C OMPOSITIO M ATHEMATICA
P ETER H ELLEKALEK
Ergodicity of a class of cylinder flows related to irregularities of distribution
Compositio Mathematica, tome 61, n
o2 (1987), p. 129-136
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Ergodicity of
aclass of cylinder flows related
toirregularities
of distribution
PETER HELLEKALEK
Martinus Nijhoff Publishers,
Institut fùr Mathematik, Universitiit Salzburg, Hellbrunnerstrasse 34, A-5020 Salzburg, Austria
Received 18 November 1985; accepted 10 March 1986
Abstract. We study ergodicity of cylinder flows (x, t) ~ (Tx, t + ~(x)), where T is a von Neumannt-Kakutani adding machine transformation on R /Z and an arc in RIZ of length R.
Introduction
We shall be interested in
cylinder
flows of thefollowing type.
Let T :R/Z~
R/Z,
x HTx,
be measurepreserving
andergodic
withrespect
toLebesgue
measure 03BB
on R/Z,
let G be either a closedsubgroup
of R or G =R/aZ
witha in R. Let h denote Haar measure on G and let ç :
R/Z ~
G be measurablewith
fep
d03BB = 0.The
cylinder
flowT,(x, t)
=(Tx, t
+T(x»
acts on the measure theoreticproduct
spaceX = R/Z
0 G and preserves theproduct
measure À 0 h on X.We shall
study ergodicity (with respect
to À 0h )
of thefollowing
class:Example
1Let
Tep
be thecylinder
flow whereT: R/Z ~ R/Z
is ageneralized
vonNeumann-Kakutani
adding
machine transformation(definition
in Part II of thispaper),
and let~(x)
=1A(x) - 03B2,
where A is an arc inR/Z
oflength 03B2,
0
f3
1. Let G be the closedsubgroup
of Rgenerated by
1 andf3.
If03B2
isirrational,
then G = OB and h will denoteLebesgue
measure. If03B2
=r/s,
r ands
positive integers, (r, s) = 1,
thenG=(1/s)
Z and h will stand for thecounting
measure.The
ergodicity
of this class ofcylinder
flows isdirectly
related toirregularities
in the distribution of
generalized van-der-Corput
sequences. For this reason, necessary conditions for theergodicity
ofT,
and hence for03B2
follow fromresults in
[Hellekalek, 1984].
For thegeneral background,
inparticular
theimportant coboundary
theorem and its consequences, the reader is referred to[Liardet, 1982, 1985].
130
Results on
ergodicity
ofcylinder
flows date back to[Anzai, 1951] (T
anirrational
rotation,
G =R/Z).
Thefollowing
class is now well-known.Example
2Let
7"
be thecylinder
flow where T:R/Z ~ R/Z,
x H x + a mod1,
airrational, and ~(x)
=1[0,03B2[(x)-03B2,
003B2
1. Let G be as inExample
1.Ergodicity
ofExample
2 was studiedby [Oren, 1983], completing
an earlierresult of
[Conze, 1980].
Oren hasproved: Tep
isergodic
if andonly if 8
isrational or
1, a
and03B2
arelinearly independent
over Z.Example
2 is also related to a class of sequences well-known in thetheory
of uniform distribution modulo
1,
the sequences(n03B1)n0.
Good references are[Petersen, 1973] and,
inparticular, [Liardet, 1985].
I. Remarks
From now on it will be assumed that
T~
is thecylinder
flow ofExample 1,
although
thefollowing
remarks caneasily
begeneralized
to coverExample
2and a
large
class of othercylinder
flows as well.T~
isergodic
if andonly if,
for everyT~-invariant
measurable subset B ofR/Z ~ G,
either B or itscomplement
has measure zero. Westudy ergodicity
of
7§ by reducing
theproblem
from the infinite case(i.e. 7"
onR/Z
0G)
toa finite case
(i.e. T~
onR/Z ~ G/aZ; a ~ G, a ~ 0).
