WITH THE DZIOK-SRIVASTAVA OPERATOR
GEORGIA IRINA OROS, GHEORGHE OROS, IN HWA KIM and NAK EUN CHO
The purpose of the present paper is to investigate differential subordination pro- perties associated with the Dziok-Srivastava operator. Moreover, we determine dominants and best dominants of differential subordinations presented here.
AMS 2000 Subject Classification: 30C45, 30A10, 30C80.
Key words: univalent function, analytic function, differential subordination, Dziok-Srivastava operator.
1. INTRODUCTION AND PRELIMINARIES
Let H(U) denote the space of holomorphic functions in the open unit disk U ={z∈C: |z|<1} and let
An={f ∈ H(U), f(z) =z+an+1zn+1+. . .} with A1 =A. Also, for a positive integer nand a∈C, let
H[a, n] ={f ∈ H(U), f(z) =a+anzn+an+1zn+1+. . .} and
S ={f ∈A; f is univalent in U}.
Iff andgare analytic functions inU, then we say thatf is subordinate tog, writtenf ≺gorf(z)≺g(z), if there is a functionwanalytic inU, with w(0) = 0 and|w(z)|<1, and such thatf(z) =g[w(z)]. Ifgis univalent, then f ≺g if and only if f(0) =g(0) andf(U)⊂g(U).
The method of differential subordinations (also known as the admissible functions method) was introduced by Mocanu and Miller [2], [3] and deve- loped in [5].
Let Ω and ∆ be any sets in C and let p be an analytic function in the unit disk with p(0) = aand let ψ(r, s, t;z) : C3 ×U → C. The heart of this theory deals with generalizations of the implication
(i){ψ(p(z), zp0(z), z2p00(z);z)|z∈U} ⊂Ω implies p(U)⊂∆.
MATH. REPORTS13(63),1 (2011), 57–64
If ∆ is a simply connected domain containing the point a and ∆ 6= C, then there is a conformal mapping q ofU onto ∆ such that q(0) =a. In this case (i) can be rewritten as
(ii){ψ(p(z), zp0(z), z2p00(z);z)|z∈U} ⊂Ω implies p(z)≺q(z).
If Ω is also a simply connected domain and Ω6=C, then there is a confor- mal mapping h of U onto Ω such thath(0) =ψ(a,0,0; 0). If in addition, the functionψ(p(z), zp0(z), z2p00(z);z) is analytic inU, then (i) can be rewritten as
(iii) ψ(p(z), zp0(z), z2p00(z);z)≺h(z) impliesp(z)≺q(z).
Definition 1 [5, p. 16]. Letψ:C3×U →Cand leth be univalent in U. If pis analytic inU and satisfies the (second-order) differential subordination (iv) ψ(p(z), zp0(z), z2p00(z);z) ≺ h(z), then p is called a solution of the differential subordination. The univalent function q is called a dominant, if p ≺ q for all p satisfying (iv). A dominant qe that satisfies qe ≺ q for all dominants q of (iv) is said to be the best dominant of (iv). (Note that the best dominant is unique up to a rotation of U.)
Definition 2 [5, Definition 2.2b, p. 21]. We denote by Qthe set of func- tions f that are analytic and injective onU \E(f), where
E(f) = n
ζ ∈∂U; lim
z→ζf(z) =∞o and are such that f0(ζ)6= 0 for ζ∈∂U\E(f).
The subclass ofQ for which f(0) =ais denoted byQ(a).
Definition3 ([3], [4], [5, Definition 2.3a, p. 27]). Let Ω be a set inC,q∈Q and n be a positive integer. The class of admissible functions Ψn[Ω, q], consists of those functions ψ : C2 ×U → C that satisfy the admissibility condition
(A)ψ(r, s;z)6∈Ω
whenever r=q(ζ), s=mζq0(ζ),z ∈U, ζ ∈∂U\E(q) and m ≥n. We write Ψ1[Ω, q] as Ψ[Ω, q].
