A NNALES DE LA FACULTÉ DES SCIENCES DE T OULOUSE
L AURA B URLANDO
Continuity of spectrum and spectral radius in algebras of operators
Annales de la faculté des sciences de Toulouse 5
esérie, tome 9, n
o1 (1988), p. 5-54
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- 5 -
Continuity of spectrum and spectral radius
in algebras of operators
LAURA
BURLANDO(1)
Annales Faculte des Sciences de Toulouse Vol. IX, nOl, 1988
RÉSUMÉ.2014 Dans cet article nous étudions la continuité spectrale dans Falgebre des operateurs lineaires et continus sur un espace de Banach. Plu- sieurs nouvelles conditions suffisantes (la plupart d’elles sont aussi neces- saires au moins dans le cas particulier d’un espace de Hilbert
separable)
pour la continuite des fonctions spectre et rayon spectrale sont etudiees et comparees a celles deja connues. Des exemples sont donnes aussi pour etu- dier les liaisons parmi toutes ces conditions. Deux sous-ensembles
(qui
aumoins dans le cas d’un espace de Hilbert separable ne sont pas propres) de
l’ensemble des points de continuite ds fonctions spectre et rayon spectrale
sont definis. Nous etudions les proprietes algebriques et topologiques de ces
ensembles.
ABSTRACT. - This paper deals with spectral continuity in the algebra of
linear and continuous operators on a Banach space. Several new sufficient conditions
(most
of which are also necessary, at least in the particular caseof a separable Hilbert
space)
for the continuity of the spectrum and spectral radius functions are studied and compared with the already known ones.Examples are given to specify the connections between these conditions.
Two subsets (which, at least in the case of a separable Hilbert space, are not proper) of the sets of the continuity points of the spectrum and spectral
radius functions are introduced, by means of two of the conditions above,
and algebraic and topological properties of theirs are studied.
Introduction
The
continuity points
of the spectrum andspectral
radius functions in thealgebra
of linear and continuous operators on aseparable
Hilbertspace have been
recently
characterizedby
CONWAY and MORREL([CM]).
~1~ Istituto di Matematica dell’ Universita di Genova Via L. B. Alberti 4 16132 Genova
Italy
A different characterization of the
continuity points
ofspectrum
has beengiven
afterwardsby
the authors of[AFHV].
Both the conditions
given by [CM]
and[AFHV]
for thecontinuity
ofspectrum
withrespect
to the Hausdorff metric at theoperator
Arequire
that the union of the union of all trivial
components
of a convenient subset of thespectrum
and the set of the semi-Fredholmpoints
of A withnonzero index is dense in the
spectrum
of A. The two characterizations differ in the subset of thespectrum
whose trivialcomponents
are considered(see
[CM],
3.1 and[AFHV],
Th. 14.15).
Both the conditions
given by [CM]
for thecontinuity
of thespectral
radius function at the
operator
Arequire
that the maximum of the su-premum of the modulus function on and ~ E
w } : w
is acomponent
ofT ~ (where
T is a convenient subset of thespectrum
)
coincides with thespectral
radius of A. The two characterizations differ in the subset of thespectrum
whosecomponents
are considered(see [CM],
2.5 and
2.6).
These four
conditions,
which characterize thecontinuity points
of spec- trum andspectral
radius in the case of aseparable
Hilbert space, are at least sufficient for thecontinuity
of the twospectral
functions for any Ba- nach space(see [CM], §4, [AFHV],
page277,
andCorollary
1. 15 and Corol-lary
2.13 of thispaper).
The authors of[AFHV] suspect
thatthey
are alsonecessary for any Banach space
(see [AFHV],
page313).
In this paper I
give
new conditions which ensure thecontinuity
of thespectrum
andspectral
radius functions in thealgebra
of all linear and continuousoperators
on a Banach space and Iinvestigate systematically
their
reciprocal
connnections and theirrelationships
with the conditions of[CM]
and[AFHV].
