C AHIERS DE
TOPOLOGIE ET GÉOMÉTRIE DIFFÉRENTIELLE CATÉGORIQUES
M. M EHDI E BRAHIMI
M. V OJDANI T ABATABAEE
M. M AHMOUDI
Metrizability of σ-frames
Cahiers de topologie et géométrie différentielle catégoriques, tome 45, no2 (2004), p. 147-156
<http://www.numdam.org/item?id=CTGDC_2004__45_2_147_0>
© Andrée C. Ehresmann et les auteurs, 2004, tous droits réservés.
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METRIZABILITY OF 03C3-FRAMES by
M.MehdiEBRAHIMI,
M.Vojdani
TABA TABAEEand M. MAHMOUDI
CAHIERS DE TOPOLOGIE ET
GEOMETRJE DIFFERENTIELLE CATEGORIQUES
Volume XL V-2 (2004)
RESUME. En
imposant
leschangements
ndcessaires a la definition de diam6tremdtrique
d’un cadre donn6e par Banaschewski etPultr,
les auteurs donnent une definition de
a-cadre,
et donc de lacatdgorie
MaFrm des a-cadresmdtriques
et desapplications
uniformes de a-cadres. Ils
prouvent
alors enparticulier I’analogue
du thdor6me de mdtrisabilitd sans
point
de Banaschewski et Pultr.Finalement,
ils caractérisent lacatégorie
M6Frm comme dtantl’intersection des
categories
MLFrm des cadres de Lindel6fmdtriques
et RaFrm des a-cadresrdguliers.
1 Preliminaries
Here,
we recall some definitions from[1], [21, [41, [6],
and[12].
1.1 A
frame (Q-frarrae)
is a lattice L which hasarbitrary (countable) joins
and satisfies thearbitrary (countable)
distributive law x AV
S =V{x
As : s ES},
for all x EL,
andarbitrary (countable)
subsetS C L. A
frame (a-frame)map h:
L-> M is a latticemorphism
pre-serving arbitrary (countable) joins.
Theresulting category
is denotedby
Frm(afbm).
1.2 A cover of a frame
(Q-frame)
is any(countable)
subset A C L suchthat
V
A = 1. The set of all covers of L is denotedby
CovL. IfA,
B arecovers we say that A
refiners B,
and write AB, if,
for each a EA,
there exists b E B such that a b. For a cover A of L and x E L we
put .4r =
B/{a:a
EA,a
1B.1’54 01.
Let L be a frame(a-frame)
andU C Cov L . We write x au y or
simply
x a y if there exists A E U such that{a:a
EA,
aAx # 0} ci
y. We say that U is an admissible.system
ifx = V T,
for some(countable)
subset T of{y:
y axl,
for eachx E L. Note
that,
if L is aframe,
then we have Ax y if andonly
if{a : a E A, a A x i= 0} C!
y, for each .4 E CovL.1.3 In a bounded
lattice,
we say that a is rather belowb,
and writea -
b,
if there exists aseparating
element s of L with a As = 0 ands V b = 1. A frame
(d-frame)
L is calledregulars
if each of its elements isa
(countable) join
of elements rather below it. Noticethat,
in aframe,
a b if and
only
if a* V b =1,
where a* =V{y:
y n a =01.
An elementx of a frame L is said to be a
Lindelöf
elements if whenever x =V
Sfor some ,S’ C L
then,
there exists a countable subset T of S such thatx =
V
T. A frame L is said to be aLindelöf frame
if 1 is a Lindelöf ele- ment. A frame(d-frame)
L is said to beparacompact
if each cover hasa
locally
finite refinement. In[2]
it is shown that anyregular
a-frame,is
paracompact.
1.4 A basis of a frame
(d-frame)
L is a subset B C L such that each element of L is a(countable) join
of elements of B. For the elements a, b of a frame(d-frame) L,
we say that a meets b if a Ab -1=
0. A subset X of a frame(d-frame)
L is said to belocally finite if,
there is a coverW of L such that each w E W meets
only finitely
many x EX,
and it issaid to be discrete
if,
each w E W meets at most one x E X . The abovecover W is said to witness the local finiteness
respectively
discreteness of X. A basis is calleda-locally ,finite (a-discrete) if,
it is a countableunion of
locally
finite(discrete) sets,
and it is called a-admissibleif,
itcan be written as union of an admissible
system
of covers.1.5 Note Let L be a frame. If Ll is an admissible
system
of covers ofL,
then
Uu
is a basis of the frame L[1].
