R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
M AURO C OSTANTINI
On the lattice automorphisms of certain simple algebraic groups
Rendiconti del Seminario Matematico della Università di Padova, tome 90 (1993), p. 141-157
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of Certain Simple Algebraic Groups.
MAURO
COSTANTINI (*)
Introduction-notation.
Given a group
G,
the set2(G)
of allsubgroups
of Gpartially
orderedby
inclusion is well known to be acomplete algebraic
lattice. Aprojec- tivity
of a group G onto a group G is any latticeisomorphism
form2(G)
onto
JE(G),
and anautoprojectivity
of G is anyprojectivity
of G onto it-self. We shall denote
by
Aut2(G)
the group of allautoprojectivities
ofG. Two
groups G,
G will be calledprojective
if there exists aprojectivi-
ty
of G onto G. _Let
G,
G be groups, and let « be anisomorphism
of G onto G. We candefine in a natural way the
projectivity
« * of G onto Ggiven by
=every X ; G. « * is called the
projectivity
inducedby
the isomor-phism
«. If G =G,
then we have ahomomorphism
*: Aut G -~ Aut2( G) given by
a H «* for every a in Aut G.An
interesting problem
is to know in which cases aprojectivity
of Gonto a group G is induced
by
anisomorphism.
In thiscontext,
a group G is said to bestrongly
lattice determined if everyprojectivity
of G on-to a group G is induced
by
anisomorphism.
It is clear that G isstrongly
lattice determined if and
only
if thefollowing
two conditions aresatisfied:
G
projective
to Gimplies
Gisomorphic
toG,
the
homomorphism
issurjective.
In literature several classes of groups whose members are
strongly
lattice determined are known
([10], [11], [12], [15], [16], [17], [24], [25]).
From the classification of the finite
simple
groups, one can see that if G is a finite non abeliansimple
group, and G isprojective
toG,
then Gis
isomorphic
to G.Therefore,
in order to prove that a finitesimple
(*) Indirizzo del’A.:
Dipartimento
di Matematica, Via Belzoni 7, Padova(Italy).
group is
strongly
latticedetermined,
it isenough
to show that the ho-momorphism
* issurjective.
The groups studied
by
Metelli([11], [12])
are aspecial family
of fi-nite
simple
groups of Lietype,
and aconjecture
was made that for all finitesimple
groups of Lietype
thehomomorphism
* wassujective.
In1985 V61klein
proved
this for the groups oftype
where the characteristic p of the base field is
sufficintly large ([22]).
If G is a group in the list
( x )
over the finite fieldk,
then G arises asthe
subgroup generated by
theunipotent
elements of the group of k-ra- tionalpoints
of a certainadjoint simple algebraic
group G defined overk. A crucial fact in the
proof given
in[22]
is that the groups in the list( k )
arise fromsimple adjoint algebraic
groups G whoseWeyl
groups have non-trivial center. Indeed in the same paper V61kleinproved
that forthe groups
PSL3 (q)
andP,S U3 ( q 2 ),
whose absoluteWeyl
group is,S3 ,
the
homomorphism
* is not ingeneral surjective.
We showed in[7]
thatq = 17 is the least
prime-power
number such thatP,SL3 (q)
hasautopro- jectivities
not inducedby automorphism.
It is in this connection that in[8]
we considered the behaviour of the map * for asimple algebraic
Ggroup over the
algebraic
closure of a finite field.For convenience here we recall some facts there
proved.
Every autoprojectivity
o_f G isindex-preserving (a projectivity p
ofa group G onto a group G is said to be
index-preserving
ifgiven
H ~ K ~ G and
[K : H] = n,
we have It is well known([26]
Corollario3)
that to prove that r; isindex-preserving
it isenough
to prove that H ~ K ~
G, K cyclic
and[K: H]
= nimplies
=n) (Theorem 2.3).
If rp is an
autoprojectivity
ofG,
then theimage under ç
of a maximaltorus,
a maximalunipotent subgroup
and a Borelsubgroup
of G are re-spectively
a maximaltorus,
a maximalunipotent subgroup
and a Borelsubgroup
of G. Inparticular ç
induces anautomorphism
of thebuilding 4(G) canonically
associated to G(Proposition 2.5, 2.7,
Theorem2.8).
For every
autoprojectivity p
of G there exists aunique
automor-phism
of Ginducing
r; on4(G) (Corollary 4.6).
