On the Fixed-Point Set and Commutator Subgroup of an Automorphism of a Group of Finite Rank
B. A. F. WEHRFRITZ
ABSTRACT- Le tfbean automorphism of a groupG. ForGpolycyclic, Endimioni and Moravec in [1] discuss the relationship between the fixed-point setCG(f) and the commutator subgroup [G,f] offinG. Here we extend these results to soluble groups satisfying various rank restrictions.
Supposefis an automorphism of thepolycyclic groupG. Endimioni and Moravec in [1] prove the following.
i) IfCG(f) is finiteandfhas order 2, then [G,f]0is finite.
ii) IfCG(f) is finite, then so isG=G;f].
iii) Ifjfjis finite, then so is the index (G: [G,f].CG(f)).
Of course CG(f) denotes the set of fixed points of f in G, [G,f] = hg 1:gf:g2Giand [G,f] is af-invariant normal subgroup ofG. Here we generalize these results to groups with some sort of rank restriction.
Generally our groups at least have finite Hirsch number and satisfy something weaker than the FAR condition. We must start by defining these terms.
If a groupGhas a series of finite length each factor of which is either locally finite or infinite cyclic, then the number of infinite cyclic factors in such a series is an invariant ofG, which wecall theHirsch number ofG(it is also sometimes called the torsion-free rank ofG). This is theweakest of the rank restrictions considered here. The structure of groups with finite Hirsch number is discussed in many places (e.g. see [3]). From our point of view the most convenient description of the structure of such a group is
(*) Indirizzo dell'A.: School of Mathematical Sciences, Queen Mary University of London, MileEnd Road, London E1 4NS, England.
E-mail: [email protected]
given by Lemma 4 of [6]. A group satisfies min-pfor theprimepif itsp- subgroups satisfy theminimal condition on subgroups. An FAR group (that is, a finite-abelian-ranks group, also called anSo group) is a soluble group with finite Hirsch number that satisfies min-pfor every primep. Se e for example [3] for a discussion and alternative definitions of the class of FAR groups. In particular all solublegroups of finite(PruÈfer) rank are FAR groups. The following summarises our main conclusions in this paper.
THEOREM. Let f be an automorphism of the finite extension G of a solubleFARgroup. Then the following hold.
i) If CG(f)is finite and f21, then[G,f]0is finite.
ii) If CG(f)is finite, then G/[G,f]is finite.
iii) Iffhas finite order, then the index(G: [G,f].CG(f))is finite.
In fact we can weaken the FAR hypothesis in the theorem considerably in many places. For i) it suffices to assume only thatGis a group with finite Hirsch number (even in a weak sense). For iii) it suffices to assume thatG is a soluble-by-finite group with finite Hirsch number satisfying min-pfor all primes p dividing theorder of f. However we do need some min-p hypothesis; suppose Gis thedirect product of thecyclic groups haiji of orderp fori1, j1, 2 andp any (fixed) prime. Definef :G!G by ai1fai1andai2fai1ai2for eachi1. Thenfis an automorphism ofG of primeorderpwithG;f CG f hai1:i1i. Thus G:G;f:CG f
is infinite. TriviallyG has Hirsch number 0. As Endimioni and Moravec point out in [1], we do needfof finite order in iii), even ifGis free abelian of rank 2. Notethat iii) implies thatG=G;fis isomorphic to a finite extension of a section ofCG(f); see Remark 6 below.
We are unable to weaken the FAR condition in ii) in general, though we can in special cases. Note that ii) implies thatCS(f) is finite for everyf- invariant sectionSofG. Iffhas finiteorder (withCG(f) finite) it suffices for ii) to hold to assumethatGis just soluble-by-finite with finite Hirsch number, see Remark 7. If f has prime order, then it suffices simply to assumethatG has finite Hirsch number, since Theorem 1 of [6], for ex- ample, reduces the problem to the soluble-by-finite and hence previous case. A (torsion-free)-by-finite group with finite Hirsch number is always a finite extension of a soluble FAR group, so this case is also covered. Of courseif G satisfies the conclusion of iii) andCG(f) is finite, then again G=G;fis always finite.
