A NNALES DE L ’I. H. P., SECTION C
A MANDINE A FTALION
On the minimizers of the Ginzburg-Landau energy for high kappa : the axially symmetric case
Annales de l’I. H. P., section C, tome 16, n
o6 (1999), p. 747-772
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On the minimizers of the Ginzburg-Landau energy for high kappa: the axially symmetric
caseAmandine AFTALION DMI, Ecole Normale Superieure, 45, rue d’Ulm, 75230 Paris cedex 05
Vol. 16, nO 6, 1999, p. 747-772 Analyse non linéaire
ABSTRACT. - The
Ginzburg-Landau theory
ofsuperconductivity
isexamined in the case of a
special geometry
of thesample,
the infinitecylinder.
We restrict toaxially symmetric
solutions and consider models with and without vortices. Firstputting
theGinzburg-Landau parameter x formally equal
toinfinity,
the existence of a minimizer of this reducedGinzburg-Landau
energy isproved.
Thenasymptotic
behaviour forlarge x
of minimizers of the full
Ginzburg-Landau
energy isanalyzed
and differentconvergence results are obtained. Our main result states
that,
when x islarge,
the minimum of the energy is reached when there are about ~ vorticesat the center of the
cylinder.
Numericalcomputations
illustrate the various behaviours. ©Elsevier,
ParisRESUME. - Le modele de
Ginzburg-Landau
dessupraconducteurs
estetudie dans le cas d’une
géométrie cylindrique
pour des solutionsradiales,
avec et sans vortex.
Quand
leparametre
deGinzburg-Landau 03BA
estinfini,
on prouve l’existence d’un minimum pour une
energie
reduite. Puis onetudie le
comportement asymptotique
des minimiseurs pour »grand
et onobtient differents resultats de convergence. On montre en
particulier
quel’énergie
est minimum pour uneconfiguration
ou le nombre de vortex au centre ducylindre
est de l’ordre de ~. Des calculsnumeriques
illustrent les diverscomportements.
©Elsevier,
ParisClassification A.M.S. 1991 : 82D55, 35Q55
Annales de l ’lnstitut Henri Poincaré - Analyse non linéaire - 0294-1449 Vol. 16/99/06/© Elsevier, Paris
748 A. AFTALION
1. INTRODUCTION
The
superconductivity
of certain metals is characterized at very lowtemperatures by
the loss of electrical resistance and theexpulsion
of theexterior
magnetic
field.Superconducting
currents in thematerial,
which exclude themagnetic field,
are due to the existence ofpairs
of electrons ofopposite sign
and momentum, theCooper pairs.
In theGinzburg-
Landau
model,
theelectromagnetic properties
of the material arecompletely
described
by
themagnetic potential
vector A(H
= curl Abeing
themagnetic field)
and thecomplex-valued
orderparameter 1/; (see [11], [13]
or[16]
forinstance).
Infact,1/;
is anaveraged
wave function of thesuperconducting electrons;
itsphase
is related to the current in thesuperconductor
and its modulus to thedensity
ofsuperconducting
carriers:== 0 when the
sample
iswholly
normaland |03C8|
= 1 when it iswholly superconducting.
The basicthermodynamic postulate
of theGinzburg-
Landau
theory
says that a stablesuperconducting sample
is in a statesuch that its Gibbs free energy is a minimum. The nondimensionalized form of this energy is
given by:
where S2 is a domain in Rn
(n
=1,
2 or3) representing
theregion occupied by
thesuperconducting sample, Ho
is thegiven applied magnetic field,
and /~ is a materialparameter
called theGinzburg-Landau parameter.
This
parameter
is the ratio ofA,
thepenetration depth
of themagnetic
fieldto
ç,
the coherencelength,
which is the characteristiclength
of variationof rf.
The value of 03BA determines thetype
ofsuperconductor: 03BA 1/ /2
describes what is known as a
type
Isuperconductor
and /~ > asa
type
II.Type
Isuperconductors
are eithernormally conducting (normal state)
orsuperconducting according
to the value of themagnetic field,
while for
type II,
a third state appears, called the mixed state: in the mixed state, thesuperconducting
and the normal states coexist in what isusually
called filaments or vortices. At the center of the vortex, the orderparameter vanishes,
so the material isnormal;
the vortex is circledby
asuperconducting
currentcarrying
with it aquantized
amount ofmagnetic
flux.