It then follows that the map * is
surjective
if andonly
if the group1-’(G)
of allautoprojectivities
of Gfixing
everyparabolic subgroup,
coin-cides with the
identity subgroup
ofAut2(G) (Corollary 4.9).
The main results o_f the
present
paper is thatif
G is asimple algebraic
group over with p odd and G notof type A2 ,
thenevery
autoprojectivity of
G is inducedby
aunique automorphism.
of
G(Theorem A, B, C).
We also provethat,
in theadjoint
case,G is
strongly
lattice determined(Theorem D).
We shall show in a
forthcoming
paper that the caseA2
is in fact anexceptional
one.For
algebraic
groups, we use the standard notation([5], [20]).
If G is a reductivealgebraic
group over analgebraically
closed fieldK,
andT is a maximal torus of
G,
for every root «: T ~7~ ~ Xa
is the root sub-group
corresponding
to «,and xa
is a fixedalgebraic isomorphism Xa: (K, +)2013>~. Also,
a v: K * ~ T is the corootcorresponding
to a.Let p
be anyprime.
We shallalways
denoteby
K thealgebraic
clo-sure of the field
IFp
with p elements. Unless otherwisespecified,
G al-ways denotes a
simple algebraic
group over K and p anelement
ofr(G).
1. The case rank G at least 3. ,
In this
paragraph
we shall shaw that1’(G) _ ~ 1 ~
when G has rank at least 3 and p is odd. We first prove someproperties
ofr(G)
which holdin
general.
PROPOSITION 1.1. ~p fixes every maximal torus and every maximal
unipotent subgroup
of G. If 0 is the set of roots relative to a maximaltorus,
then we haveX,,9,’ = Xa
and(ker
= ker « for every « in 0.PROOF. The first
part
is clear. So let now T be a maximal torus ofG,
and let 0 be the set of roots. For every « in 4l there exists a Borelsubgroup B
of Gcontaining
T such that « lies in the fundamental sys- tem II of 0 relative to the choice of B. Then we haveXa
=where P is the
parabolic subgroup (B,
is anyrepresentative
in.N( T)
of the fundamental reflection sf3and f3
isgiven by
the relation where wo is thelongest
element of theWeyl
groupX(T)IT ([5]
page59).
So weget X« _ (U
1BP’0)9
= U 1B pno =Xa .
We fi-nally
prove that(ker
= ker a. For every non-trivial u inXa,
we haveker a = T We fix a non-trivial element u in
Xa .
AsXj
= 9there exists a non-trivial u in
Xa
such that(ul’ = (u~.
If now s is in ker «and s is an element of T such then s lies as
(u, s)P
is
cyclic.
Hence s lies in T A = ker «. It follows that(ker «I’ =
= ker «..
For every « in
0,
we defineLav
to be thesubgroup
of T.Lav
is therefore a 1-dimensional subtorus of T.
PROPOSITION 1.2.
Lflv
=Lav
for every a be in ø.PROOF. We show that
Lav
= T A(Xa, X _«~.
Let na be any represen- tative of the reflection Wa of in(~,Z~)([5]
page19).
As
Lav
is a maximal torus of(Xa, X-a),
we have the Bruhatdecomposi-
tion
(Xa, X _«)
=LavXa naXa.
But fl T =0,
as B n=
0,
and so we have T A(Xa, X-,,,)
=Lav.
Henceso that
Lya =TçAXça, Xç-a> =
= Lav by
1.1.The crucial
point
in the case of groups of rank at least 3 is the follow-ing
fact about tori.PROPOSITION 1.3. Let T be a torus of dimension l. If 1 is at least
3,
then every
autoprojectivity
of T is inducedby
anautomorphism.
PROOF.
Let ~
be anautoprojectivity
of T.By
Theorem 2.3in [8],
~
fixes everyq-component Tq
of T. We haveTq
x ... xCq.
(l copies)
for everyprime
q ~ p. As 1 %3,
thereexists, by
a theoremby
Baer
([21]
Theorem 2 page35),
anautomorphism fq
ofTq inducing ~
on.C(Tq).
As T =(sum
over allprimes
q different fromp),
if we definef =
the obvious way, weget that f is
anautomorphism
of T in-ducing §..