If in ii) theorder offis infinite, then we do need some sort of min-p condition, even if f acts fixed-point freely on G. For e xample , le t G
denotethecartesian product of theadditivecyclic groups haiiof order pi, whe re pis any primeandi1;2; ::::. De fine f:G!Gby eiaif eipei 1ai, whe re the ei are integers with e00. Then f is easily seen to be an automorphism ofGof infiniteorder withCG(f h0iand [G,f pG. In particular G=G;f is infiniteand trivially G is abelian with Hirsch number 0. Clearly Gis uncountable, but if DG denotes thedirect product of thehaii, the n H S
i1Df i gives a countable counter example. Finally the converse of ii) is false, even if G is poly- cyclic and fhas primeorder, seeExample8 below.
By removing from our proof of the above theorem the complications caused by the presence of finite rank but infinitely generated sections, one can use our methods to construct somewhat shorter proofs of i), ii) and iii) than those given in [1]; this is especially the case with iii).
LEMMA1. Let G be a group with a series of finite length, each factor of which is either periodic or infinite cyclic. Iffis an automorphism of G with CG(f)finite andf2= 1,thenG;f0is finite.
Part i) of the Theorem follows at once from this. Note that the condition onGin Lemma 1 is weaker than having finite Hirsch number as we have defined it in the introduction above.
PROOF. NowGhasf-invariant normal subgroupsABwith A and G/
B finite and B/A abelian and inverted by f, see [5] Theorem 2. Also
G;f;B A; this follows from [1] Lemma 1, but it also follows immediately from simply expanding the commutatorg;f;bfor any g2Gandb2B.
ThenG;fA=Ais centre-by-finite. HenceG;f0A=AandAareboth finite.
ConsequentlyG;f0is finite.
LEMMA 2. Let A be an additive torsion-free abelian group of finite rank. Iffis an automorphism of A with CA f h0i, then A=A f 1is finite.
PROOF. Clearlyf 1 extends to an automorphismuofV QZA. In particular detu60. By the Cayley-Hamilton Theorem detu2Quu EndQV. Thus there is a positive integerewithe2ZuuEndQV. He nce eAA:ZuuAuA f 1and thereforeA=A f 1is finite.
For any group G denotetheuniquemaximal locally finitenormal subgroup ofGbyt G.
LEMMA3. Let G be a group with finite Hirsch number h and witht G
finite. Iff is an automorphism of G with CG(f) finite, then G=G;fis finite.
PROOF. We induct on h; clearly ifh0 theclaim is vacuous. Sup- poseh1. Then Ghas a non-trivial torsion-freeabelian characteristic subgroupAwith G/A(torsion-free)-by-finite (e.g. see Lemmas 4 and 6 of [6]). Clearly CA f h1i, so by Le mma 2 we have A:A;f e finite. SetBAe. The nBis characteristic in G, B G;fand A=Bis finite. Further the map a7!ae is an isomorphism of A onto B com- muting withf, so B:B;f A:A;f e. By [4] Le mma 1 we have jCG=B fj ejCG fj<1. By induction on h thegroup G=G;fB is finite. SinceB G;fwehaveG=G;f finite.
LEMMA4. Let G be a finite extension of a soluble FAR group. Iffis an automorphism of G withjCG fj n finite, then G=G;fis finite.
Part ii) of the Theorem follows at once from Lemma 4.
PROOF. Se tp{primesp:pn} andTt G. By [2] 3.17 there is a characteristic series
h1i T0T1::::TsTG
of Gwith each Ti=Ti 1 an abelianp0-group fori<s, Ts=Ts 1 a divisible abelianp-group andT=Tsfinite.
