integral
Introduction Ito integral References
Appendices
Stochastic integral
80-646-08 Stochastic Calculus I
Geneviève Gauthier
HEC Montréal
integral
Introduction Riemann integral Ito integral References Appendices
Introduction
The Ito integral
The theories of stochastic integral and stochastic
di¤erential equations have initially been developed by
Kiyosi Ito around 1940 (one of the …rst important papers
was published in 1942).
integral
Introduction Riemann integral Ito integral References Appendices
Riemann integral I
Let f
: R!
Rbe a real-valued function. Typically, when we speak of the integral of a function f , we refer to the Riemann integral, R
ba
f ( t ) dt, which calculates the area
under the curve t ! f ( t ) between the bounds a and b.
integral
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Riemann integral II
First, we must realize that not all functions are Riemann integrable.
Let’s explain a little further : in order to construct the
Riemann integral of the function f on the interval [ a, b ]
,we divide such an interval into n subintervals of equal
length
b anand, for each of them, we determine the
greatest and the smallest value taken by the function f .
integral
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Riemann integral III
Thus, for every k 2 f 1, ..., n g
,the smallest value taken by the function f on the interval a + ( k 1 )
b an ,a + k
b anis
f
(kn)inf f ( t ) a + ( k 1 ) b a
n t a + k b a n and the greatest is
_
f
(kn)sup f ( t ) a + ( k 1 ) b a
n t a + k b a
n
.integral
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Riemann integral IV
The area under the curve t ! f ( t ) between the bounds a + ( k 1 )
b anand a + k
b anis therefore greater than the area
b anf
(kn)of the rectangle of base
b anand height f
(kn), and smaller than the area
b an_
f
k(n)of the rectangle with the same base but with height
_
f
(kn). As a consequence, if we de…ne
I
n( f )
∑
n k=1b a
n f
(kn)and
_
I
n( f )
∑
n k=1b a n
_
f
(kn)then
I
n( f )
Z b
a
f ( t ) dt
_
I
n( f )
.integral
Introduction Riemann integral Ito integral References Appendices
Riemann integral V
Illustrations of I
n( f ) and
_
I
n( f )
integral
Introduction Riemann integral Ito integral References Appendices
Riemann integral VI
Riemann integrable functions are those for which the limits lim
n!∞I
n( f ) and lim
n!∞_
I
n( f ) exist and are equal.
We then de…ne the Riemann integral of the function f as
Z ba
f ( t ) dt lim
n!∞
I
n( f ) = lim
n!∞ _
I
n( f )
.It is possible to show that the integral R
ba
f ( t ) dt exists
for any function f continuous on the interval [ a, b ]
.Many
other functions are Riemann integrable.
integral
Introduction Riemann integral Ito integral References Appendices
Riemann integral VII
However, there exist functions that are not Riemann integrable.
For example, let’s consider the indicator function
IQ:[ 0, 1 ] ! f 0, 1 g which takes the value of 1 if the argument is rational and 0 otherwise.
Then, for all natural number n, I
n= 0 and
_
I
n= 1, which
implies that the Riemann integral is not de…ned for such a
function.
integral
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Riemann integral VIII
We will examine a very simple case : the Riemann integral for boxcar functions, i.e. the functions f
:[ 0;
∞) !
Rwhich admit the representation f ( t ) = c
I(a,b]( t )
,a < b, c 2
Rwhere
I(a,b]represents the indicator function
I(a,b]
( t ) = 1 if t 2 ( a, b ]
0 if t 2
/( a, b ]
.integral
Introduction Riemann integral Ito integral References Appendices
Riemann integral IX
If f ( t ) = c
I(a,b]( t ) then the Riemann integral of f is
Z t0
f ( s ) ds =
Z t
0
c
I(a,b]( s ) ds
=
8<:
0 if t a
c ( t a ) if a < t b
c ( b a ) if t > b.