We canshow,
in the same way, that this is also true for a-frames. Given a EL,
let a =V{yn:yn,
aa}.
TakeBn
E u such thatBnyn
a.Then, a
=V{b :bE Bn,bAyn # 0, n C N}.
1.6 Lemma
Any a-frarne
with a coucntable basis is aframe.
Proof: Let B be a countable basis of a a-frame L and X be an
arbitrary
subset of L. It is easy to show thatV X
exists and it isequal
to
V{b E B,
b x, for some x EXI.
Also,
for each X C L anda EL, a
1BVX
=V{a
1B b : b EB, b
x, for some x E
X} V{ a A x : x
EX} a n V X . Hence,
L is a frame.0
1.7 Note In
[1]
it is shown that, if X C L islocally
finite and x a, for each x EX,
thenV X
a.By
the abovelemma,
if L is a a-frame,with a countable basis and X C L is
locally finite,
then x a, for eachx E
X, implies V X
a.2 Some properties of bases of a-frames
Here,
we prove thefollowing theorem,
which is the counterpart
of theproperties
of bases offrames, proved
in[1].
2.1 Theorem The
following
areequivalent for a d- frame
L:(1)
L ha s a countable ba.si.s.(2)
L has a a-discrete basis.(3)
L has aa-locally finite
basis.Moreover,
these areequivalent
to thefollowing,
if L isregular (4)
L ha.s a o--admissible basis.Proof:
(1
->2)
Let B =lb, : n
EHi
be a countable basis. It isenough
to takeBn = {bn},
for each n E N.(2
->3)
This followstrivially
from the definitions.(3
->1)
Let B =U nE N Bn,
where eachBn
is alocally
finite set. Weshow that each
Bn
is a countable set. Let VV be thewitnessing
cover ofBn.
Thus each w e J’V meetsonly finitely
many x EBn.
Letfor each w E W. Let b E
Bn
andb#0.
There exists wi E LYT such thatb A wi # 0 since,
if b A w = 0, for each zu EW,
then b =BAVW
= 0. Thisshows that b E
{b(Wi, 1),
...,b(,u,., lwi)}
and so thereexists j lw,
suchthat b =
b(wi, j) . Therefore, Bn
=U { b( w , j) : w
EvV, j E {1,..., l w}}.
This
gives
thatBn
is a countableset,
since W is a countable set. HenceB =
U Bn
is a, counta,ble basis of L.(4
->3)
Let{Bn :
n EN}
be an admissiblesystem
of covers of L.Regularity
of Limplies
that L isparacompact,
and so eachBn
has alocally
finiterefinement,
sayAn. Now, {An:
n EN}
is an admissiblesystem,
and soU An
is abasis, by
Note 1.5. Thus A =U An
is a a-locally
finite basis.(2
=>4)
Let B= U Bn
be a a-discretebasis,
andBn
be witnessedby
Wn. Take Sw = {b : b E Bn,w Ab #0}.
We haveSw
=0
orSw
={bw}.
For each x E
L, put T
={b :
b EBk,b x}and xk = V T.
SinceT C
Bk,
T is a discrete subset ofL,
and soV T
x,by
Note 1.7. IfSw
-{bw},
thenbwk
bwimplies
that there existst(w, k)
E L suchthat
b-k
At(w, k) =
0 and bw Vt(w, k)
= 1. Take U ={Ank: n, k
EN},
where
and
It is easy to show that Ll C CovL. We claim that
Ankbk b,
for any b EBn.
Let x EAnk,
and x nbk#
0. We show that x - w Ab,
for some w E
1-1"n.
Wehave,
xA bk#
0implies
wA bk fl
0 and sowabo
0. ThusSw # 0
andalso s fl t(tu, k),
since if x = w At(w, k)
then x A
bk #
0implies
w nt(w, k)
Abk # 0
and sot(w, k)
Abk 0
0.This contradiction shows that x = w A bw.
Now,
we have x nbk =1=
0implies w
nb #
0 whichgives b
= bW. Therefore x = w n b b. Henceix : x
EAnk, x
nbk # 01 çt
b and sobk
au b.Also, by regularity
of Lwe have that
Thus,
for each x EL,
x =V{b E B: b x}
=V{V{bk : kEN}:
bxl,
wherebk
a b x, and hence x =V{bk : bk
Qx}.
