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Mass selection in livestock using limited testing facilities
L Ollivier
To cite this version:
Original
article
Mass selection
in livestock
using
limited
testing
facilities
L Ollivier
Institut National de la Recherche
Agronomique,
Station de G6n6tique Quantitativeet
Appliquee,
78350 Jouy-en-Josas, France(Received
29 May 1989; accepted 20 September1989)
Summary - This paper considers the problem of
maximizing
the expected annual responseto mass selection when
testing
facilities are limited and so do not allow testing of allpotential candidates. In such situations, there is room for variation both in the proportion
of
breeding
animals selected on the basis of the testresult "nd
in the allocation oftesting
places between male and female candidates. When testing facilities are very limited
(case
1), males
havepriority
in testing and the maximum proportion to select based on testresults is 27%. This means that it is then better to use untested males, i.e. taken at
random, than males which are in the lower 73%. This situation holds until the ratio
(k)
of tested to potential candidates reaches kl =1.85/c(4aA + 1),
where c is thedegree
ofpolygyny
(mating ratio),
a the age at firstoffspring
(yr)
and À, the annualfecundity
(s.e.
half the dam progenycrop).
As k increases above kl(case
2),
all replacement males should be tested andtesting
space should beentirely
devoted to males, with random choice of females. This situation holds until k reaches a critical value, k2, above which testing space should be equally distributed between the 2 sexes(case 3).
The value of k2, obtained iteratively for anygiven
set of parameters c, a and À, as defined above, is shownto increase when c increases and when aA decreases. The strategies recommended, which
imply
contrasting
turn-over rates between selected candidates and candidates chosen atrandom, are compared to those aimed at maximizing selection intensity for a fixed value of
the generation interval. Numerical examples are provided, covering the range of situations prevailing in farm livestock species.
mass selection / selection response / selection intensity / generation interval Résumé - La sélection massale chez les animaux domestiques avec une capacité
de contrôle limitée - Cet article traite de la maximisation du gain
génétique
annuel attendu en sélection massalequand
la capacité de contrôle est limitée et ne permet pas decontrôler tous les candidats potentiels à la sélection. Dans une telle situation, on peut
faire
varier à lafois
la proportion des reproducteurs sélectionnés sur leur résultat decontrôle et la répartition des places de contrôle entre les 2 sexes. Quand la capacité de
contrôle est restreinte
(cas 1),
les mâles ont lapriorité
et le taux de sélection maximal à l’issue des contrôles est de 27%. Il vaut mieux alors utiliser des mâles non controlés,c’est-à-dire choisis au hasard, que des mâles se trouvant dans les 73% inférieurs. Cette situation prévaut tant que le rapport
(k)
des candidats contrôlés aux candidats potentiels ne dépasse pas kl = 1,85/c(4aλ+1),
où c est 1_e degré depolygynie (nombre
de reproducteursfemelles/nombre
de reproducteursmâles),
à l’âge au ler descendant(an)
et ) g la fécondité
femelle).
Quand k dépasse ki(cas 2)
tous les mâles de renouvellement doivent être contrôlés et toutes les places de contrôle doivent être réservées aux mâles, les femellesétant choisies au hasard. Cette situation prévaut
jusqu’à
une valeur critique k = k2,au-dessus de
laquelle
lesplaces
doivent êtreégalement
réparties entre les 2 sexes(cas
3).
Onmontre que cette valeur k2, qui est obtenue par itération pour tout ensemble donné des
paramètres c, a et À,
définis
ci-dessus, augmente avec c et diminue quand aa augmente.Les
stratégies
recommandées, qui impliquent des taux de renouvellement trèsdifférents
entre les candidats sélectionnés et les candidats choisis au hasard, sont comparées à celles
qui visent à maximiser l’intensité de sélection à intervalle de
génération
fixé. Des exemplessont donnés pour illustrer le cas des diverses espèces animales
domestiques.
sélection massale / réponse à la sélection / intensité de sélection / intervalle de
génération
INTRODUCTION
Mass selection is a
simple
andwidely
used selection method for farm animals.Considering
a traitexpressed
in both sexes, andfollowing
a normaldistribution,
theexpected
annual response can be shown to be a function of the mean ages of males and females atculling.
The maximum response is obtainedby determining
anoptimal
balance between selection intensities andgeneration intervals,
as shownby
Ollivier(1974)
for the case when allpotential
candidates are tested. The purposeof this paper is to extend the treatment to situations where
testing
facilities are limited and so do not allowtesting
of allpotential
candidates. In such cases, there is room for variation both in theproportion
ofbreeding
animals selected on thebasis of the test
resultgand
in the allocation oftesting places
between male and female candidates. The effect of such a variation on the overall selectionintensity
haspreviously
been consideredby
Smith(1969).
