A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
V. B ENCI
D. F ORTUNATO
F. G IANNONI
On the existence of geodesics in static Lorentz manifolds with singular boundary
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 19, n
o2 (1992), p. 255-289
<http://www.numdam.org/item?id=ASNSP_1992_4_19_2_255_0>
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Lorentz Manifolds with Singular Boundary(1)
V. BENCI - D. FORTUNATO - F. GIANNONI
1. - Introduction and statements of the results
In this paper we
study
someglobal geometric properties
of certain Lorentz structures. Moreprecisely
we prove existence andmultiplicity
results aboutgeodesics joining
twogiven points
in Lorentz manifoldshaving
asingular boundary.
Werequire
that thesegeodesics
do not touch theboundary.
Some
particular
solutions of the Einsteinequations (for
instance theSchwarzschild
spacetime,
see e.g.[9,
page149]),
and of the Einstein-Maxwellequations (for
instance the Reissner-Nordstromspacetime,
see e.g.[9,
page156])
areexamples
of those Lorentz structures which we consider.Before
stating
the definitions of thegeometrical
structures, we need to recall some basic notions which can be found forexample
in[14].
Apseudo-
Riemannian manifold is a smooth
manifold 9
on which anondegenerate (0, 2)-
tensor
g(z)(z), [.,.] (z
Eg)
is defined. This tensor is called metric tensor. If g ispositive
definitethen §
is a Riemannian manifold. A Lorentz manifold L is apseudo-Riemannian
manifold with the metric tensor ghaving
index 1(i.e.
every matrixrepresentation
of g hasexactly
onenegative eigenvalue).
If a Lorentzmanifold has dimension 4, it is called
"spacetime".
If noambiguity
can occur,we denote
by (, R
the metric on a Riemannian manifold andby ~ , ~ L
themetric on a Lorentz manifold.
We recall that a
geodesic
on a Lorentz manifold f is a curvewhere
a, b
E R, is the derivative of1(8),
and is the covariant derivative of1(8)
withrespect
to the metric tensor g.It is well known that a
geodesic
is a criticalpoint
of the"energy"
~1~ Work
supported
by Ministero dell’Universita e della Ricerca Scientifica e Tecnologica (40%-60%, 1989).Pervenuto alla Redazione il 20 Marzo 1991 e in forma definitiva il 15 Ottobre 1991.
functional
If -1
is ageodesic
on L there exists a constant such thatA
geodesic 1
is calledspace-like,
null or time-like ifE,
isrespectively
greater,
equal
or less then zero. A time-likegeodesic
isphysically interpreted
as the world line of a material
particle
under the action of agravitational field,
while a null
geodesic
is the world line of alight
ray.Space-like geodesics
haveless
physical relevance,
howeverthey
are useful to thestudy
of thegeometrical properties
of a Lorentz manifold.Now we shall
give
some definitions.DEFINITION 1.1. Let
(L, (, }L)
be a Lorentz manifold. is called(stan- dard)
static Lorentz manifold if:there exist a Riemannian manifold
Mo
of classC2
with metrich(x)[-, .]
] of classC2
and a scalar field,~
CC2 ( .M o, ]0,+oo[)
such that(,G, ( , L)
is isometric to.M o
x Requipped
with the Lorentz metricg(Z)[.,.](2),
definedby
where
We shall
identify
f withMo
x R and we shall write f =.M o
x R. Ifz c L we set z =
(x, t)
with x EMo
and t E and t are called static coordinates of z. We refer to[12,
page328]
for thephysical interpretation
ofa static
spacetime.
In a
previous
paper(see [5]),
we have studied the existence and themultiplicity
ofgeodesics
in static Lorentz manifolds under theassumptions:
(i)
the Riemannianmanifold (M 0, h)
iscoinplete,
(ii)
there existN, v
> 0 such that N >~3(x) > v for
all x E,M o.
However in many
physically
relevant casesassumptions (i)
and(or) (ii)
are not satisfied. ’
Consider for
example
the solution of the Einsteinequations corresponding
to the exterior
gravitational
fieldproduced by
a staticspherically symmetric
~2) This means that there is a diffeomorphism such that
dw denoting the differential map.
(3) Here denotes the tangent space to MoxR at z, denotes the tangent space to .Mo at x and R is identified with its tangent space.
massive
body.
