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www.elsevier.com/locate/anihpc

Regularity results for degenerate elliptic systems

Michael Pingen

Fachbereich Mathematik, University of Duisburg-Essen, Lotharstr. 65, 47048 Duisburg, Germany Received 22 December 2006; accepted 12 February 2007

Available online 1 September 2007

Abstract

We prove regularity results for certain degenerate quasilinear elliptic systems with coefficients which depend on two different weights. By using Sobolev- and Poincaré inequalities due to Chanillo and Wheeden [S. Chanillo, R.L. Wheeden, Weighted Poincaré and Sobolev inequalities and estimates for weighted Peano maximal functions, Amer. J. Math. 107 (1985) 1191–1226; S. Chanillo, R.L. Wheeden, Harnack’s inequality and mean-value inequalities for solutions of degenerate elliptic equations, Comm. Partial Differential Equations 11 (1986) 1111–1134] we derive a new weak Harnack inequality and adapt an idea due to L. Caffarelli [L.A. Caffarelli, Regularity theorems for weak solutions of some nonlinear systems, Comm. Pure Appl. Math. 35 (1982) 833–838]

to prove a priori estimates for bounded weak solutions. For example we show that every bounded weak solution of the system

Dα(aαβ(x, u,u)Dβui)=0 with|x|2|ξ|2aαβξαξβ |x|τ|ξ|2,|x|<1,τ(1,2)is Hölder continuous. Furthermore we derive a Liouville theorem for entire solutions of the above systems.

©2007 Elsevier Masson SAS. All rights reserved.

Résumé

Nous prouvons des résultats de régularité pour certains systèmes elliptiques quasi linéaires dégénérés avec des coefficients dépendant de deux poids différents. En employant des inégalités de Sobolev- et Poincaré dues à Chanillo et Wheeden [S. Chanillo, R.L. Wheeden, Weighted Poincaré and Sobolev inequalities and estimates for weighted Peano maximal functions, Amer. J. Math.

107 (1985) 1191–1226 ; S. Chanillo, R.L. Wheeden, Harnack’s inequality and mean-value inequalities for solutions of degenerate elliptic equations, Comm. Partial Differential Equations 11 (1986) 1111–1134] nous déduisons une nouvelle inégalité de Harnack et adaptons une idée due à L. Caffarelli [L.A. Caffarelli, Regularity theorems for weak solutions of some nonlinear systems, Comm. Pure Appl. Math. 35 (1982) 833–838] pour prouver des évaluations a priori pour des solutions limitées et faibles. Par exemple, chaque solution limitée et faible du système−Dα(aαβ(x, u,u)Dβui)=0 avec|x|2|ξ|2aαβξαξβ|x|τ|ξ|2,|x|<1, τ(1,2)est continue selon Hölder. De plus, nous déduisons un théorème de Liouville pour les solutions entières des systèmes ci-dessus.

©2007 Elsevier Masson SAS. All rights reserved.

MSC:35D10; 35J70; 35J45

Keywords:Regularity of weak solutions; Degenerate elliptic systems; Harnack inequality; Liouville theorems

This research was supported by the Deutsche Forschungsgemeinschaft.

E-mail address:michael.pingen@uni-duisburg-essen.de.

0294-1449/$ – see front matter ©2007 Elsevier Masson SAS. All rights reserved.

doi:10.1016/j.anihpc.2007.02.008

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1. Introduction

We consider weak solutions of degenerate elliptic systems of the form

Dα

Aαβ(x, u,u)Dβui

=fi(x, u,u) (i=1, . . . , m) (1)

in a domain Ω ⊂Rn, where aαβ(x):=Aαβ(x, u(x),u(x)) are measurable and symmetric coefficients and f (x, u,u)is a measurable function. Here and in the sequel, we use the summation convention: repeated Greek indices are to be summed from 1 ton, repeated Latin indices from 1 tom. We assume there exist measurable weights v(x), w(x) >0 a.e. inΩ with the property

w(x)|ξ|2aαβ(x)ξαξβv(x)|ξ|2ξ∈Rn. (2)

Furthermore we require the following structure conditions:

1. supΩ|u|M <∞.

