A NNALES DE L ’I. H. P., SECTION C
F LORIAN M EHATS
J EAN -M ICHEL R OQUEJOFFRE A nonlinear oblique derivative boundary value problem for the heat equation. Part 2 : singular self-similar solutions
Annales de l’I. H. P., section C, tome 16, n
o6 (1999), p. 691-724
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A nonlinear oblique derivative
boundary value problem for the heat equation
Part 2: Singular self-similar solutions
Florian MEHATS
Centre
de Mathematiques Appliquees URA CNRS 756 Ecole Polytechnique, 91128 Palaiseau Cedex, FranceJean-Michel
ROQUEJOFFRE
UFR-MIG, Universite de Toulouse III UMR CNRS 5640 118, route de Narbonne, 31062 Toulouse Cedex, France
Vol. 16, n° 6, 1999, p. 691-724 Analyse non linéaire
ABSTRACT. - This paper continues the
study
started in[12].
In the upperhalf-plane,
consider theelliptic ~- zUz )
=0,
submitted to the nonlinear
oblique
derivativeboundary
conditionUx
=UUz
on the axis x = 0. The solution of this
problem
appears to be the self- similar solution of the heatequation
with the sameboundary
condition. Asc goes to
0,
the function U~ converges to the non trivial solution U of thecorresponding degenerate problem.
Moreover there exists zo > 0 such that U vanishes for z > zo, is C°° on]0, z0[ R+,
is continuous on theboundary x
= 0 and is discontinuous on the@
Elsevier,
ParisKey words: Nonlinear oblique derivative condition, degenerate elliptic problems, self-
similar solution.
RESUME. - Cet article
poursuit
Fetude commencee dans[12]. Soit,
dans ledemi-plan supérieur, l’équation
=0,
soumise a la condition aux limites a derivee
oblique
non lineaireUx
=UUz
sur l’axe x = 0. La solution de ce
probleme apparait
comme la solutionAnnales de l’lnstitut Henri Poincaré - Analyse non linéaire - 0294-1449 Vol. 16/99/06/© Elsevier, Paris
692 F. MEHATS AND J.-M. ROQUEJOFFRE
autosemblable de
1’ equation
de la chaleur soumise a la meme condition auxlimites.
Lorsque é
tend vers0,
la fonction U~ converge vers la solution U duprobleme degenere correspondant.
Deplus
il existe un reel zo > 0 tel que U s’ annule pour z > zo, est C°°sur 0, zo [ x I~+,
est continue sur la frontierex = 0 et discontinue sur le
demi-axe {z
=0, x
>0 ~ .
©Elsevier,
Paris1. INTRODUCTION AND MAIN RESULTS
This paper continues the
study
initiated in[12].
Let us firstbriefly
recallthe
problem
dealt with and the main results obtained in[12].
We consider a nonlinear
oblique
derivativeboundary
condition for the heatequation,
in thehalf-plane (~+ _ ~ ( Z, X )
E R xThe above
system
arises inplasma physics (see [11] ]
for themodeling),
and describes the diffusive
propagation
of amagnetic
field in a uniformplasma,
in presence of aperfectly
conductive electrode which isplaced
onthe axis X = 0. The
non-homogeneous
condition at Z ~ -~ stands fora source of
magnetic
field.In some realistic
physical situations,
theparameter K
turns out to be verylarge [4].
The aim of thispart
is to let K - +00 in theseequations,
thanks to an
adequate scaling.
Introduce the smallparameter E
=1/ K2
and let us define the new variables
since we will
only
work in these variables wedrop
theprimes
at once.Equation (1.1.NH)
becomesAnnales de l’Institut Henri Poincaré - Analyse non linéaire
This paper is devoted to the behaviour of the self-similar solutions of
(1.2.NH)
as c --~ 0. Recall that self-similar solutions of(1.2.NH)
aresteady
solutions in the variables
Hence the self-similar
problem
associated to(1.2.NH)
readsThis
system
becomesdegenerate
as c -~ 0. Hence classical existenceand smoothness results
[2]
forelliptic equations
cannot beapplied directly.