Thissolution,
called Schwarzschildmetric,
can be written(using polar coordinates)
in the form:where =
d192
+sin2
~9 ~ is the standard metric of the unit2-sphere
in theEuclidean
3-space,
m =GM/c2,
G is the universalgravitation
constant, M is the mass of thebody
and c is thespeed
of thelight.
The Schwarzschild
spacetime
is the Lorentz manifoldequipped
with the metric(1.4).
Notice that the Riemannian metrichas no
meaning
on theregion
Moreover it is easy to see that the radial
geodesics (r(s), 190, Spo)
SPo ER)
onMo
with respect to the Riemannian metricdx2
"reach" theregion {(r, ~9, ~p) :
r =2m~
within a finite value of theparameter
s. ThereforeMo
with the metric
dx2
is notcomplete.
MoreoverThen both conditions
(i)
and(ii)
are not satisfiedby
the Schwarzschildspacetime.
The metric
(1.4)
issingular
onaNo
x R in the sense that it cannot besmoothly
extended on8 Mo
x R. However thesingularity
is notintrinsic,
but itis a consequence of the choice of the static coordinates.
In fact if we denote
by (K, g)
the Kruskalspacetime (which
is the maximalanalytical
extension of the Schwarzschildspacetime,
cf.[11]
or[9,
pp. 153-155]),
there is aninjective isometry
and g
is notsingular
on a xR)).
However a xR))
is not a smooth 3-manifold. In this way thesingularity
has been "transferred" from the metric to the geometry of theboundary,
and thisjustifies
the title of this paper.We recall that
(1.4)
solves the Einsteinequations
for r > rM, rMbeing
the radius of the
body responsible
for thegravitational
curvature.Then,
it isphysically meaningful
toequip
allMo
x R with the metric(1.4) only
ifrM 2m. In this case the matter of the
body
is "contained" within the event horizon{r
=2m}
and we are in the presence of a universe with a black hole.The name is
justified by
the fact that alight
ray cannot leave theregion { r 2m}.
If an astronaut "falls" in the blackhole,
hespends
a finite"proper"
time,
but an observer far from the black hole does not see the astronaut to fall in it in a finite time. Moreprecisely
any time-likegeodesic
in the Schwarzschildspacetime
can reach theregion {r
=2m} only
if the time coordinate t goes to(see
theappendix).
Having
inmind,
asmodel,
the Schwarzschildspacetime
we are led tointroduce the
following
definitions:DEFINITION 1.2. Let U be an open connected subset of a manifold M and let aU be its
topological boundary.
U is said to be a static universe if(i)
U =Mo
x R is a static Lorentz manifold(see
Definition1.1 );
(ii)
supQ
+oo, where~3
is the function in(1.3);
No
(iii)
lim(3(Xk)
= 0, for anytk)
- z E aU;k +oo k
(iv)
forevery 6
> 0 the setMo : ~3(x) > 61
iscomplete (with
respect tothe Riemannian structure of
(v)
for every time-likegeodesic i(s) = (x(s), t(s))
in U such that lim = 0, we have lim supIt(s)1 =
+oo.S-50
REMARK 1.3. Condition
(v)
says that if a materialparticle
reaches thetopological boundary
of U, an observer far from theboundary (Schwarzschild observer)
does not see this event in a finitetime,
since his proper time is areparametrization
of the universal time t. This conditionjustifies
the name ofthe structure introduced in Definition 1.2.
Notice that in
general (v)
does not follow from(iii).
In fact consider the Lorentz manifoldwith metric
ds2
=dx2(3(x)dt2,
where
,Q
is bounded and(3(x)
= x - 1 if x 2.A
straightforward
calculation shows that it does notsatisfy (v).
In the
Appendix
weverify
that the Schwarzschildspacetime satisfy (v)
ofDefinition 1.2.
Then, clearly,
it is a static universe.Another
example
of static universe isgiven by
the Reissner-Nordstr6mspacetime
_when
m2
>e2.
Here mrepresents
thegravitational
mass and e the electriccharge
of the
body responsible
of thegravitational
curvature. This can be seenby
thesame
computations
used for the Schwarzschildspacetime (see
theAppendix).
Whenever U is a static universe we have the
following
results about the existence of time-likegeodesics joining
twogiven
events.THEOREM 1.4. Let U = x R be a static universe
(see Definition 1.2).
