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Multidimensional renewal theory in the non-centered case. Application to strongly ergodic Markov chains.

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Submitted on 10 Jan 2012

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Multidimensional renewal theory in the non-centered case. Application to strongly ergodic Markov chains.

Denis Guibourg, Loïc Hervé

To cite this version:

Denis Guibourg, Loïc Hervé. Multidimensional renewal theory in the non-centered case. Application to strongly ergodic Markov chains.. Potential Analysis, Springer Verlag, 2013, 38 (2), pp.471-497.

�10.1007/s11118-012-9282-0�. �hal-00632893v2�

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Multidimensional renewal theory in the non-centered case.

Application to strongly ergodic Markov chains.

D. GUIBOURG and L. HERVÉ January 10, 2012

AMS subject classification : 60J10-60K05-47A55 Keywords : Fourier techniques, spectral method.

Abstract. Let(Sn)n≥0be aRd-valued random walk (d2). Using Babillot’s method [2], we give general conditions on the characteristic function ofSnunder which(Sn)n≥0satisfies the same renewal theorem as in the independent case (i.e. the same conclusion as in the case when the increments of(Sn)n≥0 are assumed to be independent and identically distributed). This statement is applied to additive functionals of strongly ergodic Markov chains under the non-lattice condition and (almost) optimal moment conditions.

1 Introduction

Let(Sn)n0 be a Rd-valued random walk. Renewal theory gives the behavior, askak →+∞, of the positive measuresUa(·) defined on the Borel σ-algebraB(Rd)of Rd as follows :

∀a∈Rd, ∀A∈B(Rd), Ua(A) =

+

X

n=1

E

1A(Sn−a)

. (1)

To define the renewal measureUa(·), the sequence(Sn)n0has to be transient: for independent or Markov random walks, this leads to consider the following cases:

1. d≥3 and E[S1] = 0 (centered case),

2. d ≥ 1 and E[S1] 6= 0 (non-centered case): in this case, the behavior of Ua(·) is specified whenkak →+∞ in the direction of E[S1].

The behavior ofUa(·) also depends on the usual lattice or non-lattice conditions.

This work is the continuation of [11] (case d = 1) and [13] (centered case in dimension d ≥ 3). More specifically, in this paper, we consider the non-centered case in dimension d≥2, and we present some general assumptions involving the characteristic function of Sn,

Université Européenne de Bretagne, I.R.M.A.R. (UMR-CNRS 6625), Institut National des Sciences Ap- pliquées de Rennes. Denis.Guibourg@ens.insa-rennes.fr, Loic.Herve@insa-rennes.fr

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under which we have the same conclusion as in the classical renewal theorem for random walks with independent and identically distributed (i.i.d.) increments. By using the weak spectral method [14], this result is then applied to additive functionals of strongly ergodic Markov chains. This work is greatly inspired by Babillot’s paper [2]. Before presenting our results, we give a brief review of well-known multidimensional renewal theorems in both independent and Markov settings, as well as some general comments on Fourier’s method. To that effect we introduce some notations which will be repeatedly used afterwards:

- h·,·i is the canonical scalar product onRd, - k · k is the associated euclidean norm onRd, - Ld(·) is the Lebesgue-measure on Rd,

- Cc(Rd,C)is the set of complex-valued continuous compactly supported functions on Rd, - the Fourier transform of any Lebesgue-integrable functionf :Rd→Cis defined as follows:

∀t∈Rd, f(t) :=ˆ Ld(eiht,·if),

- H is the set of complex-valued continuous Lebesgue-integrable functions on Rd, whose Fourier transform is compactly supported and infinitely differentiable onRd,

- for anyR >0, we denote by BR:=B(0, R) the open ball: B(0, R) :={t∈Rd:ktk< R}, - for any 0< r < b, we denote byKr,b the annulusKr,b :={t∈Rd:r <ktk< b}.

Renewal theory for random walks with i.i.d. non-centered increments.

Let(Xn)n1 be a sequence of i.i.d. non-centered random variables (r.v) taking values inRd, and let Sn =X1+. . .+Xn. In dimension d≥2, the renewal theorem was first established by Ney and Spitzer [19] in the lattice case. Extension to the non-lattice case was obtained by Doney [6] under Cramer’s condition, and by Stam [23] under the weaker non-lattice condition.

Setting md:= max(d21,2), Stam’s statement writes as follows:

E

kX1kmd

<∞, ~m:=E[X1]6= 0 ⇒ ∀g∈ Cc(Rd,R), lim

τ+τd−12 Uτ ~m(g) =C Ld(g) (2) where C is a positive constant depending on the first and second moments of X1. In the lattice case, Property (2) still holds, butLd(·) must be replaced with the product of counting and Lebesgue measures both defined on some sublattices of Rd. Stam’s proof is based on the local limit theorem (LLT) due to Spitzer [22, Th. P7.10]1. More precisely, this LLT is applied to study the difference

P+

n=1n(d1)/2 E[g(Sn−a)]−E[g(Tn−a)]

,

where the r.v.Tn are defined as the partial sums of a i.i.d. sequence of Gaussian r.v. having the same first and second moments as X1. Then (2) is deduced from the Gaussian case.

