A NNALES DE L ’I. H. P., SECTION C
J UNCHENG W EI M ATTHIAS W INTER
Stationary solutions for the Cahn-Hilliard equation
Annales de l’I. H. P., section C, tome 15, n
o4 (1998), p. 459-492
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Stationary solutions for the Cahn-Hilliard equation
Juncheng
WEIDepartment of Mathematics, The Chinese University of Hong Kong, Shatin, Hong Kong
E-mail: wei@math.cuhk.edu.hk
Matthias WINTER
Mathematisches Institut A, Universitat Stuttgart, Pfaffenwaldring 57, D-70569 Stuttgart, Germany
E-mail: winter@mathematik.uni-stuttgart.de
Vol. 15, n° 4, 1998, p. 459-492 Analyse non linéaire
ABSTRACT. - We
study
the Cahn-Hilliardequation
in a bounded domain without anysymmetry assumptions.
We assume that the mean curvature ofthe
boundary
has anondegenerate
criticalpoint.
Then we show that there exists aspike-like stationary
solution whoseglobal
maximum lies on theboundary.
Our method is based onLyapunov-Schmidt
reduction and the Brouwerfixed-point
theorem. ©Elsevier,
ParisRESUME. - Nous etudions
1’ equation
de Cahn et Hilliard dans un domaine ouvert en nesupposant
desymetrie
pour le domaine. Nous supposons que la courbure moyenne sur la frontiere a unpoint critique
nondegenere.
Nousmontrons
qu’ il
existe une solution stationnaire avec unpic qui
atteint sonmaximum sur la frontiere du domaine. Notre methode utilise la reduction de
Lyapunov
et Schmidt et le theoreme dupoint
fixe de Brouwer. ©Elsevier,
Paris1991 Mathematics Subject Classification. Primary 35 B 40, 35 B 45 ; Secondary 35 J 40.
Key and phrases. Phase Transition, Nonlinear Elliptic Equations.
Annales de l’lnstitut Henri Poincaré - Analyse non linéaire - 0294-1449
1. INTRODUCTION
The Cahn-Hilliard
equation [5]
is anaccepted macroscopic
field-theoretical model of processes such as
phase separation
in abinary alloy.
In its
original
form it is derived from a Helmholtz free energywhere f2 is the
region occupied by
thebody, u(x)
is a conservedorder
parameter representing
forexample
the concentration of one of thecomponents,
andF ( u)
is the free energydensity
which has a double wellstructure at low
temperatures (see Figure 1).
The mostcommonly
usedmodel is for
F(u) = ( 1 - u2)2.
The constant E is
proportional
to the range of intermolecular forces and thegradient
term is a contribution to the free energycoming
fromspatial
fluctuations of the order parameter. Moreover the mass m
= ~ ~ ~ Jo
udx isconstant. Thus a
stationary
solution ofE(u) Jo
udx takesthe
following
formwhere
f(u)
=F’ (~c) (see Figure 2)
and ~E E is a constant.There have been numerous studies of the Cahn-Hilliard
equation.
Theglobal
minimizer ofE ( u)
has a transitionlayer.
Moreprecisely
there existsan open set F such that if UE is a
global
minimizerthen UE
--~ 1 ono B T.
~cE r and c~T n Q is a minimal surface and has constant Annales de l’lnstitut Henri Poincaré - Analyse non linéairemean curvature, see
[16].
Thedynamics
of the interface have been studiedextensively,
see forexample [2], [3], [23].
Also local minimizers ofE( u)
have been studied and their transition
layer
structure has been established in[6]
and[13].
Inparticular,
Chen andKowalczyk
in[6]
usedboundary
mean curvature to construct local minimizers
(therefore transition layer solutions)
forequation (1.1).
In this paper we are concerned with solutions of
(1.1)
withspike layers.
Inthe one dimensional case, Bates and Fife
[4]
studied nucleationphenomena
for the Cahn-Hilliard
equation
andproved
the existence of three monotonenondecreasing stationary
solutions when m is in the metastableregion
( 1 /3
m1), (a)
the constant solution u m,(b)
aboundary spike layer
solution where thelayer
is located at the left-handendpoint, (c)
atransition
layer
solution with alayer
in the interior of the material.Motivated
by
the results of[4],
we shall construct aboundary spike layer
solution to
(1.1)
for E « 1 in thehigher
dimensional case when m is in the metastableregion.
