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Relationship between extrinsic stacking faults and mechanical twinning in F.C.C. solid solutions with low
stacking fault energy
J.F.M. Vergnol, J.R. Grilhe
To cite this version:
J.F.M. Vergnol, J.R. Grilhe. Relationship between extrinsic stacking faults and mechanical twinning in F.C.C. solid solutions with low stacking fault energy. Journal de Physique, 1984, 45 (9), pp.1479-1490.
�10.1051/jphys:019840045090147900�. �jpa-00209887�
Relationship between extrinsic stacking faults and mechanical twinning
in F.C.C. solid solutions with low stacking fault energy
J. F. M. Vergnol and J. R. Grilhe
Laboratoire de Métallurgie Physique (*), 40, avenue du Recteur Pineau, 86022 Poitiers, France
(Reçu le 18 janvier 1984, accepti le 12 avril 1984)
Résumé. 2014 Une analyse détaillée de la nucléation et de la croissance des macles, applicable aux matériaux C.F.C.
à basse énergie de défaut 03B3, aboutit à la conclusion suivante : la nucléation des macles n’est possible que si des conditions déterminées, relatives à l’orientation, au sens de la contrainte appliquée, au taux de déformation, sont
satisfaites. L’étude de ces conditions et de leur interdépendance montre que le maclage mécanique est gouverné
par la nucléation et le développement de défauts d’empilement de nature extrinsèque. Le calcul de l’énergie néces-
saire à la nucléation des macles aboutit à une relation quantitative entre la taille des macles et l’énergie de défaut.
L’analyse est effectuée dans le cas où l’axe de traction (ou de compression) est [100] ou [111]. Les hypothèses sont
en bon accord avec les résultats expérimentaux relatifs à de nombreuses solutions solides C.F.C.
Abstract. 2014 A detailed analysis of twin nucleation and growth is performed for the case of face-centred cubic materials with low stacking fault energy 03B3. It is found that twin nucleation may occur only if certain conditions concerning the crystallographic orientation, sign of the applied stress and deformation level, are satisfied. Each of these conditions is analysed ; their interdependence leads to the conclusion that the occurrence of twinning is
controlled by the nucleation and the growth of extrinsic stacking faults. This analysis concentrates on cases where the tensile (or compressive) axis is either [100] or [111]. The discussion of the energy of twin nucleation leads to a quantitative relation between twin size and stacking fault energy 03B3. These assumptions are in good agreement with experimental data on many face-centred cubic solutions.
Classification
Physics Abstracts
62.20F
1. Introduction.
From the first theoretical
analysis
of twin nucleation in face-centred cubic materialsby
Cottrell andBilby [1],
mechanicaltwinning
was considered asbeing improbable,
because ofgeometrical
reasons deducedfrom the
crystallography
of this structure. However, after the first identification of deformation twins insingle crystal
copper(Blewitt,
Coltman and Redman[2]),
manyexperimental
observations have shown that mechanicaltwinning
isquite possible
in face-centred cubic metals oralloys,
if theirstacking
fault energy y is low enough(Venables, [3]).
But
twinning
mechanisms are not yetcompletely
understood, and manyexperimental
results differ from the theoreticalpredictions
ofMahajan
and Williams[4]. Various aspects of twin nucleation, the kinetics of twin
propagation,
the critical shear stress fortwinning
and the relation between
slip
andtwinning during
deformation are still under discussion.
The purpose of the present work is to
provide
a(*) L.A. 131 du C.N.R.S.
detailed
analysis
of the conditions which allow the nucleation and thegrowth
of mechanical twins,without any
hypothesis
about the differentpossible
mechanisms which may
produce
the twin nucleus.Starting
fromexperimental
data onsingle
crystalcopper
alloys
which have beensubject
to stress underwidely varying
conditions(Vergnol
and Villain,[5];
Vergnol [6])
andfollowing
a schemepreviously
sug-gested (Fontaine [7]),
we have divided thetwinning
mechanism into three stages :
-
development
of an initial largestacking
fault,- nucleation of a microtwin
by superposition
ofextended faults in the
neighbouring planes,
- extension of this nucleus
by propagation
of thetwin
boundary through
the strained material.We have
analysed
the nature of the faults(intrinsic
or
extrinsic)
inducedby
deformation in relation to three variables :-
crystallographic
direction of theapplied
stress,- sign of the stress
(tension
orcompression),
-
origin
of the partial dislocationsbounding
thefaults.
