• Aucun résultat trouvé

L’INSTITUTFOURIER DE ANNALES

N/A
N/A
Protected

Academic year: 2022

Partager "L’INSTITUTFOURIER DE ANNALES"

Copied!
26
0
0

Texte intégral

(1)

A L

E S

E D L ’IN IT ST T U

F O U R

ANNALES

DE

L’INSTITUT FOURIER

Cyril DEMARCHE,

Giancarlo LUCCHINI ARTECHE & Danny NEFTIN

The Grunwald problem and approximation properties for homogeneous spaces

Tome 67, no3 (2017), p. 1009-1033.

<http://aif.cedram.org/item?id=AIF_2017__67_3_1009_0>

© Association des Annales de l’institut Fourier, 2017, Certains droits réservés.

Cet article est mis à disposition selon les termes de la licence CREATIVECOMMONS ATTRIBUTIONPAS DE MODIFICATION3.0 FRANCE. http://creativecommons.org/licenses/by-nd/3.0/fr/

L’accès aux articles de la revue « Annales de l’institut Fourier »

(http://aif.cedram.org/), implique l’accord avec les conditions générales d’utilisation (http://aif.cedram.org/legal/).

cedram

Article mis en ligne dans le cadre du

(2)

THE GRUNWALD PROBLEM AND APPROXIMATION PROPERTIES FOR HOMOGENEOUS SPACES

by Cyril DEMARCHE,

Giancarlo LUCCHINI ARTECHE & Danny NEFTIN (*)

Abstract. — Given a groupGand a number fieldK, the Grunwald problem asks whether given field extensions of completions of K at finitely many places can be approximated by a single field extension ofK with Galois groupG. This can be viewed as the case of constant groups Gin the more general problem of determining for whichK-groupsGthe variety SLn/Ghas weak approximation. We show that away from an explicit set of bad places both problems have an affirmative answer for iterated semidirect products with abelian kernel. Furthermore, we give counterexamples to both assertions at bad places. These turn out to be the first examples of transcendental Brauer–Manin obstructions to weak approximation for homogeneous spaces.

Résumé. — Pour un groupe G et un corps de nombres K, le problème de Grunwald est le suivant : étant données des extensions des complétés deKen un ensemble fini de places, peut-on les approcher de façon simultanée par une seule extension deK de groupe de GaloisG? Cela peut être interprété comme un cas particulier de la question plus générale de déterminer pour quelsK-groupesGla variété SLn/Gvérifie l’approximation faible. Nous démontrons qu’en dehors d’un ensemble explicite de mauvaises places, ces deux problèmes ont une réponse positive pour les groupes obtenus par des produits semi-directs itérés à noyau abélien. En outre, nous donnons des contre-exemples aux deux affirmations dans l’ensemble des mauvaises places. Ceux-ci sont par ailleurs les premiers exemples d’obstructions de Brauer–Manin transcendantes à l’approximation faible pour les espaces homogènes.

Keywords:Grunwald problem, Galois cohomology, homogeneous spaces, weak approxi- mation, Brauer–Manin obstruction.

Math. classification:11R34, 14M17, 14G05, 11E72.

(*) The first author acknowledges the support of the French Agence Nationale de la Recherche (ANR) under reference ANR-12-BL01-0005. The second author’s work was partially supported by the Fondation Mathématique Jacques Hadamard through the grant No ANR-10-CAMP-0151-02 in the “Programme des Investissements d’Avenir”.

The third author’s work was supported by the National Science Foundation under Award No. DMS-1303990 and the Israel Science Foundation under grant No. 577/15.

(3)

1. Introduction

The Grunwald–Wang theorem has fundamental applications to the struc- ture theory of finite dimensional semisimple algebras, cf. [12, Ch. 18], and provides an answer for abelian groups G to the more general Grunwald problem. The latter is an inverse Galois problem of increasing interest due to its recently studied connections with the regular inverse Galois problem and with weak approximation, cf. [3, 6].

Fix a number field K, let Kv denote the completion ofK at a place v, and Gal(K) denote its absolute Galois group. LetGbe a finite group, and S a finite set of places of K. The Grunwald problem then asks whether every prescribed local Galois extensionsL(v)/Kv, vS, with embeddings Gal(L(v)/Kv),Gcan be approximated by a global extensionL/K with Galois groupG. More precisely:

Grunwald Problem. — Is the restriction map Hom(Gal(K), G)→ Y

v∈S

Hom(Gal(Kv), G)/∼

surjective?

Here φ1φ2 ifφ1=2g−1for some gG. Note that the quotient by

∼is necessary since the decomposition group of a placev of K is defined up to conjugation.

Families of groupsGand number fieldsK for which (G, K, S) has an af- firmative answer to the Grunwald problem for everyS include: (1) abelian groups of odd order over every number field, by the Grunwald–Wang the- orem [5, 16]; (2) solvable groups of order prime to the number of roots of unity inK, by Neukirch’s theorem [10]; and (3) groups with a generic extension overK, by Saltman’s theorem [13].

