C AHIERS DE
TOPOLOGIE ET GÉOMÉTRIE DIFFÉRENTIELLE CATÉGORIQUES
A. P ULTR
J. S ICHLER
Finite commutative monoids of open maps
Cahiers de topologie et géométrie différentielle catégoriques, tome 39, n
o1 (1998), p. 63-77
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FINITE COMMUTATIVE MONOIDS OF OPEN MAPS by A. PUL TR and J. SICHLER
CAHIER DE TOPOLOGIE ET
GEOMETRIE DIFFERENTIELLE CATEGORIQUES
l’olume XXXIX-1 (1998)
RESUME. Pour
qu’un semigroupe
commutatif fini soitisomorphe
ausemigroupe
de toutesles
applications
continues ouvertes d’un espace de Hausdorff danslui-meme,
ou a celui desendomorphismes
deHeyting complets
d’unealgebre
deHeyting qui
est Hausdorff, il faut et il sutlitqu’il
soit leproduit
d’un groupe et de divers groupesaugment6s
par (). TJne telle caract6risation n’est pas valable pour lessemigroupes
intinis.In
1966,
Paalman de Mirandaproved
that a certain finite monoid cannot berepresented
as the monoidDp(X)
of all open continuousmappings
of any Hausdorffspace X
into itself[9].
Herdiscovery interestingly
contrasts with these two facts:- every monoid is
isomorphic
to the monoid of allquasi- open
continuous map-pings
of a metric space into itself(this, together
with similarresults,
can befound in
[15],
see also[14,16]),
- every monoid is
isomorphic
to the monoidDp(X)
for aTi-space X,
see[14,16] and,
as observed in[13],
even for aspace X
that is bothTl
andsober.
In
[13],
we have extended Paalman de Miranda’s result to theconsiderably
widercontext of Hausdorff
Heyting algebras
and theircomplete Heyting homomorphisms (the
word ’wider’ is somewhatimprecise,
for there existmarginal
cases of Hausdorffspaces whose
corresponding Heyting algebra
is notHausdorff,
see Isbell[5]).
Inaddition,
wefound that, apart
fromcyclic
groups,only
asingle one-generated
finitemonoid is
representable
in eithercategory.
In the
present
paper we describe all finite commutative monoidsisomorphic
tothe monoid
Dp(X)
for some Hausdorff spaceX,
or to the monoid of allcomplete Heyting endomorphisms
of some HausdorffHeyting algebra
in the sense of Isbell[5].
It turns out that these monoids are
products
1991 Mathematics Subject Classification. Primary: 20M30. Secondary: 06D20, 54D10, 54C10.
Key words and phrases. endomorphism, open continuous map, complete Heyting homomor- phism, strong graph homomorphism, Hausdorff property.
The authors gratefully acknowledge the support of the National Science and Engineering Re-
search Council of Canada and of the Grant Agency of the Czech Republic under Grant
201/96/0119.
in which
Go
is a group and each monoidG9 (if any)
is a groupGi augmented by
a zero. This also characterizes finite commutative monoids formedby strong endomorphisms
ofsymmetric graphs.
These threecategories strongly
contrast theirrespective
non-Hausdorf ornon-symmentric counterparts:
thecategories
of-
Ti-spaces
and open maps,-
complete Heyting algebras
andcomplete Heyting homomorphisms,
- directed
graphs
andstrong homomorphisms
are
algebraically
universal(see [14,16], [13], [14]),
and hence every monoid- is repre-sentable as an
endomorphism
monoid in each of these widercategories.
We also show that the situation
changes
for infiniteendomorphism
monoids: forinstance,
the additive monoid of natural numbers isrepresentable,
and so are all itsfinite or
countably
infinite powers.Only
basic notions ofcategory theory,
those found in the initialchapters
of[1]
or
[8],
are needed here. The few facts on frames notexplained
below can be foundin
[7]
or in[13].
