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GUANGXIAN ZHU

Abstract. Lutwak, Yang and Zhang established the Orlicz centroid inequality for convex bodies and conjectured that their inequality can be extended to star bodies. In this paper, we confirm this conjecture.

1. Introduction

The centroid body operator is one of the central notions in convex geometry. Blaschke con- jectured that the ratio between the volume of an origin-symmetric convex body and that of the volume of its centroid body attains its maximum precisely when the body is an origin symmetric ellipsoid (see e.g., [15, 26, 37, 59]). By applying Busemann’s random simplex inequality (see [4]), Petty proved Blaschke’s conjecture, extended the definition of centroid bodies, and gave centroid bodies their name [57]. Petty’s theorem is known as the Busemann-Petty centroid inequality (see e.g., [15, 35–37, 59]).

With the development of the Lp Brunn-Minkowski theory and its dual (see e.g., [15, 33, 34, 59]), and the applications of this theory (see e.g., [1–3,5–11,13,18–22,24,27–39,41–44,46–55,58,60–62,64–

68]), theLpanalogues of centroid inequality became a central focus. The fundamental inequality for Lp centroid bodies was established by Lutwak, Yang and Zhang [39] with an independent approach presented by Campi and Gronchi [5]. After that, Haberl and Schuster proved a general asymmetric Lp centroid inequality [22]. For additional references regarding centroid body inequalities and Lp centroid body inequalities and their applications see e.g., [14, 16, 17, 25, 53–55, 69].

In [40] and [45] Lutwak, Yang and Zhang extended theLp Brunn-Minkowski theory to an Orlicz Brunn-Minkowski theory. In [40] they established the Orlicz centroid body inequality for convex bodies. In this paper their inequality, along with its equality conditions, will be extended from convex to star bodies.

Throughout letφ:R→[0,∞) be convex and letφ(0) = 0. Thusφis decreasing on (−∞,0] and increasing on [0,∞). We require that either one is happening strictly, that is φ is either strictly decreasing on (−∞,0] or strictly increasing on [0,∞). The class of such φ is denoted by C, and the subset of C that contains strictly convex functions is denoted by Cs.

LetK is a star body (see Section 2 for precise definition) with respect to the origin in Rn with volume |K|, and φ ∈ C. The Orlicz centroid body ΓφK of K is the convex body whose support function at x∈Rn is given by

(1.1) h(ΓφK;x) = inf

λ >0 : 1

|K|

Z

K

φx·y λ

dy≤1

,

wherex·ydenotes the standard inner product ofxand yinRnand the integration is with respect to Lebesgue measure on Rn. Obviously, when φ(t) = |t|p, with p ≥ 1, the Orlicz centroid body becomes the Lp centroid body.

In [40], Lutwak, Yang and Zhang proved the following theorem,

Mathematics Subject Classification: MR 52A40.

Key Words: Orlicz centroid body, Orlicz centroid inequality, volume ratio, star body, Steiner symmetrization.

1

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Theorem A. If φ ∈ C and K is a convex body in Rn that contains the origin in its interior, then the volume ratio

φK|/|K|

is minimized if and only if K is an ellipsoid centered at the origin.

By using the class reduction technique (introduced in [35]), Lutwak, Yang and Zhang showed that once theLp Busemann-Petty centroid inequality has been established for convex bodies, then the inequality can be extended to all star bodies (see [39]). However, it is unclear whether there exists a similar class reduction technique that is applicable for the Orlicz centroid inequality. They also posted the following open problem:

Conjecture. If φ ∈ C and K is a star body with respect to the origin, then the volume ratio

φK|/|K| is minimized if and only if K is an ellipsoid centered at the origin.

In this paper, we extend the methods (used in [40]) for convex bodies to star bodies. As a result, we can confirm the above conjecture,

Theorem. If φ∈ C and K is a star body with respect to the origin, then the volume ratio

φK|/|K|

is minimized when K is an ellipsoid centered at the origin. If φ ∈ Cs, then ellipsoids centered at the origin are the only minimizers.

This paper is organized as follows. In section 2, we recall some basic facts about convex bodies, star bodies and compact sets. In section 3, basic properties for the Steiner symmetrization of star bodies are developed. In section 4, we prove two auxiliary inequalities. In section 5, we extend two inequalities proved for convex bodies in [40] to the class of star bodies. In section 6, we complete the proof of the Orlicz centroid inequality for star bodies.