Recent results by Dèbes-Ghazi on the inverse Galois problem [3] and by Harari on weak approximation for homogeneous spaces [6], suggest that for every finite groupGthere exists a finite setT :=T(G, K) of “bad places” of Ksuch that the Grunwald problem has an affirmative answer for (G, K, S) for every set S that is disjoint from T. In fact, the existence of such a set T is implied by a conjecture of Colliot-Thélène on the Brauer–Manin obstruction for rationally connected varieties. The connection is done by considering the following more general version of the Grunwald problem for finiteK-groups G.

(4)

Approximation property. — A K-group G has (weak) approxima- tionin a setS of places of Kif the natural restriction map

H1(K, G)→ Y

v∈S

H1(Kv, G),

is surjective. We shall say G has approximation away from T, if G has approximation in S for every finite set S of places of K that is disjoint fromT.

The approximation property for every finite S ⊂ ΩK is equivalent to weak approximation for certain homogeneous spaces (hence its name), see Section 2.5. Moreover, for constant groupsG, it is equivalent to a positive answer to the Grunwald problem for (G, K, S), see Section 2.3.

The existence of a finite set T of “bad places” away from which the approximation property holds is expected to hold for arbitrary finite K- groups, and is strongly related with arithmetic properties of homogeneous spaces. Moreover, the existence of such a set T for K-groups has been proved over arbitrary number fields K for: (1) abelian K-groups G by Wang, cf. [16]; (2) iterated semidirect productsG=A1o(A2o· · ·oAr) of abelianK-groups by Harari, cf. [6]; and (3) solvableK-groupsGof order prime to the number of roots of unity in an extension ofK splittingGby the second author (hereT =∅, cf. [8]).

Ever since Wang’s work on the subject, triples (G, K, S) having a neg- ative answer to the Grunwald problem (and thus not having the approxi- mation property) are known to exist. However, it is unclear what the set T =T(G, K) should be. In fact, there is no explicit description of a setT even for basic groups such as semidirect products of two abelianp-groups.

This paper gives both affirmative and negative answers to the Grun- wald problem and the approximation property, suggesting that the set T =T(G, K) can always be taken to be the union of the places ofKwhich divide the order of G and those which ramify in the minimal extension splittingG.

1.1. Main results

We give a precise description of the set T of “bad places” for iterated semidirect products of abelian groups, complementing Harari’s result [6, Thm. 1].

Theorem 1.1. — LetK be a number field andG be a finiteK-group which is an iterated semidirect productG=A1o(A2o· · ·oAr)of abelian

(5)

K-groups. Let L/K be an extension splitting G, and T the set of places that either divide the order ofG, or ramify inL. ThenGhas approximation away fromT.

If G is constant, L=K and hence the only condition on placesvS is to be prime to the order of G. The Grunwald problem has then an affirmative answer for such (G, K, S). The family of iterated semidirect products of abelian groups contains the dihedral groups, the Heisenberg groups of orderp3, and the p-Sylow subgroups of the symmetric groups, cf. [17], of GLn(Fq), and of other classical groups over Fq whenqis prime top, cf. [7].

In an opposite scenario, whenSconsists of the primes ofK dividing the order ofGandGis constant, we give the following examples in which the approximation property doesn’t hold. Recall that abicyclic group is either cyclic or a direct product of two cyclic groups.

Theorem 1.2. — Let K be a number field and G a finite abelian p- group that is not bicyclic. Assume that G is a Galois group over some completion ofK (which a fortiori divides p) and let S be the finite set of places of K lying above p. Then there exists an abelian G-module A (of order a power ofp) such that if we consider E := AoG as a constant K-group and Kcontains sufficiently many roots of unity, the map

H1(K, E)→ Y

v∈S

H1(Kv, E),

is not surjective.

In contrast to Wang’s counterexamples, here the set S consists of the primes ofK dividing any given rational prime p, as requested in [3, Sec- tion 1.6] by Dèbes-Ghazi. Examples of constantp-groups that do not admit the approximation property at the places dividing a given prime p were also given over K =Q(µp) by the first author in [4, §6, Prop. 2], where an algebraic Brauer–Manin obstruction to the approximation property is given. However, in contrast with [6, §5], [4] and [9, §5.2], which study algebraic Brauer–Manin obstructions, Theorem 1.2 provides examples in which the approximation property doesn’t hold and the algebraic Brauer–

Manin obstruction vanishes, givingthe first examples of a transcendental Brauer–Manin obstruction to weak approximation on homogeneous spaces, see Example 5.4.

(6)

1.2. Tame problems

The above results suggest that the answer to the Grunwald problem is affirmative away from a particular set of bad primes:

Tame approximation problem. — Does the approximation property hold for every finiteK-group Gand every finite setS of places ofK that are prime to its order and are unramified in an extension splittingG?

Here we do not consider the extension C/R to be ramified, hence the question aboutreal approximation(i.e. having the approximation property for the setSof archimedean places), asked years ago by Borovoi, is included in this last one.

Negative answers to these questions are unknown, and a complete af- firmative answer is currently out of reach, as it implies a solution to the inverse Galois problem (see [6, §4]). In view of Theorem 1.1 and its proof, it seems reasonable to conjecture that the answer is affirmative for all solvable groups.

Acknowledgements

The authors would like to thank David Harari for being at the origin of this collaboration. The third author would like to thank Pierre Dèbes, David Saltman, Nguyêñ Duy Tân and Jack Sonn for helpful discussions.

