M. VAN DEN BERG E. BOLTHAUSEN
A
Estimates for the Dirichlet eigenfunctions near the boundary of an open, bounded set in euclidean space are obtained. It is assumed that the boundary satisfies a uniform capacitary density condition.
1. Introduction
Let D be an open, bounded set in euclidean spacem(ml 2, 3, …) with boundary
cD. Let k∆Dbe the Dirichlet laplacian for D. The spectrum ofk∆Dis discrete and consists of eigenvalues λ"λ#… with a corresponding orthonormal set of eigenfunctionsoφ",φ#,…q. The behaviour of the eigenfunctions near the boundary cD of D has been investigated by several authors under a variety of assumptions on the geometry of D [1–8, 11–16].
In this paper we obtain pointwise bounds on the eigenfunctions under the assumption that cD satisfies a uniform capacitary density condition. Denote by Cap(A) the newtonian capacity of a compact set A9 m (ml 3, 4, …) or the
logarithmic capacity of a compact set A9 #. For x ? mand r 0 we define
B(x ; r)l oy ? m:QykxQ rq, (1.1)
and for a non-empty set G9 m
diam(G)l supoQx"kx#Q:x"?G,x#?Gq. (1.2)
D 1.1. Let D 9 m(ml 2, 3, …) be an open set with boundary cD.
Then cD satisfies an α-uniform capacitary density condition if for some α ? (0, 1] Cap((cD)EB(x; r)) α Cap(B(x; r)), x ? cD, 0 r diam(D). (1.3) Condition (1.3) guarantees that all points ofcD are regular, and in particular that limx x
!φj(x)l 0 for all x!?cD. Definition 1.1 has been introduced in [10] in a study
of the partition function of the Dirichlet laplacian on open sets with a non-smooth or fractal boundary.
Let d : D,- (0, _) denote the distance function
d(x)l minoQxkyQ: y ? cDq, (1.4)
and let R be the inradius of D, defined by Rl max
x?D
d(x). (1.5)
The main results of this paper are the following.
Received 26 January 1996 ; revised 2 October 1996. 1991 Mathematics Subject Classification 35J25, 60J65.
Part of this research was funded by the British Council and the Swiss National Science Foundation.
T 1.2. Let D be an open, bounded set in #. Suppose cD satisfies (1.3) for someα 0. Then for j l 1, 2, … and all x ? D such that d(x) λ−"/#
j Qφj(x)Q
(
6λjlog(2\α#π) k1 log(d(x)λ"/# j )*
"/# . (1.6)T 1.3. Let D be an open, bounded set in m(ml 3, 4, …). Suppose cD
satisfies(1.3) for someα 0. Let j l 1, 2, … and suppose x ? D satisfies d(x)λ"/# j
0
α' 2"$1
"+γ(m−")/(m−#) . (1.7) Then Qφj(x)Q 2λm/% j (d(x)λ"j/#)("/#)(("/γ)+(m−")/(m−#)) −" , (1.8) where γ l 3−m−"α log(2(2\α)"/(m−#)). (1.9)The bounds in (1.6) and (1.8) are being complemented by the following well-known estimate [11, Lemma 3.1].
T 1.4. Let D be an open, bounded set in m(ml 2, 3,…). Then for j l 1, 2, …
and x? D
Qφj(x)Q λm/%
j . (1.10)
The bounds of Theorems 1.2 and 1.3 are in general not sharp. For example if D is open, bounded andcD is smooth then the eigenfunctions are comparable with d(x). If D is open, bounded and simply connected in# then it was shown by Ban4uelos [3, Corollary 2.3b] that φ" is comparable to the hyperbolic distance induced by the conformal map F from the unit disc onto D. By Koebe’s 1\4 theorem [17] one then obtains that
φ"(x)Cd(x)"/# (1.11)
for some constant C depending on D. We will use the ideas of [3] to prove (in Section 5) the following refinement of (1.11).
T 1.5. Let D be an open, simply connected set in # with olume QDQ. Then for jl 1, 2, …
Qφj(x)Q 2*/#π"/%jQDQ"/%R−#d(x)"/#. (1.12)
The following example (see [13, 4.6.7]) shows that Theorem 1.5 is sharp.