The
general
methodDickerson and Hazel
(1944)
gave ageneral
formula for theexpected
annual responseto
selection,
R
d
=(i
1
+
l
2
)/(t
i
+t
2
),
as a function of female and male selection intensities(i
l
andi
2
,’ respectively)
andgeneration
intervals(t
l
,
t
2
),
R
a
being
expressed
ingenetic
standard deviations for a trait assumed to have aheritability
equal
to 1. With selection ofrespective
proportions f
and m of the females and malesrequired
forbreeding,
andcorresponding
proportions
1 —f
and 1 — m takenat
random,
theexpected
annual response becomes:where tll and t12 are the
generation
intervals for the females selected and the females taken atrandom,
respectively,
and t21 and t22 aresimilarly
defined for males. &dquo;If selection is
by
truncation of a normaldistribution,
i
l
l, = znlwhere ni is thenumber of female candidates tested per female selected and zl the ordinate of the
normal curve for a
proportion
1/n,
selected,
andi
2
issimilarly
defined.Moreover,
generation
intervals may beexpressed
as functions ofdemographic
parameterspertaining
to anygiven
species,
and of the distribution oftesting
space betweenmales and females.
Using
thesimple demographic
model assumedby
Ollivier(1974};-.
forinstance,
one can write:-where a is the
parents’
age(in years)
at birth of firstoffspring,
assumedequal
forboth sexes; c is the
degree
ofpolygyny,
ormating
ratio;
A is the annual femalefecundity, referring
to the number of candidates of 1 sex(sex
ratio assumed to be1/2)
able to breedsuccessfully;
h
and 12 are therespective
numbers of female andmale candidates tested
annually
per dam.Expressions
(2)
are based on the definition taken for thegeneration interval,
which is assumed to be the arithmetic mean of the
parents’
ages at birth of first(a)
and of lastoffspring.
The latter is determinedby
the time necessary toreplace
1
breeding animal,
either selected among n candidates or taken at random. Forinstance,
knowing
that h
female candidates are testedannually
perbreeding
female,
ie,
Illf
candidates per femaleselected,
and that each selected female is chosen among n1candidates,
the timerequired
isfnl/l1
years, which leads toeqn(2a).
Onthe other
hand,
(A - 11)
females areuntested,
ie,
(À -1¡)/(1- f)
per female chosenat random. The time necessary to obtain 1
candidate,
if one takes the firstborn,
is
(1 - f)/(A - 1
1
),
which leads toeqn(2b).
Equations
(2c)
and(2d)
aresimilarly
obtained.Now
h
and1
2
depend
on the overalltesting
capacity,
defined as theproportion
k of available candidates which can be tested
annually,
and of the distribution oftesting places
between females andmales,
definedby
the sex ratio a among thetested
candidates,
so that:The
possible
range of a extends from 0 to 1 aslong
as k < 0.5.Then,
as k exceeds0.5,
the range isprogressively
narrowed,
until a = 0.5 when k = 1.Case 1:
only
males are tested(a
=1);
aproportion
(m
<1)
of malesrequired
forbreeding
is testedIn this case,
f
= h
= 0 and2
1
= 2kA.Expression
(1)
reduces to a function of 2variables,
m and n2, such that:with
The maximum of
R
’f
,)with
respect to m is obtained for:With this value of m,
R
a
becomes aquantity
approximately proportional
toz
2
ng.
5
,
which is maximum for n2 - 3.7.Thus,
the critical value of k for whichm =
or, with n2 -
3.7,
Consequently,
whentesting
capacity
is limited to a value k <k
i
,
aproportion
ofuntested males should be
used,
in order to maintain a constantproportion
selectedof about 27%
(1/3.7)
among those tested. Under theseconditions,
theexpected
annual response isapproximately proportional
tok
l
-’,
asCase 2:
only
males are tested(a
=1);
all malesrequired
forbreeding
are tested
(m = 1)
As k becomes
equal
tok
l
,
and then increases above,
k
l
m = 1 andeqn(4a)
reduces to:which can be maximized
iteratively
with respect to !2. But thequestion
then arisesas to whether a
higher
response can beexpected by diverting
sometesting
spacefor the selection of females. This case will now be considered.
Case 3: all males tested
(m
=1)
and aproportion
of females(a
<1;
f
>0)
With selection of all males
(m = 1),
and of aproportion
( f )
of the femalesrequired
for
breeding,
R
a
becomes:which is a function of
f,
a, ni and n2 for anygiven testing capacity.
It can
easily
be shown that the derivative ofR
a
;
with respect tof,
ispositive
when 0 <
f
<1,
provided
2i
2
> . il As selection shouldgenerally
be more intensein males
(i
2
>i
l
),
this condition isalways
fulfilled,
and theoptimum
value off
istherefore
1,
irrespective
of the other parameters.Then, assuming f
= 1(ie,
all femalesrequired
for breeding
aretested),
thequestion
is how to allocate thetesting places
between 2 sexes, within the limitspreviously
indicated for the sex ratio a among tested candidates. Infact,
the value ofR
a
is rather insensitive to variations of a(although
theoptimal
value of a isslightly
below0.5),
as shownby
Ollivier(1988:
seeeqn(6),
p446).