2. Some basics facts about convex bodies, star bodies and compact sets All the subsets of Rn appearing in this paper are compact sets unless otherwise stated. If K is a Borel subset of Rn and K is contained in an i−dimensional affine subspace of Rn but not in any affine subspace of lower dimension, then |K| denotes the i−dimensional Lebesgue measure of K. For x∈Rn, we will write |x| for the Euclidean norm of x. For A∈GL(n) we write At for the transpose of A, A−t for the inverse of the transpose of A, and |A| for the absolute value of the determinant ofA. We write e1, ..., en for the standard orthonormal basis ofRn and when we write Rn=Rn−1×Rwe always assume that en is associated with the last factor.

LetKndenote the set of convex bodies (compact convex sets with nonempty interiors),Kondenote those convex bodies that contain the origin in their interiors. A compact set K ⊂ Rn is a star- shaped set (with respect to the origin) if the intersection of every straight line through the origin with K is a line segment. Let K ⊂Rn be a compact star shaped set (with respect to the origin), the radial function ρ(K,·) : Rn\{o} →R is defined by ρ(K, x) =ρK(x) = max{λ≥0 :λx∈K}.

If ρK is strictly positive and continuous, then we call K a star body (with respect to the origin), denotes the class of star bodies (respect to the origin o) in Rn by Son.

If K,L are two compact sets in Rn and λ∈R, their Minkowski sum K+Lis defined by, K+L={x+y:x∈K, y∈L},

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and for λ >0, the scalar multiplication λK is given by λK ={λx:x∈K}.

For two compact sets K, L in Rn, the Hausdorff distance between them is defined by d(K, L) = min{t ≥0 :K ⊂L+tBn, L⊂K+tBn}.

Let h(K;·) = hK : Rn → R denote the support function of the convex body K ∈ Kn; i.e., h(K;x) = max{x·y:y∈K}. It is known that the Hausdorff distance between two convex bodies K and L is given by

d(K, L) = max

u∈Sn−1|hK(u)−hL(u)|.

Obviously for K, L ∈ Kn, we have K ⊂ L if and only if hK ≤ hL. For c > 0 and x ∈ Rn, we have hcK(x) = chK(x) and hK(cx) = chK(x). More generally for A∈GL (n) we have

hAK(x) = hK(Atx), and

hK+L(u) =hK(u) +hL(u).

For a direction en = u ∈ Sn−1, a convex body K ⊂ Rn−1 ×R and (x0, t) ∈ Rn−1 × R, we will usually write h(K;x0, t) rather thanh(K; (x0, t)). Let Ku denote the image of the orthogonal projection ofK ontou, and let

K ={(y0, z) :−lu(K, y0)≤z ≤¯lu(K, y0), y0 ∈Ku},

where lu(K;·) :Ku →Rand ¯lu(K;·) :Ku →R are the lowergraph anduppergraph functions of K in the direction u. The following lemma will be needed (see e.g., [40]).

Lemma 2.1. Suppose K ∈ Kon and u ∈ Sn−1. For y0 ∈ relint Ku, the uppergraph function and lowergraph function of K in the direction u are given by

lu(K;y0) = min

x0∈u{h(K;x0,1)−x0·y0}, and

lu(K;y0) = min

x0∈u{h(K;x0,−1)−x0·y0}. 3. Steiner symmetrization of star bodies

In this section we discuss properties of the Steiner symmetrization of star bodies. For a compact set K with nonzero measure, the intersection of K with any straight line is a compact set on the line (so the intersection is a one dimensional Lebesgue measurable set). The Steiner symmetrized body SuK of K with respect to the hyperplane u is characterized by the following properties:

First, SuK is symmetric with respect to the hyperplane u. Second, any straight line that is parallel to u and intersects K or SuK, intersects also the other and both intersections have the same one-dimensional measure. Third, the intersection of a straight line parallel to u with SuK is a segment or a point in u. A further property of Steiner symmetrization is that, if K is a compact set, then SuK is also compact for any u∈Sn−1 (see e.g., [12]).

Let {ui }1≤i≤k be a finite set of hyperplanes. A multiple symmetrization is a composite of the form

S =Su

k ◦Su

k−1 ◦ · · · ◦Su

1.