The existence of
spike layer
solutions as well as the location and theprofile
of thepeaks
for otherproblems arising
in various models suchas
chemotaxis,
patternformation,
chemical reactortheory,
etc. have beenstudied
by Lin, Ni, Pan,
andTakagi [14, 17, 18, 19]
for the Neumannproblem
andby
Ni and Wei[20]
for the Dirichletproblem. However, they
do not have the volume constraint and the
nonlinearity
issimpler
than here.To our
knowledge
the present paper is the first to establish this kind of results for the Cahn-Hilliardequation
inhigher
dimensions without any symmetryassumptions
on Q.n°
Naturally
thesestationary
solutions are essential for theunderstanding
ofthe
dynamics
of thecorresponding
evolution process. While Bates and Fife[4]
prove some results in this direction for the one dimensional case thesequestions
are open forhigher
dimensions.In
[11]
in the one dimensional case the number of allstationary
solutionsis counted
by arguments using transversality.
First we make the
following
transformation.Rewrite
Then
equation (1.1)
becomes(Figure
3 showsqualitatively
how thegraph of g
lookslike.)
To accommodate more
general g
we assume that(1) g’(o)
= EC3(R; R).
(2) g ( v )
hasonly
two zeroes for v >0,
0 a 1 a2 andAnnales de I’Institut Henri Poincaré - Analyse non linéaire
(3)
The function v - isnonincreasing
in the interval(vo, a2)
wherevo is defined as the
unique
number ina 2 )
such thatg(s)
d s = 0.(4)
C for any v.Remarks. -
(1 )
Condition(3)
can be weakened further. Forexample,
theconditions in
[7]
will beenough
since wejust
need theuniqueness
andweak
nondegeneracy
of theground
state solutions of(1.3).
(2)
Condition(4)
is not a restrictionphysically
since in thephysical
world v is
always
bounded. Hence we canmodify h
nearinfinity
so thath satisfies
(4).
It is easy to see that for
f(u)
==-2u(1 - U2)
conditions(1), (2), (3),
and
(4)
are satisfied. Our main result can be stated as follows.THEOREM 1.1. - Let f2 be a bounded smooth domain in
R~ (N
>2)
andPo
E ~03A9 be such thatH(Po)
= 0 and(~2P0 H(P0) ~
0 whereH(Po)
is the mean curvature
of P0 ~
~03A9 and ~p° is thetangential
derivative atPo.
Thenfor
E 1 there exists a solution vEof (1.2)
such that v~ ~ 0 in~‘ o~ (SZ ~ Po ),
vE hasonly
one local(hence global)
maximumpoint PE
andPE
EPo,
--~Y(o)
> 0. Moreoveras E ~ 0 where
V (y)
is theunique
solutionof
(By
the results of[9]
and[24], (1.3)
has aunique
radialsolution).
The method of our construction evolves from that of
[8], [21]
and[22]
on the semi-classical
(i.e.
for small parameterh)
solution of the nonlinearSchrodinger equation
in
R~
where V is apotential
function and E is a real constant. Themethod of
Lyapunov-Schmidt
reduction was used in[8], [21]
and[22]
toconstruct solutions of
(1.4)
close tonondegenerate
criticalpoints
of V forh
sufficiently
small.n°
Following
thestrategy
of[9], [21] ] and [22]
we shall construct a solutionvE of
(1.2)
with maximum near agiven nondegenerate
criticalpoint
of themean curvature
Po
onHeuristically
we rescale(1.2)
to obtainwhere
uE(z)
= for z =(x -
e andf2E,P
={z
Eez -E- P e
and vE
is the unit outer normal toTaking
the limit E 2014~0,
uE -~ V where V is theunique
solution ofwith
V(0)
= V. Therefore theground
state solution V restricted toR+
can be anapproximate
solution for Since the linearizedproblem arising
from(1.6)
has the(N -I)-dimensional
kernelspan{~V ~y1,...,~V ~yN-1}
we first "solve"
(1.6)
up to this kernel and then use thenondegeneracy
ofH ( Po )
to take care of the kernelseparately.
The
paper isorganized
as follows.Notation, preliminaries
and someuseful estimates are
explained
in Section 2. Section 3 contains thesetup
of ourproblem
and we solve(1.2)
up toapproximate
kernel andcokernel, respectively. Finally
in Section 4 we solve the reducedproblem.