One can thentake a to be
0.5,
and theoptimal
values of n1 and n2 are obtainedby
maximizing:
where t, l = a +
Mi/
2A:A,
and t21 = a +n
2
/2ckA,
as h = 12 = kA.For any
given testing capacity,
the maximumof eqn(10)
can becompared
to themaximum of
eqn(8)
considered in case2,
and(by iteration)
thek
2
valueyielding
equal
responses in the 2 cases is obtained.Thus,
whentesting capacity
is belowk
2
,
all
testing
space should be devoted tomales,
and when k >k
2;
it should beequally
distributed between the 2 sexes.
Numerical illustration
As an illustration of the above
results,
Table IIgives
k
i
andk
2
values for 9 setsof
demographic
parametersimplying
3 values of aA(0.5,
1 and5)
valid forsheep,
cattle and
pigs,
respectively,
and 3degrees
ofpolygyny,
eithercorresponding
tonatural
mating
(c
=10)
or artificial insemination(c
= 100 or1000).
The Tablealso
gives
theexpected
response fork = k
1
and k =k
2
,
expressed
relative to themaximum response
expected
with k = 1.The Table
clearly
showsthat,
for agiven degree
ofpolygyny,
k
l
andk
2
both decrease whenfecundity
increases. Forspecies
ofhigh
fecundity,
such aspoultry
and
rabbits,
k
l
becomesnegligible
and the low value ofk
2
islikely
to fall belowthe actual
testing
capacity, owing
to the low cost oftesting.
Therefore; case
3 willusually apply
to thosespecies.
On the otherhand, k
l
decreaseswhen
polygyny
increases,
as it isinversely proportional
to c,(from eqn(6))
!where.-t§;,k2
increases with c up to apoint
where, particulary
whenfecundity
islow,
alarge proportion
of the maximum response can be
expected
fromtesting
malesonly.
It is also worthnoting
that whenfecundity
is low(below
a limit which is somewhere between 1 and 5 foraa),
the criticaltesting capacity, k
2
;yis
above 0.5. As thiscorresponds
toone of the patterns illustrated in
Fig
1,
according
to whetherk
2
< 0.5 ork
l
> 0.5.In the latter case, rather
paradoxically,
the extra space available when all males are tested should not be used fortesting.
The worst solution wouldactually
be touse it for
testing females,
as shownby point
C inFig
la. This is because the extraselection
intensity
obtainedby testing
females is more than offsetby
the increase in theirgeneration
interval.DISCUSSION
A
parallel
can be draw between the above results and those of Smith(1969).
Heconsidered
maximizing
selectionintensity,
or response pergeneration,
for agiven
number oftesting places
(T)
available, assuming
a fixedgeneration
interval. Herethe
objective
is to maximize annual response, with variablegeneration
length,
and thetesting capacity
(k),which
is defined on ayearly
basis. Ifgeneration
interval isset at a value t, and T is defined as the number tested per
breeding
female over aperiod
of timeequal
to the averagebreeding
life of sires anddams,
2(t — a),
therelationship
between T and k is:In case
1,
the selection strategy recommendedhere, may
becompared
to therule
given by
Smith(1969),
which states that &dquo;iftesting
facilities are verylimited,
it is better to use untested
males,
than males which are belowaverage&dquo;.
Thu!!
1/2
is the maximumproportion
to select in order to maximize theresponse
per
generation,
asagainst
1/3.7 ,‘two, )
if the response per year is considered.The two
approaches
can, forinstance,
becompared
in terms ofexpected
annualresponse for a
testing capacity equal
tok
l
.
Using
Smith’sapproach,
the critical number oftesting places
below which untested males should beused,is
T =2/c,
i e, 2 male candidates tested per sire to be
replaced.
Thisimplies a
generation
interval t = 2.1a +
1/3.7A,
a value obtained fromsolving
eqn(11)
for T =2/c
and1
2
=2k, A.
Thesupplementary
gain
expected
fromapplying
Table I strategy whenk =
k
l
,
using
the valueR
a
=1.2A/(1
+4aA)
derived fromeqn(7),
can then beshown to range from 33 to
53%,’when
aa goes from 0.5 to 5.For case 2 and
3,
Smith’sapproach
leads torecommendation
of agradual
increasein the
proportion
(f)
of femalesselected,
whereas,
here no intermediateoptimum
forf
exists,
but rather anabrupt change
from- f
= 0 tof
=1,
between
case 2and case 3. In Smith’s
approach,
thegradual
increase inf
should start at T -1,
and case 3 is reached when T ! 3.
