C OMPOSITIO M ATHEMATICA
C. T. C. W ALL
On the classification of hermitian forms. I.
Rings of algebraic integers
Compositio Mathematica, tome 22, n
o4 (1970), p. 425-451
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425
ON THE CLASSIFICATION OF HERMITIAN FORMS
I. RINGS OF ALGEBRAIC INTEGERS by
C. T. C. Wall Wolters-Noordhoff Publishing
Printed in the Netherlands
In a recent paper
[10],
1 gave an account of definitions of ’reflexive’and
’quadratic’
forms in afairly general situation,
bothgeneralising
theclassical notion of hermitian forms. In this paper 1
apply
standard number theoretictechniques
toclassify nonsingular quadratic
forms onprojective,
and
especially
on freemodules,
overrings
R ofalgebraic integers,
cor-responding
to some non-trivialinvolution
a of R. If thequadratic
fieldextension
corresponding
to a is at mosttamely ramified,
there is nodistinction in this case between
quadratic
and hermitian forms. In thewildly
ramified case,however, nonsingular
hermitian forms are muchharder to
classify;
since 1 am not interested in them forapplications,
wewill not consider them further here.
To a
large
extent, this paper is are-working
of results of Shimura[9].
1 feel that a new account is
justified by
the differentemphasis:
Shimuraconsidered the
general theory (in particular,
heproved
thestrong
approx- imationtheory
for SU while wemerely quote it),
andexemplified
itby considering
maximal lattices. Our concern isexclusively
with modularlattices,
which enables us to consider also fine details.In a later paper 1 intend to
apply
thetechniques
of this one tostudy
forms over
arbitrary ’global rings’ (orders
in finitesemisimple algebras
over
Q) :
the main result below for local structure will cover what is needed for this extension.Statement of results
For
nonsingular (a, u)-quadratic
forms on R-modulesM,
with r thefixed
subring
of a, we have thefollowing
invariants:1)
Thesignatures
at realplaces
of r whichramify
in R.2)
The discriminant withrespect
to a free base of M(if
M isonly projective,
this canonly
be definedlocally).
3)
Fordyadic
ramifiedprimes
p of r, the Arf invariant of the induced formon Fp
=r/p.
4)
If M has apreferred base,
andQ
is aquotient
of R with a trivialand u = -1 on
Q,
the determinant x of achange
from thegiven
baseover
Q
to asymplectic
base.We determine which values the invariants can
take,
and the relations between them. If the invariants1), 2)
and3)
are trivial(and
the form ofrank >
2, indefinite),
we show that the form ishyperbolic; however,
notnecessarily
on a free module. The structure of the Witt group of formson
projective, free,
or free and based modules isdetermined,
modulo the structure of the groups of units. We also establish cancellation andstability
theorems.Crucial for the local
theory
is a result which reduces the classificationproblem
over the localrings
R to aproblem
on the residue class fields.For the detailed local
theory,
there is aninteresting
distinction between’bad’ and
’good’ primes, according
as u is or is notequivalent
in anappropriate
sense to -1: this isimportant
for theglobal theory.
Lifting
forms tocomplète rings
For the benefit of readers unfamiliar with
[10],
webriefly recapitulate
the main definitions. A is a
ring (with unit),
a ananti-automorphism
ofA and u a unit of A such that
For
M,
N(right) A-modules,
a mapis
a-sesquilinear
ifWe write
Sa(M)
for the(additive)
group ofa-sesquilinear
maps M M ~ A. Defineby
Then the
( a, u)-reflexive
maps are the elements ofR(03B1,u)(M)
= Ker(Tu-1),
and the( a, u)-quadratic
maps the elements ofQ(rx,u)(M) =
Coker
(Tu-1).
Multiplication by Tu+1
induces a map(bilinearisation)
b :Q(03B1,u)(M)
-
R(03B1,u)(M). Arguing
as in theproof
of[10,
Theorem1],
we find that bis an
isomorphism
for allfinitely generated projective
M if it is so for Aitself.
