A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
E. B OMBIERI
H. I WANIEC
On the order of ζ(
12+ it)
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 13, n
o3 (1986), p. 449-472
<http://www.numdam.org/item?id=ASNSP_1986_4_13_3_449_0>
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E. BOMBIERI - H. IWANIEC
(*)
1. - Introduction.
Important
for numbertheory,
, theproblem
ofbounding
the Riemann zeta-functionC(8)
in the criticalstrip
0 -Re s 1 stimulated a lot of workon
exponential
sums of thetype
where
f (x)
is a real smooth function on[-M, M,].
Since’(8)
can be wellapproximated by
finite sumsthe sums
(1.1 )
withf (x)
=(2n)-it log
x are ofspecial
interest. Three basictechniques
forbounding
sums(1.1)
are known(cf. [9]):
1) Weyl-Hardy-Littlewood method;
2)
Van derCorput method;
3) Vinogradov
method.In this paper we
develop
a new method which uses a bit of each of thesethree
techniques.
Our main result isTHEOREM..For any t > 1 und s >
0,
we havewith 19 =
9/56,
the constantimplied
in 0depending
on E alone.(*) Supported by
the Institute for AdvancedStudy,
Princeton, N. J. 08540.Pervenuto alla Redazione il 19
Giugno
1985.The
sharpest
result hithertoproved
was due to G. Kolesnik[6];
This was obtained
by
an extension of the Van derCorput
method(expo-
nent
pairs theory
in severalvariables). Using computers,
on the basis of certainconjectures,
S. W. Graham and G. Kolesnik[4] predicted
that thebest constant one can ever obtain
by
that method is e == 0.1618... whilewe have O =
9/56
= 0.16071....The method works for
general
sums(1.1),
so we carry out thearguments
in a
relatively general setting
until the end of Section 5 where wespecify f (x)
= tlog
x in order to use Theorem 4.1 whoseproof
iselementary.
Thisrestriction would not be necessary if we had extended Theorem 4.1 to the relevant form. But a
proof
of such a result wouldrequire
thehighly
advancedtechnique
of thespectral theory
ofautomorphic
functions[2].
It was ourwish to avoid this at least in the most
spectacular
case of the sums(1.2).
Our method seems to work for the divisor
problem
as well. Since this wouldrequire
substantial modifications we do not claim any results.The authors express their thanks to J.D. Vaaler for his
helpful
sugges- tionsconcerning
theproof
of Lemma 2.3.Notation and conventions.
f’, f", f m
denotes the derivatives of order1,
2 and3,
to)
denotes the derivative oforder j,
i means with some
unspecified
constant c, notnecessarily
the same in each
formula,
means
f means with some
positive unspecified
constants Ciy c2 , 1max
ini
d/c
meansdle
where d is a solution of the congruence ad=1 (mod c),
N indicates the end of a
proof
or it means the result is easy.2. - Basic lemmas.
In this section we
present
in ageneral setting
someprinciples applied throughout
the paper.LEMMA 2.1. Let N M and
cv (x)
be a realfunction
such thatthroughout
the interval[N, M].
For anycomplex
number.- an we havePROOF. Follows
by partial integration.
LEMMA 2.2. Let M
N N,, M1
and an be anycomplex
numbers. We then havewith
.g(e)
=min I
, so theLi-norm of K(O) is
PROOF. The sum on the left-hand side is
equal
towhere
X(m)
is the function whosegraph
isThe Fourier transform of
X(m)
satisfiesmin j I
This
completes
theproof.
T,-F,mmA. 2.3. Let f!lJ be a set
of points p
ERK
and letb(p), for p
E£P,
bearbitrary complex
numbers. Letð1,
...,ð K , T, ,
...,T K
bepositive
numbers.Then we have
PROOF. Let
3,
T bepositive
numbers. There exists a functionf(t),
t E
R,
such thatand such that its Fourier transform
f(u)
hascompact support in I ul 13
and
Up
to achange
ofvariables,
this is the well-knownBeurling-Selberg
func-tion
(for
a full account of this and rclated functions we refer to theexposi- tory
paperby
J.D. Vaaler[10]).