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Ito integral I
Let f W
t :t 0 g be a standard Brownian motion built on a …ltered probability space (
Ω,F
,F,P)
,F
= fF
t :t 0 g .
Technical condition . Since we will work with almost sure equalities
1, we require that the set of events which have zero probability to occur are included in the sigma-algebra F
0, i.e. that the set
N = f A 2 F
:P( A ) = 0 g F
0.That way, if X is F
tmeasurable and Y = X
Palmost
surely, then we know that Y is F
tmeasurable.
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Ito integral II
Let f X
t :t 0 g be a predictable stochastic process. It is tempting to de…ne the stochastic integral of X with respect to W , pathwise, by using a generalization of the Stieltjes integral:
8
ω2
Ω,Z
X (
ω) dW (
ω)
.That would be possible if the paths of Brownian motion W had bounded variation, i.e. if they could be expressed as the di¤erence of two non-decreasing functions.
But, since Brownian motion paths do not have bounded variation, it is not possible to use such an approach.
We must de…ne the stochastic integral with respect to the Brownian motion as a whole, i.e. as a stochastic process in itself, and not pathwise.
1X =Y P almost surely if the set of ωfor whichX is di¤erent from Y has a probability of zero, i.e.
Pfω2Ω:X(ω)6=Y(ω)g=0.
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Basic process I
Ito integral
De…nition
We call X a basic stochastic process if X admits the following representation:
X
t(
ω) = C (
ω)
I(a,b]( t )
where a < b 2
Rand C is a random variable, F
ameasurable and square-integrable, i.e. E
PC
2<
∞.
Note that such a process is adapted to the …ltration
F. Indeed,
Xt= 8<
:
0 if 0 t a C ifa<t b 0 ifb<t
which isF0 measurable thereforeFt measurable which isFa measurable thereforeFt measurable which isF0 measurable thereforeFt measurable.
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Ito integral
In fact, X is more than
Fadapted, it is
Fpredictable, but the notion of predictable process is more delicate to de…ne when we work with continuous-time processes.
Note, nevertheless, that adapted processes with continuous path are predictable.
Intuitively, if X
trepresents the number of security shares
held at time t, then X
t(
ω) = C (
ω)
I(a,b]( t ) means that
immediately after prices are announced at time a and
based on the information available at time a (C being
F
ameasurable) we buy C (
ω) security shares which we
hold until time b. At that time, we sell them all.
integral
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Ito integral
Theorem
F
adapted processes, the paths of which are left-continuous, are
Fpredictable processes. In particular,
Fadapted
processes with continuous paths are
Fpredictible. (cf. Revuz
and Yor)
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Ito integral
De…nition
The stochastic integral of X with respect to the Brownian motion is de…ned as
Z t
0
X
sdW
s(
ω)
= C (
ω) ( W
t^b(
ω) W
t^a(
ω))
=
8<:
0 if 0 t a
C (
ω) ( W
t(
ω) W
a(
ω)) if a < t b C (
ω) ( W
b(
ω) W
a(
ω)) if b < t.
Note that, for all t, the integral R
t0
X
sdW
sis a random variable.
Moreover,
nR
t0
X
sdW
s :t 0
ois a stochastic process.
integral
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Basic process V
Ito integral
Paths of a basic stochastic process, and its stochastic integral with respect to the Brownian motion
0 12 3 4 5 6 7 8 9 10
0 0,1 0,2 0,3 0,4 0,5 0,6 0,7 0,8 0,9 1
t
-5 -4 -3 -2 -10123456
0 0,1 0,2 0,3 0,4 0,5 0,6 0,7 0,8 0,9 1
t
Integrale_stochastique.xls
integral
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Ito integral
Note that
Z t0
X
sdW
s=
Z ∞
0
X
sI(0,t]( s ) dW
s.