Macroscopic
models ofsuperconducting
vortices have been formulated in[9], [10]
and the existence and behaviour of vortex solutions to theGinzburg-Landau equations
have beenwidely
studied. See[2], [4], [5], [7], [8], [12], [14]
for instance.In this paper, we
study
the minimization of theGinzburg-Landau
energy when theparameter x
islarge,
for aspecial geometry
of thesample,
Annales de l ’lnstitut Henri Poincaré - Analyse non linéaire
the infinite
cylinder. Thus,
we restrict toaxially symmetric
solutions. Theprevious
paper[1]
deals with the one-dimensional case. Our motivationwas the
study
made in[3]
of the solutions of theGinzburg-Landau system
with infinite x.
This paper is
organized
as follows. First ofall,
westudy
theasymptotic
behaviour of minimizers under the constraint that vortices do not exist: we
put formally
xequal
toinfinity
in the energy andstudy
the minimizers of this reducedform;
this will enable us to show convergence ofGinzburg-
Landau energy minimizers as x tends to
infinity.
Weespecially
prove auniqueness property
of the solutions of thesystem
for infinite ~, which extends a result of[3].
The section ends with numerical results. The sametype
of work is made in the next section for the model with vortices. Our main result states that when x islarge
the minimum of the energy is reached when there are about x vortices at the center of thecylinder.
Let us recall from
[13]
the mainproperties
of the two dimensionalGinzburg-Landau
model. We assume that thesuperconducting sample
isan infinite
cylinder.
When themagnetic
field isparallel
to the axis of thecylinder, Ho
=(0, 0, Ho ),
one can assume thatboth ~
and A are uniformin the z-direction. The state of the
superconductor
is describedby
thepair (~, A)
that minimizesE,~,
where Q is aregular
bounded domain inR2.
Let us define
We can
choose ))curl
as a norm onDEFINITION l.l. -
(~, A)
andB)
are said to begauge-equivalent if
there exists 8 E
(~)
suchthat ~ _
and B = A -(1/~)~8.
Then,
the energyE,~
ispreserved by
thistransformation.
THEOREM 1.2. - A minimizer
of E,~
over(~)
xH1 (SZ,1~3)
is gaugeequivalent
to a minimizerof E,~
overH1 (S2, U~)
xTHEOREM 1.3. - There exists a minimum
(~, A) of E,~
overHl
xIt is a solution
of.
Vol. 16, n° 6-1999.
750 A. AFTALION
PROPOSITION 1.4. -
minimizer of E,~ then ~ ~ ~
1 a. e.If H is a
general domain,
thegauge-invariance property
does not remain inEoo, (the
energy obtained when /~ isformally put equal
toinfinity),
sothat we do not have a
global
minimum of the energy. Hence we shall nowrestrict ourselves to a ball.
2. THE CASE WITHOUT VORTICES
When H is assumed to be a
ball,
we usepolar
coordinates and restrictto radial solutions. In this
section,
we make the extraassumption
that novortices exist
(so ’Ø
is neverequal
tozero)
and we look for:We
automatically
have div A =0,
which is themajor
interest of thisgauge. So
)]curl
is a norm onSince we want
A)
inH1
x we define:From now on, when we write that
Q
is inD~,
it will mean thatQ
=is in
DQ.
Notice that is a norm onD f
andis a norm on
DQ.
The energy can be rewritten as follows:The same method as in
[1]
allows us to say that:. there exists a minimizer of
E~
overD f
xD~,
~ it is a solution of
Annales de l ’lnstitut Henri Poincaré - Analyse non linéaire
Equations (7)-(8)
can be rewrittenusing
thelaplacian
inpolar
coordinates:2.1.
Properties
of solutionsFirst of
all,
wenotice,
as in[4],
that ifQ
is inD~,
itimplies
thatrQ
EH1 (0, R), Q
is continuous on[0, R]
andQ(0)
= 0. Moreprecisely,
Do
C withTHEOREM 2. I . -
If ( f , Q)
is a minimizerof
thenf
andQ
are inC°°
[o, R].
Proof -
Theprevious
remark andProposition
1.4give
that( f , Q )
is inL°° (BR).
Then the result follows from classicalelliptic
estimates on theformulation
given by equations ( 11 )-( 12).
DRemark. - As
f
isregular
in0, equation (7) implies
thatf’ (o)
= 0.PROPOSITION 2.2. -
If ( f , Q)
is a minimizerof
then eitherf -
0 orf
is neverequal
to zero.From now on, we shall assume that
f
> 0 on(0, R]
for a minimizer of The solutionfo -
0 andQo(r) _ H0r/2
is called the normal state.THEOREM 2.3. -
If ( f , Q)
is a minimizerof
thenQ
isnondecreasing.