Sincethe result follows..
LEMMA 2.4. Let X and W be two sets
of points
l ERK and t)
ERK
respec-tively
and leta(g) f or
l E X andb(p) for 0
E qy bearbitrary complex
numbers.Let
Xl,
...,Xx, Y l’
...,Yx
bepositive
numbers.De f ine
the bilinearforms
and
We have
PROOF. We
begin
with theintegral
formulaPut I and for
put
no,
for t)
with we haveBy (2.3), letting )
and weproceed
as fol-lows
by Cauchy’s inequality.
Here we haveand
for any
by
Lemma 2.3.Finally taking by (2.4)
onecompletes
theproof.
The last result admits an obvious modification.
Suppose
that for somek’s all
x,ls
takeintegral
values. Then the norms and can bereplaced by
andrespectively
and weput Yk
= 1 for suchk’s. Such a modified form of Lemma 2.4 can in fact be deduced from the lemma itself
by
anappeal
to theinequality
In the next five lemmas we prepare ourselves to appy Poisson’s summa-
tion to sums which are rather short. The
arguments
aredelicate, though
standard.
Being
unable toquote
sourcesprecise enough,
weprovide proofs
in full detail. A reader
experienced
with thestationary phase
method may find his ownproofs
easier.LEMMA 2.5. hor
y > 0
we havePROOF. The
integral
is known as theAiry-Hardy integral,
see for exam-ple [5].
One can show that itsasymptotic expansion
isconvergent
fory > 1 giving
the result. For 0 y 1 the assertion is trivial.Let us
give
a directproof
fory > 1.
We haveHence
where
and
By
achange
of variable weget
We have
with
analytic
in soSimilarly,
we deduce thatHence
But
completing
theproof.
COROLLARY. For ,u >
0,
c > 0 and h > 0 we havethe constant
implied
in 0being
absolute.LEMMA 2.6..Let and let
6(h)
be the charac-teristic
function of
the interval[31zcN2, 3,ucN,2].
For any realh =1=
0 we havethe constant
im p lied
in 0being
absolute.PROOF. This follows from Lemmas 4.2 and 4.4 of
[9]
and from theCorollary
to Lemma 2.5..LEMMA 2.7. Let
g(x)
be thefunction
whosegraph
isSuppose
that either We then havewhere the constant
implied
in « is absolute.PROOF.
By partial integration
ourintegral
isequal
tobecause the derivative is monotonic in three subintervals.
LEMMA 2.8. For we have
where the constant
implied
in « is absolute.PROOF. Our
integral splits
into 3parts (use
the formula from theproof
of Lemma
2.7)
say, whereby
Lemma 4.3 of[4],
y andsimilarly
Gathering
thesetogether
three estimates onecompletes
theproof.
LEMMA 2.9
(Poisson’s summation). Let f (x)
be a continuousfunction compactly supported
in(-
oo,co)
and let el d beintegers,
c> I. ’’PP’e then havewhere
f(y)
is the Fouriertransforrrc of f(x).
Denote the Gauss sums
LEMMA 2.10.
I f
C>1 and(a, c)
=1,
thenif I n
0 (mod 2 )
if Z _--_
1 (mod 2 )
and
3. -
Incomplete
Gauss sums.Now we are
ready
to estimate theexponential
sumwhich can be
regarded
as anincomplete (perturbed)
Gauss sum(mod c).
LEMMA 3.1. Let and We
then have
the constant
implied
in 0being
absolute.PROOF. We have
by
Poisson’s formula. The termswith lhl>16o
contributeby
Lemma 2.8. The termswith Ihl
16c and contri-bute
by
Lemma 2.7. For theremaining
terms with we writeand we
appeal
to Lemma 2.6. Theleading
term i.e. the term attached tob(h) gives
rise to the main term while the total error isunless in which case the summation over h is void and the.
final bound remains valid.