Therefore U is anadmissible
system,
and thusU u
is a a-admissible basis. 0Note that any countable basis B of a
regular
a-frame L is in fact a-admissible.Since, by
the abovetheorem,
L has a a-admissible basis A =U An. Now, putting B1
=B, Bn+1
={b:
b EB,
b a for some a EAn},
one can show that B =U Bn.
3 Metrization Theorems for a-frames
In this
section, interpreting
the definition of a metric diameter on aframe
given
in[11,
we prove thecounterparts
of the metrization theo-rems for cr-frames.
3.1 Definition A metric diameter on a a-frame L is a monotone zero-
preserving
map d : L -3R+
such that(1)
for all a,b, d(a V b) d(a)
+d(b),
whenever a Ab# 0,
(2)
for each E >0,
there is a countable subset S ofDEL
={a : d(a) el
such thatV S
=1,
(3)
for all a EL,
there is a countable subset T of{y/:y a}
such thatV T
= a, where y a a meansthat,
there exists ê > 0 such that{b : b E DE, b A y # 0} C! a.
(4)
for all a EL,
and e >0, d(a)
=sup{d(x
Vy) :
x, yEDen 4. a},
whenever
d(a)
> c.A d-frame that admits a metric diameter is said to be metrizable..
Also,
a a-frame mapf :
L -3 M between metric a-frames is said to beuniform if,
for each e >0,
there exists d > 0 such thatDdM f[DEL].
Metric frames
(a-frames) together
with uniform frame(d-frame)
maps form a
category,
denotedby
MFrm(Mo-Frm).
Metric Lindel6f framestogether
with uniform frame maps form acategory,
denotedby MLFrm,
which is a fullsubcategory
of MFrm. See[7], [9], [10], [11]
for details.
Having
Theorem 2.1, we prove theremaining parts
of thefollowing.
3.2 Theorem For a
regular a-frame,
thefollowing
statements areequivalent.
(1) L is
metrizable.(2)
L has aa-locally finite
basis.(Naga ta-Smi rnov) (3)
L has a a-discrete basis.(Bing)
(4)
L has a a-admissible basis.(5)
L has a countable basis.(6)
L has a countable adrnissiblesystem of
covers.(Moore)
Proof:
(5
->1)
Let L be aregular
cr-frame with a countable basis B.By
Lemma1.6,
L is a frarne and theregularity
of L as a a-frame,implies
theregularity
of L as a frame.Thus, by Urysohn
metrization theorem for frames[1], L
is a metrizable frame. Let d : L ->R+
be ametric diameter on the frame L.
To show that d is a metric diameter on the d-frame
L,
it isenough
to check the conditions
(2)
and(3)
of the definition. For each 6 >0,
the set
fb
E B : b x, for some x EZE}
is a countable subcover ofDg. Also,
for x EL,
x =V{6
E B :b x}. Hence,
L is a metric o--frame.(1
->6)
Let L be a metric (7-frame with metric diameter d. For eachn E M, let
An
be a countable subcover ofDll,.
Take Ll ={An:
n EN}.
We show that U is an admissible
system.
It isenough
to show that x d yimplies
x Qu y. Let x ad y. Take : > 0 such thatla :
a ED,, a
Ax 0
01 cj
y. We choose n >1/E. Then, {a : a
EAn, a
Ar fl 01 C!
y, andso x u y, since
An
E u. Hence. u is an admissiblesystem
of covers.(6
->5)
Let L be a a-frame and u ={An : n
EN}
be a countableadmissible
system
of covers of L.Then, by
Note1.5,
B =U An
ia acountable basis. O
Compare
thefollowing
with[1, 4.3J.
3.3
Proposition
Aregular Lindelöf frame
is metrizableif
andonly if
it has a corcntable basis.
Proof:
By Urysohn
metrization theorem[1],
aregular
frame withcountable basis is metrizable.
Conversely,
let L be a metric Lindel6f frame with a metric diameterd.By
Lindelöfness ofL,
there exists acountable cover
An
such thatAn
CDll,,
for each n E N, sinceV D1/n
=1. Take B =
U ,4n.
We claim that B is a countable basis of L. Givenx E
L,
we have x =V{y : y x}.
Consider C ={y : y x}.
For eachy E
C,
there exists ¿ y > 0 such that{a :
a EDyy,
aA y # 0} Ci
x. Wechoose n y >
1 /Ey .
It is easy to show thatHence,
B is a countable basis of L. O4 Characterization of metric (7-frames
In this section we characterize the
category M,7Frm,
of metrica-frames,
as the intersection of the
categories MLFrm,
of metric Lindel6fframes,
and
Rd Frm,
ofregular
a-frames.4.1 Lemma
Any
metrica-frame is a
metricLindel6f frame.