If H is any group, an
automorphism
« of H is called a power auto-morphism if
for everysubgroup K
of H we have K« = K. Hence the group of powerautomorphisms
of H is the kernel of thehomomorphism
*: Aut H ~ Aut
2(H).
If H is aperiodic
group, then anautomorphism
ais a power
automorphism
if andonly
if for every x inH,
there exists ~nin Z such that
Let T be any maximal torus of G. If the rank of G is at least
3, then, by
1.1 and1.3,
there exists anautomorphism f
of Tinducing
q on2(T).
We shall show that
f
is in fact apower-automorphism
of T. We first state some facts which hold ingeneral
forsemisimple
groups. So as- sume G is asemisimple algebraic
group over analgebraically
closedfield and let T be a maximal torus of G. We denote
by
X the character group of T andby W
the set of roots relative to T. Let B be a Borel sub- group of Gcontaining
T and let II= ~ « 1, ... a L }
be the fundamental sys- tem of W relative to the choice of B. For every closedsubgroup S
of Twe
put S1={xE X[ x( s )
= 1 Vs ES},
and for everysubgroup
A of X weput
A 1= t
E = 1 da EA } . A 1
is a closedsubgroup
of T. We areinterested in the
family
ofsubgroups {S1|S
is a subtorus ofT }
of X.Let us denote
by a
the set of allsubgroups
A of X such thatX/A
is tor-sion
free,
andby S
the set of all subtori of T. We have thefollowing
result:
PROPOSITION 1.4. The map
given by
for every A in a, is abijection
of aonto 3,
its inversebeing
themap s H
for every S in S.Also we have dim A’ = rank
(X/A)
for every A in a.PROOF. This follows from the fact that for every torus S we have dim s = rank Hom
(,S, K " ),
and from the fact that adiagonalizable
group S is a torus if and
only
in Hom(S, K " )
is a free abelian group([19] Proposition 2.5.8).
We now consider the cocharacter group Y of T. If we denote
by 0’
the set of
coroots,
then...oc~}
is fundamentalsystem
of 0’.Let
(x 1, ... , X 1), (Y 1, ... ,
be Z-bases resp. of X and of Y. LetTi
bethe
subgroup
E = 1 forevery j # z},
andLi
be thesubgroup
of T . Then both
Ti
andLi
are 1-dimensional subtori of T. For every i =1, ... , Z,
we consider thealgebraic homomorphisms
LEMMA 1.5. Let
(xl, ... , Xl)’ (Y1, ... , Yl) be
dual Z-bases resp. of X andY,
in the usualduality
X x Y - Z.Then,
for every i =1, ... , l,
wehave
Ti
=Li , and ~i , ~i
are one the inverse of the other(in particular they
arealgebraic isomorphisms).
PROOF. This is obvious.
PROPOSITION 1.6. Let
( x 1, ... , x L ), ( Y 1, ... , Y l )
be Z-bases resp. of X and of Y. Then we have thefollowing decompositions
of T asalgebra-
ic group:
PROOF. It is clear
TL~
=T1
x ... xTl ,
so that T =T1
xx ... x
T,
asthey
both have dimension l. Thisdecomposition
is ofalge-
braic groups
by
1.5. From this it also follows that T =L1
x ... xL, by cosidering
the dual basis of( y 1, ... , y L)
and 1.5.Going
back to the case when G is asimple algebraic
group overK,
we consider
separately
groups of differentisogeny types.
We startwith G of
adjoint type,
Z-basis of X.Let I be the
set {1,
... ,l}.
For every J cI,
we denoteby Aj
the sub-group of X. Hence is a subtorus of T of dimension
For every i in I we
put
= 1dj E I, j ~
Let~
be the restriction toT rxi
of thealgebraic homomorphism
a i : T -~By 1.5 ~i
is analgebraic isomorphism
fromTrxi
onto K" . We shall denoteby v
i the inverseof ~i .
For every
i, j
in I such that « lies in0,
we defineTij
== (
AkEl
k=i,j
Tij
is a 1-dimensional subtorus of Tby
1.4.PROPOSITION 1.7. ~p fixes all the subtori
Tij .
PROOF. It is
enough
to obverve that all these subtori are elements of the sublattice of2(T) spanned by
the set(ker « a
E4l),
and thenuse 1.1.