REMARKS. A similar idea of
using
Gauss’ sumsG(a, 1; c)
to evaluateincomplete
Gauss’ sumsS(o;
a,0; c)
isapplied
in[3]
in a different context.4. - The distribution of certain fractions.
The
problem
considered in this section seems to be ofindependents interest;
thus the results obtained aregiven
in the status of theorems.Let., I be the number
of
pairs
. such thatand
THEOREM 4.1. We have
the constant
implied
in «depending
on s and on the constantsimplied
in.(4.1).
Our
proof (by
induction withrespect
to certainparameters)
forces usto consider a more
general problem.
For agiven pair
ofrelatively prime positive integers r, s put
Let
A(L1l, d2;
r,s)
be the number ofpairs {a/c, aifci)
fromg(r, s) satisfying
(4.2)
and(4.3).
We aregoing
to prove,by
induction on rs, thefollowing
THEOREM 4.2. For any and
we have
the constant
A(8) depending
on e and on the constantsimplied
in(4.1).
On
taking r
= s = 1 one infers Theorem 4.1.In order to prove Theorem 4.2 we need 3 lemmas. Denote d =
(aI, c)
and
dl
=(a, CI)’
so(d, dl)
= 1 and(dd1, rs)
= 1. Putthus
(mod r)
and(mod s) .
-Let , be the number of those
pairs pertaining to d, dl.
We haveBy (4.4)
it follows that andI
areS.L(2, Z) equivalent,
i.e.for some
?Z(2y Z).
In fact is in the congruencesubgroup
I (mod r),
y =0 (mods)}.
All such z’s aregiven by
with k E
Z,
therefore one can find 7:(unique)
withFirst we deal with the
pairs
which difi’erby
a « trivial » transformation1 -1
i.e. a transformation with Let , denote the number of these «trivial»
pairs.
LEMMA 4.1. W e have
the constant
implied
in «depending
on thoseimplied
in(4.1 ) only.
PROOF. Consider the four cases :
Case 1: oc==0. This
implies
giving
at most0(AC/rs) pairs.
Case 2: 6 = 0. This is similar to case 1
giving
at most©(AC jrs) pairs.
Case
3: f3
= 0. Thissimplies
a6 =1,
a =1, 6
= 1 andThe
pairs
on thediagonal
.a1 == a, el = .c contributeFor
theremaining pairs,
we haveby (4.3)
Hence the number of such
points
is estimatedby . (mod r), ’(m0d s), (mod a),
yThe total number of
pairs
from case 3 isCase
4: y
= 0. This is similar to Case 3giving
a similar bound.Now,
we coundpairs
which differby
a transformation with Let ,,, I
denote the number of these
pairs.
LEMMA 4.2. W e have
the constant
implied
in «depending
on s and on those constantsimplied
in(4.1).
PROOF. A
simple computation
shows thatIn
particular
one deduces from(4.10)
thatand
Next, by (4.2)
and(4.7)
onegets
thus
This
together
with(4.10) yields
Here was discarded the term
0(AC-i)
because if it dominated thenby Now, by
(4.10)
and(4.3)
we inferwhence
where Zl, Z2 are the roots of the relevant
quadratic equation (real
or com-plex) :
Here one factor is thus the other one satisfies
The
points 4fz
are(rsd2 C-2 )-spaced,
so(4.13) implies
Finally, by (4.11), (4.12)
and(4.14)
we conclude thatwhich leads to
(4.9).
Lemmas 4.1 and 4.2 are useful
only
for smallddi.
Forlarge ddl
weintend to
apply
an inductionhypothesis.
With this in mind we establishLEMMA 4.3. We have
PROOF. This follows
by applying Cauchy’s inequality
towhere z ranges over
d 1-spaced points and y
ranges overJ,AC-spaced points.