2. TECHNICAL ANALYSIS
In this section we introduce a
projection
and derive some useful estimates.Throughout
the paper we shall use the letter C to denote ageneric positive
constant which may vary from term to term. We denoteR~
=>
0 ~ .
Let V be theunique
solution of(1.3).
Let P ~ We can define a
diffeomorphism straightening
theboundary
in a
neighborhood
of P. After rotation of the coordinate system we mayassume that the inward normal to at P is
pointing
in the directionof the
positive
Denote x’ =B’(Ro)
=R0}
andS21 {(x’, xN)
EPy
>p(x’ - P’)}
whereR0}. Then,
since is
smooth,
we can find a constantRo
> 0 such that ~03A9 nQi
canbe
represented by
thegraph
of a smooth function p p :B’ ( Ro ) --~ R
whereAnnales de l’Institut Henri Poincaré - Analyse non linéaire
=
0, ~ pp (o)
= 0. From now on we omit the use of P in pp andwrite p
instead if this can be done withoutcausing
confusion. The sum of theprincipal
curvatures of aS~ at P isH(P) = ~N 11
whereand
higher
derivatives will be defined in the same way.By Taylor expansion
we have
In the
following
we use pe~ to denote themultiple
differentiation where cx is amultiple
index.For x E let
v(x)
denote the unit outward normal at x and the normal derivative. Let(T~ ( ~ ) , ... , TN _ 1 ( ~ ) )
denote( N - 1) linearly independent tangential
vectors and ..,~Ta_1 )
thetangential
derivatives.In our coordinate
system,
for x G oi := ~03A9 nB(P, Ro),
we haveFor a smooth bounded domain U we now introduce a
projection Pu
ofH2 (U)
onto{v
E = 0 at as follows: For v EH2(U)
let w =
Puv
be theunique
solution of theboundary
valueproblem
Vol. 4-1998.
Let
hE,p(x)
=Y~x ~P) -
whereThen satisfies
We denote
For ~; E SZ, set now
Furthermore,
for x Ef21
we introduce the transformationNote that then
The
Laplace operator
and theboundary
derivativeoperator
becomea2 N-1 a2 ~
Let vi be the
unique
solution ofwhere il‘ is the radial derivative of
V,
i.e. V’ =Y. (r),
and r =Let v2 be the
unique
solution ofAnnales de l’Institut Henri Poincaré - Analyse non linéaire
Let v3 be the
unique
solution ofNote that v2 are even functions in
~/ ==
..., and v3 is an oddfunction in
~~
_ ...,(I.e.
=vl(-~J~, v3(~~, ~~v) _
-v3{-~~ , ~N)). Moreover,
it is easy to see that~v2 ~,
for some 0 ~c Let be a smooth cutoff function such that
=
1, x E B(0, Ro - 8)
andx(x)
= 0 for x E(for
apositive
numberb).
SetThen we have PROPOSITION 2.1.
To prove
Proposition 2.1,
webegin
withLEMMA 2.2. - Let u be a solution
of
Assume that
f ~2 fa~ i~12 ~
ThenProof. - Multiplying
theequation by u,
we haveLemma 2.2 follows
easily by
thefollowing interpolation inequality (the proof
of it isdelayed
toAppendix A),
where
= ~ z ~ x
= P + ez E for a fixed P E 0Proof of Proposition
2 .1 . - We firstcompute
theequation
forwhere denotes all the terms
involving
derivatives of x. Since for some p~/m
we havefE
Gand
f E
C. On the otherhand,
for x E ~SZ it holds thatAnnales de l’lnstitut Henri Poincaré - Analyse non linéaire
Note that
Furthermore,
where
again
denotes all the termsinvolving
derivatives of x. Thisimplies
T /‘Therefore
15, n° 4-1998.
Let = P + Ez. Then satisfies
where 9E E and both the
corresponding
normsare bounded
independent
of E. Henceby
Lemma 2.2Therefore
Proposition
2.1 isproved.
C7We next
analyze
Afterchoosing
a suitablecoordinate
system
we can assume that Thensatisfies
We
compute
Now we have
(let x
= P +Ez)
Annales de l’lnstitut Henri Poincaré - Analyse non linéaire
Let
Here wi is the
unique
solution ofNote that
]
for some pm
and w 1 is an oddfunction
in y .
Then w2 satisfiesNote
that [
for some ,uyfm.
