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HAL Id: hal-02538194

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Preprint submitted on 9 Apr 2020

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SOME REFINEMENTS OF WELL-KNOWN INEQUALITIES INVOLVING TRIGONOMETRIC

FUNCTIONS

Raouf Chouikha, Christophe Chesneau, Yogesh Bagul

To cite this version:

Raouf Chouikha, Christophe Chesneau, Yogesh Bagul. SOME REFINEMENTS OF WELL-KNOWN

INEQUALITIES INVOLVING TRIGONOMETRIC FUNCTIONS. 2020. �hal-02538194�

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INVOLVING TRIGONOMETRIC FUNCTIONS

ABD RAOUF CHOUIKHA, CHRISTOPHE CHESNEAU, AND YOGESH J. BAGUL

Abstract. In this paper, we determine new and sharp inequalities involving trigonometric functions. More specifically, a new general result on the lower bound for log(1−uv),u, v(0,1) is proved, allowing to determine sharp lower and upper bounds for the so-called sinc function, i.e., sin(x)/x, lower bounds for cos(x) and upper bounds for (cos(x/3))3. The obtained bounds improve some well-established results. The findings are supported by graphical analy- ses.

2010 Mathematics Subject Classification:26D05, 26D07, 26D20, 33B10.

Key words and phrases:Cusa-Huygens inequality; sinc function; series expan- sion; positive and increasing function.

1. Introduction

Over the last two decades, efforts were made to bound special trigonometric and hyperbolic functions as sharp as possible, with a focus on the sinc function sin(x)/x.

The resulting inequalities find applications in many applied fields, allowing quick evaluations of complex functions involving these trigonometric functions. The lit- erature on the subject is vast and growing fast. We may refer the reader to [1], [2], [3], [4], [5], [6], [7], [8], [10], [11], [12], [13], [14], [15], [16], [17] and [18], and the references therein.

This paper contributes to the subject in the following way. First of all, we prove a general and sharp lower bound result for log(1−uv), u, v∈(0,1). Then, we apply this result to determine polynomial-exponential lower bounds for sin(x)/x and cos(x), also with the use of infinite product series. We prove that they are sharp, improving some recent results of the literature. Also, as intermediate results, some new polynomial-exponential inequalities are set. As an alternative approach, we use these results to conjecture upper bounds for sin(x)/xand (cos(x/3))3. Proofs are given in details by the means of Taylor developments. Again, some recent results in the fields are refined, including the famous Cusa-Huygens inequality[9]. All the findings are supported by the visual checks of appropriate functions.

The rest of the paper is planned as follows. Section 2 investigate the lower bounds. Section 3 is devoted to the upper bounds for sin(x)/x and (cos(x/3))3, with discussions.

2. Lower bounds

This section is devoted to the proof of new lower bounds, involving sharp lower bounds for sin(x)/xand cos(x) as applications. Some graphics support the findings.

1

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2.1. Some new general results. The result below proposes a new lower bound for log(1−uv) with u, v ∈(0,1), which will be at the center of the proofs of new sharp lower bounds for sin(x)/xand cos(x).

Proposition 2.1. For any u, v∈(0,1), the following inequality holds:

log(1−uv)> uv(u−1)h

u+ 1 + uv 2

i

+u3log(1−v).

Proof. By virtue of the logarithmic series expansion and, for k≥3, uk < u3, after some algebraic manipulations, we get

log(1−uv) =−

+∞

X

k=1

ukvk

k =−uv−u2v2

2 −

+∞

X

k=3

ukvk k

>−uv−u2v2 2 −u3

+∞

X

k=3

vk

k =−uv−u2v2 2 +u3

"

+∞

X

k=1

vk

k +v+v2 2

#

=−uv−u2v2 2 +u3

log(1−v) +v+v2 2

=uv(u−1)h

u+ 1 +uv 2

i

+u3log(1−v).

This ends the proof of Proposition 2.1.

Proposition 2.2. Foru, v∈(0,1) the following inequalities hold:

1−uv >(1−v)u3euv(u−1)[u+1+uv2]>(1−v)u2euv(u−1)>(1−v)u. Proof. The first inequality is Proposition 2.1, by taking the exponential trans- formation. The second one takes the first steps of the proof of Proposition 2.1 in the following sense: Sinceu3< u2, we have

uv(u−1)h

u+ 1 + uv 2

i

+u3log(1−v) =−uv−u2v2 2 −u3

+∞

X

k=3

vk k

>−uv−u2v2 2 −u2

+∞

X

k=3

vk

k =−uv−u2v2 2 +u2

"

+∞

X

k=1

vk

k +v+v2 2

#

=uv(u−1) +u2log(1−v).