E 1.6. Let U 9 mbe the conical region in polar coordinates defined by
Ul o(r, ω): 0 r 1,ω ? Ωq, (1.13)
whereΩ is an open subset of the unit sphere Sm−". Then
}"(r,ω)0rβ(Ω), (1.14)
whereβ(Ω) is the positive solution of
β(βjmk2) l λ"(Ω), (1.15)
and whereλ"(Ω) is the first eigenvalue of the Laplace–Beltrami operator on Ω with Dirichlet conditions ofcΩ. In particular if m l 2 and
then
λ"(Ω!)l"% (1.17)
and by (1.15)
β(Ω!)l"#, (1.18)
which shows that the exponent in (1.12) cannot be improved.
The main idea of the proofs of Theorems 1.2 and 1.3 goes back to Brossard and Carmona [10] who obtained estimates for the Dirichlet heat kernel pD(x, x ; t) for x near D. We improve their lemma [10, Lemma 3.5] and its proof (see also [9]). In the proof of Theorem 1.3 we also require a refinement of Wiener’s test [18].
Let (B(s), s 0; x, x? m) be a brownian motion associated tok∆jc\ct. Let T D
denote the first exit time of the brownian motion from D :
TDl infos 0: B(s) ? cDq. (1.19)
For a compact set K we also define the first entry time
τKl infos 0: B(s) ? Kq. (1.20)
Then
x[TD t] l
&
D
pD(x, y ; t) dy. (1.21)
By the eigenfunction expansion of the heat kernel and by the semigroup property we have e−tλjφ# j(x) _ j=" e−tλjφ# j(x)l pD(x, x ; t)l
&
D p#D(x, y ; t\2) dy. (1.22) Since the Dirichlet heat kernel is monotone in DpD(x, y ; t\2) pm(x, y ; t\2) (2πt)−m/#. (1.23) Hence e−tλjφ# j(x) (2πt)−m/#
&
D pD(x, y ; t\2) dy l (2πt)−m/# x[TD t\2]. (1.24) The choice tl 2λ−" j (1.25) yields for ml 2, 3, … Qφj(x)Q e(4π)−m/% λm/% j (x[TD λ−j"])"/# λjm/%(x[TD λ−j"])"/#. (1.26)This proves Theorem 1.4 sincex[TD λ−"
j ] 1.
In Sections 2 and 3 we obtain the upper bounds for x[TD λ−"
j ] in the cases
ml 2 and m l 3, 4, … respectively. In the proof of Theorem 1.3 we use the following modification of Wiener’s test. See also [20, Theorem 4.7, p. 73] for related refinements of Wiener’s test.
T 1.7. Let D be an open, bounded set in m(ml 3, 4, …). Suppose cD
satisfies(1.3) for someα 0. If x ? D satisfies d(x) (α'\2"$) diam(D), then for any a?
9
2"$α', diam(D)\d(x)
:
(1.27)one has
x[τ(cD)EB(x;ad(x)) _] 1k2a−γ, (1.28)
The proof of Theorem 1.7 will be deferred to Section 4.
2. Proof of Theorem 1.2 Let ml 2 and define the Green function
g(x, y)lk(2π)−" log QxkyQ. (2.1)
The equilibrium measure on a compact set K9 # is the unique probability measure µKconcentrated on K for which
uK(x)l
&
K
g(x, y)µK(dy) (2.2)
is constant on the regular points of K. The function uKis the equilibrium potential of Kand its value R(K ) on the regular points of K is the Robin constant. The logarithmic capacity is defined by
Cap(K )l e−R(K). (2.3)
Then
Cap(K )l expk
(
infµ?P(K)
&
K&
Kg(x, y)µ(dx) µ(dy)
*
, (2.4)where P(K ) is the set of all probability measures supported by K. Moreover
Cap(B(x ; r))l r"/(#π) (2.5)
[18, Chapter 3, Proposition 4.11]. Define