In the special case when Ω is a simply connected domain, Ω6=C, and h is a conformal mapping ofU onto Ω, we denote this class by Ψn[h, q].
The function q(z) = 1+z1−z satisfies q(U) = ∆ = {w ∈ C : Rew > 0}, q(0) = 1, E(q) ={1} and q ∈Q. We set Ψn[Ω,1] = Ψn[Ω, q]. In the special case when Ω = ∆, we denote the class by Ψn{1} and admissibility condition (A) becomes
(A0)ψ(ρi, σ;z)6∈Ω,
when σ ≤ −n2(1 +ρ2),ρ, σ ∈R,n≥1 andz∈U.
The Dziok-Srivastava operator was defined in [1] by (1) Hml (α1, α2, . . . , αl;β1, β2, . . . , βm)f(z) =
=z+
∞
X
n=2
(α1)n−1(α2)n−1. . .(αl)n−1
(β1)n−1(β2)n−1. . .(βm)n−1(n−1)!anzn,
αi ∈C, i= 1,2, . . . , l, βj ∈C\{0,−1,−2, . . .}, j = 1,2, . . . , m), f ∈A, where (ν)n is the Pochhammer symbol defined (in terms of the Gamma func- tion) by
(ν)n:= Γ(ν+n) Γ(ν) =
1 ifn= 0 andν ∈C\{0},
ν(ν+ 1)· · ·(ν+n−1) ifn∈Nand ν ∈C. For simplicity, we write
(2) Hml [α1]f(z) =Hml (α1, α2, . . . , αl;β1, β2, . . . , βm)f(z).
We note from (1) that we have
(3) α1Hml [α1+ 1]f(z) =z{Hml [α1]f(z)}0+ (α1−1)Hml [α1]f(z).
In order to prove the new results we shall use the following lemmas:
Lemma A [5, Lemma 2.2.d, p. 24]. Let q ∈ Q with q(0) = a, and let p(z) = a+anzn+. . . be analytic in U with p(z) 6≡ a and n ≥1. If p is not subordinate to q, then there exist points z0 =r0eiθ0 ∈U and ζ0 ∈∂U\E(q), and m≥n≥1 for which p(Ur0)⊂q(U), such that
(i) p(z0) =q(ζ0);
(ii)z0p0(z0) =mζ0q0(ζ0).
Remark1. Let Ω be a set inCandψ(p(z), zp0(z);z)∈Ω forz∈U, where ψ(p(z), zp0(z);z) may not be analytic inU.
In this paper, we obtain the first order differential subordination impli- cations associated with the Dziok-Srivastava operator defined by (1) applying the concept of admissible functions introduced by Miller and Mocanu [5]. We also provide an useful example as a special case of our results.
2. MAIN RESULTS
Theorem 1. Let ψ∈Ψ{1}, α1 >0. If f ∈A satisfies (4)
ψ
Hml [α1]f(z)
z ,Hml [α1+ 1]f(z) z ;z∈U
⊂Ω ={w∈C: Rew >0}, then
Hml [α1]f(z)
z ≺q(z).
Proof. Let
(5) p(z) = Hml [α1]f(z)
z , z∈U.
From (5) we have
(6) Hml [α1]f(z) =zp(z),
and differentiating (6), we obtain
(7) {Hml [α1]f(z)}0=p(z) +zp0(z).
Using the property (3) of the Dziok-Srivastava operator, we have (8) Hml [α1+ 1]f(z) = z{Hml [α1]f(z)}0+ (α1−1)Hml [α1]f(z)
α1
. Using (7) in (8) we obtain
(9) Hml [α1+ 1]f(z)
z =p(z) + zp0(z) α1 . Then (4) becomes
(10)
ψ
Hml [α1]f(z)
z ,Hml [α1+ 1]f(z)
z ;z
=
=
ψ
p(z), p(z) +zp0(z) α1 ;z
⊂Ω ={w∈C; Rew >0}
which is equivalent to Reψ
p(z), p(z) +zp0(z) α1
;z
>0, z∈U.