Definition:
An element c of G is called aperiod
ofT~ if,
for everyT~ -
invariant function
1B, B
a measurable subset of theproduct
spaceR/Z
0G,
the
equality 1B(x, t )
=1B(x, t
+c)
holds À ~ h - a.e..The set
P~
ofperiods
ofT~
is asubgroup
of G.[Schmidt, 1976]
hasextensively
studied what he calls ’essential values’ of a
cylinder
flow. It follows from Theorem 5.2. in[Schmidt, 1976]
that essential values andperiods
are the same.Remarks: it is not difficult to see that
Ergodicity
of7§ and Sa
are related as follows.Sa
is a factor of7.
henceergodicity
of7" implies ergodicity
ofSa.
If a is aperiod
ofT,
and ifSa
isergodic
thenr
isergodic.
We shall use this observation later on.Ergodicity
ofTcp
is associated with thefollowing type
of functional equa- tion. Define- r :
{X ~
G: the functionalequation h o T = ~(~) h 03BB -
a.e. has a nontriv-ial measurable solution h :
R/Z ~ C}, and,
for a inG,
- A - a.e. has a nontrivial measurable
solution h :
R/Z~C}.
The sets r andra
aresubgroups.
LEMMA 0: Let a E
G, a =1=
0. ThenSa
isergodic if
andonly if fa
is trivial.Proof:
This result isclassical,
see[Anzai, 1951].
~THEOREM
1 If
c EPg,,
then F =0393c.
Proof: Clearly fc
is a subset of r. Let X be anarbitrary
element of f and let h be a nontrivial measurable solution of theequation hoT=~(~)h
A - a.e..The measurable function
f(x, t)=h(x)X(t)
is invariant underT~,
hencef(x,t
+c)
=h(x)X(t)X(c) = f(x, t)03BB~h-
a.e.. Thisimplies x(c)
=1, thus X belongs
to0393c.
DCOROLLARY: The
following
areequivalent:
i ) Tcp
isergodic;
ii) Pcp =1= {0}
and r is the trivialsubgroup of
G.We shall now
study example
1. We ask under which conditionsfor 03B2
and y willrl
be trivial( hence SI ergodic)
and 1 be aperiod of Tcp
=T~(03B2, 03B3).
II. A class of
cylinder
flowsWe shall consider the
following generalization
of the von Neumann-Kakutaniadding
machine transformation onR/Z.
Letq=(ql)l1
be a boundedsequence of
integers
qi,2 qi
K forall i,
with somepositive
constant K.If
A(q)
denotes thecompact
Abelian group ofq-adic integers,
then thetransformation
z ~ z + 1 on A(q) is uniquely ergodic
withrespect
to normal- ized Haar-measure onA(q) (see [Hewitt
andRoss, 1963]
for detailson A(q)).
Consider next the one-dimensional
torus R/Z
with Haar measure À. We shall writeIf
132
is an element
of A(q),
thenmod 1
belongs
toR/Z.
Themap 03A6: A(q) ~ R/Z
ismeasure-preserving
andinjec-
tive on
A(q) except
on a subset of Haar measure zero.The
q-adic representation
of an element x ofR/Z,
is
unique
under the conditionxl =1= ql+1 -1
forinfinitely
many il. We shall callx
non-q-adic
if x hasinfinitely
many nonzerodigits
xl. Theuniqueness
condition for the
representation
ensures that thefollowing
transformation T:R/Z ~ R17-
is well-defined:T is
ergodic
with respect to À andT 0 eV(z) = 03A6(z
+1)
for almost all z. For furtherproperties
of T see[Hellekalek, 1984].
T may be called a(generalized)
von Neumann-Kakutani
adding machine transformation (see [Petersen, 1983]).
A rational number
03B2
in]0, 1[, f3
=ris,
rand spositive integers, ( r, s)
=1,
is calledstrictly non-q-adic
ifkls is non-q-adic
for allk, 1 k
s -1;
equivalently,
if noprime
divisor of s divides an element of the sequence q.THEOREM 2: Let T be the
q-adic transformation defined
above and let99(x)
1 (x) - 03B2,
0f3
1. LetTcp
be thecylinder flow defined
inExample
1.Then the
following
areequivalent:
i) Tcp
isergodic;
ii) 03B2
is irrational orstrictly non-q-adic.