In Section 1 I introduce a subset of the
spectrum
of an operator A whose union with the set of all normaleigenvalues
ofA is contained in the subset defined
by [CM]
and coincides with it in theparticular
case of a Hilbert space(see
Definition1.2).
Istudy
theconnections between the unions of all trivial components of seven different
subsets of
(among
which U~p(A)
and thetwo sets introduced in
[CM]
and[AFHV])
and prove that there are somerelationships
of inclusion and three chains can be constructed(see
Theorem1.6).
Inparticular,
ifI‘1 (A)
denotes the union of all trivialcomponents
ofro(A)
denotes the union of all trivialcomponents
of the set introduced in[AFHV], I‘2 (A)
denotes the union of all trivialcomponents
of the set introduced in
[CM]
and denotes the union of all trivialcomponents
of U~p (A),
c Cr2 (A)
c andall the other three unions of trivial
components
containFi(A)
and are .contained in
r4(A). By
means of severalexamples,
I show that none of theinclusions enunciated in Theorem 1.6 can be inverted.
Moreover,
I provethat,
for any of the seven subsets above ofr(~t),
the union of the union of its trivialcomponents
and coincides with or withr4(A)
Uand,
ifr4(A)
U =a(A),
alsor1(A)
Uand
F4(A)
U coincide(see
Theorem1.13).
Hence.I have obtained five new sufficient conditions for thecontinuity
ofspectrum
at thepoint A,
which are
equivalent
to the twoalready
known ones and therefore are also necessary, at least in the case of aseparable
Hilbert space(see Corollary 1.15).
In Section 2 I
study
the connections between the suprema of the sets of the infima of the modulus function on thecomponents
of the seven subsets above ofo~(A).
Severalinequalities
can be established and three chainscan be constructed
(see
Theorem2.2).
Inparticular,
if~5 (A)
andS2 (A)
denote the suprema introduced in
[CM] (where b5 (A)
coincides with the supremum defined in[CM])
and~2 (A)
coincides with the supremumS~ (A)
defined in[CM])
and if weput ~4 (A) -
Ew } :
cv is a
component
of US5(A) b2(A) S4(A). By
meansof several
examples,
I prove that none of theinequalities
enunciated in Theorem 2.2 can be inverted.Moreover,
I prove that the maxima of and any of the seven suprema above can assume at most twovalues,
themaximum of which is
S2(A)
V =S4(A)
V =S5(A)
V(see
Theorem
2.12).
In this way, I have obtained five new sufficient conditions for thecontinuity
of thespectral
radius function at thepoint A ,
, two ofwhich are
equivalent
to the twoalready
known ones and therefore are alsonecessary, at least in the case of a
separable
Hilbert space(see Corollary 2.13).
Anexample
proves that theremaining
three conditions are not necessary for thecontinuity
ofspectral radius,
even in aseparable
Hilbertspace
(see Example 2.14).
In Section 3 I introduce a subset
Eo(X) (defined by
theequivalent
conditions of
Corollary 1.15)
of thecontinuity points
ofspectrum
anda subset
Ro (X ~ (defined by
theequivalent
conditionsiv), v), vi)
andvii)
ofCorollary 2.13)
of thecontinuity points
ofspectral
radius in thealgebra
of all linear and continuousoperators
on a Banach spaceX,
withc
Ro (X).
Both subsets are not proper, at least in the case ofa Hilbert
separable
space. Istudy algebraic
andtopological properties
ofand and compare them with another
sets-,
a subsetreX)
of
Eo(X)
and a subset7r(X)
of that I havealready
defined in aprevious
paper([B]) by
means oftopological
conditions on thespectrum.
Acknowledgement:
myspecial
thanks to ProfessorCecconi,
who wasso kind to discuss with me about the results of this paper.
0.