The desired inequality follows by taking the exponential transformation. The last inequality is follows from [7, Theorem 1-1], showing thatuv(u−1) +u2log(1−v)>

ulog(1−v). This ends the proof of Proposition 2.2.

2.2. Lower bounds for sin(x)/x. The result below presents a new sharp bound for sin(x)/xinvolving the exponential function.

Proposition 2.3. Forx∈(0, π), we have the following inequalities:

sin(x) x >

1−x2

π2 π

6 945

ex

2hπ4

94516+x22π2 945901i

>

1−x2

π2 π

4 90

ex

2

π2 9016

>

1−x2

π2 π

2 6

.

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Proof. By using the infinite product expression of sin(x)/x, takingu= 1/k2and v=x22in Proposition 2.2, and using the following well-known results on the zeta function, i.e., ζ(k) =P+∞

n=11/nk: ζ(2) =π2/6, ζ(4) = π4/90 andζ(6) =π6/945, we get

sin(x)

x =

+∞

Y

k=1

1− x2

π2k2

>

+∞

Y

k=1

"

1−x2

π2 k16

e x

2

π2k2(k12−1)hk12+1+ x2

2k2π2

i#

=

1−x2 π2

P+∞k=1k16

e

x2 π2

P+∞

k=1

h1

k61

k2+x2

2(k161

k4)i

=

1−x2 π2

π

6 945

ex2

hπ4

94516+x22

π2 945901i

.

The second inequality is due to Proposition 2.2, with similar lines of proof. The last inequality follows from [7, Proposition 2-4]. This ends the proof of Proposition

2.3.

Figure 1 illustrates the two first inequalities of Proposition 2.3 by plotting the two following functions forx∈(0, π):

A(x) =sin(x)

x −

1−x2

π2 π

6 945

ex2

hπ4

94516+x22

π2 945901i

and

B(x) =

1−x2 π2

π

6 945

ex

2h

π4

94516+x22

π2 945901i

1−x2 π2

π

4 90

ex

2

π2 9016

.

0.0 0.5 1.0 1.5 2.0 2.5 3.0

0e+002e−044e−046e−04

A(x)

0.0 0.5 1.0 1.5 2.0 2.5 3.0

0.0000.0010.0020.003

B(x)

, Figure 1. Plots for A(x) andB(x) forx∈(0, π), respectively.

As expected, we see thatA(x) andB(x) are positive, with very small variations, attesting the sharpness of the obtained bounds.

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2.3. Lower bounds forcos(x). The result below presents a new sharp bound for cos(x) involving the exponential function.

Proposition 2.4. Forx∈(0, π/2), we have the following inequalities:

cos(x)>

1−4x2

π2 π

6 960

ex2

hπ4

24012+x2

π2 120121i

>

1−4x2

π2 π

4 96

ex

2

π2 2412

>

1−4x2

π2 π

2 8

.

Proof. By using the infinite product expression of cos(x), takingu= 1/(2k−1)2 and v = 4x22 in Proposition 2.2, and using the following well-known results:

P+∞

k=11/(2k−1)2 = π2/8, P+∞

k=11/(2k−1)4 = π4/96 and P+∞

k=11/(2k−1)6 = π6/960 we get

cos(x) =

+∞

Y

k=1

1− 4x2 π2(2k−1)2

>

+∞

Y

k=1

"

1−4x2

π2

(2k−1)61 e

4x2 π2 (2k−1)2

1

(2k−1)2−1h 1

(2k−1)2+1+π2 (2k−1)22x2 i#

=

1−4x2 π2

P+∞

k=1 1 (2k−1)6

e

4x2 π2

P+∞

k=1

h 1

(2k−1)6(2k−1)21 +2x2

π2

1

(2k−1)6(2k−1)41 i

=

1−4x2 π2

π

6 960

ex2

hπ4 24012+x2

π2 120121i

.

The second inequality is also derived to Proposition 2.2, with similar mathematical arguments. The last one is a consequence of [7, Proposition 2-4]. This ends the

proof of Proposition 2.4.