Fourier techniques in renewal theory (Breiman’s method).

The weak convergence in (2) can be established by investigating the behavior of Ua(h) for h∈ H. In fact the inverse Fourier formula gives (without any assumption on the model):

∀h∈ H, E

h(Sn−a)

= (2π)dR

Rdˆh(t)E[eiht,Sni]eiht,aidt. (3) This is the starting point of Fourier’s method in probability theory. In the i.i.d. case, using (3) and the formula E[eiht,Sni] = E[eiht,X1i]n, the potential Ua(h) given by (1) is equal to the

1This LLT, established by Fourier techniques, extends tod2the one-dimensional result of [21].

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following integral:

Ua(h) =I(a) := (2π)dR

Kˆh(t)1φ(t)φ(t)eiht,aidt with φ(t) =E[eiht,X1i], (4) where K is the support of ˆh. More precisely, since E[X1] 6= 0 and d ≥ 2, the integrand in I(a) is integrable at 0. Thus I(a) is well-defined provided that |φ(t)|<1 for all t6= 0: this is the non-lattice condition. Fourier’s method also applies to the lattice case by considering a periodic summation in (4). The renewal theorem then follows from the study of the integrals I(τ ~m) when τ→+∞. This method, introduced by Breiman [4] in dimension d = 1, was extended tod≥2by Babillot [2] in the general setting of Markov random walks (see below).

Renewal theory for Markov random walks.

Let (E,E) denote a measurable space, and let (Xn, Sn)nN be an E ×Rd-valued Markov random walk (MRW), namely: (Xn, Sn)nN is a Markov chain and its transition kernel P satisfies the following additive property (in the second component):

∀(x, s)∈E×Rd, ∀A∈ E, ∀B ∈B(Rd), P (x, s), A×B

=P (x,0), A×(B−s) . (5) As usual we setS0 = 0. When (Xn)n0 is strongly ergodic and S1 is non-centered, Babillot gives in [2] some (operator-type) moment and non-lattice conditions for the additive compo- nent(Sn)nto satisfy the renewal conclusion in (2). Recall that the strong ergodicity condition states that the transition kernelQof(Xn)n0 admits an invariant probability measureπ, and that there exists a Banach space (B,k · kB), composed of π-integrable functions on E and containing the function 1E, such that π defines a continuous linear form on Band

nlim+ sup

f∈B,kfk≤1kQnf −π(f)1EkB = 0. (6) The proof in [2] is based on Fourier techniques and the usual Nagaev-Guivarc’h spectral method involving the semi-group of Fourier operators associated with(Xn, Sn)nN, namely:

∀n∈N, ∀t∈Rd, ∀x∈E, Qn(t)f

(x) :=E(x,0)

eiht,Snif(Xn) ,

where E(x,0) denotes the expectation under the initial distribution (X0, S0) ∼ δ(x,0). The operators Qn(t)act (for instance) on the space of bounded measurable functions f :E →C. The semi-group property writes as follows: ∀(m, n) ∈ N2, Qm+n(t) = Qm(t)◦Qn(t). In particular we haveQn(t) =Q1(t)n. This property is the substitute for MRWs of the formula E[eiht,Sni] =E[eiht,X1i]n of the i.i.d. case.

The content of the paper.

Section 2 focuses on Fourier’s method. More specifically we consider a general sequence (Xn, Sn)nN (not necessarily a MRW) of random variables taking values in E×Rd. In sub- stance our non-centered condition writes as follows: m~ := limnE[Sn]/n exists in Rd and is nonzero. Let f :E→[0,+∞) be such that E[f(Xn)]<∞ for every n≥1. Under a general hypothesis, calledR(m), on the functionst7→E

f(Xn)eiht,Sni

, Theorem 1 states that there exists some positive constantC (specified later) such that we have

∀g∈ Cc(Rd,R), τd−12

+

X

n=1

E

f(Xn)g(Sn−a)

−→C Ld(g)

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when a:=a(τ) ∈Rd goes to infinity "around the direction m" in the sense (specified later)~ defined in [24] (for instance, takea:=τ ~m withτ→+∞). Actually Hypothesis R(m), intro- duced in [13] (centered case), contains the tailor-made conditions to prove renewal theorems via Fourier’s method. The proof of Theorem 1 borrows the lines of [2] with the following improvements. First, the distribution-type arguments and the modified Bessel functions used in [2] are replaced with elementary computations. Second, the (asymmetric) dyadic decom- position, partially developed in [2, 1] to study integrals of type (4), is detailed in this work.

