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www.elsevier.com/locate/anihpc

The limiting behavior of the value-function for variational problems arising in continuum mechanics

Alexander J. Zaslavski

Department of Mathematics, The Technion-Israel Institute of Technology, 32000 Haifa, Israel Received 17 May 2009; received in revised form 16 July 2009; accepted 16 July 2009

Available online 5 August 2009

Abstract

In this paper we study the limiting behavior of the value-function for one-dimensional second order variational problems arising in continuum mechanics. The study of this behavior is based on the relation between variational problems on bounded large intervals and a limiting problem on[0,∞).

©2009 Elsevier Masson SAS. All rights reserved.

MSC:49J99

Keywords:Good function; Infinite horizon; Minimal long-run average cost growth rate; Variational problem

1. Introduction

The study of properties of solutions of optimal control problems and variational problems defined on infinite domains and on sufficiently large domains has recently been a rapidly growing area of research. See, for example, [3,5,6,15–19,21–24] and the references mentioned therein. These problems arise in engineering [8], in models of economic growth [10,25], in infinite discrete models of solid-state physics related to dislocations in one-dimensional crystals [2,20] and in the theory of thermodynamical equilibrium for materials [7,9,11–14]. In this paper we study the limiting behavior of the value-function for variational problems arising in continuum mechanics which were considered in [7,9,11–14,21–24]. The study of this behavior is based on the relation between variational problems on bounded large intervals and a limiting problem on[0,∞).

In this paper we consider the variational problems T

0

f

w(t ), w(t ), w(t )

dt→min, wW2,1 [0, T]

, w(0), w(0)

=x and

w(T ), w(T )

=y, (P)

E-mail address:ajzasl@tx.technion.ac.il.

0294-1449/$ – see front matter ©2009 Elsevier Masson SAS. All rights reserved.

doi:10.1016/j.anihpc.2009.07.005

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whereT >0,x, yR2,W2,1([0, T])C1([0, T])is the Sobolev space of functions possessing an integrable second derivative [1] andf belongs to a space of functions to be described below. The interest in variational problems of the form(P )and the related problem on the half line:

lim inf

T→∞T1 T

0

f

w(t ), w(t ), w(t )

dt→min, wWloc2,1 [0,∞)

(P) stems from the theory of thermodynamical equilibrium for second-order materials developed in [7,9,11–14]. Here Wloc2,1([0,∞))C1([0,∞))denotes the Sobolev space of functions possessing a locally integrable second derivative [1] andf belongs to a space of functions to be described below.

We are interested in properties of the valued-function for the problem(P )which are independent of the length of the interval, for all sufficiently large intervals.

Leta=(a1, a2, a3, a4)R4,ai>0,i=1,2,3,4 and letα,β,γbe positive numbers such that 1β < α,βγ, γ >1. Denote byM(α, β, γ , a)the set of all functionsf :R3R1such that:

f (w, p, r)a1|w|αa2|p|β+a3|r|γa4 for all(w, p, r)R3; (1.1) f, ∂f/∂pC2, ∂f/∂rC3, 2f/∂r2(w, p, r) >0 for all(w, p, r)R3; (1.2) there is a monotone increasing functionMf : [0,∞)→ [0,∞)such that for every(w, p, r)R3

max

f (w, p, r),∂f/∂w(w, p, r),∂f/∂p(w, p, r),∂f/∂r(w, p, r)

Mf

|w| + |p|

1+ |r|γ

. (1.3)

Letf ∈M(α, β, γ , a). Of special interest is the minimal long-run average cost growth rate

μ(f )=inf

lim inf

T→∞T1 T

0

f

w(t ), w(t ), w(t )

dt: wAx , (1.4)

where Ax=

vWloc2,1 [0,∞)

:

v(0), v(0)

=x .

It was shown in [9] that μ(f )R1 is well defined and is independent of the initial vector x. A function wWloc2,1([0,∞))is called an(f )-good functionif the function

φwf :TT

0

f

w(t ), w(t ), w(t )

μ(f )

dt, T(0,)

is bounded. For everywWloc2,1([0,∞))the functionφwf is either bounded or diverges to∞asT → ∞and moreover, ifφwf is a bounded function, then

supw(t ), w(t ): t∈ [0,∞)

<

[22, Proposition 3.5]. Leizarowitz and Mizel [9] established that for every f ∈M(α, β, γ , a) satisfying μ(f ) <

inf{f (w,0, s): (w, s)R2}there exists a periodic(f )-good function. In [21] it was shown that a periodic(f )-good function exists for everyf ∈M(α, β, γ , a).