Article published online by EDP Sciences and available at http://dx.doi.org/10.1051/jphys:019840045090147900
Thus, we have
computed
the energyrequired
tonucleate a twin, which varies with the nature of the
stacking
faults. Thiscomputation
indicates that the nucleation and then thegrowth
of twins is favouredor
impeded by
the nature of the faults which are formed withincreasing
strain.Finally,
we havecompared
the conclusions of thisanalysis
withexperimental
data,especially
our datafor Cu-Al
alloys.
2. Formation and
growth
of an extendedstacking
faultsAny perfect
dislocation with Burgers vector b may be dissociated into twopartials,
forexample
twoShockley
partialsb1
andb2.
Theapplied
stress agenerally
exerts on the
partials
two different forces which deter- mine the sense ofdisplacement
of each dislocation andconsequently
the nature of thestacking
fault ribbon.Moreover, for low
enough
values of S.F.E. y, the width of this ribbon may increaseenough
to reachvalues
giving
an extended fault boundedby indepen-
dent
partial
dislocations. Thedensity
ofindependent partial
dislocations and therefore thedensity
of extend-ed faults increases with the strain. This facilitates different mechanisms of twin nucleation. We have examined the
possible configurations
for tensile andcompressive stresses
applied along 1 1 1 > and
100 ),which are two stable
crystallographic
directions.2.1 APPLIED STRESS ALONG
A 111 >
DIRECTION. -Referring
to theThompson
tetrahedron offigure
1 a, theglide planes
are(a), (b)
and(c)
forperfect
dislo-cations with Burgers vectors AD, BD and CD.
2.1.1 Tensile
applied
stress.a) Dissociated dislocations
gliding freely
in theirslip plane.
Let us consider the dislocation loop BDafter dissociation :
the resultant forces on the
partials
per unitlength
are(Fig.
1 a, and1 b) :
Fig. 1. - Glide planes and dissociated dislocations with a
tensile stress in the ( 111 ) direction, referring to the Thomp-
son tetrahedron.
We note that the two partials aD and Ba
glide
inthe same direction. The tensile stress a makes the diameter of the dislocation loop BD increase with stress.
The
leading
partial is aD, becausefaD
=2fB.,
andbehind is formed a ribbon of intrinsic fault, but the
stacking
fault is removed by the partial Ba.b) Reaction
junction
in aglide
plane.For example, such a reaction may occur between BD
(a)
and CD(a)
dislocationloops
dissociated in theglide plane (a) :
The two underlined
leading partials
are attractivebecause
they
have the same Burgers vector and oppo- sitesign (Fig. 2b).
After their annihilation, the intrinsicfault surface is delimited
by
thepartial
dislocations Bat and Ca which arerepulsive,
but theapplied
stressa exerts
opposite
forces on them. Hence, a reaction ispossible,
either for a sufficient value of a, or with thermal activation(we
note that the energyrequired
to
temporarily
form theperfect
dislocationBC(a) by
recombination is the same as the energy for cross-
slip) :
where a is the lattice parameter. The
applied
stress ahas no effect on the
perfect
dislocationBC(a),
but itexerts
opposite
forces on thepartials
Boc and Ca whichbind an extrinsic fault Moreover, these
partials
arerepulsive
and each of them can react with the internalpartial
of the initial loop(Fig.
2, stages d ande)
togive
a newpartial
aD.Fig. 2. - Reaction between two dislocations initially dis-
sociated in a type (a) plane. An extrinsic fault takes place by dissociation of the junction dislocation BC.
Hence, the final
configuration resulting
from ajunction
reaction in aglide
plane is aring
of intrinsic faultssurrounding
a large area of extrinsicstacking
faults which widens with
increasing applied
stress(Fig.
2, stage f).c) Reaction on the intersection of two
glide planes.