We can
generalize
this result to:THEOREM 3 : Let T be as in Theorem 2 and let
qg(x)
=1A(x) - 03B2, where
A is anarc in
R/Z of length 03B2,
003B2 1,
A = Y +[0, 6[ [mod
1 with0
03B3 1.Define
Tcp
as inExample
1. Theni) T~ ergodic implies 03B2
irrational orstrictly non-q-adic;
ii) 03B2
irrationalimplies T~ ergodic, for
all y;iii) 03B2 strictly non-q-adic
and Yq-adic (i.e.
y =a/p(g)
withnonnegative integers
a and g, ap(g)) imply Tcp ergodic;
iv)
ql = q 2for
alli,
and03B2 strictly non-q-adic imply T~ ergodic for
almost allY-
The
proof
of these two theorems will begiven by
Lemmata 1 to 6 and their corollaries. In Lemma 6 we will prove astronger
result thaniv)
of Theorem 3.In the
sequel
we shallwrite CPn
for the sum (p + cP 0 T+ ···+(p
oTn-1,
n = 1, 2 ...
Lemma 1 below indicates how to obtainperiods.
The idea is due to[Oren, 1983] (Proposition 1).
LEMMA 1: Let
(kn)~n=1 be a subsequence of (n)~n=1
and let(Akn)~n=1
be asequence
of
measurable subsetsof
R/Z
such thatn
i ) ~p(kn) is
constant onA k n
ii)
lim~p(kn)(Akn)
exists andiii ) inf 03BB(Akn)>0.
Then c = lim
cpp(kn)(Akn)
will be aperiod of T~.
Proof.-
Let1B
be anarbitrary T,-invariant
measurable function onR/Z 0
G.The set M =
f x E R/Z
such that1B(x, t)
=1B(x,
t +c)
for almost all t inG}
is invariant underT,
thus of measure 0 or 1. We shall find a subset of M ofpositive
measure. This will prove the lemma.Let
akn
=99p(kn) (Akn
andput gkn(X, t) = 11B(TP(kn)x,
t +akn) - 1B(x,
t +c)|.
LetXN
=R/Z
X[ - N, N ],
N apositive integer.
We notethat |Tp(k)x-
x | 1/p ( k )
for all x and allpositive integers k,
henceTherefore, by diagonalization,
we can find asubsequence (k’n)~n=1
of(kn)~n=1
such that lim
gk’n(x, t)
= 0 a.e. onR/Z ~
G. Let A = limsup Ak’n.
The set Ahas
positive
measure(condition iii))
and almost allelements of
Abelong
to M(conditions i)
andii)).
DLEMMA 2:
Ergodicity of T~ implies
that03B2
is either irrational orstrictly non-q-adic.
Proof.-
IfTcp
isergodic,
so is thecompact
factorSI, S1(x, t)
=(Tx, ( t
+~(x))
mod
1).
For everycharacter X
ofG/Z X( cp(x))
=~(-03B2 ) is
constant. There-fore
Il
is trivial(hence Si ergodic)
if andonly
if there are noeigenfunctions
ofT to the
eigenvaue ~(-03B2).
Theeigenvalues
of T are known to be of the formexp(203C0i03B1), 03B1 q-adic.
DLEMMA 3:
If 03B2 is non-q-adic
and Y isq-adic,
then 1 is aperiod of Tg,.
00
Proof.-
Theq-adic representation
of03B2
isgiven by 03B2 = 03A3 /3llp(i
+1)
withdigits 03B2i~{0,1,...ql+1-1}, infinitely
many03B2l~ql+1-1.
Define03B2(k)
k-1
= 03A3 f3ilp(i
+1),
k =1, 2, 3
... Then 003B2 - 03B2(k) 1/p(k)
for all k. If134
00
03B3 = 03A3 03B3i/p(1
+1),
theny(k)
= y for all ksufficiently large.