Bm(x; r) l oy ? m:QykxQ rq. (2.6) Let a 4. Then x[TD t] x[τ(cD)EB(x;#d(x)) t] l x[τ(cD)EB(x;#d(x)) t, τ(cD)EB(x;#d(x)) TBm(x;ad(x))] jx[τ(cD)EB(x;#d(x)) t, τ(cD)EB(x;#d(x)) TBm(x;ad(x))] 1kx[τ(cD)EB(x;#d(x)) TBm(x;ad(x))]jx[TBm(x;ad(x)) t]. (2.7) Let H be an open half space in# containing Bm(x; ad(x)) such that cH is tangent to cBm(x; ad(x)). Then
x[TBm(x;ad(x)) t] x[TH t] l (πt)−"/#
&
[!,ad(x))
e−q#/(%t)dq ad(x) (πt)−"/#. (2.8)
For compact sets K"7K# we have by the variational formula (2.4)
Cap(K")Cap(K#). (2.9)
Let x!?cD be such that d(x)lQxkx!Q. Then B(x;2d(x)):B(x!;d(x)), and by (1.3), (2.5) and (2.9)
Cap((cD)EB(x; 2d(x))) Cap((cD)EB(x!;d(x)))
α Cap(B(x!;d(x)))lα(d(x))"/(#π). (2.10)
By (2.3) and (2.10)
By (2.3) and (2.9) we have for K"7K# R(K")R(K#). (2.12) Hence R((cD)EB(x; 2d(x))) R(B(x; 2d(x))) k(2π)−" log(2d(x)). (2.13) Moreover, by (2.1) and (2.2) supou(cD)EB(x;#d(x))( y) : y? cB(x; ad(x))q k(2π)−" log((ak2) d(x))
&
(cD)EB(x;#d(x)) µ(cD)EB(x;#d(x))(dy) lk(2π)−" log((ak2) d(x)). (2.14)Following the proof of [11, Lemma 3.5] we define for r 0
m(r)lk(2π)−" log((ak2) r), (2.15)
and h :# ,- by
h( y)l (R((cD)EB(x; 2d(x)))km(d(x)))−"(u
(cD)EB(x;#d(x))( y)km(d(x))). (2.16) Now h is superharmonic, harmonic outside (cD)EB(x; 2d(x)), equal to one on (cD)EB(x; 2d(x)), and by (2.14) negative on cB(x; ad(x)). Hence
x[τ(cD)EB(x;#d(x)) TBm(x;ad(x))] h(x) l u(cD)EB(x;#d(x))(x)km(d(x)) R((cD)EB(x; 2d(x)))km(d(x)). (2.17) But u(cD)EB(x;#d(x))(x)k 1 2πlog(2d(x)), (2.18) so that by (2.11), (2.15), (2.17) and (2.18) x[τ(cD)EB(x;#d(x)) TBm(x;ad(x))] log(ak2)klog 2 log(ak2)klog α#π. (2.19) Hence by (2.7), (2.8) and (2.19) x[TD λ−" j ] log(2\α#π) log((ak2)\α#π)jπ−"/#ad(x) λ"j/#. (2.20)
We make the following choice for a :
ak2 l 2 λ"/# j d(x)
0
1jlog0
1 λ"/# j d(x)11
−" . (2.21) Let zl λ−"/#j d(x)−". Then d(x) λ−j"/#implies z 1, and z 1jlog(z) implies a 4.
By (2.20) and (2.21) x[TD λ−" j ]
0
log 2 α#π10
log 1 α#πjlog(2z)klog(1jlog z)1
−" j2π−"/#z−"j2π−"/#(1jlog z)−". (2.22) L 2.1. For z 1Proof. Inequality (2.23) is equivalent to
4z (1jlog z)#. (2.24)
But (2.24) holds for zl 1. Moreover for z 1
4 2(1jlog z)\z. (2.25)
Integration of (2.25) over [1, z] yields (2.24) and hence (2.23). For z 1, 1\z (log 1\z)−". Hence by Lemma 2.1 and (2.22)
x[TD λ−" j ]
0
2 log0
2 α#π1
j 4 π"/#1
(log z)−" 60
log0
2 α#π11
(log z)−". (2.26)Theorem 1.2 follows from (1.26), (2.26) and by the definition of z. 3. Proof of Theorem 1.3
We define for ml 3, 4, … the Green function on mby
g(x, y)l 1
c(m)QxkyQ#−m, (3.1)
where
c(m)l 4πm/#(Γ((mk2)\2))−". (3.2)
For a compact set K9 mthe equilibrium measure µ
Kis the unique non-negative
measure on K satisfying
x[τK _] l
&
g(x, y)µK(dy). (3.3)The newtonian capacity of K is defined by
Cap(K )l µK(K ). (3.4)
The capacity of a ball is
Cap(B(0 ; r))l c(m) rm−#. (3.5)
Again, there is a variational description Cap(K )l
(
infµ?P(K)
&&
g(x, y)µ(dx) µ(dy)
*
−", (3.6) where P(K ) is the set of all probability measures supported by K. If K",K# are compact sets with K"7K# then Cap(K")Cap(K#). For these facts, see for example [18, Chapter 3].To prove Theorem 1.3 we adapt [10, Lemma 3.5]. Let b a 1. Then by the strong Markov property