Now,
we areready
to prove Theorem 4.2by
induction on rs. Ifrs> A C
we have
trivially
so the assertion is obvious. Let us assume that r8 10. If
ddi >2 by
the induction
hypothesis
andby
Lemma 4.3 one haswhere,
y for notationalsimplicity,
, weput
Since
we obtain
by (4.15)
on
taking
D =2)(c)
such thatFor
dd,, D
weapply
Lemmas 4.1 and 4.2getting
firstfor any -, >
0,
and thenby taking £(s) sufficiently large; ,
Combining (4.5), (4.16)
and(4.17)
onecompletes
theproof
of the induc- tionstep
and of Theorem 4.2.REMARKS. Theorem 4.1 is
important
forestimating exponential
sumsthat are related to the Riemann
zeta-function,
cf. Section 5. When moregeneral
sums aretreated,
one is faced with a similarproblem,
the condition(4.3) being replaced by
where
f (x)
andg(x)
are some smoothfunctions; f « F, g
G. In order tostudy
the mostinteresting exponential
sums oftype
it suffices to consider
f (x)
= x’‘ andg(x)
=xl.
But eventhen,
unlessx = 2A =1=
0,
theelementary arguments
which we have used to prove Theo-rem 4.1 fail. In such circumstances one should
try
toapply
the rather advancedtechnique
ofspectral theory
ofautomorphic
functions.Using
the Kuznetsov trace formula for sums of Kloosterman sums
together
withthe
large
sieveinequality
for the Fourier coefficients of Maass cusp forms(cf. [2])
one is able to extend Theorem 4.1 to the case X2+ h2
* 0.5. - Proof of theorem.
We first consider the sums of
type
where
f (x)
is a smooth function such thatfor 9n-/ M
and j>
1 with some F > 1 such thatwith the aim of
showing
thatWe
begin by applying iveyl’s
method to reduce theproblem
to the estima-tion of cubic
exponential
sums. For n > 1 we haveand
by Taylor expansion
Now average the result over n in
(N, 2N]
for some N withSince the error term
0(n4M-4F)
isbounded,
we concludeby
Lemma 2.1that
with some
Nl C 2N independent
of m and n. The innermost sum is con-sidered as a Gauss’ sum
perturbed by
the factore(-If’(m)n3). Traditionally
at this
point
oneapplies Cauchy’s inequality
a number of times until alinear
polynomial
is reached. Thisprocedure
sets the limite == -1
in(5.4).
We
depart
fromWeyl’s
method so thatCauchy’s inequality
is not used.The
key
idea is to evaluate theperturbed
Gauss’ sum rather than to estimate it. A direct use of Poisson’s summation is not recommended because of thegreat
variation ofterms,
y the worst onebeing
thequadratic
term.
Each middle
coefficient ] f’(9n)
has a rationalapproximation
with
1 c c c N
and(a, c)
= 1. Letm(a/c)
be the solution ofThen each
satisfying (5.6)
can be written aswith
1 where Notice that.. by (5.5).
Theterms
pertaining
to the fractionarc
w’ith smalldenominators,
say, when treated
trivially,
, contribute toS.,(M)
Now assume that
Co C c c N.
Denoteand
We find the
following approximations
to the extreme coefficientsand
The second error term is « e-1
provided
which we henceforth assume.
By
Lemma 2.1 we concludewith some
Nl c 2N independent
of the variables of summation.Hence,
for
some A,
C and L withwe obtain
The innermost sum
8(,u;
a, b +2al; c)
is anincomplete
Gauss’ sum(mod c)
whose order ofmagnitude
in case p = 0(no perturbation)
can beexactly
determined in a number of ways.Yet, when ,u
is not toolarge
theFourier
technique
ofcompleting
the sum works well. Thistechnique
hasbeen
applied
to prove Lemma 3.1. Now we use this result. The error terms.from Lemma 3.1 contribute to
S,(M)
The main
term £
from Lemma 4.1 can besimplified
a bit in twosteps.
h
First remove the factor
2(,ch)-1/4 by using
Lemma 2.1(partial summation)
and then
replace
the constraint3,ucN2
h3,ucN’ by
a weaker one h - Hwith
by using
Lemma 2.2. Theresulting inequality
iswhere
¿*
is restricted to h with a fixedparity,
and 77
is a real number which does notdepend
on the variables of summa-tion.
