C OMPOSITIO M ATHEMATICA
J. DE G ROOT H. DE V RIES
Convex sets in projective space
Compositio Mathematica, tome 13 (1956-1958), p. 113-118
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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
http://www.numdam.org/
by
J. de Groot and H. de Vries
INTRODUCTION. We consider the
following properties
of sets inn-dimensional real
projective
spacePn(n
>1 ):
a set issemiconvex,
if any two
points
of the set can bejoined by
a(line)segment
whichis contained in the set;
a set is convex
(STEINITZ [1]),
if it is semiconvex and does not meet a certainP n-l.
The main
object
of this note is to characterize theconvexity
of a set
by
thefollowing
interior andsimple property:
a set isconvex if and
only
if it is semiconvex and does not contain awhole
(projective) line;
in other words: a subset ofPn
is convexif and
only
if any twopoints
of the set can bejoined uniquely by
asegment
contained in the set. In many cases we can prove more; see e.g. theorem 2.H. KNESER
[2] gives
a detailed survey of the different scmi-convex sets in
P2
andP3;
see also HAALMEYER[3]. 1’hough, surprisingly enough,
he nowhere states the characterization-property just mentioned,
thisproperty
mayeasily
be concludedfrom the material contained in his paper.
However,
his methodworks
only
for n = 2, 3.Only
theorem 3, statedbelow, serving
as a lemma, is due to H. Kneser for ail n.
Recently
we learnedthat D. DEKKER
[4]
also discovercd thementioned
characteriza-tion,
butohly
for open sets. Theorem 1,theréfore, gives
no newsin the case of open sets.
However,
ourproof
is somewhat different.The authors are indebted to A.
HEYTING,
who drew their attention to thischaracterization-problem.
It is
possible,
of course, to stateanalogous problems
for then-sphere 5 n (or
for certain other spaces aswell), replacing
linesby great
circles. The resultis, roughly spoken,
that the charac-terization-property
holds for open sets inS.,
but breaks down forarbitrary
ones.However,
since the results for the5 n
may be obtained far easier than for thePn,
vi+e do not discuss thcln hère.114
We shall denote
points by
small Latinletters,
linesby
smallGreek letters or two small Latin letters if these denote
points
of the
line,
andsegments by
theend-points
of thesegment
if thisis stated
explicitly.
THEOREM 1. In order than an open or closed semi-convex set V in
Pn (n
>1) is
convex, it is necessary andsufficient
that V does not contain a whole line. Moreover:i f
Vsatisfies
thiscondition,
then
for
everypoint
q EPnB V,
there exist8 an(n -1 )-dimensional hyperplane,
which contains q, and has nopoints
in common with V.PROOF. The
necessity
of the condition is obvious. To prove thesufficiency
and the secondpart
of thetheorem,
weproceed by
induction.Let n = 2. Take a
point
v E V and let a) be the line qv.Let ,ut
be a variable line
through q, always
Ilt ~ ce, litseparates P2B03C9
into two
disjoint
connectedparts, It
andII t.
We see to it thatalways It~It’ ~
0,IIt~IIt’
=A 0. Wedecompose V
t = Iltn V into twodisjoint
setsA
t andBt
in thefollowing
way: weput
at E
V t,
resp.bt
EV t,
inA t,
resp.Bt,
if one of thesegments
atv, resp.btv,
of the line atv, resp.btv,
liesentirely
within V~It,
resp. within V
~IIt.
Since V is semiconvex and does not containa whole
line,
we haveIf V is open, then
A
t is an open set on the line pi,because,
if at E
A t,
thereis, by applying
the Heine-Boreltheorem,
an openneighbourhood
of asegment
atv which is contained in V. But then alsoBt
is open on pi. SinceVt
isconnected,
we may conclude that for a definite t eitherA
t orBt
isempty.
[If
V isclosed,
thenA t
is closed on pi since the limit of a con-verging
sequence of closedsegments aitv, ait
EA t, entirely lying
within
(V~It)~03C9~03BC
t isagain
a closedsegment lying
within(V~It)~03C9~03BCt.
Then alsoB t
is closed on 03BCt, and we may conclude that eitherA
t orB t
isempty.]
Now we
project U A and U Bt
from q upon a line Àthrough
v, À ~ co; the
projections will
beL1
andL2 respectively.
Thenobviously Li ~ L2
= 0.If V is open, then
L,
is open on À : apoint pl E L1
is theprojection
of a
point p E U A t,
p has on the line vp aneighbourhood belonging
to U
A t,
sopl t has
aneighbourhood
on Àbelonging
toLl.
Thenalso t L2
is open,L1~L2
= 0, so there exists apoint q’
E 03BB,q’ ~ Ll
uL2
U{v},
and the lineqq’
liesentirely
within the com-plement
of V.[If
V isclosed,
thenL1
andL2
are each closed on03BBBv
as caneasily
be seen. Since03BBBv
isconnected,
there exists apoint q’ E 03BBBv, q’ ~ Li
UL2,
and the lineqq’
liesentirely
within thecomplement
of
V.]