Making Z2
act on Aby T(x)
=oc(x)u,
this is so if theZ2-module
A is
cohomologically
trivial.Let
(B, fi, v) satisfy
the same conditions as(A,
a,u). Let f:A~B
bea
ring homomorphism
such thatf(u)
= v and03B2(f(a))
=f(03B1(a))
fora E A. Then for any A-module M we define N = M
OA B, regarding B
as
right
A-moduleby f.
Forany 0
ESa(M),
definef*(~)
ES03B2(N) by
It is easy to check that this is
compatible
with the relationsdefining
thetensor
product,
and thatThus f*
induces a mapand
similarly
forQ.
LEMMA 1.
Iff :
A - B issurjective,
and M is aprojective A-module,
thenis
surjective.
PROOF. Since
Q(03B1,u)(M)
is aquotient
ofSa(M),
it isenough
to showS03B1(M) ~ S03B2(N) surjective.
Choose M’ with M ~ M’ free. SinceSa(M
0M’) splits naturally
as a direct sum of 4 terms it isenough
toshow
Sa(M
0M’) - S03B2(N
~N’) surjective; equivalently,
we may suppose M free. Choose a basis{m03B1}. Taking 4J
to the matrix~(m03B1, m03B2)
now
gives
abijection
ofS03B1(M)
to a group of matrices over A.Now f*
acts on matrices
by letting f
act on eachentry.
Thussince f is surjective,
so
is..
Note that
already
this result is false for hermitian forms.We can never
expect f*
to beinjective
too, but under suitable assump- tions we canget
asgood
a result. We will need conditions onboth.f and
the forms.
A
map 0
ES(X(M)
is callednonsingular
ifits adjoint A~ :
M -HomA(M, A)
definedby
is
bijective.
Aquadratic
form isnonsingular
if its bilinearisation is.Evidently f*
preservesnonsingularity.
If A is a
ring
and I an ideal we have aquotient map f :
A ~A/I
= B.If
03B1(I)
=I,
ainduces 03B2 : B ~ B,
andtaking
v = u + I wesatisfy
theconditions
for f
to induce a map(even
asurjective one)
ofquadratic
forms. Note that here N =
M/MI.
Foreach n ~
0 we have the idealin.
andtaking
these as base ofneighbourhoods
of 0 defines the I adictopology
on A. We will suppose Acomplete
in thistopology,
orequiv- alently,
that the mapis an
isomorphism.
THEOREM 2. Let
A,
I be asabove;
let M be afinitely generated projective
A-module. Then x E
Q(03B1,u)(M)
isnonsingular if
andonly if f*(x)
is.If
x isnonsingular, and f*(x) = f*(y),
there is anautomorphism
Àof
M withÀ*(x)
= y andIm(03BB-1M)
cM. I.PROOF.
That f*(x) nonsingular implies
that x is follows from Naka-yama’s
lemma.Indeed,
it is standard(see
e.g. Bourbaki[4])
that underour
assumptions
there is abijection
ofisomorphism
classes offinitely generated projectives
over A and overAIL
For the second
part,
supposeinductively
that x and y agree moduloIr,
i.e. that there arerepresentative ç,
~ ES03B1(M)
withSince x is
nonsingular,
so is itsbilinearisation 03BE+T03BE.
Consider thecomposite
which is an A-module map: call
it f. Since fM ~ M · Ir, 1M+f
is anisomorphism.
We nowcompute (1M+f)*(x).
We haveNow
so that
Here,
the first term is il, as desired. The middle two terms define thezero
quadratic form,
since if we define x ES’a(M) by
then
The last term
belongs
toI2r.
We have thus shown that if xand y
agreemodulo
I",
there is anautomorphism (1 +f )
of M such thatf(M)
cM · Ir and
(1 +f)*x
agreeswith y
moduloI2r.
To prove the theorem we
apply
this resultinductively
as follows.Start with
representatives 03BE, ~
of xand y
which agree modulo I.Suppose
we have found
inductively endomorphisms fi
of Mwith fi(M)
c M .I2i-l
and
forms xi
ES’a(M) taking
values inI2i-1
for 1~
i ~ r withApplying
the result wefind fr+
1 and Xr+ 1 to continue the induction. Now since A isI-adically complete,
theproduct 03A0(1+fi)
converges to anautomorphism 03BB
ofM,
withand the
sum Y
xi converges to a form ~ ~Sa(M),
andtaking
the limitwe have
hence 2*x = y, as
required.
