R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
V. V. R UMJANTSEV On stability problem of a top
Rendiconti del Seminario Matematico della Università di Padova, tome 68 (1982), p. 119-128
<http://www.numdam.org/item?id=RSMUP_1982__68__119_0>
© Rendiconti del Seminario Matematico della Università di Padova, 1982, tous droits réservés.
L’accès aux archives de la revue « Rendiconti del Seminario Matematico della Università di Padova » (http://rendiconti.math.unipd.it/) implique l’accord avec les conditions générales d’utilisation (http://www.numdam.org/conditions).
Toute utilisation commerciale ou impression systématique est constitutive d’une infraction pénale. Toute copie ou impression de ce fichier doit conte- nir la présente mention de copyright.
Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
http://www.numdam.org/
On Stability Problem of
aTop.
V. V. RUMJANTSEV
(*)
This paper deals with the
stability
of aheavy gyrostate [1]
on ahorizontal
plane.
Thegyrostate
is considered as arigid body
with arotor
rotating freely (without friction)
about an axisinvariably
con-nected with the
body leaning
on aplane by
a convexsurface,
i.e. thetop
in a broad sence of this word. For mechanician thetop
is asymple
and
principal object
ofstudy [2] attracting investigators’
attention.1. Let
$ql
be the fixed coordinatesystem
with theorigin
in somepoint
of a horizontalplane
andvertically
up directedaxis I
with unitvector y;
OXIX2Xa
is the coordinatesystem rigidly
connected with thebody
with theorigin
in centre of mass ofgyrostate
and axis ~3 coincided with one of itsprincipal
central axes of inertia. Two anotheraxes x1 and x, are
parallel
to the directions of the main curvatures of thebody
surface for thepoint P
of intersection of thenegative
semi-axis x3 with this surface
tangent plane
to which in thepoint
P is sup-posed perpendicular
to the axis ~3.It is
possible
to write theequations
of motion of thetop,
for ex-ample,
in the form of the laws of a momentum and ofangular
momen-tum and also of a
constancy
of the vector y.These
equations
contain the reaction of aplane
R forexpression
of which it is necessary to make a
supposition
about the character ofan interaction of the
top
with theplane.
In the case of an idealsmooth
plane
(*)
Indirizzo dell’A.:Vyc.
Centr., ul. Vavilova 40, Moscow 117333, U.S.S.R.In the case of an ideal
rough plane
thevelocity
of the contactpoint
of thetop
with theplane
Here v and w are the vectors of the
velocity
of the centre of mass and ofmomentary body angular velocity,
r is the radius-vector of the contactpoint.
In the case of a
plane
withsliding
frictionindependently
from thehypothesis
on character ofsliding
friction.For all these cases the mechanical energy of the
top
does not increasebeing
constant in the first and second cases. Here 0 is the central tensor of inertia of the transformedbody [3],.M’
is the mass of thetop, g
isthe
gravitational acceleration, lo
= - r ~ y is the vertical coordinate of the centre of mass. The relation between the vectors r and y definesby
theequation
of thebody surface,
so[4]
Here li
are the main radii of curvature of thebody
surface in thepoint
is the distance between thepoints
0 andP,
Wi are theprojections
of the vector on axes r;(i
=1, 2, 3),
dots denote terms of morehigh
order. It follows from the(1.5)
thatAccordingly Lyapunov’s stability
theorem from the(1.4)
and(1.6)
we
get
the sufficient conditions ofstability
121
on the
equilibrium
of aheavy gyrostate
on a horizontal
plane
withrespect
to the values v, ca, y.The
inequalities (1.7)
are also the necessarystability
conditions ofequilibrium
of thetop
with notrotating
rotor[4].
In the case
(1.1)
theequations
of motion have theintegral
of theangular
momentumand also the
integral
ofconstancy
of theprojection
ofmomentary angular velocity
if the
gyrostate
hasdynamical
andgeometrical symmetry
about theaxis x3 and
gyrostatic
moment k = const isparallel
to this axis(k1= k2= 0, k3 = k).
If the surface of
axisymmetrical gyrostate
in theneighbourhood
of the
point P
isspherical
with the centre on the axis ~3 then the equa- tions of motion in thegeneral
case(1.3)
ofsliding
friction have theintegral [5]
In all these cases the
equations
of motion have the solutiondescribing
thepermanent
rotation of thegyrostate
about vertical axis ~3 witharbitrary angular velocity
w, if thegyrostatic
moment kis
parallel
to this axis(k1 = k2 = 0).
If the k is notparallel
to theaxis ~3 then the solution
(1.12)
ispossible only
for w = 0.On the motion
(1.12)
thetop
leans on aplane by
thepoint
x2 =
0,
x3 = -1)
and the reaction R = gy.Consider the
stability
of the solution(1.12) using
theintegral
relation
(1.4)
and firstintegrals (1.9)-(1.11)
for construction theLya-
punov’s
function.2. We start from
simplest
case(1.1)
of an ideal smouthplane.