For a nonempty compact setK, letS(K) denote the set of all S(K) multiple symmetrizations of K. The following well known lemma proved by Lusterink and Gross will be needed (see e.g., [23]

p.170-173).

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Lemma 3.1. Let K be a nonempty compact set, then there is a sequence {Ki} ⊂ S(K) and a closed ball rB¯n centered at the origin of radiusr such that|rB¯n|=|K| andKi →rB¯n with respect to the Hausdorff distance.

Lemma 3.2. Let K be a star-shaped set with respect to o, then K is a star body with respect to o if and only if for any u∈Sn−1, all the points of {tu : 0≤t < ρK(u)} are interior points of K.

Proof. AssumeK is a star body (respect too) but there exist au0 ∈Sn−1 and at0 ≥0, such that t0u0 ∈ {tu0 : 0 ≤ t < ρK(u0)} is not an interior point of K. Let δ = 12K(u0)−t0), since t0u0 is not an interior point of K, there exist an open ball (t0+δ)Bn centered at the origin of radius (t0 +δ) and a sequence of points Pi such that Pi ∈ ((t0+δ)Bn∩(Rn\K)) and Pi → t0u0. Let ui = (oPi)/|oPi| ∈Sn−1, then ui →u0. Since Pi are not from K, ρK(ui)<|oPi| for all i∈ N and

|oPi| →t0 < ρK(u0). We have thatρK(u) is not continuous atu0, which is a contradiction. So for any u∈Sn−1 all the points of {tu: 0≤t < ρK(u)} are interior points of K.

If for anyu∈Sn−1 all the points of{tu: 0≤t < ρK(u)} are interior points of K, but K is not a star body. Which means ρK(u) is not continuous onSn−1, then there exist aδ >0, a u0 ∈Sn−1, and a sequence of ui ∈ Sn−1 such that ui →u0 but |ρK(ui)−ρK(u0)| > δ for alli. Thus, we can either find an infinite subsequence of the ui (without loss of generality we can suppose it is ui) such that ρK(ui)−ρK(u0) > δ, or we can find an infinite subsequence of the ui (without loss of generality we can suppose it is the ui) such that ρK(u0)−ρK(ui) > δ. For the first case, since ui →u0 and ρK(ui)ui is bounded, the sequence ρK(ui)ui has at least one limit point P. Since K is compact, P ∈ K and obviously P ∈ {tu0 : t ≥ ρK(u0) +δ}, which is a contradiction. For the second case, since ui →u0 and ρK(ui)ui is bounded, the sequence ρK(ui)ui has at least one limit point P, obviously P ∈K and P ∈ {tu0 : 0≤t ≤ρK(u0)−δ}. Since K is a star-shaped set, the sequence of pointsQi = (ρK(ui) + 1/i)ui is not in K. Obviously P is a limit point of Qi and P is not an interior point ofK, which is a contradiction. ThereforeK is a star body.

Theorem 3.3. If K ∈ Son and u∈Sn−1, then SuK ∈ Son.

Proof. SinceK is a compact set, SuK is compact (see e.g., [12]). For anyv ∈Sn−1 leta0 =a0(v) = sup{a :a >0, av∈SuK}. SinceSuK is compact, a0v ∈SuK. Furthermore we claim that for any s (0 ≤ s < a0) we have, the point P = sv is an interior point of SuK. Then the intersection of SuK with any straight line through o is a segment, and except the two end points, all the points of this segment are interior points of SuK. Thus by Lemma 3.2, SuK is a star body.

For any point P = sv (0 ≤ s < a0), write (sv)u and (a0v)u for the projections of sv and a0v onto u. Since K is a star body, for any point Q∈K∩ {(a0v)u+tu:t∈R}, we have

(s/a0)Q∈K ∩ {(sv)u+tu :t ∈R}.