Let zo =
(xo,
to) and zi =(x 1, ti)
be events in U. There exists a time-likegeodesic
1 in U such that
1(0)
= zo and = z,if
andonly if
and
REMARK 1.5. When we fix xo and x 1, the condition
(1.5)
iscertainly
satisfied if
It - to ) I
islarge enough,
while it does not hold wheneverIt
-to ~ I
issmall.
REMARK. Condition
(ii)
of Definition 1.2 is essential to obtain ourexistence results. In fact the Anti-de Sitter space
(see
e.g.[9,16])
furnishescounterexamples
to the existence ofgeodesics
between twogiven
events.However if
~3(x)
goes to +oo with a mild rate as x goes to oo, Theorems 1.4 and 1.6 still hold.Now let £ =
Mo
x R be a static Lorentz manifold and(xo, to), (x 1, ti)
twoevents in ,G. If
(x(s), t(s))
is ageodesic joining (xo, to)
and(xl, tl),
since themetric tensor is
independent of t, (x(s), t(s)
+T)
is ageodesic joining (xo,
to + r)and
(xl,
t1 + T). Then the number ofgeodesics
in Ljoining
two events(xo, to)
and(Xl, t1) depends only
on xo, x 1and t
We denote
by N(xo,
zi,It
1 -tol)
the number of time-likegeodesics
in Ujoining (xo, to)
and(x 1, tl).
If U has a non-trivialtopology
weget
thefollowing
multiplicity
result ofgeodesics joining
zo and zl.THEOREM 1.6. Let U =
.Mo
x R be a static universe and(,lvlo, h)
aC3-
Riemannian
manifold
which is not contractible initself.
Moreover assume that(1.5)
holds.Then
About other existence results for time-like
geodesics joining
twogiven points
in Lorentz manifolds we refer to[1,18,19],
where the Lorentz manifoldsare assumed to be
globally hyperbolic.
In this paper we deal also with the
problem
of thegeodesical connectivity
for a Lorentz manifold. We recall that
A Lorentz
manifold
L is calledgeodesically
connectedif for
every there exists ageodesic
1 :[0, 1]
] --~ L such that~r(o) -
zo andClearly,
forstudying
thegeodesical connectivity
it is necessary to consider alsospace-like geodesics
which are more difficult to deal with. Thegeodesical connectivity
has not been treated in the works[1,18,19],
which dealonly
withtime-like and null
geodesics.
Thisproblem
has been faced in[3,4]
forstationary complete
Lorentzmanifolds (4)
withoutboundary.
Here we consider the case of static Lorentz manifolds withsingular boundary,
in order to cover the case ofthe Schwarzschild
spacetime.
For the
study
of thegeodesical connectivity
the condition ofbeing
a staticuniverse
(see
Definition1.2)
is notappropriate.
Indeed consider the Lorentz manifoldwith metric where
,Q
is bounded andSimple
calculations show that(1.7)
is a static universe while it is notgeodesically
connected
(the
events of the type(xi,
X2, to) and(-xl,
-X2, to) cannot bejoined by geodesics lying
in the Lorentz manifold(1.7)).
For this reason we introducethe
following geometrical
condition:DEFINITION 1.7. Let f be an open connected subset of a manifold N and its
topological boundary. £
is said to be a static Lorentzmanifold
withconvex
boundary
if(i)
L =Mo
x R is a static Lorentz manifold(see
Definition1.1));
(ii) sup B
+oo, where(3
is the function in(1.3);
No
(iii)
thereexists 4J
EC~(~R~B{0})
such that(iv)
for every 77 > 0 theset {x
EMo : Q(x) >n}
iscomplete (with
respect to the Riemannian structure of.M o);
(v)
there existN, M, v, 6
ER+)(0)
such that the function4J
of(iii)
satisfies:~4~ I.e. with the metric tensor not
depending
by the time variable.In the
appendix
we prove that the Schwarzschildspacetime
is a staticLorentz manifold with convex
boundary using
thefunction Q given by
Also the Reissner-Nordstrom
spacetime Ir
> m + x R is a 2o
2static Lorentz manifold with convex
boundary provided
thatm2 > 9 /5. e2,
as wehave
proved
in theappendix using
the functionDefinition 1.7 allows us to obtain the
following
result:THEOREM 1.8. A static Lorentz
manifold
with convexboundary
isgeodesically
connected.REMARK. Notice
that 0
becomes zero on8.c,
so(1.9) implies
However,
in order to get thegeodesic connectivity
of,~,
it seems we need acontrol of the rate for which the limit in
(1.10)
is achieved. Theassumption (1.9) provides
this control.Whenever the
topology
of £ is not trivial weget
thefollowing multiplicity
result about
space-like geodesics.