Nevertheless,
the scheme used in[12]
to prove the C°°regularity
of theself-similar solution is robust
enough
withrespect
to c and will beadapted
here.
Let
formally ~
--~ 0 in(1.3NH).
Thedegenerate
self-similarproblem
writes ’
We denote
by ’lj; (z)
the solution ofLet us set u = U -
~;
this is the solution of the associatedhomogeneous problem.
Thestarting point
of ourstudy
is thefollowing result, proved
in
[ 12] :
THEOREM A.1.1
(Self-similar problem
with E >0). -
There exists aunique
solution U E C°°((~+ ) of ( 1.3NH).
Moreover we have thefollowing properties:
. U is
decreasing
with and x.’ ’ ’ ~
Such a result may be
classically
obtainedby
atopological degree argument
combined withstrong enough a priori estimates,
as in[9].
Wepresented
in[12]
an alternativemethod,
based on estimates of(~~)~
andVol. 16, n° 6-1999.
694 F. MEHATS AND J.-M. ROQUEJOFFRE
( ~cz ) 3
at theboundary,
which will turn out to be suitable in thepresent
context.
The main result of this paper is the
following
existence anduniqueness
theorem:
THEOREM l.l
(Convergence
to the solution of thedegenerate problem).
-
(i)
As ~ ~0,
andafter
extractionof
asubsequence,
the solution U~of (1.3NH)
converges in strong and a. e. to a weak solution Uof (1.4NH).
(ii)
There exists zo > 0 such that thisfunction
Uverifies
( 1.7)
U is discontinuousalong
the axis z =0, x
>0,
(1.9)
the traceof U
on{x
= continuous.This result illustrates the
rapid penetration
of themagnetic
field at theelectrode: we have U > 0 on a nontrivial
portion
of the axis{x
=0, z
>0~,
whereas the
magnetic
field does notpenetrate
on thepart {z
>0 ~
of thecathode,
i.e when x = +00.Because we do not know a
priori
whatregularity property
is satisfiedby
the weak solutions of(1.4NH), uniqueness
is notcompletely
trivial. A relevant definition of weak solution may be thefollowing
one: a functionU(z, x)
is an entropy solution of(1.4NH) if,
besidessatisfying
the minimal smoothnessassumptions
so that a weak formulation makes sense, has a BV trace at{x
=0~ ,
whose z-derivative is bounded from above. The solution constructed in Theorem 1.1 istrivially
anentropy
solution.. Armed with this definition we are able to prove the
following
result:THEOREM 1.2
(Uniqueness). -
There is aunique
entropy solution to Problem(1.4NH).
As a consequence, the whole sequence( U~ ) ~ ~ o
convergesto U.
Annales de l’Institut Henri Poincaré - Analyse non linéaire
The reason
why
this theorem holds is that the functionY(z, x) _
/ U(z’, x) dz is a viscosity solution,
in the sense given
in Crandall-
Ishii-Lions [5],
to theproblem
A
uniqueness
result for the aboveproblem
will be obtained in astraightforward
way.Uniqueness
ofentropy
solutions in this framework isanything
butsurprising
if one thinks about nonlinear conservationlaws,
fromwhich we have
obviously
borrowed theterminology:
for agiven
functionf {x)
EL1 (I~),
a functionu(x)
is anentropy
solution ofAu + (u2)’
=f (x)
if and
only
ifv(x) = x-~ u(y) dy
is aviscosity
solution of the Hamilton- Jacobiequation Av + (v’)2
=dy.
In this context, anentropy
solution isprecisely
a BV solution with bounded from abovex-derivative;
see
Lions-Souganidis [10]
for more details.As a final
introductory remark,
wepoint
out that the results of papers 1 and 2 remain valid if theboundary
condition isreplaced by Bx
=f ( B ) z ,
where
f
is aC1 nonnegative nondecreasing
function.The paper is
organized
as follows. The second section ismainly
devotedto the convergence
property (i), namely
stated inProposition
2.1below,
with
(1.5)
and(1.6).
Lemma 2.2implies (1.7). Next,
the third section is devoted to theproof
of theregularity
of the solution:(1.8)
is stated inProposition
3.4 and(1.9)
is stated inProposition
3.5. Section 4 is devoted touniqueness
ofentropy
solutions to(1.4NH). Finally,
in the last section weshow some numerical simulations that enable to visualize the function U and its different
properties.