So the set (s/a0)(K ∩ {(a0v)u +tu : t ∈ R}) is a subset of K ∩ {(sv)u +tu : t ∈ R}, and it is compact. By Lemma 3.2, for any point

Q∈(s/a0)(K ∩ {(a0v)u+tu :t ∈R}),

Q is an interior point ofK, so we can find an open cube ∆Q such thatQ∈∆Q, ∆Q ⊂K and the edges of ∆Q are parallel to the axes. Thus we have an open cover of the compact set

(s/a0)(K ∩ {(a0v)u+tu :t∈R}),

so we can choose a finite open cover of (s/a0)(K∩ {(a0v)u+tu :t∈R}), and denote this cover by

Q1,∆Q2, ...,∆Qm. Obviously in u, the point (Q1)u = (Q2)u =· · ·= (Qm)u = (sv)u is an interior point of ∆0 =∩mi=1(∆Qi)u (where (∆Qi)u is the projection of ∆Qi ontou). Let

tM =|(∪mi=1Qi)∩ {(sv)u+tu:t∈R}|

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and

δ0 =|K∩ {(a0v)u+tu:t ∈R}|, then

(s/a0){(a0v)u×[−δ0/2, δ0/2]} ⊂∆0×(−tM/2, tM/2)⊂SuK.

Since ∆0×(−tM/2, tM/2) is an open set and

P =sv ∈(s/a0){(a0v)u×[−δ0/2, δ0/2]},

P is an interior point ofSuK. Thus, by Lemma 3.2, SuK is a star body.

4. Two auxiliary inequalities

In this section we prove two basic inequalities that will be needed in the following sections.

Lemma 4.1. Let φ∈ C, a1a2 <0, b1, b2 ∈R, and c1, c2 >0, then f(t) = c1φ(a1t+b1) +c2φ(a2t+b2)

is a convex function and there exists a t0 such that f(t) is decreasing on (−∞, t0], increasing on [t0,+∞), and limt→−∞f(t) = limt→+∞f(t) = +∞. If φ ∈ Cs, then f(t) is a strictly convex function and there exists a unique t0 such that f(t) is strictly decreasing on (−∞, t0], strictly increasing on [t0,+∞) and limt→−∞f(t) = limt→+∞f(t) = +∞.

Proof. Let fi(t) = ciφ(ait +bi). Since φ(t) is convex on R and c1, c2 > 0, for any 0 ≤ λ1 ≤ 1, λ2 = 1−λ1 and t1, t2 ∈R, we have

fi1t12t2) = ciφ[ai1t12t2) +bi]

=ciφ[λ1(ait1+bi) +λ2(ait2+bi)]

≤ci1φ(ait1+bi) +λ2φ(ait2+bi)]

1fi(t1) +λ2fi(t2).

(4.1)

So f(t) = f1(t) +f2(t) is convex on R. Obviously when φ ∈ Cs, the functions f1(t), f2(t), f(t) are strictly convex.

Let tm = min{−ba1

1,−ab2

2}, tM = max{−ab1

1,−ba2

2}. If tm = tM (denoted also by t0), then, since φ ∈ C and a1a2 < 0, c1, c2 > 0, both f1 and f2 are increasing on [t0,+∞) and decreasing on (−∞, t0], so is f = f1 +f2. If tm < tM, then f(t) is increasing on [tM,+∞) and decreasing on (−∞, tm]. Let f(t0) = mintm≤t≤tM f(t), if t0 = tM then f(t) is increasing on [t0,+∞); if t0 < tM then choose any t0 < t1 < t2 ≤ tM and let λ = (t2 −t1)/(t2−t0), then 0 ≤ λ ≤ 1 and λt0+ (1−λ)t2 =t1, so

f(t1) = f[λt0+ (1−λ)t2]≤λf(t0) + (1−λ)f(t2)≤f(t2),

thereforef(t) is increasing on [t0, tM]. Sincef(t) is continuous onR,f(t) is increasing on [t0,+∞).

Similarly we can prove that f(t) is decreasing on (−∞, t0]. Since a1a2 <0, c1, c2 >0 and φ ∈ C, limt→+∞f(t) = limt→−∞f(t) = +∞. Obviously when φ ∈ Cs, f(t) is strictly decreasing on (−∞, t0] and strictly increasing on [t0,+∞) (otherwise f(t) will not be strictly convex), and

limt→+∞f(t) = limt→−∞f(t) = +∞.

Lemma 4.2. Let f(t) ≥ 0 be a continuous function, decreasing on (−∞, t0] and increasing on [t0,+∞). If E is a compact subset of R, then

(4.2)

Z

E

f(t)dt ≥

Z t0+

t0−δ

f(t)dt,

where δ =|E∩(−∞, t0]|, δ+ =|E∩[t0,+∞)|.