The above result is far from
being
true for hermitian forms: in thissense it is the
key
result of this paper. Most of theapplications
below areas
easily
deduced from otherconsiderations,
but thewildly
ramified caseneeds
something
like theargument
above.If A is a
compact ring
and J itsradical,
then A iscomplete
in theJ-adic
topology,
andA/J
is the directproduct
of matrixrings
over divi-sion
rings.
Now a leaves these invariant orinterchanges
them inpairs:
the
pairs
contributenothing,
and the classification ofnonsingular quadratic
forms over A is thus reduced to matrixrings
over divisionrings,
and it is not hard to reduce further to forms over division
rings.
Programme
and notationFrom now on, ail our
rings
will be commutative. Theassumptions
above then
simplify
to:a is an
automorphism
of A witha2
=identity,
u is a unit of A with
a(u) - u-1.
The involution oc will
always
befixed,
and we denote itby
a bar:a(x)
= x.Write
A +
for the additive group ofA, A
for itsmultiplicative
group.Thus we have U E
A ,
uù = 1. Weregard
both these asZ2-modules,
with
Z, acting by
a.The
rings
to be considered are as follows. K is analgebraic
numberfield,
with involution ’bar’. The fixed field isk,
so K is aquadratic
extension of k. The
rings
ofalgebraic integers
inK,
k are denotedby R,
r. For eachprime
p(= valuation)
ofk, kp
is thecompletion
of kat p and
Kp
= KQk kp.
There are twopossibilities: K,
may be a fieldwhich is a
quadratic
extensionof kp
or a direct sum of twocopies of kp, interchanged by
’bar’. In the latter case we say that p isdecomposed.
If p is
non-archimedean, rp
andRp
denote thecorresponding completions
of r and R. But we can
always
defineRp = R Qr rp . Then rp
is a localring,
and so(except
in thedecomposed case)
isRp ;
wewrite f p
andFp
for their residue class fields.
We have identified
primes
withvaluations,
but will inpractice
writevp :
k ~Z;
alsovp : k 03C1 ~
Z for thevaluations,
and p for the cor-responding prime
ideal{x : vp(x)
>01
ofrp
={x : v03C1(x) ~ 01,
or of r.We have
rp - {x
Ek’ : vp(x)
=0}.
An element x ofrp
withvp(x)
= 1is called a
prime.
Similarterminology applies
toRp
when it is a localring.
Our
objective
is toclassify nonsingular quadratic
forms onfinitely generated projective
R-modules M. It is well known that such M are characterisedby having
M - MQR K injective
and Mfinitely generated
over R.
Putting V
= MQR K,
it is thus natural to consider first formson the vector space V and then M ce V as above: M is then called a
lattice in V. The
embedding
determines the bilinearisation of the qua- dratic form but not ingeneral
the form itself: we will have to deal with thispoint
later.The
completions
come in since we can writeMp
= MQ R R p ,
con-tained
(as
alattice)
inVp
= VQ9K K03C1,
and then M = nMp,
the inter-section over all
(non-archimedean)
p. Two latticesM,
M’ c V haveMP
=Mp
for almost all(i.e.
all but a finitenumber)
p;conversely, given
latticesMp - Mp
for almost all p, M’ = nMp
is a lattice in V.In order to pass from the ’local
theory’ (classification
overRp)
to the’global theory’ (classification
overR),
we need more thanjust
the iso-morphism
classification ofnonsingular quadratic
forms overRp;
wemust relate this to the classification over
K03C1;
andgiven
two latticesMp, MP
cYp
we have to know notonly
when there exists anisomorph-
ism
M p 4 Mp,
which(necessarily)
induces anautomorphism
A Q 1 ofTlP ,
but also when A can be chosen so thatA ~ 1
has determinant 1.In this case we call
Mp
andMp SU-equivalent.
Recall from
[10,
p.2]
thatmultiplying
the values of aform 4J by
aunit v
(scaling)
convertsu-quadratic
touv/v-quadratic
forms(we
suppressmention of the
involution,
which remainsfixed).
We will use this techni-que to normalise the unit u as far as
possible; naturally
this is much easier in the localtheory (and,
of course, over fields one needonly
considerhermitian or
skew-symmetric forms).