T is abijection
almost
everywhere
and mapselementary q-adic
intervals[a/p(k), (a+
1)/p(k)[, 0a p ( k ) - 1,
intoelementary q-adic
intervals oflength 1/p(k).
For any x
in M/Z exactly
onepoint Tjx,
0j p ( k ) - 1, belongs
to agiven elementary q-adic
interval. Forsufficiently large
k the function~p(k)
takesonly
two values onIR Ill, 1+03B2(k)p(k) -
03B2p(k)}.
LetAk={x:~p(k)(x)=(03B2(k)-03B2)p(k)}
and letBk
dénote itscomplement.
Theintegral
of the functionCPp(k)
is zero,hence 03BB(Ak)
= 1 -(03B2 -03B2(k))p(k) and 03BB(Bk)=(03B2-03B2(k))p(k). 03B2
hasinfinitely
many nonzerodigits f3i,
hence there issubsequence (in)~n=1
such that 003B2i
nand 03B2in+1
qin+2 -
1. Thisimplies 1/K (f3 - 03B2(in))p(in)
1 -11K2. Theref ore we
canfind
asubsequence (kn)~n=1
of(in)~n=1
such that 0 lim(03B2 - 03B2(kn))p(kn)
1. We
apply
lemma 1 to the sequences of sets(Akn)j
and(Bkn)~n=1
andobtain that 1 is a
period
ofT~.
DCOROLLARY:
If 03B2 is strictly non-q-adic
thenTcp is ergodic for
allq-adic
y.LEMMA 4:
If 03B2
isnon-q-adic
thenthe set {1, 2}
containsa period of T~ for
every03B3.
Proofo
Let A = y +[0, 03B2[ mod 1, 0
y1, and ~(x)
=1A(x) - f3.
In view ofLemma 3 we are
only
interested innon-q-adic
y. Let 8 = y +03B2
mod 1. Weshall assume that 8 is
non-q-adic,
otherwise Lemma 3applies.
Letinfinitely
manydigits 03B3l ~ qi+1 -1, infinitely
many03B4l~ql+1-1.
We shalldenote
by 03B3(k)
and03B4(k)
therepresentations
truncated at k(see
Lemma3).
Elementary
calculations as in Lemma 3 show that for all x,~p(k)(x)~{yk,yk -1, yk+1},
whereyk=(03B3-03B3(k))P(k)-(S-S(k))P(k) yk~{(03B2(k)- 03B2)p(k), i+(03B2(k)-03B2)p(k)}.
LetAk={x~R/Z: ~p(k)(x)=yk}, Bk =
( x : ~p(k)
= uk -1}
andCk
=f x : CPp(k)
= yk +1}.
As theintegral
of (p is zero, therelation À (Bk)
= yk+ 03BB(Ck)
holds. We shall check if conditionsii)
andiii)
of Lemma 1 can be satisfied.
- Condition
ii):
it is clear from theproof
of Lemma 3 that there is a sequence(kn)~n=1
such that 0 limyk n 1;
- Condition
iii):
due to the above relationbetween 03BB(Bk) and 03BB(Ck)
we canalways
find a suitablesubsequence (k’n)~n=1
of(kn)~n=1
such that conditioniii)
holds for(Ak’n)~n=1
and one of(Bk’n)~n=1
or(Ck’n)~n=1 (which implies
that1 is a
period)
or(Bk’n)~n=1
and(Ck’n)~n=1 (which implies
that 2 is aperiod).
LEMMA 5:
If 03B2 is irrational,
thenTcp
isergodic for
all Y.Proof.-
Weonly
have to show thatS2
isergodic,
i.e. thatf2
is trivial. Let X bean
arbitrary
element ofr2
and let h be a nontrivial measurable solution of the functionalequation
h oT = ~(~)
h a.e.. Thenh2 o T=~2(~) h2,
hencex 2 belongs
toIl. Si
isergodic
forirrational f3
and thus the latter group is trivial.Hence X
is the trivial character ofR/2Z.