Atopological
constructionpresented
in Section 4 is based on aconstruction from
Chapter
VI of[141;
to aid the reader and to avoid unnecessaryrepetition,
we refer to[14]
in considerable detail andadopt
the notation used there.1. PRELIMINARIES
1.1. A concrete
category is,
asusual,
acategory
Cequipped
with a faithful functorI I
: C Set into thecategory
Set of all sets andmappings.
We say that a finitecoproduct
in C is a concrete sum in a concrete
category (C, ||) provided |X|
is adisjoint
union|X1|
U ... UIXnl
and|ji|: |Xi|
-|X|
are thecorresponding
inclusion maps. If thisis the case, we write
A
C-object
Y is called a summand of aC-object
X if X = Y U Z is a concretesum for some Z.
Then,
of course, theC-object
Z is a summand of X as well and|Z| = |X/Y|.
A concrete
category
has tamesummands,
and is called aTS-category,
if it hasthese three
properties:
(TS1)
for any two summandsX
andX2
of X there exists a summand Y of X withIYI
=IXII n |X2|,
(TS2)
allpreimages
of summands underC-morphisms
aresummands,
(TS3)
for any two concrete sums X =U Xi
and X =U Yj
there exists a commonrefinement,
thatis,
a concrete sum X =U Zij
with|Zij I = IXE Q |yj|.
There is no
danger
of confusion inwriting
Y =X1 nX2
rather thanIY
(=|X1| |n| X2|
in
(TS 1 ) . By (TS 1 ),
for any two summandsX
1 andX2 of X ,
there is a summandZ of X with
IZI
=|X1|B |X2|,
and we willsimply
write Z =X1B X2
hereagain.
’1‘here are numerous
cxainples
of7’S-categories.
Thecategory Top2,o
of Hausdorff spaces and their open continuous maps is a
TS-category and, together
with
categories
related toit,
will be ofparticular
interest here.1.2.
Proposition.
LetX1, ..., Xn
be summands(not necessarily disjoint
of anobject
X in aTS-category C,
and let|X| = |UXi|.
Iff : |X|
-->IYI
is amapping
such that each
f [ IXi carries
aC-morphism Xi
-Y,
thenf
carries aC-morphism
X --+ Y.
Proof.
Use the common refinement of the n concrete sumsX=XtU(XBX,).
01.3. Let
(X, )
be aposet.
We say that a subset Y C X isdecreasing
if x y E Yimplies
x EY,
andincreasing
ifx > y
E Yimplies
x E Y. Recall that an orderedtopological
space X =(X, T, )
is aPriestley
space if(X, )
is aposet
and(X, T)
is a
compact topological
space, and if for any closeddecreasing
set Y‘ C X and anyx
E X B
Y there exists aclopen decreasing
set B such that Y C B andx E
B.Any continuous,
orderpreserving mapping f :
X --+ X’ betweenPriestley
spacesX, X’
is called a
Priestley
map. In whatfollows, PSp
will denote the
category
of allPriestley
spaces and allPriestley
maps.Observation. A subset Y of a
Priestley
space X is a summand of X if andonly
ifit is
increasing, decreasing
andclopen
in X . HencePSp
is aTS-category.
01.4. Recall that a
frame
is anycomplete
lattice L in which(v S) A a = V {s A a I
s E
S}
for any S C L and a EL,
and that a framehomomorphism
h : L - L’ is anymapping preserving
finite meets andarbitrary joins.
Atypical
instance of a frameis the lattice
0(X)
of al1 opon sets of o,topological
spaceX;
andif f :
X - X’is a continuous map into a space
X’,
then theinverse-image
mapf -1= iD(f) D(X’) - D(X)
is a framehomomorphism.
For the so-called sober spaces, that
is,
spacessatisfying
a certain condition weaker than the Hausdorffseparation axiom,
themapping f H D(f)
is an invertible con-travariant
correspondence
of continuous mapsf :
X --> X’ to framehomomorphisms D(f): D(X’) - D(X). Moreover,
any sober space X can be reconstructed from its frameD(X),
and this iswhy
a frame can be viewed as a naturalgeneralization
of a(sober)
space.A frame L is called
Hausdorff (in
the sense ofIsbell,
see[5,7])
if thecodiagonal
map L ® L --+ L of the free
product L D
L into L satisfies a certaincondition,
applied
in[13].