Proof. -
Let us first show thatQ ~
0 on[0, R].
IfQ
reached anegative
minimum at r = ro on
(0, R),
then we would haveQ
0 and(8)
wouldmean
on a small intervall around ro; this is in contradiction with the Maximum
Principle. Similarly,
ifQ
reached anegative
minimum at r =R,
theHopf
Lemma would
imply
thatQ’ (R)
0 but then condition(10)
would notbe satisfied.
Now if
Q
was notnondecreasing,
we would have the existence of ri and r2 in(0, R)
such that ri r2 andQ(ri)
>Q(r2).
It wouldimply
Vol. 16, n° 6-1999.
Q
reached apositive
maximum on(r1, r2).
This contradicts the MaximumPrinciple
sinceQ
0 on(0, R).
D2.2. Infinite
Ginzburg-Landau
ParameterWe
put ~ equal
toinfinity
in the energy. We defineTHEOREM 2.4. - The minimum
of
over xD~
exists and is attained. Moreover itsatisfies:
where = 1
if 1,
and 0 otherwise.The
proof
is almost the same as in[ 1 ] .
It comes from the fact that whenQ
isfixed,
the minimum of( 1 / 2) ( 1 - f 2 ) 2
+ is attained forf
= 0if >
l,
andf 2
= 1 -Q2 if Q (
1.THEOREM 2.5. - There exists
Ho
such that(i) for Ho Ho,
there exists aunique solution Q of (14)-(15)
inD~
and it remains smaller than 1 in
(0, R). If we
calla(R, Ho)
=Q(R),
then
a (R, Ho )
is a continuous andincreasing function of
RandHo.
Moreover, a(R, Ho)
reaches 1 whenHo
=Hj,
(it) for Ho
>Ho,
there is no solution that remains smaller than 1.Proof. -
Weproceed
as in[3], using
ashooting
method from theboundary
r = R. For a
given
a E(0, 1),
there is aunique
solution ofWe check that
(15)
is satisfied when r = R. The threepossible
behavioursof
Q Q
are describedby
thefollowing
sets:Annales de l’lnstitut Henri Poincaré - Analyse non linéaire
We recall from
[3]
that~
I(R, Ho) corresponds
toregular solutions,
that isQa(O)
=0,
e
Io(R, Ho)
andIl(R, H~)
are open sets,e
0
whenRH~ 1,
so itimplies
thatHo) 7~ 0
too,.
(0,
CIo(R, Ho),
so forHo
> R +2/R, I(R, Ho) = 0.
We may also notice that
Q~
cannot reach apositive
local maximum whileit remains between 0 and
1,
since(17)
can be rewrittenSo
Qa
isincreasing
on(ro,a, R)
where ro,a is such thatQa (ro,a )
= 0.It is
proved
in[3]
that there existsHo
such that forHo ( 14)-( 15)
has a solution that remains smaller than
1; Ho
is obtained as the maximum ofHo
over thepoints ( R, Ho )
in the connectedcomponent
ofIi
whichcontains the
set ((R, Ho),
stRHo 1 ~ .
Theuniqueness
result there isonly
obtained for R We aregoing
to prove that in factIo ( R, Ho )
and
Ii(R, Ho)
are connected and thatI ( R, Ho )
has at most onepoint, using
an ideainspired by [17].
Let u and v be two different
regular
solutions ofWe
already
know that u and v areincreasing
sothey
can be inverted. Wedenote the inverse functions
by r(x)
ands(~). Using
as new variableswe can rewrite
(18)
asVol. 16, n ° 6-1999.
A. AFTALION
We assume ~u G v 1 on
(0, a),
so thats(x)
for x E(0, ~(cr))
andu,’(0) v’(0).
We obtain(U-V)’(x)
> 0 and sinceU(0)
=V(0)
=0,
wehave
U(x)
>V(:r,~),
which can be rewrittenr(a )ea,’(r(a;))
>s(x)v’(s(x))
for x E
(0, u(a)).
As a consequence, for all y E(0, u( a)),
or
For any solution
Q
of(18),
we now introduceA
straightforward computation, using (18), gives F~ (r) _ ( 1 /r) Q2 ( 1- Q2 ) .