Two kinds of reaction may occur,
resulting
in thenucleation of an extrinsic fault
The
first possibility,
for example between type(a)
and
(b) glide
planes, leads to an extrinsicstacking
fault in a type
(a)
plane.The
following
reactions(with
the twoleading partial
dislocations
underlined)
are consistent withfigure
3 :The
leading partial
dislocations aD andDB
areattractive and their reaction
gives
rise to the stair-rodczp (Fig. 3b).
This stair-rod, repulsive for thepartial
dislocation Ba but attractive for the
partial RC,
reactswith the latter and
gives
thepartial
dislocation aC.Hence, we find
again
theprevious configuration
with two
repulsive Shockley
dislocations on both sides of an intrinsic faultBy
recombination,they
mayreverse their mutual
positions (Fig.
3d) andgive
riseto an extrinsic fault which extends with
increasing a :
As
previously,
the last recombination stage needs an activation energy.The second
possibility
results in the formation of aCottrell barrier between type
(a)
and(b) glide planes (Fig.
4, stagea).
However, such barriers may be des-troyed,
eitherby
the action of dislocationspiled-up
in
glide planes
behind the barrier, orby
thermal acti- vation, as in the reaction(2) :
Figures
4b and 4c summarize the twopossibilities
which result in the extension of two « half loops » of
extrinsic fault in the initial
glide planes.
In the firstcase, the Frank dislocation BB
lying along
the line CDof the Thompson tetrahedron, is sessile and
gives
rise,by
dissociation, to a first extrinsic fault surface deli- mitedby
theShockley partial
Ba(Fig. 4b),
then to asecond one
by
a similar dissociation of the Frankpartial
aA.The second
possibility
is the recombination of theperfect
dislocation BA, which,by
dissociation, givesthe same configuration as
previously.
We note that the energy needed for reaction
(2)
isa2/18
whereas it isa2/12
for reaction(1).
Thus, it is easier todestroy
a Cottrell barrier than to form aperfect
dislocation from twoShockley
dislocations,Fig. 3. - Reaction on the intersection of type (a) and type (b) slip planes with a tensile stress in the 111 > direction.
Fig. 4. - Formation of « half-loops >> of stacking faults
from a Cottrell barrier, with a tensile stress in the ( 111 >
direction. After stage a, two possible different reactions lead to the same final configuration.
and such destructions are more
likely
to occur.Finally
it appears that a tensile stress
applied
in the ( 111 )direction
gives
rise to intrinsic faults in the initial stage of deformation. But as soon as these faults grow, all the interactions between them nucleate extrinsic faults which extendeasily
withincreasing
tensile stress.2.1.2 Compressive stress. - When the
sign
of theapplied
stress is reversed, the resultant forces on theperfect
andpartial
dislocations are also reversed Thismeans that the
partial
dislocations areexchanged
inany dissociation, and
consequently
thestacking
faultsformed are of
opposite
nature. From this evidence,it is easy to show that, in every case, the
previous
conclusions for
elongation
tests must be reversed for the case ofcompression
tests.Consequently,
acompression
test in the ( 111 )direction
gives
rise to extrinsic faults in the first stage of deformation, and reactions between these faults nucleate intrinsic faults which extend withincreasing applied
stress.2.2 APPLIED STRESS IN THE (
100 >
DIRECTION. -As for the ( 111 ) direction whe have made a detailed
analysis
which is summarized here. The detailed reac-tions and
figures
aregiven
inappendix
1.2 . 2 .1 Tensile stress.
1. Dissociated dislocations
gliding freely
in theirplanes :
the twoSchockley partials
move in the samedirection with a narrow ribbon of extrinsic fault between them.
2. Junction reaction in a
glide plane :
this results in the nucleation of an intrinsic fault which grows withincreasing
stress.3. Reaction on the intersection of two
glide planes :
we have shown that if
only
one dislocation is notdissociated, or has been recombined, this results i4
the nucleation of an intrinsic fault
2.2.2
Compressive
stress. -For the same reasons asgiven previously,
the above conclusions are reversed,i.e.
compressive
stressdevelops
extrinsic faults.2.3 CoNCLUSION. - The nature of the
stacking
faultsinduced in F.C.C.