2. |f (x, u, p)|aQ(x, p)andu(x)·f (x, u, p)aQ(x, p)for a.e.xΩand for allp∈Rn×mwith somea0, a∈R, whereQ(x, p):=aαβ(x)piαpiβ.

The notion of a weak solution of (1) will be defined in Section 4; to prove regularity for weak solutions of (1) the weightsvandwhave to satisfy three further conditions, which we will state exactly in Section 2. Roughly speakingw andz:=vw2 have to be doubling weights and have to fulfill a weighted Poincaré- and a weighted Sobolev inequality. We will show that the weightsv(x)= |x|andw(x)= |x|τ withτ∈ [1,2)inB1(0)⊂Rn,n3 satisfy these conditions.

Optimal regularity results for weak solutions of uniformly elliptic systems of type (1) are well known and due to Hildebrandt and Widman [9], Wiegner [17,18] and Caffarelli [3]. For the case of equal weights, i.e.v=w, which be- long to the Muckenhoupt classA2(see Section 2 for explicit definitions), Fabes, Kenig and Serapioni [7] have proven Hölder continuity for weak solutions of an elliptic equation. For certain different weights, Chanillo and Wheeden [5] proved regularity for weak solutions of elliptic equations, while for degenerate elliptic systems only very little is known. Baldes [1] and Baoyao [2] proved some results for equal weights, e.g. weak solutions of systems with bounded weightsv=wA2are Hölder continuous provided the smallness conditiona+aM <1 holds. The results in this paper are of much more general nature than in [1] or [2], and, in fact, are the first regularity results for singular systems with different weights.

Our proof uses an idea of L. Caffarelli [3] who proved a priori estimates for weak solutions of certain uniformly el- liptic systems. His main tool was a weak Harnack inequality for supersolutions of a uniformly elliptic linear equation;

we will prove such a Harnack inequality for solutions of degenerate (in the above sense) elliptic equations in Sec- tion 3. The proof of this Harnack inequality is based upon a method of Trudinger [16] in which a Harnack inequality for solutions of some mildly degenerate elliptic equations was shown. Our regularity result reads as follows:

Theorem 1.1.Letube a bounded, weak solution of (1)inΩ⊂Rn. The coefficientsaαβare required to fulfill(2)with admissible weightswandv(see Section2). Under the assumptiona+aM <2uis Hölder continuous and for every ΩΩthere exist constantsC=C(n, a, a, M, Ω, Ω) >0andα=α(n, a, a, M) >0, such that

[u]α,ΩC. (3)

In the last section we also show a Liouville theorem for entire solutions of elliptic systems, whose coefficients are degenerate in an arbitrary large compact subset ofRnand uniformly elliptic outside this compact set, more precisely:

Theorem 1.2.Letube a bounded, weak solution of (1)inRn. The coefficientsaαβare assumed to be of type(2)in a ballBR(0)⊂Rnwith admissible weightswandvand to be uniformly elliptic outside this ball. Ifa+aM <2, then u=const. a.e. inRn.

This result extends a Liouville theorem for uniformly elliptic systems due to Hildebrandt and Widman [10] and Meier [11].

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2. The Muckenhoupt classesAp and conditions for the weights

The Muckenhoupt classes are defined in the paper [12] by Muckenhoupt in connection with Hardy functions. Let wL1loc(Rn)be a nonnegative function.

Definition 2.1.Let 1< p <∞. The weightwis an element ofAp, if sup

BR⊂Rn

1

|BR|

BR

w(x) dx 1

|BR|

BR

w(x)p11dx p1

=:Cp<, (4)

wis to be said of classA, if for every >0 there exists aδ >0 with the property that for every measurableEBR with|E|< δ|BR|the inequalityw(E)w(BR)holds, wherew(E)=

Ew(x) dx.

From [13] and [6] we inferA=

p>1Ap. A result due to Muckenhoupt and Wheeden [14], p. 223 implies the doubling propertyfor anywA:

w(B2R)Kw(BR) with someK >0. (5)

We require the following conditions for the weightswandz=vw2 (cf. [5]):

(1) w, zD, i.e. the doubling property holds:w(B2R)Cw(BR)andz(B2R)Cz(BR)with a constantC >0 independent ofR.