We shall denote the norm
by
thesymbol [[ [[ in
any normed space.If X is a
complex
nonzero Banach space, for any x E X and for any~ > 0 let
~)
denote the set of allpoints
of X whose distance fromx is smaller than c. We shall denote
by Lc(X )
thealgehra
of all linear and continuousoperators
onX, by
the ideal ofcompact operators
ofand
by Ix
theidentity
ofBy
a continuousprojection
on X we shall mean anoperator
P ELc(X)
such that
P~
= P.Obviously, Ix -P
is aprojetion too,
Im P =ker(Ix -P) (we
shallalways
use thesymbol
Im to denote the range of afunction),
sothat Im P is
closed,
and X = Im ker P(where
thesymbol
® meansalgebraic
directsum).
For any A ELc(X ),
we shall denote thespectrum
ofA
by a~(A),
thespectral
radius of Aby r(A)
and(where
thesymbol
C denotes the
complex plane) by p(A).
We recall that: iscompact
andnonempty,
the resolvent function:A e
p(A)
--~ =(aIX
- Eis
analytic, r(A)
=limn~~~An~1/n,
theperipheral spectrum
of A is theset of all
points
of whose modulus isequal
tor(A)
and aspectral
setof A is a subset of its
spectrum
that is both open and closed in the relativetopology
ofa(A).
Let denote the semi-Fredholm domain of
A,
that is the set of allpoints
A E C such that A is a semi-Fredholm operator(see [Ka],
page230).
For any n E Z U~-oo, -~-oo},
let denote the set of allpoints
A E
ps_F(A)
such that ind(aIX
-A)
= n(where,
for any semi-Fredholm operator T E ind T denotes the semi-Fredholm index of~’,
see~Ka~, IV, (5.1 )).
From thestability
of semi- Fredholm index(see [Ka], IV, 5.17)
it follows that is open for any n E Z
U ~ - oo, -~-oo ~ . Consequently,
if we
put
also and
p8_F(A)
are open subsets of C. It is immediate to remark that .Cand, consequently,
C(so that,
asis
closed,
alsoC ~(A)).
We shall denote
by r~(~4)
the set of all normaleigenvalues
ofA,
that isthe set of all isolated
points
of for which thecorresponding spectral projection (see [TL],
page321)
has finite-dimentional range. From[Ka], IV,
5.28 it follows that C
We recall
that,
for any A E there exists aneighborhood
U ofa,
contained in such that dim
ker(p,Ix -A)
and dimX/Im (p,Ix -A)
are constant
for p,
E(see [Ka], IV, 5.31). Therefore,
sinceis open for any n E Z U
~-oo, -~oo}, ~~°(A)
cWe also recall that any isolated
point
of whichbelongs
tobelongs
to~P(A),
too(see ~Ka~, IV,
5.28 and5.10).
Hence =~~(A)
U(~(A)
nWe shall denote with Since is open and
ps-F(A)
Dp(A),
it follows that is closed and C Since n8u(A)
Cby ~Ka~, IV, 5.31,
it follows that9r(A)
C U~p(A).
Hence U~P(A)
isnonempty.
If
Q :
:Lc(X)
--> is the canonical map, we shall denoteby
the essentialspectruth
of A(that
is thespectrum
ofQ( A)
inthe Calkin
algebra Lc(X)/ Lcc(X)), by
the left essentialspectrum
of A(that
is the leftspectrum
ofQ(A)
inLc(X)/Lcc(X)
andby are(A)
the
right
essentialspectrum
of A(that
is theright spectrum
ofQ(A)
inLc(X)/Lcc(X)). Obviously,
and arecompact
subsets of C and = U We recall that coincides with the Fredholm domainof A,
that isUnEZ p$_F(A) (see [CPY], (3.2.8)).
Henceor.(~) = P8 F(A)~
Sincep:;(A)
and areopen subsets of
C,
it follows that C From[CPY], (4.3.4)
it follows that U C
ps-F(A).
Hence Cn The
opposite
inclusion is notalways
satisfied in ageneric
Banach space
(see
forinstance,
in this paper,Example 1.1),
whereas from[CPY], (4.3.4)
it followsimmediatly
that = n if Xis a Hilbert space.
