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(1)

A NNALI DELLA

S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze

H ITOSHI I SHII

A boundary value problem of the Dirichlet type for Hamilton-Jacobi equations

Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4

e

série, tome 16, n

o

1 (1989), p. 105-135

<http://www.numdam.org/item?id=ASNSP_1989_4_16_1_105_0>

© Scuola Normale Superiore, Pisa, 1989, tous droits réservés.

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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques

http://www.numdam.org/

(2)

for Hamilton - Jacobi Equations

HITOSHI ISHII

0. - Introduction

In this paper we consider the

boundary

value

problem

for Hamilton -

Jacobi

equations:

in

or on ~ i

Here 11 is an

open subset

and h : an --~ R

are

given functions, u : fi

--~ R is the unknown and Du denotes the

gradient

of

u.

The

meaning

of

(solution of) problem (HJ) - (BC)

will be made

precise

in

Section 1

by modifying

the notion of

viscosity solution,

introduced

originally by

M. G. Crandall - P.L. Lions

[7],

so that the

boundary

condition is

appropriately

taken into account. There are

already

several attempts of similar modifications of the notion of

viscosity

solution. For this we refer to R. Jensen

[15],

P.L.

Lions

[18],

M.G. Crandall - R. Newcomb

[8],

H.M. Soner

[20],

P.E.

Souganidis [21],

1.

Capuzzo

Dolcetta - P.L. Lions

[4]

and G. Barles - B. Perthame

[1].

Our

introducing

the

boundary

condition

(BC)

is

strongly

motivated

by

the

analogy

to the Neumann condition for Hamilton - Jacobi

equations

in P.L. Lions

[18].

Problem

(HJ) - (BC)

is

important

in deterministic

optimal

control

theory.

The value functions of exit time

problems satisfy (HJ) - (BC),

where the first

order PDE in

(HJ)

is the so-called Bellman

equation,

in the

viscosity

sense, and

they

are characterized to be

viscosity

solutions of

(HJ) - (BC),

under

appropriate hypotheses.

We prove these in Sections 3 and 5

where, denoting H(x,

u,

p) - u again by H (x, u, p),

we treat the

problem:

in

Pervenuto alla Redazione il 25 Novembre 1986 e in forma definitiva il 7 Febbraio 1989.

(3)

and

or on

The

boundary problem

for

(HJ),

with the Dirichlet condition u = h, is not solvable in

general.

A

compatibility

condition on h is

required

to be satisfied in order that the Dirichlet

problem

for

(HJ)

is solvable

(see

P.L. Lions

[16]),

and

the condition on h is

usually

hard to check. See also the recent work

[9] by

H.

Engler.

On the other

hand, problem (HJ) - (BC)

is

solvable,

in a weak sense, under

quite general hypotheses (see Proposition

1.3 in Section

1).

Moreover the

uniqueness

and existence of a continuous

viscosity

solution of

(HJ) - (BC)

is

established under suitable

assumptions

in Sections 2 and 4. Therefore

problem (HJ) - (BC)

seems, at least for the

author,

a natural

replacement

of the Dirichlet

problem

for

(HJ).

Problem

(HJ) - (BC)

also arises

naturally

in connection with

elliptic singular perturbation problems

with the Dirichlet

boundary

condition or

with the

vanishing viscosity

method. In this direction see

Proposition

1.2 and

refer to H. Ishii - S. Koike

[14]

for an

application

of our results to

elliptic singular perturbation problems. Finally

we remark that G. Barles - B. Perthame

[2]

and P.L. Lions

[19]

have

recently

treated

(HJ) - (BC) independently.

1. -

Viscosity

solutions

In this section we define the

viscosity

solution of the

boundary problem

for a second order PDE:

in and

or on

and then present some of its

properties.

Here n is an open subset of is a subset of the

boundary

F : n u E x R x x - R, where

~N

denotes the space of real N x N

matrices,

and are

given functions,

u : n u E -~ R is the

unknown,

and

D2 u

denotes the Hessian matrix of u. When F is

independent

of the last

variables,

i.e.

F (x,

r, p,

~)

=

F (x,

r,

p),

and B =

F, problem (1.1) - (1.2)

will be

simply

written as

on

Our main interest here is to

study problem (HJ) - (BC). However,

it seems natural to see the connection between

viscosity

solutions of

(HJ) - (BC)

and

the

vanishing viscosity

method in

light

of the

stability

property of

viscosity

solutions of

(1.1) - (1.2).