As a matter of fact, Proposition 2.4 improves [2, Proposition 4], i.e., for any x∈(0, π/2),

cos(x)>

1−4x2

π2 π

2 8

. (2.1)

Figure 2 illustrates the two first inequalities of Proposition 2.4 by plotting the two following functions forx∈(0, π/2):

C(x) = cos(x)−

1−4x2 π2

π

6 960

ex2

hπ4

24012+x2

π2 120121i

and

D(x) =

1−4x2 π2

π

6 960

e4x

2h

π4

96018+2x2

π2 960961i

1−4x2 π2

π

4 96

ex

2

π2 2412

.

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0.0 0.5 1.0 1.5

0e+004e−058e−05

C(x)

0.0 0.5 1.0 1.5

0e+004e−048e−04

D(x)

, Figure 2. Plots forC(x) andD(x) forx∈(0, π/2), respectively.

We observe thatC(x) andD(x) are positive, with very small variations, attesting the sharpness of the obtained bounds.

3. Upper bounds

Here, we derive some new sharps upper bounds for sin(x)/x and (cos(x/3))3, which naturally appear in many inequality involving trigonometric functions.

3.1. Upper bounds for sin(x)/x. In [12], the authors proved the inequality of Cusa-Huygens: forx∈(0, π/2),

sin(x)

x < 2 + cos(x)

3 .

(3.1)

That is, is natural to address the following question: Based on (3.1), can we use lower bounds for cos(x) to derive upper bounds for sin(x)/x?

As a first remark, by using the simple but improvable lower bounds in (2.1), we provide a first answer to the question: Is the following inequality true ? For any x∈(0, π/2),

00 2 + cos(x) 3 > 2

3+1 3

1−4x2

π2 π

2 8

>sin(x) x

00.

The answer is negative because the functionh(x) = 3 sin(x)/x−2− 1−4x22π2/8

has not a constant sign. Indeed, as countered example, we haveh(0.3)≈0.0001>0 andh(0.8)≈ −0.00034<0.

However, based on Proposition 2.4, the following chain of inequalities is true, providing a new upper bound for sin(x)/x.

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Proposition 3.1. Forx∈(0, π/2), we have 2 + cos(x)

3 > 2 3+1

3

1−4x2 π2

π

6 960

ex

2h

π4

24012+x2

π2 120121i

> 2 3+1

3

1−4x2 π2

π

4 96

ex

2π2 2412

>sin(x) x .

Proof. We only need to prove the last right inequalities, the others follow from Proposition 2.4. The proof is based on the analytical study of the following function:

k(x) = 3sin(x) x −2−

1−4x2

π2 π

4 96

ex

2

π2 2412

. (3.2)

The desired inequality comes by proving that k(x) is non positive. The Taylor development of sin(x) gives

sin(x) =x−x3 3! +x5

5! −x7

7! +. . .+ (−1)k−1 x2k−1

(2k−1)!+ (−1)k cos(θx) (2k+ 1)!x2k+1, where θ ∈ (0,1). As a direct application, the following inequalities hold forx ∈ (0, π/2):

1−1

6x2+ 1

120x4− 1

5040x6< sin(x)

x < `(x), (3.3)

where

`(x) = 1−1

6x2+ 1

120x4− 1

5040x6+ 1 362880x8

≈1−0.166667x2+ 0.0083333x4−0.00019841x6+ 0.0000027x8. Similarly, we have

ex

2π2 2412

> m(x), (3.4)

where

m(x) = 1 + π2

24−1 2

x2+1

2 π2

24−1 2

2 x4+1

6 π2

24−1 2

3 x6

≈1−0.088766x2+ 0.0039392x4−0.00011655x6.

Applying again the Taylor decomposition technique, since 4x22<1 andπ4/96>

1, we have

1−4x2

π2 π

4 96

> n(x), (3.5)

where

n(x) = 1− 1

24π2x2+ 1

1152π4− 1 12

x4− 4 3π2

π4 1152− 1

12 π4 96 −2

x6 + 4

4 π4

1152− 1 12

π4

96 −2 π4 96−3

x8

≈1−0.411246x2+ 0.001225x4+ 0.00016305x6+ 0.000032799x8.

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By putting (3.2), (3.3), (3.4) and (3.5) together, we obtain

k(x)<3 1−0.166667x2+ 0.0083333x4−0.00019841x6+ 0.0000027x8

−2

− 1−0.41124x2+ 0.001225x4+ 0.000163x6+ 0.0000328x8

× 1−0.08876x2+ 0.0039392x4−0.00011655x6 .