2. Preliminaries

2.1. Global and local Galois groups

All throughout this text, K denotes a number field, ΩK is the set of places ofKand, forv∈ΩK,Kvdenotes the completion ofKinv. For any Galois extension L/K we denote by Gal(L/K) the corresponding Galois group, and by Gal(K) the absolute Galois group. Throughout the text, we fix an embedding of Gal(Kv) in Gal(K) and identify it with its image for eachv∈ΩK.

For a finite placev∈ΩK, letKvtr be the maximal tamely ramified exten- sion ofKv, let Γv := Gal(Kvtr/Kv) be the tame Galois group and Wv :=

Gal(Kvtr) the wild ramification group. Recall that the tame inertia group Tv := Gal(Kvtr/Kvun) is a procyclic normal subgroup of Γv of order prime

(7)

tov; Letτv be a generator ofTv. The quotient Γv/Tv∼= Gal(Kvun/Kv)∼= ˆZ is generated by a liftσv of the Frobenius automorphism.

We let σv ∈ Γv be a preimage of σv. Note that σv is defined up to conjugation and that its action by conjugation on Tv is equivalent to its action on roots of unity, that is,σvτvσ−1v =τvqv whereqv is the cardinality of the residue field ofKv, see [11, §7.5].

For archimedean v, letσv be the generator of Gal(Kv) and putτv = 1, so that Γv:= Gal(Kv) andTv =hτvi={1}.

2.2. K-groups

A finiteK-groupGis a finite group scheme overK. SinceKis of charac- teristic 0, there is an equivalence of categories between finite group schemes overK and finite Gal(K)-groups. Identifying the two, we shall writeGfor the set of its geometric points. An extension L/K is said to split G if G×KL is a constant L-group, i.e. if the Galois group Gal(L) ⊂Gal(K) acts trivially onG. We also need the following notion of “bad places” for suchG:

Definition 2.1. — LetKbe a number field,Gbe a finiteK-group and L/K the minimal extension splittingG. We define the set of “bad places”

BadG ⊂ΩK as the union of the set of places dividing the order ofG and the places ramified inL/K.

Note that the minimal extension splitting G always exists. Indeed, the action of Gal(K) onGis a (continuous) morphism Gal(K)→Aut(G) and the minimal extension splittingGis given by the kernel of this morphism.

2.3. Cohomology

Recall [14, I, §5] that for a field K and aK-group G, the set H1(K, G) is defined as the quotient of the set of 1-cocycles (also calledcrossed ho- momorphisms)

Z1(K, G) :={a: Gal(K)→Gcontinuous|aστ=aσσaτ,σ, τ∈Gal(K)}, by the equivalence

ab ⇔ ∃gGsuch thataσ=gbσσg−1,σ∈Gal(K).

(8)

Hence for aconstant K-group G, the set H1(K, G) is the set of continuous group homomorphisms Gal(K)→Gmodulo conjugation inG. In particu- lar, the Grunwald problem for (G, K, S) is equivalent to the approximation property forGconstant. IfL/Kis an extension splittingG, then Gal(L/K) acts onGand one may similarly define the set H1(L/K, G), which embeds intoH1(K, G) by inflation.

A class α∈H1(K, G) is denoted by [a] if it corresponds to the class of the cocycle a. For α ∈ H1(K, G), we denote by αv its image under the restriction map Resv: H1(K, G)→H1(Kv, G).

2.4. Twisting

We recall briefly the basic properties of twisting. For further details see [14, §I.5]. Let Γ be a profinite group and G be a discrete Γ-group.

Assume thatGand Γ act both on the left on some objectX in a compati- ble way, that is, (σ g·x) =σg·σxforσ∈Γ, gG,xX. Given a cocycle aZ1(Γ, G), define a new action of Γ onX bytwisting the first action as follows:

σ∗x:=aσ·σx.

Such a twisted object, denoted byaX, still has an action of G. However, the latter is not necessarily compatible with the action of Γ. To fix this, one twists also the action of Γ onG. To do so it suffices to viewGas acting on itself by conjugation, and repeat the same construction, so that

σ∗g:=aσσga−1σ .

This twist ofG, denoted byaG, is a Γ-group which acts onaX compatibly with the Γ-action.

This construction takes principal homogeneous spaces under Gto prin- cipal homogeneous spaces under aG. More precisely, one has [14, I.5.3, Prop. 35bis]:

Proposition 2.2. — LetaZ1(Γ, G)and letG0 =aG. The map ta:Z1(Γ, G0)→Z1(Γ, G) :a07→(σ7→a0σaσ),

is a bijection which moreover induces a bijection τa: H1(Γ, G0)→H1(Γ, G),

sending the trivial element ofH1(Γ, G0)to the class of ain H1(Γ, G).

(9)

An exact sequence of Γ-groups such as 1→HEG→1 gives rise to an exact sequence of pointed sets, cf. [14, I.5.5, Prop. 38]:

(2.1) H1(Γ, H)→H1(Γ, E)→H1(Γ, G),

which means that the elements in H1(Γ, E) falling onto the trivial element of H1(Γ, G) are precisely those coming from H1(Γ, H).