In this case
only
vertical force(R - g)y
acts on thegyrostate,
sothe
projection
of thevelocity
of the mass centre on a horizontalplane
remaines constant. Without restriction of
generality
we shall considerthis
projection
beequal
to zero, i.e. the mass centre ofgyrostate
movesonly
on immobile vertical.At first consider the case when the axis of rotor is
parallel
to theaxis xl
(kl = k, k2 = k3 = 0)
and the solution(1.12)
ispossible only
for w = 0.
Using
theintegrals
of energy(1.4)
and ofangular
mo-mentum
(1.9)
we constractLyapunov’s
functionHere are moments of inertia of the
gyrostate
about the axes z,(i
=2, 3 ) , A1-moment
of inertia of thebody
about axis xlF-centrifugal
moment of inertia for axes x, and
X2’ Â
= const.Obviously,
= 0.The conditions for the
positive
definiteness of the function(2.1)
are reduced to the
inequalities
which
accordingly
toLyapunov’s
theorem are sufficientstability
con-ditions of the
equilibrium (1.8)
ofgyrostate
withgyrostatic
momentparallel
to the axis xl withrespect
to variables Wi’ yi(i
=1, 2, 3)
andIt is
possible
to show[4]
that theequilibrium
is unstable foropposite sign
in one ofthe inequalities (2.2).
The conditions
(2.2)
contain asparticular
cases the conditions ofstability [5]
of Gervat’s gyroscop with flat rectilinearsupport (l2
=00, Il
=0)
and with flat circularsupport
ofradius p (l2
=e, 1
=0).
It follows from the conditions
(2.2)
that unstable forl1
Iposition
of the
equilibrium
of thetop
is stabilizedby
rotation of rotor withgyroscopic
moment ksatisfying
to the second condition of the ine-qualities (2.2).
Consider the
stability
of thegyrostate
with thedynamical
andgeometrical symmetry
about the axis ~3 when =Iz,
k~ = k2 = 0.
123
We shall define the orientation of the
gyrostate
about its centreof mass
by
Euler’sangles 0,
and theposition
of a rotor with theaxis
parallel
to the axis x, about thebody by
anangle
a. It iseasily
to see
[4]
thatcoordinates y, p
and Lx arecyclic,
and the firstintegrals
of
Lagrange’s equations
correspond
to them.Eliminating
thevariables and ~
fromintegral
energy(1.4),
rep- resent it in the formis the transformed
potential energy; ,
=f ( 8 )
is the functiondefining by
theshape
of the surface of rotation about the axis x,bounding
thebody, .A.1
is the centralequatorial
moment of inertia ofgyrostat, As
is the axial moment of inertia of thebody,
are constants of the
integration.
The
equation
defines for
6 ~ 0, ~
thetwo-parametrical family
of solutionsdescribing
theregular precessions
of aheavy gyrostate
on aplane.
These motions are stable if
and are unstable if the
inequality (2.6)
has theopposite sign [6].
In the case 0=0 from
(2.3)
we have H and the function(2.5)
has the next formThe
equation W’(0)
= 0 holds for any value H and 8 = 0 iff’(0)
=0;
this solution is similar to the solution
(1.12).
It is stable ifand unstable if the
inequality (2.7)
has theopposite sign [4].
In the case
W"(0)
= 0 the solution ofstability problem
of mo-tion
(1.12) depends
on members of morehigh
order in theexpansion
of the in Macloren’s serie. So if
f "’ ( o ) ~ 0
then the motion isunstable;
ifthen the motion
(1.12)
is stable. Thereforeis necessary and sufficient
stability
condition of motion(1.12)
of axis-symmetrical gyrostate
on aplane
if the(2.8)
holds. Forexample,
in the case of a
gyrostate leaning
on aplane by
a needle( Z1= 0)
whenf (0)
= l cos 0 the conditions(2.8)
hold and theinequality (2.9)
takesthe form
The condition
(2.10)
has the form of necessary and sufficientstability
condition of rotation of aheavy gyrostate
with a fixedpoint
about vertical in which however
Ai
denotes the moment of inertia fora fixed
point
whereas in the(2.10)
this value denotes the moment of inertia for the centre of mass. The last is less than the firstby M12,
so
stability
of agyrostate
on aplane
isrequired (with
anotherequale
conditions)
smaller value of cinetic moment H thanstability
of a125
gyrostate
with a fixedpoint.
This difference is due to the fact that themass centre of
gyrostate
on aplane
rather then thepoint
ofsupport plays
the role of a «fixed »point
for thesteady
motion. In the caseof
equilibrium
ofgyrostate (m
=0)
on aplane
the condition(2.9)
takes the form of the
inequality
Comparing
the(2.11)
with the(2.2)
we see that for stabilization of unstableequilibrium
ofgyrostate
in the casek2 = 0, k3 = k
thevalue k must be twice as much than in the case
kl = k, k2 = k, = o, provided
the value.A1
in(2.11)
isequal
to the valueA3
in(2.2).
Note that formulae
(2.3)-(2.11)
remain correct in the case of va-riable
angular velocity
of rotor[4].