Since
it follows that
and
Let
Kc
denote the set of allcompact nonempty
subsets of thecomplex plane,
endowed with the Hausdorff metric. Weput
03A3(X)
={T
eLc(X) :
thespectrum
function 03C3 : ~Kc
is continuous atT ~ ,
R(X)
={T
E thespectral
radius function rLc(X)
-[0, -f-oo)
is continuous at
T},
7r(X)
={T
E anyneighborhood
of theperipheral spectrum
of T contains anonempty spectral
set ofT~ (see [B], 1.1)
andreX)
={T
ELc(X) :
: any open set in the relativetopology
ofcontains a
nonempty spectral
set ofT~
(see [B], 2.1). Obviously,
cR(X)
andreX)
CIf,
for anytopological
space Wand for any w EW,
,Cw(W)
denotesthe component of W which contains w, for any A E
Lc(X)
weput
=
~a
E : =~~1~} (see [B], 2.3)
and =~a
EO’(A)
: C~~
E C :r(A)~} (see 1.3).
Werecall that
reX)
=~A
E : =(see [B], 2.4)
andx(X)
={A
ELc(X)
: E =r(A)} (see [B], 1.5).
From[M],
2.1 and 2.2 it follows thatx(X)
CR(X)
andreX)
C~(X ).
Finally
we recallthat,
if X iscomplex
infinite-dimentional Hilbert space, for anycompact nonempty
subset K of thecomplex plane
and for any orthonormal basis E of X there exists A Ediagonal
with respect to E(and
thereforenormal),
such that = K(see [Ha], Prob.46,
in whichonly
the case of aseparable
Hilbert space istreated;
thegeneral
case followsimmediately).
1.
Let X be a
complex
nonzero Banach space and let A E From[CPY], (4.3.4)
it follows thatand
Pietsch,
in theexample
at pages 366 and 367 of[P],
has shown thatin a non-reflexive Banach space there may exist a semi-Fredholm
operator
with finite-dimensional null space(resp.,
finite-codimensionalrange)
whoserange
(resp.,
nullspace)
is not the range of a continuousprojection. Hence, by [CPY], (4.3.4),
none of the two inclusions above can be inverted. Thefollowing example, inspired by
the one ofPietsch,
shows that even ina reflexive space none of the two inclusions above can be inverted and n is not
always
contained inEXAMPLE 1.1 . - Let us consider the
complex
Banach space.~p (where
p E
(0, 2)
U(2, +oo)).
Sincep ~ 2,
there exists a closedsubspace
X of.~p
such that X is not the range of any continuous
projection
on.~p (see [K6], 31.3, (6)).
.~p
x.~p
is a Banach space withrespect
to the canonical norm definedby
= + for any
(x, y)
E.~p
x andobviously
X x.~p
is aclosed
subspace
of.~p
x~p .
If denotes the canonical basis of
.~p,
that isen =
forany n
E N ,
it is not difficult toverify
that theoperator
T :.~p
---~.~p
x.~p (where,
for any x = Elp,
Tx =(03A3n~N x2nen, 03A3n~Nx2n+1en))
iSan
isomorphism
of Banach spaces. If we defineA(x, y)
=(o, T-1 (x, y))
forany
(x, y)
E X x.~p,
it follows that theoperator
A : X x.~p
---~ X islinear and
continuous,
ker A= ~ 0 ~
andConsequently
A is a semi-Fredholmoperator and,
moreover,(where
A* is theadjoint
ofA,
see[Ka], IV, 5.13).
Nevertheless,
we prove that 0 E(so that,
as, since p E(1, -E-oo),
X x
.~p
isreflexive,
0 Etoo,
and none of the two inclusions abovecan be
inverted).
We prove that Im A is not the range of any continuous
projection
onX x
~p. Suppose
that there exists aprojection
P ELc(X
x.~p)
such thatFor
any k
=1, 2,
we define the linear and continuousoperators
in the
following
way:and
If we
put Q
=P1TP2PJ2T-1J1,
it follows thatQ
E andMoreover,
for any x EX,
as E ImP it follows thatConsequently,
sinceQz
E X for any z E.~p
andQx
= x for any x EX, Q
is a continuous
projection
on.~p
and ImQ
= X . This is acontradiction,
asX is not the range of any continuous
projection
on Therefore Im A isnot the range of any continuous
projection
on X x.~p.