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If f is strictly decreasing on (−∞, t0], strictly increasing on [t0,+∞) and there exists a t00 not in E and |E∩(−∞, t00]|>0,|E∩[t00,+∞)|>0, then

(4.3)

Z

E

f(t)dt >

Z t0+

t0−δ

f(t)dt.

Proof. We will prove (4.4)

Z

E∩[t0,+∞)

f(t)dt≥

Z t0+

t0

f(t)dt and

(4.5)

Z

E∩(−∞,t0]

f(t)dt ≥ Z t0

t0−δ

f(t)dt.

SinceE is a compact set, we havet+= supE <+∞. Letti =t0+ni(t+−t0),(where 0≤i≤n).

When ti ≤ t < ti+1 (0≤ i < n−1), define fn(t) = f(ti) and fn(tn) = f(t+). Obviously {fn}n=1 is an increasing sequence of simple functions on E∩[t0,+∞) andfn(t)→f(t). By the monotone convergence theorem (see e.g., [63]) we have

Z

E∩[t0,+∞)

f(t)dt = lim

n→+∞

Z

E∩[t0,+∞)

fn(t)dt

= lim

n→+∞

n−1

X

i=0

fn(ti)|E∩[ti, ti+1]|. (4.6)

Let t0i = t0 +|E∩[t0, ti]| (0 ≤ i ≤ n), define fn0(t) = f(t0i) when t ∈ [t0i, t0i+1],(0 ≤ i ≤ n−1), andfn0(t0n) = f(t0+). Then{fn0}+∞n=1 is an increasing sequence of simple functions on [t0, t0+] and fn0(t)→f(t). By the monotone convergence theorem we have

Z t0+

t0

f(t)dt= lim

n→+∞

Z t0+

t0

fn0(t)dt

= lim

n→+∞

n−1

X

i=0

fn0(t0i)

t0i+1−t0i

= lim

n→+∞

n−1

X

i=1

fn0(t0i)|E∩[ti, ti+1]|. (4.7)

Since f(t) is increasing on [t0,+∞), fn0(t0i) ≤ fn(ti), by (4.6) and (4.7), we obtain (4.4). By a similar argument one can prove (4.5), so

Z

E

f(t)dt ≥

Z t0+

t0−δ

f(t)dt.

Assume now that f is strictly decreasing on (−∞, t0], strictly increasing on [t0,+∞) and there exist a t00 such that t00 is not in E and |E ∩[t00,+∞)| > 0, |E ∩(−∞, t00]| > 0. Without loss of generality we can assume thatt0 ≤t00 < t+. SinceEis a compact set, there exists aδ0 >0 such that [t00, t000]∩Eis empty. And sincef is continuous and strictly increasing on [t0,+∞), there exists a δ00such thatf(t)−f(t−δ0)> δ00 on [t00, t+], and whenti > t0i0,f(ti)−f(t0i)> f(ti)−f(ti−δ0)> δ00. By (4.6) and (4.7), this yields

Z

E∩[t0,+∞)

f(t)dt−

Z t0+

t0

f(t)dt≥ |E∩[t00,+∞)|δ00 >0.

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Together with (4.5), we obtain Z

E

f(t)dt >

Z t0+

t0−δ

f(t)dt.

5. Steiner symmetrization of Orlicz centroid bodies

In this section, we prove two inequalities for star bodies, both of them were proved by Lutwak, Yang and Zhang for the case of convex bodies in [40].

Lemma 5.1. If φ∈ C and K ∈ Son, then for any u∈Sn−1, and x01, x02 ∈u,

h(Γφ(SuK);1

2x01+ 1

2x02,1)≤ 1

2h(ΓφK;x01,1) + 1

2h(ΓφK;x02,−1), and

h(Γφ(SuK);1

2x01+ 1

2x02,−1)≤ 1

2h(ΓφK;x01,1) + 1

2h(ΓφK;x02,−1).

If φ∈ Cs, P1, P2 are two interior points of K, and the segment P1P2 does not completely lie in K, then, for u= (P1−P2)/|P1−P2|, equality can not hold in either of the inequalities.

Proof. According to the affine properties of Orlicz centroid bodies (see [40]), for A ∈GL(n) and K ∈ Son, we have Γφ(AK) =AΓφK. Without loss of generality we can assume that|K|=|SuK|= 1.