3. Consider the rotation
(1.12)
ofnonsymmetric gyrostate
withconstant
gyrostatic
moment k(k1= k2 = 0, k)
on an idealrough plane (1.2). Putting
co+ ~,
y3 =1- r~
it ispossible
to wrotethe
equations
ofperturbed
motion in the form[4].
Here A =
M12,
1 B =Å2 +
.lVh2 and nonlinear membersX, (s
=1, ..., 4)
vanish for ya = 0(i
=1, 2).
The characteristic
equation
for linearizedequations (3.1)
has two zero-roots and four roots with
negative
realpart
ifHere
Accordingly Lyapunov-Malkin’s
theorem[7]
the motion(1.12)
isstable with
respect
to the variables(~==1,2,3)
and asymp- totic stable withrespect
to the variables WB(s = 1, 2),
yzprovided
theconditions
(3.3).
The motion(1.12)
will be unstableaccordingly Lya- punov’s
theorem oninstability by
firstapproximation
whenextremely
one of the
unequalities (3.3)
has theopposite sign.
It has
place partial asymptotic stability
under the conditions(3.3) though
thesystem
is conservative one and there are no external dissi-pative
forces. Partialasymptotic stability
is causedby
nonholonomic constraint(1.2);
thegyrostate
issubjected (in
firstapproximation) by potential, dissipative-accelerating
andgyroscopic
forces(see (3.1));
the
stability depends
onspin
direction: the first from theinequalities (3.3) (see (3.4))
holdsonly
iftwo another
inequalities (3.3)
restrict the values co and k in the stable motion.It is
interesting
tonote,
that the motion(1.12)
with very smallvelocity
oi = s and k = 0 will unstable even in the case of staticstability,
y when the conditions(1.7)
hold: the third from the condi- tions(3.3)
will have theopposite sign. Instability
isexplained by
theaction of
accelerating forces; gyroscopic
stabilization has noplace
when
gyroscopic
forces are weak.127
If
extremely
one from the conditionsholds then a, = 0 and the conditions
(3.3)
have noplace; partical asymptotic stability
is notpossible
in this case. The necessarysimple stability
conditions are reduced to theinequalities
4. Consider at last the
stability
of the rotation(1.12) of axisym-
metrical
gyrostate leaning
on aplane
with friction(1.3) by spherical support
ofradius e
with the centre on the axis x3. The coordinate of thesphere
centre isequal to e - I
and coordinates ofsphere
contactpoint
with theplane
and thehigh
of centre of mass areUnder +
~, Ya = 1- ’YJ
theenergetic
correlation(1.4)
and theintegrals (1.11)
andy 2 =
1 take the formConsider the function
where
It is
easily
to see that the function(4.1)
will bepositive
definitewhen
[5]
and Therefore the
(4.2)
is the sufficientstability
conditionof the motion of an
axisymmetrical gyrostate
withspherical support
for every law of friction of form
(1.3)
withrespect
to the variables v, m, y.Similarly [2]
it ispossible
to show that this condition is neces-sary for
stability
in the case of viscous friction. So in the last case theinequality (4.2)
is the necessary and sufficientstability
condition withrespect
to all variables andasymptotic stability
condition withrespect
to the variables Ws
( s
=1, 2)
because all conditionsLyapunov-
Malkin’s theorem hold.
In the case k =
0,
H = theinequality (4.2)
becomes thestability
condition of the rotation alonerigid body. Comparing
itwith
(4.2)
we conclude that it ispossible
to make the motion(1.12)
of the
gyrostate
forgiven
value a) =1= 0 to be stable or unstableby wishing
under proper choice of the value and thesign
of thegyrostatic
moment k
independently
fromstability
orinstability
of alonerigid body.
BIBLIOGRAPHY
[1] V. V. RUMJANTSEV,
Dynamics
andStability of Rigid
Bodies, C.I.M.E.I
Cycle
1971, Bressanone. Coordinatore: G. Grioli,Stereodynamics,
Edi-zioni Cremonese, Roma (1972).
[2] P. CONTENSOU, The Connection Between
Sliding
andCurling
Friction inthe
Top
Problem,Kreiselprobleme, Herausgeber:
H.Ziegler,
Berlin-Göttingen-Heidelberg, Springer (1969).
[3] N. E. ZHUKOVSKY, On Motion
of Rigid Body
with Cavities Filledof
Homo-geneous
Droppinv Liquide,
C.W., v. II, Gostechizdat, Moscow(1948).
[4]
V. V. RUMJANTSEV, Onstability of
rotationof heavy
vyrostate on a horizontalplane,
Mech. Solid., no. 4(1980).
[5] V. V. RUMJANTSEV, On
stability of
motionof
some gyrostates,Appl.
Math.and Mech., no. 4
(1961).
[6]
A. V. KARAPETYAN, Onstability of steady
motionsof heavy rigid body
onideal smouth horizontal
plane, Appl.
math. and mech., no. 3(1981).
[7] I. G. MALKIN, Motion
Stability Theory,
Nauka, Moscow(1966).
Manoscritto