Exercise. Verify it!
integral
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Ito integral
Interpretation. If, for example, the Brownian motion W represents the variation of the share present value relative to its initial value (W
t= S
tS
0, where S
tis the share present value at time t), then R
t0
X
sdW
sis the present value of the pro…t earned by the investor.
This example is somewhat lame: since the Brownian motion is not lower bounded, the example implies that it is possible for the share price to take negative values. Oops!
Note on the graphs that, over the time period when the
investor holds a constant number of security shares, the
present value of his or her pro…t ‡uctuates. That is only
caused by share price ‡uctuations.
integral
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Ito integral
Theorem
Lemma 1. If X is a basic stochastic process, then
Z t0
X
sdW
s :t 0 is a (
Ω,F
,F,P) martingale.
Proof of Lemma 1. Recall that, if M is a martingale and
τa stopping time, then the stopped stochastic process
M
τ= f M
t^τ :t 0 g is also a martingale.
Since the Brownian motion is a martingale, and
τaand
τbwhere 8
ω2
Ω, τa(
ω) = a and
τb(
ω) = b are stopping
times, then the stochastic processes W
τa= f W
t^a :t 0 g
and W
τb= f W
t^b :t 0 g are both martingales.
integral
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Ito integral
Now, let’s verify condition ( M1 )
.If t a, then
EP Z t
0
X
udW
u=
EP[ j C ( W
t^bW
t^a) j ]
=
EP[ j C ( W
tW
t) j ]
= 0.
integral
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Basic process X
Ito integral
By contrast, if t > a, then
EPZ t
0
X
udW
u=
EP[ j C ( W
t^bW
a) j ] =
EP[ j C j j W
t^bW
aj ]
rEPh
C
2( W
t^bW
a)
2i(see next page)
=
rEPh
C
2EPh( W
t^bW
a)
2jF
aiiC being F
amble.
=
rEPh
C
2EPh( W
t^bW
a)
2iiW
t^bW
abeing independent from F
a.=
q( t ^ b a )
EP[ C
2] <
∞integral
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Basic process XI
Ito integral
Justi…cation for the inequality: for any random variable Y such that
EY
2<
∞,we have
0 Var [ Y ] =
EY
2(
E[ Y ])
2which implies that
E
[ Y ]
qE
[ Y
2]
.integral
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Ito integral
With respect to condition ( M 2 ) ,
Zt
0 XsdWs
= 8<
:
0 if 0 t a
C(Wt Wa) ifa<t b C(Wb Wa) ifb<t.
F0 measurable thereforeFt measurable, Ft measurable,
Fb measurable thereforeFt measurable.
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Ito integral
Condition ( M 3 ) is also veri…ed since 8 s
,t 2
R, 0 s < t,
EPZ t
0
X
udW
ujF
s=
EP[ C ( W
t^bW
t^a) jF
s]
.integral
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Ito integral
But, if s a, then F
sF
a. Since C is F
ameasurable, then
EPZ t
0
X
udW
ujF
s=
EPhEP
[ C ( W
t^bW
t^a) jF
a] jF
si=
EPhC
EP[( W
t^bW
t^a) jF
a] jF
si=
EP 264
C ( W
a^bW
a^a)
| {z }
=Wa Wa=0
jF
s 3 75since W
τaand W
τbare martingales,
= 0
=
Z s
0
X
udW
u.integral
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Ito integral
If s > a, then C is F
smeasurable and, as a consequence,
EPZ t
0
X
udW
ujF
s=
EP[ C ( W
t^bW
t^a) jF
s]
= C
EP[( W
t^bW
t^a) jF
s]
= C ( W
s^bW
s^a)
=
Z s
0
X
udW
u.The process R
X
sdW
sis indeed a martingale.
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Moments I
Basic process
We will need a few results later on, that we shall now start to develop.
Since the Ito integral for basic processes is a martingale, then
EP Z t
0
X
sdW
s=
EP Z 00
X
sdW
s= 0.
The next result will allow us to calculate variances and
covariances.
