C AHIERS DE
TOPOLOGIE ET GÉOMÉTRIE DIFFÉRENTIELLE CATÉGORIQUES
D. V AN DER Z YPEN
Order convergence and compactness
Cahiers de topologie et géométrie différentielle catégoriques, tome 45, n
o4 (2004), p. 297-300
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© Andrée C. Ehresmann et les auteurs, 2004, tous droits réservés.
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297
ORDER CONVERGENCE AND COMPACTNESS
by
D. van der ZYPENCAHIERS DE TOPOLOGIE ET
GEOMETRIE DIFFERENTIELLE CATEGORIQUES
Volume XL V-4 (2004)
Rksum6. Soit
(P, )
un ensemble partiellement ordonn6 et soit T une topolo- gie compacte sur P qui est plus fine que la topologie d’intervalles. Alors Test contenu dans la topologie de convergence d’ordre. 1
1 Topologies
on agiven poset
On any
given partially
ordered set(P,!5)
there aretopologies arising
fromthe
given
order in a natural way(see
also[2]). Perhaps
the best known suchtopology
is the intervaltopology.
Set S- -f P B (x] :
x EPI,
andS+ = {PB[x) : x E P} where (x] = {y E P: y x} and [x) = {y E P : y > x}.
Then s = S- U S+ is a subbase for the interval
topology T2(P)
on P.There is another natural way to endow an
arbitrary poset ( P, )
with atopol-
ogy. We want to describe this
topology
in thefollowing.
A
(set) filter
r on(P, )
is anonempty
subset of thepowerset
of P such that- lll § 0
(Note
that the aboveconcept
can of course be defined forarbitrary sets.)
Forany subset A C P let the set
of
lower boundsof A
be denotedby Al - {x
E P : x a for all a EA}
and the set of upper boundsby Au = f x
EP : x > a for all a E A}. If S is a
collection of subsets of P then we setSl
=U {Sl : S
ES}, similarly
set su =U{Su :
S ES}.
Let A C P be a subset
of a poset
P andy E P.
We saythat y
is the infimumof A if y
is thegreatest
elementof Al
and write/B
A = y.Dually
we defineAMS subject classification (2000): 06B15, 06B30
Keywords: interval topology, order convergence, order topology, compact ordered spaces
298
the supremum of
A,
writtenV
A. Note that ingeneral,
suprema and infima need not exist.Let F be a filter on a poset P and let x E P. We say that F
order-converges to x,
insymbols 0+z,
if/B Fu
= x= B/ Fl.
Note that theprincipal
ultrafilter
consisting
of the subsets of P that contain xorder-converges
to x.Now we are able to define the order convergence
topology To(P) (called
order
topology
in[1])
on anygiven poset
Pby:
ro(P) = {U
C P : for any x E U and any filter 0 with F -->xwe have U E
F}.
It is
straightforward
toverify
that this is atopology. Indeed, To(P)
is thefinest
topology
on P such that order convergenceimplies topological
con-vergence
(which
is not hard to proveeither).
We will make constant use ofthe
following
facts:FACT 1.1. Let P be a poset, let F be
a filter
on P. Then:3.
Suppose
F --> x.If x
a thenP B (a]
E F.Dually if x 1:-
b thenPB[b) E F.
4.
If F --> x and 9
isa filter
on Pwith G C
F thenG --> x.
Proof
Theproofs
of assertions 1 and 2 arestraightforward,
and assertion 3 followsdirectly
from[1],
p. 3. We prove assertion 4. SinceG C Fu
itsuffices to show that
Gu
9[x)
in order toget /B Gu =
x. Assume that thereis y E Gu B [x). By
assertion1, (y]
E9.
Since wehave x
y, weget
P B (y] E F C 9 (by
assertion3).
So(y]
n(P B (y]) = 0
Ewhich
is acontradiction. The statement
V 91
= x isproved similarly.
02 The result
Note that
1.1,
assertion 3implies
that for anyposet P,
the intervaltopology ri(P)
is contained in the order convergencetopology To(P).
Thefollowing
theorem connects the
concepts
of intervaltopology,
order convergence and compactness.299.
THEOREM 2.1. Let
(P, )
be a poset.If T is a
compacttopology
on Psuch that
T;(P)
C T, then T CTo(P).
Proof. Suppose
thatW E r B To(P).
Then there is x E W and a filter F onP such that F --> x and
W 1:.
F.The
strategy
now is to find an ultrafilter on the closed setQ
:=P B
W of(P, T)
that does not converge to anypoint
ofQ
withrespect
to thesubspace topology
of(P, T)
onQ.
This willimply
thatQ
is anon-compact
closed subset of(P, T),
which in turnimplies
that(P, T)
is notcompact.
Note that every element of .F intersects
Q (otherwise
we would have W E.
So 0 U{Q} is a
filter base which is contained in some ultrafilter U.Moreover, by 1.1,
assertion4,
the ultrafilter Lforder-converges
to x.It is easy to check that
is an ultrafilter on
Q (this
uses of course the fact thatQ
is a member ofU).
Claim:
U|Q
does not converge to any y EQ
withrespect
tor|Q,
thetopol-
ogy on
Q
inducedby
T.Proof of
Claim: Pick any y EQ. First,
we know that x E W and y EQ, whence x =1=
y.Suppose
that thefollowing
holds in P:(A)
For all z E Uu we havey z
and for all z’E Ul
wehave
y >
z’.Then
by
definition of order convergence this wouldimply y
x, sincex =
AU’,
andsimilarly
we wouldget y >
x, a contradictionto x #
y.So, (A)
must befalse,
and without loss ofgenerality
we may assume that there is a zo E ?,f"with y i
zo.By 1.1,
assertion1,
weget (z0]
E U whichimplies
Since y f
zo we also haveBecause T contains the interval
topology Ti(P),
statement(*)
aboveimplies
that the set
300
is an open
neighborhood of y in (Q, r|Q).
But since BE U|Q and V = QBB,
we have
V E U|Q,
soU|Q
does not convergeto y
withrespect
to7-L.
Sincey E
Q
wasarbitrary,
the claim isproved.
The claim now shows that
Q
=P B
W’ is aclosed, non-compact
subset of(P,T).
So(P,T)
cannot becompact.
DThis theorem has a direct consequence for
Priestley
spaces, i.e.compact totally
order-disconnected ordered spaces as introduced in([3], [4]).
COROLLARY 2.2.
If (P,
T,) is a Priestley
space, then T CT,(P).
ACKNOWLEDGEMENT: The author wishes to thank Jana Flaskova for
point- ing
out a mistake in theproof
of fact 1.1 andproviding
a more direct argu- ment.References
[1] ] M.Erné, Topologies on products of partially ordered sets. III. Order convergence and order topology, Algebra Universalis 13 (1981), no. 1, 1-23.
[2] G. Gierz, H. Hofmann, K. Keimel, J. Lawson, M. Mislove, D. Scott: A Compendium
of Continuous Lattices, Springer-Verlag, 1980.
[3] H.A.Priestley, Representation of distributive lattices by means of ordered Stone spaces, Bull. London Math. Soc. 2 (1970), 186-190.
[4] H.A.Priestley, Ordered topological spaces and the representation of distributive lat- tices, Proc. London Math. Soc. (3) 24 (1972), 5072014530.
D. van der Zypen
Mathematical Institute 24-29 St Gile’
Oxford OX 1 3LB Great Britain
vanderzy@maths.ox.ac.uk