Note that theequivalence
classesof u
just
constitute thecohomology
groupH1(Z2; A").
It ispossible
(c.f.
O’Meara[7])
togive
an alternative formulation in terms of ’v- modular’(rather
thanunimodular)
forms.Finally
note that for an(a, u)-reflexive form 0
on a free module Fover a commutative
ring A,
one can choose a basis{ei}
of F and formthe determinant D = det
0(ei, e j).
Theform 0
isnonsingular
if andonly
if D is a unit:
DEA x.
We haveD
= D. If the basis ischanged by
asubstitution with determinant D
(so 03B4 ~ A ),
D ismultiplied by ô3.
Themultiplicative
class of D modulo such elements is animportant
invariantof
0.
For most purposes,however,
it is convenient tomodify
it asfollows.
Suppose
that F has rank 2k. Then it admits also aforum 1/1
whichis a
hyperbolic
form on a free module of rank k. Thequotient
of the determinants Dtor 0 and 03C8
is called the discriminant ot0.
Since03C8
hasa matrix of blocks
it has determinant
( - u),
so the discriminantof 0
is(-u-1)kD.
Weusually
denote itby
4. When we refer to the discriminant of aform 4J
on a free module of rank
(2k + 1 ),
it does not matter whether weinterpret
it as D or
(-u-1)kD (provided
theinterpretation
isconsistent).
Wedefine the discriminant of a
quadratic
formby
firsttaking
the bilinearisa- tion.Li
(or D)
takes values in thequotient
of the group of invariant units ofA(0394 ~ A , 0394 = 0394) by
the group of norms of units(ô5, Ô
EA’).
This isjust
the(Tate) cohomology
groupH0(Z2; A x).
Note that the discrimi- nant is unalteredby scaling:
if the form has rank2k,
D ismultiplied by v2k
and(-u-1)kD by (VV)k.
Local
theory
DECOMPOSED CASE. The classification
problem
here isessentially
trivial.Indeed,
even in the non-abelian case, if A =A1
E9A2,
withAl
andA2 interchanged by
a.REMARK. There is a
bijection
betweenisomorphism
classesof projective
A1-modules
andof nonsingular (a, u)-quadratic (or reflexive) forms
onprojective
A-modules.Let u have
components (u1, u2): then u2 = u-11. Taking v
=(u-1, 1)
we see that
by scaling
we can suppose u = 1.Again,
one seeseasily (the Z2-module
A is induced(from A1))
that bilinearisation is anisomorphism
in this case.
Finally
an A-module M can beregarded
as apair (Ml, M2) : Ml
anA,-module, M2
andA2-module;
and aquadratic
or hermitianform amounts to a
pairing
betweenM1
andM2, nonsingular
if andonly
if this
pairing
is.One can
regard
thisbijection
ascorresponding
to the fact that aunitary
group, as
algebraic
group over afield,
is a k-form of thegeneral linear
group.
We thus see that the classification of forms both over
Kp
and overRp,
is trivial - a form
being
determined up toisomorphism by
its rank. Like-wise,
theproblem
ofSU-equivalence
comes down to theproblem
ofSL-equivalence
of latticesover rp (with
no form onthem).
Hereagain
itis worth
beginning
with ageneral
observation.REMARK. Let
Mp
have aquadratic form cPp;
let G be the groupof
determinants
of automorphisms of (Mp, ~03C1). If Mp, Mp
are lattices inTlp,
and A anisomorphism of Mp
onMp, extending
to anautomorphism A of V03C1,
thenMp
andMp
areSU-equivalent if
andonly if
det A E G.Thus if H is the group of determinants of
automorphisms
of(V03C1, ~03C1),
we have a
bijection
ofSU-equivalence
classes of latticesisomorphic
to(M03C1, ~03C1)
withH/ G.
In the case at hand there is no
Op
but theprinciple
is the same. Sincerp is a
principal
ideal domain(the only
ideals are the powers ofp), Mpl
is a free
rp-module.
Determinants ofautomorphisms
mustbelong
tor; :
any element
of r; gives
anautomorphism
of a free module of rank1,
and so does occur as a determinant.Similarly
H can be identified ask 03C1.