Section 3 is devoted to the Markov context. Specifically, we assume that (Xn)nN is a Markov chain satisfying one of the three following classical strong ergodicity assumptions:

- (Xn)n0 isρ-mixing (see [20]),

- (Xn)n0 isV-geometrically ergodic (see [18]),

- (Xn)n0 is a strictly contractive Lipschitz iterative model (see [7]).

Letξbe aRd-valued measurable function, and letSn=ξ(X1)+. . .+ξ(Xn). Then the sequence (Xn, Sn)nNis a special instance of MRW. As already used in [13], the weak spectral method [14] allows us to reduce Hypothesis R(m) to a non-lattice condition and to some (almost) optimal moment conditions on ξ, which are much weaker than those in [2].

Theorem 1 should supply further interesting applications, not only in Markov models but also in dynamical systems associated with quasi-compact Perron-Frobenius operators. On that subject, recall that the renewal theorems yield the asymptotic behavior of counting functions arising in the geometry of groups, as already developed for instance in [17, 5, 24].

2 Renewal theory in the non-centered case (Fourier method)

For any A⊂Rd,g:A→C, andτ ∈(0,1], we define the following quantities in[0,+∞]:

g

0,A= sup

xA|g(x)| and g

τ,A := sup|g(x)−g(y)|

kx−ykτ , (x, y)∈A2, x6=y .

We say that g is τ-Hölder on A if [g]τ,A <∞. Moreover, for any open subsetO of Rd and every m ∈ N, we denote by Cmb (O,C) the vector space composed of m-times continuously differentiable functionsf :O →Cwith bounded partial derivatives onO. Ifm∈(0,+∞)\N, we set τ := m− ⌊m⌋ where ⌊m⌋ is the integer part of m, and we denote by Cmb (O,C) the vector space composed of functions f :O →Csatisfying the three following conditions:

f is⌊m⌋-times continuously differentiable onO,

Each partial derivative of order j= 0, . . . ,⌊m⌋ of f is bounded onO, Each partial derivative of order ⌊m⌋ of f is τ-hölder on O.

Define∇f := (∂x∂f

i)1id if m≥1, and Hess f := (∂x2f

i∂xj)1i,jd (Hessian matrix) if m≥2.

Let (Ω,F,P) be a probability space. We denote by (E,E) a measurable space, and we consider a sequence(Xn, Sn)n0ofE×Rd-valued random variables defined onΩ. Throughout, we assumed≥2.

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HypothesisR(m). Givenm∈[2,+∞)andf :E→[0,+∞)a measurable function satisfying

∀n≥1, E[f(Xn)]<∞, (7) we say that Hypothesis R(m) holds if the following conditions are fulfilled:

(i) There exists R >0 such that, for allt∈BR and alln≥1, we have:

E

f(Xn)eiht,Sni

=λ(t)nL(t) +Rn(t), (8) whereλ(0) = 1, the functionsλ(·)andL(·)are inCmb BR,C

, and the seriesP

n1Rn(·) uniformly converges on the open ball BR and defines a function inCmb BR,C

. (ii) For all 0< r < b, the series P

n1E

f(Xn)ei,Sni

uniformly converges on the annulus Kr,b and defines a function in Cmb Kr,b,C

. Under HypothesisR(m), we set

~

m:=−i∇λ(0) and Σ :=−Hess λ(0).

Below we assume that m~ 6= 0: this is our non-centered condition. In fact, under Hypoth- esis R(m) and additional mild conditions (see [13, Prop. 1]), we have m~ = limnE[Sn]/n, so that m~ may be viewed as a nonzero mean vector in Rd. Below we also assume that the symmetric matrix Σ is positive-definite. In the Markov setting of Section 3, Σ is linked to some covariance matrix, see (36).

Hypothesis (H). Setting md := max(d21,2), there exists a real number m > md such that Hypothesis R(m) holds. We haveL(0)6= 0, m~ 6= 0, and Σ :=−Hess λ(0)is positive-definite.

Theorem 1 Assume that Hypothesis(H) holds. Then, for each function a : [0,+∞)→ Rd such that

A:= lim

τ+

a(τ)−τ ~m

√τ exists in Rd, (9)

the family{Vτ(·), τ ∈(0,+∞)} of positive measures on Rd defined by

∀A∈B(Rd), Vτ(A) := (2πτ)d−12

+

X

n=1

E

f(Xn) 1A(Sn−a(τ))

(10) weakly converges to C Ld(·) as τ →+∞, where C:=C(L, ~m,Σ,A)∈(0,+∞) is given by:

C(L, ~m,Σ,A) := L(0) detS kS ~mk exp

S ~m, SA2

− kS ~mk2kSAk2 2kS ~mk2

with S:= Σ12. Condition (9), introduced in [24], specifies what we called "around the direction m" in~ Introduction. Obviouslya(τ) =τ ~m satisfies (9).