Proof: Let L be a metric a-frame with metric diameter d.
By
Theo-rem
3.2,
L has a countablebasis,
sayB,
and so it is aframe, by
Lemma1.6.
Clearly
L is a metric frame with metric diameter d. It isenough
toshow that L is a Lindel6f frame.
Let
V S = 1, for some S C
L. We have 1= V S = V{b E B : b sb,
for some sb E
S}. Thus,
1 =V {Sb :
b EB}.
Hence L is a Lindel6f frame.Q
4.2 Note Let L be a a-fran1e with a countable basis B.
Then,
any a-frame mapf : L
-> M preservesarbitrary joins.
Given S CL,
thenfor some
4.3
Proposition
Thecategory
MoFrm is afull subcategory o.fMLFrm.
Proof:
By
Lemma4.1,
it isenough
to show that any uniform a-frame map between metric a-frames is a uniform frame map. Letf :
L - kI be a uniform a-frame map.By
Theorem3.2,
L has a count-able basis and so,
by
the above note,f
is a frame map.Uniformity
off
as a a-frame mapimplies
theuniformity
off
as a frame map.Thus,
Mufrm C MLFrm.
Also,
any uniform frame map is a uniform a-frame map. Thus, MdFrm is a fullsubcategory
of MLFrm. O4.4 Lemma Let L be a
Lindelöf frame
with countableregularity
prop-erty (each
elementof L
is a countablejoin of
elements rather belowit).
Then,
each elementof
L isLindelbf.
Proof: Let x =
V S’,
for sorne subset S of L.By
countable reg-ularity
ofL,
we have x =V{yn :
yn «x}.
For each n E N, we have 1 =y*n V x = y*n V V s
=V{Y*n
V s : s ES}.
Lindel6fness of Limplies
that there exists a countable subsetTn
C S such thatVfy*
V s : s ETn}=
1 and so YnV Tn,
for each n E N. TakeT = U Tn . Then, x = V{Yn : Yn z) VT
x .Therefore, x = VT
and T is a countable subset of ,S’. D
4.5 Lemma MLFrm n Rdfrm C Mo-Frm.
Proof: Let L be a metric Lindel6f
frame,
with a metric diameterd,
as well as aregular
a-frame. We show that d is a metric diame- ter on the a-frame L. Lindel6fness of L as a framegives
a countablecover
A,
for eachDE.
Given x EL,
we have x =V{y
EL : y x}.
By
Lemma4.4,
x is a Lindel6f element and so there exists a count- able subset Tof {y : y
axi
such that x =V T.
Thus L is a met-ric (7-frame. Therefore
Ob(MLFrm)
nOb(RuF-rm)
COb(MdFrm.)
Also, clearly
any uniform frame map is a uniforma-frame
map. Thus MLFrm n RaFrm C Mdfrm. 04.6 Note
Any
metric frame(d-frame)
is aregular
frame(d-frame).
Tosee
this,
it isenough
to show that x a yimplies x
y. Let x a y. TakeE > 0 such that
{a : a
ED E, a Ax # 01 Ci y. Then,
there exists a(count- able)
subset S CD,
such thatV
S = 1. Take t =Vis : s
E,S’,
s A x =0}.
It is easy to show that x A t = 0 and y V t = 1, and so x y.
4.? Theorem The
category
Ma Frm i.sexactly
the intersectionof
thecategories
MLFrm and RaFrm.Proof:
By
Lemma 4.5, we have MLFrm n RvFrm CMdFrm,
and
by Proposition 4.3,
MdFrm is a fullsubcategory
of MLFrm.Also,
any metric a-frame is a
regular a-frame, by
the above note. Thereforethe
category
MdFrm is asubcategory
of thecategory
RdFrm. Hence MLFrm n RvFrm = Ma Frm. 0Acknowledgements
We would like to thank Professor Banaschewski for the discussion we had with himduring
his visit to Iran and his com-ments.
Our thanks also go to the referee for
his/her suggestions making
thearrangement
and the size of the paper much more reasonable.The financial
support
from Shahid BeheshtiUniversity
of Iran isgratefully acknowledged.
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Address:
Department
of Mathematics Shahid BeheshtiUniversity
Tehran
19839, Iran
Telefax:
(98)(21)(2413135)
e-mail:[email protected] m-mahmoudiCa’cc.sbu. ac.ir