Finally, vp gives
anisomorphism
ofk 03C1/r 03C1
with Z. Thus we have abijection
of the set ofSU-equivalence
classes with Z.INERT CASE.
Here, Kp
is a field. Wechange notation,
andwrite vp : K§ -
Z for its valuation. First we recall some facts aboutcohomology.
H1(Z2; K 03C1)
= 0 as for any fieldH0(Z2; K 03C1) ~ Z2
e.g.by
local class fieldtheory.
The exact
cohomology
sequencebelonging
to the coefficient sequencenow reduces to
Clearly vp*
is nonzero if andonly
if there exists x ~kp
withvp(x)
odd:in this case the extension is
unramified,
otherwise ramified.In both cases there are two classes of forms over
K 03C1
of agiven rank,
which are
distinguished by
the discriminant. Otherquestions
are all muchmore
complicated
in the ramified case, so we discuss the inert(non- ramified)
case first.Then oc is non-trivial on
Fp,
andgenerates
the Galois group ofFp/fp, and vp
induces the valuation ofkp.
Since theH’
groupsvanish,
we cansuppose
by scaling
that u = 1. TheZ2-modules Fp+ , R+03C1, KJ
are cohomo-logically trivial,
so there is no essential distinction between hermitian andquadratic
forms. For forms overFp,
and hence(by
Theorem2)
alsoover
Rp
there isjust
oneisomorphism
class ofnonsingular
forms of agiven
rank. Since an element x ofkx
is a norm if andonly
ifvp(x)
iseven, units are norms, so
only
the forms overK03C1
with L1 = 1 containunimodular
(i.e. nonsingular)
lattices.Certainly
two lattices in the sameTlp
areequivalent:
we claim thatthey
are alsoSU-equivalent,
which willcomplete
our discussion of the inert case.Any automorphism
ofhP preserving
the form must have determinant bsatisfying 03B403B4
= 1: it thus suffices to find anautomorphism
withdeterminant ô
leaving Mp
invariant. NowVp(b) = 0, so 03B4 ~ R 03C1.
Sincea hermitian form over
Fp
is a direct sum, with one summand 1-dimens-ional,
Theorem 2implies
that the same holds overRp :
let egenerate
such a summand. The
required automorphism
is now obtainedby letting
e -
eô,
andleaving
theorthogonal complement
of e fixed.RAMIFIED CASE
(non-Archimedean).
This is the case whenK03C1
is afield,
but its valuation induces 2 x the valuation ofkp.
In this case, a istrivial
on Fp
=fp.
Again .Kp
iscohomologically
trivial(the
extensionKIkp
isseparable,
as the fields have characteristic
0).
ForRp
andF+03C1
we have to distin-guish
the cases whenF+03C1
has characteristic 2 or not. The ramification is describedcorrespondingly
as wild or tame. In the tame case,Rp
andF+03C1
are still
cohomologically trivial;
in the wild casethey
are not. We willnot discuss reflexive forms over
R03C1
andFp
in the wild case;only quadratic
ones; in the other cases
(and
overKp)
it makes no différence.Write
Up
for the kernel ofR§ - F 03C1.
In the tame case,Up
is cohomo-logically
trivial andH*(R 03C1) ~ H*(F 03C1).
In the wild case,things
aremore
complicated. However,
it follows from the exact sequence men- tioned earlier that(in
eithercase)
arepresentative
of the non-trivial class inHl(Z2; R 03C1)
is03C0/03C0,
wherev03C1(03C0)
= 1. Thusby scaling
we cansuppose that u = 1 or u =
3ilz.
It will be moreconvenient, however,
to reduce to one of the caseswhich we call
respectively
thegood
and bad cases. In the tame case, wecan take
03C0/03C0 = - 1 ;
in the wild case this may or may not bepossible.
But in the wild case the condition ûu = 1
implies
anyway that u reducestolinFp.
There are thus three cases for forms over
Fp :
GOOD TAME CASE
(characteristic odd,
u =1).
We have a
quadratic
form overFp.
There are twoisomorphism
classesof these for each
rank,
classifiedby
the discriminant.By
Theorem2,
each lifts to a
single isomorphism
class overRp: again distinguished by
the discriminant. Thus each form over
Kp
contains a unimodularlattice, unique
up toisomorphism.