Thanks to an
integration
from 0 to a ofF~ (r),
thanks to(20)
and becauseu’(0) v’(0),
weget
Therefore,
tworegular
solutions cannot intersect beforereaching 1,
otherwise we would have u v on( 0, ~ )
andu(a)
=v(a)
withu’(a)
>v’(a),
which contradicts(21).
We are now able to show
uniqueness
ofregular
solutions. Let R be fixed. Let us assumeQi (resp. Q2 )
is a solution of(17)
with a 1(resp.
a2)
andHo
=Hi (resp. H2).
If cxl c~2, since tworegular
solutions do not intersect beforereaching 1,
we haveQi Q 2
on( 0, R) .
We inferfrom
(21)
thatHi H2 .
So there is aunique I(R, Ho)
for each R and
Ho
and0152(R, Ho)
is anincreasing
function ofHo.
An immediate consequence of theuniqueness
is thatIo (R, Ho)
andHo)
are connected sets.
Moreover, 0152(R, Ho)
is anincreasing
function of R.Indeed,
letC~2 ( R2 , Ho )
be the initial data for the tworegular
solutionsQi
andQ2 .
We know thatQi
andQ2
do not intersect in(0, min(Ri, R2 ) ) .
Let us assume
Qi Q2
on(0, min(Rl, R2 ) );
we call r2 thepoint
where
Q2 (r)
= ai. We now use(20) with ~/
= cxl whichprovides
thefollowing comparison
resultF~2 (r2 ) - F~2 (0) .
This
yields Ho Q2 (r2 )
+( 1 ~r2 ) Q2 (r2 ) -
But it isimpossible
sinceAnnales de l ’lnstitut Henri Poincaré - Analyse non linéaire
Q2 (r)
+(1/r)Q2(r)
isincreasing
and reachesHo
when r =R2.
SoQ2 Q1
on(0, min(R1, R2))
and itimplies R1 R2.
The
continuity
ofa ( R, Ho )
follows from the fact thatIo(R, Ho)
andI1(R, Ho)
are open and the continuousdependence
ofQ
withrespect
to R and
Ho
on any interval that does not contain zero.Indeed,
ifao
a(R, Ho)
03B11, we haveQao (ro)
0 andQal (rl)
> 1 for some roand ri smaller than R. But these
inequalities
remain true for all(7!, Ho )
ina
neighbourhood
of( R, Ho ),
which shows ao a1.We are now able to conclude the
proof.
Let R be fixed. ForHo small,
weknow that
II (R, Ho)
isnonempty,
soI(R, Ho)
isnonempty
too. We callIt can
easily
be seen from the continuousdependence
ofh (R, Ho)
with
respect
toHo
that whenHo
reachesHo, Ho)
reaches 1. Asa(R, Ho)
is anincreasing
function ofHo,
itimplies I(R, Ho)
isempty
for
Ho
>Ho.
DPROPOSITION 2.6. - We have
Ho(R)
is adecreasing function of
R.Moreover _
Remark. - This is the same limit as in the one-dimensional case.
Proof. -
We have shown in theproof
of Theorem 2.5 that forRi R2, Ho) ~~~a, Ho).
LetHo
= so thata(R2,
= 1.It means > which is the desired
monotonicity property.
Let
Q
be theregular
solution of(17)
withHo
= so that a = 1.As
FQ
isincreasing,
we obtainFQ(0) FQ(R),
that isHo(R)
>In order to
get
the estimate on the otherside,
we introduce a new energy:A
simple computation, using (17) gives G2(r)
=-r2Q’2(r)
+Q2(r).
We now differentiateGZ
andget G2(r) _
Q2(r)).
SoG2
isdecreasing
and sinceG2(0)
=0,
it meansG1(0)
>G1(R)
which can be rewritten
Vol. 16, n ° 6-1999.
756
’ THEOREM 2.7. - There exists a
unique
minimizerQ~ ) of
For
Ho Ho,
remains smaller than 1 andf~
= 1 -Q~.
For
Ho
>Ho,
there exists aunique
R such that in(0, R~ ),
remains smaller than 1 andf ~
= 1 -Q~
while in
(R~, R), Q~
+ =Ho
andf~ -
0.Proof. -
Theorem 2.5gives
that forHo Hj,
there is aunique ( f ~ ,
solution of
(14)-(15)-(16)
and remains smaller than 1. ForHo
>Ho,
as we want a solution in
D Q,
it means~,?~ (0)
= 0 so is a solutionof
(18)
on(0, R~ ),
with(R~ )
= 1. The radius isunique
becausea(R, Ho)
is anincreasing
function of R. So there is aunique
solutionof
(14)-(15)-(16)
with 0. Whatonly
remains to show is that this solution is the minimizer ofE~,
or moreprecisely
that the normal state(any
solution definedby f o
- 0 andQo
+Qo /r
=Ho )
has ahigher
energy.We introduce a new energy
and we call
Roo
= R in the caseHo
with Q =Computing E’ (r), using equation (14), gives
This and an
integration by parts
enable us to estimate2.3.