Denote by K0 = Ku the image of the projection of K onto u. For y0 ∈ K0, denote by σy0(u) = σy0 =|K∩(y0+Ru)|the one dimensional measure of K∩(y0+Ru).

For fixed x01, x02, x00 = 12x01+ 12x02 ∈K0 and any y0 ∈K0, s∈ R and λ1, λ2, λ0 = 12λ1+ 12λ2 ∈ R+, by Lemma 4.1 the function

g(s) = λ1 λ0

φ

x01·y0+s λ1

+ λ2

λ0

φ

x02·y0−s λ2

is convex, and there exists ayu(y0) =y(y0) such thatg(s) is decreasing on (−∞, y(y0)] and increas- ing on [y(y0),∞). Let σ+y0 =|K∩(y(y0) +R+u)| and σy0 =|K∩(y(y0) +Ru)|.

By Lemma 4.2 we have (5.1)

Z

K∩(y0+Ru)

g(s)ds≥

Z y(y0)+σ+y0

y(y0)−σ

y0

g(s)ds.

Let my0 =my0(u) be the midpoint of y(y0)−σy0 ≤t ≤y(y0) +σy+0. By the convexity of φ(t) we have

(5.2) λ1 λ0φ

x01·y0+t+my0(u) λ1

+ λ2

λ0φ

x02·y0+t−my0(u) λ2

≥2φ

x00·y0 +t λ0

.

Let

A= λ1 λ0

Z

K

φ

(x01,1)·y λ1

dy+ λ2 λ0

Z

K

φ

(x02,−1)·y λ2

dy.

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By Fubini’s theorem and (5.1), we have A=

Z

K0

Z

K∩(y0+Ru)

λ1 λ0φ

x01·y0+s λ1

+ λ2

λ0φ

x02·y0 −s λ2

dy0ds

≥ Z

K0

Z y(y0)+σ+y0

y(y0)−σ

y0

λ1 λ0φ

x01·y0+s λ1

+ λ2

λ0φ

x02·y0 −s λ2

dy0ds

= Z

K0

Z y(y0)+σy+0

y(y0)−σ

y0

λ1 λ0φ

x01·y0 +s λ1

dy0ds+ Z

K0

Z y(y0)+σ+y0

y(y0)−σ

y0

λ2 λ0φ

x02·y0−s λ2

dy0ds.

(5.3a)

Sincey(y0)−σy0 =my012σy0,y(y0)+σ+y0 =my0+12σy0, by making the change of variabless=my0+t for the first integral of the last equation in (5.3a), and making the change of variables s=my0−t for the second integral of the last equation in (5.3a). Together with Fubini’s theorem and (5.2) we obtain

A≥ Z

K0

Z σy0/2

−σy0/2

λ1 λ0

φ

x01·y0+t+my0 λ1

dy0dt+ Z

K0

Z σy0/2

−σy0/2

λ2 λ0

φ

x02·y0+t−my0 λ2

dy0dt

= Z

SuK

λ1 λ0

φ

x01·y0+t+my0 λ1

+ λ2

λ0

φ

x02·y0+t−my0 λ2

dy0dt

≥2 Z

SuK

φ

1

2x01+ 12x02

·y0+t

1

2λ1+12λ2

! dy0dt.

(5.3b)

Consequently (5.3c) λ1 λ0

Z

K

φ

(x01,1)·y λ1

dy+λ2 λ0

Z

K

φ

(x02,−1)·y λ2

dy ≥2 Z

SuK

φ

(x00,1)·y λ0

dy.

Choose any numbers λ1 > h(ΓφK;x01,1) ≥ 0, λ2 > h(ΓφK;x02,−1) ≥ 0. Then, since |K| =

|SuK|= 1, and by (1.1), we haveR

Kφ((x01,1)·y/λ1)dy≤1,R

Kφ((x02,−1)·y/λ2)dy≤1. From this and (5.3c) we obtain

1≥ 1

|SuK| Z

SuK

φ

(x00,1)·y λ0

dy.

Since λ0 can be any positive number bigger than 12h(ΓφK;x01,1) + 12h(ΓφK, x02,−1), by (1.1) we conclude

(5.4) h(Γφ(SuK);1

2x01+ 1

2x02,1)≤ 1

2h(ΓφK;x01,1) + 1

2h(ΓφK;x02,−1).