(4)

Let

S,

T and U be subsets of

satisfying

S c U and S c T c

S’.

For

a function

f :

U --; R u

{ - oo, oo ~,

we define

by

sup

This function

(liS, T)*

is upper semicontinuous

(u.s.c.

in

short)

on T, and we call it the u.s.c.

envelope of f

restricted to S on T. We note /1 that

(flS,T)*(x) ~! f (x)

for x E S and

that,

if

f

is u.s.c. on S, then

I

( f ~S, T)# (x)

= for x E S. We remark

that,

if

( f I S, T)* (x)

oo for

x E T, then

We define the lower semicontinuous

(l.s.c.

in

short) envelope

of f

restricted to S on T

by (fI8, T ) * = - (- flS, T ) * .

When S = T =

U,

we

write

f *

and

f * , respectively,

for

(fI8, T ) *

and

(f I S, T ) * .

We call a function u : 11 u E -~ R Li a

viscosity

subsolution of

problem ( 1.1 ) - (1.2)

if

u* ( x )

oo, for x E fl u E, and whenever p E

and u* - p attains its local maximum at a

point y En

u

E,

then

and

or if

Similarly,

we call a function a

viscosity supersolution

of

( 1.1 ) - (1.2)

if

u* ( ~ ~

&#x3E; - oo, for x and

whenever p

E

and u* - p attains its local minimun at a

point

y E 11 u E, then

/

if and

A

viscosity

solution of

(1.1 ) - (1.2)

is defined to be a function on 11 u E which is both a

viscosity

sub- and

supersolution

of

( 1.1 ) - (1.2).

Note that

this definition makes sense even for functions

F, B

which take values in R u

(-cxJ, cxJ),

and that if

F(x, r, p, ç)

is

independent

of

~,

then the space

(5)

of "test

functions",

can be

replaced by

the space

We say also that u satisfies 0 in n and

B ( x, u, Du)

0 or

F ( x,

u,

Du, D2 u)

0 on E

(resp., F ( x,

u,

Du,

0 in H and

B ( x, u, Du) &#x3E;

0

or 0 on

E),

in the

viscosity

sense, if u is a

viscosity

subsolution

(resp., supersolution)

of

(1.1) - (1.2).

Of course, this definition is a modification of the

original

one introduced

by

M.G. Crandall - P.L. Lions

[7]

and

by

P.L. Lions

[17]

to the

boundary

value

problem.

The

boundary

condition

(1.2)

is motivated

by

the work

[18] by

P.L.

Lions

concerning

the Neumann

problem

for Hamilton - Jacobi

equations.

In our

notation,

the Neumann condition for

(HJ),

in

[18],

can be written as

or on

where v denotes the outward unit normal of an

(assuming

it

exists).

We

should also remark that G. Barles - B. Perthame

[2]

and P.L. Lions

[19]

have

independently

introduced the same notion of

viscosity

solutions for

(HJ) - (BC)

as ours. We refer to H.M. Soner

[20],

I.

Capuzzo

Dolcetta - P.L. Lions

[4]

for

another type of the

boundary

condition for Hamilton - Jacobi

equations

and to

M.G. Crandall - H. Ishii - P.L. Lions

[6],

H. Ishii

[10,12,13]

and G. Barles -

B. Perthame

[1]

for the work related to discontinuous

viscosity

solutions and

Hamiltonians.

PROPOSITION 1.1. Let E be an open subset

of

Let S be a

family of viscosity

subsolutions

of (1.1) - (1.2).

Set

u(x) =

sup

{ v ( x) :

v E

S }, for

x e n u E. Assume u is

locally

bounded

from

above on fi U E. Then u is a

viscosity

subsolution

of ( 1.1 ) - (1.2).

This is a

generalization

of M.G. Crandall - L.C. Evans - P.L. Lions

[5, Prop. 1.4]

and H. Ishii

[13, Prop. 2.4].

The

proof

of this

proposition

is similar

to that of

[13, Prop. 2.4],

and we omit

giving

it here. An

analogous

assertion

holds for

supersolutions.

To see

this,

observe that u is a

viscosity

subsolution of

(1.1) - (1.2)

if and

only

if v = -u is a

viscosity supersolution

of

(1.1) - (1.2),

with F and B

replaced, respectively, by

the functions

and

PROPOSITION 1.2.