Let eZ1(Γ, E) and let g be its image inZ1(Γ, G). To study the fiber of the class [e]∈H1(Γ, E), that is, the fiber above [g]∈H1(Γ, G), one uses twisting. SinceE acts onE, onGand onH by conjugation, one may twist all three groups bye, getting an exact sequence

1→eHeEeG→1

and the following commutative diagram of pointed sets with exact se- quences:

H1(Γ, H) //H1(Γ, E) //

τe−1

H1(Γ, G)

τg−1

H1(Γ, He ) //H1(Γ, Ee ) //H1(Γ, Gg ).

Note that the twisted form of Gis denoted by gGinstead of eG, since E acts onGvia its own image inG. Since the lower row is exact and since the τ’s are bijections sending [g] and [e] to the trivial elements, we now know that the fiber over [g] is in bijection with the image of the set H1(Γ, He ) in H1(Γ, Ee ). Note also that in general there is no vertical arrow at the level ofH (as Proposition 2.2 applies only to twists by a group acting on itself by conjugation).

Two elements in H1(Γ, H) are mapped under (2.1) to the same element of H1(Γ, E) if and only if they lie in the same orbit of H0(Γ, G), [14, I.5.5, Prop. 39]. Here an elementg∈H0(Γ, G) =GΓacts on H1(Γ, H) by sending a class [a]∈H1(Γ, H) to the class of the cocycle

(2.2) (g·a)σ=eaσσe−1

whereeE is a preimage ofg.

2.5. Homogeneous spaces

Let us now recall the notion of weak approximation forK-varieties. LetX then be a (smooth, geometrically integral)K-variety such thatX(K)6=∅.

(10)

Definition 2.3. — LetS⊂ΩK be a finite set of places of K. We say thatXhasapproximation inSifX(K)is dense in the productQ

SX(Kv).

We say that X has weak approximation away from T ⊂ ΩK if X has approximation inSfor all finiteS⊂ΩKrT. Equivalently, one can demand X(K) to be dense in the product Q

KrTX(Kv). The set T is usually refered to as the set of “bad places”.

We say thatX hasweak approximationif one can takeT =∅.

Let us briefly recall the Brauer–Manin obstruction to weak approxima- tion, cf. [15, §5.1] for details. For X a (smooth, geometrically integral) K-variety, consider its unramified Brauer group BrunX, as well as the sub- group of its “algebraic” elements Brun,alX:= ker[BrunX→Brun(X×KK)].¯ Denote, forv∈ΩK, invv: BrKv→Q/Zthe Hasse invariant map. Finally, denote byX(K) the product Q

KX(Kv) in whichX(K) embeds diago- nally. Then one can define the setX(K)Brun (resp.X(K)Brun,al) as the subset of all families of points (Pv)v∈ΩKX(K) such that

X

v∈ΩK

invv(α(Pv)) = 0, for allα∈BrunX (resp.α∈Brun,alX), whereα(Pv)∈BrKv denotes the evaluation ofαat the point Pv and the sum, which a priori is infinite, is actually finite for elements α∈ BrunX. The following inclusions then hold:

X(K)⊆X(K)BrunX(K)Brun,alX(K).

IfX(K)Brun 6=X(K) (resp.X(K)Brun,al 6=X(K)) one says that there is a Brauer–Manin obstruction (resp. an algebraic Brauer–Manin obstruc- tion) to weak approximation. A Brauer–Manin obstruction that is not al- gebraic is called transcendental.

A conjecture by Colliot-Thélène [1, Introduction] says that the Brauer–

Manin obstruction to weak approximation should be the only obstruction for rationally connected varieties, that is,X(K) =X(K)Brun. Now, given a finiteK-groupG, one can always embed it into SLnfor somenand con- sider the homogeneous spaceX = SLn/G, which is unirational (since SLn

is itself a rational variety) and hence rationally connected. In [6, Thm. 1], Harari proved that ifGis an iterated semidirect product of abelian groups, then we do haveX(K) =X(K)Brun. The fact that this theorem implies the approximation property away from a finite setTof places as we claimed in §1 follows from the finiteness of BrunX/BrK, cf. [2, Prop. 5.1(iii)], and from [6, §1.2] or [8, §1]:

(11)

Proposition 2.4. — LetGa beK-group embedded intoSLn and put X := SLn/G. Let S ⊂ ΩK be a finite set of places of K. Then X has approximation inS if and only if the natural map

H1(K, G)→ Y

v∈S

H1(Kv, G), is surjective.

Note that this result proves in particular that approximation properties for varieties such asX = SLn/G depend only onG, i.e. they are indepen- dent of the embedding ofGand even on the dimension ofX since there is no condition onn, justifying the definition of the approximation property in §1.

The tame approximation problem is thus equivalent to determining whetherG(orX = SLn/G) has weak approximation away fromT = BadG. Note that a positive answer to this question does not necessarily imply a positive answer to Colliot-Thélène’s conjecture forX = SLn/G. Conversely, if the conjecture were true, we would only get the existence of a finite set TBr of bad places. However, not enough is known on the unramified Brauer group ofX in order to show that TBr = BadG.

2.6. Poitou–Tate

We next recall the obstruction to weak approximation for finite abelian K-groups. Let Abe a finite abelianK-group and let ˆA= Hom(A,Gm) be its Cartier dual, which is also a finite abelianK-group.