(2) The following Poincaré inequality holds: There exists ak >1 such that for allBRΩ and allfC1(BR)the inequality

1 z(BR)

BR

f − 1 z(BR)

BR

f z dx 2kz dx

2k1

CR

1 w(BR)

BR

|∇f|2w dx 12

(6) holds with a constantCindependent off.

(3) The following Sobolev inequality holds: There exists ak >1 such that for allBRΩ and allfC01(BR)the inequality

1 z(BR)

BR

|f|2kz dx 1

2k CR

1 w(BR)

BR

|∇f|2w dx 1

2

(7) holds with a constantCindependent off.

Fabes, Kenig and Serapioni [7] showed that in the casev=wA2conditions (2) and (3) are satisfied. In the case of different weights, Chanillo and Wheeden [4] proved that condition (2) and (3) hold, ifwA2,zDand if there is aq >2 such that for all ballsBR, whose centers are inB2R, thebalance condition

s

z(BsR) z(BR)

1

q C

w(BsR) w(BR)

1

2

(8) holds for alls(0,1).

3. A weak Harnack inequality

To give a definition of a weak solution of a degenerate elliptic equation Dα

aαβ(x)Dβu

=0 (9)

with coefficientsaαβ(x)which satisfy (2) we first need to define the spaceH21(Ω, v, w), wherevandware weights with the properties (1)–(3) of Section 2.

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Definition 3.1.H21(Ω, v, w)is defined as completion ofC1(Ω)with respect to the norm u 1,2,Ω=

Ω

aαβ(x)DαuiDβuidx+

Ω

u2v dx.

H˚21(v, w, Ω)denotes the completion ofC1c(Ω)with respect to the norm u 1,2,0,Ω=

Ω

aαβ(x)DαuiDβuidx.

Remark.It is possible to estimate · 1,2,Ωas follows:

Ω

|∇u|2w dx+

Ω

u2v dx u 21,2,Ω

Ω

|∇u|2v dx+

Ω

u2v dx <.

If ukC1(Ω)is a sequence withukuinH21(Ω, v, w), then uk and∇uk converge inL2(Ω, v)andL2(Ω, w) resp. If limk→∞uk=v, defineu:=v;uis well defined (cf. [5], §2).

Definition 3.2.uH21(Ω, v, w)is a weak subsolution of (9), if

Ω

aαβ(x)DβuDαφ dx0 (10)

holds for everyφH˚21(Ω, v, w), φ0.uis called a weak supersolution, if−uis a weak subsolution anduis called a weak solution, ifuis a weak subsolution and a weak supersolution.

The main result of this section is

Theorem 3.3. Let u be a nonnegative weak supersolution of (9) in Ω ⊂Rn. Then for any ball BRΩ with

z(BR)

w(BR)C1and anyα, β, γ satisfying0< α < β <1,0< γ < kthe estimate 1

z(BβR)

BβR

|u|γz dx 1

γ C(n, α, β, γ , C1)inf

BαR

u (11)

holds, wherek >1is the constant from the Sobolev- and Poincaré inequalities.

The proof of Theorem 3.3 is divided into three lemmatas, extended proofs of these lemmatas can be found in [15].

All these lemmatas are based on a method developed by Trudinger [16].

Lemma 3.4.Letube a weak subsolution of (9)inΩ⊂Rn. Then for everyBRΩwithw(Bz(BR)

R) C1we have for any 0< α < β <1the estimate

sup

BαR

uC(n, α, β, C1) 1

z(BβR)

BβR

|u+|2z dx 1

2

. (12)

Proof. Forδ1 and 0< N <∞we define F (u)=FδN(u)=

(u+)δ, uN, δNδ1u−1)Nδ, u > N.

Useφ(x)=η2(x)F (u),η0, η∈Cc1(BR)as test function in (10). We arrive at

Ω

η2F(u)|∇u|2w dx2

Ω

η|ηx|F|∇u|v dx. (13)

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The inequalityF (u)u+F(u)is easily derived; by using this relation, the Hölder inequality yields

Ω

η2(x)F(u)|∇u|2w dxC

Ω

ηx2(u+)2Fz dx. (14)

Define G(u):=

u 0

F(t ) 12dt= √

δδ+21|u+|δ+12 , uN,

δNδ21|u|, u > N.