For every
i, j
in I such that xi + a j lies inø,
we introduce thealgebraic isomorphism given by
the map(a, b ) H v i ( a ) v j ( b -1 )
for every inPROPOSITION 1.8. Let D be the
diagonal
of K x x K " .Then,
forevery
i, j
in I such that a + a j lies inø,
we have =Tij .
PROOF. It is
enough
to show that DF?> £Tij ,
I as p ij isinjective,
Dand
Tij
are 1-dimensional connectedalgebraic
groups,and p ij
is analge-
braic map. So let a be an element of Let m be in
I,
Wehave = 1 as for every r # m.
Also we have
But,
forevery s in I and for every we have
_ ~s v s ( a )
= a.Hence =
1,
and(a,
lies inTij .
mLEMMA 1.9. Let F be an
automorphism
of K " x K x . Let D be thediagonal
of K " If F fixes thesubgroups
Kxx {1},{1}
and
D, then,
for every « inN,
there existsn in ~ 1, ... , ~ro " - 1 ~
suchthat
SF
= s n for every s in xJF;a.
PROOF. Let « be in N. Let k be an element of 7~ such that
(k) =
= There exist a
unique
ni and aunique ~2i~{l~...~"l}
such that( k, 1 )F = ( 1~ nl , 1 )
and( 1, I~ )F = ( 1, k’~ ).
As F fixed alsoD,
weget
n1 = n2 . Call this common value n. Now let s be in
F n
xJF;a.
Thereexist
r, t
in Z such that Hence and we aredone.
We now fix a maximal torus T of G.
PROPOSITION 1.10. Let G be
adjoint
of rank at least 3. Then anyautomorphism
of Tinducting ?
on is apower-automorphism.
PROOF.
Let f be
anautomorphism
of Tinducing p
on2(T).
Let t bein T .
By
1.6 for every i in I there exists aunique ti
inT"
such that t ==
t1 ... tl.
Let us denoteby ki
theelement ~i (ti)
ofK ~,
and letlFpa
be thesubfield of K
generated by k1, ... , kl .
Let also k be agenerator
ofBy
1.7 there exists aunique ni
such such thatv i ( k )f =
for every i in I. Let nowi, j
be such that a + a~ lies in 0. If we denoteby Fij
theautomorphism where fij
is
automorphism
ofT"i
xT,,,.
inducedby f,
we have(K "
=K" x
{1}.({1}
xK"and DFij
=D, by 1.7, 1.8. By
1.9there exists n in N such that
(a,
=(a, b )n
for every a, b in Hence wehave ni
= nj forevery i, j
in I such that a + xj lies in 0. As theDynkin diagram
of G isconnected,
we concludethat ni
= nj forevery i, j
in I. Call this common value m, so that we have - v forevery i
in I. From t = vi (ki ) ... v
it then followsthat tf
=- t m . Therefore
f
is apower-automorphism
of T.We now consider the case when G is
simply-connected.
ThenZ-basis of Y. For
every i
inI,
we denoteby Ci
thealge-
braic
isomorphism given by
=af(k)
forevery k
inAlso,
for everyi, j
in I such that a + «~ lies in0,
we define thealgebra-
ic
isomorphism
K" xby (a, b) H ~i (a) ~~ (b)
forevery a, b in K x . From the fact that « + 0~ lies in 4l it follows that
0~
++
«J
lies so that + 1X1) is also well defined. But then + 1X1) coin- cides with DfJ-ij where D be thediagonal
of K x x K ".PROPOSITION 1.11. Let G be
simply-connected
of rank at least 3.Then any
automorphism
of Tinducing
p on is apower-automor- phism.
PROOF. The
proof
is similar to theproof
of 1.10. Theonly
differ-ence is that
here,
for everyi, j
in I such that a i + lies in0,
we consid-er the
automorphism V2~
of 7~ x 7~given (where fij
isthe
automorphism
of xL"~
inducedby f ). By
1.2 we haveLtf
=Llfv
x x~1~,(~1~
x= ( l )
x K " andD Vij
= D. Then we canproceed
as in theproof
of 1.10.
We shall
finally
deal with the case left out so far. So let G be neitheradjoint
norsimply-connected.
Such a group is therefore forced to have rank at least3,
and to be oftype A,
orDi .