Similar to theproof
of
Proposition 2.1,
we havePROPOSITION 2.3. -
Vol. 4-1998.
where wl is
defined
above andFinally,
letWe have LEMMA 2.4. -
where
H~(I-~+ ) _ ~~c
EI~2(I-~+ ), ay~ _ ~
o~Proof -
See Lemma 4.2 in[19].
Q3. REDUCTION TO FINITE DIMENSIONS Let P ~ 03A9 and
Let be a Hilbert space defined
by
For u E set
Then
solving equation (1.2)
isequivalent
toTo this
end,
we firststudy
the linearized operatorAnnales de l’Institut Henri Poincaré - Analyse non linéaire
LE
is not invertible due to theapproximate
kernelin It is easy to see
(integration by parts)
that the cokernel ofLE
coincides with its kernel. We chooseapproximate
cokernel and kernelas follows:
Let denote the
projection
inL2(nE,p)
onto Ourgoal
in thissection is to show that the
equation
has a
unique
solution E03BA|~,P
if E is smallenough.
As a
preparation
in thefollowing
twopropositions
we showinvertibility
of the
corresponding
linearizedoperator..
PROPOSITION 3.1. - Let
LE, p
= oLE.
There existpositive
constantssuch that
for
all E E(0, E)
for
all 03A6 EPROPOSITION 3.2. - There exists a
positive
constantE
such thatfor
allE E
(0, E)
and P E ~03A9 the mapis
surjective.
Proof of Proposition.
3 .1 . - We will follow the method used in[9], [21 ]
and
[22]. Suppose
that{3.1)
is false. Then there existsequences ~E~~,
with
P~
E~ ~
E such thatWe omit the argument ,p~ where this can be done without confusion.
Denote ....
Note that
by Proposition
2.3 and because of thesymmetry
of the function wi , whichwas defined in
(2.9),
where is the Kroneckersymbol.
Furthermore because of(3.2),
as k - oo. Let and T be as defined in Section 2. Then T has
an inverse
T-1
such thatRecall that ~y =
T(x).
We introduce a newsequence {03C6k} by
for y E
I~+ .
Since T andT -1
have bounded derivatives it follows from(3.3)
and the smoothnessof x
thatfor all k
sufficiently large.
Therefore there exists asubsequence, again
denoted which converges
weakly
in to a limit asI~ --~ oo. We are now
going
to show that 0. As a first step we deduceThis statement is shown as follows
(note
that det DT = detDT-1
=1)
Annales de l’lnstitut Henri Poincaré - Analyse non linéaire
where
03A91
is as defined in section 2. In the lastexpression
the first twoterms tend to zero as oo since is bounded in and
[...]
-~ 0strongly
in.~2 (S~) .
The last two terms tend to zero oobecause of the
exponential decay
of atinfinity.
We conclude
This
implies (3.6).
Let
Ko
andCo
be the kernel andcokernel, respectively,
of the linearoperator
which is the Frechet derivative at V ofNote that
n° 4-1998.
Equation (3.6) implies
thatBy
theexponential decay
of V andby (3.2)
we have afterpossibly taking
a furthersubsequence
thati.e.
Ko.
Therefore = 0.Hence
as k - oo.
By
the definition of weget I>k
-~ 0 inH2
andFurthermore,
Since
we have that
In summary:
From
(3.9)
and thefollowing elliptic regularity
estimate(for
aproof
seeAppendix B)
for 03A6k
EHN
weimply
thatThis contradicts the
assumption
and the
proof
ofProposition
3.1 iscompleted.
C~Annales de l’lnstitut Henri Poincaré - Analyse non linéaire
Proof of Proposition.
3.2. - Assume that the statement is not true.Then there exist such that 6~. -~ 0 as k --~ oo and
P~,
E and such that for allk,
---~ notsurjective.
Let
KE,p
and be the kernel and cokernel ofLE, respectively.
Then:
C ~,~~ ~
is notsurjective,
i.e. for all k there exists a0 such that W for all W E This is
equivalent
to~~
E and 0. Because we can assumethat
w.l.o.g.