Suppose AT1 is a p0-group. Clearly CA f h1i. Then the map g:a7!a 1:af is an isomorphism of A into itself. If Ap is the p-primary component of A, thenApApg. IfAp>Apg, then Apgi>Apgi1 for all i0. But Ap satisfies the minimal condition (G satisfies min-p for all primesprecall). ThereforeApApgfor allpandAAg G;f. Also if K=ACG=A f, then Lemma 1 of [4] yields that K:A n.
Now supposetheAT1is a divisibleabelianp-group (thecases1).
Then Ag is divisible and hence is a direct summand of A. But kergjACA fis finitesoAAgand alsoAis a direct product of a finite (invariant) number of PruÈfer groups. ThereforeAgA. Again weobtain K:A n.
A simpleinduction on s shows thatTs G;fand that thecentralizer of f on G=Ts has order at most n. Further t G=Ts is finite. Therefore G=G;fTs is finite by Lemma 3. ConsequentlyG=G;fis finite.
LEMMA5. Let G be a soluble-by-finite group with finite Hirsch number andfan automorphism of G of finite order m. Suppose G satisfiesmin-p for every prime p dividing m. Then G:G;fCG fis finite.
Part iii) of the Theorem follows from Lemma 5.
PROOF. If N is a f-invariant subgroup of G of finiteindex with N:N;fCN ffinite, then G:G;fCG fis also finite. In particular we may assumethatGis soluble. SetC=CG(f).
Supposefirst thatTt Gis finite. Weprovethis caseby induction on theHirsch number of G. If Gis finitetheconclusion is vacuous. If not G has a non-trivial torsion-free abelian characteristic subgroup A withG/A(torsion-free)-by-finite ([6] Lemmas 4 and 6 again). Define the map g:G!G by g7!g;f and let c denotetheendomorphism 1fjA fjA2:::: fjAm 1 of A. Clearly c gjA 0, so AcC.
Also if a2A, the n am is congruent to ac modulo Ag. The re fore AmAg:Ac A;f A\C:
LetAmKGwithK=Amthe centralizer inG=Amoff. NowA=Am is finitesinceA has finiterank, so induction applies to G=Am. Conse - quently wemay assumethat G:G;fKis finite. Also A\K:Amis finiteand K A\KC, the latte r by Le mma 15 of [6]. The re fore K:AmCis finite; thus G:G;fAmCis finite. ButAm A;f A\C).
Consequently G:G;fC is finite. This completes the proof of the T- finitecase.
Let pdenote the set of prime divisors of m. By [2] 3.17 there is af- invariant normal series h1i T0T1::::Ts TofGas in theproof of Lemma 4, with factorsTi=Ti 1abelianp0-groups or divisibleabelianp- groups andT=Ts finite. For each ithesectionfx2Ti:xm2Ti 1g=Tiis finite. Hence by our initial remark we may assume that each of these sections is central in G. By theT-finitecasewemay assumethat G=Ts
satisfies theconclusion of thelemma. Thus by induction on s wemay assumethat G has a periodic abelian characteristic subgroup A with AmA, B fa2A:am1g finiteand central in G and G:G;fK
finite, whereKis given byK=ACG=A f.
Letk2K. Thenkg2AAm, saykgamfora2A. Nowam2acAg andacg1,cbeing as in theT-finitecase. Thusamc:dgforcac2C and somed2A. Hencekgc:dgand
kd 1gd:kg:d 1fd:c:dg:d 1fc2A\C:
Notethat theargument also implies that AAg A\C
A;f A\C. Sincetheactions ofkandf onAcommute, so kandkd 1 normalizeA\C. Thenfstabilizes the series
h1i A\C hkd 1i A\C
and hence kd 1;fm kd 1;fm 1. Thus kd 12L, where L=BCG=B f. Hence KLAAL; indeed KAL. Also f stabilizes the series h1i BL and B is central in L. Therefore gjL is a homo- morphism ofLintoBwith kernalC. Thus L:C jBj<1. Consequently K:AC is finiteand hence G:G;fAC is finite. As we saw above A A;f A\C. Therefore G:G;fC G:G;fA;fC is finite, as required.