This result has beenproved
in[4]
in the case ofstationary
Lorentz manifoldsMo
x R withMo
compact.THEOREM 1.9. Let ,G =
Mo
x R be a static Lorentzmanifold
with convexboundary,
and(.Mo, h)
aC3
Riemannianmanifold
which is not contractible.(5) v up(z) denotes the gradient of the function Q with respect to the Lorentz structure, i.e. it is the unique vector field F(z) on L such that
(6) denotes the Hessian of the function Q at z in the direction v, i.e.
3:2
y(7(s)))swhere 7 is a geodesic in L such that 1(0)=z and
Then, for
every zo, z, E.c,
there exists a sequenceof space-like geodesics
in Ljoining
zo and z, such thatREMARK 1.10. Theorems 1.4 and 1.6 hold even for a static Lorentz manifold with convex
boundary,
while Theorems 1.8 and 1.9 ingeneral
donot hold for a static
universe,
as we can seeusing
the Lorentz manifold(1.7).
The results
proved
in this paper have been announced in[6].
2. - Technical
preliminaries
Let £ be a static Lorentz manifold. Then
(see
Definition1.1)
f is isometricto
Mo
x Requipped
with thewarped product
where z =
(~), ~ = (~, T)
E(Tz No)
x R.In the
following
we set forsimplicity
and
Let zo =
(xo,
to), zi =(x 1, t 1 )
be two events inMo
x R - We putand
K21
1 is a Hilbert manifold(see
e.g.[10,17])
and itstangent
space at xE Ql
1is
given by
Here
TMo
is thetangent
bundle ofMo
while~~([0, l],TMo)
is the set of theabsolutely
continuouscurves ~ : [0,1]
] -~T M 0,
such thatwhere
D,
is the covariant derivative withrespect
to the Riemannian structure.Notice
that (.,.)
1 is the Riemannian structure of Q1 I inheritedby
that ofMo.
We denote
by C([o,1], Mo)
the space of the continuous curves x :[o,1]
-Mo
endowed with the metricwhere d is the distance derived from the Riemannian metric on
Mo.
Considernow the Riemannian manifold
It is easy to see that the
"energy"
functionalis
C~ on
Z. Thegeodesics
on Cjoining
zo, zi are the criticalpoints
off
on Z,namely 1
E Z is ageodesic
if andonly if,
for allwhere denotes the covariant derivative
of ~
in the direction with respect to the metric(2.1)
andWe are interested in
studying
situations in which(Mo, h)
is notcomplete (see
Section1).
In these cases alsoC([0, 1], Mo)
and Q1 are notcomplete.
Toovercome this lack of
completeness
we introduce a suitablepenalization
termin
(2.5).
Moreprecisely
we shall setwhere
We shall
specify
thepenalization
functionV~~
in Sections 3 and 4 where weshall prove Theorems
1.4, 1.6,
1.8 and 1.9.Since the
metric g
isindefinite,
the functional(2.7)
is unbounded both from below and from above. Nevertheless thestudy
of the criticalpoints
ofIe (~ > 0)
can be reduced to thestudy
of the criticalpoints
of a suitablefunctional which is bounded from below when
#
is bounded from above.In fact let zo =
(xo, to),
zi =(x 1, t 1 )
be twopoints
in L and consider the functionalJ(x) being
definedby
where A = t, - to. Observe that
(2.9)
is bounded from below if~3
is boundedfrom above.
The
following
theorem holds:THEOREM 2.1. Let
z(s) = (x(s),
t(s)) E Z(see (2.4)).
Then thefollowing
statements are
equivalent:
(i)
z is a criticalpoint of Ig
on Z;(ii)
x is a criticalpoint of J,
on921,
i. e.~~~ Here a’ and V,., denote the Riemann gradient of f3 and V, respectively.
and t =
t(s)
solves theCauchy problem
Moreover
if (i) (or (ii))
issatisfied,
we haveIn
particular
z is a criticalpoint of f iff
x is a criticalpoint of
J.When - = 0, Theorem 2.1 has been
proved
in[5]. Nevertheless,
for the convenience of thereader,
we shallgive
here aproof
of Theorem 2.1.PROOF OF THEOREM 2.1.