Letf ∈M(α, β, γ , a). For eachT >0 define a functionUTf :R2×R2R1by

UTf(x, y)=inf T

0

f

w(t ), w(t ), w(t )

dt: wW2,1 [0, T]

,

w(0), w(0)

=xand

w(T ), w(T )

=y . (1.5)

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In [9], analyzing problem (P)Leizarowitz and Mizel studied the function UTf :R2×R2R1, T >0 and established the following representation formula

UTf(x, y)=T μ(f )+πf(x)πf(y)+θTf(x, y), x, yR2, T >0, (1.6) whereπf :R2R1and(T , x, y)θTf(x, y)and(T , x, y)UTf(x, y),x, yR2,T >0 are continuous functions,

πf(x)=inf

lim inf

T→∞

T

0

f

w(t ), w(t ), w(t )

μ(f ) dt:

wWloc2,1 [0,∞)

and

w(0), w(0)

=x , xR2, (1.7)

θTf(x, y)0 for eachT >0, and eachx, yR2, and for everyT >0, and everyxR2there isyR2satisfying θTf(x, y)=0.

Denote by| · |the Euclidean norm inRn. For everyxRnand every nonempty setΩRnset d(x, Ω)=inf

|xy|: yΩ .

For each functiong:XR1∪ {∞}, where the setXis nonempty, put inf(g)=inf

g(z): zX .

Letf∈M(α, β, γ , a). It is easy to see that μ(f )inf

f (t,0,0): tR1 .

If μ(f )=inf{f (t,0,0): tR1}, then there is an (f )-good function which is a constant function. If μ(f ) <

inf{f (t,0,0): tR1}, then there exists a periodic(f )-good function which is not a constant function. It was shown in [14] that in this case the extremals of(P)have interesting asymptotic properties. In [26] we equipped the space M(α, β, γ , a)with a natural topology and showed that there exists an open everywhere dense subsetF of this topo- logical space such that for everyfF,

μ(f ) <inf

f (t,0,0): tR1 .

In other words, the inequality above holds for a typical integrandf ∈M(α, β, γ , a).

In the present paper for an integrandf ∈M(α, β, γ , a)satisfying μ(f ) <inf

f (t,0,0): tR1

we study the limiting behavior of the value-functionUTf asT → ∞and establish the following two results.

Theorem 1.1.Letf∈M(α, β, γ , a)satisfyμ(f ) <inf{f (t,0,0): tR1}. Then for eachx, yR2there exists Uf(x, y):= lim

T→∞

UTf(x, y)T μ(f ) .

Moreover,UTf(x, y)T μ(f )Uf(x, y)asT → ∞uniformly on bounded subsets ofR2×R2.

Theorem 1.2.Letf∈M(α, β, γ , a)satisfyμ(f ) <inf{f (t,0,0): tR1}. Then there exists a nonempty compact set ER2×R2such that

E=

(x, y)R2×R2: Uf(x, y)=inf Uf

.

Moreover, for any >0 there exist δ >0 and T >¯ 0 such that if T T¯ and if x, yR2 satisfy UTf(x, y) inf(UTf)+δ, thend((x, y), E).

The paper is organized as follows. Section 2 contains preliminaries. In Section 3 we prove several auxiliary results.

Theorems 1.1 and 1.2 are proved in Sections 4 and 5 respectively.

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2. Preliminaries

Forτ >0 andvW2,1([0, τ])we defineXv: [0, τ] →R2as follows:

Xv(t )=

v(t ), v(t )

, t∈ [0, τ].

We also use this definition forvWloc2,1([0,∞))andvWloc2,1(R1).

Put

M=M(α, β, γ , a).

We consider functionals of the form

If(T1, T2, v)=

T2

T1

f

v(t ), v(t ), v(t )

dt, (2.1)

Γf(T1, T2, v)=If(T1, T2, v)(T2T1)μ(f )πf Xv(T1)

+πf Xv(T2)

, (2.2)

where−∞< T1< T2<+∞,vW2,1([T1, T2])andf∈M.

IfvWloc2,1([0,∞))satisfies supXv(t ): t∈ [0,∞)

<,

then the set of limiting points ofXv(t )ast→ ∞is denoted byΩ(v).