2. NON-TRIVIAL WEAK SOLUTIONS
First recall several notations used in
[12].
If u is a function defined ondenotes its trace on the
boundary {x
=0~,
when it is welldefined;
as soon as no confusion is
possible,
we shall also denoteby u
this trace.The notation
will
stand for anintegral
calculated on theboundary
and CVol. 16, n° 6-1999.
696 F. MEHATS AND J.-M. ROQUEJOFFRE
will denote a
generic positive
constantindependent
of ~. For M >0,
we denoteby ~~
thestrip
Finally,
wewill,
as isclassical,
denoteby Co (I~+)
the set of allcompactly
supported
C°° funtions fromI~+
to R.Consider the solution U~ of
(1.3NH)
and setuE(z, x)
=UE(Z,
where ,
The
homogeneous problem
associated to(1.3NH)
writesRemark that -~ 1 - H a.e. in where H denotes the Heaviside function. Hence one can define
similarly
anhomogeneous problem
associated to
( 1.4H),
denoted( 1.4NH),
its solutionbeing
u = U - 1-1- H.PROPOSITION 2.1. - Let u~ be the solution
of ( 1.3H).
Then u~ converges -up to asubsequence-
to a weak solutionof ( 1.3H),
u EL2 ( If8+ )
nWe have u E
for
every M >0,
ux EL2 (~+),
qu E andthe convergence holds in the
following
sense:(2.1)
u~ -~ u inL2(l~+) weak,
in strong and a.e. in(2.2) u~ ~
Ux inL2(f~+)
weak and Uz in weak*,
(2.3)
qu in strong and a.e. inI~,
(2.4) ~yuz --~
quz in weak*,
where and denote
respectively
the spacesof
boundedmeasures on
~M
and R. Moreover we haveAnnales de l’lnstitut Henri Poincaré - Analyse non linéaire
Proof. -
In[ 12]
we remarked that’lj;é:
is a sub-solution of(1.3H)
and weconstructed a
super-solution
for thisproblem,
denoted’lj;é:
+ 11~ : we haveIn the rescaled
variables,
the function writesEstimate
(2.7)
enables to obtain someinformations
on the behaviour of U~ .Indeed,
as c 2014~0,
the lowerbound ~~
converges to 1 - Huniformly
oneach ] -
oo,-a]
U[a, +oo[,
a > 0.Moreover,
the upperbound ~~
+ A~converges to a function $
uniformly
on the sameinterval,
this limit ~being
definedby
Consequently
we deduce(2.5)
and(2.6).
Next, (2.7)
and theexponential decay
of the function A~ at theinfinity,
uniform with
respect
to ~,enable
to inferBy
TheoremA.1.1,
U~ isdecreasing along z
and x.Thus,
sinceuE: (z, x)
=U~ (z, x) -
isdecreasing
withrespect
to x and vanishes as x - +00. Therefore we haveVol. 16, nO 6-1999.
698 F. MEHATS AND J.-M. ROQUEJOFFRE and
Consequently
Hence, by compactness
and trace theorems([6], Chapter 5),
there existsu E
verifying
~yu E and suchthat,
after extraction ofa
subsequence,
we have(2.3), (2.4),
and theL1, A4b,
a.e., convergences stated in(2.1)
and(2.2).
Remark that since 0 Ué1,
we alsohave,
after anotherextraction,
where U = u + 1 - H.
Next, multiply (1.3H) by integrate
it over(~+
thenintegrate by parts.
We
get
the energy estimatesince we have 0 ~c~ 1 and
!7~
0(Theorem A.1.1).
HenceThis
completes
theproofs
of(2.1)
and(2.2).
It remains to see in what sense u is solution of the
limiting
model(1.4H).
For that it suffices to write a weak formulation of
(1.3H).
For allcp E we have
Properties (2.1)
and(2.2)
allow us to pass to the limit in the three linear terms. To treat the nonlinear one, we writeit 1 2 / Since 03C6
is
compactly supported, by (2.3)
we have03B3U03C6z
inL (R) strong.