Let Kvun denote the maximal unramified extension and Kvtr its max- imal tamely ramified extension. Recall [14, II, §6] that for every finite place v such that Gal(Kvun) acts trivially on A, the unramified cohomol- ogy H1un(Kv, A) is defined as the image of the group H1(Kvun/Kv, A) un- der inflation to H1(Kv, A). One can consider then the restricted product Q

`

KH1(Kv, A) with respect to these subgroups. It is well known that the product of the restriction maps Resvsends H1(K, A) intoQ`

KH1(Kv, A).

A classical result by Poitou and Tate [14, II.6.3] gives a perfect pairing

(2.3) Ya

K

H1(Kv, A)×Ya

K

H1(Kv,A)ˆ →Q/Z,

defined via local pairings and such that the image of H1(K, A) is the orthog- onal complement of the image of H1(K,A) for this pairing. A classic con-ˆ sequence of these is the following well-known proposition [11, Lem. 9.2.2].

(12)

For a subsetSof ΩK, letX1S(K, G) :={α∈H1(K, G)|αv= 1, ∀v6∈S}, and letX1(K, G) :=X1(K, G).

Proposition 2.5. — LetA be a finite abelian K-group and S ⊂ΩK

be a finite set of places. Then there is a pairing Y

v∈S

H1(Kv, A)×X1S(K,A)ˆ →Q/Z,

such that its right kernel is X1(K,A)ˆ and its left kernel is the image of the restriction map

H1(K, A)→ Y

v∈S

H1(Kv, A)

In particular,Ahas approximation inSif and only ifX1S(K,A) =ˆ X1(K,A).ˆ We shall use the following property of X1S(K,·) to descend to finite extensions:

Lemma 2.6. — LetAbe a finite abelianK-group. LetL/Kbe a Galois extension splittingA. Then for any finiteS⊂ΩK,X1S(K, A)is contained in the image ofH1(L/K, A)by the inflation map.

Proof. — Since Gal(L) acts trivially on A, we have the following com- mutative diagram with exact rows:

1 //H1(L/K, A) inf //H1(K, A)

Res //H1(L, A)

Y

v∈ΩK

H1(Kv, A) Res // Y

w∈ΩL

H1(Lw, A).

SinceLsplitsA, the H1’s on the right hand side of the diagram are actually groups of homomorphisms. Restricting a classα∈X1S(K, A) to H1(L, A), we get a homomorphism Gal(L)→Athat is trivial everywhere locally ex- cept for the finitely manyw∈ΩL that lie aboveS ⊂ΩK. By Chebotarev’s density theorem it is the trivial morphism. Thus by exactness, α comes

from H1(L/K, A).

3. Reocurrence

The main idea in proving Theorem 1.1 is to show that, given a finite K-group G of order n and a finite place v 6∈ BadG, there are infinitely

(13)

many other placeswsuch that H1(Kv, G)∼= H1(Kw, G). In the particular case of a constant group, this infinite set of places will only depend onv andn. Hence, for a place v prime to n, a group Gof ordern will appear as a Galois group overKv if and only if it appears overKw.

Let us start by proving that, for finite places not in BadG, the set H1(Kv, G) depends only on the tamely ramified part Γv = Gal(Kvtr/Kv).

Recall that Γv is generated by a liftσv of the Frobenius and a generator of the inertia groupτv, as in §2.1. For every placev, we fix a choice ofσv andτv and keep it all throughout the text.

Lemma 3.1. — Let G be a finite K-group of order n and letv ∈ΩK be a place outsideBadG. Denote by Tvn the subgroup ofΓv generated by τvn. Then there is an isomorphism H1(Kv, G) ∼= H1v/Tvn, G) given by inflation.

Proof. — The statement is trivial for archimedeanv, so we may assume that v is finite. Since the wild ramification subgroup Wv 6Gal(Kv) acts trivially onG, the inflation-restriction sequence gives:

1→H1v, G)inf−→H1(Kv, G)−−→Res H1(Wv, G),

and H1(Wv, G) is the set of morphisms WvGup to conjugation. Since Wv is a pro-p group with p not dividing n, there are no such nontrivial morphisms and hence H1(Kv, G)∼= H1v, G).

Consider now a classα∈H1v, G). Sincevis unramified in the minimal extension splittingG, Tv also acts trivially onG and henceαrestricts to a morphism (up to conjugation) fromTv to G. It is then evident that this morphism is trivial overTvn. The same inflation-restriction argument then gives

H1(Kv, G)∼= H1v/Tvn, G).

The following reocurrence result generalizes the statement given in the beginning of the section.

Proposition 3.2. — Let G be a finite K-group of order n, L/K a Galois extension splitting G and let v ∈ ΩK be either an archimedean place or a finite place which is unramified in L and does not divide n (in particular, v 6∈ BadG). Then there exist infinitely many finite places w6∈BadG for which:

(1) the decomposition groups ofv andwinGal(L/K)are conjugate;

(2) there is an epimorphism φ : Γw/Twn Γv/Tvn given by φ(σw) = σv, φ(τw) = τv, which is moreover an isomorphism ifv is finite.