After development and a acceptable approximation (with 5 digits), we arrive at k(x)<−0.0000001x12+ 0.000003x10−0.0000654x8+ 0.0010868x6−0.01667x4. This last polynomial is non positive because it has no root in the interval (0, π/2).

This ends the proof of Proposition 3.1.

Thanks to Proposition 3.1, we then obtain a better bound for the Cusa-Huygens inequality.

Also, we may derive from Propositions 2.1 and 3.1 the following new frame for sin(x)/x:

1−4x2

π2 π

6 960

ex

2h

π4

24012+x2

π2 120121i

< sin(x) x

<2 3 +1

3

1−4x2 π2

π

6 960

ex

2h

π4

24012+x2

π2 120121i

.

Figure 3 provides a graphical illustration of the main finding of Proposition 3.1 by displaying the following function forx∈(0, π/2):

E(x) = sin(x)

x −

 2 3 +1

3

1−4x2 π2

π

4 96

ex

2

π2 2412

 .

0.0 0.5 1.0 1.5

0.0000.0100.0200.030

E(x)

, Figure 3. Plots forE(x) forx∈(0, π/2).

We see thatE(x) is positive, as proved analytically.

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3.2. Upper bounds for (cos(x/3))3. In [15], the following chain of inequalities is proved. Forx∈(0, π/2),

sin(x) x <

1 3

2 cosx 2

+ 12

<

cosx 3

3

< 2 + cos(x)

3 .

The following result proposes a refinement of this results, by the use of Propo- sition 2.4.

Proposition 3.2. Forx∈(0, π/2) we have

cosx 3

3

<2 3 +1

3

1−4x2 π2

π

6 960

ex

2h

π4

24012+x2

π2 120121i

<2 3 +1

3

1−4x2 π2

π

4 96

ex

2π2 2412

< 2 + cos(x)

3 .

Proof. We follow the lines of the proof of Proposition 3.1, by proving the first left inequality; the others follows from Proposition 2.4. Firstly, the classic Taylor development of cos(x) gives

cosx= 1−x2 2! +x4

4! −x6

6! +. . .+ (−1)kx2k

2k! + (−1)k+1 cos(θx) (2k+ 2)!x2k+2, whereθ∈(0,1). Among others, this implies that

cos(x)<1−x2 2! +x4

4! −x6 6! +x8

8!. That is, we have

cosx

3 3

< q(x), (3.6)

where, doing a standard development and a acceptable approximation, q(x) =

1−(x/3)2

2! +(x/3)4

4! −(x/3)6

6! +(x/3)8 8!

3

≈1−1

6x2+ 7

648x4− 61

174960x6+ 547 88179840x8

≈1−0.166667x2+ 0.010802x4−0.0003486x6+ 0.000006x8. It follows from (3.4) that

ex

2

π2 2412

> r(x), (3.7)

where

r(x) = 1 + π2

24−1 2

x2+1

2 π2

24−1 2

2 x4+1

6 π2

24−1 2

3 x6

≈1−0.088766x2+ 0.0039392x4−0.00011655x6. We have also

1−4x2

π2 π

4 96

> s(x), (3.8)

(10)

where

s(x) = 1− 1

24π2x2+ 1

1152π4− 1 12

x4− 4 3π2

π4 1152− 1

12 π4 96 −2

x6 + 4

4 π4

1152− 1 12

π4

96 −2 π4 96−3

x8

≈1−0.411246x2+ 0.001225x4+ 0.0001631x6+ 0.0000328x8.

The relations (3.6), (3.7) and (3.8) allow us to derive an estimate of the difference

t(x) = 3 cosx

3 3

−2−

1−4x2 π2

π

4 96

ex2(π

4 2412). Indeed, we have

t(x)<3

1−1/6x2+ 7

648x4− 61

174960x6+ 547 88179840x8

−2

− 1 + π2

24−1 2

x2+1

2 π2

24 −1 2

2 x4+1

6 π2

24 −1 2

3 x6

!

×

1− 1

24π2x2+ 1

1152π4− 1 12

x4− 4 3π2

π4 1152− 1

12 π4 96−2

x6 + 4

4 π4

1152− 1 12

π4

96−2 π4 96−3

x8

, implying that

t(x)<3 1.0−0.166667x2+ 0.010802x4−0.0003486x6+ 0.000006x8

−2

− 1−0.088766x2+ 0.0039392x4−0.0001166x6

× 1−0.411246x2+ 0.001225x4+ 0.0001631x6+ 0.0000328x8 .