(Stability of viscosity solutions).

Let E be an open subset

of

an. For 0 E 1, let

(6)

be

given functions.

Assume

that, for

each 0 e 1, Us is a

viscosity

subsolution

of ( 1.1 ) - (1.2),

with

F,

and

B,

in

place of

F and B,

respectively.

Set

for

and

.for

. Assume u is

locally

bounded

from

above on 11 u E.

Then u is a

viscosity

subsolution

of ( 1.1 ) - (1.2)

with these F and B.

This

generalizes

a result of G. Barles - B. Perthame

[1,

Theorem

A.2].

Of course, we have a

proposition

similar to the above for

supersolutions.

We

can prove this

proposition

as in the

proof

of

[1,

Theorem

A.2],

and we do not

give

the details here.

The

following

observation is useful in

applications

of

Proposition

1.2 to

elliptic perturbation problems

or the

vanishing viscosity

method.

are continuous and that u E

u £)

n satisfies

F ( x,

u,

Du, D2 u)

0 in

n and

B(x, u, Du)

0 on E, in the classical sense.

Assume,

in

addition,

that

- F is

elliptic,

i.e.

for

( x,

r, p,

ç) E nxR xMN and p

E

C2(n)

such

that p

attains its maximum

at x, and that B satisfies the condition:

B ( x, r, p) +D~(~c)) &#x3E; B ( x, r, p) ,

for

(x, r, p)

E E x R x E

u £)

such

that p

attains its maximum at x. Then u is a

viscosity

subsolution of

( 1.1 ) - (1.2).

From

Proposition

1.2 we see, for

instance,

the

following.

and

h : all --~ R be continuous. For each 0 e 1, let Us E

C (fi)

n

satisfy -

+ 0 in

n,

where A denotes the N dimensional

Laplacian,

onafi, in the classical sense. Set = lim sup

r10

0 e

r},

and assume

u(x)

oo, for x

e fi.

Then u is a

viscosity

subsolution of

(HJ) - (BC).

PROPOSITION 1.3.

(Existence of viscosity solutions).

Let E be an open subset

of

an. Let

f

and g

be, respectively, viscosity

sub- and

supersolutions of

(7)

( 1.1 ) - (1.2).

Assume

f

s g on 11 U E and that

f

and g are

locally

bounded on

n U E.

by

= sup

viscosity

subsolution

of ( 1.1 ) - (1.2),

v g on n U

E).

Then u is a

viscosity

solution

of ( 1.1 ) - (1.2).

This extends Theorem 3.1 of H. Ishii

[13].

We leave it to the reader to prove this

proposition

as the

proof

is a

simple

modification of that of

[13,

Theorem

3 .1 ] . "

2. -

Comparison

of

viscosity

solutions

. Hereafter we

study problem (HJ) - (BC).

We need the

following assumptions

on H and fl.

(H 1 )

For each

(x, p)

x

the

function u ~

H (x, u, p)

is

nondecreasing

on R.

(H2)

There is a continuous

nondecreasing

function rral :

[0,oo)

--&#x3E;

~0, oo), satisfying

rral

(0)

= 0, such that

for and

p E JR. N.

(H3)

There is a continuous

nondecreasing

function m2 :

[0, 00)

-

[0, 00), satisfying m2 (0)

= 0, such that

and

(H4)

There is a continuous

function n : fi -_+

and a constant b &#x3E; 0 such that

for and

(where B (x, 6)

is the usual

sphere

centred at x with

radius 6).

THEOREM 2.1. Assume 11 is bounded and that

(H 1 ) - (H4)

hold. Let u

and v

satisfy, respectively,

in

on

where a &#x3E; 0 is a constant, and

in

on

(8)

in the

viscosity

sense. Then:

(i) If

u and v

are continuous

at

points of

a11 and h is continuous on an, then u v

on fi.

(ii) If

u

(resp., v)

is continuous at

points of a11,

h is l.s.c.

(resp., u.s.c.)

on

5n and u h

(resp.,

v &#x3E;

h)

holds on an, then u v

on-a.

REMARK 2.1. As the

proof

below

shows, the

above

theorem

is still valid if the

inequality

in

(H3)

is satisfied

only

in

a

subset

of 0 x

R x

R N

of the

form U x R x where U is a

neighbourhood

of a11 in n.