Note, if we making the change of variables s=my0−t for the first integral of the last equation in (5.3a), and making the change of variable s = my0 +t for the second integral of the second equation in (5.3a) then by similar argument one obtains,

(5.5) h(Γφ(SuK);1

2x01+ 1

2x02,−1)≤ 1

2h(ΓφK;x01,1) + 1

2h(ΓφK;x02,−1).

Assume now thatφ∈ Csand there exist two interior pointsP1, P2 of K and a pointP such that P ∈P1P2 but not fromK. Letu= (P1−P2)/|P1−P2|, and choose two open ballsriBn(Pi) (where i= 1,2) centered at Pi of radiusri. Since K is compact andP is not fromK, there exists an open ballrBn(P) centered atP of radiusrsuch thatrBn(P)∩K is empty and (rBn(P))u ⊂(riBn(Pi))u for i= 1,2. Thus, for any point Q∈rBn(P) we have|K∩(Q+R+u)|>0,|K∩(Q+Ru)|>0.

From the condition φ is strictly convex, strictly decreasing on (−∞,0] and strictly increasing on [0,+∞). By Lemma 4.1, g(s) is also strictly convex and there exists a unique yu(y0) such that g(s) is strictly decreasing on (−∞, yu(y0)] and strictly increasing on [yu(y0),+∞). Moreover, by

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Lemma 4.2 when y0 ∈ (rBn(P))u the equality in (5.1) can not hold, and since |(rBn(P))u| > 0, the equality of the first inequality in (5.3a) can not hold either. Thus, equality in both (5.4) and

(5.5) can not hold.

We note that for the Steiner symmetral SuK of K ∈ Kn in the directionu, the lowergraph and uppergraph functions are given by

(5.6a) lu(SuK;y0) = 1

2

lu(K;y0) + ¯lu(K;y0) , and

(5.6b) ¯lu(SuK;y0) = 1 2

lu(K;y0) + ¯lu(K, y0) .

Lemma 5.2. If φ∈ C and K ∈ Son, then for u∈Sn−1, Γφ(SuK)⊂SuφK)

If φ ∈ Cs and there exist two interior points P1, P2 of K such that the segment P1P2 does not completely lie in K, then, for u= (P1−P2)/|P1−P2| ∈Sn−1, we have

Γφ(SuK)6=SuφK).

Proof. Fory0 ∈relint(ΓφK)u, by Lemma 2.1, there existx01 =x01(y0), x02 =x02(y0)∈u such that (5.7a) luφK, y0) = hΓφK(x01,1)−x01·y0,

and

(5.7b) luφK, y0) = hΓφK(x02,−1)−x02·y0.

Now by (5.6a), (5.6b), (5.7a), (5.7b) followed by Lemma 2.1, and Lemma 5.1 we have lu(SuφK);y0) = 1

2luφK;y0) + 1

2luφK;y0)

= 1

2(hΓφK(x01,1)−x01·y0) + 1

2(hΓφK(x02,−1)−x02·y0)

≥hΓφ(SuK)(1

2x01+ 1

2x02,1)−(1

2x01+1

2x02)·y0

≥ min

x0∈u{hΓφ(SuK)(x0,1)−x0·y0}

=luφ(SuK);y0), (5.8)

and

lu(SuφK);y0) = 1

2luφK;y0) + 1

2luφK;y0)

= 1

2(hΓφK(x01,1)−x01·y0) + 1

2(hΓφK(x02,−1)−x02·y0)

≥hΓφ(SuK)(1

2x01+ 1

2x02,−1)−(1

2x01+1

2x02)·y0

≥ min

x0∈u{hΓφ(SuK)(x0,−1)−x0·y0}

=luφ(SuK);y0).

(5.9)

So

Γφ(SuK)⊂SuφK).

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If φ ∈ Cs, P1, P2 are two interior points of K such that the segment P1P2 does not completely lie in K, and u= (P1−P2)/|P1 −P2| ∈Sn−1. Then by Lemma 5.1 equality in inequality (5.8) and

(5.9) can not hold, thus Γφ(SuK)6=SuφK).

6. Orlicz centroid inequality For star bodies

In this section, we prove the Orlicz Busemann-Petty centroid inequality for star bodies.