0The
argument employed
in Lemma 5 is not valid forstrictly non-q-adic 03B2:
fora nontrivial
character X
in can be trivial inG/Z.
It is not difficultto see that
r2
would be trivial if the functionalequation
h·T=03A6h a.e.,03A6(x)=1 on A and (D (x) 1 on
thecomplément R/Z-A,
had no nontrivialmeasurable solution h.
LEMMA 6: Let
03B2
be rational andnon-q-adic. If
there is astrictly increasing
sequence
(in)~n=1
suchthat, for
all n,f3i =1= 0, f31 +l ql +2 - 1, in+1 - in
Lwith a constant
L,
then 1 is aperiod of T; for almost
ally in R/Z.
Proof.-
We shall take as basis theproof
of Lemma 4. Hence we assume that y and03B4 = 03B4(03B3) = 03B3 + 03B2
mod 1 arenon-q-adic.
It will be shown that for almost every y there is asubsequence (kn)~n=1
of(in)~n=1
such that conditionsii)
andiii)
of Lemma 1 are satisfied. It is then easy to deduce from Lemma 4 that 1 isa period of T~=T~(03B2,03B3).
Let 1 be an
elementary q-adic
interval oflength 1/p(k), I=[a/p(k), (a+1)/p(k)[,0ap(k)-1.
Choose iand j, 0 i, j p ( k ) - 1
suchthat
03BB(TlI0394[03B3(k), y(k)
+1Ip(k)[)
=0, À(TJId[8(k), 8(k)
+1Ip(k)[)
= 0.We write
DI = T-1]03B3(k), y[, EI = T-J]03B4(k), 8[. DI and Ei
are subsets of I and thefollowing
relations hold:Therefore Let ak and
bk
be thoseintegers with (D(ak)=y(k) and 03A6(bk)=03B4(k).
Then0 ak, bk p (k) - 1
forsufficiently large k
andak+1=ak+03B3kp(k), bk+1=bk+
8kP(k).
Let a be anarbitrary integer
such that0 a min(ak, bk).
If weconsider the
elementary
interval I =I(a)
=[03A6(a), 03A6(a)
+1/p(k)[,
then thecondition
a min(ak, bk ) implies
thatDi and EI
areintervals, DI=]03A6(a), 03A6(a)+03B3-03B3(k)[, EI=]03A6(a), 03A6(a)+03B4-03B4(kl)[.
Thisyields
thefollowing
estimate
for 03BB(Ak):
It is
1/K2 1-|yin|
1 -11K2 thus only min(aln,bln)/p(in) requires
fur-ther
study.
We see that andWe
study
F =(y
inR/Z: 03B3in03B4in ~ 0
forinfinitely
manyn}.
If ybelongs
toF,
then there is asubséquente (kn)~n=1
of(in)~n=1
such thatinf 03BB(Akn) 1/K2+L >
0. Hence conditioniii)
of Lemma 1 is satisfied. Conditionii)
willhold for a suitable
subsequence.
136
It is
elementary
to show that the set F is invariant under T.Thus À (F)
iseither zero or one. One
calculates 03BB({03B3 :
yl8i ~ 0}) 1 /3
ifqin+1
3 and thatit is
equal
to(03B2 - 03B2(in))p(in) - 1/2
ifqln+1 =
2. One deducesthat À(F)
= 1.COROLLARY: With the additional
assumption
that03B2
bestrictly non-q-adic
Lemma 6
implies
thatTcp
isergodic for
almost all y.COROLLARY:
Suppose
that qi = q 2for
alli,
q aninteger. If 03B2
isstrictly non-q-adic
thenT,
isergodic for
almost all y.Proof.-
Theq-adic representation
of rational numbers isperiodic.
As03B2
isstrictly non-q-adic, ,Sl
isergodic
and further there is a sequence(in)~n=1
whichsatisfies the conditions of Lemma 6.
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