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Moments II
Basic process
Theorem
Lemma 2. If X and Y are basic processes, then for all t 0,
EPZ t
0
X
sY
sds =
EP Z t0
X
sdW
s Z t0
Y
sdW
s .integral
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Moments III
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Proof of Lemma 2. It will be su¢ cient to show that
EPZ ∞
0
X
sY
sds =
EP Z ∞0
X
sdW
sZ ∞
0
Y
sdW
s(1) since
X = C
I(a,b]and Y = C
eI(
ea,eb] being basic processes,
X
I(0,t]= C
I(a^t,b^t],Y
I(0,t]= C
eI(
ea^t,eb^t]
et XY
I(0,t]= C C
eI(
(a_ea)^t,(
b^eb)
^t]
are also basic processes.
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Thus, if equation (1) is veri…ed, we can use it to establish the third equality in the following calculation:
EP Z t
0
X
sY
sds
=
EP Z ∞0
X
sY
sI(0,t]( s ) ds
=
EP Z ∞0
X
sI(0,t]( s ) Y
sI(0,t]( s ) ds
=
EP Z ∞0
X
sI(0,t]( s ) dW
sZ ∞
0
Y
sI(0,t]( s ) dW
s=
EP Z t0
X
sdW
sZ t
0
Y
sdW
s .integral
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So, let’s establish Equation (1)
EPZ ∞
0
X
sY
sds =
EP Z ∞0
X
sdW
sZ ∞
0
Y
sdW
s .Three cases must be treated separately:
( i ) ( a, b ] \
ea,
eb
i= ?
,( ii ) ( a, b ] =
ea,
eb
i,
( iii ) ( a, b ] 6 =
ea,
eb
iand ( a, b ] \
ea,
eb
i6 = ?
.integral
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Proof of ( i ) . Since ( a, b ] \
ea,
eb
i= ? , we can assume, without loss of generality, that a < b
ea <
eb. Since
X
sY
s= C C
eI(a,b]( s )
I(
ea,eb] ( s ) = 0, then E
PR
∞0
X
sY
sds = 0.
integral
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Now, since C , C
eand ( W
bW
a) are F
eameasurable,
EPZ ∞
0
X
sdW
sZ ∞
0
Y
sdW
s=
EPhC ( W
bW
a) C W
e ebW
ea i=
EPh EPhC ( W
bW
a) C W
e ebW
eajF
eaii
=
EP 264
C C
e( W
bW
a)
EPW
ebW
eajF
ea| {z }
=Wea Wea=0
3 75
= 0 =
EP Z ∞0
X
sY
sds
thus establishing Equation (1) in this particular case.
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Proof of ( ii ) . Let’s now assume that ( a, b ] =
ea,
eb
i. Then,
EP Z ∞
0
X
sY
sds =
EP Z ∞0
C C
eI(a,b]dt
=
EPC C
e Z ∞0 I(a,b]
dt
=
EP hC C
e( b a )
i= ( b a )
EPhC C
ei.
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On the other hand,
EP Z∞
0 XsdWs Z ∞
0 YsdWs
= EPh
C(Wb Wa) Ce(Wb Wa)i
= EPh CCeEPh
(Wb Wa)2jFa
ii sinceC andCe areFa mbles
= EPh CCeEPh
(Wb Wa)2ii
sinceWb Wa is independent ofFa
= EPh
CCe(b a)i sinceWb Wa isN(0,b a)
= (b a)EPh CCei
=EP Z ∞
0 XsYsds
thus establishing Equation (1) for this other particular case.