REMARK 2.2. Of course, it is

possible

to formulate a

comparison

theorem

like Theorem 2.1 for unbounded domains.

The

proof

below is a modification of the arguments in the

proof

of H.M.

Soner

[20,

Theorem

2.2]

to the current

problem.

PROOF.

Replacing

u and v

by

u* and v*, we may assume that u is

u.s.c. and v l.s.c. on

fi. First,

we prove assertion

(i).

To this

end,

we suppose

max(u - v )

&#x3E; 0 and will obtain a contradiction in each of the

following

three

n

possible

cases. We will use the notation:

and

CASE 1. Set

r E R and p, q E

Then H

is l.s.c.

by (H 1 )

and w satisfies in x

n,

in the

viscosity

sense.

Since

R=,(~r,p) &#x3E; limH(x,s,p)

slr and

~*(a:,r,p) limJ?(a:,5,p),

air for

by (ill) - (H3),

we have

for r, s e R

satisfying

r &#x3E; s and

Let

2 ,

2 and set

A=max(u-v)

a and

for Then we have

(9)

for and

by (H2). Also,

we have

for I

for and

for witt

Now we fix 6 so small that

max(u - v )

&#x3E; A + 26 and then e so small that

and if

and Ix - yl e (this

is

possible

since w is u.s.c. and

w(x,

A, for x E

an).

Observe that w - p attains a

positive

maximum at some

point (~, y) E ~ (~)

since w is u.s.c. on

A(e)

and

max

0 A (s)

(w - ~p)

0. Thus

(2.3)

and

(2.5), together

with

(2.4), yield

a contradiction.

CASE 2.

max(u - v) = (u - v) (z)

and

v (z) h (z),

for some z E af2. Let

and be as in

(H4).

Define 1

by

where e is a small

positive

number. Let

(~, y)

be a

point of fi x n

such that

~~ (x, y) -

max

4D,.

Let us assume e b. Then z +

by (H4),

and

hence

~~ (~, y) &#x3E; ~~ (z -~ ~r~ (z), z) . 5x5

This

yields

where m3 is the modulus of

continuity

of u and Therefore

and so

(10)

for some constant

C2

&#x3E; 0.

Using again (2.6),

we get

From

this,

we see

and

for some real-valued continuous function m4 on

~0, oo) satisfying m4(0) =

0.

Since

by (2.8) and, choosing

0 b small

enough, ~r~ ( y) - ~ (z) ~ 1+ M4 (s) -

b, for

0 e

b 1,

in view of

(2.9),

we see from

(H4)

that Y E fi, for 0 e

b 1.

Since u satisfies

(2.1),

in the

viscosity

sense, we thus find

for

Using (2.6), (2.7)

and

(2.9),

we find

Hence, selecting

0

b 2

b small

enough,

we see that if 0 e

b 2 and y E

Since v solves

(2.2),

in the

viscosity

sense, we now see

Choose 0

b3

min so small that for

0

b3.

We henceforth assume 0 e

b3.

Now

(2.6)

guarantees

u(()

&#x3E;

V(Y),

for 0 e

b 3 . Setting 6

= and

combining (2.10),

(2.11)

and

(2.4),

we get

(11)

Thus, using (H3), (H2), (2.7), (2.8)

and

(2.9),

we find

this

yields

a contradiction

by selecting

e small

enough.

CASE 3.

max(u - v) = (u - v) (z)

and

u(z)

&#x3E;

h(z),

for some z E Set

_

n

_

h = -h on afi, onil,

and

for

As

remarked

before,

u and v,

solve, respectively, (2.1 )

and

(2.2)

with H

and h

in

place

of H and

h,

in the

viscosity

sense. We

easily

see that

(HI) -

(H3)

are satisfied for H = H and that

max(v - 5) = (u - v) (z)

and

v(z) h(z).

n

Thus the present case is reduced to Case

2,

and we have a contradiction.

Now we turn to the

proof

of assertion

(ii).

If we assume

max(u - v)

&#x3E; 0 n

and argue as in the

proof

of assertion

(i),

then the

assumption u

h on

(resp.,

v &#x3E; h on

an) eliminates,

from the arguments, the

possibility

that

Case 3

(resp.,

Case

2)

occurs. Meanwhile we

only

need the

following continuity

of u, v and h: the

continuity

of u

(resp., v)

at

points

of an and the lower

(resp., upper) semicontinuity

of h in the arguments of Cases 1 and 2

(resp.,

Cases 1

and

3).