Inparticular,
theDynkin
dia-gram of G has
only single
bonds. For everysubgroup
A of Y we denoteby A the subtorus y(Kx)|yEA> of T. We have A = a1(Kx)...ar(Kx) whenever {a1, al
is a set ofgenerators
of A.LEMMA 1.12. Let A be a
subgroup
of Y of rank r. Then the dimen- sionof A ’
is r. Inparticular
we havePROOF. There exists a Z-basis
( Y 1, ... , y l)
of Y andpositive
inte-gers ni , ... , nr, such that
9 ... 9 nr -(r)
is a Z-basis of A. Then wehave ...
by 1.6,
and ... xx Y r
(K " )
as K x is divisible. Hence the dimensionof A ~
is r. Inparticular
we have
The
decomposition r==x~(~)...~CK~)
is ingeneral
not a directdecomposition
ofT,
as one can see for instance when G hastype Al . (It
is
enough
to take anon-adjoint, non-simply-connected algebraic
group oftype A3 and p odd).
In thefollowing
we shall use the same notationwe
previously
introduced. For every « in 0 we consider the 1-dimen- sional subtorusL«v
ofT,
and for every i inI,
thesurjective algebraic homomorphism ~i :
K " -~LrJ-f.
In thesimply-connected
case we alsohad the
isomorphism
x K x x for everyi, j
in I suchthat « + «~ lies in 0. In our case we do not know a
priori if
theproduct Lai
is direct and if’i
isbijective. Anyway
we can still definekx
x K"Lz,, by (a, b)
~’j(b)
for every a, b inKX,
sothat is a
surjective algebraic homomorphism.
We show that in fact the map gj isinjective (hence,
inparticular,
is a directproduct and ~i
isinjective).
~ J
PROPOSITION 1.13. Let
i, j
be elements of I such that « + «~ lies in 0. Then themap laij
is abijective algebraic homomorphisms
isinjec-
tive for every i in I.
PROOF. We
already
know that is asurjective algebraic
homo-morphism.
We prove that it isinjective.
Let(a~ b)
be in ker Hence= 1. From the fact that the rank of G is at least
3,
and that theDynkin diagram
of G hasonly single bonds,
there exists k inI,
i, j,
such that we have one of thefollowing subgraphs.
Without loss of
generality,
we may suppose we are in the first situ- ation. Therefore we_ -1, ~ a k ,
= 0and (ai, oe~) = -1.
We have 1 = = =
a ~ ~,
so that a =1,
and conse-quently a~ ( b ) = 1.
But then we have1 = a i ( 1 ) _ « i (a~ ( b )) = b -1,
which
gives
b = 1. Hence isinjective.
Now let i be in I. As theDynkin diagram
of G isconnected,
thereexists j
in I such that « lies in 0. But then weproved
that the map isinjective,
andso ~i
must be
injective. 0
PROPOSITION 1.14. Let G be neither
adjoint
norsimply-connected.
Then any
automorphism
of Tinducing p
on2(T)
is apower-automor- phism.
PROOF.
Let f be
anautomorphism
of Tinducirlg p
on2(T).
Let t bein T.
By 1.12,
for every i in I there exists anelement ti
inL,,v
such thatt =
t1...tl. By 1.13,
thehomomorphism ~i
isinjective,
and so, for every i inI,
there exists aunique ki
in K x suchthat ~i (k2)
=ti .
From the fact that for everyi, j
in I such that « + lies in0,
is abij ective,
we cannow use the same
procedure
we used in thesimply-connected
case tofind m in Z such that
tf =
Thereforef
is apower-automorphism
of T.
COROLLARY 1.15. Let G be of rank at least 3. Then we have
(sl’ = - (s~
for everysemisimple
element s of G.PROOF. Let s be a
semisimple
element of G. There exists a maxi- mal torus T of G such that s lies in T.By 1.10,
1.11 and1.14,
there exists apower-automorphism f
of Tinducing (p
on2(T).
Hence we have(s)9 = ~s~ _ (s),
and we are done. 0We are now interested in the behaviour of
subgroups generated by
a
unipotent
element under the action of1’(G).
We shall make use of the classification ofunipotent
classes of G. We prove the next lemma for groups over anyalgebraically
closed field.LEMMA 1.16. Let G be a
simple algebraic
group over analge- braically
closed field. Then everyunipotent
element u of G isconjugate
to its inverse.
PROOF. We
give
aproof
from the classification ofunipotent conju-
gacy classes if the characteristic of the field is 0 or a
good prime.
