C OMPOSITIO M ATHEMATICA
T. N. S HOREY
R. T IJDEMAN
Perfect powers in arithmetical progression (II)
Compositio Mathematica, tome 82, n
o1 (1992), p. 107-117
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Perfect powers in arithmetical progression (II)
T. N.
SHOREY1
and R.TIJDEMAN2
’School of Mathematics, Tata Institute of Fundamental Research, Homi Bhabha Road, Bombay 400005, India; 2Mathematical Institute, R. U. Leiden, Postbus 9512, 2300 RA Leiden,
The Netherlands
Received 27 November 1989; accepted 22 August 1991
©
Section 1
It is an old
question
howlong
arithmeticalprogressions
ofequal
powers ofpositive integers
can be. There existinfinitely
manytriples of coprime
squares in arithmeticalprogression,
but Fermatproved
that there are no four squares in arithmeticalprogression,
see[8,
p.21].
Dénes[2] conjectured
that forl
3there are no three 1-th powers in arithmetical
progression,
andproved
thisassertion for
3
1 30 and forsixty
otherprime
values of 1.Faltings’
celebratedresult
[5] implies
that forany 1 a
5 there areonly finitely
manytriples
ofcoprime
1-thperfect
powers in arithmeticalprogression.
Without loss ofgenerality
we can restrict our attention to thefollowing
situation:1 is a
prime number, l 3,
andm, d
and k arepositive
}
integers satisfying gcd(m, d)
= 1and k
3 such that each(1)
of the numbers m, m +
d,..., m
+(k - 1)d
is an 1-thperfect power.
Let
dl
be the maximal divisor of d such that all theprime
factors ofdl
are~ 1 (mod l). Similarly,
we define m 1 as the maximal divisor of m such that all theprime
factors of m 1 are---1 (mod 1).
For aninteger
vwith |v|
>1,
we writep(v), P(v), Q(v)
andm(v), respectively,
for the leastprime
factor of v, thegreatest prime
factor of v, the
greatest
square free factor of v and the number of distinctprime
divisors of v.
Further,
we setp( ± 1)
=P( ± 1)
=Q( ± 1)
= 1 andw(:t 1)
= 0. Wewrite
p(l, 1)
for the leastprime
~1(mod 1). Recently
Heath-Brown announced that he hasproved
p(l, 1) l10 if 1 a C (2)
for some
effectively computable
absolute constant C. Until now the bestexponent
was16,
see Wei[12].
It follows from the above mentioned results of Dénes and
Faltings
that if(1)
holds then k is bounded
by
some numberdepending only
on 1. We showed in[10]
that there exists an upper bound for kdepending only
oncv(d).
Infact,
weproved
in[10]
that(1) implies
thatand that
Furthermore,
it follows from formula(2.7)
of[11]
thatHere
C1
is aneffectively computable
absolute constant. In this paper, we find anupper bound for k
depending only
oncv(d 1 ).
Moreprecisely,
we proveTHEOREM 1. Let 8 > 0. There exists an
effectively computable
numberC2 depending only
on 8 such that(1)
withk C2 implies
thatTheorem 1
sharpens
the assertion ofCorollary
1 of[11]
under astronger assumption.
We derive thefollowing
result from Theorem1,
the Brun-Titchmarsh Theorem and
(3).
COROLLARY 1. Let 8 > 0 and
q(8) = (1
-8)/long 2.
There exists aneffectively computable
numberC3 depending only
on 8 such that(1)
withk C3 implies
thatand
Observe that
(3) gives stronger
results than(7)
for small values of 1. Forexample,
we see from
(3)
and the Prime Number Theorem for arithmeticalprogressions
that
(1) implies
thatif 1 does not exceed a fixed power of
log k
and k issufficiently large.
It is clear from
(3)
that it is notpossible
to obtain aninequality analogous
to(7)
forp(d 1 ).
Infact, p(d 1 )
is bounded whenever 1 is bounded. Moregenerally,
wesee from
(3)
and(2)
thatif (1)
holds with kexceeding
asufficiently large
absoluteconstant, then
where
C4
=2-1/10.
Next we consider
analogous
results for m.THEOREM 2.