(i)
~(ii).
Letz(s) = (x(s), t(s))
be a criticalpoint
ofIg
on Z. ThenTaking ~
= 0 in(2.13)
weget
then there exists a constant K G R such that
Integrating
in[0,1]
] we getBy (2.16)
and(2.15)
we deduce that t =t(s)
solves(2.11 ).
Now if wesubstitute
(2.11 )
in(2.13)
and choose T = 0, we see that(2.10)
is satisfied.(ii)
~(i). Suppose
that x 1 solves(2.10)
and t solves(2.11 ). Obviously
t solves
(2.14).
Now if in( 2.10 )
we add(2.14)
and substitute02 f
-2
o
fJ(x) by (2.11 ),
we seethat z = (x, t)
satisfies(2.13), namely
it is a criticalpoint
ofIg
on Z.Finally (2.12)
isimmediately
checked..The
following
Lemma will be usefulLEMMA 2.2.
Let ze = (x,, tg)
E Z be a criticalpoint of f,.
Then there existsK,
E II~ s. t.Moreover
PROOF.
(x,, te)
E Z is a criticalpoint
ofIe
we havewhere
D,
andVL
denoterespectively
the covariant derivative and thegradient
with respect to the Lorentz
metric (.,.) L
defined in(2.1 ).
From(2.19)
we deducethat,
for all s,then,
for all s,from which we deduce
(2.17).
Nowintegrating (2.17)
from 0 to 1 we haveThen
by using (2.12)
of Theorem 2.1 we get(2.18).
We conclude this section with a lemma which allows us to overcome the
difficulty
due to the lack ofcompleteness
ofMo.
LEMMA 2.3. Let f- =
Mo
x R be a static Lorentzmanifold
andsuch that
Now let be a sequence in
i2l(Mo,xo,xl)
such thatand there exists sn E
10, 11 such
thatThen
The
proof
of Lemma 2.3 isessentially
contained in[2].
Nevertheless for the convenience of the reader we shallgive
here theproof.
PROOF OF LEMMA 2.3. From
(2.24)
we deduce thatis a bounded subset of
Mo. Then, by using (2.23),
we deduce that there existsa real constant c 1,
independent
of n, such that(g) Here denotes the gradient of the function Q with respect to the Lorentz structure while denotes the gradient of the function § with respect to the Riemann structure h(~>f.~.J.
for all n E
N,
for all s E[o, 1 ] .
denotes the norm inducedby
theRiemannian
structure).
From(2.25),
for s > sn, we havewhere c2 is a constant
independent
of n. SinceØ(X1)
> 0 for all thereexists it
> 0 such thatindependently
of n.Then,
from(2.26) (with s
=Tn)
and(2.27),
we getMoreover
using again (2.26)
we getSince lim
O(x,,(.5,,))
= 0,by (2.28)
the left-hand side in(2.29) diverges,
soby
n +oo
(2.29)
weget
the conclusion..3. - Proof of Theorems
1.4,
1.6In order to prove Theorems 1.4 and 1.6 we shall
study
thepenalized
functional
Jc
definedby (2.9),
i.e.where
O(x) = O(x, 0) with 0 satisfying (iii)
of Definition1.7(9);
and,
REMARK 3.1.
By
standard methods we canmodify
thefunction Q
in orderto get another function of class
C2 (which
we continue to call4J) satisfying (2.23)
andIn all this section we shall
assume 0
tosatisfy
theseproperties.
Now consider
By (iv)
of Definition 1.2 and Remark 3.1 it follows thatAJL
iscomplete.
Now we shall prove a lemma which will
play a
fundamental role in theproof
of Theorems 1.4 and 1.6.LEMMA 3.2. Let U =
Mo
x R be a smooth static universe and letJe
be as in(3.1).
For every - E]0,1],
let Xs be a criticalpoint of Je
onS21
=Q1 (xo,
xl,.Mo).
Assume that
Then, if -
is smallenough,
Xg is a criticalpoint of
J onSZ1
andJ(x,) -~5 -it.