Let ube a
unipotent
element of G. From the Bala-Cartertheorem([3], [4])
and the results of
Pommerening ([13], [14]) (we
recall that the classifi- cation ofunipotent
classes isindependent
of theisogeny
class ofG),
there exists a Levi
subgroup
L of G and aparabolic subgroup
P of thederived
subgroup
L’of L,
such that u lies in theunique conjugacy
classC of L’ such
that C n Ru (P)
is open and dense inRu (P) ([5]
Note onpage
132).
In thefollowing
we shall denoteby
U’theunipotent
radicalRu (P)
of P. We consider the map ê: L’ - L’given
for everyx in L’. This map is an
automorphism
of affine varieties. Let... ,
Ckl
be the(finite)
set ofunipotent conjugacy
classes of L’.Then -
permutes
this set. cn U isopen and dense in U,
and so(C n
be open and dense in
U,
as e is ahomeomorphism of topolog-
ical spaces, and
U -1 = U.
Buthence we must have
G-1
=C, by uniqueness.
Thereforeu -1
lies in C.In
particular u and u -1
areconjugate
in G. If p is a badprime
the clas-sification of
unipotent conjugacy
classes may be different. However J.N.
Spaltenstein suggested
thefollowing argument. u -1
iscertainly
co-jugate
to u if theconjugacy
class C of u contains a dense open subset of U A’U for some w in theWeyl
group, where U is a maximalunipotent subgroup
of G. It is known from the classification ofunipotent
classesthat this
actually
covers all cases. Hence u isalways conjugate
tou -1.
REMARK. From the structure of reductive groups, it follows that 1.16 holds also when G is reductive.
From the
previous
result weget.
PROPOSITION 1.17. Let u be a
unipotent
element of G.If ~
is an au-toprojectivity
of Gfixing
everycyclic subgroup
of G of order a power of2,
then we have~u~~ _ (u).
PROOF. If the characteristic of the field is
2,
then there isnothing
to prove. So assume p # 2.
By 1.16,
there exists an element h of G such thatu -1.
Let 2a m be the order ofh,
with 2 x m. If wetake g
==
h m,
we havegug -1 = u -1,
and the orderof g
is 2’. We have(gU)2
=g 2
so that gu has order a power of 2 as well. Hence
(g, (g, gul’ =
=
(g, gu) = (g, u).
But then we must have~u~~ _ (u)
as(u)
is theunique p-Sylow subgroup
of the group~g, u ~, and ~
isindex-preserv- mg.
We are now able to prove the announced.
_THEOREM A. Let G be a
simple algebraic
group over the field K = If the rank of G is at least3,
and p isodd,
then everyautoprojectiv- ity
of G is inducedby
aunique automorphism
of G.PROOF. We have to show that
r(G)
coincides with theidentity subgroup
ofAut2(G).
It isenough
to show that(sl’ = (s)
and~u~~ _
=
(u)
for every 9 inr(G),
everysemisimple
element s of G andevery
unipotent
element u of G. But this follows from 1.15 and1.17,
as every element of order a power of 2 in our case is semisim-ple.
In the next
paragraph
we shall deal with the case when the rank of G is less than 3.2. The case rank G less than 3
(A2 excluded).
In the
previous paragraph
weproved
that forsimple algebraic
groups of rank at least
3,
in oddcharacteristic,
everyautoprojectivity
is induced
by
anautomorphism.
We made a crucial use of thehypothe-
sis on the rank to use a theorem
by
Baer. Here we consider groups of rank 1 or 2. In this case the above mentioned theoremby
Baer drasti-cally
fails. Nevertheless we are able to prove the result weproved
forrank G ~
3,
for groups of rank 1 and2,
if we exclude the case when G hastype A2.
OBSERVATION. Our aim is to
study
the group Aut~(G)~
Butclearly
our aim will be achieved if we determine the group Aut where G is any abstract group
isomorphic
to ourgiven algebraic
group G. If G is anysimple algebraic
group, there exists anisogeny
x: G ~Gad ,
whereG~
is theadjoint simple algebraic
group of the sametype
of G. We haveker 7t’ =
Z(G),
and soGIZ(G)
isisomorphic
toGad
as an abstract group.We introduce the abstract groups
PSL2 (K)
=SL2 (K)IZ(SL2 (K))
andPSp4(K)
=SP4 (K)/Z(SP4 (K)).