(a)
There exists aneffectively computable
absolute constantCS
> 0 such that(1) implies
that(b)
There existeffectively computable
absolute constantsC6
andC7
> 0 such that(1)
withk C6 implies
thatand
COROLLARY 2.
If (1)
holds thenFinally,
we prove a resultinvolving
both m andd,
THEOREM 3. There exists an
effectively computable
absolute constantC8
suchthat
(1)
withk C8 implies
thatSection 2. Proof of Theorem 1
We may assume that
(1) with k
c is valid where c is asufficiently large
effectively computable
numberdepending only
on 8.Further, by
the result ofDénes mentioned in Section
1,
we may suppose that 1 > 30. The case1
4w(d,)
+ 2 is treated in thefollowing
lemma.LEMMA 1.
Suppose (1)
issatisfied
with 30 1403C9(d1)
+ 2. ThenProof.
First we consider the case that31 03C9(d1).
Then there exists apositive integer
nsatisfying
Consequently,
there exists a divisor d’ ofdl
such thatand
Therefore, by (2.1)
of[11],
where
CS
is the absolute constantappearing
in(2.1)
of[11]. Further,
since1 >
30,
we observe thatNow we
proceed
toapply
Theorem1 (b)
of[11].
Forthis,
we observe from(15), (16)
and(4) (or (2.13)
of[11])
thatwhere
C8
is the constantappearing
in(2.4)
of[11]. Hence, by
theorem1(b)
of[11],
which, together
with(14), implies
thatsince 1 > 30.
Thus we may assume that 31 >
03C9(d1).
Then we may suppose that 1 >200,
otherwise weapply Corollary
3 of[11]
to conclude that k c.Next we consider the
general
case 30l 4cv(dl)
+ 2. Then there exists apositive integer n
withand a divisor d’of
d 1 satisfying
Now,
weapply
Theorem1(b)
of[11]
asabove,
to conclude thatwhich,
since 1 >200, implies
that03C9(d1) > 3 2 log k.
D Tocomplete
theproof
of Theorem1,
we consider the case l >403C9(d1)
+ 2.Then, by (5),
there exists adivisor d’of dl
such thatFurther, by (2.1)
of[11],
we observe thatwhere
C5
is the absolute constantappearing
in(2.1)
of[11].
Now weproceed
toapply
Lemma 8 of[11] with f (x)
=log
x. First we observe from(19)
and(2.7)
of[11]
thatAlso it is easy to see that
|S1| 03C0(k)
whereSi
is the setappearing
in Lemma 8 of[11].
Forthis,
observethat, by (1),
for everyprime p k
there is at most one y with0 03BC
k such that m +pd
is divisibleby
p.(In fact, (3)
is an immediateconsequence of this
assertion.)
Hence weapply
Lemma 8 of[11]
to concludethat
We write
Therefore, for M
> v0,
we haveWe
put
Except possibly 1,
everyprime
factor of xl,,v is== 1 (mod 1)
and12 x03BC,v.
Inparticular,
we observe from(20)
thatwhich
implies
thatNow we fix v =
[203B51k] -
2. We conclude from(22)
that for li > v there existpositive integers d1,03BC
=d1,03BC,v
andd2,,
=d2,03BC,v
such thatand
Furthermore,
we derive from(23)
that x03BC,v =d1,03BC
andd1,03BCl-03B4
is a divisor ofd1
where
For pi > 03BC2 > v, we observe that x03BC1,v > x03BC2,v. Now we
apply
the BoxPrinciple
to conclude that
PROOF OF COROLLARY 1. Let 8 > 0 and 81 =
e/2. Suppose
that(1)
withk C3
is valid.Further,
we may assume thatC3
issufficiently large.
Now we seefrom
(6)
thatWe recall that every
prime
divisor ofd 1
is ~1 (mod 1)
and weapply
the Brun-Titchmarsh Theorem to derive
(7)
from(24).
Next we
proceed
to prove(8).
First we assume that 14cv(dl)
+ 2. Now weapply
Lemma 8 of[ 11 ]
as in theproof
of Theorem 1 to conclude(20).
Further weobserve that
We combine
(25), (24)
and(20)
to derive(8)
if 1 >4m(di)
+ 2.Thus we may assume 1
4w(dl)
+ 2. Then weapply
Theorem1 (b)
of[11]
asin the
proof
of Lemma 1 to conclude(18).