For eachf ∈Mdenote byA(f )the set of allwWloc2,1([0,∞))which have the following property:

There isTw>0 such that

w(t+Tw)=w(t ) for allt∈ [0,∞) and If(0, Tw, w)=μ(f )Tw.

In other wordsA(f )is the set of all periodic(f )-good functions. By a result of [21],A(f )= ∅for allf ∈M.

The following result established in [13, Lemma 3.1] describes the structure of periodic(f )-good functions.

Proposition 2.1.Letf ∈M. Assume thatwA(f ), w(0)=inf

w(t ): t∈ [0,∞)

andw(t )=0for somet∈ [0,∞). Then there existτ1(w) >0andτ (w) > τ1(w)such that the functionwis strictly increasing on[0, τ1(w)],wis strictly decreasing on[τ1(w), τ (w)],

w τ1(w)

=sup

w(t ): t∈ [0,∞)

and w

t+τ (w)

=w(t ) for allt∈ [0,∞).

In [24, Theorem 3.15] we established the following result.

Proposition 2.2.Letf ∈M. Assume thatwA(f )andw(t )=0for somet∈ [0,∞). Then there existsτ >0such that

w(t+τ )=w(t ), t∈ [0,∞) and Xw(T1)=Xw(T2) for eachT1∈ [0,∞)and eachT2(T1, T1+τ ).

In the sequel we use the following result of [23, Proposition 5.1].

Proposition 2.3.Letf ∈M. Then there exists a numberS >0such that for every(f )-good functionv, Xv(t )S for all large enought.

The following result was proved in [13, Lemma 3.2].

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Proposition 2.4.Letf∈Msatisfy μ(f ) <inf

f (t,0,0): tR1 .

Then no element ofA(f )is a constant andsup{τ (w): wA(f )}<.

Proposition 2.5.Letf ∈Mand letM1, M2, cbe positive numbers. Then there existsS >0such that the following assertion holds:

IfT10,T2T1+cand ifvW2,1([T1, T2])satisfies Xv(T1),Xv(T2)M1 and If(T1, T2, v)UTf

2T1

Xv(T1), Xv(T2) +M2, then Xv(t )S for allt∈ [T1, T2].

For this result we refer the reader to [9] (see the proof of Proposition 4.4).

The following result was established in [14, Theorem 1.2].

Proposition 2.6.Letf∈Msatisfy μ(f ) <inf

f (t,0,0): tR1 and letvWloc2,1([0,∞))be such that

supXv(t ): t∈ [0,∞)

<, If(0, T , v)=UTf

Xv(0), Xv(T )

for allT >0.

Then there exists a periodic(f )-good functionwsuch thatΩ(v)=Ω(w)and the following assertion holds:

LetT >0 be a period ofw. Then for every >0there existsτ () >0such that for everyτ τ ()there exists s∈ [0, T )such that

v(t+τ ), v(t+τ )

w(s+t ), w(s+t ), t∈ [0, T]. The next useful result was proved in [13, Lemma 2.6].

Proposition 2.7.Letf ∈M. Then for every compact setER2there exists a constantM >0such that for every T 1

UTf(x, y)T μ(f )+M for allx, yE.

The next important ingredient of our proofs is established in [13, Lemma B5] which is an extension of [23, Lemma 3.7].

Proposition 2.8. Letf ∈M,wA(f )and >0. Then there existδ, q >0 such that for eachT q and each x, yR2satisfyingd(x, Ω(w))δ,d(y, Ω(w))δ, there existsvW2,1([0, τ])which satisfies

Xv(0)=x, Xv(τ )=y, Γf(0, τ, v).

We also need the following auxiliary result of [21, Proposition 2.3].

Proposition 2.9.Letf∈M. Then for everyT >0 UTf(x, y)→ ∞ as|x| + |y| → ∞.

Proposition 2.10.(See [12, Lemma 3.1].) Letf ∈Mandδ,τ are positive numbers. Then there existsM >0such that for everyT τ and everyvW2,1([0, T])satisfying

If(0, T , v)inf

UTf(x, y): x, yR2 +δ the following inequality holds:

Xv(t )M for allt∈ [0, T].

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3. Auxiliary results

Letf ∈M. By Proposition 2.2 for eachwA(f )which is not a constant there existsτ (w) >0 such that w

t+τ (w)

=w(t ), t∈ [0,∞), Xw(T1)=Xw(T2) for eachT1∈ [0,∞) and eachT2

T1, T1+τ (w)

. (3.1)

By Proposition 2.3 there exists a numberM >¯ 0 such that supXv(t ): t∈ [0,∞)

<M¯ for allvA(f ). (3.2)

Proposition 3.1.Suppose thatμ(f ) <inf{f (t,0,0): tR1}. Then inf

τ (w): wA(f )

>0.

Proof. Let us assume the contrary. Then there exists a sequence{wn}n=1A(f )such that limn→∞τ (wn)=0. It follows from (3.2), the definition ofτ (w),wA(f )and the equality above that forn=1,2, . . . ,

supwn(t )wn(s): t, s∈ [0,∞)

Mτ (w¯ n)→0 asn→ ∞. (3.3)

Since {wn}n=1A(f ) it follows from (3.2) and the continuity of the functions UTf,T >0 that for any natural numberkthe sequence{If(0, k, wn)}n=1is bounded. Combined with (3.2) and the growth condition (1.1) this implies that for any integerk1 the sequence{k

0|wn(t )|γdt}k=1is bounded. Since this fact holds for any natural numberk it follows from (3.2) that the sequence{wn}n=1is bounded inW2,γ([0, k])for any natural numberkand it possesses a weakly convergent subsequence in this space. By using a diagonal process we obtain that there exist a subsequence {wni}i=1of{wn}n=1andwWloc2,1([0,∞))such that for each natural numberk

wni, wn

i

w, w

asi→ ∞uniformly on[0, k], (3.4)

wn

iw asi→ ∞weakly inLγ[0, k]. (3.5)

By (3.4), (3.5) and the lower semicontinuity of integral functionals [4] for each natural numberk, If(0, k, w)lim inf

i→∞ If(0, k, wni).

Combined with (3.4) and (2.2), the continuity ofπf and the inclusionwnA(f ),n=1,2, . . . ,this inequality implies that for any natural numberk

Γf(0, k, w)lim inf

i→∞ Γf(0, k, wni)=0.

In view of (3.3) and (3.4),wis a constant function. Together with the relation above and (2.2) this implies that μ(f )=f

u(0),0,0

=inf

f (t,0,0): tR1 . The contradiction we have reached proves Proposition 3.1. 2 Proposition 3.2.Suppose that

μ(f ) <inf

f (t,0,0): tR1

. (3.6)

LetM, l, >0. Then there existδ >0andL > lsuch that for eachT Land eachvW2,1([0, T])satisfying

Xv(0),Xv(T )M, Γf(0, T , v)δ, (3.7)

there exists∈ [0, T −l]andwA(f )such that Xv(s+t )Xw(t ), t∈ [0, l].

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Proof. Assume the contrary. Then there exists a sequenceviW2,1([0, Ti]),i=1,2, . . . ,such that Til, i=1,2, . . . ,

Ti→ ∞ asi→ ∞, Γf(0, Ti, vi)→0 asi→ ∞, (3.8)

Xvi(0),Xvi(Ti)M, i=1,2, . . . , (3.9)

and that for each natural numberithe following property holds:

supXvi(s+t )Xw(t ): t∈ [0, l]

> for eachs∈ [0, T−l]and eachwA(f ). (3.10) We may assume without loss of generality that

Γf(0, Ti, vi)1, i=1,2, . . . . (3.11)

It follows from (2.2), (3.11), (1.6) and (1.5) that for each integeri1 If(0, Ti, vi)=πf

Xvi(0)

πf

Xvi(Ti)

+Tiμ(f )+Γf(0, Ti, vi) 1+πf

Xvi(0)

πf

Xvi(Ti)

+Tiμ(f ) 1+UTf

i

Xvi(0), Xvi(Ti)

. (3.12)

By (3.12), (3.9), (3.8) and Proposition 2.5 there exists a constantM1>0 such that Xv

i(t )M1, t∈ [0, Ti], i=1,2, . . . (3.13)

By (3.13), (3.12) and the continuity of UTf,T >0, for each natural number n, the sequence{If(0, n, vi)}i=i(n)is bounded, wherei(n)is a natural number such thatTi> nfor all integersii(n)(see (3.8)). Together with (3.13) and (1.1) this implies that for any natural numbernthe sequence{n

0 |vi(t )|γdt}i=i(n)is bounded. Since this fact holds for any natural numbernit follows from (3.13) that the sequence{vi}i=i(n)is bounded inW2,γ([0, n])for any natural numbernand it possesses a weakly convergent subsequence in this space. By using a diagonal process we obtain that there exist a subsequence{vik}k=1of{vi}i=1anduWloc2,1([0,∞))such that for each natural numbern

vik, vi

k

(u, u) ask→ ∞uniformly on[0, n], (3.14)

vi

ku ask→ ∞weakly inLγ[0, k]. (3.15)

In view of (3.14) and (3.13),

Xu(t )M1 for allt0. (3.16)

It follows from (3.14), (3.15), (3.13) and the lower semicontinuity of integral functionals [4] for each natural numbern If(0, n, u)lim inf

k→∞ If(0, n, vik).