(9) Notice that we can choose such that ~(~,t)=,o(z) for all because of
(iii) of Definition 1.2.
PROOF. The
penalization
termVc
is zero whencfJ2(x)
> ~(see 3.2): then,
in order to get the
conclusion,
it will be sufficient to prove that there exists 6 > 0 suchthat,
for 6- smallenough,
Arguing by contradiction,
assume that there exists a sequence en ---+ 0 with then
corresponding
criticalpoints
Xên such thatwhere sn E
[0, 1]
] for all n. Let q > 0 such thatO(X2)
> ~ . ThenLet be the "first" instant such
that 0
q.Up
to consider asubsequence
we have1
Since
,Q
is bounded fromabove, (3.4) implies
that iso
bounded
(independently
ofn).
Then for nlarge enough
we have thatMoreover
by
virtue of theboundary conditions,
we have that Xén is bounded in(o, 1, .Mo) (and
therefore also inC(o,1, Mo»)
soby
virtue of Remark 3.1 thereexists ff
> 0 such thatSince XSn is bounded in
W 1 ~2
andA~~2
iscomplete
we haveand
where C
([0~],~/2)
is the(complete)
space of the continuous curves defined in[0,8r¡]
andtaking
values in~2. equipped
with the distance(2.3).
Nowconsider = s c
[0, 1],
definedby
Since
0
is bounded from ds .bounded,
soby (3.9)
and(3.12) Since (3
is bounded fromabove, f ds is bounded,
soby (3.9)
and(3.12)
we deduce that is bounded in
([0,~],R)
andtherefore, passing
to asubsequence,
we haveSince Xên is a critical
point
ofJên
we havep
ds-1
Moreover f - -I is bounded;
hence by (3.9)
and (3.11), eventually
pas-
sing
to asubsequence,
theright-hand
side in(3.14)
convergesuniformly
in[0, sq ] .
ThenNow,
from(3.12)
we haveso
by (3.9)
and(3.16)
we deduce thatMoreover from
(3.12)
we havethen
Since = to for all n, from
(3.17), (3.18), (3.9)
and(3.15)
weeasily
have
Moreover from
(3.12)
weget
thattên
is monotone.Then,
if for instance to tl,Now, by
Theorem2. l,
-1, n =ten)
solves theequation
Then, by (3.8),
weobtain,
for nsufficiently large,
so
by (3.15)
and(3.19)
we getThen -1,7
is ageodesic
in the interval[0,
In order toprove that ~~ is
time-like,
observethat, by
virtue of(3.4), (2.17)
and(2.18),
we
have,
for all s E[0,1]
] and for all n,Taking
in(3.23)
the limit in the interval[0,~],
we gettherefore 117 is time-like.
Summarizing,
independence
of q > 0, we have constructed asubsequence (of
7Enwhich converges, in a suitable interval
[0,817]
] c[0, 1],
to a time-likegeodesic
such that
and
Repeating
the aboveprocedure
incorrespondence
ofq/2,
we can select from(3.24)
asubsequence
which
approaches (in
a suitable interval[0,~/2]
with 81]/2 > a time-likegeodesic
such that
and
Following
thisprocedure
we can find ageodesic
for any(k G N). Taking
the limit when k goes to +oo, we obtain a time-like
geodesic
such that
and
Now,
because of
(3.6). Then, by
virtue of Remark3.1,
Since ~y is
time-like, (3.25)
and(3.26)
contradict property(v)
of Definition 1.2.Then
(3.5) (and
therefore Lemma3.2)
isproved..
LEMMA 3.3. Let - > 0. Then
for
any a E R the sublevelsare
complete
metric spaces. Moreoverif (.Mo, h)
isof
classC3, J, satisfies
thePalais-Smale
condition,
i.e. any sequence CSZ1
such thatand
contains a
subsequence
convergent(in W 1’2)
to Xê E XO,xl).
PROOF.
Clearly
the setsand
are bounded. Then
by
Lemma 2.3 we deduce that there exists ti > 0, such thatwhere
Now
A ,
with the metric~ ~, ~ ~R,
iscomplete.
Then also the closed subsetJa
of xo,
x 1 ) (see 3.29)
iscomplete.
Now assume(.M 0, h)
to be of classC3
in order to use the Nashembedding
theorem(see [13]).