Annales de l’lnstitut Henri Poincaré - Analyse non linéaire
Hence we can pass to the limit in this term, thanks to
(2.9).
Theasymptotic problem
writesfinally
Remark that it is
equivalent
to write this weak formulation for the functionU,
which is nonhomogeneous
at theinfinity:
(2.12NH)
The
following
lemma shows that the solution of thelimiting
sys- tem(1.4H)
is nontrivial,
i.e. that U is notequal
to 1 - H:LEMMA 2.2. - The
limiting function
U decreases withrespect
to z and x, is discontinuous on the axis~0~
xI~+
and u = U - 1 + Hverifies
Proof. -
Themonotonicity properties
are consequences of Theorem A.1.1 andProposition
2.1. Thediscontinuity
of U on~Q~
xRi
is immediate andcomes from
(2.7)
and theproperties
of thelimiting sub-/super-solutions
1 - H and ~.
Consider now the solution uE of
(1.3H). Straightforward
calculationsgive
Hence
(1.3H) implies
Thanks to
(2.7)
and thedecay properties
of forevery 8
>0,
there existsa
compact
subsetK8
CI~+
and 6-0 > 0 suchthat,
for all c co,Vol. 16, n 6-1999.
700 F. MEHATS AND J.-M. ROQUEJOFFRE Thus
By (2.1)
we can pass to the limit in thisintegral
as c --~0,
6being fixed;
then we let 8 --~ 0 to obtain
(2.13).
DSet zo =
sup{z
> 0 :~yU
> 0 a.e. on[0, z~ ~ .
This real number is well defined thanks to(2.6)
and Lemma2.2,
and verifies 0zo
3. REGULARITY OF THE SOLUTION 3.1. Smoothness
on ]0, zo [ x [0, +oo[ [
To prove the smoothness of U
on
wemainly
followthe scheme of
[12]
andalternatively
obtain interior andboundary
estimatesfor U~ and its derivatives. These estimates pass to the limit
U,
afterextraction of
subsequences
from UE;. The main difference with[12]
is that the
equation (1.4H)
insideI~+
isdegenerate
and the interiorAgmon-Douglis-Nirenberg
estimates[2]
cannot beapplied
in this context.Let 8 > 0 be fixed such that 8 zo . The function U~
being
non-increasing along z,
and thanks to the a.e. convergence of and to the above definition of zo, we canfind ~
> 0 and ~s > 0 such thatIf b is small
enough,
these constant realnumbers ~ and E 8 being fixed,
we define a cut-off function such that 0xi E C°° on
~0,
andIf M is a
positive
constant, we also define a C°° cut-off function in x,x2 (z, x)
=x2 (x),
such that 0x2 (x)
1 andThe constants M and 8 will be once and for all understood to be
large
-resp. small-
enough
for our purpose. We haveAnnales de l’lnstitut Henri Poincaré - Analyse non linéaire
In the
following lemmas,
we will obtain different estimates foru~,
and their derivatives on cv and H. For that we use several test functions in the weak formulation(2.11 )
of(1.3H).
These test functions will take the formBecause of the cut-off function xl, these functions cp may not be
C1 along
the axis
{0~
xR+.
Neverthelessthey
areregular enough,
as(2.11)
willbe written instead
In the
sequel,
orC(M, b)
denotequantities
which candepend
on band M but are
uniformly
bounded withrespect
to ~.LEMMA 3.1. - There exists ~03B4 > 0 such
that, for ~
~03B4, we haveProof. -
Let us first do thefollowing
remark. To in theregular
case studied in[12],
it was sufficient toplug
the test functionp in the weak formulation.
Here,
it is not sosimple,
since we do nothave an
L2((~+)
estimate of~cz independent
of c.Nevertheless,
thanks toa suitable test
function,
we shall obtain these two estimatesby
the sametime; they
are stated in(3.6).
Setting
the idea of the
proof
is to take the testfunction
= acp2 -03B203C61
in(3.5),
if a and
,~
arepositive
real numbers that will be madeprecise
later.. We first consider
only
pi in(3.5);
we treatseparately
the differentterms of this
expression, using (2.10), Uz 0, ’lj;él
0 and theproperties
of the cut-off functions xi and x2
(3.2), (3.3), (3.4).