With (14) we infer

Ω

η2|∇G|2w dxC

Ω

η2x(u+G)2z dx.

In connection with the Sobolev inequality andGu+Gthis estimate implies 1

z(BR)

BR

|ηG|2kz dx 1

2k CR

z(BR) w(BR)

C1

1 z(BR)

BR

ηx2(u+G)2z dx 1

2

. (15)

Setq:=δ+21 and take theqth root of (15). Then chooseandσ in a way thatα < σβ andηin a way that suppηBσ R,η≡1 inBR,|ηx|2)R. IfN= ∞we seeG(u)=qδ(u+)q; by using the doubling property for zwe obtain

1 z(BR)

BR

(u+)2kqz dx 1

2kq

Cq σ

1

q 1 z(BβR)

Bσ R

(u+)2qz dx 1

2q

. (16)

Iteration of (16):

Defineq0:=1,qi :=kqi1=ki, furthermore seti=α+α)1+i,σi=i1. With this choice ofqi andi

we infer sup

BαR

u

l=0

Cql

ll+1

1

ql 1 z(BβR)

BβR

(u+)2z dx 1

2

. (17)

We can estimate the infinite product in (17) by using the geometric sum. Thus, we have sup

BαR

uC(n, α, β, C1) 1

z(BβR)

BβR

|u+|2z dx 12

.

This completes the proof of Lemma 3.4. 2

Lemma 3.5.Under the hypotheses of Theorem3.3andα < β, we have 1

infBαRuexp

C− 1

z(BβR)

BβR

loguz dx

. (18)

Proof. W.l.o.g. we assumeu >0 (in caseu0 we use Levi’s Theorem to derive the assertion). Testing (10) with the functionφ(x)=η(x)u1(x),ηCc1(Ω), η0 yields the estimate

Ω

aαβ(x)DβuDαηu1dx

Ω

aαβ(x)DβuDαuηu2dx0.

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Setv:=log(ut), wheretdenotes a positive constant which will be specified later. We see thatvis a weak subsolution of (9) and with Lemma 3.4 we infer

sup

BαR

vC 1

z(BβR)

BβR

|v+|2z dx 1

2

. (19)

To estimate the right-hand side of (19) we test (10) withφ(x)=η2(x)u1(x),ηCc1(Ω). With (2) and the Hölder inequality we arrive at

Ω

η2u2|∇u|2w dxC

Ω

η|ηxu|u1v dxC

Ω

ηx2z dx 1

2

Ω

η2|∇u|2u2w dx 1

2

.

It follows

Ωη2u2|∇u|2w dxC

Ωη2xz dx.

Chooseηin a way thatη≡1 inBβR, suppηBR,|ηx|(12β)R. From the last inequality we conclude together with the doubling property and the fact|∇v|2=u2|∇u|2the estimate

BβR

|∇v|2w dxC 1

R2

BβR

z dx

.

We definet by means of logt=z(B1βR)

BβRloguz dx, then the weighted mean value ofv is zero and the Poincaré inequality in connection with the above inequality yields

1 z(BβR)

BβR

|v|2kz dx 1

2k C

z(BβR) w(BβR)

1 z(BβR)

BβR

z dx 1

2 C(n, β, C1).

Combining this estimate with (19) we infer sup

BαR

v=logt+log 1

infBαRu

C.

By considering the definition oft we finally arrive at

BinfαRu 1

exp

C− 1

z(BβR)

BβR

loguz dx

. 2

Lemma 3.6.Under the hypotheses of Theorem3.3andα < β, we have 1

z(BαR)

BαR

|u|γz dx 1

γ exp

C+ 1

z(BβR)

BβR

loguz dx

. (20)

Proof. We may again assumeu >0. Setf=v=log(ut)+(for the definition oft see the proof of Lemma 3.5) and test the weak formulation withφ(x)=η2(x)u1(x)(fδ(x)+(2δ)δ), whereδ1,ηCc1(BR),η0. By using the ellipticity condition we conclude

Ω

η2u2

fδ+(2δ)δδfδ1

|∇u|2w dxC

Ω

η|ηx|u1

fδ+(2δ)δ

|∇u|v dx.