We combine(25)
and(18)
to deriveThus we may suppose
that l 12~(03B5) log
k. Then we see from(3)
and the Prime Number Theorem for arithmeticalprogressions
thatwhich
implies (8).
Section 3
We denote
by
cl, ... , c9effectively computable
absolute constants.Suppose
that(1)
is validwith k
Ci where c 1 issufficiently large.
We write(21).
Asalready remarked,
for everyprime q k
there is at most one J1 with0 03BC
k such thatm +
J1d
is divisibleby
q. Therefore there exists a set Twith |T| k - n(k) consisting of integers J1 satisfying 0 03BC
k andp(x03BC)
> k.Further, for J1
E T andv E T
with p
> v, we observe from(21)
thatThen we have
We
apply
the sieve-theoretic Lemma 1 of Erdôs[3]
to conclude that there existpositive integers P, Q
and R such thatand that
is satisfied
by
at leastc3k pairs
xu, xv withp(x03BC) > k, p(xv)
> k andgcd(xJl’ xv)
= 1.PROOF OF THEOREM
2(a).
We may assumethat k
cl, otherwise(9)
follows
immediately.
Now weapply
a theorem of Baker[1]
on linear forms inlogarithms
to conclude from(26)
thatwhich
implies
thatThis
inequality
is trivial ifc5 log l
1 whichimplies
thatl
c6. Ifl
c6, weapply
an estimate of Feldman[6]
on themagnitude
ofintegral
solutions of Thue’sequation (cf. [9], Chapter 5)
to(26)
forderiving
Now we combine
(27)
and(28)
toobtain m
dc8which, together
with(4), implies (9).
PROOF OF THEOREM
2(b).
Assume(1).
We may suppose thatk
c,and, by part (a), that m c2.
Then there are at leastC3k pairs
x,, xv withp(xu)
>k, p(xv)
> k andgcd(xu, xv)
= 1satisfying (26).
Observe thatNow we
apply
Theorem 2 of Evertse[4]
on an upper bound for the number of solutions of(26)
to conclude thatwhich
implies (10).
We
put
p =p(m,). Then, by Corollary 2,
we observe thatp
2. Sinceordp(m)
1 andgcd(m, d)
=1,
we see thatordp(m
+pd) = 1. If p k,
then thisis not
possible.
Thus we derive thatBy (21),
we haveFurther, by (29)
andgcd(m, d)
=1,
we observe thatOn the other
hand,
since p =1 (mod 1),
we see thatxô, x i, ... , xlk-1
lie in at most(p - 1)/l
distinct residue classesmod p.
Hence we conclude from(30)
and(31)
that
(p - 1)/l k
whichimplies (11). Finally
we observe thatQ(m1) po(- i)
which, together
with(11)
and(10), implies (12).
DSection 4. Proof of Theorem 3.
We denote
by
el 0’ c11 and c12effectively computable positive
absoluteconstants. Assume
(1) with k c10
where c10 issufficiently large.
Put|m - d| =
M. Observe that M ~0,
sincegcd(m, d)
= 1.By (21),
we haveAs in the
proof
of Theorem2(a),
we derive from the theorems of Baker and Feldman thatlog M c11 log d
which, together
with(4), implies
log M c12k2. (32)
For a
prime q k dividing m - d,
we see from(21)
thatordq (m -
d +qd)
1.Therefore,
sincegcd(m, d)
=1,
we derive thatordq(m - d)
1 for everyprime
q
k. Assume thatP(M)
k. Thenwhich contradicts
(32).
DREMARK. Estimate
(9)
can besharpened. Suppose
that(1)
is satisfied and lete > 0. We refer to
(27)
and(4)
to derive thatwhere
C9
is aneffectively computable
numberdepending only
on e. Forall l,
weapply
Theorem 1 of[7]
to(26), together
with(4)
and 1 >30,
to obtainwhere
Clo
is aneffectively computable
numberdepending only
on 8.References
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= czl, Acta Math. 88, 241-251 (1952).3. P. Erdös, Note on the product of consecutive integers (II), J. London Math. Soc. 14, 245-249 (1939).
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