As in the inert case, we see that it is alsounique
up toSU-equivalence.
BAD TAME CASE
(characteristic odd,
u= -1 ).
We have a
skew-symmetric
form overFP .
Fornonsingularity ,the
rankmust be even; in fact we can
only
have ahyperbolic
space.By
Theorem2,
the form overRp
must behyperbolic
too, hence also that overK03C1.
Wedefer the
question
ofSU-equivalence.
WILDLY RAMIFIED CASE.
We have a
quadratic
form over the finite fieldFp,
of characteristic 2.For
nonsingularity,
the rank must be even. There are twoisomorphism
classes for each
rank,
andthey
aredistinguished by
the Arf invariant[1 ] : if {e1,f1, ···, er, fr}
is asymplectic
base for the bilinearisation of x, and q is the associatedquadratic
map of x,is well defined modulo the additive group of elements
w+w2, w E Fp .
Let S :
Fp Z2
be the map whose kernel consists of theseelements;
then
c(x)
=Sc’(x) is
well-defined.By
Theorem2,
c is theonly
invariantneeded for forms over
Rp
also. If c =0,
the form ishyperbolic,
so thediscriminant is 1.
Otherwise,
it is not clear apriori
how the classificationsover
Rp and Kp
compare.THEOREM 3. In the bad case, all
nonsingular forms
overR03C1
becomehyperbolic
overKp.
In the
good
case,nonsingular forms
overRp
withdifferent Arf
invariantsare not
equivalent
overK03C1.
PROOF. Since each form over
Fp splits
as the direct sum ofnonsingular 2-dimensional forms, by
Theorem 2 the same holds overRp.
Thus itsuffices to consider the two-dimensional case. A
typical
form has base{e, f}
andThis has Arf invariant the class of b.
The
above 0 represents
an x whose bilinearisationis ~+T~ = 03C8.
Ifu
= - l,
then03C8(e, e)
=0,
so03C8
ishyperbolic
overK03C1.
This proves thefirst
part
of the Theorem.In
general,
so 03C8
has determinant(1 +u)(b+ub)-u
and discriminant thequotient
ofthis
by - u. Putting
u= -03C0/03C0,
this isWe must show that this is not a norm.
My proof
isfairly
brutal. We may choose b withS(b)
= 1 andb
= b.There are two cases,
according
as an element d ofKp
withà
= - d hasv03C1(d)
even or odd(we
may suppose 0 or1).
Ifv03C1(d)
=1,
we can taked for 7T above. Then
If Lp c Kp
is the fixed field of a, thenKp
is obtained fromLp by adjoining
the square root
of d2.
Thus A is a norm if andonly
if the Hilbertsymbol (J, d2)v
= + 1. ButJd generates
the non-ramified extension ofLp ,
andthe
prime
elementd 2 is
not a norm fromthat,
so in fact(4 , d2)v
= -1.(The
reason thatL03C1[0394 ] is
non-ramified is that sinceS(b)
=1, b is
notof the form
w + w2
mod p(in L03C1):
in theextension,
we can take w =1/2(1+0394).)
If
vp(d )
=0,
it isagain
convenient to work inLp
rather thanKp:
if clis a
prime
inLp,
thenK03C1
=L03C1[a]
for some a of the forma=1+uw2r+l
0 ~ r efor some unit u, where e is the absolute ramification index
of L03C1.
Herewe can take
so that
Again,
we must calculate(a, 0394)v.
Butby
the last exercise in[8 ] (the
conditions are
easily
verified: a EU2r+l,
L1 EU2e-2r-l),
since a reduces to 1 E
Fp,
andS(b)
= 1by
the choice of b.It remains to consider
SU-equivalence
in the ramified case. As in theother cases, this amounts to
finding
which numbers (5with 03B4 = 03B4-1
canarise as determinants of
automorphisms
of thegiven
lattice.THEOREM 4.
Suppose
L has ahyperbolic
summandH,
and we are in theramified
case. In the bad case, the latticesisomorphic
to Lfall
into twoequivalence
classes under SU. In thegood
case,they
are allSU-equivalent.