Combined with (3.14), (3.13), (2.2), (1.6), the continuity ofπf and (3.8) the inequality above implies that for any natural numbern

Γf(0, n, u)lim inf

k→∞ Γf(0, n, vik)=0.

Thus

Γf(0, T , u)=0 for allT >0. (3.17)

By (3.16), (3.17) and Proposition 2.6 there existswA(f ) such thatΩ(w)=Ω(u) and the following assertion holds:

(A1) LetTwbe a period ofw(not necessarily minimal). Then for eachγ >0 there existsτ (γ ) >0 such that for each ττ (γ )there iss∈ [0, Tw)such that

Xu(t+τ )Xw(s+t )γ , t∈ [0, Tw].

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We may assume without loss of generality that a periodTw ofw satisfiesTw> l. Assumption (A1) implies that there existτ >0 andw˜∈A(f )such that

Xu+t )Xw˜(t )/4, t∈ [0, l].

Combined with (3.14) this implies that for all sufficiently large natural numbersk Xvik+t )Xw˜(t )/2, t∈ [0, l].

This contradicts (3.10). The contradiction we have reached proves Proposition 3.2. 2

Proposition 3.3.LetM >0andδ >0. Then there exists a natural numbernsuch that for each numberT 1and eachvW2,1([0, T])satisfying

Xv(0),Xv(T )M, If(0, T , v)UTf

Xv(0), Xv(T )

+1 (3.18)

the following property holds:

There exists a sequence{ti}mi=0withmnsuch that 0=t0< t1<· · ·< ti< ti+1<· · ·< tm=T ,

Γf(ti, ti+1, v)=δ for any integerisatisfying0i < m−1, Γf(tm1, tm, v)δ. (3.19) Proof. By Proposition 2.7 there exists a constantM1>0 such that

UTf(x, y)T μ(f )+M1 for eachT 1 and each x, yR2 satisfying|x|,|y|M. (3.20) Together with (2.2) and (3.20) this implies that ifT 1 and ifvW2,1([0, T])satisfies (3.18), then

Γf(0, T , v)UTf

Xv(0), Xv(T )

+1−T μ(f ),πf Xv(0)

+πf Xv(T )

M1+1+2M2, (3.21) where

M2=supπf(z): zR2and|z|M

. (3.22)

Choose a natural numbern >4 such that

(n−2)δ >2(M2+M1+1). (3.23)

Assume now thatT 1 and thatvW2,1([0, T])satisfies (3.18). Then by (3.21) and (3.22),

Γf(0, T , v)M1+1+2M2. (3.24)

Clearly for eachτ∈ [0, T ), limsτ+Γf(τ, s, v)=0 and one of the following cases holds:

Γf(τ, T , v)δ; there existsτ¯∈(τ, T )such thatΓf(τ,τ , v)¯ =δ.

This implies that there exist a natural numbermand a sequence{ti}mi=0such that (3.19) is true. In order to complete the proof of the proposition it is sufficient to show thatmn. By (3.24), (3.19) and (3.23),

2M2+1+M1Γf(0, T , v)(m−1)δ and

m1+δ1(2M2+1+M1) < n.

Proposition 3.3 is proved. 2

The following proposition is a result on the uniform equicontinuity of the family(UTf)Tτ on bounded sets.