x[TD t] 1kx[τ(cD)EB(x;ad(x)) t]
1kx[τ(cD)EB(x;ad(x)) TBm(x;bd(x))]jx[TBm(x;bd(x)) t] 1kx[τ(cD)EB(x;ad(x)) _]
jx[B(T
To estimate the third term in the right-hand side of (3.7) we let y be such that QykxQ l bd(x). Then y[τ(cD)EB(x;ad(x))] y[τB(x;ad(x)) _] l
0
a b1
m−# . (3.8)The fourth term in (3.7) is again estimated by (2.8). Hence x[TD t] 1kx[τ(cD)EB(x;ad(x)) _]j
0
a b
1
m−#
jbd(x) (πt)−"/#. (3.9)
Choose a and b as follows :
al Ad(x)−β", (3.10)
bl B(d(x))β#−", (3.11)
whereβ", β#, A and B are the solutions of
β"γl(1kβ"kβ#)(mk2)lβ#, (3.12) A−γl
0
A B1
m−# l Bλ"/# j . (3.13) From (3.12) we obtain β#lβ"γl0
1γj mk1 mk21
−" , (3.14)and from (3.13) we obtain Bλ"/#
j l A−γl λ("/#)(("/γ)+(m−")/(m−#))
−"
j . (3.15)
If we can show that (1.7) implies (1.27) and the requirement b a, then by (3.9)–(3.11) and Theorem 1.7 x[TD λ−" j ] 2A−γd(x)β"γj
0
A B1
m−# d(x)("−β"−β#)(m−#) jBd(x)β#λ"/# j . (3.16)Substitution of the values ofβ", β#, A and B respectively in (3.16) gives x[TD λ−"
j ] 4A−γd(x)β"γl 4(d(x) λ"j/#)(("/γ)+(m−")/(m−#))
−"
. (3.17)
Estimate (1.8) follows from (1.26) and (3.17).
Note that b a is (by (3.10), (3.11)) equivalent to showing that B
A d(x)"−
β"−β#. (3.18)
It follows from (3.14) that
0 β"jβ#l 1jγ 1jγmk1
mk2
1. (3.19)
Since (1.7) implies d(x) λ−"/#
j it is (by (3.19)) sufficient to check that (3.18) holds for
d(x)l λ−"/# j , that is, B A λ−("/#)("− β"−β#) j . (3.20)
We see by (3.15) and (3.19) that (3.20) holds with the equality sign.
It remains to check the validity of (1.27). Since D is bounded, D is contained in a hypercube of sidelength diam(D). By monotonicity of the Dirichlet eigenvalues [19, Chapter XIII.15, Proposition 4(a)]
λj λ"l(diam(D))mπ# # (diam(D))1 #. (3.21) Hence the first inequality in (1.27) is satisfied if
1 λ"/# j d(x) a. (3.22) By (3.10), (3.14) and (3.15) al (λ"/# j d(x))−("/γ)(("/γ)+(m−")/(m−#)) −" . (3.23) Hence (3.22) is satisfied if (d(x)λ"/# j )"−("/γ)(("/γ)+(m−")/(m−#)) −" 1. (3.24)
This is indeed the case because (1.7) implies d(x)λ"/#
j 1 and 1k1 γ
0
1 γj mk1 mk21
−" 0. (3.25)The second inequality in (1.27) follows directly from (3.23) and (1.7). 4. Proof of Theorem 1.7
For s r 0 we define the annulus
B(x ; r, s)l B(x; s)BBm(x; r), (4.1)
and the set
cDi(x)l (cD)EB(x; bi, bi+"), (4.2)
where b 1 will be specified later. Let Ai(x) be the event Ai(x)l oτcD
i(x) _q. (4.3)
Define
Nl maxok ? : bk+" a(d(x)) d(x)q. (4.4)
Then for any n N
oτ(cD)EB(x;a(d(x))d(x)) _q : N i=n Ai(x). (4.5) If bi+" d(x) then A i(x)l 6. We will choose nl minok ? : bk 2d(x)q. (4.6)
We choose a ‘ spacing ’ s? +, s 2 (to be specified later) and use
N i=n Ai(x): [(N−n)/s] j=! An+js(x), (4.7) to obtain x[τ(cD)EB(x;a(d(x))d(x)) _] 1kx
9
[(N−n)/s] j=! Ac n+js(x):
. (4.8)For technical reasons we replace Aj(x) by A`j(x) which are defined by A`j(x)l oτcD j(x) τB(x;bj+s,_)q. (4.9) Note that x[A`j(x)BAj(x)]l 0, (4.10) and therefore x[τ(cD)EB(x;a(d(x))d(x)) _] 1kx
9
[(N−n)/s] j=! A`c n+js(x):
. (4.11)Next we derive a lower bound fory(A`j(x)) for QxkyQ bj.
