A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
T ERO K ILPELÄINEN J AN M ALÝ
Degenerate elliptic equations with measure data and nonlinear potentials
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 19, n
o4 (1992), p. 591-613
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and
Nonlinear Potentials
TERO
KILPELÄINEN -
JANMALÝ*
Introduction
Throughout
this paper let Q be an open set in > 2. Let be the set of allnonnegative
finite Radon measures on Q.The
problem
where p E and 1 p n, is not, in
general,
solvable in Ifp = 2, we are in the case of the
Laplacian
and ageneralized
solution to(1)
canbe
given by
rrwhere G is the Green function. No
corresponding integral representation
isavailable when
p # 2.
An existence result for
equations
where
lB7ulP (see
Section1),
wasrecently
establishedby
Boccardo and Gallouet
[1] ] (for
p > 2 -1 /n
and Qbounded).
In their paper, a function u in is found such that.~ ( ~ , ~7 u)
E andfor
all p
E However such a solution is"very
weak" and theuniqueness
may fail
[16].
It seems to be animportant problem
to find anappropriate
class* The second author gratefully acknowledges the hospitality of the Mathematics Depart-
ment in Jyvaskyla where part of this research was conducted during his visit in June 1990.
Pervenuto alla Redazione il 15 Novembre 1990 e in forma definitiva il 27 Agosto 1992.
of functions in which both the existence and the
uniqueness
results forequation (2)
are valid.We pursue the existence
problem
and it turns out that the class of theso called
-superharmonic
functions(see
Section1)
is wideenough
to solveequation (2). Conversely,
we show that each-superharmonic
function solvesequation (2)
with somenonnegative (not necessarily finite)
Radon measure uon Q. The
uniqueness
of-superharmonic
solutions remains open; note that Serrin’snon-unique
solution[16]
is notA-superharmonic.
Our
approach departs
from[ 1 ]
in three ways: We take care of theA-superharmonicity
of the solution. Our structuralassumptions
on theequation
continue in the tradition of nonlinear
potential theory (see
e.g.[4-13]) and, therefore,
arepartially less, partially
more, restrictive than the structural as-sumptions
in[ 1 ] 1. Finally,
we do not exclude thepossibility p
2 -1 /n.
However, this
requires
us tointerpret
the derivative Vu in a new way when u does not possess functions as distributional derivatives: we define thegradient
Du of an
A-superharmonic
function uby
(see
Section1 ).
As to our method of
proof,
the main new feature is the use ofHl,P-estimates
for truncated solutions ratherthan Hl,q -estimates
for solutions.In the second
part
of the paper, we establishpointwise
estimates for anA-superharmonic
solution in terms of a nonlinearpotential
x E R"B r > 0. The
potential Wr,p
isprincipal
in thetheory
of nonlinearpotentials.
Forexample,
anonnegative
Radon measure ubelongs
toif and
only
ifr
cf.
[3].
Our maintheorem,
whichgives
a new link between the two nonlinearpotential theories,
reads as follows:MAIN THEOREM. Let u be an
A-superharmonic function
in S2 andlet it
be the
nonnegative
Radon measure1 Note added in August 1992: After the submission of this paper for publication, the
existence result in [1] has been extended for more general classes of equations than ours by
Rakotoson (Quasilinear elliptic problems with measures as data, Differential Integral Equations
4 (1991), 449-457) and by Boccardo and Gallouet (Nonlinear elliptic equations with right hand
side measures, Comm. Partial Differential Equations 17 (1992), 641-655).
Suppose
thatB(x, 2r)
c Q. Then there is a constant cldepending only
on n,p, and the structure
of
A such thatIf,
in addition, p > n - 1, thenwhere C2 =
c2(n, p)
> 0. Inparticular, if wt,p(x; r)
isfinite,
thenu(x)
isfinite.