Proposition 3.4.LetM >0and τ >0. Then for each >0there existsδ >0 such that for eachT τ and each x, y,x,¯ y¯∈R2satisfying

|x|,|y|,| ¯x|,| ¯y|M, |x− ¯x|,|y− ¯y|δ (3.25) the following inequality holds:

UTf(x, y)UTf(x,¯ y)¯ . (3.26)

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Proof. Let >0. By Proposition 2.5 there exists a constant M1> M such that for each T τ and each vW2,1([0, T])satisfying

Xv(0),Xv(T )M, If(0, T , v)UTf

Xv(0), Xv(T )

+1 (3.27)

the following inequality holds:

Xv(t )M1, t∈ [0, T]. (3.28)

Since the functionUτ/4f s continuous, it is uniformly continuous on compact subsets ofR2×R2and there existsδ >0 such that

Uτ/4f (x, y)Uτ/4f (x,¯ y)¯ /4 (3.29)

for eachx, y,x,¯ y¯∈R2satisfying

|x|,|y|,| ¯x|,y¯|M1, |x− ¯x|,|y− ¯y|δ. (3.30) Assume thatx, y,x,¯ y¯∈R2satisfy (3.25) and thatT τ. In order to prove the proposition it is sufficient to show that

UTf(x,¯ y)¯ UTf(x, y)+. There existsvW2,1([0, T])such that

Xv(0)=x, Xv(T )=y, If(0, T , v)=UTf(x, y). (3.31)

By (3.31), (3.25) and the choice ofM1, (3.28) is valid. There existsuW2,1([0, T])such that Xu(0)= ¯x, Xu(τ/4)=Xv(τ/4), If(0, τ/4, u)=Uτ/4f

¯

x, Xv(τ/4) , u(t )=v(t ), t∈ [τ/4, Tτ/4],

Xu(Tτ/4)=Xv(Tτ/4), Xu(T )= ¯y, If(Tτ/4, T , u)=Uτ/4f

Xv(Tτ/4),y¯

. (3.32)

It follows from (3.25) and (3.28) and the choice ofδ(see (3.29) and (3.30)) that Uτ/4f

¯

x, Xv(τ/4)

Uτ/4f

x, Xv(τ/4)/4, Uτ/4f

Xv(Tτ/4),y¯

Uτ/4f

Xv(Tτ/4), y/4.

It follows from the inequalities above, (3.32) and (3.31) that

UTf(x,¯ y)¯ If(0, T , u)=If(0, τ/4, u)+If(τ/4, Tτ/4, u)+If(Tτ/4, T , u)

=Uτ/4f

¯

x, Xv(τ/4)

+If(τ/4, Tτ/4, u)+Uτ/4f

Xv(Tτ/4),y¯ Uτ/4f

x, Xv(τ/4)

+/4+If(τ/4, Tτ/4, u)+Uτ/4f

Xv(Tτ/4), y +/4

=If(0, T , v)+/2=UTf(x, y)+/2.

Proposition 3.4 is proved. 2 Proposition 3.5.Suppose that

μ(f ) <inf

f (t,0,0): tR1 .

Let >0. Then there existq >0andδ >0such that the following assertion holds:

LetT q,wA(f ), x, yR2, d

x, Ω(w) , d

y, Ω(w)

δ. (3.33)

Then there existsvW2,1([0, T])which satisfies

Xv(0)=x, Xv(τ )=y, Γf(0, τ, v). (3.34)

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Proof. By Proposition 2.8 for eachwA(f )there existδ(w),q(w) >0 such that the following property holds:

(P1) IfT q(w)and ifx, yR2satisfyd(x, Ω(w)),d(y, Ω(w))δ(w), then there existsvW2,1([0, T])which satisfies (3.34).

By Propositions 2.4 and 3.1, T¯:=sup

τ (w): wA(f )

<, (3.35)

inf

τ (w): wA(f )

>0. (3.36)

Define

E=

Ω(w)×Ω(w): wA(f )

. (3.37)

We will show thatEis compact. In view of (3.2) it is sufficient to show thatEis closed.

Let

(xi, yi)

i=1E, lim

i→∞(xi, yi)=(x, y). (3.38)

We show that(x, y)E. For each natural numberithere existwiA(f ),si, ti∈ [0,∞)such that xi=

wi(ti), wi(ti)

, yi=

wi(si), wi(si)

. (3.39)

In view of (3.35) we may assume that

ti, si∈ [0,T¯], i=1,2, . . . . (3.40)

By (3.2) and the continuity ofUf¯

T, the sequence{If(0,T , w¯ i)}i=1is bounded. Combined with (3.2) and (1.1) this implies that the sequence{T¯

0 |wi(t )|γdt}i=1is bounded. Extracting a subsequence and re-indexing if necessary we may assume without loss of generality that there exist

t= lim

i→∞ti, s= lim

i→∞si, τ= lim

i→∞τ (wi) (3.41)

and there existsuW2,γ([0,T¯])such that wiu asi→ ∞weakly inW2,γ

[0,T¯] ,

wi, wi

(u, u) asi→ ∞uniformly on[0,T¯]. (3.42)

By (3.42), (3.2), the continuity ofπf, and the lower semicontinuity of integral functionals [4], Γf(0,T , u)¯ lim inf

i→∞ Γf(0,T , w¯ i)=0 andΓf(0,T , u)¯ =0.