Convergence
of minimizersPROPOSITION 2.8. - For all
Ho,
there exists ~o such thatfor
> ~o, thenormal state is not a minimizer
of E,~.
The
proof
relies on energycomparisons
as in[ 1 ] .
THEOREM 2.9. - The whole sequence
of
minimizersof E,~
converges to the
unique
minimizerof
Moreprecisely,
whenx - oo,
Annales de l’lnstitut Henri Poincaré - Analyse non linéaire
Proof -
It is almost the same as in[1].
Weonly
mention the main ideas.For
Ho Hj,
as1, foo
is inH1(BR)
and we can test it inE~.
We infer thatf ,~
is bounded inH1(BR)
andE,~ ( f ,~ , Q,~ )
tends toAs a consequence,
Q~
is bounded inH1(BR).
So for asubsequence,
Using equation (12), ’we
canimprove
the convergence onQ,~ :
classicalelliptic
estimates and Sobolevembeddings give
that is bounded in for all finite p, andQ,~
converges in for a 1. Wesee that
Q)
=Qoo)
and Theorem 2.7gives
the conclusion.For
Ho 2::
we have seen thatfoo
is not inH1(BR),
but asin the one-dimensional case, we can find g,~ in such that
=
Energy comparisons give:
As in the one-dimensional case, up to the extraction of a
subsequence,
for
( f, Q)
EL4 x D~.
Lowersemi-continuity yields:
limE,~( f,~, Q,~)
> so that
( f , Q)
is the minimizer ofEoo.
Theorem 2.7 allowsus to know the
properties
off :
there existsRoo
withf -
0 on(0,
and
f 2
= 1 -Q2
onR).
Then the result of convergence follows asin the one-dimensional case. D
2.4. Numerical
Study
We want to
compute
solutions of theGinzburg-Landau system
such thatf
ispositive.
Instead ofsolving
thesystem (7)-(8)-(9)-(10),
we defineS(r)
=rQ(r),
choose E small and solve:Vol. 16, n ° 6-1999.
A. AFTALION
using
the same scheme as in[I],
that isimplicit
discretisation in time. Itcan be shown as in
[6],
thanks to the MaximumPrinciple,
that a minimizerof the
Ginzburg-Landau
energy is anasymptotically
stable solution of thisproblem.
Wecompute
the solutions with R = 1. Westudy
the convergenceof f,~
when x tends toinfinity. Figure
1(Ho
=1)
andfigure
2(Ho
=3)
illustrate the two different behaviours described in Theorem 2.7.Remark. - It would be
interesting
to show thatf ,~
isnonincreasing
andimprove
the convergence of the sequence.3. THE CASE WITH VORTICES
In this
section,
we allow N vortices to appear in the center of the ball and intend to minimize the energy over this number N. We aregoing
toshow that 0 for the
minimizer,
and moreprecisely
thatN/x
has alimit when ~ tends to
infinity.
The existence of vortices at the center of the ball can be describedmathematically by introducing,
as in[4],
solutionsAnnales de l ’lnstitut Henri Poincaré - Analyse non linéaire
(~, A)
such thatand A will be
regular
at theorigin.
We may notice that(’lj;, A)
is gaugeequivalent (see
Definition1.1)
to(f,(a)
withwhere is
regular
at theorigin.
In this
situation,
theGinzburg-Landau
energy is thefollowing:
Vol. 16, n° 6-1999.
760 A. AFTALION
3.1. Finite
Ginzburg-Landau
ParameterThe introduction of N in the energy comes from a number of
vortices,
that is an
integer.
But infact,
the definition(22)
has ameaning
for any real number N. So for mathematical purposes, from now on, we will allow N to vary in R. We will see that the convergenceproperties
and the limit would not be affectedby restricting
N to lie inZ,
if ajudiciously
sequence of 03BA is chosen.3.1.1. Fixed number of vortices
To start
with,
we fix N and want to minimizeE,~
onD j
xDs
whereWith the norm
~~(l~r)S’~~L2, DS
is a Hilbert space(see [4]).