Letc Ul satisfy (3.27)
and(3.28). Clearly
CJa
for some a E R, then from(3.29)
By
Nashembedding
theorem(see [13]), A~
can beisometrically
embedded into(with
Nsufficiently large) equipped
with the Euclidean metric.Then, using
Lemma
(2.1 )
in[4]
andarguing
as in theproof
of Theorem 1.1 in[5],
we candeduce that contains a
subsequence
convergent toWe are now
ready
to prove Theorems 1.4 and 1.6.PROOF OF THEOREM 1.4.
By
virtue of Theorem 2.1 we seeimmediately
thatcondition
(1.5)
is necessary toguarantee
the existence of a time-likegeodesic joining
zo and zl .In order to prove the
sufficiency,
observe thatby
theassumption (1.5)
there exists
- -
such that
Since
~(x(s))
> 0 for all s E[0, 1], by
the definition ofVe,
it is easy to see thatClearly
aminimizing
sequence(zn)
forJ,
is contained in some sublevelJ~ , which, by
Lemma3.3,
iscomplete. Then,
sinceJ,
isweakly
lower semiconti- nuous, the infimum ofJE
on 01 is attained at some xE, EJaE
C SZ1(Mo,
xo,xi).
Moreover
by (3.31)
we haveThen
by lemma
3.2 we deduce that Xe, for e smallenough,
is also a criticalpoint
for J onE21
andJ(zc)
0.Then, using
Theorem2.1,
Theorem 1.4 isproved.
PROOF OF THEOREM 1.6. Assume that
Mo
is not contractible in itself.Fadell and Husseini have
recently proved
that there exists a sequence of compact subsets ofS21
1 such that(see [7, Corollary 3.3]
and[8,
Remark2.23]).
Here denote theLjustemik-Schnirelman
category ofKm
inS21 (see
e.g.[17]),
i.e. the minimal number ofclosed,
contractible subsets ofS21 covering Km.
Now let mEN.By (3.32)
there exists acompact
subset Kc Q1
withClearly
thereexists A
such thatNow for every -
G]0,1]
] we setObviously
and
By
Lemma 3.3 and well known methods in criticalpoint theory (see
e.g.[15, 17])
we deduce that every cjc is a critical value for the functionalJ,.
Moreoverif Cig = cjc for some there are
infinitely
many criticalpoints
ofJ,
at the level Thereforefor
every eG]0,l],
there exist Xlg,..., Xmg distinct criticalpoints of J,,
withcritical values - 1.
Using
Lemma 3.2 we deducethat,
if - is smallenough,
Xlg,..., Xmg are also criticalpoints
of J with critical values -1.Then,
since m isarbitrary,
(1.6)
is obtainedby
virtue of Theorem 2.1..4. - Proof of Theorems
1.8,
1.9In order to prove Theorems 1.8 and 1.9 we shall
study
thepenalized
functional
Jc
definedby (2.9)
i.e.where x E =
and Q
satisfies(iii)
and(v)
of Definition 1.7.Now we shall prove some
preliminary
lemmas.LEMMA 4.1. Let ,G -
.M o
x II~ be a static Lorentzmanifold
with convexboundary
9L(see Definition 1.7).
For any 6 E]0, 1]
let Xe be a criticalpoint of JF
onK2’ (M o,
xo,x 1 )
and assume that there exists c 1 > 0 such thatThen
where co is
independent of
e.PROOF.
Arguing by contradiction,
assume that there exists a sequence of criticalpoints
of -0)
such thatwhere sn is a minimum
point
for the mapNow we set
where tEn
is definedby
By
Theorem2.1,
In is a criticalpoint
of thenwhere Then for all s E
[0, 1]
] we haveEventually passing
to asubsequence
let1
Since
~(~yn (o)) _ §(zo)
> 0,~(7n ( 1 )) _ ~(x 1 )
> 0, is boundedo
independently
of n, we haveo
1
Moreover, by (4.4)
and the boundness of thereis It
> 0 sucho
that
where 6 > 0 is introduced in
(1.8)
and(1.9).