We discussed above the
tamely
ramified case with u = 1. In the other cases, the bilinearised form overFp
is skew(and
hence evendimensional):
the
only
forms excluded arenon-hyperbolic
and 2-dimensional.PROOF.
Let 3
=b -1.
Then ô =ç/ç
forsome 03BE,
and we can supposevp(ç)
= 0 or 1. Ifv03C1(03BE)
=0,
we can define anautomorphism
of Lby fixing
theorthogonal complement
ofH,
andmapping
H(with
basise, f) by
this has determinant Ô. We have thus
represented
haIt thepossible
valuesof ô.
Next consider the
automorphism
this has
determinant - u,
andif u = -03C0/03C0,
this is3ilz,
one of the values of 03B4missed
before.Composing
with theautomorphisms above,
weget
all values of £5: thus for u= -03C0/03C0
allisomorphic
lattices areSU-equiv-
alent. ’
To deal with the bad case, we need a
lemma,
LEMMA.
Write %for
the idealgenerated by
allx - x,
x ~R p .
Let b ER p ,
ô3
= 1. Then b =j/j with ç a
unit ~ 1 - à E9L
PROOF. If Ô =03BE/03BE with 03BE
aunit,
thenIf not, then b =
3ilz
withprime.
Now any x ~Rp
can be written asa + bn with a,
b invariant under oc(and
inRp),
so x - x =b(03C0 - 03C0),
andU
is the idealgenerated by
03C0 - 7r. Thusdoes not
belong
toU.
Now 2(
iscertainly
an a-invariant ideal ofRp,
so a form overRp
induces one over
R03C1/U
=Qp. By
definition of2!,
a induces theidentity
on this
quotient ring,
so in the case u = - 1 we have anonsingular
skew-symmetric
form over it.Any automorphism
of the form over R(with
determinant
03B4)
induces one of thisquotient which, by
a well known result(see
e.g.[3,
p.85])
has determinant 1. Thus b ~ 1mod %,
andby
thelemma,
this isequivalent
to 1J =03BE/03BE with 03BE
a unit. Thiscompletes
theproof
of the theorem.SUMMARY. There are
essentially
4 cases:decomposed,
inert or ramifiedwith u
= -çjç
andv03C1(03BE)
even(good)
or odd(bad).
Wealways get
somenonsingular quadratic forms, though
in the ramified case the rank mustbe even
(except
in thegood, tamely
ramifiedcase).
In tabularform,
our conclusions are:Here ’classes over
R03C1(K03C1)’
denotes the number ofisomorphism
classesof
nonsingular quadratic
forms of agiven rank;
the * denotes thatonly
one of the two contains
nonsingular
lattices(it
is the one with determinantor discriminant
1).
Also ’SU-classes’ describes those in agiven isomorph-
ism class.
ARCHIMEDEAN CASE. This has to be discussed too for
completeness.
For
completeness
ofnotation, write rp
=kp, Rp
=K03C1
here. If thearchimedean
prime
of kdecomposes then,
as in the non-archimedeandecomposed
case, the classification is trivial - and there is here no ques- tion of SU-classification either.If p
ramifies,
the extension isisomorphic
to C overR,
and we have hermitian forms in the classical sense(as usual,
we can reduce u to 1by scaling).
There are(r+1) isomorphism
classes of forms of rank r ~0, represented by
for
0 ~ p ~
r. Thesignature
6 of the form is the number ofpositive
minus the number of
negative
terms:2p - r (this
is chosen to be zero forhyperbolic
forms. It satisfies theconditions |03C3| ~
r, and 03C3 ~ r(mod 2). )
We will
usually
deal with forms of evenrank,
and write 6 = 2-r.t Only one in the tamely ramified case.
The determinant of the above form is
( -1 )r -p (modulo
norms - i.e.positive
realnumbers).
If r =2k,
since thehyperbolic
form of that rank has determinant(-1)k,
the discriminant is d =(-1)k-p
=(-1)p-k = (-1)03C4.
Unlike thediscriminant,
i can bechanged by scaling. Scaling by
v
reproduces
a hermitian formif VER x :
if v ispositive,
i isunaltered,
but if v is
negative,
it isreplaced by - i.