The first term isVol. 16, nO 6-1999.
702 F. MEHATS AND J.-M. ROQUEJOFFRE
the first
integral
in theright
hand side is0(1)
thanks to(2.10).
For the other terms of(3.5)
we writePlugging
these estimates in(3.5),
we obtainfinally
.
Next,
with the test function cp2,(3.5)
can also be writtenWe estimate the different terms as follows:
Annales de l ’lnstitut Henri Poincaré - Analyse non linéaire
In the
right
hand side of thisequality, by (2.10),
the twointegrals
calculatedover are
C(l).
Theboundary integral
can also be writtenTo estimate the second term of the
right
handside,
it suffices to remark thatand
Therefore we have
The last term of
(3.9)
that we can estimatedirectly
isFinally (3.9)
reads. Let now a and
~3
be twopositive
real numbers. The test function a’P2 - in(3.5) gives
in fact the linear combination{,lj (3.8)+
a(3.11)} :
where
By (3.1)
and(3.2),
we haveUE(Z, 0)
> r~ on thesupport
of xi .Hence,
fora
large enough
and ET/2,
we haveVol. 16, nO 6-1999.
704 F. MEHATS AND J.-M. ROQUEJOFFRE Let us fix such an a ; there holds
To estimate the
integral Ii,
we use theinequality
Hence,
if wewrite,
for xM + 1,
and
setting
A = weget
Therefore
(3.12) yields
Next
by (3.2)
it comes(3.6)
isproved.
Remark that this estimate works because we consideronly
the z > 0.
The estimate
(3.7)
is immediate and comesdirectly
from(1.3),
thanks to(2.10)
and(3.6),
and since on 03A9 we have 0 ~ x ~ M. DLEMMA 3.2. - There exists ~03B4 > 0 such that
for ~
~03B4 we haveAnnales de l’Institut Henri Poincaré - Analyse non linéaire
Proof. -
To prove this lemma we will show thefollowing preliminary
estimate:
For
that,
we use the test functionin
(3.5). Straightforward computations
lead towhere
The term
L2
is0(1)
thanks to(2.10), (3.4)
and 0 uE 1. For theintegral L3
we recall moreoverthat xl (z) ~ ~ z ~
and use(3.6)
toget
L3
=0(1). Next,
since in fact we need a lower bound for these terms, forL4
it suffices to writethanks to
(3.6).
Hence(3.16)
readsThe four terms of the left hand side can in fact be estimated
separately
thanks to
sign considerations,
if we come back to thenon-homogeneous
Vol. 16, nO 6-1999.
706 F. MEHATS AND J.-M. ROQUEJOFFRE
functions
Uz
0 andU~ = u~
0. Aspreviously
inLemma
3.1,
weonly
have to take care of the fact that is not boundedin L°° . Remark that
thus
Therefore,
from(2.10), (3.10)
and(3.17),
we deduce the estimateswhich
finally imply (3.15).
The same kind of calculations
(but easier),
which we shall notdevelop here,
can lead to the same kind of estimate as(3.15),
in which wereplace
the z under the
integral by
an c. Weonly
state ithere;
it will be useful in thesequel
of theproof:
To prove
(3.14),
consider now in(3.5)
the test functionAfter some calculations we obtain
Annales de l’lnstitut Henri Poincaré - Analyse non linéaire
In the
right
hand side of thisequality,
theintegrals /
can be estimated thanks to(3.15)
and(3.18),
and theboundary integral
can be estimated thanks to(3.6), (3.10), (3.17)
andUz
0. For the lefthand side, by (3.1)
and
(3.2)
it suffices to take cr~2 /6
to obtainthus
(3.14)
isproved.
LEMMA 3.3. - For é small
enough
we haveTo prove the lemma we will
again
use a weak formulation of thissystem
and choose different test functions. Recall thatby (3.2)
and for everyinteger k
> 1 there holdsWith the test function p =
~21~2 vE:,
we obtainVol. 16, nO 6-1999.