Remark 1 Theorem 1 may be extended to the lattice case: Hypothesis R(m)(ii) must be adapted, and Ld(·) is replaced with the product of the counting measure and the Lebesgue measure both associated with some sublattices of Rd, see [12, Sect. 2.5].

The next subsections are devoted to the proof of Theorem 1.

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2.1 Some reductions and Fourier techniques

Change of coordinates. Let ~e1 denote the first vector of the canonical basis of Rd, and let T be any isometric linear map in Rd such that T(m) =~ km~k~e1. Up to replace Sn with T Sn, one may assume without loss of generality that m~ = km~k~e1. This leads to replace λ(·), L(·), Rn(·), h(·),Σ with λ◦T1, L◦T1, Rn◦T1, h◦T1, T ◦Σ◦T1.

The function w. For all x = (x1, x2, . . . , xd) ∈Rd, we set x := (x2, . . . , xd) ∈ Rd1. The following functionw(·) will play an important role:

∀x∈Rd, w(x) =−ix1+kxk2. (11) Remark 2 We have: ∀x∈Rd, |w(x)| ≥ |x1|3/4kxk1/2. Thus 1/w is integrable at 0.

Remark 3 Some simple facts on the functionλ(·)of (8) can be deduced from Hypothesis(H).

First, since md≥2, we have

λ(t) = 1 +ikm~kt112hΣt, ti+o(ktk2). (12) Second, since L(·) is continuous onBR andL(0)6= 0, one may suppose (up to reduce R) that we have: ∀t∈BR, L(t)6= 0. By HypothesisR(m)(ii), the last property then implies that, for all t∈BR\ {0}, the seriesP

n1λ(t)n converges. Hence:

∀t∈BR\ {0}, |λ(t)|<1.

Third the function v0(·) := 1−λ(·) is in Cmb BR,C), and thanks to−i∇λ(0) =m~ =km~k~e1, we have

∀j∈ {2, . . . , d}, ∂v0

∂xj(0) = 0.

Finally, up to reduceR, we deduce from (12) that there exist positive constantsα, βsuch that:

∀t∈BR, α|w(t)| ≤ |v0(t)| ≤β|w(t)|.

Use of the space H. Thanks to the well-known results on weak convergence of positive measures (see [4]), Theorem 1 will hold provided that we prove the following property:

∀h∈ H, lim

τ+(2πτ)d−12

+

X

n=1

E

f(Xn)h(Sn−a(τ))

=C(L, ~m,Σ,A) Z

Rd

h(x)dx. (13)

Integral decomposition. Leth∈ H be fixed and letb >0 such thatˆh(t) = 0 when ktk> b.

Next consider any real numberρsuch that0< ρ <min(R, b)and any functionχ∈ Cb (Rd,R) compactly supported in BR such that χ(t) = 1 when ktk ≤ ρ. For each t ∈ Rd we set En(t) :=E[f(Xn)eiht,Sni]. The inverse Fourier formula gives

(2π)dE

f(Xn)h(Sn−a)

= Z

Rd

h(t)ˆ En(t)eiht,aidt.

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Under Hypothesis(H), we prove below that, for every a∈Rd, the following series I(a) := (2π)d

+

X

n=1

E

f(Xn)h(Sn−a)

converges, and that I(a) decomposes as the sum of three integrals called E(a), E1(a) and I1(a). The integrals E(a) and E1(a) are error terms, whileI1(a) is the main part ofI(a). In fact we have

I(a) =E(a) + Z

BR

χ(t) ˆh(t) λ(t)

1−λ(t)L(t))eiht,aidt (14) with

E(a) :=

Z

Rd

h(t)ˆ

1BR(t)χ(t)X

n1

Rn(t) + 1Kρ,b(t) 1−χ(t) X

n1

En(t)

eiht,aidt.

Next we obtain

I(a) =E(a) +E1(a) +I1(a) (15)

with

E1(a) :=

Z

ktk≤R

χ(t)ˆh(t)λ(t)L(t)−h(0)ˆ L(0)

1−λ(t) eiht,aidt + ˆh(0)L(0)

Z

ktk≤R

χ(t) λ(t)−1−ikm~kt1+12hΣt, ti

(1−λ(t))(−ikm~kt1+ 12hΣt, ti)eiht,aidt (16) and

I1(a) := ˆh(0)L(0) Z

ktk≤R

χ(t)

−ikm~kt1+12hΣt, tieiht,aidt.