(14)

The epimorphismφinduces a monomorphismφ: H1(Kv, G),→H1(Kw, G), which is moreover an isomorphism ifvis finite.

Proof. — By Chebotarev’s density theorem applied to the Galois exten- sionL(µn)/K (which is unramified in v) there are infinitely many places w6∈BadGfor which the image of the decomposition group in Gal(L(µn)/K) is generated by the image of σw and is conjugate to the image of σv. In particular, we get that these groups are conjugate in Gal(L/K).

If v is finite, the images of σv and σw coincide in the quotient Gal(K(µn)/K) and hence their residue degrees qv, qw, respectively, are congruent modn. Moreover, recall that the group Γv/Tvnhas the following presentation:

v, τv|σvτvσv−1=τvqv, τvn = 1i.

Since qwqv modn, we get an isomorphism φ : Γw/Twn → Γv/Tvn by settingφ(σw) =σvandφ(τw) =τv. Ifvis archimedean, the same definition gives an epimorphismφ: Γw/Twn→Gal(Kv) sinceσ2v=τv= 1.

Let ρ ∈ Gal(K) be an element for which σw coincides with ρσvρ−1 in Gal(L/K). Denote byρGthe Kv-group where σ∈Gal(Kv) acts on Gby g7→ρσρ−1gand note that this action coincides with that of Gal(Kw) onG.

Consider the maps

H1v/Tvn, G)−→ρ H1v/Tvn, Gρ ) φ

−→H1w/Twn, G),

whereρ is a canonical isomorphism defined at the level of cocycles by the identity on Γv/Tvnand by sendinggGtoρg. We abusively denote byφ the whole composition. Then evidentlyφ is an isomorphism if v is finite and injective as an inflation morphism ifv is archimedean. Recall finally that by Lemma 3.1, we have H1(Kv, G)∼= H1v/Tvn, G) for finitev and Γv/Tvn = Gal(Kv) for archimedean v, hence the result.

We finally give a particular application necessary for the proof of Theo- rem 1.1:

Lemma 3.3. — Let G, L/K, v, w, φ and φ be as given by Proposi- tion 3.2. Letα∈H1(Kv, G)and assume that there exists a classβ= [b]∈ H1(K, G)such that βv =α,βw=φαand such that the group morphism Gal(L)→Gobtained by restriction ofbtoGal(L)is surjective. Denote by L0 the extension defined by the kernel of this morphism. Then the decom- position groups ofv andwinGal(L0/K)are conjugate.

We first note that L0/K is indeed Galois:

(15)

Lemma 3.4. — Let G be a K-group and L/K be a Galois extension splittingG. LetbZ1(K, G)and L0/Lbe the field fixed by the kernel of the restriction ofbto Gal(L). ThenL0 is Galois overK.

Proof. — Letτ∈Gal(L0) andσ∈Gal(K). Then bστ σ−1=bσσbτστ σ−1b−1σ .

SinceL/K is Galois and τ ∈Gal(L0)⊆Gal(L), we get στ σ−1 ∈Gal(L), hence it acts trivially onbσ. Asbτ= 1 by definition ofL0, we getbστ σ−1= 1, which proves thatστ σ−1∈Gal(L0) and thusL0/K is Galois.

Proof of Lemma 3.3. — We first show that the decomposition groups ofvand win Gal(L0/K) are quotients of Γv/Tvn and Γw/Twn. Indeed, this holds for archimedeanvsince Gal(Kv) = Γv/Tvn. For finitevandw,L0/Kis tamely ramified sinceL/K is unramified andL0/Lis of degreenand hence prime tov andw. Since the restriction ofbtoTv andTwis a morphism, it must be trivial onTvn andTwn, i.e.Tvn, Twn⊂Gal(L0), proving the claim.

Denote then (abusively) by σv, σw, τv, τw, the images in Gal(L0/K) of these elements. Recall that by the proof of Proposition 3.2, there exists an elementρ∈Gal(K) such thatσw coincides withρσvρ−1 in Gal(L/K).

Also note thatρτvρ−1 = τw = 1 in Gal(L/K). We claim that we may choose ρ so that bρ = 1. Note that bχρ = bχbρ for χ ∈ Gal(L). Since b is surjective when restricted to Gal(L), there exists χ∈Gal(L) such that bχ = b−1ρ so that bχρ = 1. Since χ ∈ Gal(L), we have that σw coincides with (χρ)σv(χρ)−1 in Gal(L/K), proving the claim.

The isomorphism φ between H1(Kv, G) and H1(Kw, G) is given at the level of cocycles by the morphismsρ :GG andφ: Γw/Twn →Γv/Tvn, which satisfy ρ(g) = ρg, φ(σw) = σv, and φ(τw) = τv. In particular, if α = [a] for aZ1v/Tvn, G), then φα = [a0] with a0σ

w = ρaσ

v and a0τw=ρaτv.

Now, since βv =α and βw = φα, we know that there exist g, g0G such that

ρ(

gbσvσvg−1) =ρaσv =a0σw =g0bσwσwg0−1,

ρ(

gbτvg−1) =ρaτv =a0τw=g0bτwg0−1.