= 1 this can be rewritten as follows. For all k there exists such thatNow since
and because of the
elliptic
estimate(3.10)
it follows thatfor some constant C
independent
of k . Extract asubsequence (again
denotedby
such that as defined in(3.5)
convergesweakly
in~2 ~R+ ~
to as 7~ ~ oo and satisfies
with
From
(3.12)
we deduce thatbelongs
to the kernel of and(3.13) implies
that lies in theorthogonal complement
of the kernel ofTherefore = 0. As in the
proof
ofProposition
3.1 we showby
the
elliptic regularity
estimate(3.10)
Thiscontradicts
(3.11 )
and theproof
ofProposition
3.2 is finished. D We are now in aposition
to solve theequation
Since is invertible
(call
the inverse we can rewritewhere
and the
operator
is definedby
the lastequation
for 03A6 ~We are
going
to show that theoperator ME,p
is a contraction onif 8 is small
enough.
We havewhere A > 0 is
independent
of 6 > 0 andc($)
~ 0 as 03B4 ~ 0.Similarly
we show
where -~ 0 as 8 -~ 0. Therefore
ME,p
is a contraction onB8.
Theexistence of a fixed
point
now follows from the ContractionMapping Principle
and is a solution of(3.15).
Because of
we have
We have
proved
LEMMA 3.3. - There exists E > 0 such that
for
everypair of
E, P with0 E E and P G there exists a
unique
E03BA|~,P satisfying
E
CE,p
andWe need another statement about the
asymptotic
behavior of the functionas E --~ 0, which
gives
anexpansion
in E and is stated as follows.Annales de l’lnstitut Henri Poincaré - Analyse non linéaire
PROPOSITION 3.4.
where
and
~o
is theunique
solutionof
~o
isorthogonal
to the kernelof Lo (3.18)
where
Lo
= ~ - m +h’ (V), Lo : Proof -
Note that the kernel ofLo
isFurthermore we have
The notations for
03A91, ~, 03C1
and T are as in section 2. Ourstrategy
is todecompose
into threeparts
and show that each of them is bounded in!
. as 6 2014~ 0. That means we make the ansatzwhere the
functions 03A81~, 03A82,1~, 03A82,2~
will be defined as follows.Let WQ
bethe
unique
solution ofwhere
Vol. n° 4-1998.
Since C there exists a constant C > 0 such that
Define 03A82,1~ by
where ~r is the
projection
inL2
onto Because of theexponential decay
of~o,
the smoothnessof x
and andby (3.20)
it follows thatFinally, define ~’~(~)
to be theunique
solution inH~, ( SZ )
of thefollowing equation
where
Note that the
right-hand
side of the lastequation
lies in sinceThis is clear for
by
definition.By
construction we have thatE2 (~E
+~E n )
satisfies the Neumannboundary
condition.By (3.18)
and the smoothnessof ~
we conclude that EH2. By (3.19),
~
EH2. Finally,
since ej EH2
wherewe have E
~2. Therefore
eC;p. Furthermore,
thefollowing
lemma is true.
LEMMA 3.5.
Annales de /’lnstitut Henri Poincaré - Analyse non linéaire
Proof -
We havewhere
Note that
by
the definitionof x
and theexponential decay
of V. FurthermoreThis proves Lemma 3.5. D
By
Lemma 3.5 and theinvertibility
ofProposition
3.4 follows. DVol.
4. THE REDUCED PROBLEM
In this section we solve the reduced
problem
and prove our main theorem.By
Lemma 3.3 there exists aunique
solutionKflp
such thatOur idea is to find P such that
Let
Then
WE(P)
is a continuous map of P.Let us now calculate
WEep).
First ofall,
from condition(4)
onh,
we haveTherefore
Hence
by Proposition
2.3because
Annales de I Institut Henri Poincaré - Analyse non linéaire
and
Proposition
2.3. On the otherhand,
sincewe conclude
where and
J~
are definedby
the lastequality.
We first calculateVol. 4-1998.
Note that
and
since
~o
is even and V - =EVl
whereVl
is even.By Proposition
2.1
Hence
So
We next
compute IE .
since
~o
is even.Finally,
we compute the termJE.
Annales de l’Institut Henri Poincaré - Analyse non linéaire
But
where
Combining JE,
we obtainwhere is continuous in P and =
uniformly
in P.Suppose
atPo,
we have 0 then standard Brouwer’sVol. 4-1998.
fixed
point
theorem shows that for e « 1 there exists aP~
such that=
0,P, ~ Po.
Thus we have
proved
thefollowing proposition.
PROPOSITION 4.1. - For E
sufficiently
small there existpoints PE
withPE
-~Po
such thatWE(PE)
= 0.By
Lemma 3.3 andProposition
4.1 we havei. e.
i.e. UE is a solution of the Cahn-Hilliard
equation.