We will notgive
theproof
of the next three Theorems as it is almost the same as in the case treated in[4].
THEOREM 3.2. - We have the
following regularity properties:
THEOREM 3.3. - There exists a minimizer
( f , S) of E,~.
It is in(C°° (BR - ~0~)
nC2 (BR) )2
and is a solutionof.
Annales de l ’lnstitut Henri Poincaré - Analyse non linéaire
Remark. - With the
expression
of thelaplacian
in the radial case,equations (23)
and(25)
can be rewritten:THEOREM 3.4. -
If ( f , 8)
is a minimizerof E,~
such thatf
is notidentically
zero, then 0
f
1 on(0, R]
and ,S’ > 0 on(0, R). Moreover,
neitherfunction
is constant on a subintervalof (0, R).
Proof. -
Since the solutions areregular by
Theorem3.3,
ifthey
areconstant on a
subinterval,
it meansthey
are constant on[0, R].
But theboundary
conditionS(0)
= 0 and(23)-(25)
show that S cannot be constantand the
only possibility
forf
is 0.If
( f , S)
is a minimizer ofE~,
so is( ~ f ~ , ,S’) .
Hence,5’)
is a solutionof the
Ginzburg-Landau equations and f ~ I
is C°° on(0, R).
So eitherf -
0 orf
is neverequal
to zero.Let us assume
maxr~[0,R] f (r)
=f (ro)
> 1. Asf(O)
=0,
ro E(0, R].
Equation (27)
can be rewrittenon an interval around ro, which does not contain
0,
and on whichf >
1 sothat
c(r)
ispositive.
We choose thelargest
intervalpossible. Necessarily,
either
f
= 1 on theboudary
or r = R is theright
end. Thestrong
MaximumPrinciple implies
that the maximum is reached on theboundary.
But because of condition(26),
it cannot be reached on r = R and otherwisef
= 1 onthe
boundary,
which is the minimum. So thatf
remains smaller than 1.We know that
S(0)
= 0. Let us assume that there exists ro in(0, R]
suchthat
S(r)
=8 (ro)
0.Equation (28) gives:
We
again apply
the MaximumPrinciple
on an interval around ro.The minimum is reached on the
boundary
which means ro = R. But condition(26) gives
thatS’ (R)
> 0 which contradicts theHopf
Lemma.D
Vol. 16, n° 6-1999.
A. AFTALION
THEOREM 3.5. -
If ( f , S)
is a minimizerof E,~,
then S is nondecreasing.
Proof -
We rewriteequation (28)
as follows:The Maximum
Principle implies
that S -(~V/~)
cannot reach anypositive
maximum nor any
negative
minimum in the interior. SinceS(0)
=0,
thereare two
possibilities:
. 8 ~
(N/x)
on(O,R).
So S has no local minimum in
(0,R).
AsS’(R)
>0,
itimplies
Sis non
decreasing.
.
S(r)
>(N/~)
for some r in(o, .R).
Let ro be the first
point
where S_ ~ . Necessarily,
> 0by
the
Hopf
Lemma and as in theprevious
case, S is nondecreasing
on
(0, r~o).
Then the Maximumprinciple gives
that S -(N/~)
has nopositive
maximum in(ro, l~).
So S is nondecreasing
on(ro, R).
0Remark. - It would be
interesting
tostudy
themonotonicity
off.
3.1.2. Minimization of
E~
From now on, we intend to minimize
E~ over
R xD f
xDs,
that is tofind the best number of vortices to
put
at theorigin.
We will show that the presence of vortices lower the energy.THEOREM 3.6. - There exists a minimizer
(N, f, S) of EK; ( f, S)
is in~0~)
nC2(BR))2
and is a solutionof (23)-(24)-(25)-(26)
withProof -
Let(ni, Sni )
be aminimizing
sequence. For each ni, wecan
always replace fni
andSni by
a minimizer ofE~
with fixed N = ni as in theprevious
section. Thenfni
i is bounded in n andSni
is bounded inDs. So,
up to the extraction of asubsequence,
Annales de l’Institut Henri Poincaré - Analyse non linéaire
where
( f, S)
GD j
xDs.
Thanks to lowersemi-continuity,
we haveIf the limit
f
isidentically
zero,equation (30) implies
that the normal state(fa, So),
withf o
- 0 andSo ( r ) = Ho r,
is a minimizer ofE~.
Then thenumber N of vortices does not intervene.