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Proof of ( iii ) . We have that ( a, b ] 6 =
ea,
eb
iand ( a, b ] \
ea,
eb
i6
= ? .
a = a _
ea and b = b ^
eb. On the one hand,
EPZ ∞
0
X
sY
sds =
EP Z ∞0
C
I(a,b]C
eI(
ea,eb] dt
=
EP Z ∞0
C C
eI(a ,b ]dt
=
EPC C
e Z ∞0 I(a ,b ]
dt
=
EPhC C
e( b a )
i= ( b a )
EPhC C
ei.
integral
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Moments XI
Basic process
In what follows, in case there were intervals of the form (
α,β] where
α β,then we de…ne (
α,β] = ?
.On the other hand, since
Z ∞
0 XsdWs
= C(Wb Wa)
= C(Wb Wb +Wb Wa +Wa Wa)
= C(Wb Wb ) +C(Wb Wa ) +C(Wa Wa)
= Z ∞
0 CI(b ,b]dWs+ Z∞
0 CI(a,b ]dWs+ Z∞
0 CI(a,a]dWs, (2)
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Z ∞
0 YsdWs
= C We be Wea
= C We be Wb +Wb Wa +Wa Wea
= C We be Wb +Ce(Wb Wa ) +Ce(Wa Wea)
= Z ∞
0
CIe (b ,eb]dWs+ Z∞
0
CIe (a,b ]dWs+ Z∞
0
CeI(ea,a ]dWs (3)
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and
(a,a ]\(ea,a ] = ?, (a,a ]\(a ,b ] =?, (a,a ]\ b ,ebi=?, (a ,b ]\(ea,a ] = ?, (a ,b ]\ b ,ebi=?,
(b ,b]\(ea,a ] = ?, (b ,b]\(a ,b ] =?, (b ,b]\ b ,ebi=?,
we can use the results obtained in points ( i ) and ( ii ) in order
to complete the proof: using the expressions from lines (2) and
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(3),
EP Z ∞
0
X
sdW
sZ ∞
0
Y
sdW
s=
EP Z ∞0
C
I(a,b ]dW
sZ ∞
0
C
eI(a ,b ]dW
s= ( b a )
EPhC C
ei=
EP Z ∞0
X
sY
sds
.The proof of Lemma 2 is now complete.
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De…nition
We call X a simple stochastic process if X is a …nite sum of basic processes :
X
t(
ω) =
∑
n i=1C
i(
ω)
I(ai,bi]( t )
.Since such a process is a sum of
Fpredictable processes,
then it is itself predictable with respect to the …ltration
F.
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Simple process II
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De…nition
The stochastic integral of X with respect to the Brownian motion is de…ned as the sum of the stochastic integrals of the basic processes which constitute X
:Z t
0
X
sdW
s=
∑
n i=1Z t
0
C
iI(ai,bi]( s ) dW
s.integral
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Paths of a simple stochastic process and its stochastic integral with respect to the Brownian motion
-4 -2 0 2 4 6 8 10 12
0 0,1 0,2 0,3 0,4 0,5 0,6 0,7 0,8 0,9 1
t
-6 -4 -2 0 2 4 6 8
0 0,1 0,2 0,3 0,4 0,5 0,6 0,7 0,8 0,9 1
t
The simple process is of the form C
1I(
101,106] + C
2I(
12,34]
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First, we must ensure that such a de…nition contains no inconsistencies, i.e. if the simple stochastic process X admits at least two representations in terms of basic stochastic processes, say
∑ni=1C
iI(ai,bi]and
∑mj=1C
ejI(
eaj,ebj] , then the integral is de…ned in a unique manner:
∑
n i=1Z t
0
C
iI(ai,bi]( s ) dW
s=
∑
m j=1Z t
0
e
C
jI(
eaj,ebj] ( s ) dW
s.Exercise. Prove that the de…nition of the stochastic
integral for simple processes does not depend on the
representation chosen.
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Theorem
Lemma 3. If X is a simple stochastic process, then
nR
t0
X
sdW
s :t 0
ois a (
Ω,F
,F,P) martingale.