Now we use the inequalityδfδ112(fδ+(2δ)δ)in connection with|∇f|2=u2|∇u|2and the Hölder inequality to infer

Ω

η2

fδ+(2δ)δ

|∇f|2w dxC

Ω

η2x

fδ+(2δ)δ z dx.

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By using once againδfδ112(fδ+(2δ)δ)and taking the elementary inequalityfδ+(2δ)δ2(fδ+1+(2δ)δ)into account we obtain

δ

Ω

η2fδ1|∇f|2w dxC

Ω

η2x

fδ+1+(2δ)δ

z dx. (21)

Letq:=δ+21>1, by applying the Sobolev inequality toηfqH˚21(BR, v, w)we find under consideration of (21) 1

z(BR)

BR

|ηfq|2kz dx 1

2k CR

1 w(BR)

BR

η2xfδ+1+η2+1)2fδ1|∇f|2 w dx

1

2

C

qR

z(BR) w(BR)

C1

1 z(BR)

BR

xfq)2z dx+(2δ)δsup

BR

|ηx|2 1

2

.

Chooseandσ in a way thatα < σβ andηin a way that suppηBσ R,η≡1 inBR and|ηx|2)R. With this choice of, σ andη, taking theqth root in the last estimate yields

1 z(BR)

BR

f2qkz dx 2kq1

Cq1q)1q

Cq+ 1

z(Bσ R)

Bσ R

f2qz dx 2q1

. (22)

Now setqi=ki1,i=α+2iα),σi=i+2iα), we obtain 1

z(BiR)

BiR

f2ki+1z dx 1

2ki+1

(C2iki)

1 ki

Cki+

1 z(BσiR)

Bσi R

f2kiz dx 1

2ki .

In the next step we iterate this inequality; afteri−1 iteration steps we arrive at 1

z(BiR)

Bi R

f2ki+1z dx 1

2ki+1

i j=1

Ckj i l=j

(Ckl2l)

1 kl +

i j=1

(Ckj2j)

1 kj

1 z(BβR)

BβR

f2kz dx 1

2k

. (23)

We estimate the series and products in (23) and then we find with the doubling property and the Hölder inequality the following estimate for allp >2k:

1 z(BαR)

BαR

fpz dx 1

pC

p+ 1

z(BβR)

BβR

f2kz dx 2k1

. (24)

By considering the power series expansion of ep0f forp0(0,e1)we infer by using (24) and the Stirling approxi- mationn! ≈√

2π n(ne)nfor largenthe estimate 1

z(BαR)

BαR

ep0fz dxCe(

1 z(BβR )

BβRf2kz dx)2k1

. (25)

Sincef =vthe right-hand side of (25) is bounded by the proof of Lemma 3.5. Thus 1

z(BαR)

BαR

ep0fz dx 1

p0

C. (26)

In the remainder of the proof we have to estimate ut Lγ(z,BαR)by ut Lp0(z,BαR)(α < α< β). For this, we remark that−uis a subsolution of (9); by modifying the functionF (u)appearing in the proof of Lemma 3.4 in the sense that δ(−1,0)we see that the estimate (16) holds also for q(0,12). For the iteration process we set q0:=2kγ ,

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qi := qik1 →0, i→ ∞. After finitely many iteration steps we achieve 2qi < p0<e1. From (26) and (16) (for q(0,1/2)) we infer with the definition oft

1 z(BαR)

BαR

uγz dx 1

γ exp

C+ 1

z(BβR)

BβR

loguz dx

. 2

Proof of Theorem 3.3. Multiply (18) and (20). 2

4. Results for weak solutions of degenerate elliptic systems

Now we define what we will understand under aweak solutionof a system of type (1):

Definition 4.1.uH21(Ω, v, w,Rm)is called a weak solution of (1), if

Ω

aαβ(x)DβuDαφ dx=

Ω

f (x, u,u)φ dx (27)

holds for allφH˚21(Ω, v, w,Rm).