Then from(4.6), (1.8)
and(1.9)
we deduce
that,
for nlarge enough
and for all s E[so -
~, so +Now
by (2.17)
and(2.18)
in Lemma 2.2 wehave,
for all s E[0,1],
Moreover
From
(4.9)
we deduce thatso
by (4.8)
and(4.2)
wehave,
for all s E[o,1 ],
Then, inserting (4.10)
in(4.7),
we getwhere c3, c4 are real constants
independent
of n. Sinceun(s)
6, if 6 is smallenough,
we obtain from(4.11),
Then,
since 0, we get,by
GronwallLemma,
thatun(s)
convergesuniformly
to zero and this contradicts theboundary
conditionsBy
the sameproof
of Lemma 3.3 we have thefollowing
LEMMA 4.2. Let ,G -
No
be a static Lorentzmanifold
and denoteby
9L the(topological) boundary of
L. Assume that there exists a map4J
ECo (L
Ua,G, R+)
nsatisfying (2.21), (2.22)
and(2.23).
Assumemoreover that
(ii)
and(iv) of Definition
1.7 hold. Thenfor
any a E 11~ thesublevels I I I
are
complete
metric spaces. Moreover,if (.Mo, h)
isof
classC3, Je satisfies
thePalais-Smale condition on xo,
xl).
LEMMA 4.3. Assume
(ii), (iii), (iv) of Definition
1.7. Assume moreover that( 1.8)
holds. Then,for
any c E R,PROOF. For j4 > 0, we set
Now,
if /~ > 0 is smallenough,
there is adiffeomorphism
which can be constructed
by
means of the solutions of theCauchy problem
where X
is a realC2
map on.Mo
such thatwith 0
62 61 6,
6being
introduced in(1.8).
Denoteby q = r~ (s, x),
s E Rthe solution of
(4.16). Then, by (1.8)
and standard arguments(see
e.g.[15, 17]),
it can be shown that there exist-S and u
> 0 such thatObviously
we can choose it > 0 so small thatLet us set
It is not difficult to see that
because q¡ is
Lipschitz
continuous andQ
is bounded. Now consider thepenalized
functional
1
where # is a
C2 positive
scalar field onMo
such thatClearly
for all x E we havethen
Therefore,
from(4.20)
and(4.21)
we deduce thatNow,
as in Lemma4.2,
thepenalized
functional J* satisfies the Palais- Smale condition onE21 (.M o,
xo,x 1 )
and its sublevels arecomplete. Then, arguing
as in the
proof
of Theorem 1.1 in[5],
weget
At this
point (4.22)
and(4.23)
and well knownproperties
of theLjustemik-
Schnirelman
category imply
thatso
Now we are
ready
to prove Theorems 1.8 and 1.9.PROOF OF THEOREM 1.8. Since the sublevels of
J,
arecomplete (see
Lemma
4.2)
it is not difficult toshow,
as in theproof
of Theorem 1.4that,
for all eE]0,1], J,
has a minimumpoint xe,
onClearly
there existsc 1
(independent
of~)
such thatThen, by
Lemma4.1,
we obtain that there exists co > 0 such thatMoreover, using again (4.24),
we deduce that zc is bounded in the normindependently
of e.Since, by
Lemma4.2,
J~1 iscomplete,
we obtain a sequence-
0)
such thatNow, by (4.25)
we can take the weak limit in theequation
and we get,
by (4.26),
that x is a criticalpoint
of J onK21(Mo,
xo,xl).
Then Theorem 1.8 isproved using
Theorem 2.1(with E’ = 0).
PROOF OF THEOREM 1.9. Let a E R and set
By
Lemma 4.3 there exists k =k(a)
E N such thatThen,
sinceJa
c we havefor all e >
0,
for all B 1 withk,
from which we deduce that
Since
Mo
is not contractible initself, (3.32) holds,
hence there exists a compact subset K ofQ~
such that k.Therefore,
for all ee]0,1],
we haveTherefore
by
Lemma 4.2 and well known arguments in criticalpoint theory (see
e.g.[15, 17]),
we deduce that every in(4.29)
is a critical value ofJ,,
so for all E
e]0,1],
there existsNow, by
Lemma4.1,
we have thatso,
following
the same arguments used inproving
Theorem1.8,
weget
the existence of a sequence ên - 0 with thecorresponding
criticalpoint
x,. such thatand x is a critical
point
of J on Q~.Now we want to show that
Since a is
arbitrary,
from(4.33)
weeasily
get the conclusionusing
Theorem2.1.
Clearly, (4.33)
is a consequence of(4.30)
if we show thatSince X£n is a critical