Proof of Lemma 3. The stochastic integral
Z t0
X
sdW
s=
∑
n i=1Z t
0
C
iI(ai,bi]( s ) dW
sof the simple process X =
∑ni=1C
iI(ai,bi]is the sum of the stochastic integrals of the basic processes it is made up of.
Since a …nite sum of martingales is also a martingale, the
results comes from the fact that stochastic integrals of basic
processes are martingales (Lemma 1).
integral
Introduction Ito integral
Basic process Moments Simple process Predictable process
In summary Generalization
References Appendices
Simple process VII
Ito integral
The next result is rather technical and the proof can be found in the Appendix. It will useful to us later on.
Theorem
Lemma 4. If X is a simple process, then for all t 0,
EPZ t
0
X
s2ds =
EP" Z
t 0
X
sdW
s2# .
integral
Introduction Ito integral
Basic process Moments Simple process Predictable process
In summary Generalization
References Appendices
Simple process VIII
Ito integral
That lemma is, besides, very useful to calculate the variance of a stochastic integral. Indeed,
VarP Z t
0
X
sdW
s=
EP" Z
t 0
X
sdW
s2# 0
BB
@EP Z t
0
X
sdW
s| {z }
=0
1 CC A
2
=
EP Z t0
X
s2ds =
Z t
0 EP
X
s2ds.
It is possible to extend this calculation to other processes X
and toestablish in a similar manner a method to calculate the
covariance between two stochastic integrals (see the Appendix).
integral
Introduction Ito integral
Basic process Moments Simple process Predictable process
In summary Generalization
References Appendices
Predictable processes I
Ito integral
We would like to extend the class of processes for which the stochastic integral with respect to the Brownian motion can be de…ned. We will choose the class of
Fpredictable processes for which there exists a sequence of simple processes approaching them.
Theorem
F
adapted processes, the paths of which are left-continuous are
Fpredictable processes. In particular,
Fadapted processes with continuous paths are
Fpredictible.
Let X be an
Fpredictable process for which there exists a sequence
nX
(n) :n 2
Noof simple processes
converging to X when n increases to in…nity.
integral
Introduction Ito integral
Basic process Moments Simple process Predictable process
In summary Generalization
References Appendices
Predictable processes II
Ito integral
You can’t speak of convergence without speaking of distance. Indeed, how does one measure whether a
sequence of stochastic processes ”approaches” some other process? What is the distance between two stochastic processes? To answer such a question, we must de…ne the space of stochastic processes on which we work as well as the norm we put on that space.
Recall thatk kA:A ![0,∞)is a norm on the spaceAif (i) kXkA=0,X =0;
(ii) 8X 2 Aand8a2R, kaXkA=jaj kXkA; (iii) 8X,Y 2 A, kX+YkA kXkA+kYkA
(triangle inequality).
integral
Introduction Ito integral
Basic process Moments Simple process Predictable process
In summary Generalization
References Appendices
Predictable processes III
Ito integral
Let
A = X X is a
Fpredictable process such that
EPR
∞0
X
t2dt <
∞ .Exercise, optional and rather di¢ cult! The function k k
A :A ! [ 0,
∞) de…ned as
k X k
A=
sEP Z ∞
0
X
t2dt
is a norm on the space A .
integral
Introduction Ito integral
Basic process Moments Simple process Predictable process
In summary Generalization
References Appendices
Predictable processes IV
Ito integral
It is said that the sequence
nX
(n):n 2
NoA converges to X 2 A when n increases to in…nity if and only if
n
lim
!∞X
(n)X
A
= lim
n!∞
s EP
Z ∞
0
X
t(n)X
t 2dt
= 0.
integral
Introduction Ito integral
Basic process Moments Simple process Predictable process
In summary Generalization
References Appendices
Predictable processes V
Ito integral
It is tempting to de…ne the stochastic integral of X with respect to the Brownian motion as the limit of the stochastic integrals of the simple processes, i.e.
Z t
0
X
sdW
s= lim
n!∞
Z t
0