Such equalities are established in [13, p. 389] (centered case). By using Hypothesis (H), the proof of (14) borrows the same lines. To obtain (15), use the fact that forktk ≤R,t6= 0, we have|PN

n=1λ(t)n| ≤2/(b|w(t)|), and the fact that1/wis integrable at 0 (cf. Remarks 2-3).

Property (13) then follows from (15) and the next properties (17) (18) and (23).

2.2 Study of the first error term E(a)

Here we prove that we have whenkak →+∞:

E(a) =o(kakd−12 ). (17)

Foru∈ Cmb (Rd,C) andα= (α1, . . . , αd)∈Nd such that |α|:=Pd

i=1αi ≤ ⌊m⌋, we denote by

α the derivative operator defined by :

α:= ∂|α|

∂xα11. . . ∂xαdd =∂1α1. . . ∂dαd where ∂j := ∂

∂xj. The following proposition is classical. Let O be a bounded open subset of Rd.

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Proposition 1 Let m ∈ (0,+∞) and τ = m − ⌊m⌋. Assume that u is a function in Cbm(Rd,C) compactly supported in O and that its restriction to O is in Cmb (O,C). Then the following properties hold:

(i) u∈ Cmb (Rd,C), and forα∈Nd,|α|=⌊m⌋, we have: [∂αu]τ,Rd = [∂αu]τ,O= [∂αu]τ,O (ii) ∃C∈(0,+∞), ∀a∈Rd, kakm|u(a)ˆ | ≤C kuk0,Rd+P

|α|=m[∂αu]τ,Rd

.

Proof of (17). Define:

∀t∈BR, R(t) :=

+

X

n=1

Rn(t) and ∀t∈Rd\ {0}, E(t) :=

+

X

n=1

En(t),

∀t∈Rd, F(t) := 1BR(t) ˆh(t)χ(t)R(t) and G(t) :=

( 1Kρ,b(t) ˆh(t) (1−χ(t))E(t) ift6= 0 0 if t= 0.

We have

∀a∈Rd, E(a) = ˆF(a) + ˆG(a).

Note that χˆh ∈ Cc (Rd,C) is compactly supported in the closed ball BR, and that, by Hypothesis (H), we have R ∈ Cmb (BR,C) with m > md. By applying Proposition 1 to u := F, we obtain kakm|F(a)ˆ | = O(1), thus Fˆ(a) = o(kak(d1)/2) when kak →+∞ since m >(d−1)/2. The same result holds for G(a)ˆ (replace BR withKρ,b).

2.3 Study of the second error term E1(a)

In this subsection we prove that we have when kak →+∞:

E1(a) =o(kak(d1)/2). (18) LetE11(a)andE12(a)denote the two integrals in the right hand side of (16), so that we have:

E1(a) :=E11(a) +E12(a). Define: ∀t∈BR, θ1(t) =χ(t) ˆh(t)λ(t)L(t)−ˆh(0)L(0) . Then E11(a) =qb1(a) with q1:= 1BRθ1/v0, (19) where v0(t) = 1−λ(t). Next define: ∀t ∈ BR, θ2(t) := χ(t) λ(t)−1−ikm~kt1+ 12hΣt, ti and ˜v0(t) :=−ikm~kt1+12hΣt, ti. Then

E12(a) =qb2(a) with q2 := 1BRθ2/(v00). (20) Unfortunately, since q1 and q2 are not defined at 0, qb1(a) and qb2(a) cannot be studied by the elementary arguments of Subsection 2.2. This fact constitutes the main difficulty of the proof in [2]. Below, we present the two key results (Propositions 2 and 3) to obtain (18). In the next subsection, these two propositions are also used to obtain the desired result for the main part I1(a) (by difference with the Gaussian case, see Lemma 1).

Recall thatw(·)is defined in (11). In the two next propositions, we consider any real numbers m > mdand r >0.

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Proposition 2 Letθ and v be complex-valued functions on Br such that:

θ∈ Cmb Br,C

with compact support inBr and θ(0) = 0,

v∈ Cmb Br,C and

∀j∈ {2, . . . , d},(∂jv)(0) = 0 (21)

∃(a, b)∈(R+)2, ∀x∈Br, a|w(x)| ≤ |v(x)| ≤b|w(x)|. (22) Then q := 1Brθ/v is integrable onRd and limkak→+kak(d1)/2q(a) = 0.ˆ

Proposition 3 In addition to the hypotheses of Proposition 2, we consider another complex- valued functionv˜ on Br satisfying the same hypotheses as v(·). Moreover we assume that all the first and second partial derivatives of θvanish at 0. Thenq := 1Brθ/(vv)˜ is integrable on Rd andlimkak→+kak(d1)/2q(a) = 0.ˆ

The proofs of Propositions 2-3, based on dyadic decompositions, are partially presented in [1, 2]. Since dyadic decomposition is not familiar to probabilistic readers, these proofs are detailed in Appendix A for the sake of completeness.