From
[CPY], (4.3.4)
it follows that 0 EObviously,
since Im A has notcomplementary
closedsubspace,
X x
lp /
ImA isinfinite-dimensional,
sothat, by
the inclusionsabove,
0 E
are(A),
too.We have thus
proved
thatIf X is a
complex
nonzero Banach space and A ELc(X),
letro(A)
denotethe set of
all points
A E such that~~1~
is a component ofand let denote the set of all
points
A E such that A is a compo- nent of n U We recall two recent characterizations offor a
separable
Hilbert space, that will be useful afterwards.THEOREM
(1) ([CM], 3.1).
Let X be acomplex
nonzeroseparable
Hil-bert space and let A E
Lc(X);
then A E~(X )
= UI’2(A).
.
The condition = U
I‘2 (A)
is at least sufficient for member-ship
in for anycomplex
nonzero Banach space X . Infact,
even ifps-F(A)
does notalways
coincide withole(A)
fl theequality
is anyway satisfied in any Banach space, so that
Conway
and Morrel’sproof
of thesufficiency
of the condition above formembership
inE(X)
canbe
repeated
without alterations in thegeneral
case of acomplex
nonzeroBanach space.
THEOREM
(2) ([AFHV],
Th.14.15).-Let
X be acomplex
nonzeroseparable
Hilbert space and let A E then A Eiff
=Fs F(A)
Uro(A).
a.
We take the
opportunity
ofremarking
thatin [AFHV],
Th. 14.15 theproof
thesufficiency
of the condition above formembership
inE(X),
in order to avoid
pathological examples
like S 9) 0 on12
?12,
shouldbe stated more
exactly by observing that,
ifD(~; , E/2)
does not containany
component
of7(A),
it contains anyway acomponent
of sothat
Corollary
1.6 can still beapplied (see [He], Cor.16).
Thispart
ofthe
proof
of Theorem 14.15 can beextended,
without furtheralterations,
to the
general
case of acomplex
nonzero Banach space.Therefore,
ifX is a
complex
nonzero Banach space and A ELc(X),
the conditiono-(A)
= U is at least sufficientmembership
inDEFINITION 1.2. Let X be a
complex
nonzero Banach space and letA E
Lc(X).
Wedefine
We remark that
X(A)
n- ~
and that C Cfl
a~re(A) (SO that,
if X is a Hilbert space, = =n
THEOREM 1.3. Let X be a
complex
nonzero Banach space and letA E
Lc(X);
then =for
any ~ E and= n
for
any a Ex(A).
Proof
. Forany 03BB
E~(A),
since CCa
it followsthat
In
addition,
since A EX(A)
andC~. (vle (A)
flvre (A))
=Ca (vle (A)
nvre (A))
for any E n it follows that
Ca(vle(A)
flvre(A))
CX(A)
Cv,,,t (A),
so thatCa (vle (A)
flvre(A))
C ThereforeFor any A E since C C n it follows
that
Moreover,
since A E nC’a(ale(A)
n(~,
so that=
~.
It follows that =~.
HenceC
and, consequently,
C .Therefore = for any ~ E
DEFINITION 1.4. - Let X be a
complex
nonzero Banach space and let A E Wedefine
and
We remark that c
u(A)
forany j
=0, ... , 5 and,
if X is aHilbert space,
r2 (A) - r3 (A)
=r4 (A)
forany A
E(because
= n
are(A)
=a"z (A)
in a Hilbertspace).
LEMMA 1.5. - Let X be a
locally compact Hausdorff
space and let C bea nonempty connected
compact
subsetof
X. . Then C is acomponent of
Xthere exists an open subset U
of
X such that C is a componentof
U.Proof.