It follows from (3.38), (3.39), (3.40), (3.42) and (3.41) that x= lim

i→∞xi= lim

i→∞

wi(ti), wi(ti)

= lim

i→∞

u(ti), u(ti)

=

u(t), u(t)

, (3.43)

y= lim

i→∞yi= lim

i→∞

wi(si), wi(si)

= lim

i→∞

u(si), u(si)

=

u(s), u(s)

. (3.44)

By (3.42), the inclusionwiA(f ),i=1,2, . . ., (3.35) and (3.41), Xu(0)= lim

i→∞Xwi(0)= lim

i→∞Xwi τ (wi)

= lim

i→∞Xu τ (wi)

=Xu).

In view of (3.41), (3.40) and (3.36), 0< τT .¯

We have shown that

Xu(0)=Xu), 0Γf(0, τ, u)Γf(0,T , u)¯ =0.

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This implies thatucan be extended on the infinite interval[0,∞)as a periodic(f )-good function with the periodτ. Thus we have thatuA(f )and in view of (3.43), (3.44) and (3.37)

(x, y)Ω(u)×Ω(u)E.

ThereforeEis compact. For eachwA(f )define an open setU(w)R4by U(w)=

(x, y)R4: d

x, Ω(w)

< δ(w)/4, d

y, Ω(w)

< δ(w)/4

. (3.45)

ThenU(w),wA(f )is an open covering of the compactEand there exists a finite set{w1, . . . , wn} ∈A(f )such that

En

i=1

U(wi). (3.46)

Set

q=max

q(wi): i=1, . . . , n

, δ=min

δ(wi)/4:i=1, . . . , n

. (3.47)

LetT q,wA(f )and letx, yR2satisfy (3.33). There exist

˜

x,y˜∈Ω(w) (3.48)

such that

|x− ˜x|,|y− ˜y|δ. (3.49)

In view of (3.37), (3.46) and (3.48),(x,˜ y)˜ ∈Eand there isj∈ {1, . . . , n}such that

(x,˜ y)˜ ∈U(wj). (3.50)

Relations (3.50) and (3.45) imply that there exist

¯

x,y¯∈Ω(wj) (3.51)

such that

| ˜x− ¯x|,| ˜y− ¯y|< δ(wj)/4. (3.52)

By (3.49), (3.52) and (3.47)

|x− ¯x|,|y− ¯y|< δ+δ(wj)/4δ(wj)/2.

It follows from this inequalities, (3.51), property (P1) withw=wj, (3.47) and the inequalityT qthat there exists vW2,1([0, T])satisfying (3.34). Proposition 3.5 is proved. 2

4. Proof of Theorem 1.1

By Proposition 3.4 in order to prove the theorem it is sufficient to show that for eachx, yR2there exists

Tlim→∞

UTf(x, y)T μ(f ) .

Letx, yR2and fix >0. We will show that there existT >¯ 0 andq >0 such that

USf(x, y)Sμ(f )UTf(x, y)T μ(f )+ (4.1)

for eachT T¯ and eachST +q.

By Proposition 3.5 there existq >0,δ0>0 such that for the following property holds:

(P2) For eachT q, eachwA(f )and eachx, yR2satisfying d

x, Ω(w) , d

y, Ω(w)

δ0 (4.2)

there existsvW2,1([0, T])such that

Xv(0)=x, Xv(T )=y, Γf(0, T , v). (4.3)

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In view of Proposition 2.4 there exists a real number l >sup

τ (w): wA(f )

. (4.4)

Choose

M0>|x| + |y| +2. (4.5)

By Proposition 2.5 there existsM1> M0such that for eachT 1 and eachvW2,1([0, T])satisfying Xv(0),Xv(T )M0, If(0, T , v)UTf

Xv(0), Xv(T )

+1 (4.6)

the following inequality holds:

Xv(T )M1, t∈ [0, T]. (4.7)

By Proposition 3.2 there existδ1>0,L1> lsuch that for eachT L1and eachvW2,1([0, T])satisfying