D

A more

precise

result is needed in Section 4.

THEOREM 2.2. Let a be a

positive

number and h : R be l.s.c..

Assume fl is

bounded

and that

(HI) - (H3)

hold. Let u and v,

respectively,

be

u.s.c. and l.s.c. on

fi,

and

satisfy (2.1)

and

(2.2),

in the

viscosity

sense. Let

r be an open subset

of

an, and assume:

(i)

u v, on

anBr,. (ii) u

h, on

r; and

(iii) for

each z E r, there is a

positive

number b, a bounded sequence and a sequence C

(0, 00) converging

to 0, such that

for

and lim n-00

u(z

+ =

u(z).

Then u v on

fi.

The

proof

of this theorem is similar to that of Theorem 3.1. We

just

present its outline here and leave the details to the reader.

OUTLINE OF PROOF.

Suppose max(u - v )

&#x3E; 0. Let z

e n

be a

point

j n

where the maximum of u - v is attained.

By assumption, z

e H U F. If

max(u -

an

v ) max ( u -

n

v),

then the same

argument,

as in Case 1 of the

proof

(12)

of Theorem

2.1, yields

a contradiction. If z E r, then we go as in Case 2 of the

proof

of Theorem

2.1,

except that we now use

with

instead of and will get a contradiction. Thus i

COROLLARY 2.1. Let S~ be bounded and conditions

(H 1 ) - (H4)

be

satisfied.

Let u and v :

0 -+

R be,

respectively, viscosity

subsolution and

supersolution of (HJ)’ - (BC)’.

Then the same assertions, as

(i)

and

(ii) of

Theorem

2.1,

hold.

REMARK 2.3. We have an

assertion,

similar to this

collorary,

which

corresponds

to Theorem 2.2. This remark also

applies

to

Corollary

2.2. below.

-

PROOF. Let e &#x3E; 0 and define u E

by

Then Us

solves

in

on

in the

viscosity

sense. From Theorem 2.1 we find that v on

0

in all cases.

Sending e 10,

we conclude the

proof.

D

COROLLARY

2.2. be bounded and

(HI) - (H4)

be

satisfied.

Let u and

v : 0 -+

R

be, respectively, viscosity

sub- and

supersolutions of (HJ) - (BC).

Assume moreover that p --&#x3E; H

( x,

r,

p) is

convex on

R N for

each

( x, r)

E

n

x R,

and that there is a

function 0

E cl

(0)

and a constant a &#x3E; 0

for

which

for

Then the same assertions, as

(i)

and

(ii)

in Theorem 2.1, hold.

PROOF. Note that h is bounded below on afi, in all cases. Therefore we may

h(x),

for x E

by adding

a

negative

constant to h, if necessary.

Then 0

is a

viscosity

subsolution of

(HJ) - (BC)

and hence the

maximum of u

and 0

taken

pointwise,

is a

viscosity

subsolution of

(HJ) - (BC) by Proposition

1.1. Now let 0 6 1 and set =

8 u V ~ ( x ~ -+- ( 1- 8 ) ~ ( ~ ~ ,

for x E

n. By

the

convexity

of H, we see that wo satisfies

in

on

in the

viscosity sense.

To check

this, let p

E and suppose attains its maximum

at yEn. Suppose

further

0

(13)

(this implies if y E

otherwise we are done. Then

attains its maximum at y, and hence

Thus

by (2.12);

this proves

(2.13).

Now

Theorem 2.1

guarantees v, on

fi.

Sending

0

T

1, we see that v &#x3E; u

V 0

&#x3E; u on

fi.

D REMARK 2.4.

If

u

(resp., v)

is

Lipschitz

continuous on

fi,

in assertion

(ii) of

Theorem

2.1,

then we have the same conclusion with the weaker

assumption (2.14)

below in

place of (H2)

and

(H3).

(2.14)

For each R &#x3E; 0, there is a continuous

function

mR :

[0, 00)

-

[0, 00), satisfying

mR

(0)

= 0, such that

for and ;

Analogous

remarks are valid for Corollaries 2.1 and 2.2.

PROOF OF REMARK 2.4. Assume all the

hypotheses

of Theorem

2.1,

except

(H2) - (H3). Assume

further

(2.14) and,

for

definiteness,

that u is

Lipschitz

continuous on

n,

with

Lipschitz

constant C &#x3E; 0. Set R = C + a, and define

Set

for E n x Then G satisfies

(H2)

and

(H3),

with

appropriate

functions mi and m2.