.Obviously,
if C is a component of ~’’ and we put U =X
, itfollows that U is an open subset of X and C is a
component
of U.Conversely,
suppose that there exist an open subset U of X such that C is acomponent
of U. Since X is alocally compact
Hausdorff space andC is
compact, compact neighborhoods
of C are aneighborhood
base of C.o
Therefore there exists a
compact
subset V of X such that CSince C is a
component
ofU,
C is also acomponent
of V . Since V is acompact
Hausdorff space and C CV,
from[Hy], 2.4,
Th. 2.15 it followsthat there exists an open and closed set W in the relative
topology
of Vsuch that C C W C V. .
Since V is
compact
and X is a Hausdorff space, V isclosed,
so that Wis a closed subset of X.
Moreover,
since W is open in the relativetopology
of V and is contained in
V,
W is open also in the relativetopology
ofV,
sothat,
asobviously V
is open inX, W
is an open subset of X. .Hence there exists an open and closed subset W of X such that C C W C U. If D denotes the
component
of X that containsC,
it follows that D C W C U.Consequently,
D is acomponent
ofU,
sothat,
as also C is acomponent
ofU,
D = C. Therefore C is acomponent
of X. . 0THEOREM 1.6.2014 Let X be a
complex
nonzero Banach space and let A ELc(X).
. Thenand
moreover,
Proof.-Since
is open in the relativetopology
offrom Lemma 1.5 it follows that C We prove that
~(A)
C U~p(A).
Since C
~(A),
it follows thatHence
~(A)
n =~p(A),
and therefore C U~p(A)
CU
~p (A). Consequently,
for any a Eso that A E
Hence
~(A)
Crs(A).
We prove that
Let A E
rs(A);
then U ={,1},
so that a E8Qe(A)
UC U Since
Q9_F(A)
C flQre(A)
Coe(l4)
andCa(Qe(A)
Uo~°(A))
={,~},
it follows thatand therefore a ~
I‘2 (A~
nr3 (A~.
We prove that
For any A e
~p (A),
A is isolated ino(A),
sothat,
as U~~° (A)
Ca(A),
A is isolated in U~p (A),
too.Consequently,
and therefore
For any a E a E and =
(A).
Consequently, by
Theorem1.3, ~a},
so that alsoTherefore
For any A E A E n and
so
that, obviously, ~a~.
Since a~’
it followsthat ~ E
x(A)
C C and hence_ ~ a},
sothat also U
~~°(A))
=~a}.
Therefore
We have thus
proved
thatConversely,
forany A
EF4(A),
if A E U~p(A)
it follows thatConsequently,
and therefore
If, instead,
A Ex(A),
from Theorem 1.3 it follows thatso that A E
F2(A).
Therefore
We have thus
proved
thatand
Now we prove that
r1(A)
Cro(A).
We define
Since C
s(A)
Co(A),
it follows that =Therefore is open in the relative
topology of s(A).
We remark that
(because
C~(A)Bpe_F(A));
therefores(A)
is the inter-section between an open and a closed subset of the
complex plane and, consequently,
it is a Hausdorfflocally compact
space. Hence from Lemma 1.5 it follows that Cro(A).
o
We have
proved
that C Since C_________ o 0
and C
a (A) (so
that _~)
for anyn E
Z~{0~,
it follows thatConsequently,
so that
ro(A)
n~(A)
c Hence = n~~A~.
Finally
we prove thatObviously
For
any n E Z,
o
consequently, ~p~_F(A)
is open in the relativetopology
ofo
so that any trivial component of
~ p9 F(A)
is also acomponent
of(and
therefore it is acomponent
of Utoo) by
Lemma1.5.
Hence
We have thus
proved
thatWe shall prove that none of the inclusions enunciated in Theorem 1.6 can
be inverted. _
First of
all,
we provethat,
ingeneral,
there is not anyrelationship
ofinclusion between and
LEMMA 1.7. - Let X and Y be Banach spaces, let ,~ E and let T E
Lc(Y).