For the proof of Theorem 1.1 we now can use an idea of L. Caffarelli [3]. In fact we only have to replace the weak Harnack inequality for weak supersolutions of uniformly elliptic equations by the weak Harnack inequality proven in Section 3 (Theorem 3.3).

Examples.

1) v(x)=w(x)= |x|α, xBR(0)⊂Rn andα >n. Ifα(n, n) it is easy to show thatv=wA2 and if α >n+2 we can interpret|x|α as a weight which arises from a quasiconformal mapping (cf. [7], pp. 105–

112). This weight has also the properties which were needed in the proof of Theorem 3.3 (cf. [7]) and so it is an admissible weight for the system (1).

2) v(x)=w(x)=(log|x|)k,xB1/2(0)⊂Rn,k∈2N.

3) v(x)=w(x)= |x|α(log|x|)2,xB1/2(0)⊂Rn,α(n, n).

4) v(x)= |x|,w(x)= |x|τ,τ(1,2),xB1(0)⊂Rn, n3. It is obvious thatwA2,z= |x|2τD. In view of a result due to Chanillo and Wheeden [4] it is enough to show that the balance condition (8) holds. We remark that forα >0 andaBR(0)there are positive constantsc1andc2with the property

c1Rn

R+ |a|α

BR(a)

|x|αdxc2Rn

R+ |a|α

. (28)

From (28) we infer w(Bz(BR)

R)C1; forq(2,n+2nτ2]we have for anys(0,1)the estimates s

z(BsR(a)) z(BR(a))

1

q Cssnq and

w(BsR(a)) w(BR(a))

1

2 sn2sτ2.

Sincessnq Csn+2τ the validity of (8) is shown.

Liouville theorem for entire solutions.Here, we assume the coefficientsaαβ(x)satisfy the estimate 1

Cs(x)|ξ|2aαβ(x)ξαξβCt (x)|ξ|2 (29)

withC1 and s(x)=

w(x), |x|< L,

1, |x|L, t (x)=

v(x), |x|< L, 1, |x|L, wherewandvare weights which satisfy the conditions of Section 2.

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The proof of the Liouville Theorem uses an idea of Meier [11], who proved the corresponding Liouville theorem for uniformly elliptic systems. First we have to consider some lemmatas:

Lemma 4.2.Letube a bounded, weak solution of (1)in a domainΩ⊂Rn. Ifa<1andξ ∈Rm is a vector with

|ξ|1aa, thenDα(aαβ(x)Dβ|uξ|2)0inΩ.

Proof. We useφ=η(uξ ),ηCc(Ω),η0 as a test function in the weak formulation (27) and take the structure conditions of the introduction into account. 2

With the notationz1(x):=ts(x)2(x)we can formulate the next lemmatas.

Lemma 4.3. Let B4L(0)Ω and u be a bounded, weak, nonnegative supersolution of Dα(aαβ(x)Dβu)=0 in Ω⊂Rn with coefficientsaαβ(x)of the form(29), furthermore let zs(B1(BL)

L) C1. Then we have for anyR >0 with B4R(0)Ωthe estimate

1 z1(B2R)

B2R(0)

uz1dxC(n, C1) inf

BR(0)u.

Proof. If B4R(0)BL(0), the lemma is a direct consequence of Theorem 3.3 with γ =1 and suitable α, β. If BL(0)B4R(0)we can prove similarly to [8], pp. 195–198 a Harnack inequality for supersolutions ofLu=0 with uniformly elliptic coefficients on annular regionsB4SBS(SL), i.e.

1 z1(Bβ1SBβ2S)

Bβ

1SBβ

2S

uz1dxC inf

Bα

1SBα

2S

u (30)

with 1< β2< α2< α1< β1<4.

The main difference in the proof of (30) compared with [8] is to construct suitable test functions on the correspond- ing annular regions.