Proof of (18). Proposition 2 applied with θ := θ1 and v := v0 (see Rk. 3) gives qb1(a) = o(kak(d1)/2) when kak → +∞. Similarly Proposition 3 applied with θ :=θ2, v := v0 and

˜

v:= ˜v0 gives qb2(a) =o(kak(d1)/2). Then (18) follows from (19) (20).

2.4 Study of the main part I1(a) of I(a)

Leta:R+→Rd be a measurable function satisfying (9). Here we prove that

limτ+τ(d1)/2I1(a(τ)) = (2π)(d+1)/2C(L, ~m,Σ,A) ˆh(0). (23) The proof of (23) in [2] involves the modified Bessel functions and some related computations partially made in the book [26]. Here we present a direct and simpler proof of (23) based on the next proposition. We denote byS(Rd) the so-called Schwartz space.

Proposition 4 Let w~ ∈ Rd\ {0}, and let p : R+ → Rd such that P := limτ+p(τ)/√ τ exists inRd. Then we have for all function k∈S(Rd)

τlim+τd−12 Z

Rd

k(u)eihu,τ ~w+p(τ)i

−ihw, u~ i+kuk2 du= 2πd+12

kw~k k(0) exp

−kPk2kw~k2− hP, ~wi2 4kw~k2

.

The proof of Proposition 4 (again based on Propositions 2-3) is presented below. Let us first apply Proposition 4 to establish (23).

Proof of (23). Since m~ =km~ke~1, one can rewrite (9) as follows: a(τ) = τkm~ke~1+√ τb(τ) with b : [0,+∞) → Rd such that limτ+b(τ) = A. Denote by λ1, . . . , λd the (positive) eigenvalues of Σ. Let ∆ := diag(√

λ1, . . . ,√

λd) and let P be any orthogonal d×d-matrix such that

P1ΣP = ∆2 = diag(λ1, . . . , λd).

(11)

Observe that hΣt, ti = h∆2P1t, P1ti = k∆P1tk2. Set ~ℓ := ∆1P1e~1. By using the variable t=P∆1u, one obtains (use t1=hP∆1u, ~e1i=hu, ~ℓi)

I1(a) = 2ˆh(0)L(0) (det ∆)1

Z χ(P∆1u)eih−1u,P−1ai

−ih2km~k~ℓ, ui+kuk2 du.

Setζ(x) :=χ(P∆1x) (x∈Rd) and p(τ) :=√

2τ∆1P1b(2τ) (τ >0). From the equality h∆1u, P1e~1i=hu, ~ℓi, it follows that

I1(a(τ)) = 2ˆh(0)L(0) (det ∆)1

Z χ(P∆1u)ei

−1u , P−1 τkm~ke~1+τb(τ)

−ih2km~k~ℓ, ui+kuk2 du

= 2ˆh(0)L(0) (det ∆)1

Z ζ(u)ei

u ,2(τ2)km~k~ℓ+p(τ2)

−ih2km~k~ℓ, ui+kuk2 du.

Now ∆1 = P1Σ12P gives ~ℓ = P1Σ12e~1, so k~ℓk = kΣ12e~1k and kΣ12m~k = km~kk~ℓk. Moreover, we haveζ(0) =χ(0) = 1and

τlim+p(τ)/√

τ =P with P:=√

2 ∆1P1A=√

2P1Σ12 A.

From Proposition 4, applied with P previously defined, w~ := 2km~k~ℓ = 2P1Σ12m, and~ finally with the function k:=ζ, one obtains:

τlim+

2)d−12 I1(a(τ)) = 2ˆh(0)L(0) (det Σ)12d+12 2kΣ12m~k

× exp

−kΣ12m~k212Ak2− hΣ12m,~ Σ12Ai2 2kΣ12m~k2

,

from which we easily deduce (23).

Proof of Proposition 4. Let U be an isometric linear map on Rd such that U(w) =~ kw~ke~1. Letτ >0. The change of variable v= (v1, v) =U(u) in the integral of Proposition 4 gives

Z

Rd

k(u)eihu,τ ~w+p(τ)i

−ihw, u~ i+kuk2 du= Z

Rd

k(U1(v))ekw~kv1eihv,U(p(τ))i

−ikw~kv1+kvk2 dv, and by hypothesis we know that limτ+U(p(τ))/√

τ = U(P). Set U(P) := (ℓ1, ℓ) with ℓ1 ∈ R et ℓ ∈ Rd1. As U is isometric, we have kU(P)k = kPk and ℓ1 = hU(P), ~e1i = hP, U1(e~1)i=hP, ~wi/kw~k. Thus

kℓk2=kPk2− hP, ~wi2/kw~k2 = kw~k2kPk2− hP, ~wi2 /kw~k2.