We havePGL 2 (K) = (A1)ad PSL2 (K)
and
(B2)~ =
We shall first
study
the group Aut2(PSL2(K)).
We recall the fol-lowing
resultby
C.Metelli ([11]).
Let qwhere p
is aprime and f is
any natural number. If q is at least
4,
for everyprojectivity 7
of thesimple
groupPSL2 ( q )
onto a groupH,
there exists aunique
isomor-phism
a :P,SL2 ( q ) -~ H inducing
7.We can now prove.
THEOREM 2.1. Let T be a
projectivity
ofPSL2 (K)
onto a groupH,
where K = Then there exists a
unique isomorphism
ofPSL2 (K)
on-to H
inducing
7.PROOF. Let us denote
by
Z the centre of,SL2 (K).
For every n inN,
we denote
by Gn
thesubgroup
ofPSL2 (K),
and we considerthe restrictions induced
by
T.By
Metelli’sresult,
forevery n =
2, 3, ...,
there exists aunique isomorphism
an : in-By
theuniqueness
of we have = 1 for every g inGn
andevery n ;
2. This enables us to define the map «:P,SL2 (K)
- Hby g"
=for g
inPSL2 (K),
where n is such that g lies inGn .
a is anisomorphism,
and it is clear that « induces 2.Uniqueness
of « followsfrom the fact that the group of
power-automorphisms
of aperfect
group is theidentify
group([6] 2.2.2.).
In
particular if
G isadjoint
of rank1,
everyautoprojectivity
of G isinduced
by
aunique automorphism
of G. We shall now consider the otherpossibility
for groups of rank1,
i.e. the case when G =SL2 (K).
We prove a lemma which we shall use also when G has
type B2.
LEMMA 2.2. Let G be one of the groups
SL2 (K), SP4 (K). Suppose
is an
autoprojectivity
of Gfixing
everysubgroup
of Gcontaining
thecentre of G.
Then ~
is theidentity.
PROOF. Let us denote
by
Z the centre of G. If the characteristic p of K is2,
we have Z and there isnothing
to prove. So let p # 2.Then Z is
cyclic
of order 2. Let x be an element of G of orderr",
where r is aprime,
and « a 1. If r isodd,
then(x~
is theunique r-Sylow
sub-group of
(x, Z).
Hence we have(x~~ _ (x)
as(x, Z~~ _ (x, Z), and
isindex-preserving.
Now let r = 2. We have two cases. If x > ~Z,
then we have
~x)~ _ ~x) by hypothesis (this
isalways
the case if G ==
,SL2 (K)).
Otherwise let T be a maximal torus of Gcontaining
x. As T isa divisible group, there exists y in T such that
y2
= x. We have(y, Z) =
=
(y)
xZ and Frat ((y, Z)) = ~y2~ _ (x).
Hence~x~~ _ (x),
as the Frattinisubgroup
isclearly
an invariant underprojectivities.
We can now prove.
PROPOSITION 2.3.
Let ç
be anautoprojectivity
of,SL2 (K).
Thenthere exists a
unique automorphism
of,SL2 (K) inducing
rp.PROOF. Let us denote
by
Z the centre ofSL2 (K). If p
is2,
we haveZ
= ~ 1 ~,
and so the result follows from 2.1. So let us assume p # 2.By Corollary
2.10 in[8],
we have Z9= Z,
and so we can define theautopro- jectivity 15
ofPSL2 (K) by
= XP/Z,
for everysubgroup
X ofSL2 (K) containing
Z.By 2.1,
there exists anautomorphism a
ofPSL2 (K) inducing 15. Also,
from the structure of the group AutPSL2 (K) ([9]),
there exists anautomorphism
« ofSL2 (K) inducing
a on
PSL2 (K).
We therefore have xq; = X" for everysubgroup X
of,SL2 (K) containing
Z.By 2.2,
weget
p = «*.Uniqueness
followsagain
from the fact that
SL2 (K)
is aperfect group.
We summarize the
previous
results inTHEOREM B. Let G be a
simple algebraic
group of rank 1 over K.Then every
autoprojectivity
of G inducedby
aunique automorphism
of G.
(This gives
an alternativeproof
ofCorollary
4.6in [8]
for groups of rank1).