When
f
is notidentically
zero, the sequence ni is bounded.Indeed,
we have
and since
Sn
Z is inDs,
itimplies
EL2(BR).
As a consequence, wecan assume ni -~
N,
and(N, f, S)
is a minimizer ofE~
because of(30)
andCOROLLARY 3.7. - When the normal state is not a
minimizer,
then theminimizing
solution has vortices at theorigin.
Proof. -
When0, equation (29) gives
that S -changes sign.
The
study
in section 2implies
that N ispositive.
3.2. Infinite
Ginzburg-Landau
ParameterWe let
formally x
= oo in the energy. The difference with the onedimensional case is that we shall have to find the constant C
(which
comesfrom the term
N/x)
which minimizes the energy. We defineVol. 16, n° 6-1999.
764 A. AFTALION
satisfies
Proof. -
We call aminimizing
sequence and defineQn (r) _ (Sn (r) - Cn ) /r.
Weproceed
as in the one dimensional case:replacing f n by (1 -
canonly
lower the energy soQn
is aminimizing
sequence ofSince
( 1 /r) (rQ)’
is bounded inL2,
is bounded inL2
too, so itimplies Sn
is bounded in L°° . As we areonly
concerned with r such that1,
we can also assumeCn
is bounded. Then we can extract asubsequence
that will converge to a minimizer ofEoo. Equations (32)
and
(34)
are thecorresponding Euler-Lagrange equations
for the variationsof S and C.
THEOREM
3.9. - Any
minimizerf ~ , of
is such that 0.More
precisely,
let Then isincreasing
on
(0,R),
remains smaller than one in an annulus(rl , R)
with-1. On
(0, rl),
= 0 and(1/2)Hor -
where
Coo
=ri(l
+Rori/2).
Proof. -
We aregoing
tostudy
theshape
of solutions of(32)-(33)-(34)- (35).
An easycomputation
shows that ifQ’(r)
+(l/r)Q(r)
=Ho,
thenQ (r) = ( 1 /2) Hor - ( 1 /r) C
for agiven
constant C. As(32)
can be rewrittenthe Maximum
Principle implies
thatQ
can neither reach apositive
localmaximum nor a
negative
local minimum while it remains between -1 and 1. Moreover(34) implies
thatQ changes sign.
So any solution of(32)- (33)-(34)-(35)
with 0 is such thatQ
isincreasing, |Q|
1 in an annulusAnnales de l’lnstitut Henri Poincaré - Analyse non linéaire
and outside the
annulus,
the solution is definedby (33)
and thecontinuity
condition on the
boundary.
There are twopossible types
of solution:e
type
a: 1 on(rl, R)
withQ(~~1) _ -1
andQ(R)
= a E(0, 1),
e
type
b : 1 on(rl, r2)
withQ(~~1) _ -1, Q(r2)
= 1 and r2 R.We are
going
to show thattype
b solutions cannot occur. Let us defineon the annulus
where I Q I
1. Thanks to(32),
we see thatF’(r) = (1/r)C~z(1 - Q2),
so F isincreasing
on the annulus. But this isimpossible
in the case of a
type b
solution sinceF(r1)
=F(r2)
=Ho~2.
So we haveto
investigate
the existence oftype
a solutions. Theproof
now relies on ashooting
method: for agiven
a E(0, 1),
there is aunique
solutionQa
ofWe check that
(33)
is satisfied when r = R. We are interested in the interval whereQa
remains smaller than 1. We introduce the same sets as in theproof
of Theorem 2.5 :1(R, Ho ) , Io ( R, Ho )
andh ( R, Ho ) .
Notice that the MaximumPrinciple applied
to(37) implies
that when Q EIo (R, Ho )
thereexists rl,a E
(0, R)
withQa(rl,~) _ -1
andQ~
isincreasing
on(rl,a, R).
For Q E
Io(R, Ho),
we defineWe notice thanks to
(32)
thatClassical ODE
theory implies
thatf R
is a continuous function of a.1 st step. - Let Rand
Ho
be fixed. We aregoing
to show that when0,
there is a minimizer of oftype
a. In this case, we know from theproof
of Theorem 2.5 thatIo(R, Ho) = (0, a*)
witha* E
I(R, Ho).
For a =0, Qa
0 onR)
so(40) gives
thatfR(O)
0. As a consequence,f R
isnegative
for a small.Vol. 16, n° 6-1999.
766 A. AFTALION
We let a tend to cx * . We call the
point
whereQ a (T)
= 0.Up
to theextraction of a
subsequence,
we have ro,c. --~ ro. If ro >0,
then classical ODE estimatesgive
that -~(ro).