The actual form of this condition issecondary,
for we shall useonly
its consequenceproved
in[13],
and use itonly
once. It should be noted thatthe frame
D(X)
of a Hausdorffspace X
is notnecessarily
Hausdorff in the sense ofIsbell,
but thatD(X)
is Hausdorff whenever X isregular.
1.5. The distributive law of 1.4
implies
that any frame L is also acomplete Heyting algebra,
and that theHeyting operation
- isuniquely
determinedby
L.Moreover,
for Hausdorff spaces X and
X’, complete Heyting homomorphisrns D(X’) ---+
D(X) correspond
to those continuous mapsf :
X ---+ X’ which are open, see[2,6] .
In what
follows,
H H eyt
will denote the
category
of a.llHeyting algebras
that are Hausdorff in the sense ofIsbell,
and of all theircomplete Heyting homornorphisms.
1.6. We now recall the celebrated
Priestley duality,
a contravariant natural iso- functorD : PSp - D
of the
category PSp
ofPriestley
spaces onto thecategory
D of distributive(0,1)-
lattices and their
(0,1 )-homomorphisms.
For anyPriestley
spaceX,
the elementsof D(X)
arerepresented by clopen decreasing
subsets of Xand,
for anyPriestley
map
f :
Y --iX,
thehomomorphism D(f): D(X) --> D(Y)
is the restriction of the inverseimage
mapf-1
to the collection of theserepresenting
sets.In what
follows,
theimage
of the categoryH Heyt
under the inverseV-1
of D will be denoted asHPSp
and referred to as the
category
of allHP-spaces
andHP-maps.
It is clear thatH P S p
is not a fullsubcategory
ofPSp.
2. HAUSDORFF CATEGORIES
2.1. Definition. We say that a
TS-category
C isHausdorff if,
for anyC-object X,
the
image
of any
endomorphism
h : X --> X withh2
= h is a summand of X . 2.2.Proposition.
Thecategory Top2,o
is HausdorffProof.
If h : X - X is continuous and open, then itsimage h[X]
is open. Sinceh[X] = {x| h(x)
=z)
and X isHausdorff,
the seth[X]
is alsoclosed,
and it is clear that anyclopen
subset of X is a summand of X inTop2,o.
02.3.
Proposition.
Thecategory H PSp is
HausdorffProof.
Wealready
know thatH PSp
is aTS-category.
Let X be a HausdorffPriestley
space, and let h =
h2
E End X . Since h is thePriestley
dual of acomplete Heyting endomorphism,
theimage
Y= h[X]
is a closedsubspace
of X that is alsodecreasing,
see
[12]. Furthermore,
theH PSp-map h
has adecomposition X h1 -->
Yh2 --> X
in which thePriestley
maph.l
issurjective,
and the inclusion maph2
is such thatD(h2)
is a
complete surjective Heyting homomorphism.
Inparticular, D(h2)
is asurjective
frame
homomorphism,
and henceD(Y)
isHausdorff,
see[7].
Therefore Y EHPSp.
Next we note that
h2
is anequalizer
of h andidX. Indeed,
h oh2 = idx
oh2
follows from h o
h2
oh,
= h o h = h =h2
oh,
becausehl
issurjective.
On theother
hand,
if h o k =k,
thenh2
0(hl
ok)
=k,
and thefactorizing
maphl
o k isunique
becauseh2
is one-to-one. Thisimplies
that thesurjective complete Heyting homomorphism D(h2) : D(X)
--+D(Y)
is acoequalizer of D(h)
andidD(X).