We now consider the case when G has rank 2. We deal
only
withgroups of
type B2
orG2.
Using
anargument
similar to the one usedby
V61kleinin [22]
forthe
corresponding
finitesimple Chevalley
groups(here
theproof
iseven easier as in our case every
unipotent
element isconjugate
to itsinverse)
it ispossible
to prove thefollowing
theorem:THEOREM 2.4. Let G be an
adjoint simple algebraic
group oftype B2
orG2
over the field K of odd characheristic. Then everyautoprojec- tivity
of G is inducedby
aunique automorphism
of G.The crucial
point
in theproof
is that if the centre of theWeyl
group of anadjoint simple algebraic
group G is non- trivial(as
in the caseB2
or
G2), then,
for every maximal torus T ofG,
there exists an involutiona of G such that sc =
s -1
for every s in T. Then one first proves thatif ?
lies
r(G), p
fixes everysubgroup
of order 2 of Gusing
thedecomposi-
tion T =
Tal
xTa2
we introduced in § 1. From theprevious
observation it follows that p fixes everysubgroup
of Ggenerated by
asemisimple element,
andfinally
cp fixes also everysubgroup generated by
aunipo-
tent element
by
1.17.Let us now consider the
simply-connected
case. As thesimply-con-
nected
simple algebraic
group oftype G2 ,
is alsoadjoint,
weonly
haveto deal with the
simply-connected
group oftype B2 ,
i.e. with the sym-pletic
groupPROPOSITION 2.5. Let G be the group
Sp4 (K)
over the field K of odd characteristic. Then everyautoprojectivity
of G is inducedby
aunique automorphism
of G.PROOF.
Let (p
be inF(G).
We consider theisogeny
~: G ~Goo.
7r in-duces an abstract
isomorphism IA
betweenG/Z(G)
andGoo,
and abijec-
tion between the set of
parabolic subgroups
of G and the set ofparabol-
ic
subgroups
ofGoo. Let -
be theautoprojectivity
ofG/Z(G)
inducedby
9. We denote
by y
theprojectivity
ofG/Z(G)
ontoGoo
inducedby 03BC,
andwe
put ~ = y -1 cpy.
From the fact that cp lies in1’(G),
it followsthat ~
liesin But then we must
have ~
=1, by 2.4,
and so we are left withp
= 1. Hence we have Xrp = X for everysubgroup X
of Gcontaining Z(G),
and so ç =1, by
2.2.We summarize the
previous
results inTHEOREM C. Let G be of
type B2
orG2
over the field K of odd char-acteristic. Then every
autoprojectivity
of G is inducedby
aunique
au-tomorphism
of G.3. Final remarks.
The methods used so far cannot be carried over to the case
A2 .
Weshall show in a
forthcoming
paper that in factA2 represents
an excep- tional case among thesimple algebraic
groups G overF p ,
from the sub- group latticepoint
of view.We underline that we dit not consider the case
when p
=2,
with theexception
of groups of rank 1. Thedifficulty
arises from the classifica- tion ofunipotent conjugacy
classes in characteristic2,
which isusually
more
complicated
than in the case of odd characteristic. We have some results also in this direction. Forinstance,
it ispossible
to extend theresults obtained
by
V61klein([23])
for the groups(where
Dis any central
subgroup
of to the groups Inpartic- ular, if
G is oftype A,,
then everyautoprojectivity
of G is inducedby
anautomorphism
if 1 is not 2. Ingeneral,
if G is anysimple algebraic
groupover
F2, and ç
lies1,(G), then, using
the classification of involutions([1], [2]),
it ispossible
to provethat ç
fixes all thesubgroups
of order 2of G.
Hence,
from the results weproved if
G is not oftype A2 ,
it followsthat r:p, in this case, fixes every
subgroup generated by simisimple
ele-ments of G.
Finally
I would like to mention theproblem
whether theprojective image
of asimple algebraic
group G over isisomorphic (as
an ab-stract
group)
to G. We prove that this is true if G is ofadjoint type.
LEMMA 3.1 Let G be a finite
simple Chavelley
group overF~ (q
apower of a
prime
p with q >3)
and suppose T is anautoprojectivity
of Gfixing
everyp-Sylow subgroup
of G. Then for every root a and every k inF ,
i T fixes thesubgroup (xrx (k)~
of G.PROOF. Let a be root of G. We observe that r fixes every