But as a* EI(R, Ho),
wecannot have = 0 for ro >
0,
so ro = 0. SinceQa
isincreasing,
rl,a ro,a and r~,a --~ 0 too. We know that
Qa
is bounded on(rl,~, R),
so we have
It
implies
thatf R ( a )
> 0 for a close to c~ * . Asf R ( a )
0 for small a, thereexists
13
E(0, a* )
such thatf (,~)
= 0. SoQ~
is a solution to(32)-(33)-(34).
We
already
know that the minimizer ofEoo
exists. Either it is the normal state, that is a solution(Co, fa, So)
withf o
- 0and So
=Ho r,
or a solution of
type
a. We may notice that once we have a solutionQ
oftype
a, we can go back to(C, f, S)
thanks to(35),
thecontinuity
condition
Horl /2 - C/ri
= -1 and the definition ofQ
whichgives S(r)
= C +rQ(r). Moreover, f, S)
=J(Q,).
Now let us showthat
Q,~ provides
a minimizer ofEoo.
We introduce a new energyComputing E’ (r), using equation (32), gives
This and an
integration by parts
on(l~r)((rQ~)’)2
enable us toestimate
J ( Q f3 ) .
~’"
Since =
1-~2/4,
it meansQ~
has a lower energy than the normal state.2nd step. - We assume
Ho
is fixed. Then for small R(R 1 /Ho
forinstance),
the firststep
indicates that there exist a minimizer oftype
a.We call
Ro
=max~I~
st the normal state is not a minimizer ofEoo.} (42)
Annales de l’Institut Henri Poincaré - Analyse non linéaire
Let us assume that
Ro
is finite. Astraightforward argument
shows that ifQaR corresponds
to a minimizer ofEoo
with = and ifJo
=R20/4 is
the energy of the normal state for R =Ro,
thenAccording
to(41),
it means that 1 and --~ 0.But this is
impossible,
soRo
= +00. DRemark. - Numerical
computations
show thatf R
isincreasing
on(0,1)
hence the minimizer of
Eoo
isunique.
COROLLARY 3.10. - For all
Ho,
there exists ~o such that ~o, the normal state is not a minimizerof E,~.
The
proof
relies on energycomparisons
as in[1].
PROPOSITION 3.11. - When R is
large, C~ is equivalent
toHoR2 /2.
Proof -
Wealready
know thatCoo
=r1(1
+Horl /2),
where rl is suchthat
Q( T1)
_ -1 andQ
is as in Theorem 3.8 associated to the minimizer of Weonly
need to show that rl isequivalent
to R when R islarge.
Let V be the solution of
where a =
Q(R).
It is easy to see that there exists pi in(0,R)
such thatV(pl) _ -1,
V isincreasing
on and the energyV’2
+(1 - V2)2~2
is
preserved
on(pl, R).
Astraightforward computation gives
So if we show that 7-1 > pi, the
proof
is over. We know thatQ
V forr close to R and we are
going
to show thatQ
and V cannot intersectbefore
reaching
-1. LetWe
immediately get E~(r)
=(2/r~)Q’(Q - rQ’).
Let ro be thepoint
where
Q
crosses zero. SinceQ
isincreasing, Ei
0 on(ri, ro).
LetE2(r)
=rQ - r2Q’
on(ro, R).
SinceE2 (r) _ -r2Q( 1 - Q2 ),
itimplies
Vol. 16, n° 6-1999.
768 A. AFTALION
E2 (r)
0 on(ro, .l~)
andEl
isdecreasing.
Since for r = l~ the energyEi
is the same forQ
andV,
it meansSo
Q
and V cannot intersect beforereaching
-1 and r1 > 03C11. 0 3.3.Convergence
ofminimizers
THEOREM 3.12. - Let
(N,~, f~, S~)
be a sequenceof minimizers of Ex.
There existsf ~ ,
aminimizer of
and asubsequence (N,~~Z , S’,~n ),
such that when ~n tends to 00Proof -
Let(Coo,
be a minimizer ofEoo.
We have seen thatfoo
is not in but as in[1],
we can find g,~ inH1(BR)
such thatLet be a minimizer of
Energy comparisons give:
We let 03BA tend to
infinity
and obtainIt
implies
that is bounded inDs.
As1,
up to the extraction of asubsequence,
Annales de l’lnstitut Henri Poincaré - Analyse non linéaire