Next, let us setU(p(τ)) :=u(τ) = (u1(τ),· · ·,ud(τ)), and u(τ) = (u2(τ),· · · ,ud(τ)). Then Z

Rd

k(u)eihu,τ ~w+p(τ)i

−ihw, u~ i+kuk2 du= Z

Rd

k(U1(v))ei(τkw~k+u1(τ))v1eihu(τ),vi

−ikw~kv1+kvk2 dv.

(12)

Observe that the functionk◦U1 is in S(Rd) and that

τlim+u1(τ)/τ = 0 and lim

τ+u(τ)/√

τ =ℓ. (24)

Consequently Proposition 4 will be established if we prove that, for any µ∈ R, µ6= 0, and any h∈S(Rd), we have:

τlim+τ(d1)/2 Z

Rd

h(v)ei(τ µ+u1(τ))v1eihu(τ),vi

−iµv1+kvk2 dv = 2π(d+1)/2e−kk2/4

|µ| h(0). (25) Lemma 1 Property (25) holds withh(v) =H(v) :=e2v21+kvk4)/2, namely:

Jµ(τ) :=

Z

Rd

e2v21+kvk4)/2ei(τ µ+u1(τ))v1eihu(τ),vi

−iµv1+kvk2 dv ∼τ+

(d+1)/2e−kk2/4

|µ|τ(d1)/2 . (26) Let us first assume that Lemma 1 is valid, and let us deduce (25) from (26). To that effect, we shall proceed by difference and use Propositions 2 and 3. For anyτ >0, we define d(τ) := (τ µ+u1(τ),u(τ)). Moreover we set

∀v∈Rd\ {0}, ∆(v) := h(v)−h(0)H(v)

−iµv1+kvk2 −h(0) v12H(v)

(−iµv1+kvk2)(−iµv1+kvk2). (27) We have:

Z

Rd

h(v)ei(τ µ+u1(τ))v1eihu(τ),vi

−iµv1+kvk2 dv−h(0)Jµ(τ) = Z

Rd

ei(τ µ+u1))v1eihu),vi∆(v)dv

= Z

Rd

eihd(τ), vi∆(v)dv.

Thanks to (26), Property (25) will be established provided that we prove the following:

τlim+τd−12 Z

Rd

eihd(τ), vi∆(v)dv = 0. (28)

Let us consider the functions G1 and G2 in S(Rd) defined by G1(v) = h(v)−h(0)H(v) and G2(v) =v21H(v). One can easily check that G1(0) =G2(0) = 0, and

∀j∈ {1, . . . , d}, (∂jG2)(0) = 0 and (∂12G2)(0) = 2,

∀(j, ℓ)∈ {1, . . . , d}2\ {(1,1)}, (∂jℓ2 G2)(0) = 0.

with∂jℓ2 := ∂x2

j∂x. Next, letg∈S(Rd) such that g(0) =−1/µ2, and define

∀v= (v1, . . . , vd)∈Rd, s(v) := −iµv1+kvk2

−iµv1+kvk2 g(v),

where v = (v2, . . . , vd). One can easily check that s(0) = 0, ∀j ∈ {1, . . . , d}, (∂js)(0) = 0, (∂12s)(0) = −2µ2g(0) = 2 and ∀(j, l) ∈ {1, . . . , d}2\ {(1,1)}, (∂j l2 s)(0) = 0. Therefore the first and second derivatives of the difference G3:=G2−svanish at 0. Rewrite∆(v)as:

∀v∈Rd\ {0}, ∆(v) = G1(v)

−iµv1+kvk2 − h(0) G3(v)

(−iµv1+kvk2)(−iµv1+kvk2) − h(0)g(v).

(13)

Letγ ∈ Cb (Rd,[0,1]) be compactly supported and such thatγ|B = 1for some closed ball B ofRd centered at 0. Since γgc∈S(Rd) and limτ+kd(τ)k= +∞, we have

τlim+kd(τ)kd−12 Z

Rd

eihd(τ), viγ(v)g(v)dv = 0.

Moreover Propositions 2 and 3 yield the following properties:

τlim+kd(τ)k(d1)/2 Z

Rd

eihd(τ), vi γ(v)G1(v)

−iµv1+kvk2 dv = 0,

τlim+kd(τ)k(d1)/2 Z

Rd

eihd(τ), vi γ(v)G3(v)

(−iµv1+kvk2)(−iµv1+kvk2)dv = 0.