Assume p ⊀ q. By Lemma A there exist points z0 = r0eiθ0 ∈ U and ζ0 ∈
∂U \E(q), andm≥n≥1 that satisfy
p(z0) =q(ζ0), z0p(z0) =mζ0q0(ζ0).
Using these conditions in Definition 3, we obtain ψ
p(z0), p(z0) + 1 α1
z0p0(z0);z0
=ψ
q(ζ0),mζ0q0(ζ0) α1
+q(ζ0);z0
6∈Ω.
Since this contradicts (10), we must have p≺q, i.e., Hml [α1]f(z)
z ≺q(z).
From the proof of Theorem 1, it is easy to see that Theorem 1 also holds if under condition (4), z ∈ U is replaced by a function w(z) which maps U into U and so we have the following corollary.
Corollary 1. Let ψ∈Ψ{1}, α1 >0. If f ∈A satisfies
ψ
Hml [α1]f(z)
z ,Hml [α1+ 1]f(z)
z ;w(z)
⊂Ω,
then
Hml [α1]f(z)
z ≺q(z), where w(z) is any function mappingU into U.
For the case when Ω =h(U), wherehis a conformal mapping ofU in Ω, Theorem 1 can be rephrased as the following equivalent theorem.
Theorem 2. Let ψ∈Ψ{1} withq(0) = 1. If Hml [αz1]f(z) ∈ H[1,1], ψ
Hml [α1]f(z)
z ,Hml [α1+ 1]f(z)
z ;z
is analytic in U, and
(11) ψ
Hml [α1]f(z)
z ,Hml [α1+ 1]f(z)
z ;z
≺h(z), then
Hml [α1]f(z)
z ≺q(z).
This result can be extended to those cases in which the behavior ofq on the boundary of U is unknown.
Theorem 3. Let h and q be univalent in U, with q(0) = 1 and set qρ(z) = q(ρz) and hρ(z) = h(ρz). Let ψ : C2 ×U → C satisfy one of the following conditions:
(j)ψ∈Ψ[h, qρ], for someρ∈(0,1),
(jj)there exists ρ0 ∈(0,1) such thatψ∈Ψ[hρ, qρ], for allρ∈(ρ0,1).
If Hml[αz1]f(z) ∈ H[1,1], ψ
Hml [α1]f(z)
z ,Hml [α1+ 1]f(z)
z ;z
is analytic in U, and ψ
Hml [α1]f(z)
z ,Hml [α1+ 1]f(z)
z ;z
≺h(z), then
Hml [α1]f(z)
z ≺q(z).
Proof. Case (j). By applying Theorem 1 we obtain p≺qρ. Since qρ≺q we have p(z)≺q(z), i.e.,
Hml [α1]f(z)
z ≺q(z).
Case (jj). If we let pρ(z) =p(ρz), then ψ
Hml [α1]f(z)
z ,Hml [α1+ 1]f(z)
z ;z
=ψ
pρ(z), pρ(z) + 1 α1
zp0ρ(z);ρz
=
=ψ
p(ρz), p(ρz) + 1 α1
zp0(ρz);ρz
∈hρ(U).
By using Corollary 1, with w(z) =ρz, we obtain pρ(z)≺qρ(z), forρ∈(ρ0,1).
By letting ρ→1 we obtain p(z)≺q(z), i.e., Hml [α1]f(z)
z ≺q(z).
The next theorem yields the best dominant of the differential subordina- tion (4).
Theorem 4. Let hbe univalent in U andψ:C2×U →C. Suppose that the differential equation
(12) ψ
q(z), q(z) + 1 α1
zq0(z);z
=h(z)
has a solutionq, withq(0) = 1, and one of the following conditions is satisfied:
(k) q∈Q andψ∈Ψ[h, q],
(kk) q is univalent in U and ψ∈Ψ[h, qρ], for some ρ∈(0,1), or
(kkk) q is univalent in U and there exists ρ0 ∈ (0,1) such that ψ ∈ Ψ[hρ, qρ] for allρ∈(ρ0,1).