That the
potential
is bounded if the solution of(2)
is bounded seems to be known tospecialists. Nevertheless,
we have not been able to locate the result in the literature.Moreover,
our theoremgives
apointwise
estimate forWi, Apparently,
the reverse direction is not yet well understood. Our method breaks down if p n - 1 because itstrongly employs
the Sobolevembedding
theorem on
(n - 1 )-spheres. Loosely
related to our upper estimate is a result of Rakotoson and Ziemer[15]; they
show that iffor all small r, then a solution to
(1)
is notonly
bounded butlocally
Holdercontinuous;
see also[14].
Our paper is
organized
as follows. Section 1provides
the necessarypreliminaries
of the nonlinearpotential theory
ofA-superharmonic
functionsas well as
precise definitions;
some of the results in Section 1 may be ofindependent
interest. Then existenceproblem
is discussed in Section 2. In Section 3 we establish the first part of the main theorem and theconcluding
section contains the upper bound in the case when p > n - 1.
NOTATION. Our notation is
fairly
standard andself-explanatory.
Let usemphasize
that Qalways
stands for an open set in Rn, n > 2, for theset of all
nonnegative
finite Radon measures inQ,
and for the set of allinfinitely
many times differentiable functions with compactsupport
in Q. The minimum of functions u and v is denotedby u
A v, the maximum of u and vby u
V v, and thepositive
part of uby u+
= u V 0. The open ballB(O, r)
of radius r centered atorigin
is abbreviatedby
Br and itssphere aB(o, r) by Sr.
The
Lebesgue
measure of a set E is writtenas JEJ.
1. -
A-superharmonic
functionsWe assume
throughout
this paper that A : Rn x R’ - is amapping
which satisfies the
following assumptions
for some numbers 1p
n andthe
h)
is measurable for all h ER",
andthe function h -
h)
is continuous for a.e. x cR7;
whenever
hi fh2,
andA solution u to
equation
always
has a continuous version which we call A-harmonic. Hence u is A-harmonic in Q if u E nC(Q)
andfor
all p
ECoo(12).
A function u is called asupersolution
of(1.6)
if u Eand r
for all
nonnegative p
EA lower semicontinuous function u: 0. ~
(-oo,
oo] is calledA-superharmonic
if u is notidentically infinite
in each component of 0., andif for all open D C C Q and all h E
C(D),
A-harmonic in D, h u on aDimplies h u
in D.To ease some formulations we say that u is
A-hyperharmonic
in 0. if ineach
component
of 0. u is eitherA-superharmonic
oridentically
oo.In this section we record some
properties
ofA-superharmonic
functions.For more on their nonlinear
potential theory
see[4-6], [8-10],
and[12].
Clearly,
and areA-superharmonic
if u and v are, and E R, À > 0. Moreover we have thefollowing
relation betweenA-superharmonic
functions
andsupersolutions
of(1.6).
PROPOSITION [4] 1.7.
(i) If
u is asupersolution of (1.6),
then there is anA-superharmonic function
v such that u = v a. e. Moreover,(ii) If
v isA-superharmonic,
then(1.8)
holds. Moreover, v is a superso- lutionof ( 1.6) provided
that v E(iii) If
v isA-superharmonic
andlocally bounded,
then v E andtherefore
it is asupersolution.
It is worth
mentioning
thatA-superharmonic
functions are(I, p)-finely
continuous which in
particular
means thatthey
areapproximately
continuousC8] .
BALAYAGE 1.9. Let u be a
nonnegative A-superharmonic
function in Q and E c Q. IfR’(x; Q)
=inf{v(x):
v isJI.-superharmonic,
v >0,
and v > u onE},
then the lower semicontinuous
regularization
of
Ru
is called thebalayage of u
on E. The functionRE
isA-superharmonic
in Q and A-harmonic in
S2/E. Moreover,
if Q isbounded,
E C C Q, and u isbounded,
then1~E belongs
to(see
theproof
of[6, 2.2]).
GRADIENT OF AN -SUPERHARMONIC FUNCTION 1.10. It may occur that
an
A-superharmonic
function is notlocally integrable
or that its distributional derivative is not a function. Thus we are led to thefollowing
concept of derivative whichassigns
agradient (a function!)
to eachA-superharmonic
function
and,
moregenerally,
to each function whose truncations arelocally
in a Sobolev space.
Suppose
that u is a function in Q such that the truncations =1, 2, ..., belong
to We let Du stand for the a.e. defined functionIf u E the function Du is the distributional
gradient
of u. However, for p 2 -1 /n
there areA-superharmonic
functions u not inHl,l (see 1.16)
and thus Du is not, in
general,
the distributionalgradient
of u.We show
that
islocally integrable
for anA-superharmonic
u. Firstwe prove an
auxiliary
result.LEMMA 1.11. Let S2 be bounded and let u be a
nonnegative,
a. e.finite function
on Q.Suppose
thatfor
alland
for
some constant M,independent of
k.If :
thenwhere
c=c(n,p,q,M,diamQ).
PROOF. Let
... -- I
Fix k and choose an
integer
m with k 2m.Writing
v = u A 2m we haveby
the Sobolev
embedding
theorem and(1.12)
that-, "
Using
the Holderinequality
we obtainwhere c =
c(n,
p, q,M,
diam(1)
> 0 andHence
and the lemma follows.
THEOREM 1.13. Let u be a
nonnegative A-superharmonic function
in abounded open set S2 such that
for
each q with PROOF.Assumption (1.2) implies
where
We show that the sequence ak is
decreasing,
and henceand the assertion follows from Lemma 1.11.
Now Uk
= u A(k
+1)
E is asupersolution
andan
appropriate
testfunction;
we concludeas desired.
Lindqvist [11]
showed that 1 - islocally integrable
if u is
p-superharmonic (i.e. h) = IhIP-2h).
We extend his result forgeneral A-superharmonic
functionsby using
a differenttechnique.
THEOREM 1.15.
Suppose
that u isA-superharmonic
in SZ and 1 qn .
n-l* Thenboth
andA(., Du) belong
toMoreover,
if
p > 2 -1 /n,
then Du is the distributionalgradient of
u.PROOF. Fix open sets G C C G’ cc Q. Then m = inf u > - oo . Now
~ G’
the
balayage
v(x) -G’)
is anonnegative
A-superharmonic
functionsatisfying
the weak zeroboundary
condition(1.14)
in G’. Henceby
Theorem1.13,
ELq (G’ ) .
S ince u = v + m in G, we havethat E Lq (G)
andtherefore
A(., Du)
ELq (G).
For p > 2 -
1/n
we can choose qon/(n - 1)
such thatqo(p - 1)
> 1.Then the compactness
properties
of allow us to conclude thatand hence Du is the distributional
gradient
of u.fundamental
A-superharmonic function,
Then
is not the distributional derivative of u because
THEOREM 1.17.
Suppose
that uj is a sequenceof nonnegative
A-superharmonic functions
in Q. Then there is anA-hyperharmonic function
uin S2 and a
subsequence
ujiof
PROOF.
Step
1. Assume that forall j.
Choose open sets G cc G’ cc Q.By
theCaccioppoli inequality [4, 2.16]
we havesuch that
where the constant c is
independent of j. Consequently,
the sequence u j is bounded in and we maypick
asubsequence
Ujiof u j
and a functionu E such that both
weakly
in andpointwise
a.e.We show that this
subsequence,
denoted from now onby
u j , has the desiredproperties
in G.If vi
= then the lower semicontinuousregularization
v2 of via,j>i
is
A-superharmonic and i3,
= vi a.e. in G’[5,
Theorem6.1].
Now the functionsi3, increase to an
A-superharmonic
function v and v = u a.e..Next we show that
Fix e > 0 and let
We estimate the measure of
Ej.
First we have thatLet be a cut-off
function,
and
then both and are
nonnegative
functions inHo’p(G’),
henceappropriate
test functions. Since u
and uj
aresupersolutions and uj
- uweakly
inHI,P(GI),
we obtain
using (1.18)
thatwith c
independent of j
and 6-, andsimilarly
Adding
thesetogether
we arrive at the estimateand since the
integrand
isnonnegative
we haveby (1.19)
thatwhere the constant c is
independent of j
and e.We infer from
(1.20)
thatIndeed, writing
we have that h -
A(h, ho)
iscontinuous, A(h, ho)
> 0 if andA(h, ho)
-> o0as h -~ oo.
Using (1.20)
weeasily
conclude(1.21).
The
proof
of the assertion under theassumption
ofStep
1 is nowcompleted by using
an exhaustionargument
andchoosing
adiagonal subsequence.
Step
2. Now we treat thegeneral
case. Inlight
ofStep
1 we may selectsubsequences of uj
and findA-superharmonic functions vk
suchthat for all l~ =
1, 2, ...,
is asubsequence
of Ak - vk
a.e., andA
k)
~VVk
a.e. It is easy to see that Vk increases to anA-hyperharmonic
function u
and,
moreover, u A k for each k. Thediagonal
sequenceu~ ~
obviously
has the desiredproperties.
2. - Existence of
A-superharmonic
solutionsWe introduce an operator
TA
= Tacting
on thefamily
of allA-superhar-
monic functions u in S2
by
for
all p
ECol(Q).
Note that the function z -Du)
islocally integrable
in Q(Theorem 1.15)
and thus itsdivergence
divA (x, Du)
in the sense of distributionsis -T u,
i.e.Obviously,
T u is anonnegative
Radon measure on Q if u is asupersolution
of
(1.6).
Thefollowing
theorem shows that the same is true for eachA-super-
harmonic function u.
THEOREM 2.1.
Suppose
that u isA-superharmonic
in SZ. Then there is anonnegative
Radon measure Jj on Q such thatwhenever cp E
co 00 (K2),
that is,PROOF. Fix a
nonnegative
ECo(o.).
SinceA(.,Du)
E(Theorem 1.15),
it follows from theLebesgue
dominated convergence theorem thatI
Using
the Rieszrepresentation
theorem we conclude that Tu is anonnegative
Radon measure.
REMARK 2.2. The
proof
of Theorem 2.1 shows:if
u is anA-superharmonic function
in Q and tt = Tu, then the measures =T(u
Ak)
convergeweakly
toJ-t on Q.
Next we show that the
equation
where u
EM+(Q),
has anA-superharmonic
solution with weak zeroboundary
values.
THEOREM 2.4.
Suppose
that Q is bounded and ti E.M+(S~).
Then there isan
A-superharmonic function
u in SZ such thatin 0. and
PROOF.
Let lij
be a sequence ofnonnegative
measures associated with densities in such that tij convergesweakly
to It. We may assume thatLet
then uj
be theA-superharmonic
function in Q such that Uj E and(see
e.g.[13]). By
Theorem 1.17 we may select asubsequence
of uj, denotedagain by
uj, such that Uj converges to anA-hyperharmonic
function -it a.e. onQ. We have the estimate
It now follows from the Poincaré
inequality
thatwith c
independent of j
and k. Henceand u is thus
A-superharmonic. Moreover,
Du a.e. in Q(Theorem 1.17).
These estimates also guarantee that
Then let v = Tu. We show that v = u which
completes
theproof.
To thisend,
fix 1 q
$.
From(2.5)
and Lemma 1.11 we obtain fix 1 on - I
From(2.5)
and Lemma 1.11 we obtainwhere c is
independent of j. Therefore, Du) weakly
inLq(n)
becauseVuj -
Du a.e. Thus we have for each p ECo-(Q)
thatSince lLj
2013~ /~weakly,
we also haveConsequently, p
= v as desired.REMARK 2.6. In
light
of Theorem 1.13 and the Poincaréinequality we
have
that,
for p > 2 - the solution u in Theorem 2.4belongs
toHo,q(Q)
REMARK 2.7.