Xv(0),Xv(T )M1, Γf(0, T , v)δ1 (4.8)

there existσ∈ [0, T −l]andwA(f )such that

Xv+t )Xw(t )δ0, t∈ [0, l]. (4.9)

By Proposition 3.3 there exists a natural numbernsuch that for eachT 1 and eachvW2,1([0, T])satisfying Xv(0),Xv(T )M1, If(0, T , v)UTf

Xv(0), Xv(T )

+1 (4.10)

there exists a sequence{ti}mi=0⊂ [0, T]withmnsuch that

0=t0<· · ·< ti< ti+1<· · ·< tm=T , (4.11) Γf(ti, ti+1, v)=δ1 for all integersisatisfying 0i < m−1,

Γf(tm1, tm, v)δ1. (4.12)

Choose a number

T >¯ 1+nL1. (4.13)

Let

T T ,¯ ST +q. (4.14)

There existsvW2,1([0, T])such that

Xv(0)=x, Xv(T )=y, If(0, T , v)=UTf(x, y). (4.15)

By (4.5), (4.13), (4.14), the choice ofM1and (4.15), the inequality (4.7) holds. In view of (4.15), the choice ofn(see (4.10)–(4.12)), (4.14), (4.13) and (4.5) there exists a sequence{ti}mi=0⊂ [0, T]withmnsuch that (4.11) and (4.12) hold. It follows from (4.14), (4.13) and (4.11) that

max

ti+1ti: i=0, . . . , m−1

T /mT /n > L¯ 1. Thus there existsj ∈ {0, . . . , m−1}such that

tj+1tj> L1. (4.16)

By (4.16), (4.7), (4.12) and the choice ofδ1, L1(see (4.8), (4.9)) there exist

σ∈ [tj, tj+1l], wA(f ) (4.17)

such that (4.9) holds.

In particular d

Xv(σ ), Ω(w)

δ0. (4.18)

(13)

It follows from (4.14), (4.17), the property (P2) and (4.18) that there exists hW2,1

[σ, σ +ST] such that

Xh(σ )=Xv(σ ), Xh+ST )=Xv(σ ),

Γf(σ, σ+ST , h). (4.19)

It is easy to see that there existuW2,1([0, S])such that

u(t )=v(t ), t∈ [0, σ], u(t )=h(t ), t∈ [σ, σ +ST],

u(σ+ST+t )=v(σ+t ), t∈ [0, T −σ]. (4.20) By (4.20) and (4.15),

Xu(0)=x, Xu(S)=y. (4.21)

By (4.21), (2.2), (4.15), (4.20) and (4.19), USf(x, y)Sμ(f )If(0, S, u)Sμ(f )

=πf Xu(0)

πf Xu(S)

+Γf(0, S, u)

=πf Xu(0)

πf Xu(S)

+Γf(0, σ, u)+Γf(σ, σ+ST , u)+Γf+ST , S, u)

=πf Xv(0)

πf Xv(T )

+Γf(0, σ, v)++Γf(σ, T , v)

=+If(0, T , v)T μ(f )=UTf(x, y)T μ(f )+.

Thus we have shown that (4.1) holds for eachT T¯ and eachST+q. By Proposition 2.7 sup

UTf(x, y)T μ(f ): T ∈ [1,∞)

<. On the other hand by (1.6) for eachT 1

UTf(x, y)T μ(f )πf(x)πf(y).

Hence the set{UTf(x, y): T ∈ [1,∞)}is bounded. Put d= lim

T→∞inf

USf(x, y)Sμ(f ): S∈ [T ,)

. (4.22)

We show that d= lim

T→∞

UTf(x, y)T μ(f ) .

Let >0. We have shown that there existT >¯ 0,q >0 such that (4.1) holds for eachT T¯ and eachST +q. By (4.22) there existsT0T¯ such that

dinf

USf(x, y)Sμ(f ): S∈ [T0,)

d. (4.23)

There existsT1T0such that UTf

1(x, y)T1μ(f )−inf

USf(x, y)Sμ(f ): S∈ [T0,). (4.24)

LetT T1+q. Then in view of (4.23) UTf(x, y)T μ(f )inf

USf(x, y)Sμ(f ): S∈ [T0,)

d.

On the other hand by the relationT T1+qT0+qT¯+q, (4.1) (which holds withT =T1,S=T), (4.24) and (4.23)

UTf(x, y)T μ(f )UTf

1(x, y)T1μ(f )+ inf

USf(x, y)Sμ(f ): S∈ [T0,)

+2d+2.

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