Also,

u and v

satisfy, respectively, (2.1)

and

(2.2),

with

G in

place

of H, in the

viscosity

sense. Theorem 2.1 now guarantees our

assertions. D

(14)

3. - Value functions of exit time

problems

In this section we will show that value functions of exit time

problems,

in deterministic

optimal

control

theory, satisfy

the associated Hamilton - Jacobi

(Bellman) equations.

Let 0

be,

as

usual,

an open subset A a compact

topological

space,

f

a real-valued function x

A, g

a function x A

into RN and h

a real-valued function on an. We assume:

(A 1 )

Functions

f, g

and h are continuous. Moreover, there is a constant L &#x3E; 0 such that

for and

Let ,~ denote the set of

controls,

i.e.

For X E and a

E A,

we consider the initial value

problem

The

unique

solution of

(3.1 )_will

be denoted

by

=

X ~t;

x,

a).

The exit

times T from n and 7 from 11 are

defined, respectively, by

and

Associated with these are cost functionals:

and

With these cost functionals at

hand,

the main purpose of

optimal

control is

stated

as follows: Find controls or sequences of controls which minimize

a)

and

J ( x, a )

over A. Our interest

here, however,

is restricted to

characterizing

value functions:

and on

(15)

~

as

viscosity

solutions of the

boundary

value

problem

in

on

where

The

first order PDE in

(3.3)

is called the Bellman

equation.

Note that

H : 0

x I1~ satisfies

(H 1 ) - (H3),

under

assumption (Al ).

LEMMA

3.1. (Dynamic programming principle).

Assume

(A 1 ).

For any t &#x3E; 0 one has

and

where,

for

any subset B

of A,

1B denotes the characteristic

function of

B.

We refer to P.L. Lions

[16]

for a

proof

of this lemma.

THEOREM 3.1. Assume

(A 1 ).

The

functions

V and V,

defined by (3.2),

are

both

viscosity

solutions

of

the

boundary

value

problem (3.3),

with H

defined by (3.4).

PROOF.

We

only

prove that V is a

viscosity

solution of

(3.3).

The

proof

for V is

similar,

and

we leave

it to the reader. To see that V is a

supersolution

of

(3.3),

let p E

Cl (0),

y

E 0 and V* - ~p

attains its minimum at y. We may

assume

min(V* - p)

= 0

by adding

a constant to p. We may also assume either

n

y E fl, or y E an and

V* ( y) h(y),

because otherwise we have

nothing

to

prove.

We suppose

(16)

and will

get

a contradiction.

By continuity,

there is a

positive

constant e &#x3E; 0 such that

Moreover we assume

and

Select M &#x3E; 0 so that

I g (x, a)

for

(x, a)

x A. Note that, if

then

X(s) = X(s; x, a)

E

B(y, e),

for 0 ~ s

2M.

Set

t =

E ,

and choose

2 a S

&#x3E; 0 so that

e(l - e - t )

&#x3E; 26.

By

Lemma

3.1,

for any

x E

B (y, ±) nO,

there is an a = a ~ such that

if if

Therefore,

if t r, then we have

Also,

if t &#x3E; r, then we have

(17)

In both cases, we thus obtain

a contradiction.

Similarly

we can check that V is a subsolution of

(3.3),

and we omit

giving

the

proof

here. D

4. -

Continuity

of

viscosity

solutions

We continue to

study problem (HJ)’ - (BC)’

for Bellman

equations.

Let

0, A, f, g

and h be as in

§3,

and .H be the function defined

by (3.4).

We

present

a sufficient condition under which

(HJ)’ - (BC)’

has a continuous

viscosity

solution. In order to state our

assumptions,

we need the notation: For a subset

S we write for the closed convex hull of S.

Throughout

this paper, the term "cone" will stand for a cone with vertex at the

origin.

For a subset S

of R N and s &#x3E; 0, we denote

by cn, S

the e - convex conic

neighbourhood

of

S, i.e. the set

We note that

cneS

is a closed convex cone We set

for

The

following

are

pieces

of the sufficient condition mentioned above. Let z Ean and A c aQ .

(A2)

There is an open convex cone K and a constant e &#x3E; 0 for which

G (z)

c K

and

(z

+

K)

n

B(z,,6)

n H = 0.