708 F. MEHATS AND J.-M. ROQUEJOFFRE where
These four terms are
(9(1)
thanks toThis proves
(3.19).
To show(3.20), similarly
to(3.6),
we use the testfunction
The calculations are very close to those of Lemma
3.1;
we use(3.6), (3.10), (3.19)
and(3.22)
to obtainwhere
We
just
notice that theexponent
of xi in p has been chosen toestimate,
thanks to(3.19),
thefollowing
term that appears in the calculations(in
the
right
handside):
To
conclude,
it suffices to take the same a and~3
as for(3.12),
then toestimate
Zl
asZl.
DAnnales de l ’lnstitut Henri Poincaré - Analyse non linéaire
From this lemma and Sobolev
embeddings
we deducefor 0 a
1/2
and 0,~
1.Following
the samescheme,
withappropriate
cut-off functionsxil x2,
we could prove thecontinuity
on wof functions of the form and the
continuity
on H offunctions of the form
Nevertheless,
for the sake ofsimplicity,
we will not consider in the
sequel
the behaviour of the self-similar solution U near the axis{z
=0~
and restrict ourstudy
onWe define another cut-off function 0
X3(z)
1 such thatPROPOSITION 3.4. - We have U E
z0[ [0,
Proof. - Setting
we will prove
recurrently,
for everyinteger
n, theproperty
By (2.10)
and Lemma3.1,
wealready
have(Po)
andby
Lemma3.3,
wehave
(Pi).
We now assume that(Pk)
holds for 0 k n -1, 6
> 0 and that n > 2. The functionu(n)
is solution of thesystem
In this
system
we do not need the values of the coefficients an,k ; we willonly use
further an,o = 1.Multiply (3.24H) by
~p = andintegrate
over After some calculations we obtainVol. 16, nO 6-1999.
710 F. MEHATS AND J.-M.
ROQUEJOFFRE
where
Since
u(n)
=o~z~c~n-1~, Property implies Vi
=C~(1). Next,
Property
writesIf k > 1 then
by Property (Pn-k)(iii)
we also haveMoreover,
k~ n21 ~ and n 2:
2imply
1 I~ n -1;
thusby (Pk)( iii), (Pk-1)(iii)
and Sobolevembeddings
we haveFrom these three estimates
(3.25), (3.26)
and(3.27)
we inferdirectly J2
=C(l).
Remark now that~~n~
writeswhere
Q
is apolynomial; thus,
since z 2: 8 on c~s,(3.26), (3.27)
and(3.28) imply J3
=C~ ( 1 ) . Finally,
weintegrate by parts
the two terms ofJ4;
thanks to(3.25), (3.27)
and(3.28)
we haveAnnales de l ’lnstitut Henri Poincaré - Analyse non linéaire
Therefore we
get
Property (P n+ 1) ( i)
isproved.
With a
change
of6,
we can now consider(3.29)
with theintegrals
calculated on
S2~
instead of522b.
Let the test functionThanks to
(Pn-i)
and(3.29), similarly
to theproofs
of(3.6)
and(3.20),
straightforward
calculations lead towhere
Let us treat the
boundary
term.Replacing (C‘~x2G~,n~ )2 by
itsexpression given by (3.24H)
leads toestimating
terms of the formIf k > 1 and
l~’ > 1, by (3.26)
and(3.27)
we haveZ( 1~,1~’ )
=C~ ( 1 ) .
Ifk = 0 and k’ = 1 then an
integration by parts yields
We
already
know that E and the functionsUé, U~l),
x3 andx3
are bounded in
L°° (c,vb ) .
Hence the second and the third terms ofZ( 0,1 )
are
(9(1).
For the first one, two cases have to be considered. If n > 2then, by (3.27), U(2)
is also inL°° (cvs ) .
If n = 2 the term to estimate writesVol. 16, nO 6-1999.
712 F. MEHATS AND J.-M. ROQUEJOFFRE Thanks to
and
Gagliardo-Nirenberg inequality [I],
we havethus,
for every a >0,
since 0
X3 :::;
1.Finally
we addI(O, 0)
and obtainSet 03C3 = 1. The other
boundary integrals
of(3.30)
are easier to estimatesince
they
contain lower order terms. We do not detail the calculations and(3.30)
writesWe conclude
exactly
as for(3.12),
and obtain and(P,L+i ) (iii).