By
Holder’sinequality
weget
Here the sum can be
regarded
as a bilinear form oftype
considered in Lemma
2.4,
wherea(X)
is themultiplicity
ofrepresentations of z
in the formwith
relevant A,
andb (t))
is themultiplicity
ofrepresentations of t)
in theform
Therefore
and
with
By
Lemma 2.4(see
the remarks after theproof)
weget
where,
in ourparticular context, M(b ; 3i)
is the number ofpairs {(a,
c,l)
(al,
Cl,i))
such thatsimultaneously
and is the number of such that
simultaneously
and
The second
system
isinvestigated,
among otherthings,
in aseparate
paper
[1]
with the resultIt remains to estimate -,
By (5.10)
we deduce that(notice
that.LH’ N N,
so - and that’Therefore
where
%(A, C, H)
stands for the number ofpairs {(a, c), (a,l, c1)} satisfying (5.9), (5.16)
and(5.11).
Since the numbersdepend
on a, c in a verycomplex
way, we are forced to discard(5.16).
This is a
place
at which our method is wasteful.So far our
arguments
have beenapplicable
toquite general
sums8,(M).
Now
specifying
to.so I’
= t,
we find that-and
thus, c-lv(a, c)
is a function of ac. The condition(5.11)
isequivalent
towith
By
Theorem 4.1 we inferwith Here we have
and
The other three terms are
smaller,
therefore we concludeFinally
we argue as follows.By (5.8), (5.15), (5.17)
and(5.20)
onegets
This
together
with(5.7) yields
on
taking
This
completes
theproof
of(5.4)
for M in(5.3)
andf (x)
definedby (5.18).
For
1 M F3/7
weappeal
to theexponent pair theory,
y cf.[7]
and[8], giving
The
pair (x, Â)
_(1/9, 13/18) yields
which is
stronger
than(5.4). Finally (5.4)
and(5.21) imply our theorem7 cf . [9] .
REFERENCES
[1]
E. BOMBIERI - H. IWANIEC, Some mean-value theorems jorexponential
sums,Ann. Scuola Norm.
Sup.
Pisa Cl. Sci., 13, no. 3 (1986), pp. 473-486.[2]
J.-M. DESHOUILLERS - H. IWANIEC, Kloosterman sums and Fouriercoefficients
of
cuspforms,
Invent. Math., 70(1982),
pp. 219-288.[3] J. B. FRIEDLANDER - H. IWANIEC, On the distribution
of
the sequencen203B8(mod
1),to appear in the Canadian J. Math.
[4] S. W. GRAHAM - G. KOLESNIK, One and two dimensional
exponential
sums,preprint
1984 (to bepublished
in theProceedings
from the Conference onNumber
Theory
Held at the OSU inJuly
1984).[5] G. H. HARDY, On certain
definite integrals
consideredby Airy
andby
Stokes, Quart. J. Math., 44 (1910), pp. 226-240.[6] G. KOLESNIK, On the method
of
exponentpairs, Acta Arith., 55 (1985), pp.115-143.
[7] E. PHILLIPS, The
zeta-function of
Riemann:further developments of
van derCorput’s
method, Quart. J. Math., 4(1933),
pp. 209-225.[8] R. A. RANKIN, Van der
Corput’s
method and thetheory of
exponentpairs,
Quart.J. Math., 6
(1955),
pp. 147-153.[9] E. C. TITCHMARSH, The
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Institute for Advanced