(A3)

There is an open convex cone K and a constant c &#x3E;

0

such that

G(z) nK=l 0

and

(x+K)

c fl, for xc-

B(z,,E) n?i.

(A4)

There is an open convex cone K and a constant e &#x3E; 0 for which for and

(

for

(A5)

There is an open convex cone K and a constant c &#x3E; 0 such that

G(z)

and

(z+K)

nil =

0.

It is easy to check that if z is an interior

point (relative

to of A, then condition

(A4)

is

equivalent

to

(A4)’

There is an open convex cone K and a

constant

e &#x3E; 0 such that

G(z)

c K

and

(~ + ~) nB(z,e)

c

0,

for x E

B(z,e) n n.

THEOREM 4.1. Assume

(A 1 ).

Let r and E be,

respectively,

an open and

a closed subsets

of

ao such that ao =

Let fo

be an

(18)

open subset

of

r. Assume that

(A2), (A3), (A4),

with A =

ro,

and

(A5) hold, respectively, for

z E

E,

z E

r,

z E

ro

and z E

rBr o. If

u is a

viscosity

solution

of (HJ)’ - (BC)’,

with H

defined by (3.4),

then u E

C(fl),

and

ulll

has a

unique

continuous extension

to a

which is also a

viscosity

solution

of (HJ)’ - (BC)’.

It may

happen

that some of

F, E

and

Fo

are empty in this theorem.

Proposition

1.3 or Theorem 3.1

guarantees

the existence of a

viscosity

solution

of

(HJ)’ - (BC)’.

Thus we see, from this theorem,

that under

the above

hypotheses

(HJ)’ - (BC)’

has a

unique viscosity

solution in

C (0).

The

assumption

of Theorem 4.1 is

motivated by

the

following

observation.

Let T &#x3E; 0, and

set li = (0, T) x fi.

Let E = =

(0,

and

ro = {T}

x Q.

Clearly E

and r are,

respectively,

a closed and an open subsets of 9H and

ro

is an open subset of F. Let

f and g

be as above and

satisfy (Al).

Let A E R, and define

f :

x A - R and

g :

x A -

by

=

and g(t, x, a) = (-1, g(x, a)),

for

(t,

x,

a)

E x A.

The associated Hamiltonian

given by

for t,

s E R and x, p and the

corresponding

Bellman

equation

is:

On the other

hand,

if

(A3)

and

(A5)

hold for z E afi, then

(A2), (A3),

(A4),

with A =

Fo,

and

(A5) hold, respectively,

for z E

E, z

E

F, z

E

fo

and

z E

fBfo.

This observation and Theorem 4.1

imply

that if

(A3)

and

(A5)

hold

for z E ao and h is a

given

continuous function

ona fi,

then the

problem

in

on

has a

unique viscosity

solution in where Note

that this

problem

for u is

equivalent

to the

problem

in

on

for where Also note

u C .r.

that the

following

theorem and Lemmas 4.1 and 4.2

assert

that the solution of this

problem

does not

depend

on the values of h on

Fo

and

equals

to h on ~.

Thus our result covers the

initial-boundary

value

problem

for Hamilton - Jacobi

equations.

(19)

THEOREM 4.2. Assume the

hypotheses of

Theorem 4.1. Let u and v

be, respectively, viscosity

sub- and

supersolutions of (HJ)’ - (BC)’,

with H

defined by (3.4).

Then

on

Moreover, (ull1

and

(vIOBfo,O)*

are,

respectively, viscosity

sub-

and

supersolutions of (HJ)’ - (BC)’.

For the time

being,

we assume Theorem 4.2 is correct and prove Theorem 4.1.

PROOF. Let u be a

viscosity

solution of

(HJ)’ - (BC)’. By

virtue of Theorem

4.2 we have

on

while on

ii, by

definition. Therefore

on

Thus is continuous

on n

and is a

viscosity

solution of

(HJ)’

-

(BC)’, by

Theorem 4.2. The

uniqueness

follows

immediately

from Theorem

2.1. D

In what follows we

always

assume the

hypotheses

of Theorem 4.2 and will prove the theorem.