Therefore, recurrently, (Pn)
holds for everyinteger n
> 0.To end the
proof
of thelemma,
thanks to Sobolevembeddings
it issufficient to show that
Recurrently
it is easy to seethat,
for all(p, m),
we havewhere
Qp,m
and arepolynomial in z, x
and c. This formula comes after successive derivations of(3.24H):
a term can bereplaced by
terms of order 0 or 1 in
8x.
Therefore(3.32)
can be deduced from theproperties (Pn).
0Annales de l’Institut Henri Poincaré - Analyse non linéaire
3.2.
Continuity
at theboundary
In this section we consider the trace of the self-similar solution at the
boundary. By Proposition 2.1,
we have 0on ] - oo, 0]
U[zo, [
and, by Proposition 3.4,
this function is C°°on 0, zo ~.
Since~yU
isdecreasing,
one can definePROPOSITION 3.5. - We have
",/U
EProof. -
Consideragain
the weak formulation(2.12H)
of(1.4H),
withappropriate
test functions. Remark that(2.12H)
can also be written in aweaker formulation that does not take in account ux E
L~(R~_):
(3.33)
_Let M denote an
arbitrary large positive
constant, and define x2 = x2(x)
by (3.3). Next,
let po = be such thatLet 0
r~ zo /3
and define thefollowing
three subsets ofR~_:
Plug
now the test function =cpo(z)xz(:c)
in(3.33).
Wesplit
thedifferent
integrals
which appears in this formulation as followsRecall
that,
otherwisementioned,
a one-dimensionalintegral
denotes anintegral
calculated on the axis{x
=0~:
Vol. 16, nO 6-1999.
714 F. MEHATS AND J.-M. ROQUEJOFFRE
Denoting by [a, b]
an interval of R(bounded
ornot),
we introduce the notationHence, Equation (3.33)
writes. On
Di, u
= 0 and thus. On
D3
nSupp(p), by Proposition 3.4, u -
U issmooth;
hence we canintegrate
the different terms ofA(u,
p,by parts:
Moreover U is a
strong
solution of(1.4NH).
Thisimplies
Finally (3.34)
readsthus
~yU(0+)
= 1 =yU(0-).
This
proof
can beadapted easily
to show1’U(zo-)
= 0 =Consider indeed the test function
cp(z,.r,)
= in(3.33),
whereis defined
by
Annales de l’Institut Henri Poincaré - Analyse non linéaire
It suffices to
split ~+
as followsthen to remark that U - 0
on zo,
and U is smooth on]
- oo, zo -77]
xR+
n we can thusproceed
as above. D4.
UNIQUENESS
OF THE SOLUTIONThis
part
is devoted to theproof
of Theorem1.2,
i.e. theuniqueness
ofan
entropy
solution to Problem(1.4H).
Let us say that a functionu( x, z)
isan
entropy
solution to(1.4NH)
if andonly
if it satisfies the twofollowing properties.
.
(E1) u
E nL°°((~+),
~yu E EL2((~+);
moreverit is a solution of the weak formulation
.
(E2)
Thereholds, uniformly
in x ER+:
.
(E3)
Theboundary
measure uz islocally
bounded from above.A few remarks are in order. First of
all,
notice that the aboveassumptions
are
trivially
satisfiedby
the solution U that we constructed in theprevious
parts
of this paper.Second,
let us notice that theregularity properties
ofAssumption (E1)
are the minimal ones so that the weak formulation(4.1)
makes sense. Let us recall
that, by
virtue ofChap. 5,
Section 2 of[6],
thefact that u
belongs
to ensures the existence of of anL~
trace;because we wish the term
u2
to make sense, werequire u
to be inwhich is not a very
stringent assumption. Finally, Assumption (E3) implies (i)
that ~yubelongs
to and(ii)
that ~yu has lateral limits and moreover, if zo is apoint
ofdiscontinuity
of -yu we have>
The
integrated
version of Problem(1.4) reads,
at leastformally:
Vol. 16, nO 6-1999.