L 4.1. Let
bl 2
0
2 α1
"/(m−#)
. (4.12)
Then for j n satisfying b(bjjd(x)) 2 diam(D) and any y satisfying QykxQ bj
y[A`j(x)] 2:3−mα. (4.13)
Proof. Let x!?cD be such that d(x)lQxkx!Q. One easily checks that if bj 2d(x)
cDj(x): (cD)EB(x!;r,br\2), (4.14)
where
rl bjjd(x). (4.15)
From this we obtain, by the monotonicity and subadditivity of the newtonian capacity,
Cap(cDj(x)) Cap((cD)EB(x!;r,br\2))
Cap((cD)EB(x!;br\2))kCap(B(x!;r))
α Cap(B(x!;br\2))kCap(B(x!;r)), (4.16)
since br\2 diam(D) by assumption. By the choice of b and by (3.5)
Cap(cDj(x)) αc(m) (br\2)m−#kc(m) rm−# l c(m) rm−# c(m) bj(m−#). (4.17)
For z? cDj(x) andQykxQ bjwe have since b 2
QykzQ QzkxQjQxkyQ bj+"jbj 3bj+"\2. (4.18) Hence by (4.17) and (4.18) y[Aj(x)]l
&
cDj(x) c(m)−" QykzQm−# µcDj(x)(dz) c(m)−"(3\2)#−mb(#−m)(j+")Cap(cD j(x)) c(m)−"(3\2)#−mb(#−m)(j+")c(m) bj(m−#) l (3b\2)#−m. (4.19) Furthermore y[A`j(x)] y[Aj(x)]kw[τB(x;bj+") _], (4.20) whereQwkxQ l bj+s. Hence y[A`j(x)] (3b\2)#−mkb(m−#)("−s). (4.21)From now on we choose sl 3. Then by (4.21) and (4.12) y[A`j(x)] 3#−mα 2kα#2#("−m) 2:3−mα. (4.22) Let j σ(B(t): t τB(x;bj,_)). (4.23)
By definition of A`j(x), we have that A`j(x) is j+
$-measurable. Let x be such that
Nkn 3. (4.24)
Then for any k? o1, 2, …, [(Nkn)\3]q we have x
9
k j=! A`c n+$j(x):
l x9
x[A`cn+$k(x)Q n+$k] ; k−" j=! A`c n+$j(x):
l x9
B(τB(x;bn+$k,_))(A` c n+$k) ; k−" j=! A`c n+$j(x):
(1k2:3−mα) x9
k−" j=! A`c n+$j(x):
. (4.25)From this we finally obtain x
9
[(N−n)/ $] j=! A`c n+$j(x):
(1k2:3−mα)[(N−n)/$] exp ko[(Nkn)\3] 2:3−mαq. (4.26) Since Nkn 3, [(Nkn)\3] (Nkn)\6, (4.27) and x9
[(N−n)/ $] j=! A`c n+$j(x):
exp ko(Nkn) 3−m−"αq. (4.28)By the choice of N and n we have
bN+# a(d(x)) d(x) bN+", (4.29) bn−" 2d(x) bn, (4.30) and hence bN−na(d(x)) 2b$ . (4.31) By (4.28) and (4.31) we obtain x
9
[(N−n)/ $] j=! A`c n+$j(x):
0
a(d(x)) 2b$1
−α$−m−"/logbl a(d(x))−γeα$−m+α$−m−"(log#)/logb
a(d(x))−γe%α$−m−" 2a(d(x))−γ, (4.32)
by definition ofγ and the fact that b 2, m 3 and α 1. Estimate (1.28) follows from (4.11) and (4.32) provided x? D is such that (i) b(bjjd(x)) 2 diam(D) for
jl n, …, N, (ii) (4.24) holds. But (i) is satisfied if
bN+"j2bN−n+"d(x) 2 diam(D), (4.33)
since b 2. But bN+" a(d(x)) d(x) and 2bN−n+" a(d(x)). So (4.33) and hence (i)
are clearly satisfied if
For (4.24) to hold we have to have bN+#−(n−") b'. This is the case by (4.29) and
(4.30) if
a(d(x)) 2b'. (4.35)
But b 4\α since 0 α 1 and ml 3, 4, …. Hence (4.35) and (4.24) hold if a(d(x))2"$
α'. (4.36)
This completes the proof of Theorem 1.7.