Taking
ageneration
interval t =2a,
usualin livestock
populations,
it can be seen fromeqn(ll)
that theequivalent testing
capacity
necessary to reach case 3 is k =3/4aA.
This means that when thegeneration
interval is not acted upon, case 3 can be reachedonly
if aa > 0.75. The model used in thisstudy,)
rests on severalsimplifying
assumptions,
of which a detailed discussion has eengiven
by
Ollivier(1974).
Thepopulation
undergoing
selection issupposed
to belarge
andstationary
insize,
and a uniform age distribution of thebreeding
animals is assumed. Itperhaps
should be stressedthat
testing
space is defined relative to agiven
population
size. If thetesting
space were defined as an absolute
value,
thepopulation
sizemight
be reduced to match thetesting
capacity
in order to increase the immediate response. Lossof
genetic
variancewould, however,
beincurred,
thuscompromising long-term
response.
Optimal
strategies
formaximizing
long-term
response to selection in suchsituations have been
explored by
Robertson(1960; 1970),
Smith(1969;
1981mand
James(1972),
amongothers,
under theassumption
of a fixedgeneration
time. In a situation of restrictedyearly testing facilities,
it would then be advisable to maximize thegeneration
length
in order to also maximize the number of candidatesper
generation.
The
assumption
of a uniform age distribution is notgenerally
met inpractice
and can
only
beaccepted
as anapproximation
in situations of fastreplacement,
or when the increase infecundity
with age can compensate for thegradual
decay
in the number of
breeding
individuals. With lowtesting
capacity,
however,
theprocedure
recommendedherp
r
,
-
-implies
contrasting
turnover rates between males(selected)
and females(takei
r
at
rand
Q
m).
When k <k
2
,
the femalegeneration
interval should beminimized, whereas,
the malegeneration
interval willgradually
increase as k decreases. When k =k
l
;‘£his
interval exceeds 3 timesthe
age at birthof the first
offspring,
as shown in Table I.Obviously,
such astrategy
can bestrictly
implemented,,
provided
enough
semen from the selected sires can be stored and ifbreeding
canbe
carriedon$ artificially
if necessary.In
spite
of the limitations discussedabove,
the resultspresented
may serve asguidelines
for theoptimal
use of limitedtesting
facilities.They
also show that a sizeableproportion
of the maximumgenetic gain
can be obtained with very limitedtesting
facilities. The conclusions are restricted to massselection,
whichrequires
nopedigree
information. Extension tofamily
selection may be considered. Extra selectionintensity could,
forinstance,
be obtainedby applying
family
selection tountested candidates whenever tested relatives are available.
However,
in a situation of limitedtesting facilities,
information on relatives would also be limited and the extra selectionintensity
would have to be setagainst
theresulting
increase ingeneration
interval. Evaluation of tested candidates could also be made moreand Rouvier
(1971)
or, moregeneraly,
with best linear unbiasedprediction
ofbreeding
value(Henderson, 1963).
One would then expect the accuracy of selection to increase with thetesting
capacity.
This would mean, for anygiven
testing
capacity,
a lower response relative tocomplete
testing,
than with mass selection. N Anoptimal
strategywould, therefore,
be morecomplex
to establish for combinedselection,
as it woulddepend
on therelationship
between thetesting
capacity
andthe selection accuracy.
REFERENCES
Dickerson
GE,
Hazel LN(1944)
Effectiveness of selection on progenyperformance
as a
supplement
to earlierculling
in livestock. JAgric
Res69,
459-476Henderson CR
(1963)
Selection index andexpected
genetic
advance. In: Statistical Genetics and PlantBreeding
(Hanson
WD,
RobinsonHF,
eds)
NASNRC Publ.982,
141-163James JW
(1972)
Optimum
selectionintensity
inbreeding
programmes. Anim Prod14,
1-9Ollivier L
(1974)
Optimum replacement
rates in animalbreeding. Anim
Prod19,
257-271Ollivier L
(1988)
Currentprinciples
and future prospects in selection of farmani-mals. In:
Proceedings of
the Second InternationalConference
onQuantitative
Ge-netics
(Weir
BS,
EisenEJ,
GoodmanMM, Namkoong G,
eds)
SinauerAssociates,
Sunderland, MA,
438-450Poujardieu
B,
Rouvier R(1971)
Optimisation
duplan
d’accouplement
dans la selection combin6e. Ann G6n6t S61 Anim3, 509-519
Robertson A
(1960)
Atheory
of limits in artificial selection. Proc RSoc,
SerB,
153,
234-249Robertson A
(1970)
Someoptimum problems
in individual selection. TheorPop
Biol,
1,
120-127Smith C
(1969)
Optimum
selectionprocedures
in animalbreeding.
Anim Prod 11,433-442 .