Moreoverand
FE
-~Po E
~SZ.Finally,
westudy
theshape
of the solutions LetPE
be any local maximumpoint
of Thenby (1.1),
But
f~
-~ +h(V)
>0,
henceSo a1 > 0. On the other
hand,
from ourconstruction,
Annales de l’lnstitut Henri Poincaré - Analyse non linéaire
Similar
proof
as in Theorem 1.2 of[18],
we concludePE
E and thereis
only
one suchPE.
Appendix
A: TraceInequality
LEMMA A.I. - Let 0 E 1. Then
for
all E where the constant C isindependent of
E.Note that the constant C in
(A.I)
isrequired
to beindependent
ofE. Therefore Lemma A.I is
special although
traceinequalities
arequite
standard.
Proof of
Lemma A .1. - For 03A6 E define W Eby
alinear transformation:
Observe that
~~~’~~L2~a~E,P)
= =and = Therefore
(and
after
translation) (A.I)
isequivalent
tofor all ~ E and 0 E 1 where C is
independent
of E. Theproof
of(A.2)
is standard and is omitted here(see
forexample
theproof
of Theorem 3.1 in
[1]).
DAppendix
B: Anelliptic regularity
estimateIn this section we prove the
following inequality
for all ~ E 0 ~ Eo where is as defined in Section 2 and C is a constant
independent
of E. For apoint
P on 9Q we can finda constant
Ro
> 0 and a smooth function p :B’ (l~o ) ~
R such that inB (P, Ro)
theboundary
~03A9 is describedby
thegraph
of p where p satisfiesp(0)
=0, Vp(0)
= 0(compare
Section2).
Furthermore there exists a map?7 =
T(~)
withDT(0)
= I(the identity map)
from aneighborhood Up
ofP onto a ball
B(O, Rl ) (compare
Section3). By
a linear transformationwe
naturally
get a map T E fromUp = ~ (~ -
e onto a ballVol. 4-1998.
with center at 0. We Then the
Laplace operator
becomes =Dy
+ AE whereObserve that for
given 8
> 0 we can findl~l
> 0 and Eo such that forIn the same way we transform
where BE is a differential
operator
on =0~
with coefficients which are bounded in L°° for 0E
Eo(compare
section2).
From{ Up I P
e we select a finitesubcovering
of and denote itby
~ Ul , ... , Un ~ . Choosing Uo
the is a finitecovering
of f2
consisting
of open sets. Wekeep
thiscovering
fixed from now on.Let
~80, ... ,
be apartition
ofunity
subordinate to this opencovering.
Denote
Of (y) = 9i
o Sincewe have
Since
8o
has compactsupport
inRN
Annales de l’lnstitut Henri Poincaré - Analyse non linéaire
(see
forexample [10], Corollary 9.10).
Because ofand
we obtain
We are now
going
to estimate i =1,...,
n. Note thatwhere k =
0,1,
or 2 andfor v E
H2(UiE).
Then(see
forexample [15],
Theorem4.1).
Now(B.2) implies
thatTherefore from
(B.6)
Vol. n° 4-1998.
For the
operator
BE we can calculate in ananalogous
way. The trace theoremimplies
Since C is
by
constructionindependent
of E we can choose 8 so small that1 -
Cb2 > 1/2.
Thisimplies
Similarly
as beforeand
because of = 0.
Combining (B.7) - (B.9)
weget
We
conclude, using (B.3), (B.4)
and(B.10),
thatwhere
Cn depends
on n. Since n isindependent
of 6 theproof
of(B.I)
is finished. D
Annales de l’lnstitut Henri Poincaré - Analyse non linéaire
ACKNOWLEDGEMENTS
The first author would like to thank Professor
Wei-Ming
Ni for hisenlightening
discussions. Part of the work isinspired by
some related workby
ProfessorWei-Ming
Ni and Professor Y.-G. Oh. This research wasdone while the second author visited the
Department
ofMathematics,
The ChineseUniversity
ofHong Kong.
It issupported by
a Direct Grant from The ChineseUniversity
ofHong Kong
andby
agrant
of theEuropean
Union
(contract ERBCHBICT930744).
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(Manuscript received May 9, 1996;
revised June 26, 1996.)
Annales de l’Institut Henri Poincaré - Analyse non linéaire