
0, 0,
2. ~x E aSZ such that a E
then there is no
viscosity supersolution
toProof of
Theorem 3.4.Assume for instance that
~F(~)
0 for~~~ sufficiently large.
Fixb E
int( conv( Z p ))
and 0 for which there is some x E ~03A9 such that a EVol. 16, n° 2-1999.
If
F(b)
>0,
then the result is clear because F is continuous andF(b
+Aa)
isnegative
for Asufficiently large.
Let us now assume that
F(b)
0. Let u be asupersolution
toSet
F(~)
:==F(~
+b)
andu(y)
:=u(y)- b, y
>. It is easy to checkthat ii is a
supersolution
toSo,
from Lemma 3.6 there is some 0 such thatF(~«a) > 0, i.e.,
F(b
+ 0. SinceF(b
+Aa)
isnegative
for Asufficiently large,
thereis A >
Ao
such thatF(b
+Aa)
= 0.We have therefore
proved
that there 0 such that b + Aa EZF.
0Proof of
Theorem 3.1.Since F is continuous and
Zp
isbounded, F(~)
has a constantsign
forsufficiently large. Say
it isnegative.
Let bE and r > 0 be such that
B.,.(b) f1 ZF
=~J.
Fromthe
Separation Theorem,
there is some a ERN, ~a~
=1,
such thatNote that
F(b)
0.Indeed,
F is continuous andF(b
+~a)
0 forlarge
A.Moreover,
b + Aa neverbelongs
toZF
forpositive A
becauseFrom Lemma 5.3 in
Appendix 2,
there is some x E 9~ and ageneralized normal vx ~ NRNB03A9(x)
such that’ Set 0 ~ = >, a = +
6), ~
= b - aa. Let A > 0. Weare
going
to prove that~
+A~ ~
If Acr/6,
thenAnnales de l’lnstitut Henri Poincaré - Analyse non linéaire
so that
F(ba
+ 0 becauseBr(b)
nZp = 0
andF(b)
0.If A >
a/E,
thenso that
b«
+ZF .
Since vx
is ageneralized
normal to at x and sincebo-
+03BBvx ~ ZF
for
any À 0,
Theorem 3.4 states that there is noviscosity supersolution
to the
problem (3.1)
with = >. DProof of
Lemma 3.6.The main tool for
proving
Lemma 3.6 is theviability
theorem. Theviability
theorem(c.f.
Theorem 3.3.2 and 3.2.4 in[2])
statesthat,
if G isa
compact
convex subset ofR~
and K is alocally compact
subset ofRP,
then there is an
equivalence
betweeni)
‘dx GK,
there exists T > 0 and a solution toii)
‘dx EK,
‘dv ENK(x),
inf g, v > 0.gEG
As
usual,
the solution of the constrained differential inclusion(3.2)
canbe extended on a maximal interval of the form
[0, T)
such that’either
T = +00, or
x(T) belongs
toAssume now
that, contrary
to ourclaim,
there is someviscosity supersolution u
to theproblem.
We willproceed by
contradiction.First step: We claim that
Indeed, otherwise,
there is some x E H minimum of u. Note that 0 ED-u(x),
so thatF(0) >
0 because u is aviscosity supersolution.
This is in contradiction with
F(Aa)
0 for all A > 0.The
proof
of the lemma consists inshowing
thatinequality (3.3)
doesnot hold.
Second
step:
Without loss ofgenerality
we set~a~
= l. SinceZF
iscompact
and 0 for 03BB ~0,
there is somepositive
E such thatSince u is a
supersolution,
weknow,
from a result due to H. Frankowska[15] (see
also Lemma 5.1 inAppendix 2),
thatLet x E 0 and
(vx, vp)
Eu(x)).
SinceF( ~vx~ ) > 0,
we havethanks to
(3.4),
PAn easy
computation
shows that thisinequality implies
Let G =
{a
+(1 - Ez)1~2 B}
x{0}
where B is the closed unit ball of Then theprevious inequality
isequivalent
with thefollowing
so that K =
Epi(u)
n(H
xR)
is alocally compact
subset such thatIn
particular,
it satisfies the condition(ii)
of theviability
theorem.Thus,
from theviability theorem, ‘d (x, u(x) )
EK,
there is a maximalsolution to
where either T = o0 or
x (T )
ELet us
point
out thatp’(t)
=0,
so thatp(t)
=u(x)
on[0, T).
Annales de l ’lnstitut Henri Poincaré - Analyse non linéaire
Third
step:
Let x E ~03A9 be such that a E We claim that there is a solution to(3.5) starting
from(x, u(~)) _ (x, 0)
defined on(0, T).
Since a
belongs
to from Lemma 5.2 of theAppendix 2, applied
to C ={a
+(1 - EZ)1~2 B~,
there is some a > 0 such thatVc E
C,
Vb ERN with |b| l,
VB E(0, a), x
+9(c
+ab)
E H.Since
0 ~ C,
we can choose also a > 0sufficiently
small such that0 ~
C +aB,
where B is the closed unit ball.We denote
by
S the setIt is a subset of 0 and x E o~s.
Let zn E S converge to x,
(xn ( ~ ) , pn ( ~ ) )
be maximal solutions to(3.5)
with initial data(xn, u(xn))
defined on[0, Tn ).
Let us first proveby
contradiction that the sequence Tn is bounded from below
by
somepositive
T. Assume on the
contrary
that Tn 2014~0+.
Note thatbecause
x’ (t)
E C which is convexcompact. Thus,
for any n, there is cn E C such thatXn(Tn)
= xn +Since xn E
S,
forany n >
N there areOn
E(0, a), bn
E B andcn
E Csuch that xn =
+abn).
Since xn converges to x and0 ~ C + aB,
we
have 9n
-~0+.
LetNo
be such thatNo, 8n
+ Tn a.Then
Since C is convex,
belongs
to C.Moreover,
Thus,
forany n > No, belongs
to S which is a subset of 0 andwe have a contradiction with
Xn ( Tn)
EVol. 16, nO 2-1999.
So we have
proved
that the sequence Tn is bounded from belowby
some
positive
T.Since G is convex
compact
and since the solutions(~~(~), p~(~))
aredefined on
[0, T],
the solutions(x,L(~), p,z(~))
converge up to asubsequence
to some
(~(~), p(.))
solution to(see
Theorem 3.5.2 of[2]
forinstance).
Since, :x’(t)
EC,
forany t
E[0, T]
there is somec(t)
E C such thatx(t)
=m-f-tc(t). Thus,
for t E(0, inf f T, a}), x(t) belongs
to S and so to S2.In
particular, (x(t), p(t))
_(~(t,), 0) belongs
to theepigraph
of u fort E
(0, T’) (with
T’ =i.e.,
This is in contradiction with
inequality (3.3).
D4. APPENDIX 1
We now state two lemmas which are well-known in the literature. The first one is a Mac Shane
type
extension lemma forLipschitz
functions.The second one can be found in F.H. Clarke
[7]
and H. Frankowska[14].
However for the sake of
completeness
we prove themagain.
LEMMA 4.1. - Let 0 be a convex set
of I~N
and u E withp(Du(x))
1 a.e. inH,
then there exists an extension ic Eof
u with
p(Dic(x))
1 a.e. inProof.
The task here is to check that ic
given by
satisfies the
requirements
of Lemma 4.1.(Note
thesimilarity
with theviscosity
solution(1.8).)
1. We first show that n is an extension of u.
Annales de l’lnstitut Henri Poincaré - Analyse non linéaire