Butthen, by
Lemma 4.4 of[13],
there exists acomplemented
a ED(X )
suchthat,
forany
b,
c ED(X),
-D(h2)(b)
=D(h2)(C)
--> b A a = c A a.D(h2)(b)=D(h2)(c) =>
6Aa=cAa.Therefore
D(h2)(b)
=1D(Y)
if andonly
if b > a inD(X). Simultaneously,
sinceh2
is the inclusion map of Y’ intoX,
it follows t,hath2 -1 (b) = bn
Y for anyclopen decreasing
b C X. Inp,-ii-t,iciilar
, and hencey C a. If there exists an .1: E a w Y
then, hy
I .($, there exists aclopen decreasing
setb C X with
x E b and
Y C G. But thenD(h2)(b)= h2-1 (b)
= Y =1D(y)
whileb l
a- a contradiction. Therefore Y = a. Since the element a is
complemented
inD(X),
the set Y =
h[X]
isincreasing, decreasing
andclopen
inX,
and this isobviously
true also for the set X w Y . Therefore X is a summand of
X ,
see 1.3. 02.4. Recall that a
pair (X, R)
is a directedgraph
if X is a set and R C X x X isa
binary
relation onX ,
and that amapping f :
X --> Y is agraph homomorphism
from
(X, R)
to a directedgraph (Y, S)
if(f(x), f(x’))
E ,S’ for every(x, X’)
E R.If o denotes also the
composition
ofrelations,
then the conditiondefining
agraph homomorphism
isequivalent
to the inclusionA map
f :
X - Y is called astrong homomorphism
from(X, R)
to(Y, S)
ifThe
category
of all directedgraphs
and theirstrong homomorphisms
isalgebraically universal,
and hence every monoid isisomorphic
to the monoid of allstrong
endo-morphisms
of some directedgraph,
see[14].
As we will see, this is no
longer
true forstrong homomorphisms
ofsymmetric
directed
graphs,
thatis, graphs (X, R) satisfying (x, x’)
E R if andonly
if(x’, x)
E R(see
3.5 and 4.6below). Thus,
in a sense, thegraph symmetry plays
a role similar to the Hausdorfftopological
axiom.Observation. The
category
SymGraphs
of all
symmetric
directedgraphs
and theirstrong homomorphisms
is Hausdorff.Proof.
It is easy toverify
that Y C X is a sumrnand of asymmetric
directedgraph (X, R) exactly
when(s) xRy
and y E Yimply
x EY,
and that
SymGraphs
is aT,S’-category.
Letf
be any(not necessarily idempotent)
strong endomorphism
of(X, R).
To show thatf [X]
is afactor,
suppose thatxRy
and y E
f [X].
Then y =f(t)
for some t EX,
and hencex(R o f )t.
But thenx( f
oR)t
becausef
isstrong,
and hence x =f (u)
for some u with uRt. Thereforef [X]
satisfies(s),
and hence it is a summand in(X, R).
02.5. Our main interest is the behaviour of
endomorphism
monoids inHHeyt
orHPSp,
and now we return to thesecategories.
Since the lattercategory
does notcontain all
of Top2,o
and becauseproofs
for hothcategories
areessentially identical,
we work in the more
general setting
of Hausdorffcategories
that covers both of them.Moreover,
this notional)l)lles
to othercategories,
such asSymGraphs.
3. ENDOMORPHISMS IN HAUSDORFF CATEGORIES
3.1. With the
exception
of Theorem 3.6 and itscorollary,
thesymbol X
willalways
denote an
object
in a HausdorffTS-category.
In whatfollows,
End X is the
endomorphism
monoidof X,
Aut X is the
automorphism
group ofX,
andIdpX={f~EndX f2= f}.
3.2.
Proposition.
Lem, End X be finite and cmnmutative. Then everyf E
End Xhas a
decomposition
f =
g o !iwith g E
Aut X and h EIdp X,
in which the
idempotent
b isuniquely
determined.Proof.
Since End X isfinite,
there is a leastinteger n >
0 such thatfn+k
=f’
forsome k > 0.
If n =
0,
thenf
E Aut X and we are done.Suppose
that n > 0. ThenFor any
integer
kr > n we thus havefkr [X]
=fn [X].
Fromf 2kr = fkr
it thenfollows that F =
fn [X]
is a summand. But then thepreimage f-1(F) D
F of F isalso a
summand,
and hence themap cp : X -->
X definedby
is an
endomorphism
of X . For any x Ef -2(F) B f -1 (F)
we then havewhich is
impossible.
Fromf-2 (F) D f -1 (F)
it then follows thatand
hence, by induction,
But then
f [X]
= Fand, consequently,
Therefore the restriction of
f k
to F is theidentity
onF,
and hence themapping
g : X-->X
given by
belongs
to Aut X.Furthermore,
(3.2.1)
Next we define h E End X
by
Since
h2(x)
=h f (x)
=J(x)
=h(x)
forx V F,
we haveh E Idp X .
Ifx E F,
thengh(x) = gf(x) = f (x) by (3.2.1) and,
if x EF,
thengh(x) = g(x)= f(x) again.
Therefore
f
= g o h as claimed.Finally,
suppose thatf
=g1h1 = 92h2 with gi
E Aut X andhi
EIdp X .
Theng1h1 = 92h2h2
=g1h1h2
and hencehi
=hl h2. By symmetry h2
=h2hi ,
and thenhl
=h2
follows fromhi h2
=h2h¡.
03.3. For any
f
E End X defineSince X
belongs
to a Hansdorffcategory,
forany h
EIdp X,
(3.3.1) Fix(h)
=h[X]
andMov(h)
are summands of X.3.4. Lemma. Let End X be commutative. Then for any
h,
k EJdp
X andf
EEnd X
Proof. By (3.3.1),
there is anendomorphism
For x E
Mov(h)
we thus havefh(x) = cph( x)
=hcp(x) = h(x),
and this proves(3.4.1). Suppose
that x EMov(h) r1 Mov(k).
Thenh(x)
EFix(k)
andk(x)
EFix(h), by (3.4.1),
and hence11.(.1’) = k,h(x)
=hk(x)
=k(x).
03.5. Theorem. IJef, A IHB an
object
of a Hausdorffcategory,
alld /(’t, End X be finite and commutative. Then there is an n > 0 such thatwhere
Go is
a groupand CT°, ... , G’
are groupsaugmented by
an external zero.Proof.
The monoidIdp
X is a semilattice. Forevery h
EIdp
X we writep(h) = Mov(h). By (3.4.1),
forany k
EIdp X
we haveMov(h)
UMov(k)
gMov(hk) and,
since the reverse inclusion is
obvious,
we conclude thatSecondly,
ifh, k
EIdp X
andli(h) = p(k) then, by (3.4.2),
for every EMov(h) = Mov(k)
we haveh(x)
=k( J;),
and then h = k follows.Therefore 03BC
is aninjective homomorphism
ontoa join
scmHatticc(.I, U)
of Stl bsets ofX, and 0 = I-,,(idx)
E J.If .S is a summand of X and h E
Idp X,
thenMov(h)
fl S is a summand of X aswell,
see(3.3.1),
and hence themapping 11,(5) : X ---4
Xgiven by
is an
idempotent endomorphism
withMov(h(S))
=Mov(h)
n S. Since ,S’ =Mov(k)
and S = X w
Mov(k)
are summands ofX ,
see(3.3.1),
we concludethat p
mapsIdp X isomorphically
onto thejoin
reduct(J, U)
of a finite Booleanalgebra
J ofsubsets of X . If J =
{0},
thenIdp X
={idx}
and hence End X = AutX. Fromnow on, we assume that J is
non-trivial,
and leth 1, ... , hn
EIdp X
denote thoseendomorphisms
for which{03BC(hi)|
i =1, ... ,n}
is the set of atoms of J. Sinceany finite Boolean
algebra
J with more than t,wo elements isatomistic,
for every h EIdp X
there is a(possibly empty) unique
subset AC {1,..., n}
such that h is thecomposite
of the ’atomic’idempotents hi
with i EA,
and we -vrite h =hA .
Thus the
sets
are
nonvoid, pairwise disjoint
minimal summands ofX,
andFrom
(3.4.2)
it now follows thatFinally,
writeM0 = X 1, (All
U ... UMn ).
ThenMo
is a nonvoid summand of X becaiise of(TS3),
and henceIt is clear that
Let
f
E EndX and la EIdpX.
If x EMov(h),
thenfh(x)= h(x) by (3.4.1),
while,
for any x EFix( h. ) ,
weobviously
havefh (x)
=f(x).
Inparticular,
If g E Aut X and h = 11; for some i =
1,...,n,
thenhi,g(x) - ghi(x) = hi(x)
forevery x, E
Mi
=Mov(h,),
t.hat.is,
Since g
isinvertible,
we havehig(x)
=ghi(x) =1= g(x)
for every x EMi.
Thusg[Mi]
CMs
for every i =1, ... ,
n, and it follows thatNow let
,f
E End X bearbitrary.
Thenf
= g o h for some g E Aut X and auniquely
determined h EIdp X , by Proposition
3.2. Since h =hA
for aunique
A C
{1,..., n},
from(3.5.4)
and(3.5.1)
it then follows thatFor j
=0, 1, ... ,
n,denote fj
=f |Mj. Then Ii = hj for j
E Aand fi
E AutMj
=Gi
forall i E {0,1,..., n}B A.
Sincehi
is an external zero ofGi
for all i =1, ... ,
n,see
(3.5.5),
this shows thatis a well-defined
mapping
of End X into the Cartesianproduct
of the group
Go
and monoidsG9
=Gi
U{0i}
obtained from the groupsGi by
theaddition of an external zero
Oi
for each i =1,
... n.Using (3.5.7),
it is easy toverify that p :
End X --+ P is a monoidhomomorphism.
Conversely,
let(fo, 11, ... , fn)
E P. Thenfo
E AutMo
andfi
E AutMi
U{0i}
for i >
0,
and themapping f
=V)(f0, f1,..., fn ) given by
belongs
to End X because of(3.5.2).
It is clear that themapping 1/J
is the inverse ofthe
homomorphism
p. 0Corollary
3.6. Let X he anobject
of a Hau.sdorffcategory.
Let End X be finite andcommutative,
and let Aut X be trivial. Then End X isisomorphic
to a freejoin
semillatice with zero, or,
equivalently,
to a semilattice(2n, U).
04. MONOID REPRESENTATIONS
In this
section,
we shall use certain spaces andgraphs
constructed in[14]
asbuilding
blocks forrepresentations
of the finite commutative monoids describedby
Theorem 3.5 as
endomorphism
monoids in thecategories Top2,o (and
hence also inHHeyt
andPSp)
andSymGraphs.
First we turn to thetopological
construction.4.1.
For j = 0, 1, ... ,
let HJ be non-trivial metric continua withdistinguished points
aj0, aj1, aj2 E Hj
constructed in Section 6 ofChapter
VI in[14].
We divide up thesecontinua into two families
and denote
Further,
we recall the metric spacesM(X, R, cp) amalgamated
from these metric con-tinua
Hj
elsewhere inChapter
VI of[14],
and consideronly
those spacesM(X, R, cp)
such that
Thus we
begin
with- non-trivial metric continua
Hi
withdistinguished points aj0, aj1, aj2
EH’
forj=0,1,...,
- a
countably
infinite collectionP1
of metric spaces P =M(X, R, cp) subject
to
(*)
above.The
proof
of Lemma 6.9 in Section 6 ofChapter
VI in[14]
shows thatP1
has theseproperties:
(4.1.1)
ifHi
is embedded into a space P EPi
in such a way thatHj0
is open, thenevery continuous map
f : H0k ---+
P withf [H0k]
flHj0#0
is either a constantor
else j
= k andf
is theembedding,
(4.1.2)
ifHi
E11°
and P EPi
then any continuousf : Hj --+
P is constant.Furthermore,
we recall that for any monoid S there exists a spaceP(Sf)
EP1
suchthat all non-constant continuous maps
f : P(,f)
-P(S)
form a monoidisomorphic
to S.
Thus,
inparticular,
(4.1.3)
for any group G there exists someP(G)
EP1
such that the monoid of all open continuousmappings f : P(G) - P(G)
isisomorphic
to G.4.2. Construction. For a metric space P and a non-trivial metric continuum
Hi,
we define a space
P * IIj
on the Cartesian
product
P xHi by requiring
that- the
neighbourhoods of (x, ai)
are the setscontaining (U
x(a( ))
x({x}
xV),
where U is a
neighbourhood
of x in P and V is aneighbourhood
ofao
inHj,
while- the
neighbourhoods
of any(x, y)
withy# ao
are the setscontaining {x}
xV,
where V is aneighbourhood
of y inHj.
Having
renamed each(x, aj)
as x, we observe that P is asubspace
of P* Hi.
Thespace P *
Hi
may thus be visualized as the space obtainedby attaching separate copies
ofHi
to members of Pby
theirdistinguished
elementao.
The claim below is immcdiate.
Lemma. The
mapping
g x id : P *Hj --+ Q* Hj
is continuous and open for any opencontinuous 9 :
P -Q .
04.3. Lemma.
Let Q
be such that every continuousmapping of Hk to Q
isconstant,
and let amapping
be open continuous. Then k
= j
andf
= g x id for someopen continuous g :
P -Q.
Proof.
Let x E P. Sincef
is open, the setf [IXI
xHk]
is not asingleton,
and hencef [{x}
xHk] Cl Q by
thehypothesis.
But then(’1.1.1) implies
that k= j
and there isa
unique y ~ Q
such thatf (x, z) = (y, z)
for all z EHk .
Thisgives
rise to aunique
mapping
g : P -Q
for whichf
= g x id. It is routine toverify
that g is open. 04.4. Recall
that,
for any spaceP,
thesymbol Dp(P)
denotes the monoid of all open continuousselfmaps
of P .Lemma. Let
{Pa| a E A} be a
countable collection of metric spaces fromP1.
Then there exists a metric space P such thatProof.
Select distinct metrizable continuaHj(a) E 1-l°,
and thenapply (4.1.2),
Lemma 4.3 and Lemma 4.2. D
4.5. Now we turn to the
category SymGraph,s
ofstrong homomorphisms
od sym-metric directed
graphs.
Let A be an
arbitrary set,
and let Z =({0}) {(0, 0)})
denote thesingleton graph
in the
alg-universal category Grac
of all connected directedgraphs
and their ho-momorphisms.
From Theorem 3 of[4]
and from the results ofChapter
II of[14]
it follows that for every a
E A
there is a fullembedding
ofGrac
into its fullsubcategory
formedby
connectedsymmetric graphs
such that(4.5.1)
thehomomorphism Oa: (X, R) --+ Oa (Z) belongs
toSymGraphs
for any(X, R),
(4.5.2)
there is nohomomorphism Oa(X, R)
--+R)
for distinct a, a’ E A.Since
Grac
is analg-universal category,
for every group G there exists agraph (X, R)
withEnd(X,R)=
G. But thenEnd Oa(X, R)=
G as welland,
since every 9 E EndOa (X, R)
isinvertible,
the monoid of allstrong endomorphisms
ofOa(X, R)
is
isomorphic
to the group G. Therefore(4.5.3)
for any a EA,
every group isisomorphic
to the monoid of allstrong
endo-morphisms
of someOa(X, R).
4.6. The
category Metro
of all metric spaces and all their open continuous maps isa
subcategory of Top2,o.
Since metric spaces areregular,
the contravariant functor T from 1.4 mapsMetro
onto a fullsubcategory
ofH Heyt. Accordingly,
thepositive,
constructive claim of the theorem below for
categories
other thanSymGraphs
willbe established
through
a construction ofappropriate
metric spaces.Theorem. Let C be any one of the
categories Top2,o , H Heyt, PSp,
orSyrrtGraphs,
and let S be a finite commutative monoid. Then S= End X for some
object
X E Cif and
only if,
for some 11 >0,
where
Go
is a group and eachCi°
its a groupaugmented by
zero.Proof.