Sincebrestricted to Gal(L0/L) is an isomorphism by hypothesis, there are uniqueχ, χ0 ∈Gal(L0/L) such thatbχ =g,bχ0 =g0, so that

(3.1) ρbχρbσvρσvb−1χ =bχ0bσwσwb−1χ0,

ρb

χρbτvρb−1χ =bχ0bτwb−1χ0.

(16)

Note now that sincebρ= 1, we havebρηρ−1 =ρbη for everyη∈Gal(L0/L), so in particular forη=χ, τv, andχ−1. Noting that

ρGal(L0/L)ρ−1⊆Gal(L0/L),

sinceL/K is Galois, that the restriction of bto Gal(L0/L) is a homomor- phism, and puttingρ0:=χ0−1ρχ∈Gal(L0/K), (3.1) givesbρ

0τvρ−10 =bτw and henceρ0τvρ−10 =τw in Gal(L0/L)⊂Gal(L0/K).

Finally, we claim thatρ0σvρ−10 =σwin Gal(L0/K). Sinceχ, χ0∈Gal(L), we already know that σw and ρ0σvρ−10 coincide on Gal(L/K) and hence act equally onG. Thus, on the one hand, (3.1) gives

bρ0ρbσvσwb−1ρ0 =bσw.

On the other hand, we have ρ0σvρ−10 = ψσw for some ψ ∈ Gal(L0/L).

Applyingb to this equality another direct computation gives bρ0ρbσvσwb−1ρ0 =bψbσw.

From the two last equalities we get thatbψ= 1. Sincebis an isomorphism over Gal(L0/L), we getψ= 1, proving the claim. Thus conjugation byρ0 sends the decomposition group ofv inL0/K to that ofw.

4. Weak approximation away from BadG

We now restate and prove Theorem 1.1 in the language of approximation properties. Recall that, given aK-group G, BadG denotes the set of bad places associated to it, cf. Definition 2.1.

Theorem 4.1. — LetK be a number field andG be a finiteK-group with weak approximation away fromBadG. Then every semidirect product E=AoGwithAan abelianK-group has weak approximation away from BadE.

Remark 4.2. — Note that this result does imply Theorem 1.1. Indeed, one can prove it by induction starting with the fact that the trivial group has weak approximation.

Proof of Theorem 4.1. — Consider a finite set of places S ⊂ ΩK not meeting BadE and local classes βv ∈H1(Kv, E) for vS. We will find a global classβ∈H1(K, E) mapping to the βv’s in three steps:

Step 1. — Constructing a class β0 ∈H1(K, E) with prescribed images in H1(Kv, G) forvin SS0 for a suitableS0.

(17)

We have the following commutative diagram of pointed sets with exact rows:

(4.1)

H1(K, A)

//H1(K, E)

//H1(K, G)

ww

Y

v∈ΩK

H1(Kv, A) // Y

v∈ΩK

H1(Kv, E) // Y

v∈ΩK

H1(Kv, G),

zz

where the arrows going left are set-theoretical sections induced by a fixed sectionGE.

The βv’s give us images γv ∈ H1(Kv, G) for vS. Let n = |E| and La Galois extension splittingE. Then, by Proposition 3.2 applied to the extensionL(µn)/K (which splits G), we know that for everyvS there exist placesv06∈S∪BadE for which there are inclusions

φv: H1(Kv, G),→H1(Kv0, G).

Choose one suchv0for eachvSand denote byS0the set of these places.

We may assume that all thev0 are different since we have an infinite choice at each time. Define thenγv0 :=φvv)∈H1(Kv0, G).

Since we’ve chosen these new places away from BadE ⊃BadG, we know by hypothesis that there exists a global classγ∈H1(K, G) mapping onto γv for every vSS0. Moreover, we may assume that the restriction of a cocycle cZ1(K, G), representing γ, to Gal(L(µn)) is surjective:

Indeed by Chebotarev’s density theorem, there are infinitely many places w6∈SS0∪BadE totally split inL(µn), so in particular such that G is constant overKw; then, for each element gGwe may choose one such w and an unramified class γw ∈ H1(Kw, G) represented by a morphism sendingσwtog, so that allw’s are distinct; then finally, adding these local conditions toSS0forcescto be surjective when restricted to Gal(L(µn)).

Let β0 be the image ofγ in H1(K, E) via the section of diagram (4.1).

Viewing G as a subgroup of E, the class β0 is represented by the same cocyclec.

Step 2: Twisting. — We twist by c to look for a class in H1(K, E) satisfying the necessary prescribed local conditions inS.

(18)

Let us now twist diagram (4.1) by the cocycle c representing β0. This gives us the following new diagram with exact rows

(4.2)

H1(K, Ac )

//H1(K, Ec )

//H1(K, Gc )

Y

v∈ΩK

H1(Kv, Ac ) // Y

v∈ΩK

H1(Kv, Ec ) // Y

v∈ΩK

H1(Kv, Gc ).

For every cohomology classξin a set of diagram (4.1), we denote bycξits twisted image in the corresponding set of diagram (4.2).

Since the images of βv and β0 coincide on H1(Kv, G) for vS by con- struction andcβ0 is trivial by the very definition of twisting, we know by exactness thatc vβ ∈H1(Kv, Ec ) comes from an elementαv∈H1(Kv, Ac ).