5. Proof of Theorem 1.5 Let GD(:, :) be the Green function for k∆D. Then
GD(x, y)l
&
_ !pD(x, y ; t) dt, (5.1)
and any Dirichlet eigenfunction ofk∆Dsatisfies }j(x)l λj
&
D
GD(x, y)}j( y) dy. (5.2)
By the Cauchy–Schwarz inequality Q}j(x)Q λj
(&
D G#D(x, y) dy*
"/# (5.3) since R}jR#l1. L 5.1. For j l 1, 2, … λj 8πjR−#. (5.4)Proof. By definition of R, D contains an open ball with radius R. Hence D contains an open square with sidelength RN2. Since the Dirichlet eigenvalues are monotone in D,λjis bounded from above by the jth eigenvalue of this square. The eigenvalues for this square are given by
λk,ll π#(k#jl#)\(2R#), k ? +, l? +. (5.5)
By definition
jl Fo(k, l): k#jl# 2λjR#\π#q. (5.6)
Suppose j 4. Then k#jl# 8 since j l 1 corresponds to (k, l) l (1, 1) and j l 2, 3 corresponds to (k, l )l (2, 1) and (k, l) l (1, 2). Hence
λj4R#π#, j 4. (5.7)
But the right-hand side of (5.6) is equal to the number of lattice points in the first quadrant of the disc with radius R(2λj\π#)"/#. Hence by (5.6) and (5.7) we have
for j 4
jπ
4((2λjR#\π#)"/#k2"/#)# λj
R#
8π . (5.8)
Let F be the conformal map from the unit disc onto D with F(0)l x. Then by the results of [3,§1]
GD(x, y)l 1
2πlog coth(ρD(x, y)), (5.9)
where )D(x, y)l inf γ
&
" ! Qγh(t)Q QFh(0)Qdt, (5.10)and where the infimum is taken over all rectifiable curves γ in D with γ(0) l x, γ(1) l y, and where Fh(0) is evaluated at γ(t). By Koebe’s 1\4 theorem
d(γ(t)) QFh(0)Q 4d(γ(t)). (5.11)
Without loss of generality we may assume thatγ has a parametrisation with constant speed c. Then for any suchγ we have
d(γ(t)) d(x)jtc. (5.12) By (5.10)–(5.12) )D(x, y)1 4
&
" ! c d(x)jtcdtl 1 4log0
1j c d(x)1
. (5.13)Since c QxkyQ we have by (5.9) and (5.13) GD(x, y) 1
2πlog
(d(x)jQxkyQ)"/#jd(x)"/#
(d(x)jQxkyQ)"/#kd(x)"/#. (5.14)
We note that the right-hand side of (5.14) is positive and strictly decreasing inQxkyQ for x fixed. Hence the square of the right-hand side of (5.14) is strictly decreasing in QxkyQ for x fixed. Let R! be defined by
πR#!lQDQ. (5.15) By spherical-symmetric rearrangement
&
D G#D(x, y) dy 1 2π&
R! ! rdr0
log(d(x)jr)"/#jd(x)"/# (d(x)jr)"/#kd(x)"/#1
# l2d(x)#π&
_ d(x)/R! dr r$(log((1jr)"/#jr"/#))# 8d(x) R!π , (5.16) since log((1jr)"/#jr"/#) 2r"/#. The theorem follows from (5.3), (5.4) and (5.16).C 5.2. Let D be open, simply connected in # with finite olume QDQ. Then x[TD] 2$/#π−$/%QDQ$/%d(x)"/#. (5.17)
Proof. By the Cauchy–Schwarz inequality
x[TD]l
&
D
GD(x, y) dy QDQ"/#
(&
D
G#D(x, y) dy
*
"/# (5.18)Acknowledgements. The first author wishes to thank R. Ban4 uelos for helpful discussions.
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