Then theoperator
S ~ T ELc(X
®Y)
is semi-Fredholmiff
,Sand T are semi-Fredholm and
~
indS,
ind T} ~ ~-oo, -~-oo};
moreover,if
S ® T is a semi-Fredholm
operator,
ind(S
®T)
= ind S + ind T.Proof.2014
We define A = S’ ® T. From[TL], V,
5.2 it follows that ker A =ker S ~
ker T and Im A = Im S (B Im T(so
that the vector space(X ® Y) 11m
A isalgebrically isomorphic
to the vector spaceX/Im
S ~Y/Im T).
It is not difficult toverify
that Im A is closed if andonly
if bothIm ,S‘ and Im T are closed. Therfore A is a semi-Fredholm
operator
if andonly
if Im S and Im T are closed and either ker S and ker T are finite- dimensional orX/Im
,S’ andY/Im
T are finite-dimensional. Hence A is a semi-Fredholmoperator
if andonly
if S and T are semi-Fredholmoperators
and{ind S, ind T~ ~ {-oo, -f-oo}.
In
addition,
from theequalities
enunciated above it followsthat,
if A isa semi-Fredholm
operator,
ind A = ind S’ + ind T. DThe
following example
shows thatro(A)
is notalways
contained in~(A).
Example
1.8 . - We denoteby
S the unilateral left shiftoperator
on.~Z
and
by
0 the nulloperator
onl2.
Let us consider theoperator
A =S ~
0 ELc (£2
C.~2).
From[TL], V,
5.4 it follows that = =.BC(o, I}
(see [Ha],
Sol.67). Therefore,
sinceobviously Bc(o,1 )
isconnected,
=0.
We prove that
0.
We recall that =
p9_F(S‘)
and ind -S)
= 1 for anyA E
(see [Ka], IV, 5.24).
Since - A =(~I~e2
-S)
®~Ie2
for
any A
E C and 0 is not a semi-Fredholmoperator,
from Lemma 1.7 ~ ~ it follows that =C~ ({0}
UôBc(O, 1))
and indA)
=ind
S)
= 1 for any A EBC(0,1)B{0}.
Therefore = and
p°~_F(A)
= -C~B~(0,1),
so thatConsequently, ro(A) = ~0~ ~ 0. D
Since
ro(A)
is notalways
contained intP(A), ri(A)
C andC it follows that is not
always
contained inFi(A)
and is not
always
contained inThe
following example
proves that is notalways
contained in EXAMPLE 1.9. - We denoteby
S unilateral left shift on~2.
Let us considerthe
complex
Hilbert spacethe norm in X is defined in the
following
way :for any Since =
1,
the sequenceof linear and continuous
operators
on£2
is bounded in norm, so thatfor any and the linear
operator
(where {~(1/2n)~.~z
-~-~L~2n+Z),S’n+1~
for any(xn)n~N
EX)
is continuous.For any n
EN,
we define two closedsubspaces
ofX,
(which obviously
isisomorphic
to.~2 )
andand two linear and continuous
operators,
(where Tn(03B4nkx)k~N
=(6nk ((1/2")Ir, + (l/2n+2)sn+l)
for any x E22 )
and(where Anz
= for any z EXn).
Obviously,
for any n EN, X
=( B&=o ® Yk) ~ Xn / and A = ( k=0 ® Tk) ~ An /
.
Moreover,
since ~(S’)
= BC(o,1 )
and p8_F(,S’)
= J?c(0,1) (see [Ka], IV,
5.24),
it follows thatand,as
for
any 03B4
> 0 and forany 03B8
E[0,203C0), 03C1n+1s-F(Sn+1)
=Bc(o,1) (see [CPY], (3.2.7)) (so
that ="t" (1/2’z+2),S‘n’+~) -
It is not difficult to
verify
that the ballsBc ( 1 /2n,1 /2n+2 ),
n EN,
arepairwise disjoint.
For any n E
N,
since 0 forany k
=0,...,
n and for any EXn
it follows thatfor any E
Xn.
Therfore
5/2n+3 and, consequently,
CBC(o, 5/2n+3).