crystals by
anincreasing applied
stress on
( 111 )
or100 >
directions is as follows : 1. Stress inthe ( 111 )
direction :- initial faults nucleated at the
beginning
of the deformation, before any interaction betweengliding
dislocations, are :+ intrinsic for a tensile test,
+ extrinsic for a compressive test,
these faults widen
slowly
withincreasing
stress;- in the next stages of the deformation, the reac-
tion either between
coplanar
dislocations, or on the intersection ofglide planes, gives
rise to new faults;for the most part, the nature of these is :
+ extrinsic for a tensile test,
+ intrinsic for a
compressive
test;2. With ( 100 ) direction these conclusions are
reversed
3. Computation of the energy for twin nucleation The
following
computationpoints
out the influence of the nature ofstacking
faults ontwinning
nucleation.We consider an idealized twin with a
cylindrical shape.
The planar surfaces are coherent boundaries,for
example
twostacking
faults inplane (a),
that wename twin « faces ». The
cylindrical
surface, namedtwin « front », is
composed
ofpiled-up
partials(as
B0153, Ca orDa) surrounding stacking
faults. Thecrystal
is
perfect
inside and outside thiscylinder, bounding
a twinned volume of matrix, and the energy stored is in consequence localized
only
on the surface of thiscylinder.
3.1 STORED ENERGY ON THE TWIN FRONT. - We consider
stacking
faults of the same nature(intrinsic
or
extrinsic)
oncontiguous planes
of type(a)
sur-rounded
by partial
dislocations(B0153,
Ca orDa) piled-
up in a
regular
array. Threetypical
cases arepossible :
1. Intrinsic faults bounded
by
identical sets of threedifferent
partial
dislocations.This structure
(Fig. 5a)
istypical
inrecrystallised
materials. The stored energy is low because each
triplet gives equivalence
with theperfect crystal :
2. Intrinsic faults bounded
by
identicalpartial
dis-locations.
This type of twin front
(Fig. 5b)
ispromoted
whenone
slip
system is activatedby
theapplied
stress. Theinteractions between
piled-up
dislocations are at amaximum, and the stored energy is
proportional
to b2.3. Intrinsic faults bounded
by
alternatepartial
dis-locations. This last structure is
possible
with twoslip
systemsbeing
activated Theequivalent crystallo- graphic configuration
isgiven by
extrinsic faultspiled-up
at a distance of twoplanes,
since we have(Fig.
5c) :We notice that
(Fig. 5d) :
The energy of the
dipole (b’, - b’)
can beneglected
The
partial
dislocationsb3
= aD areequivalent
toimperfect
dislocations withb" - 1 b 3 Burgers vector,
piled-up
oncontiguous planes,
and the stored energy isproportional
tob2/4. Consequently,
the storedenergy on the front of two identical twins is propor- tional to :
b2 with intrinsic faults
piled-up
oncontiguous
planes,
Fig. 5. - Structure of a twin front composed of piled-up
dislocations on type (a) planes. Three typical arrangements (a, b, c) of partial dislocations are drawn with two equivalent possibilities for (c) arrangement.
b2/4
with extrinsic faultspiled-up
on alternate planes, where b =b1
I =b2 = b3 .
Except for the
configuration (5a)
which is the mostinteresting
but also the lessprobable
withonly
oneor two
glide planes,
the lastconfiguration
is the onewhich
requires
the least energy.3.2 TOTAL ENERGY FOR TWIN NUCLEATION. - The final energy for the nucleation of a twin
depends
alsoon the nature of the
piled-up stacking
faults. We shallsuccessively
examine the cases for the 111 > and 100 ) directions.At first we determine the critical stress for a twin nucleus with extrinsic or intrinsic faults.
3 . 2 .1 Critical stress on the twin front. - The critical
stress (Ie for the
growth
of a twin nucleus is reached whenequilibrium
is achieved between the resolved forcef i on
the unitlength
of each dislocation loopconstituting
the front of the nucleus, and the backforce
f2
resulting from the energy stored on the sur-face of the nucleus
during
itsgrowth.
This energyis
equivalent
to a surface tension E and the backlbrce on the unit surface of a
cylindrical
nucleus withradius r is :
In the
following
computation, weonly
consider the energy stored at the front of the twin nucleus(for
thecomputation
with the energy of the total surface, see§ 3.3.1).