So the theorem is
proved
for n = 2.Now we assume the theorem to be true for n = k -1 and prove the theorem for n = k
(k
>2).
We
take q E PkBV
and 03A9 as aPk_1
inPk
notcontaining
q.We
project
Tl from q uponS2,
thusobtaining
V’ ~ 03A9. Then withpl, p2 E V’, V’
containsobviously
one of thesegments
ofp’1p’2,
and does not contain both
segments:
the two-dimensionalplane generated by
q,p’, p’
contains a linethrough
q, which avoids V(the
intersection of a semiconvex set notcontaining
a whole linewith a
hyperplane
is a similarset),
and so this line intersectspip2 in a point,
notbelonging
to V’.Using
theinduction-hypothesis
we
get
that V’ avoids aPk-2 lying in
D. The(k-1)-dimensional hyperplane through
thatPk_2 and q
avoidsV, q.e.d.
THEOREM 2.
Il
V is an open or closed convex set in aPn (n
>1),
and H is a
Pn_k (k
>0 ) avoiding V,
then there exisis aPn-1 containing
H andavoiding
V.PROOF. For k = 1 the theorem is trivial. We assume further k > 1. We
proceed by
induction withrespect
to n.For n = 2 the theorem has been
proved
in theorem 1.Assuming
the theorem to be true for n -1, we prove the theorem for n.
Choose an
(m-1)-dimensional hyperplane S containing
H.S ~ V is convex.
So, according
to theinduction-hypothesis,
thereexists a
Pn_2
C Scontaining
H andavoiding s
r1Tl,
thus alsoavoiding
V. Let il be aPn-1 avoiding
V. If Q D H we areready.
Assume
03A9 ~ H.
LetFt
be a variable(n -1 )-dimensional hyper- plane containing
the above-mentionedP,-21
thus alsocontaining
H.
FtB(Pn-2~03A9)
isdecomposed by Pn-2
and03A9~Ft
into twodisjoint
connectedparts
of whichonly
one may containpoints
of V. If V is open, we
get by varying Ft continuously
"a first situation" in which thispart
contains nopoints
of V. Neithercan in this situation the other
part
containpuints
ofV,
sinceif it would then that
part
would also containpoints
of V in"an earlier situation". If V is closed the theorem is
proved
similarly.
-THEOREM 3.
(KNESER ). I f a
-semiconvex set V in aPn
contains n+1linearly independent points
po, Pl’ ..., P., then eachof
thesepoints, for
instance Po, is vertexof
an n-dimensional-simplex
the116
interior
points of
whichbelong
to V. This includes, that everypoint of
V is accumulationpoint of
interiorpoints of
V.PROOF. The theorem is true for n = 1. We assume the theorem to be true for n = N-1 and prove it for n = N.
The
PN-1
definedby
pi, ..., pN contains an(N-1)-dimen-
sional
simplex E,
the interior of whichbelongs
toV, according
to the
induction-hypothesis applied
to the semiconvex set V ~PN-1.
In the N-dimensionalprojective
spacePN,
thesimplex
27 and the
point
po define two N-dimensionalsimplices 039B1, 039B2
of which 1 is a face. Let
Ml ,
resp.M2,
be the set ofpoints
of27 wh ieh can be
joined
with Po withinV ~ 039B1,
resp.V ~ 039B2.
Ml
andM2
are notnecessarily disjoint.
If one of the setsMi
contains interior
points,
then it contains an(N-1)-dimensional simplex P,
and hence there exists an N-dimensionalsimplex,
defined
by
P and po, contained inV;
so the theorem isproved.
We prove that
necessarily
at least one of the31,
containsinterior
points.
Let
L1,
resp.L2,
be the interior of039B1,
resp.A2.
The setPNBV
is semiconvex as can
easily
be seen. Wedistinguish
thefollowing
three cases: the maximal number of
linearly independent points
of
(PNBV)n(LluL2)
is1°.N+1,
2°.N, 3°.
N. In the secondcase we have two
possibilities:
allpoints
of(PNBV)~(L1~L2)
lie on an
(N-1 )-dimensional hyperplane containing
either notpo or po. In case of 1 °. and the first
possibility
of 2°. there existsan
(N-1)-dimensional hyperplane Q,
such thatPo 1- Q,
andQ~(PNBV)~(L1~L2)
contains Nlinearly independent points.
Using
theinduction-hypothesis,
weeasily get
thatQ
~(PNBV)
rl~
(L1
UL2)
contains interiorpoints.
Thisimplies Q
n(PNBV)
flLI
or resp.
Q~(PNBV)~L2
contains interiorpoints,
whichgives
that
M2
or resp.Ml
contains interiorpoints.