Combining
the methods of this paper and[ 1 ]
we arrive at thefollowing
existence result:if tL
is a finitesigned
Radon measure on Q, then there is a"very
weak" solution u to theproblem
That
is, u
has theproperties
that all its double-sided truncations uk =belong
to and-divA(z, weakly
on Q.3. - Lower estimate
In this section we prove a lower estimate for an
A-superharmonic
functionin terms of a nonlinear
potential.
THEOREM 3.1. Let u be an
A -superharmonic function
in SZ and it = Tu.If B(xo, 2r)
C Q, thenwhere c =
c(n,
p,I)
> 0 andFor the
proof
we first record anappropriate
form ofTrudinger’s
weakHarnack
inequality [17].
LEMMA 3.2. Let u be a
nonnegative supersolution of ( 1.6)
inB4R. If
q > 0 is such thatq(n - p) n(p - 1),
thenwhere c =
c(n,
p, q,~/)
> 0.PROOF.
By [17,
Theorem1.2],
such a constant c exists if u 1 inB4R.
However,
as wellknown,
thesimpler
structure of ourequation
allows us toobtain the
inequality
without boundedness restriction.Indeed,
set(u/ j) A
1.Then
and hence
Letting j
- oo we obtain the desired estimate.Also we need the
following
well known estimate._
LEMMA 3.3. Let u be a
supersolution of (1.6)
in an open setcontaining BR
such that u > 0 inBR. Let 11
ECü(BR)
benonnegative.
For all - E(o, p -1 )
we have
~ _
where c =
(p,/e)P.
PROOF. For the sake of convenience we include a short
proof. Fix j E
Nand
write uj = u
+ Set v =ujé
and w = Then w EH~"P(BR)
isnonnegative
and henceUsing
the structuralassumptions
and the Holderinequality,
it follows thatwhich
implies
thereguired
estimate when u isreplaced by
uj.Letting j
- 00completes
theproof.
The next estimate is a refined version of an estimate of
Gariepy
andZiemer
[2].
LEMMA 3.4. Let u be a
nonnegative supersolution of (1.6)
inB4R.
Letr~ E
Cü(B3R)
be acut-off function
such that 0 q 1, q = 1 onB2R,
andwhere c =
c(n,
p,I)
> 0.PROOF.
We use the argument of theproof
of Theorem 2.1 in[2].
Lete
= 2 min(p - l,p/(yz - p) (if
p = n, let - =(n - 1)/2)).
Denote q =p/(p - 1),
II
= p - 1 - -,
and ~2 =(p- 1)(1+6-). Using
Lemmas 3.2 and3.3,
and the Holder Theninequality
we obtainand the lemma is
proved.
The
following
estimate takes the measure data into account.LEMMA
3.5. Suppose
that u isA-superharmonic
and J.-t = Tu in an open setcontaining BR.
Thenwhere c =
c(n,
p,~y)
> 0.PROOF. Write a = inf u and b = inf u. Choose a
positive integer j
> b andBR BR12
let uj = u
A j. Let /-lj = Tuj
and let 1] E 0 1] 1, be a cut-offfunction such
that ?7
= 1 inand IV?71 I 10/R.
We use the test functionw~ in
BR, where v j = (u j A b) - a.
Thenand wj
= b - aon
BR~2. Using
theCaccioppoli
estimate for b - a - vj(cf. [4,
Lemma2.16])
and Lemma 3.4 for uj - a, we obtain
Now it follows that
Since tij
- tiweakly (Remark 2.2),
we have thatthis concludes the
proof.
Now we are
ready
to prove Theorem 3.1.PROOF OF THEOREM 3.1. We may assume that xo = 0. Choose a radius
r > 0 such that B2r C Q. Let rj =
21-~ r and aj
= inf u. Thenusing
thepreceding BrJ
lemma we have
The desired estimate
follows,
sinceREMARK 3.6. The
proof
of Theorem 3.1 and theminimum principle imply:
if u is
A-superharmonic and u
= Tu in aneighbourhood
ofB(xo, 2r),
thenwhere
4. -
Upper
estimate when p > n - 1In this section we establish the
following
upper estimate if p > n - 1.THEOREM 4.1.