From
previous
results of Kroner [8] and de Wit[9],
we may write the energy of the twin front as follows :
where G and v are
respectively
the shear modulus and the Poisson ratio, h the thickness of the twin, p thedensity
of dislocations(with
Burgers vectorb)
on thefront of the twin. If this front is constituted of n
piled-
up dislocations, we have p =
n/h
and therefore :The critical stress (J c is
proportional
to the back forcef2
on the unitlength
of dislocation at the front of thetwin, and this back force is
J2
=F/n,
hence we may write :where A
depends
on the radius r.If we
neglect
the energy of thedipoles (bi, - b’),
the
configuration given by
intrinsic faultspiled-up
oncontiguous planes
isequivalent
to thatgiven by
extrinsic faults
piled-up
at a distance of twoplanes,
since each
configuration
isequivalent
to dislocations withBurgers
vectorb/2
oncontiguous planes (Fig. 5c).
Thus, the critical stress (J c does not
depend
on thenature of the
stacking
faultsbuilding
up the twin nucleus.3.2.2
Applied
stress in the 111 > direction. - Thefollowing computation
may beapplied
both forthe cases of a
compressive
or a tensile stress in the ( 111 ) direction.Let us consider a twin on n
contiguous planes.
Ifit is
composed
of ni intrinsic faults boundedby,
for example, the samepartials
aD, we have ni = n and the formation of this twin under theapplied
stress ainduces a variation of
length hi
of the crystal, where(Fig.
1) :The expended energy is :
If the same twin is
composed of ne
extrinsic faults boundedby
the samepartials (Ba
orCa)
we havenow ne =
n/2,
and withthese ne
faults, thechanges
in length
he
and energyWe
are :But a’ D = 2 6 a’, and
consequently :
Thus,
twinning
on n planes induces a variation of thelength
which is four times smaller for extrinsic faultsas
compared
with intrinsic faults.Alternately,
a defi-nite change in
length
is inducedby
a twin four timesas thick if
piled-up
faults are extrinsic. We note that theexpended
energy isnearly
the same for both cases,because the
energetic density
on the twin front is four times as small with extrinsic faults.As a result, the nature of the constitutive faults, in
twins induced
by
anapplied
stress on the ( 111 >direction, cannot be
predicted
from the consideration ofexpended
energy of twingrowth.
However, we note that the twin nuclei with extrinsic faults will reach their critical size (for a critical stress
(J c)
before the other nuclei, if we assume that thiscritical size is not
dependent
on the nature of thefaults. Since further growth of the « extrinsic .nuclei » may occur for stresses lower than a,
(Friedel [10]),
it can be
predicted
thatonly
twinscomposed
ofextrinsic
faults
will appearduring plastic
strain in theI I I > direction.
3.2.3
Applied
stress in the 100 > direction. - A similaranalysis (see appendix 2)
for two twins of thesame thickness,
composed
either of ni intrinsic faults,or
of ne
=n; j2
extrinsic faults,gives
thefollowing
relation between the
change
inlength hi
orh.,
and theenergy
W
orW e :
In consequence, the same energy W allows
twinning
on n
planes,
either with ni = n intrinsic faults orne =
n/2
extrinsic faults, with the samechange
inlength
h(for
both tensile andcompressive stresses).
But the
energetic density
on the twin front is four timesas low with extrinsic faults.
Consequently,
forplastic
strain in
the 100 >
direction, theexpended
energy promotestwinning
with extrinsic faults. For a differentreason this conclusion is the same as that with the stress in
the 111 >
direction.3.2.4 Conclusion concerning the occurrence
of ’ twin-
ning. - Theenergetic
cost for the formation of a twinnucleus was determined
by
the computation of twotypical
parameters :- the
energetic density
on the twin front,- the thickness of the twin, connected to the shear
of the
crystal.
It appears that for the four cases considered
(tension
and
compression
in the 111 ) and ( 100 )directions)
twins are
preferentially
formed with extrinsic faults :- in the 111 ) direction because, for the same
expended
energy, the critical size of the nucleus is morerapidly
attained,- in the 100 ) direction because, for the same
twin size the energetic cost is lower.