It is not difficult to
verify
thatBC (o, 5/2’~+3 )
flBC ( 1 /2’~,1 /2’~+2 ) _ ~;
therefore
BC ( 1 /2n,1 /2’~+~ )
Cp(An )
n . From Lemma 1.7 it follows thatBc(l/2", 1/2"-~)
Cp$±~(A).
By [TL], V,5.4,
for any n
EN;
thereforefor any n E N. Since
5/2n+3
-~0,
it follows thatn-+oo
Consequently, = ~
for anynegative integer
n,for any
positive integer n
andTherefore
so that = and
Hence
fo(A)
=0, whereas, obviously,
=~ 0 ~ .
ThereforetP(A)
is notcontained in
ro (A).
Since is not
always
contained inFi(A)
Cfo(A)
andC
fs(A),
it follows that is notalways
contained in andrs(A)
is notalways
contained inro(A).
We prove
that, generally speaking,
neitherr2 (A)
norr3(A)
are containedin
rs(A).
EXAMPLE 1.10 We consider the
complex
Hilbert space.~2
and thelinear and continuous
operator
A : :.~2
--~.~2 (where,
if denotesthe canonical basis of
~2,
that is en = for any n EN,
=03A3n~N
xne2n for any(Xn)nEN
612 ).
Obviously,
for any x E.~2,
so that~~A~~
= 1 and CBC (0,1 ).
Inaddition,
forany A
EBC(0,1 )
and for any x E~2,
Consequently, ~h2 -
A is one-to-one andA)
is closed for any A EBc(0,1) (see [TL] ,IV,5.9),
so thatBc(0,1)
Cps- F(A).
Since the function:
is
locally
constant(see [Ka], IV, 5.17)
andBC (o,1 )
isconnected,
it followsthat
We consider two closed
subspaces
and
It is not difficult to
verify
that Im A =Xi
andt2
=Xi ~X2.
Sinceobviously 22/Im
A = isisomorphic
toX2,
which isinfinite-dimensional,
itfollows that ind A = -oo.
Therefore =
Bc(O,l),
=Bc(U,1), oa-F(A)
=88c(0,1)
and =
BC(0,1).
Let us consider the
operator
0 on12 (where
0 is the nulloperator
one2). By [TL], V,5.4,
~0)
=o(A) U{0}
=Bc(0,1).
Since=
C~{0}
=p(0),
from Lemma 1.7 it follows thatand
Therfore
0)
=Bc(0,1),
so that0)
=0.
Since
e2~P2
is a Hilbert space, it follows that = =f 0}.
Hence neither
0)
nor0)
are contained in0).
We prove
that,
ingeneral,
there is not anyrelationship
of inclusion betweenr2(A)
andr3(A).
The
following example
shows thatr2(A)
is notalways
contained inF3(A).
EXAMPLE 1.11 . - Let us consider the
complex
Banach spaceQ~
x~oo?
with the canonical norm of the
product
+ for any(x, y)
Eeoo
x and theoperator
(where
= for any EObviously
H is anisomorphism
of Banach spaces, andIf we consider the
complex
Banach space co x.~~
and define the linear and continuousoperator
(where I A(x, y)
= for any(x, y)
E co x it follows thatfor any
(x, y)
E co x so that 1.Consequently, u(A)
CBc(0,1).
In
addition,
for any A EBc(0,1),
for any
(x, y)
E co xl~.
Thereforeker(03BBIc0 l~ - A) = {0}
andIm
A)
is closed forany A
E(see [TL], IV, 5.9) and, consequently, Bc(0,1)
Cpa_p(A).
Since the function:
is
locally
constant(see [Ka], IV, 5.17)
andBc(0, 1)
isconnected,
it followsthat
We remark that Im A is not the range of any continuous
projection
on Coxe~
(see [P], example
at pages 366 and367); consequently, (co
x A isinfinite-dimensional.
Therefore
u(A)
=Bc(O, 1)
and =Bc(0,1).
It follows that
U
=ôBc(O, 1),
and thereforer3(A)
=0.
We prove that