716 F. MEHATS AND J.-M.
ROQUEJOFFRE
Most of the results that will be needed are
gathered
in the Crandall-Ishii- Lions ’User’sguide’ [5].
Let us recall the definition of aviscosity
solutionto
(4.2). If p =
denotes a vector of(~2,
and M = letH(z,x,v,p,M)
andH(z,x,v,p,M)
denote thefollowing hamiltonians:
A
viscosity supersolution
to(4.2)
will here be auniformly
continuousfunction
v(z, x)
suchthat,
forall §
ECo ( (~ 2 -~ ) ,
there holdsat any local minimum
point (zo, xo)
of v -~. Similarly,
aviscosity
subsolution to
(4.2)
will be auniformly
continuous functionv(z, x)
suchthat,
forall cp
ECo ( ~ 2 -~ ) ,
there holdsat any local maximum
point (zo, xo)
of v -~.
Aviscosity
solution to(4.2)
will be a
uniformly
continuous function such that the twofollowing properties
hold:.
(VI)
thereholds, uniformly
in x ER+:
.
(V2) v
is a both aviscosity
subsolution and aviscosity supersolution
to
(4.2).
Once
again,
this definition calls for a one remark. Due to the unboundedness of the coefficients and theparticular
form of thehamiltonian,
it is necessary to
prescribe
in aprecise
manner thegrowth
of the solution atz = - oo .
Indeed,
for any cx >0,
Problem(1.4NH)
has a solutiontending
to a as z --~ -oo,
producing
aviscosity
solution to(4.2) behaving
likeat z = - oo . This is to be
compared
with the situationpresented
in
[5],
Section 5.D.To prove Theorem
1.2,
weproceed
in twosteps: first,
we prove auniqueness
result for Problem(4.2);
then we provethat,
for anyentropy
solution of(1.4NH),
the functionv(z, x) _ u(z’, x) dz’
is aAnnales de l ’lnstitut Henri Poincaré - Analyse non linéaire
viscosity
solution to(4.2). Although
theuniqueness
result belowis, striclty speaking,
not contained in theliterature,
theproof
that we aregoing
togive
is
by
nowextremely
classical. Let us concentrate on the firstpart
of ourprogramme;
the mostgeneral
result in this direction is due to Barles[3];
our situation does notcompletely
fit in this context due(i)
to the unboundedness of the solution and of thehamiltonian, (ii)
to thequadratic growth
in theboundary
conditions.However,
as ispointed
out in Section 5.A of[5], things
areconsiderably simpler
when smooth sub andsupersolutions
areknown. This is the case
here;
as a matter of fact there holdsLEMMA 4.1. - Let
U(z, x) be
the solution constructed in Theorem l.l.Then
V(z,x)
=U(z’, x) dz’
is aviscosity
solution toproblem (4.2).
Moreover,
it is an admissble testfunction
in thisproblem.
Proof. -
Let us first recall thatY(z, 0)
=U(z’,O) dz’
isC1
andLipschitz
overI~,
and the functionzVz(z,x) _ - z U ( z , ~ ) belongs
toC(R+,X)
nC(R-.,X)
whereand denotes the space of all bounded
uniformly
continuousfunctions on
~~.
Recall now that theoperator L,
defined fromto
X,
and with theexpression
is an
isomorphism.
Hence we have V EC1(I~+, D(L))
nC1((~_, D(L)),
and the result of the lemma follows
immediately:
. if
(zo, ~o)
is a maximum(resp. minimum)
of V -~,
then- if
0,
thenVx
=03C6x, Vxx ~ 03C6xx
at(zo, x0 ) (resp. Vxx ~ 03C6xx);
because
z~z
vanishes at thepoints
ofdiscontinuity
ofVz,
this is sufficientto
get
theresult;
- if Xo =
0,
because1’V
EC1 (I~),
thenVz
=~z
and-Vx
>-~x (resp.
- Vx
>2014~.r).
This is onceagain
sufficient.. Because V E
C1(I~+, D(L))
nC1(I~_, D(L)),
V is an admissible testfunction,
forz Vz
= 0 at thepoints
ofdiscontinuity
ofVz.
DVol . 16, n° 6-1999.