Chooseα, α1, β, β1in a way that 1< α < α1<2,α1< β1< β <4 andBα1LBβ1R. We conclude 1

z1(BβR)

BβR

uz1dx= 1

z1(BβRBαL)+z1(BαL)

BβRBαL

uz1dx+

BαL

uz1dx

1

z1(BβRBαL)

BβRBαL

uz1dx+C 1 z1(B2L)

B2L

uz1dx

C inf

Bβ1RBα1L

u+C inf

Bα1L

uCinf

BR

u.

Here, we used (30) and Theorem 3.3.

IfBL(0)B2R(0)we chooseβ=2, β1=3/2, α1=5/4, α=9/8 to arrive at the assertion. IfBL(0)B2R(0)we choose someβ(2,4)withBL(0)BβR(0); the doubling property ofz1yields the desired estimate. 2

Lemma 4.4.Letu be a weak solution ofDα(aαβDβu)0inB4R(0)⊂Rn with coefficients of the form(29). If

z1(BR)

s(BR) C1, then there is a constantδ(n, C1)(0,1)with the property sup

BR(0)

u(1δ) sup

B4R(0)

u+δ 1 z1(BR)

BR(0)

uz1dx.

Proof. From Lemma 4.3 we infer for the nonnegative supersolution supB4R(0)uuthe estimate 1

z1(B2R)

B2R

sup

B4R

uu

z1dxCinf

BR

sup

B4R

uu

.

(10)

With the help of the doubling property we can estimate the left-hand side from below by C˜ 1

z1(BR)

BR

sup

B4R

uu

z1dx

and we infer C˜ Csup

B4R

uC˜ C

1 z1(BR)

BR

uz1dxsup

B4R

u−sup

BR

u. 2

Lemma 4.5.Letube a bounded, weak solution of(1)inRnwith coefficientsaαβ(x)of the form(29). Ifzs(B1(BR)

R) C1 for someRL2 anda<1, then we have

(i) limR→∞ 1 z1(BR)

BR(0)u(x)z1dx=: ¯uexists and| ¯u| =supRn|u| =M.

(ii) limR→∞ 1 z1(BR)

BR(0)|u− ¯u|2z1dx=0.

(iii) supRn|uξ| = | ¯uξ| ∀ξ∈Rmwith|ξ|1aa.

Proof. (i) In view of Lemma 4.2 we have−Dα(aαβ(x)Dβ|uξ|2)0∀ξ∈Rmwith|ξ|1aa. From Lemma 4.4 we infer by letting R→ ∞the estimate supRn|uξ|2limR→∞ 1

z1(BR)

BR(0)|uξ|2z1dx. It’s obvious that the reverse inequality is also true. Thus,

Rlim→∞

1 z1(BR)

BR(0)

|uξ|2z1dx=sup

Rn |uξ|2. (31)

Since 1 z1(BR)

BR(0)

|uξ|2z1dx= 1 z1(BR)

BR(0)

|u|2z1dx−2ξ· 1 z1(BR)

BR(0)

uz1dx+ |ξ|2

we see in view of (31) that limR→∞ξ·z1(B1R)

BR(0)uz1dxexists and we infer sup

Rn |uξ|2=M2+ |ξ|2−2ξ· lim

R→∞

1 z1(BR)

BR(0)

uz1dx. (32)

Setτ :=1aMa and chooseu¯∈Rmin a way that| ¯u| =Mand supRn|u+τu¯| =(1+τ )M. Withξ:= −τu¯we observe from (32)

M2= lim

R→∞u¯ 1 z1(BR)

BR(0)

uz1dx.

Since| ¯u|,|z1(B1R)

BR(0)uz1dx|Mwe conclude assertion (i).

(ii) We have 1 z1(BR)

BR(0)

|u− ¯u|2z1dx= | ¯u|2+ 1 z1(BR)

BR(0)

|u|2z1dx−2u¯· 1 z1(BR)

BR(0)

uz1dx.

By lettingR→ ∞we infer from the proof of (i)

Rlim→∞

1 z1(BR)

BR

|u− ¯u|2z1dx=M2+M2−2M2=0.

(iii) (32) and (i) yield for everyξ∈Rmwith|ξ|1aa the equation sup

Rn |uξ|2= | ¯u|2+ |ξ|2−2ξ· ¯u= | ¯uξ|2. 2

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