Suppose that
p > n - 1. Let u be anA-superharmonic function
in S2 and tz = Tu.If B(xo, ro)
C Q, thenhere c =
c(n, p)
> 0,and
then
u(xo) is finite.
We need the
concept
ofp-capacity.
If K is a compact subset of Q, letwhere the infimum is taken over all y~ E with y> > 1 on K. The
p-capacity
of a set E c 0. in Q is the number(see
e.g.[9]).
The
following
lemmacrucially
relies on the fact that p > n - 1. Its variants haveconstantly
been used in nonlinearpotential theory (see [12], [6],
and[7]).
For a
proof
see e.g. theproof
of Lemma 5.3 in[7].
LEMMA 4.3. For p > n - 1 there is a constant c =
c(n, p)
> 0 such thatif
E c
BR
withthen there is such that
LEMMA 4.4. Let u be an
A-superharmonic function
in an open setcontaining BR
and J-l = Tu.If
u M onSR, then for
all k > 0PROOF. Fix a
positive integer j
with andThen vj
is an admissible test function for Uj inBR
and we obtainSince vi
= 0 onSR
and anapproximation yields
The desired estimate follows since tij 2013~ ~
weakly
and henceThe next lemma is the essential
step
in theproof
of Theorem 4.1.LEMMA 4.5.
Suppose
that p > n - 1. Let u beA-superharmonic
in anI -. 1. 1
open set
containing BR and
J-t = Tu. Then there is a radius such thatif
then
here c =
c(n, p)
> 0.PROOF. Set
where co is the constant of Lemma 4.3. If
then Lemma 4.4
implies
appealing
to Lemma 4.3 we find a radiusSince
such that.
the lemma follows.
LEMMA 4.6.
Suppose
that rj is adecreasing
sequenceof
radii withfor
some constants C2 > c 1 > 1. Then there arepositive
constants C-1 = C-1(n,
p,c 1 )
and C2 =
c2(n,
p,C2)
such thatPROOF.
Obviously
we have thatwhere Hence
Similarly,
where c =
c(n,
p,C2)
and we arrive at the secondinequality
of the claim.Now we prove Theorem 4.1 and its
corollary.
PROOF OF THEOREM 4.1. There is no loss of
generality
inassuming
thatxo = 0.
Suppose
that u is bounded on thesphere SO. Using
Lemma 4.5 weconstruct
inductively
a sequence rj of radii such that forevery j
=0, 1,...
wehave -
and
Since u is lower
semicontinuous,
we conclude inlight
of Lemma 4.6 thatand the theorem is
proved.
PROOF OF THEOREM 4.2. We may
assume
that u isA-superharmonic
andnonnegative
in aneighbourhood
U ofB(xo, ro)
where ro > r. Let v be thebalayage
A
Then
ro)
is finite, sincer)
is. Hence becauseTheorem 4.1
implies
as desired.
REMARK 4.7. Our estimates
(Theorems
3.1 and4.1 )
can be used togive
apartial
answer to thefollowing question posed by
PeterLindqvist:
Given two
equations
of our type withmappings
.~ and A*.Suppose
that u isA-superharmonic
in Q. Does there exist anA*-superharmonic
function v such thatThe answer is affirmative at least if p > n - 1 and Q is bounded.
Indeed,
let/i = T u and let v be an
A-superharmonic
solution towith weak zero
boundary
values. ThenREFERENCENS
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measure data, J. Funct. Anal. 87 (1989), 149-169.
[2] R. GARIEPY - W.P. ZIEMER, A regularity condition at the boundary for solutions of quasilinear elliptic equations, Arch. Rational Mech. Anal. 67 (1977), 25-39.
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Department of Mathematics
University of Jyvaskyla
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