If Hml [αz1]f(z) ∈ H[1,1], ψ
Hml [α1]f(z)
z ,Hml [α1+ 1]f(z)
z ;z
is analytic in U, and
(13) ψ
Hml [α1]f(z)
z ,Hml [α1+ 1]f(z)
z ;z
≺h(z), then
Hml [α1]f(z)
z ≺q(z), and q is best dominant.
Proof. By applying Theorem 1 and Theorem 3 we deduce that q is a dominant of (13). Since q satisfies (12) it is solution of (13) and therefore q will be the dominant of all dominants of (13). Hence q will be the best dominant of (13).
Example1. Letf ∈A. If (14) Hml [α1+ 1]f(z)
z −Hml [α1]f(z)
z ≺h(z), where
(15) h(z) =− 1
α1 2z (1−z)2 then
Hml [α1]f(z)
z ≺ 1 +z 1−z. Proof. Using (5) and (9) we have
ψ
Hml [α1]f(z)
z ,Hml [α1+ 1]f(z)
z ;z
=ψ
p(z), p(z) + 1 α1
zp0(z);z
=
=p(z) + 1
α1zp0(z)−p(z) = 1
α1zp0(z).
Then (14) becomes
(16) 1
α1zp0(z)≺ − 1
α1 · 2z (1−z)2. Since
h(U) = (
w∈C; Rew > 1 2α1sin2 θ2
) , where z=eiθ, (16) is equivalent to
(17) Reψ
p(z), p(z) + 1
α1zp0(z);z
> 1
2α1sin2θ2 >0, z∈U.
Assume p(z) ⊀q(z) = 1+z1−z. By Lemma A there exist points z0 =r0eiθ0 ∈U, ζ0∈∂U\E(q), andm≥n≥1 that satisfy
p(z0) =q(ζ0) =ρi, ρ∈R and z0p0(z0) =mζ0q0(ζ0) =σ, σ∈R. Then
ψ
p(z0), p(z0) + 1 α1
z0p(z0);z0
=ψ
q(ζ0), q(ζ0) + 1 α1
ζ0q0(ζ0);z0
= 1 α1
σ.
Using Definition 3 and condition (A0), we calculate Reψ
p(z0), p(z0) + 1
α1z0p0(z0);z0
= Re 1
α1σ
= 1
α1σ≤ 1 α1·−1
2 (1 +ρ2)≤0.
Since this contradicts (17), we must have p(z)≺q(z), i.e., Hml [α1]f(z)
z ≺q(z).
Remark 1. If we take l = 1, m = 0 and α1 = 1 in Example 1, then we have the following implication. If
f0(z)− f(z)
z ≺h(z) =− 2z (1−z)2
then f(z)
z ≺ 1 +z 1−z, and q is the best dominant.
REFERENCES
[1] J. Dziok and H.M. Srivastava,Classes of analytic functions associated with the generalized hypergeometric function. Appl. Math. Comput.103(1999), 1–13.
[2] S.S. Miller and P.T. Mocanu,Second order differential inequalities in the complex plane.
J. Math. Anal. Appl.65(1978), 298–305.
[3] S.S. Miller and P.T. Mocanu,Differential subordinations and univalent functions. Michi- gan Math. J.28(1981), 157–171.
[4] S.S. Miller and P.T. Mocanu,Differential subordinations and inequalities in the complex plane. J. Differential Equations67(1987),2, 199–211.
[5] S.S. Miller and P.T. Mocanu,Differential Subordinations. Theory and applications. Pure and Applied Mathematics, Marcel Dekker, Inc., New York, 2000.
Received 5 June 2009 Georgia Irina Oros and Gheorghe Oros University of Oradea
Department of Mathematics Str. Universit˘at¸ii, no. 1 410087 Oradea, Romania georgia oros [email protected]
gh [email protected] In Hwa Kim and Nak Eun Cho
Pukyong National University Department of Applied Mathematics
Pusan 608-737, Korea