The greatest
probability
fortwinning
occurrencecorresponds
with the strain conditions which induces extrinsic faults in thecrystal.
Table I summarizesthese conclusions.
3.3 MINIMIZATION OF THE ENERGY OF A TWIN NUCLEUS.
- Up to this
point,
we havecompared
twins whichonly
differby
their thickness and the nature of theirconstitutive
stacking
faults, and we tookonly
intoaccount twin front energy. We now compute the total energy of a twin nucleus
composed
with extrinsicfaults,
according
to the above conclusions.The minimization of this term will
give
theoptimum
distribution of the total energy between the twin front and the faces for each stage of the
growth.
According
to thehypothesis
of Sumino [11], we consi-der that this minimization determines the
dynamic equilibrium
of the twinsduring
deformation at cons- tant strain rate.3.3.1 Qualitative
features of
the model. - Let usconsider a circular
loop (radius r 1)
ofpartial
dislo-cation
bounding
an extrinsic fault(area Sl, S.F.E.y).
The dislocation
loop
energy is a functionF(rl).
Thetotal energy
Ei
of the set « dislocation loop +stacking
fault » may be written as :
Table I. -
Effect of
a tensile or compressive stress oapplied
in the 100 > or 111 > direction, on the natureof
nucleatedfaults,
andresulting
twinning occurrence.The variation of
sample
inlength,
inducedby
thegrowth
of thisloop
is the same as that inducedby n
identical loops,
coaxially piled-up, bounding
a stack-ing
faults, withSn
=S1/n and r.
=r,l.,,In-.
The totalenergy
En
of this twin nucleus,composed
of these n faults, is the energy of the two faces(with
a surfacedensity y/2)
and of the front :With a determined value rj, i.e. for a definite strain of the
crystal,
the first and the second terms are res-pectively decreasing
andincreasing
functions of n.Then En
takes a minimum valueEN
for a definite valueN of n, as shown in
figure
6.3.3.2 The
physical
meaning and computationof
N.Influence of
the S.F.E. y. - From a mechanisticpoint
of view, the
growth
of one extrinsicstacking
faultS,
is
exactly equivalent
to thegrowth
of n identical extrin- sic fault loops, such asSi
=nS,,,
for allpossible
valuesof n. But the
energetic
cost varies with n and the most favourable mechanism is realized when n = N. Then,starting
from its critical size, determinedby
N, nucleustwin
growth
takesplace by
simultaneous extension of the N loops, each of them in its ownglide
plane.The thickness of such a nucleus is 2
N d111,
whered 111
1 is the distance between the{ 111 } planes
in theF.C.C. structure. Then,
assuming
that :we condense n
partial
dislocations b into one dislo- cation(nb),
and write, with G shear modulus :With
aEn/an
= 0, we find :Fig. 6. - Energy En of a twin nucleus vs. the number n of piled-up stacking faults.
A more accurate
computation (see appendix 3)
basedon
previous
results(de
Wit[9])
leads to a relationwhich is
nearly
the same as that obtained with theabove
approximation :
Figure
7 shows thecorresponding
curves. The most important feature of this result is that the critical value N increases with y/G, i.e. with the S.F.E. y(generally
the modulus G does not vary very much incomparison
withy).
Consequently
we expect asignificant
variation ofthe thickness of twins when the S.F.E. y varies
signi- ficantly.
3. 3. 3 Conclusions concerning the energetic cost
of
thetwin nucleation. - These conclusions may be summa-
rized in two
points :
a) whatever the conditions of nucleation
(sense
anddirection of the
applied
stressa),
theenergetic density
of the twin front is a minimum when the
piled-up
dislocations
constituting
this front delimit extrinsicfaults;
b)
a definite shear may be related to asingle
twin,formed
by
a number n of extrinsic faults which may vary. The total energy of this twin is lowest when n isequal
to a definite value N whichdepends
on thematerial through the
S.F.E. y,
the modulus G, the Burgers vector b. This value N increases with the S.F.E. y. In the nextparagraph,
we compare these theoreticalpredictions
with differentexperimental
results.
Fig. 7. - Computation of the energy En of a twin vs.
number n of extrinsic stacking faults and stacking fault
energy y.