In case of the secondpossibility
of 2°. and3°., (PNBV)~(L1~L2)
is included in an(N-I )-dimensional hyperplane containing
po, and bothM1
andlaf 2
have interiorpoints.
THEOREM 4. An
arbitrary
semiconvex setV,
notcontaining
awhole
line,
in n-dimensionalprojective
spacePn (n
>1),
avoidsan
(n-1)-dimensional hyperplane.
1.11 oreover:i f
a is aiz interiorpoint 0f PnBV,
then there exists an(n-1)-dimensional hyperplane containing a
andavoiding
V.PROOF. We
proceed by
induction. First we prove the theorem for n = 2.If V is contained in a
line,
the theorem is trivial. If Il’ is notcontained in a
line,
then the closure W of the interior W of V containsV, according
to theorem 3.Clearly
W does not containa whole line. We prove, that W is also semiconvex
(and
thusconvex
according
to theorem1).
Choose p, q E
W, p ~
q. Join pand q by
asegment
S within V.Take a
point
r E pq, r 1. V. LetOp
C W andOq
C W be two con-nected
neighbourhoods
of p resp. q. Draw a variable line03BBt through
r
meeting Op
andOq.
S is contained in the interior of the sum of thesegments
in V on theÂ,, joining points
ofOp
andOq,
thatmeans S C
W, q.e.d.
W
=P2 implies
thatP2BW is
a line: the semiconvex setP2B W
cannot contain threelinearly independent points by
theorem 3, but
P2BW
contains at least one whole lineby
theorem1, thus
P2B W
is a line. Then W =V,
since other,yise V would contain a whole line. So the theorem holds in this case.If
W ~ P2,
there exists an open convexneighbourhood
0 of a,O C
P2B W. According
to theorem 1, we can draw a line octhrough
a,
avoiding
Hl.Let P
be anarbitrary
linethrough
a, oc ~03B2.
oc
and P decompose P2B(03B1 u fi)
into two connectedparts,
I and II.If V avoids ci., we are
ready.
a cannot contain accumulationpoints
of W~03B2.
If oconly
contains accumulationpoints
of W r1 Ior of W
~ II,
we can find a line «’through a avoiding W,
thusavoiding
V,by turning
a a little around a. On the otherhand,
if s E 03B1, resp. t E a, is an
accumulation-point
of W~ I, resp. W
rl IIwhile moreover s ~ t, we could find a line
joining
thepoints
x E W ~ I and y E W
~ II, x
and y near s resp. t,intersecting
ocin u
and
in v while v E0 ;
but in that case x, y and u, v would formseparated pairs,
x and y inW, u and v e W,
in contradiction with thesemiconvexity
of W. If s = t weproceed
as follows :W is not contained in a
line,
so we can find c, d EW,
sc ~ sd.Be III one of the
parts
ofP2B(sc ~ sd)
into whichP2B(sc ~ sd)
is
decomposed by
sc and sd, « notlying
in III. Allpoints
z of IIIbelong
to W : the interval III r1 cd of cd lies inW,
so we canconnect z with a
point
z’ of Wsufficiently
near to s, such that thepoints z
and z’ do notseparate
theintersection-points z",
z"’of zz’ with oc resp. cd, thus the
segment
of z’z"’ which containsz lies in
W,
and therefore z c W. Thencertainly
a whole linethrough s
minus s lies inW,
so s e V and a ~ V = 0, whichcompletes
theproof
for n = 2.If the theorem is assumed to be true for n =
k - 1,
we canprove it for n = k in
exactly
the same way as has been done in theproof
of theorem 1. Wehave only
to assume thatP,BV
118
contains interior
points.
If this is not the case, thenP,BV
isexactly
aPk-1 using
theorem 3by
a reduction ad absurdum and the theorem holds.REMARK. If V is an
arbitrary
convex set in n-dimensionalprojective
spacePn(n > 1),
and H is an(n-2)-dimensional hyperplane lying
in the interior ofPnBV,
then there exists an(n-1)-dimensional hyperplane containing
H andavoiding
V.This can be
proved
in a wayanalogous
to that used in theproof
of theorem 4.
Mathematisch Instituut
University of Amsterdam.
REFERENCES.
E. STEINITZ
[1] Bedingt konvergente Reihen und konvexe Systeme, J. für die reine und angew. Math. 146, p. 34, (1916).
H. KNESER
[2] Eine Erweiterung des Begriffes "konvexer Körper". Math. Ann. 82, p.
287-296, (1921).
B. P. HAALMEYER
[3] Bijdragen tot de theorie der elementairoppervlakken, Amsterdam, 1917.
D. DEKKER
[4] Convex regions in projective space, The Amer. Math. Monthly, 62, no. 6, p. 4302014431, (1955).
(Oblatum 29-8-55).