That is, after development and a suitable approximation (with 5 digits), we arrive at

t(x)<−0.00925926x4+ 0.000636532x6−0.00005245x8+ 0.00000241x10. We verify that this polynomial is non positive because it has no root in the interval (0, π/2). This proved the first left inequality, ending the proof of Proposition 3.2.

As illustration of the main result in Proposition 3.2, Figure 4 shows the curve of the following function forx∈(0, π/2):

F(x) = 2 3+1

3

1−4x2 π2

π

6 960

ex

2h

π4

24012+x2

π2 120121i

− cosx

3 3

.

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0.0 0.5 1.0 1.5

0.0000.0050.0100.015

F(x)

, Figure 4. Plots forF(x) forx∈(0, π/2).

As expected, we see thatF(x) is positive.

References

[1] Bagul, Y. J. and Chesneau, C. (2019). Some New Simple Inequalities Involving Exponential, Trigonometric and Hyperbolic Functions, Cubo. A Mathematical Journal, 21, 1, 21-25.

[2] Bagul, Y.J. and Chesneau, C. (2019). A Note on some new bounds for trigonometric functions using infinite products, preprint HAL: https://hal.archives-ouvertes.fr/hal-01934571v2 [3] Barbu, C. and Piscoran, L-I. (2014). Jordan type inequalities using monotony of functions,

J. Math. Inequal., 8, 1, 83-89.

[4] Bhayo, B.A. and Sandor, J. (2017). New trigonometric and hyperbolic inequalities, Miskolc Math. Notes, 18, 1, 125-137.

[5] Bercu, G. and Wu, S. (2016). Refinements of certain hyperbolic inequalities via the Pade approximation method, J. Nonlinear Sci. Appl., 9, 5011-5020.

[6] Chesneau, C. and Bagul, Y. J. (2019). New refinements of two well-known inequalities, Eurasian Bulletin of Mathematics, 2, 1, 4-8.

[7] Chouikha, A. R. (2020). Sharp inequalities on circular and hyperbolic functions using a Bernoulli inequality type. https://hal.archives-ouvertes.fr/hal-02496097/document

[8] Chouikha, A. R. (2020). Sharp inequalities for ratio of trigonometric and hyperbolic functions, https://hal.archives-ouvertes.fr/hal-02496089/document

[9] Huygen, C. (1888-1940). Oeuvres Completes, Soci´et´e Hollondaise des Sciences, Haga.

[10] Neuman, E. (2012). Refinements and generalizations of certain inequalities involving trigono- metric and hyperbolic functions, Adv. Inequal. Appl., 1, 1, 2012, 1-11.

[11] Qi, F., Niu, D-W. and Guo, B-N. (2009). Refinements, Generalizations, and Applications of Jordans Inequality and Related Problems, J. Inequal. Appl., 2009, Article ID 271923, 52 pages.

[12] Sandor, J. and Bencze, M. (2005). On Huygens trigonometric inequality, RGMIA, Res. Rep.

Collection, 8, No. 3, Art. 14.

[13] Sandor, J. and Bhayo, B.A. (2015). On an Inequality of Redheffer, Miskolc Math. Notes, 16, 1, 475-482.

[14] Wang, M-K., Hong, M-Y., Xu, Y-F., Shen, Z-H. and Chu, Y-M. (2020). Inequalities for generalized trigonometric and hyperbolic functions with one parameter, J. Math. Inequal., 14, 1, 1-21.

[15] Yang, Z.-H. (2013). Three families of two-parameter means constructed by trigonometric functions, J. Inequal. Appl. 2013, Article 541.

[16] Zhang, B. and Chen, C-P. (2020). A double inequality for tanh x, J. Inequal. Appl., 2020, Article ID 19, 1-8.

[17] Zhang, L. and Ma, X. (2019). New Polynomial Bounds for Jordans and Kobers Inequalities Based on the Interpolation and Approximation Method, Mathematics,7, 1-9.

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[18] Zhu, L. (2019). Sharp inequalities for hyperbolic functions and circular functions, J. Inequal.

Appl., 2019, 1-12

4, Cour des Quesblais 35430 Saint-Pere Email address:chouikha@math.univ-paris13.fr

LMNO, University of Caen-Normandie, Caen, France Email address:christophe.chesneau@unicaen.fr

Department of Mathematics, K. K. M. College, Manwath, Dist : Parbhani(M.S.) - 431505, India

Email address:yjbagul@gmail.com

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