Tocomplete
theproof
for the three’topological’ categories,
in view of The-orem
3.5,
we needonly represent
a group G and any zero extensionG9
of a groupGi by
a metric spacesatisfying
thehypothesis
of Lemma 4.4. Torepresent
agiven
group
G,
wesimply
use the metric spaceP(G)
EPi
of(4.1.3).
A proper extensionP(Gi)U{p}
of the spaceP (Gi)
EPl
from(4.1.3) by
an opensingleton {p} obviously represents G?
and satisfies thehypothesis
of Lemma 4.4.To
complete
theproof,
we need torepresent
the monoidGo
xGo
x ... xGo
in the
category SymGraphs .
But this is also easy.For j = 0,1,
..., n, we select(Xj , Rj)
EGrac
so that thestrong endomorphisms
ofOj (Xj, Rj)
form a monoidisomorphic
toGj,
see(4.5.3),
and then we form adisjoint
unionThen X
belongs
toSytnGraphs and,
since allgraphs Oj(...)
areconnected,
from(4.5.2)
it follows that everystrong endomorphism g of X
preservesO0(X0, Ro)
andalso every
Oi (Xi, Ri)
U(Oi (Z)
with i =1,
... , n. ThereforeFurthermore,
anyendomorphism g
either preservesOi(Xi, Ri)
or else maps thisgraph
toOi (Z).
From(4.5.1)
it now follows that End(Oi(Xi,Ri)UOi=(Z))= G9
forall i =
1, ... ,
n. Therefore End X =,S,
as claimed. 04.7.
By
Theorem4.6, any join
reduct(2ri, U)
of a finite Booleanalgebra
isisomorphic
to
Dp(P)
for some metric space P. This result can be extended to the infinite case.Theorem. For any set
C,
there exists a metric space P such thatDp(P)
is isomor-phic
to(2C, U).
Proof.
Since thecategory
of metric spaces is almostuniversal,
seeChapter
VI of[14],
there exists a colelction{Pc
c EC}
of metric connected spaces such that anon-constant continuous
f : Pc
--->PC’
existsonly
when c =c’,
and then it is theidentity mapping
ofPc.
For thedisjoint
unionwith the union
topology
we thenobviously
haveDp(P) = (2c, U).
0Remark. From 4.5 it follows that a similar claim holds true for the Hausdorff
category SymGraphs
ofsymmetric graphs
and theirstrong homomorphisms.
4.8. Infinite commutative monoid with no nont,rivial invertible elements need not contain
idempotents,
and this is also true forendomorphism
monoids in Hausdorffcategories.
Theorem. Let N denote the additive monoids of all natural numbers.
Then,
for anyn =
1, 2, ... , w,
there is a metric space P withDp(P)=
Nn.Proof.
ForH’
EH1
from4.1,
denote H =H1 B (a§)
and setwhere the
neighbourhoods
of any(z, k)
withx =1= al
are all setscontaining
the setU x
{k}
for someneighbourhood
U of x inH,
while theneighbourhoods
of(al, k)
are all sets
containing
the set(U
x{k})
U((VB {a01})
x{k
+1})
in which U is aneighbourhood of a11
in 11 and V is aneighbourhood of a’ 0
inH1.
In otherwords,
P is obtained from
by
means ofidentifying
each(a’, k)
with(ao, k
+1).
An open map
f :
P --+ P is notconstant,
andhence, by (4.1.1),
it sends eachH x
{j} identically
onto some H x{k},
and it, is not difficult to seethat,
infact,
there is some n > 0 such that
f (x, j)= (x, j
+n)
forall j >
0. Since any such mapf
is open, this proves thatHigher
powers of N can berepresented
because Lemma 4.4applies,
see(4.1.1).
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Academia, Prague, 1975, pp. 511-515.APPLIED MATHEMATICS MFF KU
MALOSTRANSK9 NAM. 25 118 00 PRAHA 1 CZECH REPUBLIC
E-mail address: pultr@kam.Yus.ntff.curu.cz
DEPARTMENT OF MATHEMATIC;S UNIVERSITY OF MANITOBA WINNIPEG, MANITOBA CANADA R3T 2N2
E-mail address: sichler*cc.tinianitoba.ca