REMARK6. SupposeGandfareas in Lemma 5. Then alwaysG=G;fis a finite extension of some section ofCG(f). For ifNdenotes the intersection of theconjugates inGofG;fCG f, thenG=Nis finiteby Lemma 5 and
G;f N. ThusN G;fCN fandN=G;f CN f= G;f\CN f.
In particular if X is a subgroup and imageclosed class of groups containing CG(f) and if F denotes the class of finite groups, then G=G;f 2XF. IfGis polycyclic, this is Proposition 1 of [1].
REMARK 7. Let G bea soluble-by-finitegroup with finiteHirsch number. Iffis an automorphism ofGof finiteorder withCG(f) finite, then G/[G,f] is finite.
PROOF. Se t Tt G. Repeated use of [6] Lemmas 9 and 13a) yield thatT=T;fandCG=T fare both finite. ThenG=G;fTis finiteby Lemma 5 (or Lemma 3 if you prefer). TriviallyT;f G;f. ThereforeG=G;fis finite.
EXAMPLE8. Letvbea primitivep-th root of unity inCfor someprime pand putRZv CandGTr1 3;R. (HereZdenotes the integers, C the complex numbers and Tr1 3;R thelower unitriangular group of degree 3 over the ringR; laterQwill denote the rational numbers.) ThenG is a 2 p 1-generator nilpotent group of class 2 (and in particular is polycyclic). IfZdenotes the centre ofGand {eij} thestandard set of matrix units inC33, thenZ1Re31G0andZRandG=ZRR.
Let f denote the automorphism of G induced by conjugation by the diagonal matrix diag 1;v;1. Thenf has orderp, centralizes Zand acts
fixed-point freely on G=Z. If x1ae21 and y1be32 for some a, b2R, then a simple calculation shows that
x 1:xf;y 1:yf 1 v 12v 1abe312 G;f0: Also 1vv2::::vp 10, so p P
1i<p 1 vi 2 v 1R.
Therefore 1p2Re31Z\ G;f0 and in particular G;fZ:G;f Z:Z\ G;fdividesp2 p 1:
Supposeg gij 2G. Themapg7! g21;g32is a homomorphism ofG onto RR with kernel Z that maps G;f onto v 1 RR. Thus G:G;fZalso dividesp2 p 1. ConsequentlyG=G;fis finiteof order dividingp4 p 1. HoweverCG f Z, which is infinite. Thus the converse of Part ii) of the Theorem does not hold, even for polycyclic groups and au- tomorphisms of finiteprimeorder.
Supposeinstead of Tr1 3;RwesetGTr1 3;K, whereKis thefield Qv C, but withfstill given by conjugation by diag 1;v;1. Then here Gis torsion-free nilpotent of finite rank and class 2 andZCG f Kis infinite,Zbeing the centre ofGagain. Our previous argument shows that G=G;f has finite exponent (dividing p3). But Gis divisible, so here we havejfj p,G G;fandCG(f) infinite.
REFERENCES
[1] G. ENDIMIONI- P. MORAVEC,On the centralizer and the commutator subgroup of an automorphism, Monatsh. Math., to appear.
[2] O. H. KEGEL- B. A. F. WEHRFRITZ,Locally Finite Groups, North Holland Pub. Co., Amsterdam 1973.
[3] D. J. S. ROBINSON,Finiteness Conditions and Generalized Soluble Groups (2 vols.), Springer-Verlag, Berlin 1972.
[4] B. A. F. WEHRFRITZ, Almost fixed-point-free automorphisms of soluble groups, J. Pure& Appl. Algebra,215(2011), pp. 1112-1115.
[5] B. A. F. WEHRFRITZ, Almost fixed-point-free automorphisms of order 2, Rend. Circ. Mat. Palermo,60(2011), pp. 365-370.
[6] B. A. F. WEHRFRITZ,Almost fixed-point-free automorphisms of prime order, Cent. Eur. J. Math.9(2011), pp. 616-626.
Manoscritto pervenuto in redazione il 5 settembre 2011.