Theorem. If φ∈ C and K ∈ Son, then the volume ratio

φK|/|K|

is minimized when K is an ellipsoid centered at the origin. If φ ∈ Cs, then ellipsoids centered at the origin are the only minimizers.

Proof. We prove this theorem in two steps. First we prove the inequality and in the second step we prove the uniqueness of minimizers.

ForK0 =K ∈ Son and a sequence of positive number εm →0, by Lemma 3.1 and Theorem 3.3, there exist a closed ball rB¯n centered at the origin of radius r and a sequence u11, u12, ..., u1i1 ∈ Sn−1, such that

d(K1, rB¯n)< ε1, whereK1 =Su

1,i1

◦Su

1,i1−1◦· · ·◦Su

1,1K is a star body obtained fromK by multiple symmetrization.

In particular |rB¯n|=|K|.

From Lemma 5.2 we have (6.1) |Γφ(Su

1,i1

◦Su

1,i1−1 ◦ · · · ◦Su

1,1K)| ≤ |Γφ(Su

1,i1−1 ◦ · · · ◦Su

1,1K)|.

Therefore, in particular,

(6.2) |ΓφK1| ≤ |ΓφK0|=|ΓφK|.

If i = m−1 then we can find a sequence um,1, um,2,...,um,i

m such that d(Km, rB¯n) < εm and

φKm| ≤ |ΓφKm−1|, where Km = Su

m,im ◦ Su

m,im−1 ◦ · · · ◦ Su

m,1Km−1 is a star body. When i=m, sinceKm is a star body, by Lemma 3.1 and Theorem 3.3 we can find a sequence of um+1,1, um+1,2,...,um+1,i

m+1, such that d(Km+1, rB¯n) < εm+1 and |ΓφKm+1| ≤ |ΓφKm|, where Km+1 = Su

m+1,im+1 ◦Su

m+1,im+1−1 ◦ · · · ◦Su

m+1,1Km is a star body and |Km+1| = |rB¯n|. By induction we obtain a sequence of {Km} with |Km|=|K| such that

(6.3) d(Km, rB¯n)< εm

for all m ∈N, and

(6.4) |ΓφKm| ≤ |ΓφKm−1|

for all m ∈N.

By (6.3), Km → rB¯n with respect to Hausdorff distance, so limm→+∞φKm| = |Γφ(rB¯n)|, (see [40]). By (6.2) and (6.4) we obtain that

(6.5) |ΓφK| ≥ |Γφ(rB¯n)|.

ForA ∈GL(n), we have Γφ(AK) =AΓφK, (see [40]), thus

φK|

|K| ≥ |Γφn|

|B¯n| .

Consequently, the volume ratio |ΓφK|/|K| is minimized when K is an ellipsoid centered at the origin.

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We turn now to the equality conditions. For this assume thatφ∈ Cs and K ∈ Son. If K ∈ Son is not convex, then for any point P ∈∂K, by Lemma 3.2 all the points of the segmentoP except P are interior points ofK. Since K is not convex, we can chooseP3, P4 ∈∂K such that there exists a point Q∈P3P4, but not in K. SinceK is compact, we can choose an open ballr0Bn(Q) centered at Q of radius r0, such that r0Bn(Q)∩K is empty. Also we can choose P1 ∈oP3,(P3 6= P1) and P2 ∈ oP4,(P4 6= P2), such that P1P2 ∩(r0Bn(Q)) is not empty and from Lemma 3.2 P1, P2 are interior points of K. Let u1 = (P1−P2)/|P1−P2| ∈Sn−1, by Lemma 5.2 we have

(6.6) Γφ(Su1K)⊂Su1φK),

and the inclusion is not an identity. If we use Su1K to replace K =K0 in the first step, by (6.3), (6.4), (6.5), (6.6) and the affine property of Orlicz centroid body, we have

φK|

|K| > |Γφn|

|B¯n| .

If φ ∈ Cs and K ∈ Son is a convex body, then, by Theorem A, ellipsoids centered at the origin are the only minimizers of |ΓφK|/|K|. So when φ ∈ Cs and K ∈ Son, ellipsoids centered at the

origin are the only minimizers.

After work on this project was completed, the author learned of the work of Paouris [56]. While there is some overlap of results, the methods employed to achieve them are quite different.

This work can be extended to compact sets and will be done in a future paper.

Acknowledgment. I thank the referee for very careful reading and helpful comments on the paper.

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