This isunimportant
for ourtheory,
but may necessitate a little care inusing
our results.Global
theory
We first recall the classification of hermitian forms over K
(note
thatby scaling
we can suppose u = 1 overfields). Nonsingular
forms of agiven
rank are classified[6] by
thediscriminant,
and thesignatures
atArchimedean ramified
primes.
Another mnemonic for this result is the’Hasse
principle
forH1(SU)’ [5a]:
for forms of fixed(nonzero)
dis-criminant,
theglobal
classification isequivalent
to classifications at the Archimedean ramifiedprimes alone;
it iseasily
seen that the discriminantcan take any value
already
in the 1-dimensional case.As we have
already said,
we will tackle forms over Rby considering
lattices in vector spaces V with forms over K. To economise
notation,
thiswill mean a lattice L in the usual sense
(finitely generated
R-module whichspans V
overK), together
with aquadratic
form(over R)
on Linducing
the
given
form on V. We inherit on the localisedLp quadratic
forms overRp.
These are not determinedby
the form on V and theembedding
ofL in Tl
(or locally)
ingeneral.
But the bilinearised form isdetermined,
and hence so is the
quadratic
form onLp except
when p iswildly
ramified.The
key
observation to circumvent thisdifficulty
is thatQ
is an arithmetic functor in thefollowing
sense. Let F be a functor defined onpairs consisting
of aring
A and an A-moduleM, perhaps
with some extrastructure
(we
willactually
take F =Q(ex,u)(L)
orS03B1(L, M)
with twomodules
involved);
covariant in A and contravariant in M. We call Fan
arithmetic.functor
if thediagram
is a
pullback,
for therings R
etc. definedabove,
and L aprojective
R-module of finite
type 1.
If F is additive in the variableL,
then thediagram corresponding
to L (D M will be apullback
if andonly
if the1 For this to make sense in the decomposed case, the primes p must be interpreted
as primes of r.
diagrams
tor L and for M both are. Thus it suinces to check thepullback
property
when L isfree,
or indeedjust
when L = R.PROPOSITION 5.
The functors Sa, R(03B1, u)
andQ(03B1, u)
are arithmetic.PROOF.
Sa,(L, M)
is additive in L and inM,
andS03B1(R, R) ~
R. Sincethe
diagram
is a
pullback,
the functorSa.
is arithmetic. Now sinceR(03B1, u)(L) =
Ker
( 1- Tu), arithmeticity
ofR(a,
u) followsby di agram chasing (essential- ly
the snakelemma).
ForQ(03B1, u)
the result is not formal. Butalthough Q
is not
additive,
the(natural) splitting
Q(a, u)(I’
~M) ~ Q(a., u)(L)
~S03B1(L, M)
~Q(a, u)(M)
shows,
as in the additive case, that it is sufficient to consider the caseL = R. Note that
Q(a., u)(R)
is thequotient of’ R+ by
the additivesubgroup
of elements x - ux
(x E R); similarly
for the other rings involved.There are two
things
tocheck,
which we will do in the next two para-graphs.
The first amounts to this: let z E K be such that forall
p there existsx03C1 ~ K03C1
withz + x03C1 - ux03C1 ~ R03C1;
then we must find XE K withz + x - ux ~ R.
However,
sincez ~ R03C1
for almost all p(say p e S),
itsuffices to
apply
thestrong approximation
theorem(for K+)
to findx ~ K such that x ~
Rp
forp 0
S and(x - xp)
ERp
for p E S. This x does what we need.Secondly
we must show that if z e R is of theform xp - uxp (xp
ERp)
for all p, and of the form x - ux with x
~ K,
then we can choose x E R.Let
Z2
act onR+ (and
the otherrings) by
x H ux. SinceK+
andK+03C1
are
cohomologically
trivial(we
can divideby 2),
what we have to showis that
is an
isomorphism.
Nowif p is non-dyadic, H’(Z,; R’)
= 0. But ~Rp,
extended over
dyadic
p, can be identified with the tensorproduct (over Z)
of R with thering Z2)
of 2-adicintegers.
It now remainsonly
toobserve that for any
finitely generated Z2-module M,
the natural mapis an
isomorphism.
It follows from the
Proposition
that the relation of L and theLp
isthe classical one: