R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
B. F ELZENSZWALB
P. M ISSO
Rings S-radical over PI-subrings
Rendiconti del Seminario Matematico della Università di Padova, tome 73 (1985), p. 55-61
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Rings PI-Subrings.
B. FELZENSZWALB - P. MISSO
(*)
1. A
ring
.R is said to be radical over asubring
Aif,
for every there exists aninteger n(x) ~ 1
such that E .A. One of the resultsconcerning
the structure of radical extensions is a result due to Herstein and Rowen. In[5] they proved:
if .l~ is aring
with nonil
right ideals,
radical over asubring A
and A satisfies apolynomial identity,
y then .R satisfies the same multilinear identities. In[6]
Zel-manov showed that the conclusion still holds if we
merely
assumethat .R is without nil ideals.
In this paper we shall be concerned with the same
problem
oflifting polynomial
identities in thesetting
ofrings
with involution.If .R is a
ring
with involution and S the set ofsymmetric
elements of.R,
we say that .R is S-radical over asubring
Aif, given s
eS,
thenA for some
integer n(s) ~
1.S-radical extensions were studied in
[1]
where it was shown thatif I~ is a division
ring
S-radical over a propersubring
Athen,
for allx xx~ is central in Rand so, R is at most 4-dimensional over its center.
Here we shall prove the
following:
let .R be aprime ring
with nonil
right
ideals and char .R =1=2,
3. If 1~ is S-radical over asubring
A and A satisfies a
polynomial identity
ofdegree d,
then .R satisfiesa
polynomial identity (PI)
andPI-deg (R) c d.
We remark that if every element in S is
nilpotent
then .R contains(*)
Indirizzodegli
AA.: B. FELZENSZWALB : Instituto de Matematica, Universidade Federal do Rio de Janeiro, C.P. 68530, 21944 Rio de Janeiro, Brazil; P. Mtsso : Istituto di Matematica, Università di Palermo, Via Archi- rafi 34, 90123 Palermo,Italy.
56
a nonzero nil
right ideal;
however it is not known if .R contains a nonzero nil ideal(this
is tied in with aconjecture
due to McCrimmon[4]).
Throughout
this paper .R will denote aring
with involution*,
Z itscenter and ~’ =
(ce
E .R : x = andjE~={~e~:~==2013 ce*),
the set ofsymmetric
and skew elementsrespectively. Finally
N= E.R~
will denote the set of norms of .R.
If .R is a
prime ring satisfying
apolynomial identity,
then itsring
of central
quotients,
yQ,
is a centralsimple algebra
of dimension n2over its center and we define
PI-deg (R)
== n.2. We first prove a result of
independent
interest which will be very useful inproving
the maintheorem, namely:
THEOREM 1. Let R be a
ring
with no nonzero nilright
ideals. If .Ris S-radical over a division
ring A, A #
R then either1 ) .R
is a direct sum of a divisionring
and itsopposite
with theexchange
involution or2 ) .R
issimple,
anddimz .R c 4.
PROOF. Since .R is also S-radical over .A
r1 A*,
we may assume A = A*. Let U = U* be a proper *-ideal of Since U is proper and A is a divisionring,
U r1 A = 0. Thus UnS consists ofnilpotent
elements. Let s E be such that s2 = 0. If r e
I-~,
sr+
r* s E so, for asuitable n,
0 =(sr -E- r* s)n= (sr)n-[-
sys for some y E .R. Hence(sr) n s
= 0. This shows that sR is nil and so, sR = 0consequently s
= 0. Therefore weget
= 0.then x
+
x* = 0implies x
= - x* E K and so x2 = 0. Thusevery element in U is
nilpotent
of index 2. It follows that U = 0.We have
proved
that .R is*-simple.
SinceJ(R),
the Jacobson radical ofR,
is a *-ideal andJ(A)
=0,
weimmediately get J(R)
= 0 that is.R is
semisimple.
Now each s E S is eithernilpotent
or invertible soby
([4],
Theorem 2. 3.4)
.R is one of thefollowing types:
(i)
a divisionring,
(ii)
a direct sum of a divisionring
and itsopposite
with theexchange involution,
y(iii)
the 2 X 2 matrices over a field.F’,
or(iv)
a commutativering
with trivial involution.If the first case occurs,
by
the result of Chacron and Herstein[1]
weare done. In case
(ii)
or(iii)
we areobviously
done. In case(iv)
.R isradical over a division
ring
and soby ([2],
Theorem1.1)
.R is a field.This
completes
theproof
of the theorem.We now state our main theorem.
THEOREM 2. Let jR be a
prime ring
with involution of characteristic~ 2, 3
which is S-radical over asubring
A. If .R has no nonzero nilright
ideals and A satisfies apolynomial identity
ofdegree d,
then .Rsatisfies a
polynomial identity
andPI-deg (.l~) c d.
The
proof
of theorem 2requires
severallemmas;
we first make a fewpreliminary
remarks and then state and prove therequired
lemmas.In what follows A c .R be
rings satisfying the hypotheses o f
thetheorem and ... ,
Xd)
will be a multilinearpolynomial identity
ofdegree d
satisfiedby
A. Moreover we assume, as we may, that A = A*.We remark
that, by
a theorem of Giambruno[3],
either 8 çor In the former case .R satisfies the standard
identity
of
degree
4 and there isnothing
to show.Hence,
we shallalways
assume that
Z(A) C Z(.R).
Inparticular
since R isprime,
every nonzeroelement in
Z(A )
isregular
in .R.We
begin
withLEMMA 1. If A is a domain then ù is PI.
PROOF.
By ([4],
Theorem1.4.2)
we have thatZ(A) #
0. If welocalize A and .I~ at
Z(A)
weget rings
with induced involutionAl’
Ri respectively.
Then.Rl
has no non-zero nilright
ideals and is S-radicalover
Ai. Moreover,
since A is adomain, by ([4],
Theorem1.3.4),
A1
is a divisionalgebra.
From theorem 1 weget
that either.I~1
or S =
S(.Rl) ~ Z(.Rl).
In any case.Rl,
and so.R,
is PI.LEMMA 2. If E is PI then
PI-deg (1~) c d.
PROOF.
By ([4],
Theorem1.4.2),
0.Hence,
sinceZ(.R)
isS-radical over
Z(A.), Z(A) ~ 0.
If we localize .R atZ(.R)
and A atZ(1~),
weget rings .R1, Ai respectively. Then, by ([4],
Theo-rem
1.4.3), .Rl
is a finite dimensional centralsimple algebra
with inducedinvolution which is S-radical over
A1. Moreover, .A1
satisfies thepoly-
nomial
identity f (.Xl,
... ,Xd). Thus,
in order tocomplete
theproof
ofthe
lemma,
we may assume that R is a finite dimensional centralsimple
algebra. Therefore,
.R =Dn,
thering
of n X n matrices over a divisionring D,
and the involution * is eithersymplectic
or oftranspose type.
58
Suppose
first that * issymplectic.
Then D is afield,
moreover, since ~Scf. Z(R),
n > 2. Let eH be the usual matrix units in .R. Fora e D and i > 1
odd,
the elementsand
lie in A since
they
aresymmetric idempotents.
Hence+ e2,i+l) E
A andmultiplying
these elements first from the left and then from theright by
ell+
e22 we conclude thatSimilarly,
sincef or i >
2 even the elementsare
symmetric indempotents,
we obtainFrom
(1)
and(2)
since e22 EA,
it follows that c A forall i, j.
Thus A = Rand we are done.
Suppose
now that * is oftranspose type,
thatis,
there exists aninvertible
diagonal
matrix withsuch that
(xij)*
=O(X;i)
0-1 for all(xij)
EDn.
In this case eii(i
==1, ... , n)
is asymmetric idempotent
and so lies in A.We claim that for every eij there exists 0 ~ a = E
Z,
the centerof
D,
such that a - eij E A. Since A is asubring and eii
E A(i
=1, ... , n),
it is
enough
to show that this holdsfor ei,i+1
and(i
=1, ..., n -1).
Moreover,
since * restricted to thediagonal
2 X 2 blockDeii + + Dei+1, i --E-
is still an involution oftranspose type,
in order to prove the
claim,
we may assume that .I~ =D2.
Now,
since D is S-radical over A r1D,
it followsby [1]
that eitherS(D) C Z
or D ç A.Moreover, by [3],
sinceZ,
there exists s E Ssuch
that,
for somek,
and Inparticular
s~ _=
t
not adiagonal matrix,
say b # 0.c
d C,
0 .If
Z,
then C== (0 ()B
c-Z2
and * induces an involution onZ2.
Thus,
in this case we may assume that S eZ2 .
Hence =bel2 E
Aand
(bel2)*
= withb,
On the other
hand,
ifAe bel2
= and e12 E A. Hence= and e2l lies also in A. Thus the claim is
established;
inother
words,
there exist 0 ~ ocij e Z such that e =ly ..., n).
Now,
if J9 cA,
thenclearly Dn
= JL and there isnothing
to prove.Therefore we may assume that and so
PI-deg
Let
f
be the multilinearidentity
for A ofdegree
d. If d C2n,
thena contradiction.
(Dn)
and the lemma isproved.
LEMMA 3. If .Z~ satisfies a
generalized polynomial identity (GPI),
then .R is PI and
PI-deg (l~) c d.
PROOF.
Suppose
that .i~ is not a PIring. Then, by
a theorem ofMontgomery ([4], Corollary
to Theorem2.5.1),
for everypositive integer n,
.I~ contains a~‘-subring
which is aprime
PIring
withPI-deg (.R~~>) ~ n.
But is S-radical over and r1 Asatisfies the
polynomial identity
... , ofdegree
d.By
Lemma2,
yd>PI-deg (.R~n>) ~ n,
for everypositive integer n,
a contradiction.Thus R is PI and
by
Lemma2, PI-deg (.R) c d.
We are
finally
able to prove our main theorem.PROOF OF THEOREM 2.
Since, by assumption, ~S ¢ Z(.R), by ([4],
Theorem
2.2.1),
either S contains non-zeronilpotent
elements or theinvolution is
positive definite,
that is xx*=: 0 in .R forces x = 0.Suppose
first that there 0 in S with 82 -- 0. If x E.R,
let
n(x, s) > 1
be such that(sx +
E A and letA1
be thesubring
of .R
generated by
all x E .R. ThenRi
= s .R is radical overAl. Now,
ifb E Al,
saythen,
since s2 =0,
e60
where a E A. From this it
easily
follows that ifbi, ..., bd E Al
then(bi
...bd)
s =(al ... acd)
s where acl, ..., acd E A.Hence,
In other words
A1
satisfies thepolynomial identity
...~ ·Let
.R2
= where is the nil radical of Since .R has no non-zero nilright ideals,
neither doesMoreover, .R2
isradical over
A2,
theimage
of.A1
in Since and soA2,
satisfiesf (a’i ~ ~ ~~ ~ Xi) by [5], -R2
also satisfies ... , Therefore .R satisfies a GPI andby
Lemma 3 the result follows.Suppose
now that * ispositive
definite. Weproceed by
inductionon the
degree
of the multilinearpolynomial identity
... ,Xci)
satisfied
by
A.Since * is
positive definite,
A. issemiprime. Moreover,
since thecenter of a
prime ring
is adomain, Z(A)
SZ(R)
is also a domain. But in asemiprime PI-ring,
every ideal hits the center nontrivially ([4],
Corollary
to Theorem1.4.2),
therefore A isprime.
If A has no non-zero
nilpotent elements,
then A is a domain andwe are done
by
Lemma 1. Hence we may assume that there exists 0 in A with a2 = 0.Let
aRa* ;
then .R’ is a*-subring
of.R,
S-radical over ~1.’=r1
A, and,
since * ispositive definite,
.R’ is aprime ring.
Let
where
Xd
never appears as first variable in any monomial of g. Since a2 =0,
if Xl’ ... , Xà-l E A’ and xdE A,
we haveHence
aAh(x1, ... ,
= 0and,
since0,
theprimeness
of Aforces
h(xl,
... ,oeà_1)
= o. In other words A’ satisfiesh(xl,
... ,xd_1)
·By
our inductionhypothesis,
.R’ is PI. From this weget
that .Rsatisfies a GPI.
By
Lemma3,
the result follows.REFERENCES
[1] M. CHACRON - I. N. HERSTEIN, Powers
of
skew andsymmetric
elementsin division
rings,
Houston J. Math., 1 (1975), pp. 15-27.[2] C. FAITH, Radical extensions
of rings,
Proc. Amer. Math. Soc., 12 (1961), pp. 274-283.[3] A. GIAMBRUNO, On the
symmetric hypercenter of
aring,
Canad. J. Math.(to
appear).
[4] 1. M. HERSTEIN,
Rings
with involution,University
ofChicago
Press, Chi-cago, 1976.
[5] 1. N. HERSTEIN - L. ROWEN,
Rings
radical overPI-subrings,
Rend. Sem.Mat. Univ. Padova, 59 (1978), pp. 51-55.
[6] E. I. ZEL’MANOV, Radical extensions
of PI-algebras,
Siberian Math. J., 19 1978), pp. 982-983 (1979).Manoscritto