LEMMA 4.1. One has

for

PROOF. We

begin by observing

that

where ,

Fix z E

By translation,

we may assume z = 0. Since

by assumptions (A2)

and

(A5)

there is an open convex cone K and an e E

(0,1)

such that

and

Choose finite sequences and so that

and Set and for

(20)

Note that .... -- for

By

the

continuity

of g,

we see

that e (x)

E

K,

for

x

in a

neighbourhood

of 0. Set

Cc =

x

E B(0, E) }, E,

=

cnE, CE

and

Ka

=

cneEe.

Then

CE , Ee

and

Ke

are nonempty

closed convex cones.

Replacing

e &#x3E; 0

by

a smaller one, we may assume that

and

for

Define d :

R N -+ 0, oo ) by

= dist

( x, E~ ) ,

for x E

JR N.

It is

well-known that d e and

for ~ 1

where

P ~ x)

denotes the nearest

point

of

E,

from x.

(One

way to see

these,

for

instance,

consists in

observing

that

and then

applying general

results

(e.g.,

H. Br6zis

[3, Prop. 2.11])

for convex

functions to

d2 ).

Note also that d is

positively homogeneous

of

degree

1.

We claim that

for

In view of

(4.4), by continuity,

it is

enough

to prove

(4.6)

for x E

K~ .

To

this

end,

recall that and set then

Assume x E

Kc

and that

~P(x)~ &#x3E; ,8lxl.

Then

As and we find that , The

homogeneity

of d

yields that

. ~

(21)

Thus we have

proved (4.6).

Let x E

E~

and p E

Ca satisfy Ipl

= 1.

Let q

E

B ( o,1 ) .

Since p + eq E

E,

and

P(x) ~ (P(x) - x)

= 0, we have

Taking q

= with x E

E~ ,

in this

inequality,

we find that

for and

Now fix M &#x3E; 0, so that

Let a &#x3E; 0, and select a constant C &#x3E; 0 so that

Let p E

E~,

and set for with

to be fixed later on. Since we have for

and

hence, by (4.4),

By

the same reason, we have

for

Therefore, using (4.6),

we see that if B &#x3E;

2 max 1!2, ~ } ,

then w &#x3E; h on

B (0, e)

n an and w &#x3E; u* on

aB(0, e) nn. Using (4.7)

and

(4.5),

we calculate

that

for Fix

and set

no

= n n

B(0, e)°

and

ho (x)

=

w (x),

for x E

(9f]o.

Then z,v satisfies

in

on

(22)

in the classical sense, while u* is a

viscosity

subsolution of

(HJ)’ - (BC)’,

with

00

and

ho

in

place

of n and

h.

A

simple

argument which leads to a contradiction

now shows that u *

on 00 and,

in

particular, u*(0)

+ a +

B d (- p).

Sending

p - 0, while

keeping

p E

E~,

and then a

10,

we conclude

(4.2).

D LEMMA 4.2. One has

for

Our

proof

is similar to the above one, and we

only give

its outline here.

OUTLINE OF PROOF. We may assume z = 0. Fix e &#x3E; 0. We set and

By assumption (A2),

we can choose an e &#x3E; 0 so that

and

for

Let and

B &#x3E; 0,

and define

by

There is a

positive

constant

Ba , independent

of p, such that if B &#x3E;

Ba ,

then w

h on

B(0,e)n80,

z,v v*

on 8B(0,e)nn

and 0

in in the

classical

sense. Thus we

conclude,

as in the above

proof,

that w v* on

B (0, e) n a,

and hence

h(0) v* (0).

D

In what

follows,

we write

and

We note that u u * and v &#x3E; v * on an and that û = u * and v = v * in fi.

LEMMA 4.3. Assume

u* ( x ~ &#x3E; - C’ for

x

E fi

and some constant C &#x3E; 0.

Then, for

each z E r, there is an open convex cone K and a constant e &#x3E; 0 such that

and

for

(23)

PROOF. Let z E r. We may assume z = 0.

By assumption (A3),

there is

an open convex cone K and a constant e E

(0,1)

such that

G(0)

n

K ~ ~

and

for We select finite sequences

and so that

and Set

and for

Also,

set and define

and

Replacing e

&#x3E; 0

by

a new one, we may assume that for

and

for

In view of

(4.11),

it is

enough

to show that

(4.9)

holds for K =

Feo.

To

this

end,

we will prove

that,

for any r E

(0,e],

for where

and

Note that

(4.9),

with K =

Fz,

is a direct consequence of

(4.13). Also,

notice that

Let r E

(0, e],

and let

b, Mr

and B be as above. Observe that for

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