Note that we have kd(τ)k ∼τ+|µ|τ fromd(τ) = (τ µ+u1(τ),u(τ)) and (24). Hence:

τlim+τ(d1)/2 Z

Rd

eihv,d(τ)iγ(v) ∆(v)dv = 0. (31) Now observe that all the derivatives of γ(·) are bounded on Rd and that ∆ is defined on Rd\ {0} as the quotient of a function of S(Rd) by a polynomial function (cf. (27)). Since 1−γ(·) vanishes on the closed ball B (centered at 0), we deduce that (1−γ)∆∈S(Rd). So the Fourier transform of(1−γ)∆ is inS(Rd)and we have

τlim+τ(d1)/2 Z

Rd

eihd(τ), vi(1−γ(v))∆(v)dv = 0. (32) Hence (28) follows from (31) and (32). As already mentioned, we have (28)⇒ (25), so that

Proposition 4 is proved.

Proof of Lemma 1. It suffices to prove Lemma 1 in caseµ= 1(if not, setw1 =µv1, w =v).

Since R+

0 v13/4ev21/2dv1 < ∞ and R

Rd−1kvk1/2e−kvk4/2dv < ∞ (use 12 < d−1 for the second integral), it follows from the Fubini-Tonelli theorem thatR

Rd

e−(v1 +2 kv′k4)/2

|−iv1+kvk2| dv <∞ (cf. Rk. 2). Next we have:

∀n∈N, ∀b∈Rn, (2π)n/2R

Rne−kxk2/2eihx,bidx=e−kbk2/2 (33a)

∀v 6= 0, R+

0 e(iv1−kvk2)udu= iv 1

1+kvk2. (33b)

From (33b), Fubini’s theorem and(33a), it follows that J1(τ) =

Z

Rd−1

eihu(τ),vie−kvk4/2 Z

R

ei(τ+u1(τ))v1ev12/2

−iv1+kvk2 dv1

! dv

= Z

Rd−1

eihu(τ),vie−kvk4/2

Z + 0

e−kvk2u Z

R

ei(τ+u1(τ)u)v1ev21/2dv1 du

dv

= √

2π Z

Rd−1

eihu(τ),vie−kvk4/2

Z + 0

e−kvk2ue(τ+u1(τ)u)2/2du

dv.

By using the following obvious equality kvk2u+ τ+u1(τ)−u2

/2 = 1 2

u+kvk2−(τ +u1(τ))2

− kvk4+ 2 τ +u1(τ) kvk2

,

(14)

and by setting y =p

2(τ +u1(τ))v (forτ large enough), we obtain:

J1(τ)/√ 2π =

Z

Rd−1

eihu(τ),vie(τ+u1(τ))kvk2

Z + 0

e12

u+kvk2(τ+u1(τ))2

du

dv

= Z

Rd−1

eihu(τ),vie(τ+u1(τ))kvk2

Z +

kvk2(τ+u1(τ))

ex22dx

! dv

= 2(τ +u1(τ)d−12 Z ×

Rd−1eih

u′(τ)

2(τ+u

1(τ)),yi −ky′k2 2 Z +

|y′|2

2(τ+u1(τ))(τ+u1(τ))

ex

2 2 dx

! dy.

Finally, sinceτ +u1(τ)∼τ+τ by (24), Lebesgue’s theorem and (33a) give

τlim+τ(d1)/2J1(τ) = √

2π2(d1)/2 Z

Rd−1

eih

2,yieky′k

2 2

Z +

−∞

ex

2 2 dx

dy

= √

2π2(d1)/2√ 2π(√

2π)d1e−kk2/4

= 2π(d+1)/2e−kk2/4.

Hence the desired property for J1(τ).

3 Applications to additive functionals of Markov chains

In this section, (Xn)n0 denotes a Markov chain with state space (E,E), transition kernel Q(x, dy) and initial distribution µ. We assume that Q admits an invariant probability mea- sure, denoted byπ. We denote byPµ the probability distribution of (Xn)n0 with respect to the initial distribution µ. The associated expectation is denoted by Eµ. Finally we consider a measurable functionξ :E→Rd and we define the associated additive functional:

∀n≥1, Sn=ξ(X1) +· · ·+ξ(Xn). (34) The next moment conditions onξ will ensure thatξ is π-integrable. We can then define the first moment vectorm~ ofξ w.r.t. toπ. We assume thatm~ is nonzero, that is

~

m=Eπ[ξ(X0)] =R

Eξ dπ 6= 0. (35)

Setξc:=ξ−m, and for each~ n≥1 define the following random variable, taking values in the set of nonnegative symmetricd×d-matrices:

Sn,c2 =Pn

k,ℓ=1ξc(Xkc(X),

where stands for the transposition. The next conditions on ξ will also enable us to define the following nonnegative symmetricd×d-matrix:

Σ =m~ ·m~+ lim

n

1

nEµ[Sn,c2]. (36)

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