It suffices then to find a global classα∈H1(K, Ac ) mapping ontoαv for vS to conclude. Indeed, the image of αin H1(K, Ec ) would then map onto thec vβ ’s forvSand hence its preimage in H1(K, E) by the twisting morphism would map onto theβv’s as desired. Thus, in order to conclude, it will suffice by Proposition 2.5 to prove thatX1S(K,cAˆ) =X1(K,cAˆ).

Step 3: Proof of X1S(K,cAˆ) = X1(K,cAˆ). — Consider a class α in X1S(K,cAˆ), i.e. a class in H1(K,cAˆ) such that its image αv∈H1(Kv,cAˆ) is trivial for everyv 6∈S, so in particular forv0S0. We must show that αv= 0 forvS too.

Fix thenvS and its correspondingv0S0. Lemma 3.3 applies in this context to the local classesγv andγv0 =φvv), the global classγand the extensionL(µn)/K. By the lemma the decomposition groups ofv and v0 in Gal(L0/K) are conjugate, whereL0 is the extension ofL(µn) given by the kernel ofcrestricted to Gal(L(µn)). Note moreover thatL0 splitscAˆ. Indeed, since|A|dividesnwe havecAˆ= Hom(cA, µn) and sinceL0contains µn, then this amounts toL0 splittingcA. The latter holds since the action ofσ∈Gal(K) onacAis given bycσσac−1σ , whereσadenotes the action ofσonaas an element of A. Sincec is trivial over Gal(L0) andL0 clearly splitsA, we get then our claim. In particular, by Lemma 2.6, we know that the whole groupX1S(K,cAˆ) comes by inflation from H1(L0/K,cAˆ).

Our element α∈X1S(K,cAˆ) comes then from H1(L0/K,cAˆ) and hence αv comes from H1(L0(v)/Kv,cAˆ), whereL0(v)denotes the (unique) exten- sion ofKvinduced byL0/K. The same goes forv0. Since the decomposition

(19)

groups ofvandv0are conjugate in Gal(L0/K), there is a canonical isomor- phism

H1(L0(v)/Kv,cAˆ)−→H1(L0(v

0)

/Kv0,cAˆ),

which is compatible with the restrictions from H1(L0/K,cAˆ). But αis in X1S(K,cAˆ) and v0 6∈ S, so thatαv0 = 0 and hence αv = 0 too. Since the same argument works for everyvS, we deduce that α ∈ X1(K,cAˆ),

proving the claim.

5. Counterexamples to weak approximation

In this section we show that Theorem 4.1 is sharp in the sense that one cannot expect to get approximation (or to solve the Grunwald problem) on the set of bad places.

Recall that a group is bicyclic if and only if it is cyclic or a direct product of two cyclic groups. For a finite groupGand a finiteG-moduleA, we let

X1bic(G, A) := ker

H1(G, A)→ Y

H∈bic(G)

H1(H, A)

,

where bic(G) denotes the set of bicyclic subgroups of G.

Theorem 5.1. — Let Gbe a finite abelian group, K a number field, andSa finite set of places ofK. LetAbe a finiteG-module andE=AoG a constantK-group. Assume:

(1) Kcontains the exp(A)-th roots of unity;

(2) there existsv0S such thatGis a Galois group overKv0; (3) S contains all the places ofKdividing the order ofG;

(4) X1bic(G,A)ˆ 6= 0 (in particularGis not bicyclic).

Then the mapH1(K, E)→Q

v∈SH1(Kv, E)is nonsurjective.

Remark 5.2. — Note that, given the structure of local Galois groups recalled in Section 2.1, Condition (4) implies that the place v0 in Condi- tion (2) must divide the order ofG.

Corollary 5.3. — Assume in addition thatKcontains theexp(E)-th roots of unity, then there is a transcendental Brauer–Manin obstruction to weak approximation onX := SLn/E.

Proof. — Indeed, Theorem 5.1 and Proposition 2.4 tell us that X does not have approximation in S and hence it doesn’t have weak approxima- tion. Now, by [6, Thm. 1] the Brauer–Manin obstruction to weak approx- imation for such a variety is the only obstruction, whereas the formula

Références

Documents relatifs

Under suitable boundary conditions and assuming a maximum principle for the interior points, we obtain a uniform convergence similar to that of Theorem 1.1.. Theorem 2.1 below can

Finally, the last section gives an overview of the results in [3] and [4] (see also [2]), where tame Galois realizations of the groups in the family GSp 4 ( F ` ) are obtained for

In addition to the new approximation bounds that they provide, the obtained results enable to establish the robustness of the algorithm that is addressed here, since this

focuses on the inverse Galois problem, and therefore on homogeneous spaces of the form SL n,k /Γ, it is an essential point for this induction that the theorem can be applied

L’accès aux archives de la revue « Annales de la faculté des sciences de Toulouse » ( http://picard.ups-tlse.fr/~annales/ ) implique l’accord avec les conditions

A connected Langlands dual group is functorial only with respect to normal homomorphisms, and therefore Kot- twitz’s is functorial only with respect to normal

2014 The Brauer-Manin obstruction for homogeneous spaces with connected or abelian stabilizer, J. für die reine und

We will focus our study on the approximation of Problem 1.1 with piecewise linear éléments, including numerical intégration, and obtain rates of convergence.. The layout of the paper